the product of three negative is _________ integer​

Answer:

\(\frac{1}{3}\)

Step-by-step explanation:

Since 3 feet is a yard, one foot is 1/3.

So that is the answer.

Answer:

1/3

1 mile to yards as a fraction would probably be 1/3. I'm not so sure...

Answer:

y=-.5x-7

Step-by-step explanation:

The given equations represent the solutions of 0 = 0.25x² - 8x

An equation is a mathematical statement that shows the equality of two expressions, typically separated by an equal sign. Equations are used to solve problems and model real-world situations in many fields, including physics, engineering, and finance.

Redirecting to answer:

The equation 0 = 0.25x² - 8x can be rewritten as:

0.25x² - 8x = 0

Factoring out x gives:

x(0.25x - 8) = 0

So the solutions are x = 0 and 0.25x - 8 = 0, which gives x = 32.

Therefore, none of the given equations represent the solutions of 0 = 0.25x² - 8x

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Answer:

The values of sine, cosine, and tangent of θ = 7 pi over 4 radians are -√2/2, √2/2 and -1.

The fraction of the original passengers remaining on the bus is 11/21.

A fraction is written in the form of p/q, where q ≠ 0.

Fractions are of two types they are proper fractions in which the numerator is smaller than the denominator and improper fractions where the numerator is greater than the denominator.

Given, A crowded bus makes several stops along a city street, with no passengers boarding the bus at any stop.

.At the 1st stop 1/3 of the passengers exit.

At the 2nd stop, 3/7 of the remaining passengers exit the bus.

Therefore, The fraction of the original passengers who remain on the bus is,

= [(1 - (1×1/3) - (1)×(1/3)×(3/7)].

= [ 1 - (1/3) - (3/21)].

= [ (2/3) - (3/21)].

= [(14 - 3)/21].

= 11/21.

So, 11/21 remains on the bus.

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3²×3^-5

Multiply the terms with the same base by adding their exponents

3²-5

Calculate the differences

3^-³

Express with a positive exponent using  a ^-n =1/n

                                                                             a

1/3³

Write the exponentiation as a multiplication

3×3×3

Multiply the numbers

27

Answer is 1/27

Answer:

8.96 g/cm3

Step-by-step explanation:

89.6 divided by 10 is 8.96

Answer:

f(2) = 0 and f(6) = -4

Step-by-step explanation:

First, find f(x) when x = 2

Plug in 2 as x in the function:

f(x) = -(x - 2)​

f(2) = -(2 - 2)

f(2) = -(0)

f(2) = 0

Next, find f(x) when x = 6. Plug in 6 as x in the function:

f(x) = -(x - 2)​

f(6) = -(6 - 2)

f(6) = -(4)

f(6) = -4

So, f(2) = 0 and f(6) = -4

The Domain depends on the value of n.

The Domain is all real numbers if n is ODD.

The Domain is all real numbers if n is EVEN.

Assuming that p(x) is a real-valued function, we can make the following statements about the domain of the function f(x) = n√(p(x)):

The domain of the function f(x) depends on the domain of the function p(x) since we cannot take the square root of a negative number. Therefore, the domain of f(x) is all real numbers x for which p(x) is non-negative (i.e., p(x) ≥ 0).

If n is odd, then the domain of f(x) is still all real numbers x for which p(x) is non-negative since the odd root of a negative number is negative, which is not allowed in the real numbers.

If n is even, then the domain of f(x) is all real numbers x since the even root of a negative number is allowed in the real numbers.

Therefore, the statement "The domain is all real numbers" is not true in general. It depends on the value of n and the domain of p(x).

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Answer:

About 11.025

Step-by-step explanation:

\(\sin{58^\circ}=\dfrac{x}{13}\\\\x=13\cdot\sin{58^\circ} \approx11.025\)

1. The quadratic function for the Area in terms of x: A(x) = 24x.

2. The cross-sectional area is maximized when the depth of the gutter is 0.

3. The maximum cross-sectional area is square inches 0.

To determine the depth of the gutter that maximizes its cross-sectional area and allows the greatest amount of water to flow, we need to follow a step-by-step process.

