The solution set for -18 < 5x - 3 is _____.
please i need help

Answer: 2/6

Step-by-step explanation:

There’s only 2 numbers greater than 4 on a die, so two would be the numerator and the denominator would be the number of possibilities you could roll, which is 1-6.

2/6, 1/3, or approx. 33.3%

A number cube will have six sides and two out of six will be greater than four, therefore, there is around a 33.3% chance you will roll a number greater than 4. :)

In Pascal's Triangle, the first prime row is Row 5, where all entries except the 1s are non-prime numbers. The second prime row is Row 11, which also follows the same pattern with non-prime entries except for the 1s.

a) To find a row whose row number is prime, we can start from the second row (row index 1) and iterate through the rows of Pascal's Triangle, checking if each row number is prime. Let's find the first prime row:

Row 1: 1

Row 2: 1 1

Row 3: 1 2 1

Row 4: 1 3 3 1

Row 5: 1 4 6 4 1

Row 6: 1 5 10 10 5 1

Row 7: 1 6 15 20 15 6 1

Row 8: 1 7 21 35 35 21 7 1

Row 9: 1 8 28 56 70 56 28 8 1

Row 10: 1 9 36 84 126 126 84 36 9 1

Row 11: 1 10 45 120 210 252 210 120 45 10 1

Row 12: 1 11 55 165 330 462 462 330 165 55 11 1

Row 13: 1 12 66 220 495 792 924 792 495 220 66 12 1

Row 14: 1 13 78 286 715 1287 1716 1716 1287 715 286 78 13 1

Row 15: 1 14 91 364 1001 2002 3003 3432 3003 2002 1001 364 91 14 1

The first prime row is Row 5, and except for the 1s in that row, all the other entries are non-prime numbers.

b) Let's find another prime row:

Row 1: 1

Row 2: 1 1

Row 3: 1 2 1

Row 4: 1 3 3 1

Row 5: 1 4 6 4 1

Row 6: 1 5 10 10 5 1

Row 7: 1 6 15 20 15 6 1

Row 8: 1 7 21 35 35 21 7 1

Row 9: 1 8 28 56 70 56 28 8 1

Row 10: 1 9 36 84 126 126 84 36 9 1

Row 11: 1 10 45 120 210 252 210 120 45 10 1

Row 12: 1 11 55 165 330 462 462 330 165 55 11 1

Row 13: 1 12 66 220 495 792 924 792 495 220 66 12 1

Row 14: 1 13 78 286 715 1287 1716 1716 1287 715 286 78 13 1

Row 15: 1 14 91 364 1001 2002 3003 3432 3003 2002 1001 364 91 14 1

The second prime row is Row 11, and similar to the previous case, except for the 1s in that row.

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The sum of the series when evaluated are ∑aₙ² + 1 = 45, ∑bₙ² - 1 = 35, ∑(2aₙ + bₙ) = 0, ∑(aₙ + 3bₙ) = 0, ∑(aₙ/bₙ)² = 2, ∑(aₙ/bₙ)³ = -2, ∑aₙ² + ∑bₙ² = 80 and ∑aₙ² - ∑bₙ² = 0

Series 61

This series represents the summation of aₙ² + 1 from n = 1 to 5

From the graph, we have

a₁ = -4; a₂ = -2; a₃ = 0; a₄ = 2 and a₅ = 4

So, we have

∑aₙ² + 1 = (-4)² + 1 + (-2)² + 1 + (0)² + 1 + (2)² + 1 + (4)² + 1

∑aₙ² + 1 = 45

Series 62

This series represents the summation of bₙ² - 1 from n = 1 to 5

From the graph, we have

b₁ = 4; b₂ = 2; b₃ = 0; b₄ = -2 and b₅ = -4

So, we have

∑bₙ² - 1 = (4)² - 1 + (2)² - 1 + (0)² - 1 + (-2)² - 1 + (-4)² - 1

∑bₙ² - 1 = 35

Using the above formats, the sum of the remaining series is

Series 63

∑(2aₙ + bₙ) = (2 * 4 - 4) + (2 * 2 - 2) + (2 * 0 - 0) + (2 * -2 + 2) + (2 * -4 + 4)

∑(2aₙ + bₙ) = 0

Series 64

∑(aₙ + 3bₙ) = (4 - 3 * 4) + (2 - 3 * 2) + (0 - 3 * 0) + (-2 + 3 * 2) + (-4 + 3 * 4)

