the number of monthly purchases reported at a local bike store forms a bell-shaped distribution with a mean of 121 purchases and a standard deviation of 6.8 purchases. during a recent month, the bike store experienced 139 purchases. assuming the data possesses a bell-shaped distribution, does the 139 purchases fall within an interval which contains 95% of the number of monthly purchases? show the sigma rules and explain why or why not?

Answer: A

The problem says "to the right" which means you will be *SUBTRACTING 4 to x ( the x-axis is left and right )

"down" means you will be subtracting from y ( y-axis is up and down)

Option C shows x - 4 and subtracts 3.

MY DUM B A$.S WASNT THINKING ITS C

Answer:

C

Step-by-step explanation:

fuction y=3/x intersects the coordinate axes at points (3; 1) and (1; 3). These coordinates on request will put 4 units to the right and 3 units down and will now be (5; 0) (7; -2). Try all the alternatives and the correct alternative comes out C: Eg. substitute the coordinate (5: 0) for the function C and it will be 0 = (3 / 5-4) -3 => 0 = 0 (this is the required function; if we replace the other coordinate (7; -2) why both sides of the function are equal)

a. A club's profit is maximized when it produces the output where marginal revenue is equivalent to marginal cost. The inverse demand function can be represented as p = 100 + 2q which is same as q = 50 - 0.5p. The total revenue function is TR = pq. The marginal revenue is represented by the derivative of the total revenue with respect to the quantity q. The derivative is given by \(MR = ∂TR/∂q =\)

\(p + q∂p/\)

Given that the marginal cost of each round of golf is $20, the marginal cost of playing an extra round of golf will be constant. The marginal cost will be equal to marginal revenue for each additional round of golf that Sharon plays.MC = MR

=> $20

= p + q*(-2)

=> $20

= p - 2q.

Therefore, Sharon's demand function can be represented by p = 20 + 2q.

Substituting this demand function in TR = pq yields

TR = (20 + 2q)q

= 20q + 2q^2.

The derivative of TR with respect to q is MR = ∂TR/∂q

= 20 + 4q.

Setting the MR equal to MC yields MC = MR

=> $20

= 20 + 4q

=> q = 0.

Therefore, the club cannot maximize profits by selling a membership to Sharon for unlimited golf rounds. The club will need to have a membership fee of $10 or less.
b. The club's total revenue from two-part pricing will be TR = Pm + (MC - Pm)q, where Pm is the membership fee and MC is the marginal cost. From part (a) of the question, the club can maximize profit by setting a membership fee of $10. Therefore,

TR = $10 + $20q - $10q

= $10 + $10q.

By single-pricing, the club would sell q* rounds of golf at a price of $30 - 0.5q*. The club can equate the single-pricing with the two-part pricing to obtain the number of rounds where the profits will be the same.

$10 + $10q* = $30 - 0.5q*

=> q* = 16 rounds of golf.

The profit from two-part pricing is given by the membership fee plus the profit from the rounds of golf sold. The profit is Profit

= $10 + ($20 - $10)*16

= $170.

The profit from single-pricing is Profit = ($30 - 0.5*16)*16

= $192.

Therefore, the club could have made an extra profit of $22 by using single-pricing instead of two-part pricing. The club made more profit using single-pricing because the marginal cost of a round of golf is constant. Therefore, charging a fixed fee per round would have been the best pricing method for the club.

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Answer:

Step-by-step explanation:

You want two methods of choosing points on the line with slope 1/2 through A(-1, 2).

Writing the equation in standard form, we can find the x- and y-intercepts. To get there, we can start from point-slope form:

  y -k = m(x -h) . . . . . . line with slope m through point (h, k)

  y -2 = 1/2(x -(-1)) . . . . . using given slope and point

  2y -4 = x +1 . . . . . . . . . . multiply by 2

  x -2y =  -5 . . . . . . . . . . . . add -1 -2y

Setting x=0 tells us the y-intercept is ...

  0 -2y = -5

  y = -5/-2 = 5/2

So, the y-intercept is (0, 5/2).

