The idea that the earth is divided into a number of small plates that float on the mantle and slide,collide,and slip past each other. Law or Theories

Answers

Answer 1

Answer:

Theories

Explanation:

It is theories because it was a generalistee abstract or thinking generalising the principle of fact about Earth tectonic plates ,it was formulated and concluded as plate tectonic theories after many findings. The theories conclude that the Earth has an outer layer called lithosphere and lies overly a plastic layer called asthenosphere. The lithosphere is divided into several plates and they move close to each other where they diverge, converge or slip over one another.


Related Questions

All rocks can form into other types of rocks

All rocks can form into other types of rocks

Answers

Answer:false

Explanation:

how is the water cycle the driving process behind weathering erosion and deposition

Answers

It plays multiple roles, dealing with erosion and deposition

Explain why the chemical properties of Mg 24 12 and Mg 26 12 are the same

Answers

This is because they have the same number of protons and electrons

the valency of magnesium is 2 why

Answers

The valency of magnesium is 2 because it has two valence electrons in its outermost shell. Magnesium belongs to the second group of the periodic table, which means it has two electrons in its outermost shell or valence shell. In order to achieve a stable configuration, magnesium tends to lose these two valence electrons to form a positively charged ion with a charge of 2+. This makes magnesium a bivalent or divalent element with a valency of 2.

Answer:

Because the outer shell of magnesium contains 2 atoms

Assume that 0.491 g of diborane is combusted in a calorimeter whose heat capacity (Ccalorimeter) is 7.854 kJ/°C at 19.63°C. What is the final temperature of the calorimeter?

Answers

Answer:

The combustion of diborane (B2H6) is as follows:

2B2H6(g) + 6O2(g) → 4H2O(g) + B4O(g)

The balanced chemical equation shows that 2 moles of B2H6 react with 6 moles of O2 to produce 4 moles of H2O and 1 mole of B4O. We can use this information to calculate the amount of heat released by the combustion of 0.491 g of B2H6:

0.491 g B2H6 × (1 mol B2H6/27.67 g B2H6) × (1 mole B4O/2 moles B2H6) × (-2037 kJ/mol B4O) = -7.89 kJ

The negative sign indicates that the reaction releases heat.

The heat released by the reaction is absorbed by the calorimeter, which causes its temperature to increase. We can use the equation:

q = Ccalorimeter × ΔT

where q is the amount of heat absorbed by the calorimeter, Ccalorimeter is the heat capacity of the calorimeter, and ΔT is the change in temperature of the calorimeter.

Rearranging the equation, we get:

ΔT = q/Ccalorimeter

Substituting the values we obtained, we get:

ΔT = (-7.89 kJ)/(7.854 kJ/°C) = -1.005°C

The negative sign indicates that the temperature of the calorimeter decreases by 1.005°C. Therefore, the final temperature of the calorimeter is:

19.63°C - 1.005°C = 18.625°C

Rounding to the appropriate number of significant figures, the final temperature of the calorimeter is 18.6°C.

Hope this is what you are looking for.

How many moles of copper ar there in the copper sample shown?
95.33

A.1.5 mol
B. 29 mol
C. 95.33 mol
D 6.02×10to the 23 power mol​

Answers

Answer:

1.5 mol

Explanation:

Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 1.50moles are there in  95.33 grams of  copper. The correct option is option A.

What is mole?

The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity or amount of substance. We know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number. The stoichiometry represents the number of moles.

Mathematically,

number of moles of copper=given mass of copper÷ molar mass of copper

Molar mass of 1 mole of copper=63.55g/mol

mass of copper=95.33g

Substituting all the given values in the above equation, we get

number of moles of copper=95.33/63.55

number of moles of copper =1.50moles

Therefore, 1.50 moles are there in  95.33 grams of  copper. The correct option is option A.

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How do you out pizza the hut?

Answers

Awnser : you can’t. Pizza Hut can’t be outfitted

Significant digits give information about (select all that apply)
a. The results of an experiment.
b. The accuracy of data from an experiment.
c. The digits that are known to be accurate.