∑(aₙ + 3bₙ) = 0

Series 65

∑(aₙ/bₙ)² = (2/-2)² + (4/-4)²

∑(aₙ/bₙ)² = 2

Series 66

∑(aₙ/bₙ)³ = (2/-2)³ + (4/-4)³

∑(aₙ/bₙ)³ = -2

Series 67

∑aₙ² + ∑bₙ² = (-4)² + (4)² + (-2)² + (2)² + (0)² + (0)² + (2)² + (-2)² + (4)² + (-4)²

∑aₙ² + ∑bₙ² = 80

Series 68

∑aₙ² - ∑bₙ² = (-4)² - (4)² + (-2)² - (2)² + (0)² - (0)² + (2)² - (-2)² + (4)² - (-4)²

∑aₙ² - ∑bₙ² = 0

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Answer:

just free your mind drink water and go outside take fresh air you will get answers.

Explanation:

This a best method to solve the answer.I hope it is helpful to you

When an algorithm necessitates extensive sharing of instantaneous results, parallelism slows it down. Because there are multiple independent parallel processes and the right number of threads, parallelism will speed up an algorithm.

The ones with data dependencies are the most challenging. It will be exceedingly challenging, for instance, if you are dealing with a vector and the input for the computation at point n depends on the output at position n-1.

When this occurs, you must comprehend what the original algorithm is doing and take an alternative approach. For the aforementioned case, it might be a difficulty with digital signal processing including a feedback-containing digital filter. These are challenging to parallelize, but that is not the sole solution. Instead, you might use the filter and signal's fast Fourier transforms, multiply them, and then perform the inverse transform. All of these operations can be partially parallelized.

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If she wants to meet her target distance 3/20 steps need to be taken.

Emily made the decision to walk 4/5 kilometers every day in order to keep healthy. She walked a distance of 2/5 miles to work and a distance of 1 mile for lunch.

The desired range is 4/5 miles.

walked for 2/5 miles and for 1/4 miles.

Total miles walked is \(\frac{2}{5} + \frac{1}{4}\)

= \(\frac{13}{20}\)

Mileage walked overall is +

LCD is 20

add the fractions after matching the denominators

The desired range is 4 to 5 miles.

Now deduct the distance you walked from the goal distance.

\(\frac{4}{5} - \frac{13}{20} \\\\\frac{16}{20} - \frac{13}{20} \\\\\frac{3}{20}\)

the required walking distance is 3/20

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Answer:

There are 20 customers all together.

Step-by-step explanation:

Let x = the total number of customers.

12% of what number is 24.  12% as a decimal is .12

.12x = 24  Divide both sides by .12

\(\frac{.12x}{.12}\) = \(\frac{24}{.12}\)

x = 200

Helping in the name of Jesus.

To calculate the standard deviation of the sampling distribution of p-hat, the answer will be 59 students.

By calculating,

600/10=60 and 59 students which is less than 10% of the population.

A sampling distribution, also known as a finite-sample distribution, in statistics is the probability distribution of a given random-sample-based statistic. The sampling distribution is the probability distribution of the values that the statistic takes on if an arbitrarily large number of samples, each involving multiple observations (data points), were used separately to compute one value of a statistic (such as, for example, the sample mean or sample variance) for each sample. Although only one sample is frequently observed, the theoretical sampling distribution can be determined.

Because they offer a significant simplification before drawing conclusions using statistics, sampling distributions are crucial in the field. They enable analytical decisions to be made based on the probability distribution of a statistic rather than the combined probability distribution of all the individual sample values

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When a sprinkler head is installed on a finished ceiling or wall, a(n) escutcheon is required and may be included as part of the listed assembly or as a decorative touch.

An escutcheon is a protective and decorative cover that is used when a sprinkler head is installed on a finished ceiling or wall. It is designed to conceal the gap between the sprinkler head and the surrounding surface, providing a neat and finished appearance. The installation of an escutcheon is necessary for several reasons. First, it helps to prevent the accumulation of dust, dirt, or debris around the sprinkler head, which could potentially interfere with its functions.

By covering the gap, the escutcheon acts as a barrier, keeping the area clean and maintaining the proper operation of the sprinkler system. Secondly, the escutcheon serves an aesthetic purpose. It enhances the overall appearance of the sprinkler head installation, making it visually appealing and blending it seamlessly with the surrounding ceiling or wall.

