The motor is lifting the 6 kg box at a constant velocity. How much work is done on the
box to lift it 2 m? (Assume no resistance from the pulley.)

Answers

Answer 1

Answer:

117.6 J

Explanation:

We use the formula for work as force times the distance. The force applied to lift the box at constant speed must equal the weight of the box:

F = m * g = 6 * 9.8 N = 58.8 N

Then we multiply this times the distance the box is moved:

Work = F * d = 58.8 * 2  J = 117.6 J

Answer 2

The work done will be "117.6 J".

Work done:

According to the question,

Mass of box, m = 6 kg

Displacement, d = 2 m

Acceleration due to gravity, g = 9.8 N

We know the formula,

→ Force = Mass × Acceleration due to gravity

or,

→ F = m × g

By substituting the values, we get

      \(= 6\times 9.8\)

      \(= 58.8\) N

hence,

The work done will be:

→ Work = Force × Displacement

or,

→ W = F × d

By substituting the values,

       = \(58.8\times 2\)

       = \(117.6\) J

Thus the above response is correct.

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Related Questions

Select the correct answer.
Which type of energy is thermal energy a form of

Answers

kinetic energy. thermal energy (a low form of energy ) is a form of kinetic energy as it is produced as a result of motion of particles either if they vibrate at their position or they move along longer paths. Motion produces friction or resistance which leads to excitation and thus the heat is produced. The higher the motion of the particles, the higher would be the thermal energy.

The surface temperature of our sun is about 5800 K, and the peak of its intensity curve is in the middle of the visible spectrum. Mammals have a body temperature of about 310 K. A star that appears reddish could have a surface temperature of:

Answers

Explanation:

i expected to use Stefan's law of heat exchange but the value you gave aren't conclusive.

I should say that the temperature of the star should be close to that of the sun because of the similarity in the intensity curves

Say the tortoise and the hare are racing. If the tortoise moves straight
backwards from the starting point, what is true about its
displacement?

Answers

Explanation:

It's displacement would be negative

displacement is a vector quantity.

'Backwards', we can assume, would be negative.

and forwards, positive. So going backwards would mean a negative displacement.

1)What is the pressure at point D in kPa ?
2)Temperature at point D
3)What is the net work done on the gas as it is taken through four cycles?
4)What is the internal energy of the gas when it is at point A?
5)What is the total change in internal energy of this gas during four complete cycles?

1)What is the pressure at point D in kPa ?2)Temperature at point D3)What is the net work done on the

Answers

The answer is 1) The pressure at point D is 80 kPa. 2) The temperature at point D is 800 K. 3) The net work done on the gas over four cycles is zero. 4) The internal energy of the gas at point A is 100 J. 5) The total change in internal energy during four complete cycles is zero.

The total change in internal energy of this gas during four complete cycles is zero. The given diagram represents the Carnot cycle involving four stages. The four stages of the Carnot cycle are reversible and follow an ideal gas that is placed in a cylinder with a movable piston.Let's solve each question asked one by one.1) From the graph, it can be observed that the pressure at point D is 0.08 M Pa, which is equal to 80 kPa. Hence, the pressure at point D in kPa is 80 kPa.2) Temperature at point D The isotherm at point D is about 800 K. Hence, the temperature at point D is 800 K.3) The net work done on the gas as it is taken through four cycles is zero because the Carnot cycle is a cycle that has four stages. In each cycle, the net work done is the area enclosed by the cycle. Therefore, for a complete cycle, the net work done is zero because the area enclosed is a loop.4) The internal energy of the gas when it is at point A is 100 J because the internal energy of the gas is directly proportional to the temperature and volume. Here, at point A, the temperature is 500 K, and the volume is 2 m³, so the internal energy of the gas when it is at point A is 100 J.5) The Carnot cycle is a reversible cycle that is used to determine the efficiency of heat engines. It is a closed cycle that does not involve any net energy exchange with the surroundings. Therefore, the total change in internal energy of this gas during four complete cycles is zero since the initial and final states are the same. Hence, the total change in internal energy of this gas during four complete cycles is zero.