Answers

Significant digits give information about:

a. The results of an experiment.

b. The accuracy of data from an experiment.

What is an experiment?

An experiment can be defined as a scientific investigation which typically involves the process of manipulating an independent variable (the cause), so as to determine or measure the dependent variable (the effect).

What is a significant figure?

In Science, a significant figure can be defined as the number of digits in a numerical data (value), typically a measurement from an experiment, which enhances its degree of accuracy.

In this context, we can infer and logically deduce that significant digits give information about:

The results of an experiment.The accuracy of data from an experiment.

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Low concentrations of EDTA near the detection limit gave the following dimensionless instrument readings: 175, 104, 164, 193, 131, 189, 155, 133, 151, and 176. Ten unknowns have a mean reading of 60.0. The slope of the calibration curve is 1.75×109M−1.
a) Estimate the signal detection limit for EDTA.
b) What is the concentration detection limit?
c) What is the lower limit of quantitation?

Answers

Answer:

Following are the solution to these question:

Explanation:

Calculating the mean:

\(\bar{x}=\frac{175+104+164+193+131+189+155+133+151+176}{10}\\\\\)

  \(=\frac{1571}{10}\\\\=157.1\)

Calculating the standardn:

\(\sigma=\sqrt{\frac{\Sigma(x_i-\bar{x})^2}{n-1}}\\\\\)

Please find the correct equation in the attached file.

\(=28.195\)

For point a:

\(=3s+yblank \\\\=3 \times 28.195+50\\\\=84.585+50\\\\=134.585\\\)

For point b:

\(=3 \ \frac{s}{m}\\\\ = \frac{(3 \times 28.195)}{1.75 \times 10^9 \ M^{-1}}\\\\= 4.833 \times 10^{-8} \ M\)

For point c:

\(= 10 \frac{s}{m} \\\\= \frac{(10 \times 28.195)}{1.75 x 10^9 \ M^{-1}}\\\\ = 1.611 \times 10^{-7}\ M\)

It is calculated by using the slope value that is \(1.75 \times 10^9 M^{-1}\). The slope value \(1.75 \times 10^9 M^{-1}\)is ambiguous.

Low concentrations of EDTA near the detection limit gave the following dimensionless instrument readings:

Which seasons in Atlanta GA have worst AQI

Answers

In Atlanta, GA, certain seasons are associated with poorer air quality due to various factors such as weather conditions, human activities, and geographical location.

Typically, the seasons with the worst AQI in Atlanta, GA, are summer and early fall. This is primarily due to the combination of high temperatures, stagnant air masses, and increased pollution from various sources.

During the summer months, Atlanta experiences hot and humid weather, which can contribute to the formation of ground-level ozone. Ozone is a harmful pollutant that is created when pollutants from vehicles, power plants, and industrial activities react with sunlight and heat. High levels of ozone can cause respiratory issues and other health problems.

In addition to ozone, Atlanta also experiences increased levels of particulate matter (PM) during the summer and early fall. PM refers to tiny particles suspended in the air, which can come from sources such as vehicle exhaust, industrial emissions, and wildfires.

These particles can be inhaled into the lungs and can have detrimental effects on respiratory health.

It's important to note that air quality can vary from year to year and is influenced by various factors. Local regulations, weather patterns, and changes in pollutant emissions can all impact the AQI during different seasons.

Monitoring air quality reports and taking necessary precautions such as reducing outdoor activities during times of poor air quality can help individuals stay informed and protect their health.

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How many molecules are in 5 moles of O2?

Answers

Answer: 6.02 × 10^24

Explanation:

List the three different temperature scales

Answers

Answer:

Celcius

Farenheit

Kelvin

Explanation:

Question 15 Which of the following Is not an electrophile in electrophilic aromatic substitution ? CH; NH3 SO3 NO both (b) and (c) are not electrophiles

Answers

The one which Is not an electrophile in electrophilic aromatic substitution is the NH₃.

The electrophile are the species which are the electron deficient . this means that they are attracted to the one which is electron rich species. The electrophile will accepted the electron by the electron rich species and form the bond with the nucleophile. From the given option  the which Is not an electrophile in electrophilic aromatic substitution is the NH₃. as it contains the lone pair of electrons.  the nitrogen is more electronegative than the hydrogen. the nitrogen will get the partial negative charge.

