Answer:
100...................
Scientists have detected an asteroid that is 700,000,000 km from Earth. About how many astronomical units is that? 0. 5 AU 1 AU 3. 5 AU 4. 5 AU.
Answer:
it is 4.67921098559 astronomical units
Explanation:
An asteroid that is 700,000,000 km is equivalent to 4.67 AU.
Option D is the correct answer.
How do you convert KM into AU?Given that an asteroid that is 700,000,000 km from Earth.
We know that 1 AU is equal to 149597870.691 KM. The expression can be given below.
\(1 \;\rm AU = 149597870.691\;\rm KM\)
\(1 \;\rm KM = \dfrac {1}{149597870.691} \;\rm AU\)
\(700,000,000 \;\rm KM = \dfrac {1}{149597870.691} \times 700,000,000 \;\rm AU\)
\(700,000,000 \;\rm KM = 4.67 \;\rm AU\)
Hence we can conclude that 700,000,000 km is equivalent to 4.67 AU. Option D is the correct answer.
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A person standing on the top of a cliff kicks a football into projectile motion. The ball is kicked horizontally at an initial velocity of
15 m/s, and it reaches the bottom of the cliff some time after. If the height of the cliff is 50 m, how many seconds does the ball take
to reach the ground?
The ball takes 3.194 seconds to reach the ground.
What is projectile?Any object launched into space with only gravity acting on it is referred to as a projectile. Gravity is the main force affecting a projectile. This doesn't imply that other forces don't affect it; it merely means that their impact is far smaller than that of gravity.
A projectile's trajectory is its route after being fired. The projectile is something like a baseball that is batted or hurled.
Given parameters:
Initial horizontal velocity; u₁ = 15 m/s.
Height of the cliff: h= 50 m.
There has no initial vertical velocity and in vertical motion the object moves under acceleration due to gravity.
So, let t be the time taken by the football to reach the ground, then:
h = 1/2gt²
⇒ 50 = 1/2 × 9.8 × t²
⇒ t = √(2×50/9.8) = 3.194 s.
Hence, the ball takes 3.194 second to reach the ground.
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Exoplanet Period Looking back at the graph above, you can see that there are multiple times, during the 30 days of observation, when the planet passes in front of the star. The time between transit events is a direct measure of how long it takes the exoplanet to orbit the star (orbital period). Try to be as accurate as you can in determining the period of the two exoplanets. Question 5 2 pts The orbital period for Exoplanet A is------- days.
The orbital period for Exoplanet A is estimated to be 18.4 days based on the time between two transit events observed on the graph. This calculation assumes a regular and consistent orbital pattern, but the actual period may vary slightly due to factors like orbital eccentricity.
The first transit event occurs at day 10.5 on the graph. The second transit event occurs at day 28.9 on the graph. The time between these two events is 28.9 - 10.5 = 18.4 days.
It is important to note that this is just an estimate of the orbital period. The actual orbital period may be slightly different due to factors such as the eccentricity of the orbit.
Here are the steps I took to calculate the orbital period:
I identified the two transit events on the graph.I subtracted the time of the first transit event from the time of the second transit event.I rounded the result to the nearest whole number.The orbital period for Exoplanet A is 18.4 days.
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A 0.035 bullet strikes a 5kg wooden block that is stationary and gets stuck inside the block. The block and bullet move together at 8.6 m/s. What is the initial velocity of the bullet?
Answer:
1240 m/s
Explanation:
[Do you mean 0.035 kg bullet?]
Since the momentum of the system is conserved,
Let u m/s be the initial velocity of the bullet
0.035u = 8.6(5+0.035)
u ~= 1237.1714 m/s
u = 1240 m/s (3 sig. fig.)
A steam engine receives steam at 500 K. The engine used a part of this thermal energy for work. Exhausts the rest to a condenser at 250 K. What is the maximum efficiency of this steam engine? *
The maximum efficiency of the steam engine can be calculated using the formula: Efficiency = (1 - Tc/Th) x 100%. Therefore, the maximum efficiency of this steam engine is 50%, which means that half of the thermal energy received by the engine is used for work, and the other half is exhausted to the condenser.
Where Tc is the temperature of the condenser (250 K) and Th is the temperature of the steam (500 K).
