The molecular weight of NaCl is 58.44 g/mol. How much NaCl do you need to weigh out to make 100 ml of a 1 M solution

A photosynthetic reaction is the formation of the glucose and oxygen molecule by water and carbon dioxide. 12 moles of water will be used in the reaction.

Moles are the ratio of the mass of the substance to the molar mass of the substance.

In the photosynthetic reaction, 6 moles of carbon dioxide and 6 moles of water are utilized to produce 1 mole of a glucose molecule and 6 moles of oxygen.

From this, it can be said that the number of moles consumed of carbon dioxide and water will be equal and in the ratio of 1:1.

The number of moles of carbon dioxide will be equal to that of the water molecule and will also be equal to the ratio of the mass of carbon dioxide to the molar mass of carbon dioxide.

The moles of water will be calculated as:

\(\begin{aligned}\rm moles &= \rm \dfrac{\text{mass of CO}_{2}}{\text{molar mass of CO}_{2}}\\\\&= \dfrac{528}{44.01}\\\\&= 12\;\rm moles\end{aligned}\)

Therefore, option A. 12 moles of water will be used.

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In the context of atomic orbital (AO) wavefunctions, the terms "radial node" and "nodal plane" refer to different aspects of the wavefunction's behavior.

A radial node is a region in the AO wavefunction where the probability of finding an electron is zero along the radial direction. In other words, it represents a spherical shell where the electron is unlikely to be found. The number of radial nodes is determined by the principal quantum number (n) of the orbital. For example, the 2s orbital has one radial node, while the 2p orbital has no radial nodes.

On the other hand, a nodal plane is a flat plane within the AO wavefunction where the probability of finding an electron is zero along a particular direction. It represents a surface that divides the orbital into two regions of opposite phases. The number of nodal planes is determined by the angular quantum numbers (l and m) of the orbital. For example, the 2s orbital has no nodal planes, while the 2p orbital has one nodal plane (the xz or yz plane).

Radial nodes arise from the radial part of the wavefunction because they depend on the distance from the nucleus. The radial part determines the distribution of the electron density as a function of distance, and the nodes correspond to regions where the density drops to zero.

On the other hand, nodal planes arise from the angular part of the wavefunction because they depend on the orientation and shape of the orbital. The angular part describes the angular distribution of the electron density around the nucleus, and the nodal planes correspond to regions where the phase of the wavefunction changes sign.

In summary, radial nodes are related to the distance from the nucleus and arise from the radial part of the wavefunction, while nodal planes are related to the orientation and shape of the orbital and arise from the angular part of the wavefunction. The 2s orbital has one radial node and no nodal planes, while the 2p orbital has no radial nodes and one nodal plane.

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Answer:

Metallic and covalent bonds are strongly attractive; hydrogen bonding and Van der Waals forces are weakly attractive.

Explanation:

cause

Answer:

47

Ag

Silver

107.87

Explanation:

Answer:Super-giants

Explanation:

Answer:

THE 3 third one

Explanation:

Answer:A heating curve graphically represents the phase transitions that a substance undergoes as heat is added to it. The plateaus on the curve mark the phase changes. The temperature remains constant during these phase transitions.

The process of turning the raw materials gathered by mining corporations into finished goods is known as material processing.

Manufacturing is the process of converting raw materials or component components into completed products using tools, labor, machinery, and chemical processing.

The objective of material processing is to create the structural characteristics (such as crystal structure, microstructure, size, and shape) required for the product to function effectively in its intended use. Processing materials is essential to production and is at the heart of the area of materials science and engineering.

We manipulate materials to improve their strength, durability, water proofness, or even merely their aesthetic appeal. When new materials are created by combining other components, they are sometimes referred to as mixtures.

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Answer:

How do the water molecules closest to the burner compare to the water molecules closest to the surface of the liquid? ... They are closer together and moving slower than those at the surface. They are more spread out and moving faster than those at the surface. The diagram shows the sun's interior.

Explanation:

Answer:

it's c if u don't want to read all that

Explanation:

Answer:

M1 and M2 are the masses of two. objects exerting the force on each other, and R is the distance. between their centers.

Explanation:

M1 and M2 are the masses of two. objects exerting the force on each other, and R is the distance. between their centers.