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A fighter jet takes off from the horizontal deck of an aircraft carrier. Starting from rest, it achieves a speed of 71.1m/s as it travels 85.3m along the deck to the end of the runway. As it leaves the deck, its acceleration changes to 4.57m/s^2 at an angle of 34.8 degrees above horizontal. What is the altitude of the jet, in meters above the deck, 5.24s after it leaves the end of the deck of the aircraft carrier? What horizontal distance, in meters, is the jet from the end of the runway 5.24s after it leaves the deck of the aircraft carrier?

Answers

The altitude is 34.18 m. The second answer is 325 m.

How can we calculate this question?

Let's utilize the kinematic equation to determine the magnitude of the acceleration on the deck.

V² = U² + 2•a•S

V is the final speed here.

Initial Velocity = U

a stands for speed.

= displacement

assigning values

56.32 = 02 + 2×a×89.4

a = 17.7275 m/s2

Part - 2

Now that we are aware that the aircraft's acceleration when it departs the deck is 4.18 m/s2 at a 39.8-degree angle

velocity in the x-axis

Vx = Ux plus ax t

Vx = 56.3 + 4.18×Cos39.8°×5.05

Vx = 56.3 + 16.2176

Vx = 72.5176 m/s

speed along the y axis

Uy + ayt = Vy

Vy = 0 + 4.18×Sin39.8°×5.05

Vy = 13.512 m/s

Part - 3

Let's now apply a kinematic equation to determine the jet's altitude.

H = Uyt+ayt2/2

assigning values

Uy = 0

H = 4.18×Sin39.8°×(5.05)2/2

H equals 34.118 meters

Part - 4

applying the same calculation from part 3 once more

Hx = Uxt plus axt2/2

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Which of the following is a description of the Remote Associates Test (RAT)?

Answers

Answer:

The description is outlined throughout the clarification section following, and according to the given word.

Explanation:

Throughout the 1960s, Sarnoff Mednick created the RAT as a tool used for testing imaginative convergent thought. Through each RAT test query lists a set of terms, which demands that we have a single additional term that will tie any of the others around.  Those other words may also be related in something like a variety of ways, such as through creating a compound word or perhaps a semantic connexon.

assignment questions

Answers

Answer:

which on a is the question

In the Roman soldier model for refraction, what happens to the first soldier who hits the muddy stream?
A. They slow down and keep going straight
B. They slow down and turn slightly
C. They speed up and keep going straight
D. They speed up and turn slightly

Answers

In the Roman soldier model for refraction, the first soldier who hits the muddy stream would slow down and turn slightly. Option B is correct.

The Roman soldier model is a simplified model used to explain the behavior of light when it passes from one medium to another. In this model, a group of Roman soldiers is marching across a field towards a muddy stream. The soldiers represent light rays, and the muddy stream represents the boundary between two media with different refractive indices.

When the first soldier hits the muddy stream, they slow down because the speed of light decreases when it passes from a medium with a lower refractive index to a medium with a higher refractive index. Additionally, the soldier turns slightly because the direction of the light ray changes as it passes through the boundary between the two media. This change in direction is called refraction, and it occurs because the speed of light changes when it passes through a medium with a different refractive index.

The amount of refraction that occurs depends on the angle at which the light ray hits the boundary between the two media and the difference in refractive indices between the two media. The Roman soldier model is a useful tool for understanding the basics of refraction, but it has limitations and cannot fully explain all aspects of the phenomenon. Option B is correct.

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Sadly, the car crashed into a tree at a speed of 5 ms*'. It took 1.2 s for the car to come to a full stop. Calculate the force exerted on the tree. the car weighs 1600kg

Answers

Sadly, the car crashed into a tree at a speed of 5 ms*'. It took 1.2 s for the car to come to a full stop, then the force exerted on the tree would be  6666.67 N.

What are the three equations of motion?

