Following the putty's adhesion to a ball, both are propelled forward by the combined momentum of two units.
What is meant by momentum in physics?Momentum was defined as the amount the the body's motion. As momentum depends on both velocity and the direction of a body's motion, it is quantified by "mass velocity". Since velocity is indeed a vector and mass is a scalar, momentum is a vector. Mass times speed equals momentum.
What is momentum in real life?Quantity may be assessed in the this scenario since a moving item has mass and momentum. If such an object is stationary, it has no momentum.
Briefing:The system's momentum is conserved in this instance of an inelastic collision.
Here, the principle of momentum conservation will be applied.
As either a result, following a collision, the combined momentum will equal the initial momentum. The answer "2 units" is the one that is right.
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A jet plane is speeding down the runway during takeoff. Air resistance is not negligible, friction is negligible. Identify the forces on the jet.
Jet aircraft naturally accelerate quickly during takeoff. There is barely any air resistance. Weight, drag, thrust, and normal force are the forces that the jet plane is subject to.
How does flight impact Newton's law?Issac Newton discovered that every action has a corresponding and diametrically opposed reaction. While an engine pushes air backward, for instance, the airplane will move forward with a similar but opposing force. In order for the plane to fly in the opposite direction, each engine expels air in one direction. Thrust is the name for this reactive force.
Is the conservation of linear momentum the basis for jet aircraft?Jet aircraft operate under the conservation of momentum principle, which states that if the system's starting momentum was zero, therefore the system's final momentum must also be zero. Hence, the recoil of the fuel gasses ejected in the backward direction causes the jet to proceed in the forward direction.
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Calculate the number of moles of water molecules in 12 cubic decimate of water vapour at STP
There are 0.0568 moles of water molecules in 12 cubic decimetre of water vapour at STP.
The given quantities are as follows; Volume of water vapour at STP = 12 cubic decimetre, Temperature of water vapour at STP = 273 K, Pressure of water vapour at STP = 1 atm
1. Firstly, we need to convert the given volume to liters.
1 decimetre = 0.1 meters
1 cubic decimetre = 0.1 x 0.1 x 0.1 cubic meters = 0.001 cubic meters
1 cubic meter = 1000 liters
1 cubic decimetre = 0.001 x 1000 liters = 1 liter
Therefore, the volume of water vapour at STP is 12 liters.
2. Next, we use the ideal gas law:
PV = nRT
where P = pressure, V = volume, n = number of moles, R = ideal gas constant, and T = temperature.
We can rearrange this equation to solve for n:
n = PV/RT
We need to convert the pressure to Pascals, volume to cubic meters, and temperature to Kelvin.
1 atm = 101325 Pa
12 liters = 0.012 cubic meters
273 K = 0 °C + 273 = 546 R
Now, we can plug in these values:
n = (101325 Pa)(0.012 m³)/(8.314 J/mol·K)(546 K)
n = 0.0568 mol
Therefore, the number of water molecules are 0.0568 moles.
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A machine has a velocity ratio of 6 and an efficiency of 75%.calculate the effort needed to raise a load of 90n
The effort needed to raise a load of 90N is 20N.
The effort needed to raise a load of 90N can be calculated using the formula:
Effort = Load / (Velocity Ratio x Efficiency)
Given that the velocity ratio is 6 and the efficiency is 75%, we can substitute these values into the formula:
Effort = 90N / (6 x 0.75)
To simplify the calculation, let's first calculate the product of the velocity ratio and efficiency:
6 x 0.75 = 4.5
Now, we can substitute this value back into the formula:
Effort = 90N / 4.5
Simplifying this further:
Effort = 20N
Therefore, the effort needed to raise a load of 90N is 20N.
In conclusion, the effort needed to raise a load of 90N is 20N.
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in the equation for the gravitational force between two objects which quantity must be squared?
Answer:
Distance
Explanation:
trust me
Answer:
The distance "r" must be squared
Explanation:
In the equation F=GMm/r^2, the distance "r" is squared, which represents the distance between masses M and m and G is the gravitational constant.
