Suppose a 20.0 g gold bar at 35.0°C absorbs 70.0 calories of heat energy. Given that the specific heat of gold is 0.0310 cal/g °C, what is the final
temperature of the gold bar?

Answers

Answer 1

We know, change in temperature is given by :

\(T_2-T_1=\dfrac{q}{mC_p(Gold)}\)

Putting all given values, we get :

\(T_2-T_1=\dfrac{70\ cal}{20\ g\times 0.0310\ cal/g^o\ C}\\\\T_2-T_1=112.90^oC\\\\T_2-35^oC=112.90^oC\\\\T_2=(112.90+35)^oC\\\\T_2=147.9^oC\)

Hence, this is the required solution.


Related Questions

A hospital saline solution is analyzed to confirm its concentration. A 50.0 mL sample with a mass of 50.320 g is evaporated to dryness. If the solid sodium chloride residue has a
mass of 0.669 g. what is the mass percent and molar concentration of the saline solution?

Answers

The mass percent of the sodium chloride in the saline solution is approximately 1.33%. The molar concentration of the saline solution is approximately 0.229 M.

To determine the mass percent and molar concentration of the saline solution, we need to analyze the mass of the sodium chloride residue and the initial mass of the sample.

Mass percent:

The mass percent is calculated by dividing the mass of the sodium chloride residue by the initial mass of the sample and then multiplying by 100%.

Mass percent = (Mass of NaCl / Initial mass of sample) × 100%

Mass of NaCl = 0.669 g

Initial mass of sample = 50.320 g

Mass percent = (0.669 g / 50.320 g) × 100% ≈ 1.33%

The mass percent of the sodium chloride in the saline solution is approximately 1.33%.

Molar concentration:

To calculate the molar concentration of the saline solution, we need to determine the number of moles of sodium chloride and the volume of the solution.

Moles of NaCl = Mass of NaCl / Molar mass of NaCl

The molar mass of NaCl is 58.44 g/mol.

Moles of NaCl = 0.669 g / 58.44 g/mol ≈ 0.01144 mol

Since the volume of the sample is given as 50.0 mL, we need to convert it to liters.

Volume of solution = 50.0 mL = 50.0 mL × (1 L / 1000 mL) = 0.0500 L

Now we can calculate the molar concentration (Molarity) using the formula:

Molarity (M) = Moles of solute / Volume of solution (in liters)

Molarity = 0.01144 mol / 0.0500 L ≈ 0.229 M

The molar concentration of the saline solution is approximately 0.229 M.

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Heart, 5 stars, and Brainiest to first right answer!

Which of these is a likely impact of stronger than normal trade winds in the Pacific Northwest of the United States?
A. Jet stream would be displaced northwards causing drought
B. Jet stream would be displaced southwards causing drought
C. Jet stream would be displaced southwards causing heavy rain and flooding
D. Jet stream would be displaced northwards causing heavy rain and flooding

Answers

I think correct answer is C.Jet stream would be displaced southwards causing heavy rain and flooding

The statement that is a likely impact of stronger than normal trade winds in the Pacific Northwest to the United States is Jet stream would be displaced southwards causing heavy rain and flooding.

Which one of the following statements about balanced is true? A reaction is balanced by

Answers

Just helping the community
Which one of the following statements about balanced is true? A reaction is balanced by

Suppose that you have 70 grams of calcium chloride (CaCl2) contaminated with 5% sodium chloride (NaCl) and 2% sand. You dissolve the impure solid in 54 ml of hot water, and allow it to cool and crystallize. What would be the maximum mass (grams) of purified CaCl2 that would you would be able to recover

Answers

Answer:

65.1 grams

Explanation:

The percentage of impurities in the contaminated CaCl₂ sample is:

% of NaCl + % of sand = 7%

Meaning that the purity of the sample is (100 - 7) 93%.

Now we calculate the mass of pure CaCl₂ in the contaminated sample:

70 g * 93/100 = 65.1 g

Thus the answer is 65.1 grams, as that amount is how much CaCl₂ is in the sample and it would be impossible to obtain more than that.

HELP NEEDED!!!!
The volume of a gas is 760 ml. The temperature changes from 20 oC to 40 oC. What will be the new volume?
A. 1520 ml
B. 1220 ml
C. 812 ml
D. 612 ml

Answers

The answer for this question is A. 1520ml... by using Charles law.. l hope it helped?? :)

Consider a triangle ABC like the one below. Suppose that C=83°, a = 43, and b = 44. Solve the triangle.
Carry your intermediate computations to at least four decimal places, and round your answers to the nearest tenth.
If there is more than one solution, use the button labeled "or".

