the earth naturally fluctuates between what concentrations of co2? group of answer choices 180-410 ppm 100-400 ppm 180-280 ppm 0-500 ppm

Answer:

2 electrons

Explanation:

The result will be a decrease in the money market and an increase in the bond market, which will push bond prices down and interest rates will rise until a new equilibrium is reached.

Suppose the Federal Reserve decreases the money supply, this action will lead to a decrease in the money market equilibrium and an increase in the bond market equilibrium. As a result, bond prices will drop, and interest rates will rise until a new equilibrium is established. This shift will occur because as the money supply decreases, the demand for money will increase, leading to an increase in interest rates.

This increase in interest rates will then cause bond prices to drop as the cost of borrowing rises, and investors will demand a higher yield. Ultimately, a new equilibrium will be established where the demand for money equals the supply, and the bond market is in equilibrium with the new interest rate.

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1.78 grams of silver can be produced from 1.40 g silver nitrate and excess copper. The balanced chemical equation for the reaction of copper with silver nitrate (use cu2) is as follows: Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag

To determine how many grams of silver can be produced from 1.40 g of silver nitrate and excess copper, we first need to calculate the limiting reactant.

The stoichiometry of the reaction is such that 2 moles of silver nitrate react with 1 mole of copper to produce 2 moles of silver. The molar mass of silver nitrate is 169.87 g/mol while that of copper is 63.55 g/mol,

therefore, the number of moles of silver nitrate present in 1.40 g can be calculated as follows:Number of moles of silver nitrate = mass/molar mass= 1.40/169.87= 0.008240 molSimilarly, the number of moles of copper required to react with this quantity of silver nitrate is 0.004120 mol (half of the number of moles of silver nitrate).

Since there is an excess of copper, it will not limit the reaction and hence the limiting reactant is silver nitrate.To calculate the mass of silver produced, we use the molar mass of silver, which is 107.87 g/mol.Mass of silver produced = number of moles of silver x molar mass= 0.01648 x 107.87= 1.78 g

Therefore, 1.78 grams of silver can be produced from 1.40 g silver nitrate and excess copper.

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The rate of disappearance of NH3 was known, and the rates of disappearance of N2 and H2 were calculated by relating the rates of disappearance of all three species using the stoichiometry of the reaction.

We must first formulate the balanced chemical equation for the reaction involving NH3, N2, and H2: N2 + 3H2 2NH3 in order to calculate the rates of disappearance of N2 and H2. The stoichiometry of the reaction allows us to relate the rates at which NH3, N2, and H2 dissipate. Specifically, we have (rate of disappearance of N2) = (1/2)* since two moles of NH3 are created for every one mole of N2 that reacts (rate of disappearance of NH3), Similarily, because for every mole of N2 that reacts, three moles of H2 are used. N2 dissipates at a rate of 0.016 mol/L/s and H2 dissipates at a rate of 0.048 mol/L/s as a result. These rates were determined utilising the reaction's stoichiometry and the specified pace of the reaction. The rate of disappearance of NH3 was known, and the rates of disappearance of N2 and H2 were calculated by relating the rates of disappearance of all three species using the stoichiometry of the reaction.

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The sample of oxygen will occupy approximately 18.5 mL at -70 °C and the same pressure.

The force exerted by a gas on specific area is known as gas pressure..

As we know, (P₁ V₁) /(T₁) = (P₂V₂) /(T₂)

Given, P₁ is the initial pressure (452 torr); V₁ is initial volume (32.2 mL)

T₁ is initial temperature in Kelvin (30 °C + 273.15 = 303.15 K)

P₂ is final pressure (452 torr); V₂ is final volume (what we want to find)

T₂ is the final temperature in Kelvin (-70 °C + 273.15 = 203.15 K)

Now, V2 = (P₁ V₁ T₂) / (P2 T₁)

V₂ = (452 torr x 32.2 mL x 203.15 K) / (452 torr x 303.15 K)

V₂ ≈ 18.5 mL

Therefore, the sample of oxygen will occupy approximately 18.5 mL at -70 °C and the same pressure.

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Answer:

[He] 2s2 2p2

Explanation:

Answer:

latent heat, also called the heat of vaporization, is the amount of energy necessary to change a liquid to a vapour at constant temperature and pressure. The energy required to melt a solid to a liquid is called the heat of fusion, and the heat of sublimation is the energy....................

When choosing a substance for use in a cooling system, we want a substance that can absorb a large amount of heat without undergoing a significant temperature change. This is where the specific heat capacity of a substance comes into play.

The specific heat capacity of a substance is defined as the amount of heat required to raise the temperature of one unit of mass of the substance by one degree Celsius (or Kelvin). A substance with a high specific heat capacity requires more heat to raise its temperature by a certain amount than a substance with a low specific heat capacity. Therefore, a substance with a high specific heat capacity would be best for use in a cooling system.

Out of the options given, a liquid with a high specific heat would be the best choice for use in a cooling system. Liquids have a higher specific heat than gases, which makes them better at absorbing and storing heat. Additionally, liquids have a higher thermal conductivity than solids, which means they can more efficiently transfer heat from one location to another.

