Answers
The maximum angle a light ray can make with the wall of the core if it is to remain inside the fibre will be \(21.4^0\)
By using shells law,
We can write it as: \($n_1 \sin \theta_1=n_2 \theta_2$\)
Here, \($\theta_1$\) and \({\theta}_2\) are incident and reflected angles.
\($$\begin{aligned}\Rightarrow 1.6 \sin \theta_1 & =1.49 \sin 90^{\circ} \\\Rightarrow \sin \theta_1 & =\frac{1.49 \sin 90^{\circ}}{1.6}\end{aligned}$$\)
\($$\begin{aligned}\Rightarrow \sin \theta_1 & =\frac{1.49 \sin 90^{\circ}}{1.6} \\& \sin \theta_1=0.931 \Rightarrow \theta_1=68.6\end{aligned}$$\)
The maximum angle that light rays with the wall will be,
\($\theta=90-68.6^{\prime}$\)
\($$\Rightarrow \theta=21.4^{\circ}$$\)
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The complete question should be:
The glass core of an optical fibre has an index of refraction of 1.60. the index of refraction of the cladding is 1.49. you may want to review it. What is the maximum angle a light ray can make with the wall of the core if it is to remain inside the fibre? Express your answer with the appropriate units.
Related Questions
3. Water near the poles receives much less solar energy than the tropical regions and often has water temperatures around 0 degrees Celsius. Why is the water in the polar
regions not completely frozen?
A color
C salinity B density
D phytoplankton
Answers
Answer:
Yes
Explanation:
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A 42.4 N block is sliding down an inclined plane with a constant speed. The kinetic friction acting on the block is N.
Answers
When a mass m particle is released onto a smooth inclined plane (where the frictional force F=0), it will glide down the slope.
We resolve in the direction of motion in order to get the particle's sliding acceleration.
F=ma,
mg cos(90∘−θ)=ma,
g cos(90∘−θ)=a,
g sin(θ)=a.
How many Newtons is the net force while the block is travelling at a constant speed?
Zero. Newton's first law of motion states that any object travelling at a constant speed experiences no net external forces, hence the total amount of forces acting on the object must be zero. The mathematical expression for an item being under no net external force is Fnet=0 or F=0.
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How many electrons does Gold have?
Answers
Answer:
79 I believe! don't mind the rest sjjdjdiwowjekwhfjdoaoqhenfixiwnsodjd djdjsiwuwieodjskrkf
In the work and energy lab, a cart was pulled up a ramp and the force and distance were measured.
a. If the force is 4.5 Newtons and the cart travels 1.00 meters, how much work is done by your arm on the cart?
b. If the work done by your arm to the cart is 5.00 Joules, how much potential energy does the cart now have?
c. How much kinetic energy does the cart have when it is allowed to roll back down the ramp just before it hits the stop at the end of the track if the work done is 5.00 Joules? The mass of cart is 0.250 kilograms.
d. What is the velocity of the cart at the bottom of the track just before it hits the stop, if the mass of the cart is 0.250 Kg and the work done is 5.00 Joules?
e. If a mass of 250 g is added to the cart, what is the total energy given to the cart if the work done is 5.00 Joules?
f. Since the mass on the cart was doubled, what is another way to calculate the energy given to the c
Answers
D.
Explanation:
You need to know when it hit and when it stop
two asteroids crashed the crash caused both asteroids to change speeds scientist want to use the change
Answers
Answer:
The force each one experienced
Explanation:
Hope this helps :)
. What is the height in meters of a 5'4" person?
Answers
Answer:
1.62 meters
Explanation:
For an approximate result, divide the feet (height) by 3.3 to get your approximate meters (height).
A 200 W engine generates 4000 J of energy. How long did it run for?
A. 20 s
B. 200 s
C. 0.2 s
D. 2 s
Answers
Answer:
A
Explanation:
power = energy/time
200 = energy / t
200 = 4000/t
t = 4000/200= 20 sec
importance of projectile
Answers
The amount of energy for a coulomb of charge at one end of a conductor is 40 joules. The amount of energy for a coulomb of charge at the other end of the conductor is 20 joules. The potential difference across the ends of the conductor is ______.