1. Write a quadratic function for the area in terms of x:

The cross-sectional area of the gutter can be represented as a rectangle with a width of 24 inches and a depth of x. Therefore, the area, A(x), is given by A(x) = 24x.

2. The cross-sectional area is maximized when the depth of the gutter is:

To find the value of x that maximizes the area, we need to find the vertex of the quadratic function. The vertex of a quadratic function in form f(x) = ax² + bx + c is given by x = -b/(2a). In our case, a = 0 (since there is no x² term), b = 24, and c = 0. Thus, the depth of the gutter that maximizes the area is x = -24/(2 * 0) = 0.

3. The maximum cross-sectional area is square inches:

Substituting the value of x = 0 into the quadratic function A(x) = 24x, we get A(0) = 24 * 0 = 0. Therefore, the maximum cross-sectional area is 0 square inches.

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The number of weeks that Vanessa ran for the number of miles given would be = 24 weeks

The amount of distance that Vanessa covers for a week = 4 miles

The amount of weeks it will take for her to cover 96 moles would be = ?

That is;

1 week = 4 miles

X weeks = 96 miles

Make X the subject of formula;

X = 96× 1/4

= 24 weeks

Therefore Vanessa will be able to cover 96 miles in only 24 weeks.

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The value of side EA is,

EA = 16.9

We have to given that;

Circle E with diameter CD and radius EA.

And, AB is tangent to E at A.

Here, AB = 34 and EB = 38

Hence, By using Pythagoras theorem we get;

AB² + AE² = EB²

34² + AE² = 38²

1156 + AE² = 1444

AE² = 1444 - 1156

AE² = 288

AE = √288

AE = 16.9

Thus, The value of side EA is,

EA = 16.9

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The difference of the algebraic expressions is 3x² - 11x + 4

An algebraic expression is an expression that is made up of variables and constants, along with algebraic operations like addition, subtraction, square root, etc.

The difference of two algebraic expressions means the subtraction of the expressions. That is:

(-4x+3) - (7x - 3x² - 1) = -4x+3 -7x+3x²+1

                                 =  3x² - 11x + 4

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Answer:

A

Step-by-step explanation:

From the information given:

To create the required stochastic matrix, we need to take parents who are shown to be vegetarian or nonvegetarian in the column and the children who are vegetarian or nonvegetarian into the row section.

So;

Vegetarian V → 70% →            nonvegetarian NV → 30%

nonvegetarian NV → 40%             vegetarian    V →  60%

                                                           V     NV

The 2x2 stochastic matrix  =     \(\left \Big { {{V} \atop {NV}} \right.} \left [\begin{array} {cc}0.7&0.4\\0.3&0.6\\\end{array}\right]\)

The best description of the car's motion as shown in the graph is: A. It travels for 1 hour, then stops for 1 hour, and finally travels again for 3 hours.

In a distance-time graph, an horizontal line implies no distance was covered within that time frame, meaning there was a stop.

Thus, in the graph given, the stop occurred 1 and 2, which is equivalent to an hour. From 2 to 5 on the x-axis means there was movement for up to 3 hours.

Therefore, the best description is: A. It travels for 1 hour, then stops for 1 hour, and finally travels again for 3 hours.

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Answer:

Step-by-step explanation:

We know that:

Work:

Hence, the value of x is 35°.

Hoped this helped.

\(BrainiacUer1357\)

\(\\ \tt\longmapsto x+40=75\)

\(\\ \tt\longmapsto x=75-40\)

\(\\ \tt\longmapsto x=35\)

Answer:

26275

Step-by-step explanation:

if simple interest its just .017*25000 which is 1 year then multiply by 3 and add to 25000

Find the tangent vector T to the given line (t) = 〈 x(t), y(t), z(t) 〉, with parametric equations,

x(t) = -1 + 3t

y(t) = 6 - 3t

z(t) = 3 + 7t

by differentiating (t) component-wise:

T = '(t) = 〈 dx(t)/dt, dy(t)/dt, dz(t)/dt 〉

T = 〈3, -3, 7〉

Scale T by any real number t to get the line through the origin (when t = 0) and the point (3, -3, 7) (when t = 1), which of course runs parallel to '(t). This gives the vector tT. Translate this by any vector v = 〈a, b, c〉 to force this line to pass through the point (a, b, c) instead of the origin, while still remaining parallel. You want the new line to pass through (0, 11, -9), so take v = 〈0, 11, -9〉.