So, Efficiency = (1 - 250/500) x 100% = 50%
To calculate the maximum efficiency of a steam engine, we will use the Carnot efficiency formula, which considers the input and output temperatures.
Step 1: Convert the input and output temperatures to Kelvin, if not already provided.
In this case, the input temperature (hot reservoir) is already given as 500 K, and the output temperature (cold reservoir) is given as 250 K.
Step 2: Apply the Carnot efficiency formula:
Carnot efficiency = 1 - (Tc/Th)
where Tc is the temperature of the cold reservoir, and Th is the temperature of the hot reservoir.
Step 3: Substitute the given values into the formula:
Carnot efficiency = 1 - (250 K / 500 K)
Step 4: Calculate the efficiency:
Carnot efficiency = 1 - (0.5) = 0.5
Step 5: Convert the efficiency to a percentage:
Maximum efficiency = 0.5 * 100% = 50%
So, the maximum efficiency of this steam engine is 50%.
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how is light reflected from a prism
Answer:
White light entering a prism is bent, or refracted, and the light separates into its constituent wavelengths. Each wavelength of light has a different colour and bends at a different angle. The colours of white light always emerge through a prism in the same order—red, orange, yellow, green, blue, indigo, and violet.
Question. 1 How much heat is necessary to warm 500g of water from 20°C to 65°C?
Answer:
The heat necessary to warm 500g of water from 20°C to 65°C is 37,620 J.
Explanation:
GIVEN: m = 500 gm, T₂ = 65°C AND T₁ = 20°C, we know that c (specific heat capacity) = 4180
TO FIND: The heat necessary to warm 500g of water from 20°C to 65°C.
SOLUTION:
By using the heat equation,
Q=m c ΔT
ΔT = T₂ - T1
ΔT = 65 - 20 = 45°C
In this case,
Q = 0.2 × 4180 × 45 = 37,620 J
A certain ideal gas has a molar specific heat of CV = 7/2 R. A 2. 00-mol sample of the gas always starts at pressure 1. 00×10⁵ Pa and temperature 300mK. For each of the following processes, determine(e) the energy added to the gas by heat. (i) The gas is heated at constant pressure to 400 K. (ii) The gas is heated at constant volume to 400 K. (iii) The gas is compressed at constant temperature to 1. 20×10⁵Pa(iv) The gas is compressed adiabatically to 1. 20×10⁵Pa
i) Therefore, the heat added to the gas when heated at constant pressure to 400 K is 14.9 kJ. iv) Therefore, the heat added to the gas when compressed adiabatically to 1.20×10⁵ Pa is 0.
Given data:
Molar specific heat of CV = 7/2 R2.00 mol of gas
Initial pressure, P1 = 1.00×10⁵ Pa
Initial temperature, T1 = 300 mK = 0.3 K
(i) Heating at constant pressure to 400 K
When a gas is heated at a constant pressure, the process is called isobaric process.
Initial pressure, P1 = 1.00×10⁵ Pa
Final temperature, T2 = 400 K
Heat added to the gas by formula is,
q = nCpΔT
where n = 2 mol of gas
Cp = molar specific heat of gas
Cp = CV + R
Cp = 7/2 R + R
Cp = 9/2 R
= (9/2) × 8.31 J/mol
K = 37.3 J/mol
KΔT = T2 - T1
KΔT = (400 - 0.3)
K = 399.7 K
Substitute the given values in the formula,
q = (2 × 37.3 J/mol K × 399.7 K)
q = 14.9 kJ
(ii) Heating at constant volume to 400 K
When a gas is heated at a constant volume, the process is called isochoric process. Initial volume,
V1 = nRT1/P1
V1 = (2 mol × 8.31 J/mol K × 0.3 K)/1.00×10⁵ Pa
V1 = 0.0498 m³
Final temperature, T2 = 400 K
Heat added to the gas by formula is,
q = nCvΔT
where n = 2 mol of gas
Cv = molar specific heat of gas
Cv = CV - R
Cv = 7/2 R - R
Cv = 5/2 R
Cv = (5/2) × 8.31 J/mol K
Cv = 20.8 J/mol
KΔT = T2 - T1
KΔT = (400 - 0.3)
K = 399.7 K
Substitute the given values in the formula,
q = (2 × 20.8 J/mol K × 399.7 K)
q = 16.6 kJ
Therefore, the heat added to the gas when heated at constant volume to 400 K is 16.6 kJ.