Setting y=0 tells us the x-intercept is ...

  x -2(0) = -5

  x = -5

So, the x-intercept is (-5, 0).

It will be convenient to choose an arbitrary y-value to find another point on the line. We can pick y = 6, for example, Then the corresponding x-value is ...

  x -2y = -5

  x = -5 +2y = -5 +2(6) = 7

Another point on the line is (7, 6).

__

Additional comment

If we were to choose an arbitrary value for x, we would want it to be odd, so the corresponding y-value would be an integer. We chose to pick an arbitrary value of y so we didn't have to worry about how to make the x-value an integer.

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The  solution to this system of equations −4x+9y = 9 and x−3y = − 6 is,

(10, 5)

By using the substitution method, the solution to this system of equations −3x + 3y = 4  and −x + y = 3 is, No solution

The equation of a straight line is a relationship between x and y coordinates, The general equation of a straight line is y = mx + c, where m is the slope of the line and c is the y-intercept.

Given that,

System of equation,

−4x + 9y =   9

 4x − 4×3y = − 4×6   (multiplying equation by 4)

 0  - 3y   = -15

         y  =  5

−4x + 9×5 = 5

-4x  = -40

  x  =  10  

Second, system of equations

By substitution method,

−3x + 3y = 4

 −x  +  y  =   3      

Both the lines are parallel ,

so they will never intersect each other

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Step-by-step explanation:

It doesn't matter what order they are drawn in, so youi have a combination problem

26C5

My calculator gives the answer directly,

It is 65780

The Probability Density Function (PDF) for a uniform distribution ranging between 3 and 5 is 0.5. Answer is option C.

In a uniform distribution, the probability of a random variable taking any value between the two endpoints of the interval is constant. The probability density function (PDF) of a uniform distribution is a constant value over the range of possible values, and is 0 outside that range. In this case, the PDF for the uniform distribution ranging between 3 and 5 is 0.5, which means that the probability of the random variable taking any value between 3 and 5 is the same, and is equal to 0.5.

The PDF being a constant value of 0.5 implies that the distribution is symmetric, with equal probability of the random variable taking any value between the two endpoints. Thus, option C is answer.

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In the Olympic Volleyball event with 16 participating countries, there are a total of 6,240 different ways in which the Gold, Silver, and Bronze medals can be awarded.

To determine the number of different ways the medals can be awarded, we can use the concept of permutations. The Gold medal can be awarded to any one of the 16 countries, the Silver medal can be awarded to any one of the remaining 15 countries (since one country has already received the Gold), and the Bronze medal can be awarded to any one of the remaining 14 countries (as two countries have already received the Gold and Silver medals).

Therefore, the total number of different ways the medals can be awarded is given by the product of the number of choices for each medal: 16 choices for Gold, 15 choices for Silver, and 14 choices for Bronze. This can be calculated as:

16 x 15 x 14 = 3,360.

However, since the order of awarding the medals doesn't matter (e.g., awarding Gold to Country A and Silver to Country B is the same as awarding Gold to Country B and Silver to Country A), we need to consider the permutations of the medals as well. Since there are 3 medals, we divide the above result by 3! (3 factorial) to account for the different arrangements of the medals.

3! = 3 x 2 x 1 = 6.

So, the final number of different ways the medals can be awarded is:

3,360 / 6 = 6,240.

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Answer:

K

Step-by-step explanation:

techincally, I don't know if I am right, but there is more than one answer. The boundries/restrictions of what length DF could be are 2.477 < x < 8.477

it takes 2 years 1 month for Kevin to save enough with his high-deductible plan to pay for a possible $5,000 out-of-pocket expense

What is the solution to an equation?

In order to make the equation's equality true, the unknown variables must be given values as a solution. In other words, the definition of a solution is a value or set of values (one for each unknown) that, when used as a replacement for the unknowns, transforms the equation into equality.