Then the vector equation of the new line is

tT + v = t 〈3, -3, 7〉 + 〈0, 11, -9〉 = 〈3t, 11 - 3t, -9 + 7t〉

with parametric equations

x(t) = 3t

y(t) = 11 - 3t

z(t) = -9 + 7t

The length of WZ is 7.5 inches and the measurement of angle Y is 45 degrees for the similar shapes QRST and WXYZ.

Similar shapes are two or more shapes that have the same shape, but different sizes. In other words, they have the same angles, but their sides are proportional to each other. When two shapes are similar, one can be obtained from the other by uniformly scaling (enlarging or reducing) the shape.

If Lynn's quadrilateral WXYZ is a smaller shape of QRST, and they are similar, then:

the side QR corresponds to WX and QR corresponds to WX, so:

QR/WX = QT/WZ

2/5 = 3/WZ

WZ = (3 × 5)/2 {cross multiplication}

WZ = 15/2

WZ = 7.5

The angle RST corresponds to XYZ, so:

angle S = angle Y = 45°

Therefore, length of WZ is 7.5 inches and the measurement of angle Y is 45 degrees for the similar shapes QRST and WXYZ.

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Answer : it’s linear,

because it’s line, and exponential function is curved

hope this helped =)

This is a linear graph. To tell the difference between an exponential and linear graph is simple. Linear graphs have a straight line, exponential graphs do not and have a curve instead.

Here we have a polynomial of even degree with positive leading coefficient, so the end behavior is:

as x → ∞, f(x) → ∞

as x → -∞, f(x) → ∞

How is the end behavior of F(x)?

Here we have the function:

F(x) = 2x^4 - x^3 + 5x - 9

For any polynomial of even degree, we will have the same end behavior in both ends of the domain.

If the leading coefficient is positive, in both ends the function will tend to infinity.

If the leading coefficient is negative, in both ends the function will tend to negative infinity.

In the case of our function:

F(x) = 2*x^4 - x^3 + 5x - 9

We can see that the leading coefficient is 2, so it is positive, which means that the end behavior is:

as x → ∞, f(x) → ∞

as x → -∞, f(x) → ∞

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To find:

The type of transformation mapping P(x) to I(x).

Solution:

Here, the red line is the reflection of blue line over the x-axis.

Thus, the third option is correct.

The experimental probability that the next train to pull into Lakeside Station will be full is 7/10.

The experimental probability of the next train to pull into Lakeside Station being full can be calculated by dividing the number of times a full train occurred by the total number of trains observed.

Given that out of the last 20 trains, 14 were full, we can express the experimental probability as a fraction:

P(full) = Number of full trains / Total number of trains observed

P(full) = 14 / 20

Simplifying the fraction, we get:

P(full) = 7 / 10

Therefore, the experimental probability that the next train to pull into Lakeside Station will be full is 7/10.

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Answer:

513

Step-by-step explanation:

B×L=Area

Base=24

Length =19

24×19=513

Answer:

7

Step-by-step explanation:

7 is the mode because it occurs the most in the set of numbers.

a) The distance from point P to the pole  is: 6.2 m

b) The height of the Pole is: 6.2 m

The triangle attached shows us the triangle formed as a result of the given word problem about angle of elevation and distance and height.

Now, we are given that:

The angle of elevation of the top of the pole =  45°

Angle of elevation of the top of the pole = 58°.

|PQ|= 10m

a) PR is distance from point P to the pole and using trigonometric ratios, gives us:

PR/sin 58 = 10/sin(180 - 58 - 45)

PR/sin 58 = 10/sin 77

PR = (10 * sin 58)/sin 77

PR = 8.7 m

b) P O can be calculated with trigonometric ratios as:

P O = PR * cos 45

P O = 8.7 * 0.7071

P O = 6.2 m

Now, the two sides of the isosceles triangle formed are equal and as such:

R O = P O

Thus, height of pole R O = 6.2 m

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Answer:

594.1

Step-by-step explanation:

87÷15=5.1

672-83=589

so then you add those to together and get 594.1