Moreover, among the liquids, water is a commonly used coolant due to its high specific heat capacity, which means it can absorb a large amount of heat without undergoing a significant temperature change. Additionally, water has a high boiling point, which makes it effective at absorbing heat from high-temperature sources without boiling and evaporating.

In summary, a liquid with a high specific heat, such as water, would be the best choice for use in a cooling system due to its ability to absorb and store heat efficiently.

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Answer:

2) a

3) c

explanation:

both gain from the relationship in number 2

while in number 3 one gains and one is hurt

Answer:

Explanation:

Matter that always has exactly the same composition is classified as a pure substance. Every sample of a given substance has the same properties because a substance has a fixed, uniform composition.

Answer: The vapor pressure of ethanol at \(26.3^{o}C\) is 238.3 torr.

Explanation:

Given: \(\Delta H_{vap}\) = 38.6 kJ/mol

\(T_{1} = 26.3^{o}C = (26.3 + 273) K = 299.3 K\)

\(T_{2} = 78.4^{o}C = (78.4 + 273) K = 351.4 K\)

Formula used to calculate the vapor pressure of ethanol is as follows.

\(ln\frac{P_{2}}{P_{1}} = \frac{\Delta H_{vap}}{R} [\frac{1}{T_{1}} - \frac{1}{T_{2}}]\\\)

Substitute the values into above formula as follows.

\(ln\frac{P_{2}}{P_{1}} = \frac{\Delta H_{vap}}{R} [\frac{1}{T_{1}} - \frac{1}{T_{2}}]\\ \\ln \frac{760 torr}{P_{1}} = \frac{38600 J}{8.314 J/mol K}[\frac{1}{299.3} - \frac{1}{351.4}]\\\frac{760}{P_{1}} = 3.18\\P_{1} = 238.3 torr\)

Thus, we can conclude that the vapor pressure of ethanol at \(26.3^{o}C\) is 238.3 torr.

Answer:

Number of moles = 0.075 mol

Explanation:

Volume = 500.0 mL = 0.5 (Converting to L by dividing by 1000)

Molarity = 0.15 M

Number of moles = ?

The relationship between the quantities is given as;

Molarity  = Number of moles / Volume

Number of moles = Molarity * Volume

Number of moles = 0.15  * 0.5

Number of moles = 0.075 mol

The given number is written incorrectly because in the integer part of the number there should be a number between 1 and 10, here it is 423, which is not in this interval.

To write it properly, put the decimal dot two place to the left and add 2 to the power of 10. This way:

Answer:

Temperature is one of the major factors that affects the rate of change of the liquid colour, this is because ; like when if you freeze hot water the ice formed will be clear transparent, while on the other hand, if we freeze cold water it would be foggy inside the ice. This change occurs because of the temperature difference of the cold and hot water.

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The molecular ion of a hydrocarbon is m/z = 68 and it has IR absorptions at 3310, 3000−2850, and 2120 cm−1. The structure of the given hydrocarbon can be drawn as follows:

Drawn structure of the given hydrocarbon as per the given data is shown below:

It has six carbons and 14 hydrogens. It is an alkene as it has a C=C bond which gives an absorption at 2120 cm−1.The absorption at 3310 cm−1 indicates the presence of an sp hybridized carbon attached to hydrogen, as in the case of C ≡ CH. The IR spectrum shows a strong and broad peak, which is consistent with the presence of a -OH or -NH group.

However, in this case, it is not present as the molecular ion doesn't show any odd mass peak.

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Answer:

0.5 mole of H₂.

Explanation:

We'll begin by calculating the number of mole in 23 g of Na. This can be obtained as follow:

Mass of Na = 23 g

Molar mass of Na = 23 g/mol

Mole of Na =?

Mole = mass / Molar mass

Mole of Na = 23 / 23

Mole of Na = 1 mole

Next, the balanced equation for the reaction.

2Na + 2H₂O —> 2NaOH + H₂

From the balanced equation above,

2 moles of Na reacted to produce 1 mole H₂.

Finally, we shall determine the number of mole of H₂ produced by the reaction of 23 g (i.e 1 mole) of Na. This can be obtained as follow:

From the balanced equation above,

2 moles of Na reacted to produce 1 mole H₂.

Therefore, 1 mole of Na will react to produce = (1 × 1) / 2 = 0.5 mole of H₂.

Thus, 0.5 mole of H₂ is obtained from the reaction.

Answer:

Sulfer

Explanation:

We just took the lesson lol

The pKb of the weak base can be calculated using the equation pKb = 14 - pH. In this case, pKb = 14 - 11.58 = 2.42.

This is because the pH scale is logarithmic, meaning that if the pH is lower than 7, the solution is acidic and if the pH is higher than 7, the solution is basic. In this case, the pH of the solution is 11.58, which is lower than 7 and indicates that the solution is acidic. Therefore, the pKb of the weak base can be calculated by subtracting 11.58 from 14, which gives a value of 2.42.

