)the decomposition of dinitrogen pentoxide is described by the chemical equation2 n2o5(g) 4 no2(g) o2(g)if the rate of appearance of no2 is equal to 0.560 mol/min at a particular moment, what is the rateof appearance of o2 at that moment?2)a)0.280 mol/minb)1.12 mol/minc)2.24 mol/mind)0.140 mol/min

Answer:

when organisms decompose, or burning fossil fuels and pollution and such

Explanation:

Answer:

To separate sand and table salt you would add water. Table salt dissolves in water leaving salt water and sand. The sand then will go through the process of filtration leaving salt water and sand separated.

Explanation:

Answer:

Explanation:

Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions.

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Theoretical yield of copper is 7.22 g when 4.25g of iron in the chemical reaction.

2Fe(s) + 3Cu2(aq.) ---->  2Fe3(aq.)  + 3Cu (s)

Molar mass of Iron (Fe) is 56g/mole.

Molar mass of copper (cu) is 63.5g/mole.

2 mole ( 2 * 56g/mole) Iron produces = 3 mole ( 3 * 63.5g/mole ) copper

Theoretical yield is the maximum amount of product that could be formed from the given amounts of reactants. The actual yield is the amount of product that is actually formed when the reaction is carried out in the laboratory. The theoretical yield is the amount of product that would be formed from a reaction if it was 100% efficient.

There are 4. 25 g of Iron .so,

4.25 g Iron produces = (3 * 63.5g / 2 * 56 g ) * 4.25 g copper

                                     = 7.22 g copper

Theoretical yield of copper is 7.22g.

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Answer:

hot

Explanation:

Answer:

The change from a liquid phase to a gaseous phase.

so the answer would be it changed to a gaseous phase

---------------

This is what occurs when the vapor pressure of the liquid is equal to the atmospheric pressure exerted on the liquid.

Answer:

OH⁻ (aq) + H⁺ (aq) → H₂O (l)

General Formulas and Concepts:

Chemistry

Explanation:

Step 1: RxN

NaOH (aq) + HCl (aq) → H₂O (l) + NaCl (aq)

Step 2: Balance RxN

Reaction is already balanced.

Step 3: Ionic Equations

Total Ionic Equation:

Break up the aqueous solutions into individual ions.

Na⁺ (aq) + OH⁻ (aq) + H⁺ (aq) + Cl⁻ (aq) → H₂O (l) + Na⁺ (aq) + Cl⁻ (aq)

Net Ionic Equation:

Remove spectator ions.

OH⁻ (aq) + H⁺ (aq) → H₂O (l)

The complete ionic equation for the reaction is:

Na⁺(aq) + OH⁻(aq) + H⁺(aq) + Cl⁻(aq) → H₂O(1) + Na⁺(aq) + Cl⁻(aq)

To write the complete ionic equation for the given chemical reaction, we need to break down all the reactants and products into their respective ions (if they are ionic compounds) or molecules (if they are covalent compounds) when they are in an aqueous solution.

The given chemical equation is:

NaOH(aq) + HCl(aq) → H₂O(1) + NaCl(aq)

In this reaction, both NaOH and HCl are strong electrolytes, which means they fully dissociate into ions when dissolved in water.

Therefore, the complete ionic equation for the reaction is:

Na⁺(aq) + OH⁻(aq) + H⁺(aq) + Cl⁻(aq) → H₂O(1) + Na⁺(aq) + Cl⁻(aq)

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6.9 g of sodium chloride will be produced.

Antoine Lavoisier discovered in 1789 that mass is neither created nor destroyed in chemical reactions, which led to the formulation of the Law of Conservation of Mass. That is to say, the mass of any one element at the start of a reaction will be equal to that element's mass at the conclusion of the reaction.

The total mass of the reactants and products are equal under the principle of conservation of mass.

                  BaCl₂ + Na₂SO₄ => BaSO₄ + 2NaCl

Molecular weight of BaCl₂ = 137 + 35.5 × 2

                                            = 208 g/mole

Molecular weight of NaCl = 22.99 + 35.45

                                           = 58.44 g/mole

208 g/mol BaCl₂ produces 58.44 g/mole NaCl.

1 g/mol BaCl₂ produces (58.44 / 208) g/mole NaCl.

24.7 g  BaCl₂ produces   (58.44 / 208) × 24.7 g NaCl

                                       = 6.9 g NaCl

Therefore, 6.9g of sodium chloride will be produced.

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Methanol's combustion enthalpy can be calculated at -540 (kJ mol-1).

Methanol, the most basic form of alcohol (CH3OH), serves as the chemical basis for countless items used in daily life, such as paints, plastics, auto parts, and building supplies. Additionally, methanol is a renewable resource that powers fuel cells, boilers, cook stoves, ships, automobiles, trucks, and buses.