A.) 60 joules per coulomb
B.) 60 joules
C.) 20 joules per coulomb
D.) 20 joules
Answers
A student on skateboard pushes off from the top of small hill with a apees of 2.0m/s, and then geos down the hill with a constant acceleration of 0.5 m/s2
After traveling a distancie 12.0m, how fast is the student going?
Answers
The final velocity of the student after travelling 12 m is 4 m/s.
What is the final velocity of the student?
The final velocity of the student is determined by applying the following Kinematic equation.
v² = u² + 2as
where;
u is the initial velocity of the studentv is the final velocity of the studenta is the acceleration of the students is the distance travelled by the studentv² = (2)² + 2(0.5)(12)
v² = 16
v = √16
v = 4 m/s
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calculate the force on an object with mass of 50kg and gravity of 10
Answers
Explanation:
The formula to find the force exerted by a mass, we may use F = mg, where g, the gravity, and a, the acceleration, can be interchangeable in the formula.
1) F = 50 x 10
2) F = 500 N
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An object in free fall is at heights y1, y2, and y3 at times t1, t2, and t3 respectively.
Part (a) Which of the following is the correct algebraic expression for the average velocity v12 of the object as it moves from y1 to y2?
ANSWER: (y2-y1)/(t2-t1)
Part (b) Which of the following is the correct expression for the midpoint of the time interval t12 at which the instantaneous velocity is exactly equal to this average velocity?
ANSWER: (t1+t2)/2
Part (c) Based on your answers to parts (a) and (b), you can now write similar expressions for the average velocity v23, and the midpoint t23 of the time interval from t2 to t3. Use your answers from parts (a) and (b), and the above information to write the algebraic expression for the average acceleration for these two time intervals. (Use the following as necessary: t12, t23, v12, v23.)
aaverage = _____________
Answers
Answer:
a = (v₃₂ - v₂₁) / (t₃₂ -t₂₁)
Explanation:
This is an exercise of average speed, which is defined with the variation of the distance in the unit of time
v = (y₃ - y₂) / (t₃-t₂)
the midpoint of a magnitude is the sum of the magnitude between 2
t_mid = (t₂ + t₃) / 2
the same reasoning is used for the mean acceleration
a = (v_f - v₀) / (t_f - t₀)
in our case
a = (v₃₂ - v₂₁) / (t₃₂ -t₂₁)
2. A 7 kg. Mass is moved across the table at 25 m/sec. What force caused the acceleration?
Answers
A 7 kg mass moving across the table at an acceleration of 25 m\(/s^2\)requires a force of 175 N.
To determine the force required to cause the acceleration of a 7 kg mass moving across the table at 25\(m/s^2\), we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration.
Given:
Mass (m) = 7 kg
Acceleration (a) = 25 \(m/s^2\)
We can substitute these values into the equation:
Force (F) = mass (m) * acceleration (a)
F = 7 kg * 25 \(m/s^2\)
F = 175 kg·\(m/s^2\)
Therefore, the force required to cause the acceleration of the 7 kg mass is 175 kg·\(m/s^2\).
To understand the calculation, we need to know that force is a measure of how much an object accelerates when a certain amount of mass is acted upon by that force. In this case, the mass of the object is 7 kg, and it is experiencing an acceleration of 25\(m/s^2\).
By multiplying the mass and acceleration together, we find that the force required is 175 kg·\(m/s^2\). This unit, also known as a Newton (N), represents the force required to accelerate a 1 kg mass at a rate of 1 \(m/s^2\)
In summary, the force required to cause the acceleration of the 7 kg mass across the table at 25 \(m/s^2\) is determined to be 175 kg·\(m/s^2\). This calculation follows Newton's second law of motion and shows the relationship between mass, acceleration, and force.
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When the rate of the forward reaction equals the rate of the backward reaction, the system is said to be in
Answers
Answer:
equilibrium
Explanation:
bcoz forward reaction equals backward reaction
If 2000 kg cannon fires 2 kg projectile having muzzle velocity 200 m/s then the KINETIC ENERGY of the CANNON will be ("E4" means "*10^4") *
1 point
4 J
40 J
400 J
None of the above
Answers
Answer:
M V = m v conservation of momentum (Caps-cannon Small-projectile)
V = m / M * V = 2 / 2000 * 200 m/s = .2 m/s recoil velocity of cannon
KE = 1/2 M V^2 = 2000 / 2 kg * (.2 m/s)^2 = 40 kg m^2/s^2 = 40 J
Listed below are mostly vestigial structures. Select the one that serves a purpose in humans.
