The reaction when solid ammonium fluoride (NHF) is put into water (H₂O) is NH₄F (s) + H₂O (l) → NH₄+ (aq) + F- (aq).
In this equation, (s) represents solid, (l) represents liquid, and (aq) represents aqueous (dissolved in water). The dissociation of ammonium fluoride into its ions in water results in the formation of a strong electrolyte solution that can conduct electricity.
This is because the ions in the solution are free to move and carry an electric charge, allowing the solution to conduct electrical current.
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What mass of fluorine-18 (F-18) is needed to have an
activity of 1 mCi? How long will it take for
the activity to decrease to 0.25 mCi?
To have an activity of 1 mCi, approximately 3.7 MBq (megabecquerels) of fluorine-18 (F-18) is needed. It will take approximately 28.2 hours for the activity to decrease to 0.25 mCi.
The decay of radioactive isotopes follows an exponential decay law, where the activity decreases over time.
The decay of F-18 follows this law, and its half-life is approximately 109.77 minutes.
To calculate the initial mass of F-18 required for an activity of 1 mCi, we can use the decay equation:
A(t) = A₀ * e^(-λt),
where:
A(t) is the activity at time t,
A₀ is the initial activity (1 mCi = 37 MBq),
λ is the decay constant (ln2 / half-life), and
t is the time.
First, let's calculate the decay constant:
half-life = 109.77 minutes
half-life = 1.8295 hours
λ = ln2 / half-life
λ is ≈ 0.693 / 1.8295
λ ≈ 0.3784 hours⁻¹.
Now, we can rearrange the decay equation to solve for A₀:
A₀ = A(t) / e^(-λt).
Given A(t) = 1 mCi = 37 MBq and t = 0 hours, we have:
A₀ = 37 MBq / e^(-0.3784 * 0)
A₀ ≈ 37 MBq.
Since 1 mCi is approximately 37 MBq, the required mass of F-18 is also approximately 37 MBq.
To calculate the time required for the activity to decrease to 0.25 mCi, we can rearrange the decay equation as follows:
t = (ln(A₀ / A(t))) / λ.
t = (ln(37 MBq / 9.25 MBq)) / 0.3784
t≈ 4 * (ln(4)) / 0.3784
t ≈ 28.2 hours.
Approximately 37 MBq of F-18 is needed to have an activity of 1 mCi. It will take approximately 28.2 hours for the activity of F-18 to decrease to 0.25 mCi.
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What are the conditions for STP?
Answer:
STP is Standard temperature and Pressure, which are o degrees C and 1.013 x 10^5 Pascals. At those values, one mole of any ideal gas occupies 22.41 litres.
7. What measures are applicable in the context of Nepal to push energy crisis further. Describe any three points clearly.
Answer:
which energy?........
Explanation:
..........................
........
....
# Problem
1.
The temperature of
8.4 L of SF6 is
changed from 919.3
K to 304 K. What is
the new volume of
the gas in milliliters?
Answer: 25.402 L
Explanation:
charles law
V2= V1 x T2/T1 = 8.4 x 919.3 / 304 = 25.402 L
Find how much mass is in 2.1 moles H2O
2.1 moles of \(H_2O\) will have a mass of 37.8 grams.
Moles and masses of substancesThe number of moles a substance contains and the mass of the substance are related by the following equation:
Mole = mass/molar mass
In other words, the mole of a substance is the ratio of the mass of the substance and its molar mass.
Rearranging the equation:
Mass = mole x molar mass.
In this case, we want to find the mass of 2.1 moles of water. The molar mass of water can be calculated as follows:
\(H_2O\) = (1 x 2) + 16
= 18 g/mol
Mass of 2.1 moles of water = 2.1 x 18
= 37.8 grams
In other words, 2.1 moles of water will have a mass of 37.8 grams.
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If the same large amount of heat is added to a 250 g piece of aluminum and a 150 g piece of aluminum, what will happen?
the chemical bond formed when two atoms share electrons is called
Answer:
covalent bond
...........