Thus, the NH₃ act as a nucleophile and not a electrophile.

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what happens when water changes from a solid to a liquid to a vapor

Answers

Answer:

It forms a water cycle!

Hope it helps!!!

Ozone in the stratosphere forms the ozone layer and is beneficial.
Where is ozone a pollutant?

Answers

Answer:

Within smokestacks and tailpipes

Explanation:

this is where manmade ozone is usually produced

What mass (g) of AgBr is formed when 50.5 mL of 0.405 M AgNO3 is treated with an excess of aqueous hydrobromic acid?234001.9223.40.1093.84

Answers

Answer

The mass in grams of AgBr formed = 3.84 g

Explanation

The given parameters are:

Volume of AgNO3 = 50.5 mL

Molarity of AgNO3 = 0.405 M

What to find:

The mass in grams of AgBr formed.

Step-by-step solution:

Step 1: Write a balanced equation for the reaction.

The balanced chemical equation for AgNO3 treated with an excess of aqueous hydrobromic acid is

\(AgNO_3(aq)+HBr(aq)\rightarrow AgBr(s)+HNO_3(aq)\)

Step 2: Convert the volume of 0.405 M AgNO3 that reacted to moles.

The moles of AgNO3 that reacted can be determined using the molarity formula.

\(Molatrity=\frac{Moles}{Volume\text{ }in\text{ }L}\)

The volume of AgNO3 needs to be converted from mL to L using the conversion formula below.

Conversion factor: 1000 mL = 1 L

50.5 mL = (50.5 mL/1000 mL) x 1 L = 0.0505 L

So,

\(\begin{gathered} 0.405M=\frac{Moles}{0.0505L} \\ \\ Moles=0.405M\times0.0505L \\ \\ Moles=0.0204525\text{ }mol \end{gathered}\)

Step 3: calculated the moles of AgBr formed.

Using the mole ratio of AgNO3 and AgBr in step 1 and the moles of AgNO3 in step 2; the moles of AgBr is calculated as shown below.

\(\begin{gathered} 1mol\text{ }AgNO_3=1mol\text{ }AgBr \\ \\ 0.0204525mol\text{ }AgNO_3=x \\ \\ Cross\text{ }multiply\text{ }and\text{ }divide\text{ }both\text{ }sides\text{ }by\text{ }1mol\text{ }AgNO_3 \\ \\ x=\frac{0.0204525mol\text{ }AgNO_3}{1mol\text{ }AgNO_3}\times1mol\text{ }AgBr \\ \\ x=0.0204525\text{ }mol\text{ }AgBr \end{gathered}\)

Step 4: Convert the moles of AgBr formed in step 3 to mass in grams.

Note that the molar mass of AgBr = 187.77 g/mol

Mass in grams of AgBr formed can be calculated using the mole formula.

\(\begin{gathered} Moles=\frac{Mass}{Molar\text{ }mass} \\ \\ Mass=Moles\times Molar\text{ }mass \\ \\ Mass=0.0204525\text{ }mol\times187.77\text{ }g\text{/}mol \\ \\ Mass=3.84\text{ }g \end{gathered}\)

Therefore, the mass in grams of AgBr formed when 50.5 mL of 0.405 M AgNO3 is treated with an excess of aqueous hydrobromic acid is 3.84 g.

Given the reaction: Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
The reaction occurs more rapidly when a 10-gram sample of Mg is powdered rather than in one piece, because powdered
Mg has
1. less surface area
2. more surface area
3. a lower potential energy
4. a higher potential energy

Answers

It’s 4 I did this the other day

How many mg of water are present in a 500. mg sample of 2.9 m/m% solution?

Report your answer to 3 significant figures and without units.

Answers


The answer is 14.5 mg.

To solve the problem, we need to first understand what a 2.9 m/m% solution means. "m/m%" stands for mass per mass percentage, which indicates the mass of the solute (in this case, water) divided by the total mass of the solution (water + solvent, which is not specified). Therefore, a 2.9 m/m% solution means that for every 100 grams of the solution, 2.9 grams are water.