(1 point)
Responses
ear muscles: ability to wiggle ears in humans versus rotating ears to hear predators in prey animals like deer and rabbits
ear muscles: ability to wiggle ears in humans versus rotating ears to hear predators in prey animals like deer and rabbits
tail: tail bone in humans versus long tails for balance and communication in other animals like lizards and wolves
tail: tail bone in humans versus long tails for balance and communication in other animals like lizards and wolves
pelvis: supports upper body and attaches to lower body in humans versus being tiny and nonfunctional in legless animals like whales and snakes
pelvis: supports upper body and attaches to lower body in humans versus being tiny and nonfunctional in legless animals like whales and snakes
hair raising: goosebumps in humans versus raising hackles to appear larger and aggressive in other animals like cats and monkeys
Answers
The pelvis in humans serves a functional purpose by supporting the upper body and attaching it to the lower body. Other vestigial structures in humans include ear muscles, tail bone, and hair raising.
As humans evolved, the pelvis became increasingly important in supporting the weight of the upper body and allowing for efficient movement of the legs. In fact, the shape of the pelvis is one of the key factors that distinguishes humans from other primates, as it evolved to accommodate the unique demands of bipedalism. However, not all structures in the human body are as essential as the pelvis. Some, like the ear muscles and tail bone, have lost their original function over time. The ear muscles, for example, were once used to orient the ears towards sounds, but are no longer functional in most humans. Similarly, the tail bone, or coccyx, is a vestige of the tail that our primate ancestors once had, but which no longer serves any purpose in humans. Other vestigial structures in humans include the appendix, which may have once been used to digest a more plant-based diet, and the ability to raise our hair, which was likely used to intimidate predators but now only causes goosebumps.
Despite their lack of function, these vestigial structures continue to exist in humans due to their evolutionary history. And while they may not be essential to our survival, they serve as a reminder of our evolutionary past and the many adaptations that have made us the unique species we are today.
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V nx,ny,nz. (x, y, z) = Vnz, (x)Vny, (y)Vnz,(Z),
where are the wave functions that solve the familiar harmonic oscillator in one dimension.
The three integers nx, ny, nz, are independent and each of them can take the any positive
integer value n = 0, 1, ....
(a) Find the spectrum of the spherically symmetric harmonic oscillator. In other words,
find the energies that can be realized in quantum theory.
(b) For the four lowest energies, indicate the quantum numbers (nx, ny, n₂) that give this
energy and note the degeneracy at each level. The degeneracy is the number of distinct
quantum states that have the same energy.
Bonus question: find the degeneracy of an arbitrary energy level..
(c) Another approach to this problem is to exploit radial symmetry. Write the radial
equation for this problem. Also record the boundary conditions for the radial equation.
=
(d) For orbital angular momentum l 0, the radial equation reduces to an eigenvalue
problem that is familiar. Compute the eigenvalues/energies in the l = 0 sector.
Hint: only some solutions are compatible with the applicable boundary conditions.
(e) For other values of l, the radial equation is more difficult to solve. Without doing
explicit work, it reminds us that the degeneracies found in (b) correspond to angular
momentum. At each level, some values of are allowed and for each that appear
there are 2l + 1 values of m.
Use this reasoning to deduce the allowed values of & for the three lowest energies.
Answers
The wave functions that solve the familiar harmonic oscillator in one dimension, then the limit the values of nx, ny, and nz to positive integers only, then there are still infinitely many possible combinations of values, but provide some general observations about the distribution of these values.
(a) The spectrum of the spherically symmetric harmonic oscillator is given by the energy eigenvalues:
E(n) = (n + 3/2)ℏω, where n = nx + ny + nz.
(b) For the four lowest energies:
E(0) = 3/2 ℏω, n = 0, degeneracy = 1
E(1) = 5/2 ℏω, n = 1 (1,0,0), (0,1,0), (0,0,1), degeneracy = 3
E(2) = 7/2 ℏω, n = 2 (2,0,0), (1,1,0), (1,0,1), (0,2,0), (0,1,1), (0,0,2), degeneracy = 6
E(3) = 9/2 ℏω, n = 3 (3,0,0), (2,1,0), (2,0,1), (1,2,0), (1,1,1), (1,0,2), (0,3,0), (0,2,1), (0,1,2), (0,0,3), degeneracy = 10
(c) The radial equation for the spherically symmetric harmonic oscillator is given by:
1/r² (d/dr) (r²(dR/dr)) + (2m/ℏ²) [E - V(r)] R = l(l+1)R
with the boundary conditions:
R(0) < ∞, R(∞) = 0.