There are three equations of motion given by  Newton,

v = u + at

S = ut + 1/2 × a × t²

v² - u² = 2 × a × s

By using the first equation of the motion,

v = u + at

0 = 5 + 1.2a

a = 5 / 1.2

a = 4.167 m / s²

The force exerted on the tree = 1600 × 4.167

                                                  = 6666.67 N

Thus, the force exerted on the tree would be 6666.67 N.

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Question 2 of 10
During which step of the scientific method does a scientist determine
whether the hypothesis was supported?
OA. Draw conclusions
OB. Design an experiment
OC. Collect data
OD. Perform the experiment
SOBMIT

Answers

When the scientists draw conclusions the scientist find out whether the hypothesis was supported.

A hypothesis is a theory put up to explain a phenomenon. A hypothesis cannot be called a scientific hypothesis unless it can be tested using the scientific process.

Once your experiment is complete, you collect your measurements and analyze them to see if they support your hypothesis.

Scientists frequently discover that their hypotheses and predictions were not supported by the results of their experiments. In these circumstances, they will discuss the results of their experiment before reevaluating their initial theories and predictions in light of the fresh information. The scientific method is essentially restarted in this way. Even if they discover that their theory was correct, they could still wish to verify it once more using a different approach.

The correct option is (a).

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Which gas is forming in the test tube shown below?

Which gas is forming in the test tube shown below?

Answers

Answer:

Oxygen

Explanation:

The goal of photosynthesis is to convert radiant energy from a light source, which the lamp acts as this form of energy; and thus, turns that into chemical energy that is used for its 'food'. As a result of the green water plant and water present, photosynthesis converts carbon dioxide and water into oxygen, and even glucose! Without photosynthesis making the glucose, it would not be possible for cellular respiration to make ATP (or much less ATP would be produced). Both processes are important to the carbon cycle.

According to the principal of superposition,

Answers

Answer:

the resultant wave is the algebraic sum of all the waves reaching that particular point at a given time.

Explanation:

imagine two or three waves reaching a particular particle x at the same time. The particle will vibrate those waves and give out or transmit a resultant wave which is the algebraic sum of the incoming two waves. If both the waves have the same amplitude and phase, the resultant wave will be amplified. However if the waves have the same amplitude and equal but opposite phase then the resultant wave will be a straight line

The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?

Answers

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Which statements correctly describe the effect of distance in determining the gravitational force and the electrical
force? Check all that apply.
The gravitational force has an infinite reach.
The electrical force has an infinite reach.
The gravitational force is inversely proportional to the distance.
U The electrical force is inversely proportional to the distance.
O The gravitational force is inversely proportional to the square of the distance.
O The electrical force is inversely proportional to the square of the distance.

Answers

The statements 1,4 and 5 accurately describe the influence of distance on gravitational and electrical forces.

What is Newton's law of gravity?

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

Decreasing the distance would increase the gravity of the planet.

The following statements accurately describe the influence of distance on gravitational and electrical forces.

1. The gravitational force has an infinite reach.

4. The gravitational force is inversely proportional to the square of the distance.

5. The electrical force is inversely proportional to the square of the distance.

Hence, options 1,4 and 5 are correct.

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HELPPP PLEASE!!!!!!!

HELPPP PLEASE!!!!!!!

Answers

Answer:

S = V t - 1/2 a t^2      a here is negative due to deceleration

S = 4 * 8 - 1/2 * 64 = 0

The object just returns to its original starting point

It started out at 8 m/s which was reduced to 0 m/s after 4 sec

In 4 more seconds it was moving at -8 m/s, just the opposite of where it started

100 points plus brainlist, answer quick
CO2 + 2H₂O Based on Look at the partial chemical equation below. _____+ the conservation of mass, select the TWO molecules that best complete the reactants' side of this equation. Select 2 correct answer(s)
NaCl3
HS4
CH4
202
CO ​

Answers

The two molecules that best complete the reactants' side of the equation\(CO_2\) + 2\(H_2O\) are \(O_2\) and CO.

The correct answer would be \(O_2\) and CO.