To find the amount of water present in a 500 mg sample of this solution, we can set up a proportion:

2.9 g water/100 g solution = x g water/500 mg solution

Simplifying this proportion by converting units to milligrams, we get:

2.9 mg water/100 mg solution = x mg water/500 mg solution

Cross-multiplying and solving for x, we get:

x = 14.5 mg

Therefore, there are 14.5 mg of water present in a 500 mg sample of 2.9 m/m% solution.

Pls help I’ll brainlest and add extra points

Pls help Ill brainlest and add extra points

Answers

Answer:

a top predator, fighting

What is the molar concentration of Zn2+ ions in a solution, if the electrode potential value is 59mV less than the standard electrode potential value at 298 K?

Answers

Molar concentration of Zn2+ions in a solution is 3.481 mol/lit

The electrode potential value is 59mV

Temperature=298k

What is electrode potential?

It is a force of galvanic cell. basically it is the difference between an electrolyte and electrode.

equation formed- Zn → Zn2+ + 2e

              from Nernst equation-

E=E cell - 0.059 log [Zn2+]

[zn2+]=3.481 mol/lit

hence, Molar concentration of Zn2+ions in a solution is 3.481 mol/lit

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Question 5

1 pts

What is the correct interpretation of an 85% yield for a given reaction?

85% of the anticipated amount of products were produced (relative to the theoretical yield)

O 15% of the reactants were used up

O 85% of the reactants were used up

15% of the anticipated amount of products were produced (relative to the theoretical yield)

Question 6

1 pts

True or false: The limiting reactant is the reactant that is used up after the reaction is complete.

O True

False

Answers

Answer: a) 85% of the reactants were used up

b) True

Explanation:

Percentage yield is defined as the ratio of actual yield to theoretical yield in terms of percentage. The actual yield is the amount of product obtained after the experiment and the theoretical yield is the amount of ideal product that should have been obtained.  

Formula :  

\(\text {percentage Yield}=\frac{\text {Actual Yield}}{\text {Theoretical Yield}}\times 100\)

Thus 85 % yield means 85 % of the reactants were used up to give only 85% of products.

The limiting reactant is the reactant that limits the amount of product formed and hence is completely used up after the reaction is complete. Thus the given statement is True.

A 1.85-mole sample of H₂O2 weighs
(A) 33.3 amu
(B) 35.9 g
C) 62.9 g
(D) 1.85 g
E 33.3 g

Answers

Considering the definition of molar mass, the correct answer is option c): the mass of 1.85 moles H₂O₂ is 62.9 grams.

Definition of molar mass

The molar mass of substance is a property defined as the amount of mass that a substance contains in one mole.

The molar mass of a compound is the sum of the molar mass of the elements that form it (whose value is found in the periodic table) multiplied by the number of times they appear in the compound.

Molar mass of H₂O₂

In this case, you know the molar mass of the elements is:

O= 16 g/moleH= 1 g/mole

So, the molar mass of the compound H₂O₂ is calculated as:

H₂O₂= 2× 1 g/mole + 2× 16 g/mole

Solving:

H₂O₂= 34 g/mole

Mass of 1.85 moles H₂O₂

You can apply the following rule of three: If by definition of molar mass 1 mole of the compound contains 34 grams, 1.85 moles of the compound contains how much mass?

mass= (1.85 moles× 34 grams)÷ 1 mole

mass= 62.9 grams

Finally, the mass of 1.85 moles H₂O₂ is 62.9 grams.

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An aqueous solution ggggggggggggg

Answers

Answer:

cool

Explanation:

A reaction has a theoretical yield of 27.6 g. When the reaction is carried out, 13.4 g of the product is obtained. What is the percent yield?

A) 48.6 %
B) 206 %
C) 370 %
D) 64.7 %

Answers

I believe it’s A

13.4 is 48.6% of 27.6

Answer:

yee I'm excellent in maths and science

A chemist wants to make a 17.85 %(m/m) solution of NaCl using a only 50.0 g of the salt. How much water is needed to make the solution? Numerical answer only. No units.