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Answer:

Radius - 25.4cm²

Circumstance- 159. 593cm²

Area - 2,026.83cm²

I think not sure

Answer:

,,,

Step-by-step explanation:

Answer:

Scientifically proven that there is a 60% chance you will get an odd number and a 40% chance you will get an even number.

I hope this helps!!

Answer:

5= log2(32)

Step-by-step explanation:

IT IS CORRECT! I took the test :)

The df values for the A x B interaction are also 4, 36.

According to the question

The F-value for Factor A has df = 2, 36

The F-value for Factor B has df = 2, 36

The source of variation between columns has ( c- 1); rc(n-1) degrees of freedom and  the source of variation between  rows has (r-1); rc(n-1) degrees of freedom and the  source of variation of interaction

(between rows and columns)  has ( c-1) ( r-1); rc(n-1) degrees of freedom.

Therefore

Factor A:  ( c- 1); rc(n-1) = 2, 36

Factor B:    (r-1); rc(n-1) = 2, 36

Interaction : ( c-1) ( r-1); rc(n-1)   =  2*2, (36)= 4, 36

where c refers to columns , r refers to rows and n refers to the total sample size.

The df values for the A x B interaction are also 4, 36.

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could you please re post the question clearly as right now I don't understand what this means, you can try just taking a picture of the question and attach it to your post

Answer:

12 inches

Step-by-step explanation:

This is a square of sidee length 3 inches.  As there are four (equal) sides, the perimeter of this square magnet is 4(3 inches), or 12 inches.

First, we need to find the equilibrium solutions for the differential equation:

0.06y(1-y/2400) - c = 0

0.06y - 0.06y^2/2400 - c = 0

y(0.06 - 0.000025y) - c = 0

0.06y - 0.000025y^2 - c*y = 0

This is an autonomous logistic growth equation with a harvesting term. The term "-cdy/dt" represents the effect of harvesting on the population, where c is the harvesting rate.

The equilibrium solutions occur when dy/dt = 0, so we have:

0.06y(1-y/2400) - c = 0

0.06y - 0.06y^2/2400 - c = 0

0.06y - 0.000025y^2 - c*y = 0

The only possible equilibrium solutions are at y = 0 or y = 2400. To determine whether there is only one equilibrium solution, we need to evaluate the sign of the derivative of the right-hand side of the equation:

d/dy (0.06y - 0.000025y^2 - cy) = 0.06 - 0.00005y - c

This derivative is negative when y < 1200 - 20000/c and positive when y > 1200 - 20000/c. Therefore, there is only one equilibrium solution if c is greater than 0.003 and less than 3.

For the population of fish in the lake, the equilibrium solutions occur when:

0.08y(1-y/3800) = 0

y = 0 or y = 3800

Since the initial population is 940, the equilibrium solution at y=0 is not possible. Therefore, the only possible equilibrium solution is at y = 3800.

To determine how many fish can be harvested each year to maintain the population in equilibrium, we need to set d/dt (0.08y(1-y/3800) - h) = 0, where h is the harvesting rate. Solving for h, we get:

h = 0.08y - 0.0002y^2

At equilibrium, y = 3800, so the maximum harvesting rate that would maintain the equilibrium population is:

h = 0.08(3800) - 0.0002(3800)^2 = 608 fish per year

Therefore, to maintain the population in equilibrium, the lake can sustainably harvest up to 608 fish per year.

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Answer:

It will be 40

Step-by-step explanation:

Hope this helped have an amazing day!

The given statement is,

→ if u have 10 and add 20 and add 10.

In mathematical expression,

→ (10 + 20) + 10

→ 30 + 10

→ 40 is the answer.

Answer:

(0,8) (1,7)

Step-by-step explanation:

The vertex is (0,8)

We must find a second point to plot so we will put x as 1, after further simplifying we have 7, so (1,7) is the second point.

Answer:

,

Step-by-step explanation:

1. The covariance between X1+X2 and X3+X4 is zero.

2. The probability that the price of the share at the end of the four weeks is higher than it is today is 0.9544 or 95.44%.

Q1) Cov(X1+X2, X3+X4) is to be found given that Cov(Xm, Xn) = mn−(m+n) where m and n are natural numbers.

Cov(X1+X2,X3+X4)

Now, X1+X2 and X3+X4 are independent, so their covariance will be zero.Therefore, Cov(X1+X2,X3+X4) = 0

Hence, the covariance between X1+X2 and X3+X4 is zero.