Consider a triangle ABC like the one below. Suppose that C=83, a = 43, and b = 44. Solve the triangle.Carry

Answers

Answer:

Explanation:

   In a triangle

a / sin A = b / sinB = c / sinC

Putting the values

43 / sin A = 44 / sinB

sinA / sinB = 43 / 44 = 1 / 1.023

A + B = 180 - 83 = 97

sinA / sin ( 97 - A ) = 1 / 1.023

sin 97 cos A - cos 97 sin A = 1.023 sin A

= .9925 cos A + .122 sin A = 1.023 sin A

.9925 cos A = .901 sin A

squaring

.985 cos²A = .8118 sin²A

.985 - .985 sin²A = .8118 sin²A

.985 = 1.7968 sin²A

sinA = .74

A = 47.73

B = 49.27

c / sin C = b / sin B

c = b sinC / sinB

= 44 x sin 83 / sin 49.27

= 44 x .9925 / .7578

= 57.62

Based on the thermodynamic properties provided for water, determine the energy change when the temperature of 0.950 kg of water decreased from 103 °C to 60.5 °C.

Property Value Units
Melting point 0 °C
Boiling point 100.0 °C
ΔHfus 6.01 kJ/mol
ΔHvap 40.67 kJ/mol
cp (s) 37.1 J/mol · °C
cp (l) 75.3 J/mol · °C
cp (g) 33.6 J/mol · °C

Answers

The energy change when the temperature of 0.950 kg of water decreased from 103 °C to 60.5 °C is 2308.87 kJ.

What is the heat energy change when the temperature of 0.950 kg of water decreased from 103 °C to 60.5 °C?

The heat energy change when the temperature of 0.950 kg of water decreased from 103 °C to 60.5 °C is determined from the formulas below:

Heat change 1 = Heat capacity as gas * moles * temperature change

Heat change 2 = Heat of vaporization, ΔHvap * moles

Heat change 3 = Heat capacity as liquid, Cp (l) * moles * temperature change

moles of water = 950 kg * 1000 g/kg * 1 mol/ 18g = 52.78 mole

Heat change 1 = 33.6 * 52.78 * (103 - 100) = 5320.224 J

Heat change 2 = 40.67 * 1000 * 52.78 = 2146562.6 J

Heat change 3 = 75.3 * 52.78 * (100 - 60.5) = 156986.193 J

Total heat change = 5320.224 J + 2146562.6 J + 156986.193 J

Total heat change = 2308869.017 J = 2308.87 kJ

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Write a balanced chemical equation for the complete combustion of methane to produce CO2(g) as the only carbon-containing product.

Answers

Answer:

CH4(g)+2O2(g)→CO2(g)+2H2O(g)

Explanation:

For a complete combustion reaction of a hydrocarbon, oxygen is always one of the reactants, and the products are always carbon dioxide and water.

To solve such this we must know the concept of combustion reaction. The balanced reaction of methane and oxygen can be written as:

CH\(_4\)(g)+2O\(_2\)(g)→CO\(_2\)(g)+2H\(_2\)O(g)

What is Balanced equation?

Balanced equation is the one in which the total number of atoms of a species on reactant side is equal to the total number of atoms on product side. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, displacement reaction.

Combustion reaction is a type of combination reaction. The reaction between methane and oxygen is example of combustion  reaction. The products are carbon dioxide and water and energy.

CH\(_4\)(g)+2O\(_2\)(g)→CO\(_2\)(g)+2H\(_2\)O(g)

Therefore, the balanced equation is

CH\(_4\)(g)+2O\(_2\)(g)→CO\(_2\)(g)+2H\(_2\)O(g)

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Why is a rotting apple a reaction in which energy is neither absorbed nor released?
A. The chemical energy in the reactants is almost equal to the chemical energy in the products.
B. The chemical energy in the reactants is much greater than the chemical energy in the products.
C. The chemical energy in the reactants is much less than the chemical energy in the products.
( don’t send links, I won’t click them)

Answers

I don’t know the answer but ik it is due to oxidation rooting apple is a reaction but it neither absorb or release energy

Good's buffers are compounds that are useful near neutral pH. MES buffer has pKa of 6.15, MOPS has pKa of 7.5, and HEPPS has pKa of 8.0.Required:Identify which Good's buffers are most effective near pH 7.0 and near pH 6.0.

Answers

Answer:

MES for pH near to 6.0 and MOPS for pH near to 7.5.

Explanation:

Hello,

In this case, given that the Henderson-Hasselbach equation is:

\(pH=pKa+log(\frac{[Base]}{[Acid]} )\)

Good's buffers are those having pKa's near to the required pH since we look for a [Base]/[Acid] ratio to approach 1, thus, for a pH near to 7.0 a good buffer may be MOPS as it has a pKa of 7.5 and for a pH neat to 6.0 a good buffer may be MES as it has a pKa of 6.15.