Explanation:
..............................
onsider the reaction A3+ (aq) + B+ (aq) = AB2+ (aq) A) In 1.00 Liter of water at equilibrium, there are 1.00 moles of A3+, 4.00 moles of B and 8.00 moles of AB2+(ag). What is the value for the equilibrium constant? B) Draw an image to represent this initial state. (below) C) At some time, t, 13.00 moles of ABCl2 is added, the volume change is negligible. ABC12 is a completely soluble compound that forms AB2+ (aq) and 2 Cl(aq) ions, the chloride ions are spectator ions and do not affect the equilibrium
A) The value of equilibrium constant is 2.00. B) The initial state represents 8.00 moles of AB2+. C) The reestablished equation is AB2+ particles react with the additional Cl- ions, resulting in the formation of ABCl2. D) The concentrations of A3+ and B+ would remain constant
A) In order to find the value of the equilibrium constant, K, we use the formula
Kc = [AB2+] / [A3+][B+]
Here, we are :[A3+] = 1.00 moles[B+] = 4.00 moles[AB2+] = 8.00 moles
Substituting the values into the equation, we get
Kc = [AB2+] / [A3+][B+]
Kc = 8.00 / (1.00 x 4.00)
Kc = 2.00
B) Since it's not possible to directly draw images here, I'll describe the initial state:
In the initial state, we have a 1.00-liter container filled with water. In the container, there are 1.00 moles of A3+ (represented as particles labeled "A"), 4.00 moles of B+ (represented as particles labeled "B"), and 8.00 moles of AB2+ (represented as particles labeled "AB" with a charge of 2+).
C) The first model to represent the occurrence when 13.00 moles of ABCl2 is added:
In the container, add 13.00 moles of ABCl2. ABCl2 dissociates into AB2+ (represented as particles labeled "AB" with a charge of 2+) and 2 Cl- ions. Therefore, you would have additional AB particles and 26.00 moles of Cl- ions. The overall charge of the system remains balanced.
The second model represents the reestablishment of equilibrium after the addition:
The AB2+ particles react with the additional Cl- ions, resulting in the formation of ABCl2 (represented as particles labeled "ABCl2"). This reaction consumes AB particles and Cl- ions until a new equilibrium is established. The equilibrium concentrations of A3+, B+, and AB2+ remain the same as initially.
D) The graph that represents the changes mentioned above would have concentration (or moles) on the y-axis and time on the x-axis. Initially, you would have a horizontal line representing the constant concentrations of A3+, B+, and AB2+. When the ABCl2 is added, there would be a sudden increase in the concentration of AB2+ and Cl- ions, represented by a step increase in the graph. As the reaction proceeds to reestablish equilibrium, the concentrations of AB2+ and Cl- ions would gradually decrease, represented by a decreasing slope on the graph until a new equilibrium is reached. The concentrations of A3+ and B+ would remain constant throughout, represented by horizontal lines.
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Complete question is:
"YOU DO: 1) Consider the reaction A3+ (aq) + B+ (aq) = AB2+ (aq) A) In 1.00 Liter of water at equilibrium, there are 1.00 moles of A3+, 4.00 moles of B and 8.00 moles of AB2+(ag). What is the value for the equilibrium constant? B) Draw an image to represent this initial state. (below) C) At some time, t, 13.00 moles of ABCl2 is added, the volume change is negligible. ABC12 is a completely soluble compound that forms AB2+ (aq) and 2 Cl(aq) ions, the chloride ions are spectator ions and do not affect the equilibrium, you do not have to include them in the diagram. Draw two models to represent this occurrence; one for the instant the substance was added and once to show the reaction reestablishing the equilibrium. Key A3+ (aq) Baq) AB2+ (aq) X Initial state Addition of AB2+ (aq) Reestablish the equilibrium D) Sketch a graph that represents the changes shown above."
The percent error was relatively high in this lab. There were several factors that may have caused this error. The transfer of heat from the burning Cheeto to the water was inefficient. Reasons for this were ______, _____, and _____. Since a great deal of heat from the Cheeto did not transfer to the water in the can, this would have accounted for the significant percent error.
The percent error was relatively high in this lab. There were several factors that may have caused this error. The transfer of heat from the burning Cheeto to the water was inefficient. The reasons for this were Deficiently contact between the Cheeto and the water, the Misfortune of being warm to the encompassing environment, and Inadequate combustion of the Cheeto.