Let x be the time it takes Kevin to save enough with

his high-deductible plan

200*x=5000

Divide both the sides by 100

2x=50

x=25 months = 2 years 1 month

it takes 2 years 1 month  for Kevin to save enough with his high-deductible plan to pay for a possible $5,000 out-of-pocket expense

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Answer:

n = 10

Step-by-step explanation:

20/4 = 50/n

20n = 50 x 4

20n = 200

n = 10

Hope that helps!

Answer:

V = π r^2 h = π · 10^2 · 15 ≈ 4712.38898

Step-by-step explanation:

Break it up into two trapezoids as shown

area = trap1 + trap2

      = 2 *   (7+3) / 2   + 3 *  ( 7 + 3) / 2 = 10 + 15 = 25 units^2

We can fit 25 notebooks on the space.

Now, According to the question:

The width of the notebook is 2/5

The length of the space is 10 inches.

To find the number of the notebooks can put there divide 30 by 2/3

Number of the books : \(\frac{10}{\frac{2}{5} }\) = 10 × \(\frac{5}{2}\)

=> 50/2 = 25

The number of the notebook is 25

We can fit 25 notebooks on the space.

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Some of the factors that can make a reunion unhappy or bittersweet are:

This refers to the situation where two or more people meet each other again after a long time of being apart.

We can note that sometimes, a reunion is happy, other times, it is bittersweet or unhappy as either some good thing or unfortunate event has occurred during the period spent apart from each other.

Please note that your question is incomplete so I gave you a general overview to help you get a better understanding of the concept.

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Answer: 12

Step-by-step explanation:

Convert fraction (ratio) 3 / 25 Answer: 12%

Answer:

Step-by-step explanation:

You will need to subtract the amount paid from the total amount

100 - 46.23

= 53.77

Ricardo will receive $53.77 in change. :)

Answer: x=1.8617                                                                                                                                                                

Step-by-step explanation: 9.4x+17.5                                                                     9.4x/9.4=17.5/9.4                                                                                                     x=1.8617                                                                                                                                                                  

The bijection could be defined from the set of numbers and it is proved.

We can define a bijection f from S to T as follows: for any integer x in S, let f(x) = x + 1.

To show that f is a bijection, we need to prove that it is both injective and surjective.

To prove that f is injective, suppose f(x) = f(y) for some x, y in S. Then x + 1 = y + 1, which means x = y. Thus, f is injective.

To prove that f is surjective, let y be an arbitrary element of T. Since y is odd, we can write y = 2n + 1 for some integer n. Now consider the element x = 3n in S. We have f(x) = x + 1 = 3n + 1 = y, so f is surjective.

Therefore, f is a bijection from S to T, so |S| = |T|.

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Infinitely many position vectors with length 2 in xyz-space are orthogonal to the nonzero position vector v. (D)

A position vector in xyz-space is a vector that starts at the origin and ends at a point in xyz-space. The length of a position vector is the distance from the origin to the point it ends at.

If we want to find position vectors with length 2 that are orthogonal (perpendicular) to a given nonzero position vector v, we can use the dot product.

Let w be a position vector with length 2 that is orthogonal to v. Then, the dot product of v and w must be zero, since they are orthogonal. That is, v · w = 0. Since the length of w is 2, we can write w as 2u for some unit vector u. Thus, v · w = v · (2u) = 2(v · u) = 0.

This means that v and u are orthogonal as well, since the dot product of two vectors is zero if and only if they are orthogonal.

There are infinitely many unit vectors u that are orthogonal to v, and therefore, there are infinitely many position vectors with length 2 that are orthogonal to v. Therefore, the answer is (d) infinitely many.

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Answer:

Step-by-step explanation:

Answer:

t>=45

Step-by-step explanation:

The perimeter of the regular hexagon is 42 inches.

Since a regular hexagon can be divided into six equilateral triangles, each triangle shares a side with the hexagon. Let's denote the perimeter of the hexagon as P.

Since the perimeter of one equilateral triangle is 21 inches, each side of the triangle has a length of 21/3 = 7 inches.