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Explanation:

Answer:

Each copper atom has lost one electron and become a positive ion. ... The electrons can move freely through the metal. For this reason, they are known as free electrons. They are also known as conduction electrons, because they help copper to be a good conductor of heat and electricity.

Answer:

\(distance = speed \: \times time\)

D = S × T

Explanation:

\(distance = 3.5 \times 5 \\ = 17.5 \: m\)

The molar flow rate of the vapor product (n_v) is 1.99 kmol/h, and the molar flow rate of the liquid product (n_l) is 8.01 kmol/h.

Let's denote:

F = Feed rate (10.0 kmol/h)

F_a = Molar flow rate of acetone in the feed

F_w = Molar flow rate of water in the feed

V = Molar flow rate of vapor product

L = Molar flow rate of liquid product

To solve the balances, we need to consider the total moles and the acetone component separately.

Total Moles Balance:

F = V + L

Acetone Balance:

F_a = 0.35 * F (Acetone in the feed)

0.75 * V = 0.187 * L (Acetone in the vapor and liquid products)

Now, we can solve these equations to find the values of V and L.

From the Total Moles Balance:

V + L = 10.0

From the Acetone Balance:

0.75 * V = 0.187 * (10.0 - V)

Simplifying the equation:

0.75V = 1.87 - 0.187V

0.937V = 1.87

V = 1.99 kmol/h

Substituting the value of V in the Total Moles Balance equation:

1.99 + L = 10.0

L = 8.01 kmol/h

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The volume of the air bubble that will form if the pressure outside the submarine breaks it will be approximately 13.95 liters.

What is the volume?

Assuming that the temperature remains constant, we can use Boyle's law to determine the volume of the air bubble that will form if the pressure outside the submarine breaks it. Boyle's law states that the pressure of a gas is inversely proportional to its volume when temperature is held constant.

Let V1 be the initial volume of the air in the submarine, P1 be the initial pressure inside the submarine (1.01 atm), P2 be the pressure outside the submarine (1086 atm), and V2 be the final volume of the air bubble.

According to Boyle's law, we have:

P1 x V1 = P2 x V2

Substituting the given values, we get:

1.01 atm x 15,000 L = 1086 atm x V2

Solving for V2, we get:

V2 = (1.01 atm x 15,000 L) / 1086 atm = 13.95 L

Therefore, the volume of the air bubble that will form if the pressure outside the submarine breaks it will be approximately 13.95 liters.

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Complete question is: Submarines need to be extremely strong to withstand the extremely high pressure of water pushing down on them. An experimental research submarine with a volume of 15,000 liters has an internal pressure of 1.01 atm. If the pressure of the ocean breaks the submarine, 13.95 liters the bubble of air in the submarine be if the pressure outside the sub is 1086 atm.

Answer:

c. Both i & ii

Explanation:

Moles do not change with temperature hence Mole fraction does not depends of temperature.

Molality is number of moles of solutes per kilogram of solvent. It has no relationship with temperature.

This means both of them do not change wit the change in temperature.

Correct option;

c. Both i & ii

Answer:

The answer is "It leads to the formation of underground caves"

Explanation:

Texas Hill Land is popular for its rolling hills, good wine, and authentic food. Its Texas Hill Property appeal is no mystery, recognized as being one of the top vacation destinations in the World. Texas Hill Structure is primarily mostly of weak calcareous stone. Calcium may worsen or degrade if exposed to carbon dioxide in rainwater. This practice affects the land of the Texas smoky Mountains leading to the formation of underwater groves.

Answer:

99758 meters

Explanation: 1 mile=1609 meters. Just multiply 62 with 1609. Let me know if you want a conversion sheet.

The best solvent choice for this analysis will be 50% hexanes in ethyl acetate.

Ethyl acetate having a molecular weight of 174.28, is observable in chromatography paper.

In the chemical examination, chromatography could be a research facility strategy for the partition of a blend into its components.

The blend is broken down into a liquid dissolvable (gas or fluid) called the versatile stage, which carries it through a framework (a column, a capillary tube, a plate, or a sheet) on which a fabric called the stationary stage is settled.

Since the distinctive constituents of the blend tend to have diverse affinities for the stationary stage and are held for distinctive lengths of time depending on their intuition with their surface destinations causing them to partition.

The partition is based on the differential dividing between the portable and the stationary stages. Unpretentious contrasts in a compound's parcel coefficient result in differential maintenance on the stationary stage and hence influence the division.

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Answer:

Mass will be equal to 874.56 gram

Explanation:

Molar mass of sulfur = 32 u

Molar mass of Florine = 19 u

Therefore molar mass of \(SF_2\) \(=32+2\times 19=70u\)

So mass of \(6.023\times 10^{23}\) particle is 70 gram

Therefore mass of 1 particle

\(=\frac{70}{6.023\times 10^{23}}=11.62\times 10^{-23}g\)

Therefore mass of \(7.525\times 10^{24}\) particle is

\(7.525\times 10^{24}\times 11.62\times 10^{-23}=874.56gram\)