Energy required to dissociate the bonds connecting reactants

3 × 413 + 358 + 464 + 1.5 × 498 (kJ mol-1) / 2808 (kJ mol-1);

Total energy released when products form bonds

4 × 464 + 2 × 746 (kJ mol-1) / 3348 (kJ mol-1);

∆H = -540 (kJ mol-1).

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The complete question is -

Methanol is made in large quantities as it is used in the production of polymers and in fuels.

The enthalpy of combustion of methanol can be determined theoretically or experimentally.

CH₃OH(l) + 1 O₂(g) → CO₂(g) + 2H₂O(g)

Using the information from Table 10 of the Data Booklet, determine the theoretical enthalpy of combustion of methanol.

Answer:

The decay of radioactive elements occurs at a fixed rate. The half-life of a radioisotope is the time required for one half of the amount of unstable material to degrade into a more stable material. For example, a source will have an intensity of 100% when new. At one half-life, its intensity will be cut into 50% of the original intensity.

Explanation:

Red Litmus paper turns blue

Answer:

\( Ca(OH) _2 \)

Explanation:

In lime water \( \red{\bold {RED}} \) litmus paper turns \( \blue {\bold {BLUE}} \) because lime water is alkaline.

\(formula \: for \: lime \: water : Ca(OH) _2 \\ \)

The original volume of HBr that was titrated can be calculated as the ratio of the moles of HBr to its concentration.

To determine the original volume of HBr that was titrated, we can use the concept of stoichiometry and the equation balanced for the neutralization reaction between HBr and KOH.

The balanced equation is:

HBr + KOH → KBr + H₂O

From the balanced equation, we can see that the stoichiometric ratio between HBr and KOH is 1:1. This means that for every mole of HBr, we need an equal number of moles of KOH to complete neutralization.

First, let's determine the moles of KOH used in the titration:

Moles of KOH = 0.500 M × 0.075 L = 0.0375 mol

Since the stoichiometric ratio is 1:1, this also represents the number of moles of HBr that were neutralized.

Now, we can calculate the original volume of HBr using the concentration of the unknown solution:

Moles of HBr = 0.0375 mol

Concentration of HBr = unknown (let's assume it is C mol/L)

Volume of HBr = Moles of HBr / Concentration of HBr = 0.0375 mol / C mol/L

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Answer:  There are therefore 6.02 × 1023 water molecules in a mole of water molecules.

Explanation: Hope this helps

Answer:

The system will shift to the left producing more moles of gases trying to maintain the original pressure of the system

Explanation:

Based on LeChatelier's principle, a change in temperature, pressure, volume or concentration on a system result in an opposing change trying to maintain the initial equilibrium conditions.

In the reaction:

N₂(g) + 3H₂(g) ⇄ 2NH₃(g)

4 moles of gas reacts producing 2 moles of gas.

In a gas reaction, the system will try to maintain the total pressure.

If the volume of the container increases, the system will shift to the side of the reaction that has more moles of gases in order to maintain the pressure.

That means if in the reaction the volume of the container increase from 2.0L to 4.0L the system will shift to the left producing more moles of gases trying to maintain the original pressure of the system.

49 becase you multilpy it

Explanation:

Answer:

Neon and Methane

Explanation:

Nitrogen and Oxygen made up way over half of the atmosphere so it's without a doubt, not those two. Precisely, Nitrogen makes up 78% of the atmosphere while oxygen makes up 21%

Answer: neon and methane

Answer:

the answer is a

Explanation:

Voltage can be thought of as the pressure pushing charges along a conductor, while the electrical resistance of a conductor is a measure of how difficult it is to push the charges along.

Answer: Reaction is already balanced

Explanation: The balanced chemical equation for the reaction H2O -> OH- can be written as:

H2O → OH-

However, this equation is already balanced as there is only one atom of oxygen on each side of the arrow and two atoms of hydrogen on each side of the arrow. There is no need to adjust the coefficients of the reactants or products to balance the equation.

This reaction represents a dissociation reaction, where a molecule of water (H2O) dissociates into a hydroxide ion (OH-) and a hydrogen ion (H+).

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Answer:

the molecular formula of the compound is N9O9.

Explanation:

To determine the molecular formula of the compound, we need to know the empirical formula mass of NO. The empirical formula of NO indicates that the compound contains one nitrogen atom and one oxygen atom.

The empirical formula mass of NO can be calculated as:

Empirical formula mass = atomic mass of N + atomic mass of O

Empirical formula mass = 14.01 + 16.00

Empirical formula mass = 30.01

The mass of the compound is given as 276. We can use this information along with the empirical formula mass to calculate the factor by which the empirical formula should be multiplied to obtain the molecular formula.