What areas of the world would a tidal-power-generating facility be viable? World wide, all coastal cities, lake towns, coastal cities with large tidal range
Answer:
Coastal cities with large tidal range
Explanation:
Tidal-power energy generatgeneration, is a form of renewable energy source of power generation, that makes use of ocean tides and currents kinetic energy to power electricity generating turnines, and paddles connected to an electricity generator, to produce electricity
Therefore, a tidal-generating-facility would be viable in coastal cities with large tidal range
Answer:
Coastal cities with large tidal range
Explanation:
Calculate how much energy (Q) in Joules in needed to raise 125 g of aluminum from 25.0'C to 100.0'C.
the Specific Heat (C) of Aluminum = 0.90 J/g"C Q = mcΔT MUST SHOW WORK
Answer:
Below
Explanation:
125 g * (100-25 C) * .90 J / (g °C) =8437.5 J
A hockey puck with mass 170 g is attached to a rope of length 65.0 cm and swung in a horizontal circle against the ice at a rate of 53.0 rpm. Assuming the ice is frictionless, what is the tension in the rope?
This question involves the concepts of tension force and centripetal force.
The tension force in the rope is "3.4 N".
In this scenario, the centripetal force shall be acting as the tension force of the rope. Because in order for the puck to move in a circular path, the tension force in the rope must be equal to the centripetal force.
\(Tension\ Force = Centripetal\ Force\\F = \frac{mv^2}{r}\)
where,
F = tension force = ?
m = mass of puck = 170 g = 0.17 kg
r = radius of path = length of rope = 65 cm = 0.65 m
v = linear speed of puck = r(angular speed) = (0.65 m)(53 rpm)\((\frac{2\pi\ rad}{1\ rev})(\frac{1\ min}{60\ s})\)
v = 3.61 m/s
Therefore,
\(F = \frac{(0.17\ kg)(3.61\ m/s)^2}{0.65\ m}\)
F = 3.4 N
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The attached picture shows the centripetal force.
Can you help me on this please
Answer: the water level would rise since the pebble displaces minimal water compared to the boat.
Explanation:..........
A 70.0kg person walks from the ground to the roof of a 25.3 m tall building. How much gravitional Potential Energy does she have at the top of the building.
A-17,394.4
B/18,865.8 J
C-17,355.8 J
D-12,873.2 J
Answer:
i would say C
Explanation:
if im right can i get the crown?
Three balls are thrown off a cliff with the same speed, but in different directions. Which ball has the greatest speed just before it hits the ground?.
The relationship between the speed and height of the three balls is that; each ball will have the same speed.
What is the relationship between speed and height?
We are given that;
Three balls are thrown from a cliff with same speed
Ball A is thrown in the horizontal direction.
Ball B starts out at 45° above the horizontal.
Ball C begins its flight at 45° below the horizontal
From law of conservation of energy, we know that potential energy is equal to kinetic energy. Thus;
mgh = ¹/₂mv²
v = √2gh
Therefore, the speed is directly proportional to the height and as such since the three balls have the same height, their speeds will be the same.
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[NOTE : THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS:
Three balls are thrown off a cliff with the same speed but in different directions. Ball A is thrown in the horizontal direction; ball B starts out at 45° above the horizontal; ball C begins its flight at 45° below the horizontal. Which ball has the greatest speed just before it hits the ground? Assume that the ground near the building is level, and ignore any effects due to air resistance.]
- Find the Ideal Mechanical Advantage of an inclined plane wit length of 16 feet and a height of 4 feet
The ideal mechanical advantage (IMA) of an inclined plane with a length of 16 feet and a height of 4 feet is 4:1.
An inclined plane allows us to exert a smaller force over a longer distance, making it easier to move objects along the slope. The IMA is determined by dividing the length of the inclined plane by its vertical height. In this case, the length is 16 feet and the height is 4 feet, resulting in an IMA of 4. This means that for every 1 unit of vertical height, the object will move a distance of 4 units along the inclined plane. It demonstrates the mechanical advantage gained by utilizing the inclined plane to reduce the effort required to move objects. However, factors like friction can reduce the actual mechanical advantage in practical situations.
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Planet
P
Note: Figure not drawn to scale.
In the figure above, a spaceship (not shown) from point P is traveling along the dashed
line towards the planet. The net gravitational force at point P is 4.0 x 1010 N. Assume that
any motion of the planet is negligible.