There are a few reasons why the exchange of warmth from the burning Cheeto to the water within the can might have been wasteful, driving to a high percentage of mistakes within the lab. Here are three conceivable clarifications:
1. Deficiently contact between the Cheeto and the water:
In arranging for warmth to exchange from the burning Cheeto to the water, the two substances got to be in contact with each other.
On the off chance that the Cheeto was not completely submerged within the water, or in case it was not touching the sides of the can, at that point, the warm exchange would have been reduced. This seems to have been caused by the measure or shape of the Cheeto, or by the way it was situated within the can.
2. Misfortune of warm to the encompassing environment:
When warm is created by a chemical response (in this case, the burning of the Cheeto), it tends to disseminate into the encompassing discussion or materials.
This means that a few of the warm created by the Cheeto may have been misplaced in the discussion or to the metal of the can, instead of being exchanged for the water. This seems to have been exacerbated by variables such as a drafty room or a metal can that was not a great conductor of warmth.
3. Inadequate combustion of the Cheeto:
On the off chance that the Cheeto did not burn totally, at that point it would have created less warmth than it would have in the event that it had burned completely. This seems to have been caused by variables such as a more oxygen concentration within the can or deficient ventilation.
Furthermore, on the off chance that the Cheeto was not consistently burned, with a few parcels burning more totally than others, at that point the warm produced would not have been equitably disseminated all through the can, driving to less effective warm exchange.
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In CO2, how many UNSHARED pairs of electrons does each oxygen have?
a. 4
b. 6
c. 1
d. 2
explain why
Answer:
2, I believe.
Explanation:
In the cO2 molecule, each oxygen atom has two lone pairs of electrons. The carbon atom has no lone pairs.
Explanation:
In the cO2
molecule, each oxygen atom has two lone pairs of electrons. The carbon atom has no lone pairs. The carbon-oxygen bonds are double bonds.
which is the correct molecular structure for carbon dioxide
=> It is centrosymmetric and linear .
√so in that case carbon dioxide has no electric dipole.Explanation:
The central carbon atom is joined to two oxygen atoms by covalent double bonds
1. Analysis of a 50-g sample of a liquid compound composed of carbon, hydrogen, and nitrogen showed it to contain 9.5 g C, 3.40 g H, and 5.71 g N. What is the percent composition of Hydrogen?
The chemical contains 18.26% hydrogen in terms of percentage.
What is mass?A fundamental physical characteristic of matter is mass, which expresses how much matter is present in an item. It serves as a gauge for an object's resistance to acceleration, therefore the more massive an object, the more force is needed to move it.
How do you determine it?Calculating the total mass of the compound and the mass of the hydrogen in the compound is necessary to determine the percent composition of hydrogen in the compound.
mass of compound = sum of masses of carbon, hydrogen, and nitrogen.
mass of the mixture= 9.5 g + 3.40 g + 5.71 g
Mass of the compound= 18.61 g.
The compound's mass of hydrogen is:
mass of hydrogen=3.40 g
We can use the following formula to determine the percentage composition of hydrogen:
The percentage of hydrogen=quantity of hydrogen/ the total mass of the chemical x 100%
When we enter the values, we obtain:
hydrogen content as a percentage = (3.40 g/18.61 g) x 100% = 18.26%
Thus, 18.26% of the compound is hydrogen, according to its percent composition.
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Can someone help me with these please?
Answer:
Hex-3-ene of Question no 5
The reactants in a chemical reaction are shown below.
Li₂CO3 + H2SO4
Answer:
Li2SO4+H2CO3
Explanation:
put d equation this way
negative ions to positive ions
As you stare out the window after a rainstorm, you notice water drops on the window. Explain why those drops don’t stream down the window
uses three departments to produce plastic handles for​ screwdrivers: Mixing,​ Moulding, and Drying. The Assembly Department attaches the screwdriver shanks to the handles. Drying Department requires no direct materials. Conversion costs are incurred evenly throughout the drying process. Other process costing information​ follows:
The company uses the Mixing, Moulding, and Drying departments to produce plastic handles for screwdrivers. Each department incurs different costs, such as direct materials, direct labor, and conversion costs. By using process costing, the company can accurately determine the cost of production at each step.