Answers

The mass percentage is an important method which is used to calculate the concentration of a solution. The amount of water needed to add in order to make 17.85 % NaCl solution is 230.1 g.

What is mass percentage?

The mass percentage of a component in a solution is defined as the mass in grams of that component present per 100 g of the solution. The term mass percentage is denoted as w/w. It is used to calculate the concentration of a binary solution.

Mass percentage = Mass of the component in the solution / Total mass of solution × 100

17.85 = 50.0 / 50.0 + x × 100

0.1785 (50.0 + x) = 50.0

8.925 + 0.1785 x = 50.0

0.1785 x = 41.075

x = 230.1 g

Thus the amount of water added to make the solution is 230.1 g.

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5SO2 + 2MnO4- + 2H205SO42- + 2Mn2+ + 4H+ Calculate the number of grams of SO2 in a sample of air if 7.37 mL of 0.008 M KMnO4 solution are required for the titration.

Answers

Answer:

0.09536 g of SO2 in the sample of air

Explanation:

The first step is to convert the volume of KMnO4 solution to moles. This can be done using the formula:

moles = Molarity x volume (in liters)

So,

moles = 0.008 M x (7.37 mL) x (1 L/1000 mL)

= 0.0000596 moles

Next, we need to find the ratio of moles of SO2 to moles of KMnO4 in the balanced equation:

5SO2 + 2MnO4- + 2H205SO42- + 2Mn2+ + 4H+

From the equation, it can be seen that 2 moles of KMnO4- react with 5 moles of SO2. So,

moles of SO2 = (moles of KMnO4) x (5 moles of SO2 / 2 moles of KMnO4)

= 0.0000596 x (5/2)

= 0.0001495 moles

Finally, to convert moles of SO2 to grams, we can use the formula:

grams = moles x molar mass

Since the molar mass of SO2 is 64 g/mol,

grams = 0.0001495 x 64

= 0.09536 g

So, there are 0.09536 g of SO2 in the sample of air.

Which type of chemistry
uses experimentation and
equipment to identify the
components of molecules
and materials?
A. Analytical Chemistry
B. Organic Chemistry
C. Biochemistry
D. Nuclear Chemistry

Which type of chemistryuses experimentation andequipment to identify thecomponents of moleculesand materials?A.

Answers

A. Analytical chemistry

The  type of chemistry that uses experimentation and equipment to identify the components of molecules and materials is analytical chemistry.

Option A is correct.

A branch of chemistry that deals with the determination of the composition of any substance is analytical chemistry. It studies and uses instruments and methods used to separate, identify, and quantify matter.

Analytical chemistry consists of classical, wet chemical methods and modern, instrumental methods.

Analytical chemistry can be applied in forensic science, bioanalysis, clinical analysis ,environmental analysis and materials analysis.

Analytical chemistry is a field that has much to contribute to microbiology by providing methods for the rapid identification of microorganisms, characterization of microbial products and constituents, and trace detection of microbial chemicals.

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describe gravity to a 3rd grader

Answers

Answer:

you know how when you jump, you don't go flying away, that's because of a thing called gravity, it keeps everyone from floating into the sky.

Answer: if you were jumping on the bed you don’t just fly off right?! That’s crazy! Gravity keeps us from falling of the earth!

Explanation:

What is the atomic mass of element X

What is the atomic mass of element X

Answers

Answer:

Which one of the table is element X?

Explanation:

I have no idea and help!!!!!!!!!!!!!!!!!!!!!!!!!

Which of the following equation is correct? Can be more than one.

Which of the following equation is correct? Can be more than one.

Answers

There are actually no disproportionation reaction in the question. They are all incomplete and unbalanced.

Example of a disproportionate reaction:

\(Cl_{2(g)}+2OH_{(aq)}^-\rightarrow Cl_{(aq)}^-+ClO_{(aq)}^-+H_2O\)

For this reaction the chlorine atom on the reactant side as an oxidation state of 0. It gets reduced to -1 in Cl- and oxidized to +1 in ClO3-

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