If the spaceship stops halfway between the planet and point P, what happens to the magnitude of the net gravitational force exerted on the spaceship by the planet?
o The net gravitational force stays constant.
o The net gravitational force is half as great.
o The net gravitational force is twice as great.
The net gravitational force is four times as great
If the spaceship stops halfway between the planet and point P, the net gravitational force is four times as great.
Gravitational force between two objects
The gravitational force between two objects is determined from Newton's second law of universal gravitation.
F = GmM/R²
where;
R is the distance between the spaceship and the planet.when the distance halved
F = GmM/(0.5R)²
F = GmM/(0.25R²)
F = 100GmM(25R²)
F = 4GmM/R²
Fnet = 4F
Thus, if the spaceship stops halfway between the planet and point P, the net gravitational force is four times as great.
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With an increased walking speed in water, the weight-bearing percentages of the lower extremities __________. Question 11 options: decreases increases change only in persons who weigh over 200 lb none are true
As the speed in water increases, the percentage of the lower extremities to bear weight increases.
Archimedes PrincipleAccording to the Archimedes principle, when a substance is fully or partly immersed in a liquid, it experiences an upthrust that is equal to its weight. This is the reason why an object weighs less in a fluid than in air.
As such, with With an increased walking speed in water, the weight-bearing percentages of the lower extremities increase.
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The period of a pendulum of length 0.500 m is
14.2 s
7.02 s
1.42 s
0.702 s
0.450 s
Answer:
C. 1.42 s
Explanation:
Givens:
length = 0.5m
gravity = 9.807 m/s
Solve:
T = 2π√(L/g)
T = 2π√(0.5/9.807)
T = 2π√(0.0509)
T = 2π * 0.22579
T = 6.28318 * 0.22579
T = 1.418 ≈ 1.42s
aluminum allows for the flow of electrons, while glass does not. would an aluminum wire surrounded by glass be an effective design for a device that will need to carry an electric current?
No, an aluminum wire surrounded by glass would not be an effective design for a device that needs to carry an electric current since glass is an insulator, meaning it does not allow the flow of electrons.
In order for a device to effectively carry an electric current, it requires a continuous path for the flow of electrons. Aluminum is a metal that is commonly used as a conductor in electrical applications because it has a high electrical conductivity. It allows electrons to move freely through its structure, facilitating the flow of current.
On the other hand, glass is an insulating material that does not conduct electricity. It has a high resistance to the flow of electrons and is used to isolate and protect electrical components from coming into contact with conductive materials. If an aluminum wire is surrounded by glass, the glass acts as a barrier, blocking the flow of electrons from the aluminum wire. This interruption in the current path would prevent the device from effectively carrying an electric current.
To ensure the device can carry an electric current, it would be necessary to use a material that allows the flow of electrons throughout the entire path. For example, a more suitable design might involve using an aluminum wire surrounded by another conducting material, such as a plastic or rubber coating. This would provide insulation while still allowing the current to flow through the conductor.
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Can aurora be found in other planets?
Answer:
Yes
Explanation:
Any planet with a sufficiently dense atmosphere that lies in the path of the solar wind will have aurora. It has been discoveres in planets like Jupiter, Saturn, etc.
Answer:
yes
Explanation:
TRUE / FALSE. which of the following are equivalent to 652 mmhg? select all that apply.
None of the given options (a, b, c) are equivalent to 652 mmHg.
To determine which of the following options are equivalent to 652 mmHg, we need to compare them and check if they represent the same pressure value. Here are the options:
a) 871 Pa
b) 0.881 atm
c) 17.89 psi
To determine if any of these options are equivalent to 652 mmHg, we can use the following conversion factors:
1 atm = 760 mmHg
1 psi = 51.71 mmHg
1 Pa = 0.0075 mmHg
Now, let's check each option:
a) 871 Pa:
To convert mmHg to Pa, we can use the conversion factor of 1 Pa = 0.0075 mmHg.
652 mmHg × 0.0075 Pa/mmHg ≈ 4.89 Pa
The value of 871 Pa is not equivalent to 652 mmHg, so this option is not correct.
b) 0.881 atm:
To convert mmHg to atm, we can use the conversion factor of 1 atm = 760 mmHg.