(iii) Compression at constant temperature to 1.20×10⁵Pa
When a gas is compressed at a constant temperature, the process is called isothermal process.
Final pressure, P2 = 1.20×10⁵ Pa
Heat added to the gas by formula is,
q = nRTln(P2/P1)
where n = 2 mol of gas
R = gas constant = 8.31 J/mol
Kln(P2/P1) = ln(1.20×10⁵/1.00×10⁵)
= ln(1.20)
= 0.182
q = (2 × 8.31 J/mol K × 0.182)
= 3.02 J
Therefore, the heat added to the gas when compressed at constant temperature to 1.20×10⁵ Pa is 3.02 J.
(iv) Compression adiabatically to 1.20×10⁵PaWhen a gas is compressed adiabatically, the process is called adiabatic process. Heat added to the gas in adiabatic process, q = 0
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The space between two metallic coaxial cylinders of length L = 0.450 m and radii a = 1.70 cm and b = 2.70 cm is completely filled with a material having a resistivity = 33.0 m. The figure below shows a cross section of the configuration.
The space between two metallic coaxial cylinders o
a) What is the resistance between the two cylinders? Give your answer with a unit of "Ohm".
b) Find the current between the two cylinders if a potential difference of 19.0 Volts is maintained between the two cylinders.
Please answer both parts and explain how you got the answer.
The resistance between the two cylinders is 2.13 Ohm. The current between the two cylinders if a potential difference of 19.0 Volts is maintained between the two cylinders 8.92 A.
Cylinder length = 0.450 m
Radii a = 1.70 cm
Radii b =2.70 cm
resistivity = 33.0 m
a) To estimate the resistance between the two cylinders, the resistance of a cylindrical conductor formula is used:
R = (ρL) / A
A = π(b^2 - a^2)
Substituting the above values in A:
A = \(π(2.7^2 - 1.7^2) × 10^-4 m^2\)
Now we can calculate the resistance:
R = (ρL) / A
R = \((33.0 × 0.450) / (π(2.7^2 - 1.7^2) × 10^-4)\)
R = 2.13 Ohm
b) To find the current between the two cylinders, we can use Ohm's Law.
I = V / R
Substituting the given values, we get:
I = 19.0 / 2.13
I = 8.92 A
Therefore, we can conclude that the current between the two cylinders is approximately 8.92 A.
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a child with a mass of 30 kg is standing on a spring scale in an elevator. if the spring scale reads 360 n, what are the magnitude and direction of the acceleration of the elevator at this time? the acceleration due to gravity is 10 m/s2 .
The acceleration of the elevator at this time was 2m/s² and the elevator was accelerating the upward direction.
The mass of the child standing on a spring scale in an elevator is 30 kg the elevator is showing a reading of 360 Newtons.
The reading note by the elevator is given by radiation,
W = M(g+a)
Where w is the reading of the spring scale,
M is the mass of the child,
g is the gravitational acceleration which is given to be 10m/s² and a is the acceleration of the elevator.
Putting values,
360 = 30(10+a)
12 = 10+a
a = 2m/s²
As you can see from the above result that the acceleration of the lift is 2m/s² and because it is positive it means that the elevator is accelerating in the upward direction.
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define mechanical advantage
Answer:
Mechanical advantage is a measure of the force amplification achieved by using a tool, mechanical device or machine system. The device trades off input forces against movement to obtain a desired amplification in the output force. The model for this is the law of the lever
Explanation:
A bookshelf is 2 m long, with supports at its ends (P and Q).
a)A book weighing 10 N is placed in the middle of the shelf. What are the upward forces at P and Q?
b)The book is moved so that it is 50 cm from Q. Use moments to calculate P the forces at P and Q.
c)The bookshelf weighs 10 N. Repeat parts b and taking into account
weight of the shelf as well as the weight of the book.
