The function h(x) is given below.

h(x) = {(3, –5), (5, –7), (6, –9), (10, –12), (12, –16)}

Which of the following gives h–1(x)?

Answer:45%

Step-by-step explanation:

Answer: The answer is (x-5)^2

Answer:

1st and 3rd for first question.

no for second question.

Step-by-step explanation:

please mark me as a brainlist...

Answer:

Solution given:

3y^3 + 9

communative property is taking common

3(y³+3)

is a required answer.

Answer:

p = 2L + 2W

total fencing = 100 feet

we have w = 20

then

100 = 2L + 2W

100 = 2L + 2*20

100 -40 = 2L

2L = 60

L= 60/2 = 30

Answer:

B

Step-by-step explanation:

The equation of the line that is parallel to the given line and has an x-intercept of -3 is y= 2/3x + 2.

A line's slope is determined by how its y coordinate changes in relation to how its x coordinate changes. y and x are the net changes in the y and x coordinates, respectively. Therefore, it is possible to write the

change in y coordinate with respect to the change in x coordinate as,

m = Δy/Δx where, m is the slope

We have a graph.

So, slope of line in graph is

= (-1-1)/ (0.-3)

= -2/ (-3)

= 2/3

and, we know that two parallel line have same slope.

so, the slope of parallel line is 2/3 and the x intercept is -3.

So, the Equation line is y= 2/3 x  + b

0 = 2/3 (-3) +b

b= 2

Thus, the required equation is y= 2/3x + 2.

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The general formula for f'(x) would be f' (x) = - 8 sin (x) + C.

The most general formula based on the first would be f(x) = 8 cos ( x ) + Cx + D.

To find the most general formula for f ' ( x ), we need to integrate f'' ( x ) with respect to x:

f'' ( x ) = - 8 cos (x)

f' (x) = ∫ ( -8cos(x)) dx

f ' (x) = - 8 sin(x) + C, where C is an arbitrary constant.

We need to integrate f'( x ) with respect to x to find the most general formula for f ( x ):

f'(x) = - 8 sin(x) + C

f(x) = ∫ ( - 8sin ( x ) + C) dx

f(x) = 8 cos ( x ) + Cx + D, where D is another arbitrary constant.

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Answer:

C

Step-by-step explanation:

Answer:c

Step-by-step explanation:the answers we’ll change we careful

Answer:

x = 9.9 in.

Step-by-step explanation:

area of triangle = base * height /2

49 = x*x /2

49*2 = x^2

98 = x^2

\(\sqrt{98}\) = x

\(7\sqrt{2}\) = x

9.9 = x

Answer:

Step-by-step explanation:

y = -7x+3

substitute -7x+3 for y in the other equation.

y + 7x = 10

(-7x+3) + 7x = 10

3 = 10, a contradiction, so there is no solution.

If you were to graph both equations, you would see that they are parallel lines. There is no point that belongs to both lines, so there is no (x,y) that satisfies both equations.

The rate of the jet in still air is 740 mph and the rate of the wind is 110 mph.

The given parameters;

Let the rate of the jet in still air = R₁

Let the rate of the wind = R₂

The rate of the jet against the wind:

\(R_1 - R_2 = \frac{3780}{6} \\\\R_1 - R_2 = 630\)

The rate of the jet with the wind:

\(R_1 + R_2 = \frac{5950}{7} \\\\R_1 + R_2 = 850\\\\\)

The rate of the jet in still air is calculated as follows;

\(R_1 = \frac{630 + 850}{2} \\\\R_1 = 740 \ mph\)

The rate of the wind is calculated as follows;

\(R_1 - R_2 = 630\\\\R_2 = R_1 - 630\\\\R_2 = 740 - 630 \\\\R_2 = 110 \ mph\)

Thus, the rate of the jet in still air is 740 mph and the rate of the wind is 110 mph.

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Based on the above scenario, an equation that shows how much Gwen paid. The equation for Gwen is y = 100 + 10x

Since Gwen burns  about 10 cal/min. THen she had used up 100 calories if Tristan and Keith began ar (Y g=100 if  x=0)

Then Y(g)= 10x + 100

Since Tristan is known to burns 125 cal in 10 minutes always, then one can write her own as 12.5 cal every minute.

Therefore Y (t) = 12.5x

Since Keith burns 300 calories in 30 min always, or 10 calories in every minute.

Then Y (k) = 10x

The   general function of y:

y=10x +100 + 12.5x + 10x

y = 32.5x + 100

Therefore, Based on the above scenario, an equation that shows how much Gwen paid. The equation for Gwen is y = 100 + 10x

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The angle m∠FCD is 56°

Here the line CF is an angle bisector of ∠GCD.

By this we have,

∠GCF = ∠FCD

It is given that

∠GCF = ∠GCB - 12°

Let ∠GCB be x.

∠GCF = x - 12° = ∠FCD

BCD is a straight line which form 180°.