652 mmHg ÷ 760 mmHg/atm ≈ 0.858 atm
The value of 0.881 atm is not equivalent to 652 mmHg, so this option is not correct.
c) 17.89 psi:
To convert mmHg to psi, we can use the conversion factor of 1 psi = 51.71 mmHg.
652 mmHg ÷ 51.71 mmHg/psi ≈ 12.61 psi
The value of 17.89 psi is not equivalent to 652 mmHg, so this option is not correct.
In conclusion, none of the given options (a, b, c) are equivalent to 652 mmHg.
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all materials that enter or leave the cell must pass across the
All materials that enter or leave the cell must pass across the cell membrane. The cell membrane is a selectively permeable barrier that regulates the movement of substances in and out of the cell.
The cell membrane consists of a phospholipid bilayer embedded with various proteins and other molecules. It controls the passage of molecules and ions by different mechanisms:
Passive Diffusion: Small, non-polar molecules such as oxygen and carbon dioxide can passively diffuse across the cell membrane. This occurs due to the concentration gradient, where substances move from an area of higher concentration to an area of lower concentration.
Facilitated Diffusion: Larger or charged molecules, such as glucose or ions, require the assistance of specific membrane proteins called transporters or channels to move across the cell membrane. Facilitated diffusion also occurs along the concentration gradient but relies on protein-mediated transport.
Active Transport: Some molecules need to move against the concentration gradient, from an area of lower concentration to an area of higher concentration. Active transport involves the use of energy (ATP) and specific carrier proteins to pump molecules across the membrane, allowing the cell to accumulate substances or maintain concentration gradients.
Endocytosis and Exocytosis: Large molecules, such as proteins or cellular waste, can be transported across the cell membrane through processes called endocytosis and exocytosis. Endocytosis involves the cell engulfing substances by forming vesicles from the cell membrane, while exocytosis releases substances by fusing vesicles with the cell membrane.
Overall, the cell membrane plays a crucial role in maintaining the internal environment of the cell by selectively allowing the passage of specific molecules while preventing the entry or exit of others. This regulation ensures proper functioning and survival of the cell.
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uppose you are an astronaut and you have been stationed on a distant planet. You would like to find the acceleration due to the gravitational force on this planet so you devise an experiment. You throw a rock up in the air with an initial velocity of 6 m/s and use a stopwatch to record the time it takes to hit the ground. If it takes 6.8 s for the rock to return to the same location from which it was released, what is the acceleration due to gravity on the planet
Answer:
g = -3.143 m/s²
Explanation:
To determine acceleration due to the gravitational force, it can be used the following formula:
v = v₀ + gt, where:
v₀ is the initial velocity;
g is acceleration due to gravity
t is the time to return to the point of origin
A force of 9 N is applied to an object. The moment arm for the force is 0. 21 m. What is the torque produced by the force?
The work done on the object by the applied force is 1500 J, and the power developed is 8000 W.
The torque produced by the force can be determined by multiplying the force by the moment arm. This can be represented using the formula:Torque = Force × Moment armGiven that a force of 9 N is applied to an object with a moment arm of 0.21 m, the torque produced by the force can be calculated as follows:Torque = 9 N × 0.21 m= 1.89 N·mTherefore, the torque produced by the force is 1.89 N·m.Answer in 200 words.Torque is the tendency of a force to rotate an object around an axis or pivot. The torque produced by a force is proportional to the force applied and the moment arm.The moment arm is the shortest distance between the line of action of the force and the axis of rotation. It is the perpendicular distance from the axis of rotation to the line of action of the force. The moment arm is an important factor in determining the torque produced by a force.A torque of 1 N·m is produced when a force of 1 N is applied perpendicular to a moment arm of 1 m. This is known as the moment of force or the turning effect of a force.The torque produced by a force is measured in newton-metres (N·m) in the SI system of units. In order to calculate the torque produced by a force, the magnitude of the force and the moment arm need to be known.The formula for calculating the torque produced by a force is:Torque = Force × Moment armWhere torque is measured in N·m, force is measured in newtons (N), and moment arm is measured in metres (m).