Answer:
a) P + Q = 2 P = 10 N P = Q = 5 N each exerts the same force
b) P x1 = Q x2 if x1 and x2 are not equal (torque about pivot point)
50 Q = 150 P or Q = 3 P balancing torques
Since P + Q = 10 Q = 7.5 N and P = 2.5 N
c) take torques about P
100 * 10 + 100 * 10 = 200 * Q
Q = 10 N P + Q = 20 N upward and the force on the fulcrum in the middle is 10 + 10 = 20 N down (10 N for shelf and 10 N for book)
a rock is dropped from a bridge and it hits the river 4.5 seconds later. How high is the bridge?
Answer:
99 meters
Explanation:
Apply the distance formula:
\( \displaystyle{s = ut + \dfrac{1}{2} g{t}^{2} }\)
where u is initial velocity which is 0 m/s since there is no initial velocity by dropping an object.
t is time which we know is 4.5 seconds. Finally, g is a constant of acceleration due to gravity which on Earth equals to 9.8 m/s². Therefore:
\( \displaystyle{s = 0 \cdot 4.5 + \dfrac{1}{2}(9.8) {(4.5)}^{2} } \\ \\ \displaystyle{s = \dfrac{1}{2}(9.8) {(4.5)}^{2} } \\ \\ \displaystyle{s \approx 99 \: \text{m}}\)
Therefore, the bridge is around 99 meters height.
A small block of mass m is given an initial speed vo up a ramp inclined at angle theta to the horizontal It travels a distance d up the ramp and comes to rest. Part A Determine a formula for the coefficient of kinetic friction between block and ramp. Part B What can you say about the value of the coefficient of static friction?
To determine the coefficient of kinetic friction (μ_k) between the block and the ramp, we can use the formula:
μ_k = tan(θ)
We can say that the value of the coefficient of static friction (μ_s) is greater than or equal to the coefficient of kinetic friction (μ_k), which is given by μ_s ≥ μ_k.
How to determine the equationSum of forces parallel to the ramp - frictional force = 0
The sum of forces parallel to the ramp is mg*sin(theta), so we can write:
mg*sin(theta) - f = 0
Solving for the frictional force (f), we get:
f = mg*sin(theta)
The coefficient of kinetic friction (μ_k) is defined as the ratio of the frictional force to the normal force:
μ_k = f / N
Substituting the value of f from the equation above and N = mg*cos(theta), we have:
μ_k = (mgsin(θ)) / (mgcos(θ))
μ_k = tanθ)
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An observer standing near a window 5 m high observe that an object falling downwards is passing across the window in 0.5 s. Find at what height above the window the object was dropped. (g = 10 m/s2).
Answer:
Explanation:
An object in free fall, NOT experiencing parabolic motion, has an equation of
\(h(t)=\frac{1}{2} gt^2+h_0\) which says:
The height of an object with respect to time in seconds is equal to the pull of gravity times time-squared plus the height from which it was dropped. Normally we use -9.8 for gravity but you said to use 10, so be it.
For us, h(t) is 5 because we are looking for the height of the window when the object is 5 m off the ground at .5 seconds;
g = 10 m/s/s, and
t = .5sec
\(5=\frac{1}{2}(-10)(.5)^2\)+h and
5 = -5(.5)² + h and
5 = -5(.25) + h and
5 = -1.25 + h so
h = 6.25
That's how high the window is above the ground.
Height above the window object was dropped is 6.25 m
Given:
Height of window = 5 m
Time taken to drop object = 0.5 sec
Gravitational acceleration = 10 m/s²
Find:
Height above the window object was dropped
Computation:
We know that;
\(H(T) = \frac{1}{2}(g)(t^2) + H(S)\\\\5 = \frac{1}{2}(10)(0.5^2) +H(S)\\\\5 = (5)(0.5^2)+H(S)\\\\H(S) = 6.25\)
So,
Height above the window object was dropped = 6.25 m
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A block of mass 0.10kg is attached and secured to one end of a spring with spring constant 50N/m. The other end of the spring is secured to a wall. The block is pushed against the spring, which compresses the spring to a position of x=−0.04m. When uncompressed, the end of the spring that is attached to the block is at a position of x=0.00m . The block-spring system is then released from rest, and the block travels along a horizontal, rough track. A motion sensor is placed so that it measures the velocity of the object as it slides along the track. A graph of total mechanical energy of the block-spring system as a function of position is shown. Which of the following statements about the block-spring system are true? Select two answers.
