The number of electrons in a neutral atom of an element is always equal to the number of protons in that element. True or False

Answer:

S.G = 0.79.

Explanation:

Hello there!

In this case, according to the given information in the problem, it turns out possible for us to calculate the specific gravity of this alcohol by simply dividing its density, 0.79 g/mL by that of the water, 1 g/mL just as a reference for us to work with:

\(S.G=\frac{\rho _{alc}}{\rho _w}\)

Thus, we plug in the densities to obtain:

\(S.G=\frac{0.79g/mL}{1g/mL}\\\\S.G=0.79\)

Which is dimensionless as g/mL is cancelled out due to its presence on both top and bottom of the previous formula.

Regards!

Answer:

that is some above

Explanation:

because of the chemical reaction

For the acid-base reaction between cesium hydroxide and nitric acid, the given equations are as follows:

Acid-base reactions are reaction in which acids reacts with bases to form salt and water only.

Acid-base reactions are called neutralization reactions since the acid and base are both neutralized to a neutral substance, salt.

The equations in the acid-base reaction of Cesium hydroxide (aq) and nitric acid (aq) are described below:

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Answer:

depending on what you guys are doing someone could get hurt or knock something over and break it

Explanation:

Answer:

the amount of gravitational force between the object and Earth

Answer:

2, the gravitational force

Answer:

No

Explanation:A single property is insufficient for identifying a substance

Answer:

The fact that most alpha particles went straight through the foil is because the atom is mostly empty space.

Those that passed straight through did so because they didn't encounter any nuclei.

Explanation:

Answer:

2/ Protons and neutrons are found in the nucleus.

Explanation:

The molarity of the solution, which contains 58.5 g of NaCl dissolved in 0.25 L of solution, is approximately 4.004 M.

To calculate the molarity of a solution, we need to determine the number of moles of solute (NaCl) and then divide it by the volume of the solution in liters.

Given:

Mass of NaCl = 58.5 g

Volume of solution = 0.25 L

Step 1: Calculate the number of moles of NaCl.

To find the number of moles, we need to divide the mass of NaCl by its molar mass. The molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl).

Molar mass of NaCl = 22.99 g/mol (Na) + 35.45 g/mol (Cl) = 58.44 g/mol

Moles of NaCl = Mass of NaCl / Molar mass of NaCl

= 58.5 g / 58.44 g/mol

≈ 1.001 mol

Step 2: Calculate the molarity.

Molarity (M) is defined as moles of solute per liter of solution.

Molarity = Moles of solute / Volume of solution

= 1.001 mol / 0.25 L

≈ 4.004 M

Therefore, the molarity of the solution, which contains 58.5 g of NaCl dissolved in 0.25 L of solution, is approximately 4.004 M.

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Answer:

5.4 atm

Explanation:

P•V/T = P'•V'/T'

2.4•2.2/290 = P'•2/296

5.28/290 = P'/296 Multiply both sides by 296

1562.88/290 = P'

I'm = 5.4 atm

The volume of the gas in the tank at 293K and 3.0 atm pressure is 248 L. Hence, option B is correct.

Given:

T1 = 473K

T2 = 293K

P1 = 0.92 atm

P2 = 3.0 atm

The ideal gas law equation is:

PV = nRT

where P is pressure, V is volume, n is the number of moles of gas, R is the universal gas constant, and T is temperature.

n1 = (PV)/(RT)

= (0.92 atm × 500.0 L)/(0.0821 Latm/molK × 473K)

= 10.42 mol

Use the ideal gas law again to find the final volume of the gas in the tank under high pressure:

V2 = (n1 × R × T2)/P2

= (10.42 mol × 0.0821 Latm/molK × 293K)/(3.0 atm)

= 248 L

Therefore, the volume of the gas in the tank at 293K and 3.0 atm pressure is 248 L.

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Answer:

Using the ideal gas law, PV=nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature in Kelvin, we can solve for n:

n = PV/RT

We know that the initial volume is 500.0 L, pressure is 0.92 atm, and temperature is 473K. We can use this information to find the initial number of moles:

n1 = (0.92 atm x 500.0 L)/(0.08206 L atm/mol K x 473K) = 11.80 mol

Next, we can use the ideal gas law again to find the final volume. We know that the final pressure is 3.0 atm and the final temperature is 293K:

V2 = nRT2/P2

V2 = (11.80 mol x 0.08206 L atm/mol K x 293K)/3.0 atm = 95 L

Therefore, the volume of the gas at the lower temperature and higher pressure is approximately 95 L. Answer: 95 L.