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What voltage is needed to cause a 50A current flow through a 1022 resistor?
The voltage across the conductor is 500V.
What is Ohm's law ?Ohm's law states that the current through a conductor is directly proportional to the voltage across the conductor.
Here,
Current in the conductor, I = 50A
Resistance of the conductor, R = 10 Ω
According to Ohm's law,
V α I
V = IR
V = 50 x 10
V = 500 V
Hence,
The voltage across the conductor is 500V.
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A Sledding Contest. You are in a sledding contest where you start at a height of 50.0 m above the bottom of a valley and slide down a hill that makes an angle of 25.0
∘
with respect to the horizontal. When you reach the valley, you immediately climb a second hill that makes an angle of 15.0
∘
with respect to the horizontal. The winner of the contest will be the contestant who travels the greatest distance up the second hill. You must now choose between using your flat-bottomed plastic sled, or your "Blade Runner," which glides on two steel rails. The hill you will ride down is covered with loose snow. However, the hill you will climb on the other side is a popular sledding hill, and is packed hard and is slick. The two sleds perform very differently on the two surfaces, the plastic one performing better on loose snow, and the Blade Runner doing better on hard-packed snow or ice. The performances of each sled can be quantified in terms of their respective coefficients of kinetic friction on the two surfaces. For the plastic sled: μ= 0.17 on loose snow and μ=0.15 on packed snow or ice. For the Blade Runner, μ=0.19 on loose snow and μ=0.09 on packed snow or ice. Assuming the two hills are shaped like inclined planes, and neglecting air resistance, (a) how far does each sled make it up the second hill before stopping? (b) Assuming the total mass of the sled plus rider is 55.0 kg in both cases, how much work is done by nonconservative forces (over the total trip) in each case? (b) For the flat-bottomed plastic sled: Number Units For the "Blade Runner" sled: Number Units
The work done by nonconservative forces (over the total trip) for the flat-bottomed plastic sled is 1403.43 J and for the "Blade Runner" sled is 1707.57 J.
(a) Distance traveled by each sled up the hill before stopping is given below:
Plastic Sled: The force of gravity, frictional force, and the normal force acting on the sled can be resolved into components parallel and perpendicular to the slope. Here, the force of gravity (mg) acts straight down the slope and can be resolved into two components.
One component (mg sin 25°) is parallel to the slope and the other component (mg cos 25°) is perpendicular to the slope. The normal force (N) acting on the sled is perpendicular to the slope, and it can be resolved into two components. One component (N sin 25°) is parallel to the slope and the other component (N cos 25°) is perpendicular to the slope.
Frictional force (f) acting on the sled is given by:
f = μN From the diagram, it is observed that sin 25° = (50 - d)/x, where d is the horizontal distance traveled by the sled down the slope (i.e., the distance between the start and end points), and x is the length of the slope, which is given by x = 50/sin 25°
= 116.26 m.
Therefore, d = x sin 25°
= 50.15 m.
Similarly, cos 25° = h/x, where h is the vertical drop of the slope.
Therefore, h = x cos 25°
= 107.69 m.
Using the work-energy principle (neglecting air resistance), we can write:
mgh = Wf + 0.5mv2
where m is the total mass of the sled and rider, v is the speed of the sled at the end of the slope, and Wf is the work done by the frictional force (f) over the distance traveled by the sled.
Therefore, we can write:
Wf = f × d The kinetic energy of the sled at the bottom of the slope is given by:
KE = 0.5mv2
where v is the speed of the sled at the bottom of the slope.