(d) For l = 0, the radial equation reduces to:
1/r² (d/dr) (r² (dR/dr)) + (2m/ℏ²) [E - V(r)] R = 0
The eigenvalues for this equation are given by:
E(n) = (n + 3/2)ℏω, where n = 0, 1, 2, ....
(e) For other values of l, the radial equation is more difficult to solve. The allowed values of l for the three lowest energies can be deduced from the fact that for each n, the degeneracy is given by 2l + 1.
Therefore, for the first three energies, the allowed values of l are,
E(0) = 3/2 ℏω, l = 0, degeneracy = 1
E(1) = 5/2 ℏω, l = 0,1, degeneracy = 3
E(2) = 7/2 ℏω, l = 0,1,2, degeneracy = 6
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Make 3 observation about the picture to the right.
Pleas help
Answers
The picture shown in the figure represents the Milky Way Galaxy. The Galaxy in which the entire solar system is present.
The million and trillion of stars in the universe form Galaxy. The galaxy in which the entire solar system is present is called Milky Way Galaxy. The Milky Way Galaxy is spiral in shape. This Galaxy has four major arms. The major arms have both old and young stars and the minor arms have the gas and star formation activity. This galaxy also has a black hole at its center. Galileo Galilei was the first to see the Galaxy.
The Milky Way Galaxy is made up of a dense cloud of gas that stretches across the sky as seen from the Earth. The age of the Milky Way Galaxy is 13.61 billion years ago and the Andromeda Galaxy is the nearest galaxy to the Milky Way Galaxy.
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why is electromagnet are called temporary magnet
pls its urgent
Answers
Answer: because when you remove the battery, the the magnet no longer has electricity flowing through it, therefore the magnetic field disappears. Thats why its called a temporary magnet
Explanation:
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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A 1400-N crate rests on the floor.
How much work is required to move it at constant speed 5.0 m
vertically.
Express your answer to two significant figures and include the appropriate units.
Answers
The work required to move the crate vertically at a constant speed of 5.0 m is approximately 7000 Joules (J).
To determine the work required to move the crate vertically, we need to calculate the gravitational potential energy change. The work done is equal to the change in potential energy.
The formula for gravitational potential energy is given by:
Potential energy = mass * acceleration due to gravity * height
In this case, the mass of the crate is not provided, but we can use the given weight of the crate to find the mass. Weight is equal to mass multiplied by the acceleration due to gravity (W = mg).
Given:
Weight of crate (W) = 1400 N
Acceleration due to gravity (g) = 9.8 m/s^2
Vertical distance (height) = 5.0 m
First, calculate the mass of the crate:
1400 N = m * 9.8 m/s^2
m = 1400 N / 9.8 m/s^2 ≈ 143 kg
Now we can calculate the work:
Work = Potential energy = mass * g * height
Work = 143 kg * 9.8 m/s^2 * 5.0 m ≈ 7000 J
Therefore, the work required to move the crate vertically at a constant speed of 5.0 m is approximately 7000 Joules (J).
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Complete the sentence.
When a force applied at an angle causes an object to move horizontally,
only the
of the force does work.
Answers
Answer: horizontal component
Explanation: only force which is parallel to motion does work
A force applied at an angle causes an object to move horizontally only force which is parallel to motion does work.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force.
An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
A force applied at an angle causes an object to move horizontally only force which is parallel to motion does work.
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Give an example of each element,compound, and mixture
Answers
Answer:An element cannot be broken down into any other substance. ... Compounds are substances made from atoms of different elements joined by chemical bonds. They can only be separated by a chemical reaction. Common examples are water (H2O), salt (sodium chloride, NaCl), methane (CH4).
Explanation:I hope this helps
Answer:
Mixture is a substance that is formed when two or more compounds or elements are mixed in any ratio. For example- sherbet, air. sand, etc.