Answer:

3

Explanation:

Answer:

A: Hydrogen bonding causes water to be strongly cohesive.

Explanation:

Water has a high surafce tension. Hence droplets of water

Water cannot dissolve non polar substances like oil; only polar

Water is actually less dense in solid form :)

Hydrogen bonding causes water to be strongly cohesive.

This sticking together of like substances is called cohesion. Depending on how attracted molecules of the same substance are to one another, the substance will be more or less cohesive. Hydrogen bonds cause water to be exceptionally attracted to each other. Therefore, water is very cohesive.

Cohesion, also called cohesive attraction or cohesive force, is the action or property of like molecules sticking together, being mutually attractive. It is an intrinsic property of a substance that is caused by the shape and structure of its molecules, which makes the distribution of surrounding electrons irregular when molecules get close to one another, creating an electrical attraction that can maintain a microscopic structure such as a water drop. In other words, cohesion allows for surface tension, creating a "solid-like" state upon which light-weight or low-density materials can be placed.

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The total distance (ΔX) covered by the object is 19.6 meters and the maximum height (ΔYmax) reached by the object is 1.23 meters.

1. Fundamental physical quantities:Fundamental physical quantities are those physical quantities that are independent of one another and are the basic quantities of measurement. In total there are seven fundamental quantities. These fundamental physical quantities include length, mass, time, electric current, thermodynamic temperature, amount of substance, and luminous intensity.

Converting 1500 miles/hr to cm/sec:1 mile = 1609.34 m (metres)1 hour = 3600 secNow,1500 miles/hr = (1500*1609.34)/3600 m/s (meter per second)

herefore, 1500 miles/hr = 669.12 m/s (meter per second)Converting 10 nano-gram (ng) to Kg:1 kg = 10^12 ng(1 nano = 10^-9)Therefore, 10 ng = 10/10^12 kg = 10^-11 kg

Converting 100 pico sec (ps) to nano sec (ns):1 nano sec = 10^3 ps(1 pico = 10^-12)

Therefore, 100 ps = 100/10^3 ns = 0.1 ns2.

Average velocity:

Average velocity refers to the total displacement of an object per unit time.

Instantaneous velocity:

Instantaneous velocity refers to the velocity of an object at any given instant of time.

Acceleration:

Acceleration refers to the rate of change of velocity of an object with respect to time.

Horizontal and Vertical Components:

Horizontal component = velocity*cos(45)

Vertical component = velocity*sin(45)Given, velocity = 20 miles/hr = 8.94 m/s

Therefore,

Horizontal component = 8.94*cos(45) = 6.32 m/s

Vertical component = 8.94*sin(45) = 6.32 m/s

Vector Diagram:

3. Motion with constant acceleration:

Motion with constant acceleration is defined as motion in which the velocity of an object changes at a constant rate. Three equations of motion:

For an object with initial velocity (u), final velocity (v), acceleration (a), displacement (s), and time taken (t), the three equations of motion are:

v = u + ats = ut + 1/2 at^2v^2 = u^2 + 2as

Initial speed of the car:

Here, the displacement (s) = 500 m, rate (r) = 0.5 m/sec, final speed (v) = 30 m/sec, and acceleration

(a) = 0. We have to find the initial speed (u) of the car.Using the formula v^2 = u^2 + 2as, we get:30^2 = u^2 + 2 * 0.5 * 500u^2 = 22500u = 150 m/s4. Motion under gravity:Motion under gravity is the motion of an object that is influenced by the force of gravity. The equation of motion of a ball thrown vertically up (+y) and then falls down (−y) is given as:S = u*t + 1/2 * g * t^2where u is the initial velocity, t is the time taken, S is the displacement, and g is the acceleration due to gravity. When the ball is thrown vertically up, the initial velocity is positive and when it falls down, the initial velocity is negative. Therefore, the initial velocity becomes negative when the ball falls down.

g = 9.8 m/s^2 (acceleration due to gravity)When you will catch a ball thrown vertically up at a speed of 4.9 m/sec - No air resistance:

The time taken by the ball to reach the maximum height is given by the formula:

v = u + gt0 = 4.9 m/s (initial velocity)g = 9.8 m/s^2Therefore, t = -u/g = -4.9/9.8 = -0.5 secS

ince the ball is thrown upwards, it takes a total time of 1 second to return back to the ground. Hence, it can be caught after 1 second.