The other end of the spring is secured to a wall. The block is pushed against the spring, which compresses the spring to a position of x=-0.04x=−0.04 m.
What is compress process?Compression is a process under which volume of the system is gradually reduced, pressure and temperature increases where heat transfer may or may not be possible. While in expansion process volume is gradually decrease with the decrease in pressure and temperature and heat transfer may or may not be possible.
Does compress mean pressure?Compression force or the compressive force occurs when the physical pressure pushes inward on a particle making it compacted. During this phenomenon, the relative position of the molecules and the atom of a particle changes rapidly.
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What is the main power and purpose of the legislative branch?
i always need help with physics
Answer:
House and Senate.
Explanation:
declares war, regulates interstate and foreign commerce and controls taxing and spending policies.
A charged sphere is near an uncharged sphere. Does the charged sphere exert a force on the uncharged sphere? If so, what is the direction of the electric force the charged sphere exerts on the uncharged sphere? Select One of the following: (a) No net force is exerted on the uncharged sphere. (b) The uncharged sphere is attracted by the charged sphere. (c) The uncharged sphere is repelled by the charged sphere. (d) The uncharged sphere may be either attracted or repelled by the charged sphere.
Yes, a charged sphere does exert a force on an uncharged sphere. This is because the charged sphere creates an electric field, which can influence nearby objects.
The direction of the electric force that the charged sphere exerts on the uncharged sphere depends on the polarity of the charged sphere. If the charged sphere is positively charged, it will attract the electrons in the uncharged sphere, causing the uncharged sphere to become polarized with a net negative charge on the side closest to the positively charged sphere. This results in an attractive force between the two spheres.
On the other hand, if the charged sphere is negatively charged, it will repel the electrons in the uncharged sphere, causing the uncharged sphere to become polarized with a net positive charge on the side closest to the negatively charged sphere. This results in a repulsive force between the two spheres.
Therefore, the correct answer is (d) The uncharged sphere may be either attracted or repelled by the charged sphere, depending on the polarity of the charged sphere.
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The uncharged sphere is attracted by the charged sphere.
When a charged sphere is near an uncharged sphere, it creates an electric field in its surroundings.
The uncharged sphere, being neutral, experiences an electric force when placed in the electric field generated by the charged sphere.
According to Coulomb's Law, opposite charges attract each other, so the uncharged sphere will be attracted towards the charged sphere.
Therefore, the charged sphere exerts a force on the uncharged sphere, and the direction of the electric force is towards the charged sphere, resulting in attraction.
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A roller coaster goes from 2.00 m/s [forward] to 10.0 m/s [forward) in 4.50 s. What is its acceleration?
How earth's magnetic field is taken as uniform magnetic field ?
Answer:
It is in contact with two vertical rails which are joined at the top. The rails are without friction and resistance. There is a horizontal uniform magnetic field of magnitude B perpendicular to the plane of the ring and the rails.
Explanation:
Not sure if this is correct but pls give thanks anyway!
what is temperature and how did we create the celsius scale
Answer:
the degree of hotness or coldness of a body is called temperature
Explanation:
we can create Celsius scale by
that rule
A tennis ball is dropped off of some stadium bleachers. If the ball was in free fall for 3
seconds, how high were the bleachers( how far did the tennis ball fall)? For acceleration
due to gravity on Earth use 10 m/s².
The height of the bleachers when a tennis ball dropped from the top and takes 3 seconds in flight is 45 m.
What is height?
Height can be defined as the vertical distance between two points.
To calculate the height of the bleachers, we use the formula below.
Formula:
H = ut+gt²/2............ Equation 1Where:
H = Height of the bleachersu = Initial velocity of the tennis ballt = Timeg = Acceleration due to gravityFrom the question,
Given:
u = 0 m/st = 3 secondsg = 10 m/s²Substitute these values into equation 1
H = (0×3)+(10×3²)/2H = 45 m.Hence, the height of the bleachers is 45 m.
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An instant soup is very low in fat and calories but high in sodium. Can this food be labeled “ healthy”?