Therefore, we can write:
v2 = 2gh - (2f/m) × d
Using the value of g = 9.81 m/s2 and the given values of μ, we can find the value of f for loose snow:
f = μN
= μmg cos 25°
Therefore, f = 0.17 × 55 × 9.81 × cos 25
° = 88.64 N
And the value of f for packed snow or ice:
f = μN
= μmg cos 15°
Therefore, f = 0.15 × 55 × 9.81 × cos 15°
= 80.28 N
Substituting these values, we can find the speed of the sled at the end of the slope for loose snow:
v2 = 2gh - (2f/m) × dv2
= 2 × 9.81 × 107.69 - (2 × 88.64/55) × 50.15
Therefore, v = 20.89 m/s
And for packed snow or ice:
v2 = 2gh - (2f/m) × dv2 = 2 × 9.81 × 107.69 - (2 × 80.28/55) × 50.15
Therefore, v = 20.94 m/s
Using the value of the speed of the sled at the end of the slope and the work-energy principle, we can find the distance traveled by each sled up the hill before stopping. For the plastic sled:
KE = 0.5mv2
KE = 0.5 × 55 × 20.89²
KE = 12744.57 J
Since the sled is starting from rest, the initial kinetic energy is zero, and we can write: Wf + mgh = KE
Therefore, the work done by the nonconservative forces (frictional force) over the total trip is given by:
Wf = KE - mgh
Wf = 12744.57 - (55 × 9.81 × 50)Wf = 1403.43 J
Using the work-energy principle again, we can find the distance traveled by the sled up the hill before stopping:
KE = 0.5mv2
where v is the speed of the sled at the end of the slope. Therefore, we can write:v2 = 2gh - (2f/m) × dv2 = 2 × 9.81 × h - (2 × 88.64/55) × 50.15Therefore,h = 49.91 m
Therefore, the distance traveled by the plastic sled up the hill before stopping is 50.0 - 49.91 = 0.09 m.
For the Blade Runner:Using the value of the speed of the sled at the end of the slope and the work-energy principle, we can find the distance traveled by each sled up the hill before stopping.KE = 0.5mv2KE = 0.5 × 55 × 20.94²KE = 13048.17 J
Since the sled is starting from rest, the initial kinetic energy is zero, and we can write:
Wf + mgh = KE
Therefore, the work done by the nonconservative forces (frictional force) over the total trip is given by:
Wf = KE - mgh
Wf = 13048.17 - (55 × 9.81 × 50
)Wf = 1707.57 J
Using the work-energy principle again, we can find the distance traveled by the sled up the hill before stopping:
KE = 0.5mv2
where v is the speed of the sled at the end of the slope. Therefore, we can write:v2 = 2gh - (2f/m) × dv2 = 2 × 9.81 × h - (2 × 80.28/55) × 50.15Therefore,h = 62.45 m
Therefore, the distance traveled by the Blade Runner up the hill before stopping is 50.0 + 62.45 = 112.45 m.
(b)The work done by nonconservative forces (frictional force) over the total trip is given above:
For the plastic sled:
Wf = 1403.43 J
For the Blade Runner:
Wf = 1707.57 J
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number 8 please i will give you so many points
(8a) The work done on the block is 2,000 J.
(8b) The energy converted into thermal energy is 1,000 J.
What is the work done on the block?The work done on the block is calculated by applying the following formula.
W = F x d
where;
F is the applied forced is the displacement of the blockW = 200 N x 10 m
W = 2,000 J
The energy converted into thermal energy is equal o work done by friction force.
W = 100 N x 10 m
W = 1,000 J
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If you stood on Mars and lifted a 15kg pack,you would be pulling with a force greater than...
Answer: See answers below.
Explanation: In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.
We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.
where:
W = weight [N] (units of Newtons)
m = mass = 15 [kg]
g = gravity acceleration [m/s²]
Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.
Mercury
Venus
Moon
Mars
Jupiter
Saturn
Uranus
Neptune
Pluto
In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.
We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.
where:
W = weight [N] (units of Newtons)
m = mass = 15 [kg]
g = gravity acceleration [m/s²]
Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.
Mercury
Venus
Moon
Mars
Jupiter
Saturn
Uranus
Neptune
Pluto
Question at position 3
The table shows mass and weight data of some common items.
Based on the data, which conclusion is valid regarding the relationship between the force of gravity, mass, and weight?
The table shows mass and weight data of some common items.
Based on the data, which conclusion is valid regarding the relationship between the force of gravity, mass, and weight?
The weight of an object depends on the force of gravity of the planet, but the mass does not.
Neither the mass nor the weight of an object depends on the force of gravity.
The mass of an object depends on the force of gravity of the planet, but the weight does not.
Both the mass and the weight of an object depend on the force of gravity.
An increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass. It depends on the object's mass and acceleration due to gravity.