Based on the partial chemical equation provided, \(CO_2\) + 2\(H_2O\), we need to select two molecules that complete the reactants' side of the equation while also considering the conservation of mass. Let's evaluate the given options:

1. \(NaCl_3\): This compound, sodium trichloride, does not contain carbon (C) or oxygen (O) atoms, which are required to balance the equation. Therefore, \(NaCl_3\) is not a suitable choice.

2. \(HS_4\): This compound, hydrogen tetrasulfide, also does not contain carbon (C) or oxygen (O) atoms necessary to balance the equation. Hence, \(HS_4\) is not the correct choice.

3. \(CH_4\): This molecule, methane, consists of one carbon atom (C) and four hydrogen atoms (H). It contains carbon but lacks oxygen atoms required for balancing the equation. Thus, \(CH_4\) does not complete the reactants' side.

4. \(O_2\): Oxygen gas (diatomic oxygen) is represented by\(O_2\). It contains two oxygen atoms, which helps balance the equation since there are two oxygen atoms on the product side (2\(H_2O\)). \(O_2\) is a valid choice for completing the reactants' side.

Considering the conservation of mass, we still need a molecule that contains carbon. Among the given options, CO is the only molecule that consists of one carbon atom (C) and one oxygen atom (O). By adding CO to the reactants' side, we balance both carbon and oxygen atoms in the equation.

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A runner is jogging in a straight line at a steady v, 3.5 km/hr. When the runner is L= 3.1 km from the finish line, a bird begins flying straight from the runner to the finish line at v= 17.5 km/hr (5 times as fast as the runner). When the bird reaches the finish
line, it turns around and flies directly back to the runner. finish line What cumulative distance does the bird travel? Even though the bird is a dodo, assume that it occupies only one point in space (a "zero" length bird), travels in a straight line, and that it can turn without loss of speed.Answer in units of km.

A runner is jogging in a straight line at a steady v, 3.5 km/hr. When the runner is L= 3.1 km from the

Answers

If a bird begins flying straight from the runner to the finish line at v= 17.5 km/hr, the bird would reach the finish line in 10 minutes and 37.71 seconds.

What is Velocity?

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.

As given in the problem A runner is jogging in a straight line at a steady v, 3.5 km/hr. When the runner is L= 3.1 km from the finish line, a bird begins flying straight from the runner to the finish line at v= 17.5 km/hr (5 times as fast as the runner).

The time is taken by the bird to reach the finish line = 3.1 km /17.5 km/hour

                                                                                     =0.177 hours

                                                                                     = 10 minutes 37.71 seconds

Thus, the bird would reach the finish line in 10 minutes and 37.71 seconds.

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Kepler's laws and explanations​

Answers

Answer:

The first law states that every planet describes an elliptical path about the sun as a single focus.

The second law states that The line joining the planet to the sun sweeps out equal areas in equal time intervals.

The third law states that The squares of the period of revolution is proportional to the cubes of the mean distance between the planet and the sun

Kepler's Law of equal areas for equal times. As a planet moves in an orbit about the Sun, the areas swept out by the planet are equal for equal time intervals. A: For circular orbits the equal areas are identical in shape and size (red areas).

How the government can ensure basic human dignity is maintained in relation to safe and healthy living

Answers

To ensure basic human dignity in relation to safe and healthy living, governments can implement various measures such as accessible healthcare, adequate housing, and sanitation and clean water.

How government can ensure basic human dignity is maintained

Governments should place a high priority on ensuring that everyone has access to healthcare services, enabling them to receive the essential medical care without suffering financial difficulty. This entails providing access to necessary pharmaceuticals, cheap healthcare, and a strong healthcare system.

All citizens should have access to affordable and good housing, according to governments. Policies may include restrictions on rental costs, programs to expand the supply of affordable housing, and efforts to combat homelessness. Basic hygienic and safety criteria should be met by housing.

Governments must make sure that everyone has access to clean, safe drinking water and adequate sanitary facilities. The spread of diseases and the maintenance of sanitary living circumstances can be aided by investments in sewage systems, water treatment facilities, and public hygiene education.