The company uses three departments to produce plastic handles for screwdrivers: Mixing, Moulding, and Drying. The Assembly Department attaches the screwdriver shanks to the handles. In this process, the Drying Department does not require any direct materials.
Conversion costs are evenly incurred throughout the drying process.
Process costing is a method used to assign costs to each step of the production process. It helps track and allocate costs accurately. In this case, the company is using process costing to determine the cost of producing the plastic handles for screwdrivers.
Let's break down the process:
1. Mixing Department: This is where the raw materials are combined to create the plastic mixture. The costs incurred in this department include direct materials (raw materials used in the mixture) and direct labor (workers involved in the mixing process).
2. Moulding Department: Once the plastic mixture is ready, it is sent to the Moulding Department. Here, the plastic is shaped into handles using molds. The costs incurred in this department include direct materials (molds) and direct labor (workers involved in the molding process).
3. Drying Department: After the handles are molded, they need to be dried to remove any moisture. The Drying Department incurs conversion costs, which include indirect materials (utilities used for drying) and indirect labor (supervisors or maintenance staff involved in the drying process).
4. Assembly Department: Finally, the handles are sent to the Assembly Department, where they are attached to the screwdriver shanks. The costs incurred in this department include direct materials (screwdriver shanks) and direct labor (workers involved in the assembly process).
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match each statements with the state of matter it describes?
Answer:
Solid liquids , plasma gas
Explanation:
It retains its shape regardless of the shape of the container
Give the formula for the compound formed between the following ions:
Aluminum and hydroxide
2 pc
Answer:
Al(OH)3
Explanation:
-Aluminum hydroxide is an antacid. Aluminum hydroxide is used to treat heartburn, upset stomach, sour stomach, or acid indigestion. Aluminum hydroxide is also used to reduce phosphate levels in people with certain kidney conditions. Aluminum hydroxide may also be used for purposes not listed in this medication guide.
-Aluminium hydroxide is an inorganic basic compound used as an intermediary in organic synthesis and as an additive in pharmaceutical and fine chemical industries. Formula and structure: The aluminum hydroxide chemical formula is Al(OH)3 and its molar mass is 78.00 g mol-1.
what are consumers? what kind of animals are they.
Answer:
There are four types of consumers: omnivores, carnivores, herbivores and decomposers. Herbivores are living things that only eat plants to get the food and energy they need. Animals like whales, elephants, cows, pigs, rabbits, and horses are herbivores. Carnivores are living things that only eat meat.
Explanation:
a student adds 0.426 g of anhydrous sodium sulfate to his wet solution. what is the maximum amount of water that can be removed this way?
The maximum amount of water that can be removed from the wet solution using 0.426 g of anhydrous sodium sulfate is 0.54 g if all the anhydrous sodium sulfate combines with water, which corresponds to 0.03 mol of water.
Water can be drawn out of a solution using anhydrous sodium sulfate as a drying agent. Sodium sulfate decahydrate is created when anhydrous sodium sulfate is given to a moist solution through a reaction with the water molecules there. Depending on how much anhydrous sodium sulfate is added and how much water was initially present in the solution, the maximum amount of water that can be extracted from the mixture will differ.
The student in this instance react the moist solution with 0.426 g of anhydrous sodium sulfate. We first figure out how many moles of anhydrous sodium sulfate must be supplied, which comes out to 0.003 mol, in order to find the maximum amount of water that may be extracted. If all of the anhydrous sodium sulfate combines with water, the greatest amount of water that results is 0.54 g. However, the actual amount of water removed will depend on the original amount of water in the solution.
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What kind of change forms a new substance?
A. A solubility change
B. A chemical change
C. A phase change
D. A physical change
Answer:
B
Explanation:
Psychology is considered a science because it uses a systematic method of asking and answering questions true or false
Psychology is considered a science because it uses a systematic method of asking and answering questions true or false
It's true
Which is a characteristic of nuclear fission?
Question 1-7
In any chemical reaction, the mass of the reactants equals the mass of the products. This result forms the basis of the Law of
Conservation of Mass. Which statement correctly explains why this is a law, rather than a theory?