∠BCG + ∠GCF + ∠FCD = 180°

x + x - 12° + x - 12° = 180°

3x = 204°

x = 68°

∠FCD = x - 12°

          = 68° - 12°

          = 56°

Therefore m ∠FCD = 56°.

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Answer:

\(\cos G=\dfrac{2}{3}\)

\(\csc E=\dfrac{3}{2}\)

\(\cot G=\dfrac{2}{\sqrt{5}}\)

Step-by-step explanation:

If the right angle of right triangle EFG is ∠F, then EG is the hypotenuse, and EF and FG are the legs of the triangle. (Refer to attached diagram).

Given ΔEFG is a right triangle, and EG = 6 and FG = 4, we can use Pythagoras Theorem to calculate the length of EF.

\(\begin{aligned}EF^2+FG^2&=EG^2\\EF^2+4^2&=6^2\\EF^2+16&=36\\EF^2&=20\\\sqrt{EF^2}&=\sqrt{20}\\EF&=2\sqrt{5}\end{aligned}\)

Therefore:

\(\hrulefill\)

To find cos G, use the cosine trigonometric ratio:

\(\boxed{\begin{minipage}{9 cm}\underline{Cosine trigonometric ratio} \\\\$\sf \cos(\theta)=\dfrac{A}{H}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle. \\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse (the side opposite the right angle). \\\end{minipage}}\)

For angle G, the adjacent side is FG and the hypotenuse is EG.

Therefore:

\(\cos G=\dfrac{FG}{EG}=\dfrac{4}{6}=\dfrac{2}{3}\)

\(\hrulefill\)

To find csc E, use the cosecant trigonometric ratio:

\(\boxed{\begin{minipage}{9 cm}\underline{Cosecant trigonometric ratio} \\\\$\sf \csc(\theta)=\dfrac{H}{O}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle. \\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse (the side opposite the right angle). \\\end{minipage}}\)

For angle E, the hypotenuse is EG and the opposite side is FG.

Therefore:

\(\csc E=\dfrac{EG}{FG}=\dfrac{6}{4}=\dfrac{3}{2}\)

\(\hrulefill\)

To find cot G, use the cotangent trigonometric ratio:

\(\boxed{\begin{minipage}{9 cm}\underline{Cotangent trigonometric ratio} \\\\$\sf \cot(\theta)=\dfrac{A}{O}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle. \\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse (the side opposite the right angle). \\\end{minipage}}\)

For angle G, the adjacent side is FG and the opposite side is EF.

Therefore:

\(\cot G=\dfrac{FG}{EF}=\dfrac{4}{2\sqrt{5}}=\dfrac{2}{\sqrt{5}}\)

The item most likely to weigh 2 kilograms is a roast chicken.

The size, breed, and any other ingredients or stuffing used can all affect the weight of a roast chicken. Weights of roast chickens can range from petite ones weighing less than 1 kilogram to larger ones weighing more than 2 kilograms.

The other things that we have there would either weigh less than 2 Kg such as a tea bag or much more than 2 Kg such as a horse. The egg and the tea a very light and would be less than 2 Kg in weight while the bag and the horse would be above 2 Kg in weight.

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Answer:

Step-by-step explanation:

Let us begin with the AA Similarity definition. It states that if two angles of one triangle are congruent to two angles of another triangle, then the triangles are similar.

This means that we need:

For this problem, it is unclear that there are more than one angles that are congruent to each other. We see that angle <DEF and <ABC are congruent, but the problem does not give any other angles. In another case, we must find one more to prove similarity by the AA similarity theorem.

After answering the presented question, we can conclude that This is equation true for all values of a and (11n+3), so we can conclude that the value of "a" is simply 30.8 divided by (11n+3): a = 30.8/(11n+3)

An equation in mathematics is a statement that states the equality of two expressions. An equation is made up of two sides that are separated by an algebraic equation (=). For example, the argument "2x + 3 = 9" asserts that the phrase "2x Plus 3" equals the value "9." The purpose of equation solving is to determine the value or values of the variable(s) that will allow the equation to be true. Equations can be simple or complicated, regular or nonlinear, and include one or more elements. The variable x is raised to the second power in the equation "x2 + 2x - 3 = 0." Lines are utilised in many different areas of mathematics, such as algebra, calculus, and geometry.

We are given that the factored form of 30.8n+8.4 is a(11n+3).

To find the value of a, we can expand the product a(11n+3) and equate it to the given expression 30.8n+8.4.

Expanding a(11n+3), we get:

a(11n+3) = 11an + 3a

Equating this to 30.8n+8.4, we have:

11an + 3a = 30.8n + 8.4

We can factor out an "a" from the left-hand side:

a(11n + 3) = 30.8n + 8.4

Now we can see that this is the same as the given factored form, so we can equate the two expressions:

a(11n + 3) = a(11n + 3)

This is true for all values of a and (11n+3), so we can conclude that the value of "a" is simply 30.8 divided by (11n+3):

a = 30.8/(11n+3)

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Answer:

8

Step-by-step explanation:

There are less people on the 8.

The probability that it is raining and the flight is delayed is 0.011, or approximately 0.011 rounded to the nearest thousandth.