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A 3.00N rock is thrown vertically into the air from the ground. At h=15.0m, v=25m/s upward. Use the work-energy theorem to find the initial speed of the rock.

a. 3m/s
b. 30.3 m/s
c. None of the above

Answers

Answer:

so initial speed of the rock is 30.32 m/s

correct answer is b. 30.3 m/s

Explanation:

given data

h = 15.0m

v = 25m/s

weight of the rock m = 3.00N  

solution

we use here work-energy theorem that is express as here

work = change in the kinetic energy    ..............................1

so it can be written as

work = force × distance     ...................2

and

KE is express as

K.E = 0.5 × m × v²  

and it can be written as

F × d = 0.5 × m × (vf)² - (vi)²      ......................3

here

m is mass and vi and vf is initial and final velocity

F = mg = m  (-9.8)  , d = 15 m and v{f} = 25 m/s

so put value in equation 3 we get

m  (-9.8) × 15 = 0.5 × m × (25)² - (vi)²

solve it we get

(vi)² =  919

vi = 30.32 m/s

so initial speed of the rock is 30.32 m/s

A boy held a ball in the air what force is he applying?

Answers

Answer:

strength

Explanation:

Answer:

Potential energy

Explanation:

Since the boy is holding is, it is not moving. So, it has potential energy. Also, since it is in the air, it has gravitational potential energy.

An Atwood's machine consists of blocks of masses
m1 = 11.0 kg
and
m2 = 19.0 kg
attached by a cord running over a pulley as in the figure below. The pulley is a solid cylinder with mass
M = 7.90 kg
and radius
r = 0.200 m.
The block of mass m2 is allowed to drop, and the cord turns the pulley without slipping.

Answers

Answer:

Explanation:

Given that:

\(mass \ m_ 1 = 11.0 \ kg\)

\(mass \ m_2 = 19.0 \ kg\)

\(mass \ of \ the \ pulley\ M = 7.90 \ kg\)

\(Radius \ of \ the \ pulley = 0.200\ m\)

1) Provided that the mass in \(m_2\) is greater than the mass we have in \(m_1\), then likewise the tension we have in \(T_2\) will be greater than the tension in \(T_1\)

Using Newton's second law to mass \(m_1\), we have:

\(m_2g - T_2 = m_2 a \\ \\ T_1 = m_1 g +m_1 a \\ \\ T_1= m_1 (g+a) --- (1)\)

By using the second law, we have:

\(m_2g - T_2 = m_2a \\ \\ T_2 = m_2 (g-a)---(2)\)

For the pulley, let's use the torque equation, so we have:

\(T_2 r -T_1 r = I \alpha \\ \\ T_2r -T_1r = \Big ( \dfrac{Mr^2}{2}\Big) \dfrac{a}{r} \\ \\ T_2 -T_1 = \dfrac{Ma}{2} ---- (3)\)

Altogether, from equation (1)(2) and (3), we have:

\(m_2(g-a) -m_1 (g+a) = \dfrac{Ma}{2} \\ \\ m_2g -m_2a -m_1g-m_1a = \dfrac{Ma}{2} \\ \\ a = \dfrac{(m_2 -m_1) g}{(m_1 + m_2 + \dfrac{M}{2})} \\ \\ a = \dfrac{(19.0 \ kg - 11.0 \ kg ) ( 9.8 \ m/s^2)}{(19.0 \ kg + 11.0 \ kg + \dfrac{7.90 \ kg }{2} )}\)

\(a = 2.31 \ m/s^2\)

Also; from equation (1), the tension in the string is:

\(T_1\) = (11.0 kg ) ( 9.8 + 2.31) m/s²

\(T_1\) = 133.21 N

\(T_1\) ≅ 133 N

From equation (2):

\(T_1\) = m_2(g-a)

\(T_1\) = (19.0 kg) ( 9.8 - 2.31) m/s²

\(T_1\) = 142.31 N

\(T_1\)  = 142 N

a sound is sent out from the sheep and it's reflection from the floor of the ocean return s over second later . Assuming that the velocity of sound in water is 1500metre per second .how deep is the ocean?​

Answers

The depth of the ocean is 3750 m

How do you find the depth of the ocean?