Answer:

The density of water is 1 gram per cc, so 1 mole of water takes 18cc of volume. 1 cup is approximately 250ml (i.e. 250cc) - so 1 cup will contain approximately 13.89 moles of water, which will contain approximately 8.36 x 1024 molecules of water.

Explanation:

1 mole of water requires 18cc of volume due to the density of water, which is 1 gram per cc. Since a cup contains roughly 250ml of liquid, it will likely contain 13.89 moles of water, or 8.36 × 10²⁴ molecules.

The mass of a substance per unit of volume is its density. Density is most frequently represented by the symbol, however the Latin letter D may also be used. The formula for density is mass divided by volume:

Because it enables us to predict which compounds will float and which will sink in a liquid, density is a crucial notion. As long as an object's density is lower than the liquid's density, it will often float.

One of an object's most significant and practicable physical characteristics is density. Densities are frequently used to distinguish between pure materials, as well as to describe and infer the composition of various types of mixes.

Thus, 1 mole of water requires 18cc of volume due to the density of water, 8.36 × 10²⁴ molecules of water are in the cup.

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Answer:

Explanation:

Here, we want to calculate the mass that would dissolve

Mathematically:

The molar mass of carbon (iv) oxide is 44 g/mol

Thus, we have the number of moles as:

According to Henry's law:

Where;

C is the concentration of dissolved gas

K is the Henry's constant

P is the pressure

Now, from the question, we have:

k = 3.2 * 10^-2

P = 2.75

C is the number of moles per liter which we will represent by the number of moles

Thus, we have it that:

Answer:

Commercially, 2-methylpentenal is synthesized by the aldol condensation of propanal in the presence of liquid base like KOH or NaOH in stoichiometric amount,,. Under optimum reaction conditions, 99% conversion of propanal is achieved with 86% selectivity of 2-methylpentenal using liquid base.

Explanation:

hope this helps

Answer:

HMM, what the person above said.

Answer:

A. The reaction shifts to the right (products) and the concentrations of I and H₂ decrease.

Explanation:

If gas is removed from the system at equilibrium, the system will try to compensate for the loss by shifting the reaction in a direction that produces more gas molecules. This is known as Le Chatelier's principle, which states that a system at equilibrium will respond to a disturbance by shifting in a way that minimizes the effect of the disturbance.

In this case, since gas is being removed from the system, the reaction will shift to the side that produces more gas molecules. Looking at the balanced equation, we can see that 2HI(g) has a greater number of gas molecules compared to H₂(g) and I₂(g). Therefore, the system will shift to the right (products) to produce more HI(g) and reestablish equilibrium.

A) The chemical symbol for the ion is Fe+

B) It has 20 electrons in total, and there are 6 3p electrons in the ion.

C) There are 6 electrons present in the 3p orbital.

The atomic cation with the given electron configuration is represented by the chemical symbol Fe+.

To determine the number of electrons in the ion, we need to count the electrons present in the electron configuration. In the given configuration, we can see that the 1s orbital has 2 electrons, the 2s orbital has 2 electrons, the 2p orbital has 6 electrons, the 3s orbital has 2 electrons, the 3p orbital has 6 electrons, the 3d orbital has 1 electron, and the 4s orbital has 1 electron. Adding up these numbers, we have:

2 + 2 + 6 + 2 + 6 + 1 + 1 = 20

Therefore, the ion has 20 electrons.

To determine the number of 3p electrons in the ion, we look at the 3p orbital. In this case, there are 6 electrons present in the 3p orbital.

In summary, the chemical symbol for the ion is Fe+, it has 20 electrons in total, and there are 6 3p electrons in the ion.

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The birth weight of cats at the 90th percentile would be approximately 3.7 ounces. b. The birth weight of cats at the 10th percentile would be approximately 2.3 ounces.

There are three main methods of calculating weight:

1. Balance Beam Scale: A balance beam scale is an example of a mechanical weighing system. It uses a set of calibrated weights to measure the weight of an object.

2. Digital Scale: A digital scale uses an electronic or digital readout to display the weight of an object.

3. Calipers: Calipers are devices used to measure the distance between two points, such as thickness or diameter. They come in various sizes and shapes, depending on the type of measurement the user wants to take.