Q2) The evolution of prices assumes that the price ratios F(n)/F(n−1) for n≥1 are independent and identically distributed lognormal random variables and lognormal parameters μ=0.012 and σ=0.048 is given, we have to find the probability that the price of the share at the end of the four weeks is higher than it is today.

Let's consider the lognormal distribution formula, which is:

F(x;μ,σ) = (1 / (xσ√(2π))) * e^(- (ln(x) - μ)² / (2σ²))whereμ = 0.012 and σ = 0.048. x is the current price and x(4) is the price after four weeks.

The ratio F(4)/F(0) = F(4) / x is log-normally distributed with parameters μ = 4μ = 0.048 = 0.192 and σ² = 4σ^2 = 0.048² * 4 = 0.009216.

The required probability isP(F(4) > x) = P(ln(F(4)) > ln(x)) = P(ln(F(4)/x) > 0) = 1 - P(ln(F(4)/x) ≤ 0)  = 1 - P(z ≤ (ln(x(4)/x) - μ) / σ), where z = (ln(F(4)/x) - μ) / σ = (ln(F(4)) - ln(x) - μ) / σ is a standard normal random variable.

Then,P(z ≤ (ln(x(4)/x) - μ) / σ) = P(z ≤ (ln(x) - ln(F(4)) + μ) / σ) = P(z ≤ (ln(x) - ln(x * e^(4μ)) + μ) / σ) = P(z ≤ (ln(1/e^0.192)) / 0.048) = P(z ≤ -1.693) = 0.0456

Therefore, the probability that the price of the share at the end of the four weeks is higher than it is today is 1-  0.0456 = 0.9544 or 95.44%.

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To compare 56.607 and 56.617 you have to look at the hundredths place. Given that 0 is less than 1, then 56.607 is less than 56.617

Answer:

  -11x² +14x -11

Step-by-step explanation:

When one polynomial is subtracted from another, each of the terms of the subtrahend is subtracted from the corresponding term of the minuend.

  (-2x² +4x -10) -(9x² -10x +1)

  = (-2 -9)x² +(4 -(-10))x +(-10 -1)

  = -11x² +14x -11

Answer

14 notebook computers: 3850$

16 desktop computers: 2400$

Step-by-step explanation:

275x14=3850

150x16=2400

The equivalent expression of this 19 - 6(-k + 4) will be 6k + 5.

Given that:

Expression, 19 - 6(-k + 4)

The equivalent is the expression that is in different forms but is equal to the same value.

The definition of simplicity is making something simpler to achieve or grasp while also making it a little less complicated.

Simplify the expression, then we have

⇒ 19 - 6(-k + 4)

⇒ 19 + 6k - 24

⇒ 6k - 5

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Answer:

if you solve the question please i request you please read the question carefully after solve the question

The solutions of the equation f(x) = g(x) include the following: B. -3, 0, 2, -4.

In Mathematics and Geometry, a point of intersection simply refers to the location on a graph where two (2) lines intersect or cross each other, which is primarily represented as an ordered pair containing the point that corresponds to the x-coordinate (x-axis) and y-coordinate (y-axis) on a cartesian coordinate.

By critically observing the graph of the lines representing the given system of equations, we can reasonably and logically deduce that the correct solution set lies in both Quadrant II and IV and it is denoted by the point of intersection of both the x-coordinate (x-axis) and y-coordinate (y-axis), which is given by this ordered pair (-3, 0) and (2, -4).

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Answer:

135°

Step-by-step explanation:

The sum of interior angles of a regular polygon is (n-2) x 180

N is the number of sides, this shape has 8

(8-2) 180

= 1080 total degrees in the shape. Reach angle is equal so then divide by 8.

1080/8 = 135°

y=-4x+7

the -4 is the slope and the 7 is the y-intercept

AB || CD and AC is oblique ;

So : Angle ( BAC ) = Angle ( DCA )

_________________________________

∆ ABC - ∆ ACD :

(1) AB = CD

(2) Angle ( BAC ) = Angle ( DCA )

(3) AC = AC

So According to (1) , (2) , (3) :

∆ ABC =~ ∆ ACD

Well, if two triangles are deposited, all their components are equal peer to peer.

So : AD = BC

A Negative correlation coefficient means that as one variable increases, the other decreases (i.e., an inverse relationship).