Let's use the formula for calculating the probability of the intersection of two events: P(A and B) = P(A) × P(B|A), where P(B|A) is the probability of event B occurring given that event A has occurred.

Let A be the event that it is raining, and B be the event that the flight is delayed. We are looking for P(A and B).

We know that:

P(A) = 0.1 (the probability that it will rain)

P(B) = 0.11 (the probability that the flight will be delayed)

P(not A and not B) = 0.88 (the probability that it will not rain and the flight will leave on time)

We can use the complement rule to find P(A or B):

P(A or B) = 1 - P(not A and not B)

P(A or B) = 1 - 0.88

P(A or B) = 0.12

Now we can use the formula for the intersection of two events:

P(A and B) = P(A) × P(B|A)

We know that P(A) = 0.1, and we need to find P(B|A), the probability of the flight being delayed given that it is raining.

We can use Bayes' theorem to find P(B|A):

P(B|A) = P(A and B) / P(A)

P(B|A) = (P(A) × P(B|A)) / P(A)

P(B|A) = P(B and A) / P(A)

We can rearrange this to get:

P(A and B) = P(B|A) × P(A)

Substituting the values we know:

P(B|A) = P(A and B) / P(A)

0.11 = P(A and B) / 0.1

P(A and B) = 0.11 × 0.1

P(A and B) = 0.011

Therefore, the probability that it is raining and the flight is delayed is 0.011, or approximately 0.011 rounded to the nearest thousandth.

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Answer:

We start with 17 marbles, 4 of which are red. So P(first marble is red) = 4/17. Since the red marble is not replaced, there are now 16 marbles, 3 of which are red. So P(second marble is red) = 3/16.

The correct calculation is

P(red, then red) = 4/17 × 3/16

The constant differences between the consecutive terms are 2 (a); 2 (b), -3 (c), 7 (d), 1(e), and 6(f).

In math, the constant difference can be defined as the number that defines the pattern of a sequence of numbers. This means that number that should be added or subtracted to continue with the sequence.

Due to this, to determine the constant difference it is important to observe the pattern and find out the number that should be added. For example, if the sequence is 2, 4, 6, 8, there is a difference of 2 between each of the numbers and this is the constant difference.

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Answer:

A, B

Step-by-step explanation:

Square both sides

5x+1=sqr7        (sqr is square root)

Isolate x

x=sqr7-1/5

Because the square root can also be negative, -sqr7 is also an answer

9514 1404 393

Answer:

  (a) 90°, 90°

  (b) 5, 1

  (c) 10°, 20°

  (d) 10°, 20°, 150°

Step-by-step explanation:

You need to consider ways in which each statement might not apply.

(a) An obtuse angle is greater than 90°. If both angles are 90°, then neither is obtuse.

  counterexample: m∠1 = 90°, m∠2 = 90°

__

(b) If the perimeter is 12, the sum of the side lengths must be 6. There are many ways to get two numbers that have a sum of 6. Here's one:

  counterexample: length = 5, width = 1

__

(c) All that is required is that the sum of angles be 30°. They don't have to be equal.

  counterexample: m∠ABC = 10°, m∠CBD = 20°

__

(d) We know the three angles of a triangle have a sum of 180°, but that does not require it to be an acute triangle. A triangle can also be right or obtuse.

  counterexample: m∠P = 10°, m∠Q = 20°, m∠R = 150°

Answer:

101 students

since a whole circle is 360 degrees just subtract 259 from 360

Answer:

x = √130

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Trigonometry

[Right Triangles Only] Pythagorean Theorem: a² + b² = c²

Step-by-step explanation:

Step 1: Define

Leg a = 9

Leg b = 7

Hypotenuse c = x

Step 2: Solve for x

let's go like the crab, go backwards, start at the last

if you don't have a Unit Circle, this is a good time to get one, there are many online.

Check the picture below.

\(~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{6}~,~\stackrel{y_1}{7})\qquad (\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ x +6}{2}~~~ ,~~~ \cfrac{ y +7}{2} \right) ~~ = ~~\stackrel{midpoint}{(-5~~,~~-5)} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{ x +6}{2}=-5\implies x+6=-10\implies \boxed{x=-16} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{ y +7}{2}=-5\implies y+7=-10\implies \boxed{y=-17}\)

The required angle is 24.5°.

Given is a right triangle with perpendicular side 16 and the base = 35 we need to find an acute angle in it,

To find the acute angle in a right triangle given the lengths of the perpendicular side and the base, you can use the tangent function.

The tangent of an angle is defined as the ratio of the length of the perpendicular side to the length of the base side.

In this case, the perpendicular side is 16 and the base is 35.

Let's denote the acute angle as θ.

Using the tangent function, we can set up the equation:

tan(θ) = perpendicular side / base

tan(θ) = 16 / 35

To find the value of θ, we can take the inverse tangent of both sides:

θ = tan⁻¹(16 / 35)

θ = 24.5°

Hence the required angle is 24.5°.

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