The law of conservation of matter says that in chemical reaction and the statement is the total mass of the product must equal the total mass of the reactant
The law of conservation of mass states that the mass in an isolated system is neither created nor destroyed by chemical reaction or physical transformation and according to the law of conservation of mass and the mass of the product in a chemical reaction must equal to the reactant that means total mass of the product must equal the total mass of the reactant
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The active ingredient in Tums is calcium carbonate. One Tums tablet contains 500 mg of calcium carbonate. If the Daily Value (DV) for Ca2+ to maintain bone strength in older women is 1500mg, how many Tums tablets are needed each day?
If the daily value for Ca is 1500 mg, the number of Tums tablets needed by older women each day would be 7.5 tablets.
Stoichiometric problemCalcium carbonate consists of calcium and carbonate ions as follows:
\(CaCO_3 -- > Ca^{2+} + CO_3^{2-}\)
Thus, for every 1 mole of calcium carbonate, 1 mole of calcium is involved.
Recall that: mole = mass/molar mass
500 mg of calcium carbonate would be equivalent to:
0.5/100 = 0.005 mol
The equivalent mole of calcium would also be 0.005 mol.
5 mol of calcium would be equivalent to:
0.005 x 40 = 0.2 grams or 200 mg of calcium.
This means that 1 Tums tablet, contains 200 mg of calcium. But 1500 mg is needed daily.
1500/200 = 7.5
This means that older women will need to take 7.5 tablets of Tums per day in order to meet up with the daily calcium requirement of 1500 mg.
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What is the heat of combustion of ethane, c2h6, in kilojoules per mole of ethane? enthalpies of formation can be found in the table of thermodynamic properties.
The heat of combustion of ethane (C2H6) in kilojoules per mole can be determined by subtracting the sum of the enthalpies of formation of the products from the sum of the enthalpies of formation of the reactants.
The enthalpy of formation is the change in enthalpy when one mole of a compound is formed from its constituent elements in their standard states. By referring to the table of thermodynamic properties, the enthalpies of formation for ethane (C2H6), carbon dioxide (CO2), and water (H2O) can be obtained.
The heat of combustion of ethane can be calculated using the following equation:
ΔHcomb = ΣΔHf(products) - ΣΔHf(reactants)
For the combustion of ethane, the reaction equation is:
C2H6 + 3.5O2 → 2CO2 + 3H2O
Using the enthalpies of formation from the table, the heat of combustion of ethane can be calculated.
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Helllpppppppppppppppppppp
Answer:
90% of people marry there 7th grade love. since u have read this, u will be told good news tonight. if u don't pass this on eight comments your worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say i love you.!
Explanation:
How does a liquid change as it is moved from one container to another?
When liquid is moved from one container to another, its shape, level, temperature, and composition may change depending on the properties of liquid and containers involved.
How does a liquid change as it is moved from one container to another?When liquid is moved from one container to another, its shape and volume may change depending on the properties of liquid and the containers involved.
If liquid is poured from one container to another, it may change its shape to fit the new container's shape. For example, if liquid is poured from a wide container to a narrow one, it will take the shape of the new container and become taller and narrower.
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What tool do you use to measure mass in chemistry?
Answer:
Balance Mass
Explanation:
It could be Balance Mass
an aluminum aerosol can will burst if the pressure inside reaches 210.0 psi. if the can initially contains an ideal gas at 518.0 kpa at 298.15 k, at what temperature (in k) will the can burst?
Assuming the container initially contains an ideal gas at 518.0 kpa at 298.15 k, the aluminium aerosol can will rupture when the internal pressure reaches 210.0 psi, whereas it will burst at 822.50 K.
Pressure is the force applied per unit area over the force perpendicular to an object's surface (symbol: p or P). The pressure as it relates to the air pressure around it is referred to as the gauge pressure. There are several different units used to express pressure. The behaviour of multiple ideal gas under varied conditions is accurately approximated by the ideal gas law in thermodynamics. The Charle's Law, Boyle's Law, and T2 = (298.15*14.29)/5.18sT2 = 822.50K empirical laws are all combined in the Ideal Gas Equation.
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