Echoing  is a method of measuring the depth of the ocean by sending sound waves down to the ocean floor and measuring the time it takes for the sound waves to bounce back. The depth is calculated by multiplying the time taken by the speed of sound in water.

Given that;

V = 2x/t

x = distance

Then we have that

Vt = 2x

x = Vt/2

x = 1500 * 5/2

= 3750 m

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Missing parts;

A sound is sent out from the sheep and it's reflection from the floor of the ocean return 5 s over second later . Assuming that the velocity of sound in water is 1500metre per second .how deep is the ocean?​

3. Why is the term cold blooded a misconception? Explain​

Answers

Answer:

The term “cold-blooded” implies that these animals are in a never-ending struggle to stay warm. That really isn't correct. A cold-blooded animal can warm up their blood by being in the sun for hours.

The weight of a box is found to be 30 N. What is the approximate mass of the box?
3 kg
300 kg
120 kg
30 kg

Answers

Answer:

3kg

Explanation:

3kg is the appropriate mass

Answer:

3kg

Explanation:

just took the test

Two 51 g blocks are held 30 cm above a table. As shown in the figure, one of them is just touching a 30-long spring. The blocks are released at the same time. The block on the left hits the table at exactly the same instant as the block on the right first comes to an instantaneous rest. What is the spring constant?

Answers

The concept of this question can be well understood by listing out the parameters given.

The mass of the block = 51 g = 51 × 10⁻³ kgThe distance of the block from the table = 30 cmLength of the spring = 30 cm

The purpose is to determine the spring constant.

Let us assume that the two blocks are Block A and Block B.

At point A on block A, the initial velocity on the block is zero

i.e. u = 0

We want to determine the time it requires for Block A to reach the table. The can be achieved by using the second equation of motion which can be expressed by using the formula.

\(\mathsf{S = ut + \dfrac{1}{2}gt^2}\)

From the above formula,

The distance (S) = 30 cm; we need to convert the unit to meter (m).

Since 1 cm = 0.01 mThen, 30cm = 0.3 m

The acceleration (g) due to gravity = 9.8 m/s²

inputting the values into the equation above, we have;

\(\mathsf{0.3 = (0)t + \dfrac{1}{2}*(9.80)*(t^2)}\)

\(\mathsf{0.3 = \dfrac{1}{2}*(9.80)*(t^2)}\)

\(\mathsf{0.3 =4.9*(t^2)}\)

By dividing both sides by 4.9, we have:

\(\mathsf{t^2 = \dfrac{0.3}{4.9}}\)

\(\mathsf{t^2 = 0.0612}\)

\(\mathsf{t = \sqrt{0.0612}}\)

\(\mathbf{t =0.247 \ seconds}\)

However, block B comes to an instantaneous rest on point C. This is achieved by the dropping of the block on the spring. During this process, the spring is compressed and it bounces back to oscillate in that manner. The required time needed to get to this point C is half the period, this will eventually lead to the bouncing back of the block with another half of the period, thereby completing a movement of one period.

By applying the equation of the time period of a simple harmonic motion.

\(\mathbf{T = 2 \pi \sqrt{\dfrac{m}{k}}}\)

where the relation between time (t) and period (T) is:

\(\mathsf{t = \dfrac{T}{2}}\)

T = 2t

T = 2(0.247)

T = 0.494 seconds

\(\mathbf{T = 2 \pi \sqrt{\dfrac{m}{k}}}\)

By making the spring constant (k) the subject of the formula:

\(\mathbf{\dfrac{T}{2 \pi } = \sqrt{ \dfrac{m}{k}}}\)

\(\Big(\dfrac{T}{2 \pi }\Big)^2 = { \dfrac{m}{k}\)

\(\dfrac{T^2}{(2 \pi)^2 }= { \dfrac{m}{k}\)

\(\mathsf{ T^2 *k = 2 \pi^2*m} \\ \\ \mathsf{ k = \dfrac{2 \pi^2*m}{T^2}}\)

\(\mathsf{ k =\Big( \dfrac{(2 \pi)^2*(51 \times 10^{-3})}{(0.494)^2} \Big) N/m}\)

\(\mathbf{ k =8.25 \ N/m}\)

Therefore, we can conclude that the spring constant between the two 51 g blocks held at a distance 30 cm above a table as a result of instantaneous rest caused by the compression of the spring is 8.25 N/m.