Mass is an intrinsic unchanging property. Weight is a force and it depends on gravitational force. This force is directly proportional to mass the more mass the object has the stronger the force of gravity will be. Because of this, it turns out that gravity does not matter when we compare the distance traveled by objects with different masses. The important part of the force is air resistance also called drag.
The slope of the graph is the relationship between weight and mass. The slope tells how many newtons of weight pull down on each kilogram of mass. Mass is the measure of the amount of matter in an object. This is an immutable property inherent in the body. Mass cannot be destroyed or created. Weight is the production of mass and acceleration due to gravity.
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2. A block of mass 1.2 kg lies on a frictionless surface. A man slides the block
against a spring, compressing it .15m. When the man lets go of the spring, the
block moves at 5 m/s. What is the spring constant of the spring?
mm
.
Answer:
The spring constant will be "1333.33 N/m".
Explanation:
The given values are:
Mass,
m = 1.2 kg
Displacement compression,
x = 0.15 m
Block's velocity,
\(v_i=5 \ m/s\)
As we know,
⇒ \(E_i=E_f\)
or,
⇒ \(K_i+v_i=K_f+v_f\)
⇒ \(\frac{1}{2}mv_i^2+0=0+ \frac{1}{2}Kx^2\)
So,
⇒ \(K=\frac{mv_i^2}{x_2}\)
On substituting the values, we get
⇒ \(=\frac{1.2\times 5\times 5}{0.15\times 0.15}\)
⇒ \(=\frac{30}{0.0225}\)
⇒ \(=1333.33 \ N/m\)
how many strings of eight english letters are there that contain no vowels, if letters can be repeated?
There are 20,971,520 strings of eight English letters that contain no vowels when letters can be repeated.To calculate the number of strings of eight English letters that contain no vowels.
we need to consider the total number of possible choices for each letter position.
In the English alphabet, there are 26 letters, including five vowels (A, E, I, O, U) and 21 consonants.
Since we want to create strings without vowels, we can choose any of the 21 consonants for each position in the string.
For each of the eight positions in the string, there are 21 choices (consonants) available.
Therefore, the total number of strings can be calculated as:
Total number of strings = Number of choices for each position ^ Number of positions
Total number of strings = 21^8 = 20,971,520
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A duck is 12 m from the edge of a pond. A student stands in the middle of the pond
and creates ripples that travel past the duck and towards the edge of the pond. The
ripples are produced uniformly at 2 ripples per second. The student determines that
the ripples take 3.0 seconds after they pass the duck to reach the edge of the pond.
Determine the wavelength of the ripples.
Answer:
The wavelength is 2 meters
Explanation:
The relationship between the frequency, the speed and the wavelength is given by the relation;
v = f × λ
The given parameters are;
The distance of the duck from the edge of the pond = 12 m
The number of ripples produced per second = Frequency, f = 2 Hz
The time it takes the ripple to reach the edge of the pond after travelling past the duck = 3 seconds
Therefore, speed of the wave, v = Distance/time = 12 m/(3 s) = 4 m/s
The wavelength, λ, is therefore;
λ = v/f = (4 m/s)/(2 Hz) = 2 meters.
a wire 2.0 m long is suspended parallel to a uniform magnetic field of 0.50 t. if the current in the wire is 0.60 a, what is the magnetic force in n on the wire?
The magnetic force on the wire is 0.60 N.
The magnetic force on the wire can be calculated using the formula F = BIL, where F is the magnetic force, B is the magnetic field, I is the current and L is the length of the wire. Given that the wire is suspended parallel to a uniform magnetic field of 0.50 T, and the current flowing through the wire is 0.60 A, the magnetic force on the wire can be calculated as follows:
F = BIL = 0.50 T * 0.60 A * 2.0 m = 0.60 N
Therefore, This means that the wire experiences a force of 0.60 N in a direction perpendicular to both the magnetic field and the current flowing through the wire. The direction of the force can be determined using the right-hand rule, which states that if the fingers of the right hand are curled in the direction of the current, the thumb points in the direction of the magnetic force.
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Which force determines if an object is going to move or stay at rest?
a. Friction Force
b. Normal Force
c. Applied Force
d. Net Force
Answer:
a
Explanation:
because it's need someone moving it so it can move somewhere else