Birth weight is the weight of a baby at the time of birth. It is usually measured soon after delivery, with a special baby scale, though sometimes the baby's weight is estimated. The normal range of birth weight is anywhere between 5 lbs 8 oz and 10 lbs, though preterm or premature babies may be significantly lighter. A baby's birth weight is important because it can provide a clue to the baby's overall health. High birth weights may indicate an underlying medical condition, and low birth weights can be a sign of premature or difficult delivery and health risks associated with such a delivery.

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Answer:

Subbituminous coal can form at temperatures as low as 35 to 80 °C (95 to 176 °F) while anthracite requires a temperature of at least 180 to 245 °C (356 to 473 °F).

Sub-types: Cannel coal

Child material class: Lignite

Explanation:

Answer:

A small amount of chemical splashes in Frank's eye. What should happen next? Frank should go to the eyewash station while his lab partner tells the teacher what happened.

Explanation:

Brainlist

Let's write the chemical equation:

Using the mass of sodium (Na), we can calculate the number of moles of sodium:

2 mol of Na produces 1 mol of hydrogen gas (2 moles because hydrogen gas contains 2 moles).

We can calculate the number of hydrogen moles required like this:

Now, to calculate the mass of hydrogen, we're going to use the molar weight, like this:

So, hydrogen will be 5.217 g produced by 120 g of sodium.

Answer: A

Explanation:

Oxidation is the process through which electrons are gained. This indicates that only organisms on the electron side have the potential to be oxidizing agents. c, d, and e are, by definition, eliminated.

We also know that H+ is in the +1 oxidation state. The same is true for 'H' in H2O... it doesn't change oxidation states

Therefore, the answer must be a) nitrate

Answer:

Lower density than water

The answer to the question “Why does oil float on water?” is that oil floats on water because of its lower density than water. Oil and water molecules do not mix with each other due to the polarity of water molecules and the non-polarity of oil molecules. The volumetric mass of a liquid, expressed in cubic meters, is its density.

Isoleucine is an amino acid that has the following structure at a pH of 1:

What is isoleucine?

Isoleucine is an essential amino acid, which means that the human body cannot produce it and it must be obtained through diet. Isoleucine is one of the 20 standard amino acids that are commonly found in proteins. It has a specific chemical structure of H3N-C(CH3)3-COOH. Isoleucine has an aliphatic side chain with a branched carbon skeleton.

H3N-C(CH3)3-COOH

At a pH of 1, isoleucine is in its acidic form, with a carboxyl group (-COOH) that is ionized and carries a negative charge. This ionization occurs when a hydrogen ion (H+) is removed from the carboxyl group, making it -COO-.

At a pH of 13, isoleucine is in its basic form, with a carboxyl group (-COOH) that is fully ionized and carries a negative charge. This ionization occurs when a hydrogen ion (H+) is removed from the carboxyl group, making it -COO-.

To show the structure of isoleucine at a pH of 1:

H3N-C(CH3)3-COO-

To show the structure of isoleucine at a pH of 13:

H3N-C(CH3)3-COO-

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Answer:

strong and rigid

Explanation:

The crystal structure of ionic compounds is strong and rigid. It takes a lot of energy to break all those ionic bonds. As a result, ionic compounds are solids with high melting and boiling points. You can see the melting and boiling points of several different ionic compounds in the Table below

Answer:

3.25 mol CO₂

Explanation:

Step 1: Write the balanced equation

C(s) + O₂(g) ⇒ CO₂(g)

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of O₂ to CO₂ is 1:1.

Step 3: Calculate the number of moles of CO₂ produced from 3.25 moles of O₂

We will use the previously established molar ratio.

3.25 mol O₂ × 1 mol CO₂/ 1 mol O₂ = 3.25 mol CO₂

Taking into account the definition of molarity, the number of moles of MgCl₂ present in 60.0 mL of 0.100 M MgCl₂ solution is 0.006 moles.

Molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by:

molarity= number of moles of solute÷ volume

Molarity is expressed in units moles/L.

In this case, you have:

Replacing in the definition of molarity:

0.100 M=number of moles of MgCl₂÷ 0.06 L

Solving:

0.100 M × 0.06 L= number of moles of MgCl₂

0.006 moles= number of moles of MgCl₂

Finally, the number of moles of MgCl₂ is 0.006 moles.

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At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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