5. Projectile motion:2D motion refers to motion along two different directions at the same time.

Projectile motion is a type of 2D motion that involves the motion of an object projected into the air that moves in a curved path due to gravity. The formula for projectile motion is given as:S = ut + 1/2at^2ΔX = V0cosΘ(2V0sinΘ/g)ΔYmax = (V0sinΘ)^2/2g

Where S is the displacement,

u is the initial velocity,

a is the acceleration, t is the time,

V0 is the initial velocity,

Θ is the angle of projection,

g is the acceleration due to gravity, ΔX is the horizontal distance,

and ΔYmax is the maximum height reached.

Given, initial speed of the object = 9.8 m/s, angle of projection = 45Therefore, V0 = 9.8 m/sΘ = 45 degreesNow,ΔX = V0cosΘ(2V0sinΘ/g) = 9.8*cos45*(2*9.8*sin45/9.8) = 19.6 metersΔYmax = (V0sinΘ)^2/2g = (9.8*sin45)^2/(2*9.8) = 1.23 meters

Therefore, the total distance (ΔX) covered by the object is 19.6 meters and the maximum height (ΔYmax) reached by the object is 1.23 meters.

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Answer: 5

Explanation:

Answer:

0.68 mol/L

Explanation:

M=m/l

m is moles and l is liters

Since they gave us the values in the correct units, all we have to do it plug it in

M=0.34 mol/0.5 liters

M=0.68

The AC disconnect must be turned OFF before the entire rectifier can be safe to work on. This will prevent any live AC voltage from reaching the rectifier, reducing the risk of electric shock or electrocution.

Additionally, it is important to ensure that the DC disconnect is also turned OFF to prevent any residual DC voltage from lingering in the system. Once both disconnect switches are OFF, the fuse on the circuit board should also be removed to ensure that there is no current flowing through the circuit. This will allow technicians to work on the rectifier without any danger to themselves or others nearby.In summary, before working on a rectifier, it is essential to turn off both the AC and DC disconnect switches and remove the fuse on the circuit board to ensure that there is no live current flowing through the system.

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Answer:

Time allowed for incubation, size of the dish, the amount of light, amount of agar, the type of agar…etc

Explanation:

We define a control variable as any variable that has to be held constant during a study.

If i wish to study what temperature allows for bacterial growth to occur quickly, i will have to subject different bacterial cultures to different temperatures.

The variables that must remain the same across all these cultures at different temperatures is what we call the control variables. They ensure that the results of the study are reliable.

Such variables include but are not limited to;

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The amount of carbon flux in the atmosphere will be 3.3 GtC/yr

The carbon flux in the atmosphere can be calculated by:

1. Removing the amount of carbon that leaves the atmosphere from the amount that enters the atmosphere.

2. Adding the amount of carbon released by fossil fuel burning.

Thus,

Carbon flux = 211.6 - 213.8 + 5.5 = 3.3 GtC/yr

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A formula for the sensitivity dR/dM  represents the sensitivity of the body's reaction to the medication. It shows how the reaction changes with respect to the dose of the medication, M. The term M*C represents the contribution of the constant C to the sensitivity, while the term \((2M^2)/3\) represents the contribution of the dose M itself.

To find a formula for the sensitivity, dR/dM, let's differentiate the given function R(M) with respect to M.

Step 1: Start with the function \(R(M) = M^2(C/2 - M/3).\)

Step 2: Apply the power rule of differentiation to differentiate M^2. The power rule states that if

\(f(x) = x^n, then f'(x) = n*x^(n-1). \\\)

n this case, n = 2.

\(dR/dM = 2M^(2-1)*(C/2 - M/3).\)

Simplifying, we have:

\(dR/dM = 2M*(C/2 - M/3).\)

Step 3: Distribute the 2M to each term inside the parentheses:

\(dR/dM = M*C - (2M^2)/3.\)

This formula represents the sensitivity of the body's reaction to the medication, dR/dM. It shows how the reaction changes with respect to the dose of the medication, M. The term M*C represents the contribution of the constant C to the sensitivity, while the term \((2M^2)/3\) represents the contribution of the dose M itself.