Explanation:
An element cannot be broken down into any other substance. ... Compounds are substances made from atoms of different elements joined by chemical bonds. They can only be separated by a chemical reaction. Common examples are water (H2O), salt (sodium chloride, NaCl), methane (CH4).
;-; sorry hopes this helps a little
WILL GIVE BRILLIANT
If you run at 12 m/s for 90 seconds, how far will you go?
Answers
D= 12 m/s • 90 s
D=1080 m
Solution
The runner will go 1080 m far
A diver jumps from a 3.0 m board with an initial upward velocity of 5.5 m/s. What is the time the diver was in the air?
Answers
The answer is that the time the diver was in the air is 1.13 seconds.
To determine the time the diver was in the air, we can use the kinematic equation:
Δy = viΔt + 1/2at²,
where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0
m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²
Simplifying, we get:
4.9t² + 5.5t - 3.0 = 0
We can solve for t using the quadratic formula:
t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s
Since time cannot be negative, the time the diver was in the air is 1.13 seconds.
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In a DC generator, the generated emf is directly proportional to the
Answers
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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A ball is held at rest at some height above a hard, horizontal surface. Once the ball is released it falls, hits the surface, and starts bouncing vertically up and down. Suppose that with each bounce the ball loses a fixed fraction p (with 1>p>0) of its energy. This loss could be due to a number of reasons (inelasticity, drag, etc) that are left unspecified.How many times will the ball bounce before coming to rest (if at all)? Provide a detailed explanation of your reasoning, not simply a one-line answer.How long will it take for the ball to come to rest (if at all)? Give your answer as a formula that contains as variables only p and the time T1 from the moment that the ball was released to the first contact with the horizontal surface.
Answers
It can never theoretically become 0. After n bounces, it may be closer to 0 or extremely tiny, depending on the precise values of p and T1.
Briefing:initial height dropped =h = gT12/2
T1 - time from the moment that the ball was released to the first contact with the horizontal surface.
initial energy T = mgh
after first bounce energy loss = mghp
height it will raise after first bounce mgh1 = mgh(1-p)
after each bounce its energy is reduced by p
after n bounces it will raise to a height
mghn=mgh(1-p)n
hn= h(1-p)n = gT12/2 *(1-p)n
gT₁² (1-p)n/2
Theoritically hn can never become 0. It can be closer to 0 or can be negligibly small after n bounces, depending on the actual values of p and T1 .
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A ball is thrown in the air at an angle of 60.0° to the ground, with an initial speed of 30m/s. How far from its original position does it land?
Answers
Answer:
The distance is \(R = 79.5 \ m\)
Explanation:
From the question we are told that
The angle at which the ball is thrown is \(\theta = 60^o\)
The initial speed is \(u = 30 \ m/s\)
Generally the distance from the original position which the ball covered is mathematically evaluated as
\(R = \frac{ u^2 * sin 2\theta }{g}\)
=> \(R = \frac{ 30^2 * sin (2* 60)}{9.8}\)
=> \(R = 79.5 \ m\)
experiments allow psychologists to isolate different effects by manipulating an independent variable, and keeping other variables constant. true or false?
Answers
Answer:
True
Explanation:
the independent variable would be like if the psychologist is experimenting the impact of sleep deprivation, sleep deprivation would be the independent variable that is being manipulated or changing its level systematically in the experiment.
what is the voltage supplied to a wire that has a resistance of 1200 Q and a current of 0.10 amps
Answers
The voltage supplied to the wire is 120 volts.
To calculate the voltage supplied to a wire, we can use Ohm's Law, which states that voltage (V) is equal to the product of current (I) and resistance (R). Mathematically, this relationship is expressed as V = I * R.
In this case, the wire has a resistance of 1200 Ω (ohms) and a current of 0.10 amps. We can substitute these values into the formula to find the voltage:
V = I * R
V = 0.10 A * 1200 Ω
V = 120 A * Ω
Therefore, the voltage supplied to the wire is 120 volts.
It's important to note that Ohm's Law holds true for resistors and other components in a circuit that obey Ohm's Law. In real-world scenarios, there may be other factors to consider, such as the presence of non-ohmic devices or components with varying resistance.
Additionally, in an AC (alternating current) circuit, the relationship between voltage, current, and resistance may involve complex quantities and phase differences. However, for a simple DC (direct current) circuit with a linear resistor, Ohm's Law provides an accurate relationship between voltage, current, and resistance.
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