Answer:
no
Explanation:
it is not healthy because sodium is not good to our body
No it is not healthy.
The following information should be considered:
The instant soup is the processed food and it have the expire time of about 6 months.If we make the soup homemade than it will be okay for only 1 or 2 foods. Also it is high in sodium.Learn more: brainly.com/question/17429689
correct answer will be marrk as braineast answer
Answer:
d) harvesting and threshing both.
Explanation:
Hope it helps you...
Which equation is perpendicular to the line
(1901
y = 3 and passes through the point (- 1, 3).
a. x = 3
b. y = 3
c. y = -1
d. X = -1
The equation perpendicular to the line is y=3.
The slope of the line \($3 x+y=3$\) is \($m=-3$\)
Hence slope of the perpendicular line is \($\mathrm{m}^{\prime}=\frac{1}{3}$\)
Therefore the equation of a perpendicular line is
Therefore the equation of a perpendicular line is
\($(\mathrm{y}+1)=\frac{1}{3}(\mathrm{x}-3) $\)
\((y+3)=\frac{1}{3}(x-1)\)
Switch sides
\(\frac{1}{3}(x-1)=(y+3)\)
\($\frac{1}{3}(x-1)=y+3$\)
Multiply both sides by 3
\($3 \cdot \frac{1}{3}(x-1)=3 y+3 \cdot 3$\)
Simplify
\($x-1=3 y+9$\)
Add 1 to both sides
\($$x-1+1=3 y+9+1$$\)
Simplify
\($$x=3 y+10$$\)
y= 3.33 (Approx 3)
The two different lines that cross each other at a 90° angle are called perpendicular lines. Have you observed any similarities between the walls' intersecting corners, such as the letter "L"? They are parallel lines, which are straight lines that cross each other at the proper angle.
If two lines cross at a 90° angle, we say that they are perpendicular to one another.
the vertex's matching angle is a right angle. All crossing lines are not necessarily perpendicular to one another, but perpendicular lines always cross each other. Perpendicular lines have two key characteristics.
In every case, perpendicular lines cross or intersect.
Any two perpendicular lines will always intersect at an angle of 90 degrees.
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3. A dog walks a distance of 100 ft. in 20 s of time. What is the dog's
speed in feet per second?
O C 120 ft/s
O B80 ft/s
O D 2000 ft/s
O A 5 ft/s
Where did all the golden carals go?
Answer:
Thanos went *snap*
Explanation:
Saturn is approximately 10 times as far away from the sun as the earth. This means that its orbital acceleration is _____ that of the earth. A. 1/10 B. 1/100 C. 1/1000 D. 1/10,000
Saturn is approximately 10 times as far away from the sun as the Earth. This means that its orbital acceleration is 1/10,000 that of the Earth.
The orbital acceleration of a planet depends on its distance from the sun according to Newton's law of universal gravitation. According to this law, the gravitational force between two objects is inversely proportional to the square of the distance between them.
Considering that the orbital acceleration is directly proportional to the gravitational force, and the gravitational force is inversely proportional to the square of the distance, it can be concluded that the orbital acceleration of Saturn is 1/10,000 times that of the Earth.
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when you grip the steering wheel, you should place your hands on the steering wheel at the 3 and 9 or 4 and 8 o'clock positions to allow room for air bags to deploy.
According to the information we can infer that it is true that when we grip the steering wheel, we should place our hands on the steering wheel at the 3 and 9 or 4 and 8 o'clock positions to allow room for airbags to deploy.
How to determine if the declaration is true?To determine if the declaration is true we have to look for some information related with the position of our hands while we drive a car. In this case we can conclude that when gripping the steering wheel some experts recommend to place your hands at the 3 and 9 o'clock positions or the 4 and 8 o'clock positions.
The main reason to use these positions is because these allow us to get a better control and also ensure that there is enough space for the airbags to deploy in case of an accident.
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How is the input energy carried to the light bulb's energy stores?
Answer:
the electric energy travels through the plug or wire or whatever is connecting the energy source to the lightbulb, which conducts electricity, and to the light bulb. the electric energy is transfered into light energy and thermal energy
Explanation:
i hope i understood this question and answered it correctly XD