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the formula for the sensitivity, or the rate of change of the reaction R with respect to the dose M, is

dR/dM = MC - M\(^2^/^3\)

We calculate the derivative of the reaction function R(M) with respect to M.

the reaction function: R(M) = M²(C/2 - M/3)

We will apply  the power rule and the constant multiple rule of differentiation,

dR/dM = d/dM [M²(C/2 - M/3)]

= 2M(C/2 - M/3) + M²(0 - (-1/3))

= 2M(C/2 - M/3) + M\(^2^/^3\)

dR/dM =\(MC - 2M^2^/^3 + M^2^/^3\)

= \(MC - M^2^/^3\)

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Answer:

D. Density is defined as mass/volume.

To determine the partial pressure of O2 gas collected over water, we need to consider the vapor pressure of water at the given temperature and subtract it from the total pressure measured.

The partial pressure of O2 in the collected gas sample is 577.9 torr. The vapor pressure of water at 23 degrees Celsius is approximately 21.1 torr. We subtract this value from the total pressure of the gas mixture to find the partial pressure of O2. Partial pressure of O2 = Total pressure - Vapor pressure of water. Partial pressure of O2 = 599 torr - 21.1 torr. Partial pressure of O2 = 577.9 torr. Therefore, the partial pressure of O2 in the collected gas sample is 577.9 torr.

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Answer:

Follows are the solution:

Explanation:

A + B = C

Its response decreases over time as well as consumption of a reactants.  

r = -kAB

during response A convert into 2x while B convert into x to form 3x of C

let's  y = C

y = 3x

Still not converted sum of reaction  

for A: 100 - 2x

for B: 50 - x

Shift of x over time  

\(\frac{dx}{dt} = \frac{-k(100 - 2x)}{(50 - x)}\)

Integration of x as regards t  

\(\frac{1}{[(100 - 2x)(50 - x)]} dx = -k dt\\\\\frac{1}{2[(50 - x)(50 - x)]} dx = -k dt\\\\\ integral\ \frac{1}{2[(50 - x)^2]} dx =\ integral [-k ] \ dt\\\\\frac{-1}{[100-2x]} = -kt + D \\\\\)

D is the constant of integration

initial conditions: t = 0, x = 0

\(\frac{-1}{[100-2x]} = -kt + D \\\\\frac{ -1}{[100]} = 0 + D\\\\D= \frac{-1}{100}\\\\\)

hence we get:

\(\frac{-1}{[100-2x]}= -kt -\frac{1}{100}\\\\or \\\\ \frac{1}{(100-2x)} = kt + \frac{1}{100}\)

after t = 7 minutes , \(C = 10 \ g = 3x\)

\(3x = 10\\\\x = \frac{10}{3}\)

Insert the above value x into \(\frac{1}{(100-2x)}\) equation \(= kt + \frac{1}{100}\) to get k.  

\(\to \frac{1}{(100-2\times \frac{10}{3})} = k \times (7) + \frac{1}{100} \\\\ \to \frac{1}{(100- 2 \times 3.33)} = \frac{700k + 1}{100} \\\\ \to \frac{1}{(100-6.66)} = \frac{700k + 1}{100}\\\\ \to \frac{1}{93.34} = \frac{700k + 1}{100} \\\\\)

\(\to 100 = 93.34(700k + 1) \\\\ \to 100 = 65,338k + 700 \\\\ \to 65,338k = -600 \\\\ \to k = \frac{-600}{ 65,338} \\\\ \to k= - 0.0091\)

therefore plugging in the equation the above value of k  

\(\to \frac{1}{(100-2x)} = kt +\frac{1}{100} \\\\\to \frac{1}{(100-2x)} = -0.0091t + \frac{1}{100}\\\\\to \frac{1}{(100-2x)} = \frac{1 -0.91t}{100}\\\\\to \frac{1}{2(50-x)} = \frac{1 -0.91t}{100}\\\\\to \frac{1}{(50-x)} = \frac{1 -0.91t}{50}\\\\\to 50= (1-0.91t)(50-x)\\\\\to 50 = 50-45.5t-x-0.91tx\\\\\to x+0.91xt= -45.5t\\\\\to x(1+0.91t)= -45.5t\\\\\to x=\frac{-45.5t}{1+0.91t}\)