Factor = Molecular mass / Empirical formula mass

Factor = 276 / 30.01

Factor = 9.198

The molecular formula can be obtained by multiplying the empirical formula by this factor:

Molecular formula = Empirical formula x Factor

Molecular formula = NO x 9.198

Molecular formula = N9O9

Therefore, the molecular formula of the compound is N9O9.

If 150cm³ of carbon(11) oxide burns in 80cm³of oxygen according to the given equation the volume of oxygen that was in excess is 5.6 cm³.

From the balanced equation, we can see that 2 moles of CO react with 1 mole of O2. Therefore, we need to determine how much O2 is required to react with 150 cm³ of CO.

Let's start by calculating the number of moles of CO:

n(CO) = V(CO) / molar volume at STP

= 150 cm³ / 22.4 L/mol

= 0.006696 mol

Since the stoichiometric ratio of equation of CO to O2 is 2:1, we need half as many moles of O2 as CO. Therefore, the number of moles of O2 required is:

n(O2) = 1/2 * n(CO)

= 1/2 * 0.006696 mol

= 0.003348 mol

Now we can calculate the volume of oxygen required using the ideal gas law:

PV = nRT

Assuming the temperature and pressure are constant, we can simplify this to:

V = n(RT/P)

where V is the volume of gas in liters, n is the number of moles of gas, R is the ideal gas constant, T is the temperature in Kelvin, and P is the pressure in atmospheres.

At STP, the temperature is 273 K and the pressure is 1 atm. Therefore:

V(O2) = n(O2)(RT/P)

= 0.003348 mol * (0.0821 L·atm/mol·K * 273 K / 1 atm)

= 0.0744 L

= 74.4 cm³

So the volume of oxygen required to react with 150 cm³ of CO is 74.4 cm³. Since the initial volume of O2 was 80 cm³, the volume of O2 in excess is:

V(excess) = V(initial) - V(required)

= 80 cm³ - 74.4 cm³

= 5.6 cm³

Therefore, the volume of oxygen that was in excess is 5.6 cm³.

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Answer:

KBr final solution:

V = 250mL --> 0.25L

Concentration/Molarity = 1.5 mol/L

To find the amount of moles of KBr here, just multiply the volume by the concentration (0.25 x 1.5 = 0.375 mol)

So the amount of moles for KBr is 0.375 mol. Now we know that the mass divided by the molar mass (the atomic mass values of K and Br in the periodic table added together) would give us the amount of moles aswell.

n = moles

m = mass

M = molar mass

n = m/M

so if we rearrange this equation to find mass, we would get:

m = n x M

Molar mass for KBr: (39.09) of K + (79.90) of Br = 118.99

m = 0.375 mol    x    118.99

m = 44.62g

Therefore 44.62g of KBr is needed to make 250mL of a 1.5 M KBr solution.

The amount of zinc metal in grams consumed in the given reaction is 20.27g.

The mass of a substance in a stoichiometric calculation can be proceeded as follows;

According to this question, a sample of zinc metal reacts completely with an excess of hydrochloric acid. The number of moles of the hydrogen gas produced can be calculated thus;

PV = nRT

0.980 × 7.8 = n × 0.0821 × 298

7.644 = 24.47n

n = 0.31 moles.

In the reaction, 1 mole of zinc metal produces 1 mole of hydrogen gas. Hence, 0.31 moles of zinc metal will be required to produce 0.31 moles of hydrogen gas.

mass of Zn = 0.31 mol × 65.38g/mol = 20.27g

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An aqueous potassium carbonate solution is made by dissolving 6.29 moles of K₂CO₃ in sufficient water so that the final volume of the solution is 4.20L. The molarity of a solution is 1.50M.

Molarity is defined as the moles of solute present in the specific amount or volume of a solution. We calculate the moles of a substance using the formula

moles=(mass/molar mass)

If the volume of a solution is given in ml, then convert it into L.

Molarity is calculated as

Molarity=moles/volume(in L)

Given that moles=6.29, and volume=4.20L

Plug both values in the formula

Molarity=(6.29 mol/4.20 L)

Molarity=1.4976 mol/L

Molarity=1.50 M (∵M=mol/L)

Therefore, the molarity of a K₂CO₃ solution is 1.50M.

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Answer:i

i believe its contraction but i might be wrong

Explanation:

Answer:

It might be expansion, sorry if it's wrong.

Answer:

Density = \(20\ g/cm^3\)

Explanation:

Given that,

Mass of the object, m = 1000 g

Volume of the block, V = 50 cm³

We need to find the density of the object. Density is equal to mass per unit volume.

d = m/V

\(d=\dfrac{1000\ g}{50\ cm^3}\\\\=20\ g/cm^3\)

So, the density of the object is \(20\ g/cm^3\).