Since the hexagon consists of six equilateral triangles, it will have six sides, each of length 7 inches. Therefore, the perimeter of the hexagon is given by:

P = 6 * 7 = 42 inches.

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Answer:

m=2

Step-by-step explanation:

-16=m-18

-16+18=m

2=m

the optimal values of O, 6, and ik to maximize the lower bound are O = (Yk1*x1 + Yk2*x2)/(Yk1+Yk2), 6 = (Yk1*hatmu_k1 + Yk2*hatmu_k2)/(Yk1+Yk2), and ik = Yk1/(Yk1+Yk2), where Yk1 and Yk2 are the probabilities of y=k given x1 and x2  

The question is asking for the optimal values of O, 6, and ik to maximize the lower bound, given that p(y=k|x,60) is fixed. We are given two data points x1 and x2, and we define Yki as the probability of y=k given xi, for i=1,2.

To find the optimal O, we can use the formula for the lower bound and take the derivative with respect to O, then set it to zero and solve for O. This gives us O = (Yk1*x1 + Yk2*x2)/(Yk1+Yk2).

To find the optimal 6, we can similarly take the derivative of the lower bound with respect to 6, set it to zero, and solve for 6. This gives us 6 = (Yk1*hatmu_k1 + Yk2*hatmu_k2)/(Yk1+Yk2), where hatmu_k is the expected value of x given y=k.

Finally, to find the optimal ik, we can use the constraint that i1+i2=1 and the formula for the lower bound. We take the derivative of the lower bound with respect to ik, set it to zero, and solve for ik in terms of Yk1 and Yk2. This gives us ik = Yk1/(Yk1+Yk2).

Therefore, the optimal values of O, 6, and ik to maximize the lower bound are O = (Yk1*x1 + Yk2*x2)/(Yk1+Yk2), 6 = (Yk1*hatmu_k1 + Yk2*hatmu_k2)/(Yk1+Yk2), and ik = Yk1/(Yk1+Yk2), where Yk1 and Yk2 are the probabilities of y=k given x1 and x2, and hatmu_k1 and hatmu_k2 are the expected values of x given y=k for each data  point.

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Answer: y=1/5x+8

Step-by-step explanation:

Write the given equation in slope - intercept form:

-5y = -x+15

y = -(1/5)(-x+15)

y = (1/5)x -3.

The given slope is 1/5 and the required slope is -5.

Parallel lines have the same slope as the parent, the line goes through (-5,7) is y = mx+b with (x,y) = (-5,7) and m = 1/5.

7 = 1/5(-5) + b

-1+b=7

b=8

Therefore, the equation of the line is y=1/5x+8

Answer:

≠ and ≤ and <

Step-by-step explanation:

The probability that at least 290 seniors are actually enrolled in school is 0.96736.

The most significant probability distribution in statistics for independent, random variables is the normal distribution, sometimes referred to as the Gaussian distribution. In statistical reports, its well-known bell-shaped curve is generally recognized.

The majority of the observations are centered around the middle peak of the normal distribution, which is a continuous probability distribution that is symmetrical around its mean. The probabilities for values that are farther from the mean taper off equally in both directions. Extreme values in the distribution's two tails are likewise rare.

Given that the value of mean = 310 and the value of standard deviation is 10.85.

P(X ≥  290) = P (Z ≥ 290 - 310 / 10.85)

= 1 - P (Z < 290) = 1 - P(Z < 290 - 310 / 10.85)

= 1 - P(Z < -1.84)

= 1 - 0.032641

= 0.96736

Hence, the probability that at least 290 seniors are actually enrolled in school is 0.96736.

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To calculate the net sales, we need to subtract the discounts, sales returns and allowances, and freight in from the gross sales.

Therefore, we have:

Net sales = Gross sales - Discounts - Sales returns and allowances - Freight in

Substituting the given values, we get:

Net sales = $50,000 - $1,800 - $4,380 - $2,750 = $41,070

Therefore, the net sales of the company are $41,070. Answer: (d).

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