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Two 51 g blocks are held 30 cm above a table. As shown in the figure, one of them is just touching a

If you are driving 100 km/h
along a straight road and you look to the side for 3.0 s
, how far do you travel during this inattentive period?

Answers

The distance you will travel during this inattentive period is 0.083 Km

How do I determine the distance travelled?

We'll begin by listing out the given parameters from the question. This is given below:

Speed = 100 Km/hrTime = 3 s = 3 / 3600 = 0.00083 hrDistance travelled = ?

We know that speed is defined as:

Speed = distance / time

Cross multiply

Distance = speed × time

With the above formula, the distance travelled can be obtained as follow:

Distance = speed × time

Distance travelled = 100 × 0.00083

Distance travelled = 0.083 Km

Thus, from the above calculation, we conclude that the distance travelled is 0.083 Km

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Which is the equation for a machine’s efficiency?(1 point)

Which is the equation for a machines efficiency?(1 point)
Which is the equation for a machines efficiency?(1 point)
Which is the equation for a machines efficiency?(1 point)
Which is the equation for a machines efficiency?(1 point)
Which is the equation for a machines efficiency?(1 point)

Answers

The equation  for a machine’s efficiency is = (output energy ÷ input energy) × 100%

What is efficiency ?

Efficiency is the ability to achieve something or get a desired outcome without wasting resources, time, money, energy, or effort. In a broader sense, it is the capacity to carry out tasks effectively and efficiently.

It denotes the degree of performance that requires the fewest inputs to provide the greatest amount of output in more mathematical or scientific words.

Hence, mathematically, machine’s efficiency can be expressed as:

machine’s efficiency =  (output energy ÷ input energy) × 100%

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If it takes 963 calories to increase the temperature of 100 grams of a substance by 90.0 degrees Celsius then how many calories does it take to raise the temperature of 300 grams of the same substance by 90.0 degrees Celsius? A)28890 B)578 C)413

If it takes 963 calories to increase the temperature of 100 grams of a substance by 90.0 degrees Celsius

Answers

Given:

The mass of the substance is m = 100 g

The temperature change is

\(\Delta T=90^{\circ}\text{ C}\)

The heat provided to the substance is Q = 963 cal

To find the heat required by the same substance to raise the temperature of the substance by 90 degrees Celsius of mass m' = 300 g

Explanation:

First we need to find the specific heat of the substance by the formula

\(Q=mc\Delta T\)

Substituting the values, the specific heat of the substance will be

\(\begin{gathered} c=\frac{Q}{m\Delta T} \\ =0.107cal/g^{\circ}C \end{gathered}\)

The heat required by the same substance of mass m' to raise the temperature by 90 degrees Celsius will be

\(\begin{gathered} Q^{\prime}\text{ =m'c}\Delta T^{\prime} \\ =300\times0.107\text{ }\times90 \\ =2889\text{ calories} \end{gathered}\)

Final Answer: The heat required by the substance of mass 300 g to raise the temperature by 90 degrees Celsius is 2889 calories.

A person starts at a point on a square which has a side of 1.5 metres in the clockwise direction and reaches the same point after time of 4 s . The value of distance is

Answers

To find the distance traveled, we just have to add all the side lengths of the square, in other words, the perimeter.

\(\begin{gathered} P=1.5m+1.5m+1.5m+1.5m \\ P=6m \end{gathered}\)Therefore, the value of the distance is 6 meters.
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