Let y = C

, calculate C:

y = 3x

\(y =3 \times \frac{-45.5t}{1+0.91t}\)

amount of C formed in 28 mins

\(x = \frac{-45.5t}{1+0.91t} ,\) plug t = 28

\(\to x = \frac{-1274}{1+25.48} \\\\\to x = \frac{-1274}{26.48} \\\\\to x= -48.26\)

therefore amount of C formed in 28 minutes is = 3x = 144.78 grams

C: \(y =3 \times \frac{-45.5t}{1+0.91t}\)

y= 136.5 =137

The mass of water that can be made would be 36.03 grams.

From the balanced chemical equation:

1 mole N2H4 produces 4 moles H2O2

0.750 mole N2H4 will produce = 0.750 x 4/1 = 3.000 moles H2O2 (limiting reactant)

0.500 mole H2O2 is used, which is less than the amount produced by N2H4, so it is also a limiting reactant.

Now, we can use the mole ratio between H2O2 and H2O to calculate the moles of water produced:

1 mole H2O2 produces 4 moles H2O

0.500 mole H2O2 will produce = 0.500 x 4/1 = 2.000 moles H2O (limiting reactant)

Finally, we can use the molar mass of water to convert the moles of water to grams:

2.000 moles H2O x 18.015 g/mol = 36.03 g H2O

Therefore, 36.03 grams of water can be made from the given amounts of N2H4 and H2O2.

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Answer:

Grey school buses would likely get in more accidents because other drivers are expecting a yellow bus to make frequent stops and the lights and stop sign are noticeable on a brighter color.

Explanation:

yellow buses are easier to see in fog than a grey bus

If the sample of magnesium used in a lab was contaminated with another metal that doesn't react with hydrochloric acid, then the results obtained in the experiment would be affected.

This is because the data collected during the experiment would reflect the reaction between hydrochloric acid and the contaminated sample instead of pure magnesium. As a result, the following changes in results might have been observed:

1. The mass of the contaminated sample would be higher than the mass of pure magnesium.

2. The rate of reaction between the contaminated sample and hydrochloric acid would be slower than the reaction between pure magnesium and hydrochloric acid.

3. The volume of hydrogen gas collected from the reaction would be lower than the volume of hydrogen gas collected in the reaction between pure magnesium and hydrochloric acid.

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ujgcxdrthfdr

Explanation:

rghc gmrhj3tu3theth3tj3tht4 eg 3is get the area 5of 6

Answer:

Waxing Crescent: We see the waxing crescent phase as a thin crescent opening to the left. First Quarter: We see the first quarter phase as a half moon. Waxing Gibbous: The waxing gibbous phase is between a half moon and full moon. Waxing means it is getting bigger.

Explanation:

Answer:

A weak acid has a low concentration of H+ Ions and a dilute acid is a solution where acid is dissolved in a more volume of water than that of acid.

A resonance effect is electron delocalization when resonance structures place a negative charge on carbons of the benzene ring.

In a benzene ring, the delocalization of electrons occurs due to resonance, which is the movement of pi electrons within the ring. Resonance structures are alternative arrangements of pi electrons in a molecule, and they contribute to the overall electronic structure of the molecule. When resonance structures are formed, electrons are delocalized and spread out over multiple atoms, resulting in increased stability of the molecule.

In the case of a benzene ring, resonance structures can be drawn with a negative charge on different carbon atoms. This occurs because the pi electrons can move freely around the ring, creating a symmetrical distribution of electron density. The negative charge is not localized on any specific carbon atom but rather delocalized over all the carbon atoms in the ring. This delocalization of negative charge leads to greater stability of the molecule.

The resonance effect in benzene is significant because it helps to explain the unique properties of benzene, such as its stability and reactivity. The delocalization of electrons lowers the overall energy of the molecule and makes benzene less reactive compared to other unsaturated hydrocarbons. It also influences the reactivity of benzene derivatives and their reactions with electrophiles or nucleophiles.

In summary, a resonance effect is the delocalization of electrons when resonance structures place a negative charge on carbons of the benzene ring. This delocalization occurs due to the movement of pi electrons, resulting in increased stability and unique properties of benzene.

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