Best regards.

how many electrons do nonmetals atoms tend to gain when forming ions

Answers

Since nonmetals have five, six, or seven electrons in their valence shells, it takes less energy to gain the necessary electrons, and therefore form anions.

zn zn2+ + 2e oxidation or reduction; what are the redox reactions that take place?; zn(s) + 2hcl(aq) → zncl2(aq) + h2(g); oxidation can also be defined as the loss of oxygen atoms and/or the gain of hydrogen atoms; the first step when balancing redox reaction involves:; hcl reduction half reaction; cu half reaction; acetone redox reaction

Answers

Zn (s) + 2 HCl (aq) --→ ZnCl2 (aq) + H2 (g) Zn being oxidized during the reaction: Correct answer is 1. oxidized. Zn's oxidation status is shifting from 0 to +2.

A chemical process called oxidation occurs. As a result of atoms or groups of atoms losing electrons, it is described as a process. The addition or loss of oxygen or hydrogen in a chemical species is another method to define oxidation. An oxidation reaction takes place when oxygen interacts with a substance or an element. Another way to think of oxidation is as the process of removing hydrogen from the species of reactants. Molecule, atom, or ion oxidation is the process of losing electrons. Initially, reactions where an element interacts with oxygen were referred to as oxidations. For instance, the chemical interaction between magnesium metal and oxygen to produce magnesium oxide is the oxidation of magnesium.

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Acetic acid (HC2H3O2) is the active ingredient in vinegar. Calculate the mass percent composition of H in acetic acid.
Express the mass percent composition to four significant figures.

Answers

The molecular weight of acetic acid is:

2(12.01 g/mol) + 2(1.01 g/mol) + 4(16.00 g/mol) = 60.05 g/mol

The mass of one H atom in acetic acid is:

2(1.01 g/mol) = 2.02 g/mol

To calculate the mass percent composition of H in acetic acid, we divide the mass of H by the molecular weight of acetic acid, and then multiply by 100:

mass percent composition of H = (2.02 g/mol / 60.05 g/mol) x 100% = 3.36%

So that means, the mass percent composition of H in acetic acid is 3.36%, expressed to four significant figures.

Which of the following upon reacting with oxygen would form the greatest amount of carbon dioxide? a) n-pentane b) isopentane c) neopentane d) two of the above would form equal amounts e) all (a-c) of the above would form equal amounts

Answers

Upon reacting with oxygen would form the greatest amount of carbon dioxide e) all (a-c) of the above would form equal amounts.

Isomer are compound which are same molecular formula but different structural formula. The isomers of pentane are n-pentane, isopentane and neopentane, they have same molecular formula but the arrangement of atoms is different. Pentane is an organic compound with the formula C5H12—that is, an alkane with five carbon atoms.

Thus, Upon reacting with oxygen would form the greatest amount of carbon dioxide will be the same in all isomers.

Thus, the correct option is e.

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Help Please!! (The Question is in the picture!)

Help Please!! (The Question is in the picture!)

Answers

Answer:

the answer that best describe the two methods is c

How many hydrogen atoms are there in 2.25 moles of H2CO3?

Answers

Answer:

4.5moles

Explanation:

2.25moles times 2 hydrogen atoms per one molecule

The number of hydrogen atoms present in 2.25 moles of hydrogen carbonate is 4.5.

What is a mole?

A mole of a compound is equivalent to the one formula unit of the compound. The number of atoms of each element in a mole of the compound can be given from the formula unit.

1 unit of hydrogen carbonate consists of 2 atoms of hydrogen. Thus, 1 mole of hydrogen carbonate has 2 hydrogen atoms.

The number of hydrogen atoms in 2.25 mole of hydrogen carbonate can be given as:

\(\rm 1\;mol\;H_2CO_3=2\;atoms\;Hydrogen\\2.25\;mol\;H_2CO_3=2.25\;\times\;2\;atoms\;of\;hydrogen\\2.25\;mol\;H_2CO_3=4.5\;atoms \;of\;Hydrogen\)

The number of hydrogen atoms present in 2.25 moles of hydrogen carbonate is 4.5.

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density of a liquid if 500.cm3 weighs 752.0 g​

Answers

Explanation:

jrjrji8 que se ha dicho nada. pero si lo que se le puede dar un paseo de la ciudad, y el 5 que se le puede pasar por alto

Polonium-214 has a relatively short half-life of 164 seconds. How many seconds would it
take for 8,0 g of this isotope to decay to 0.25 g?

Answers

Answer:

820 Seconds Or 5 Periods

Explanation:

A 75.0- mL
volume of 0.200 M
NH3
( Kb=1.8×10−5
) is titrated with 0.500 M
HNO3
. Calculate the pH
after the addition of 17.0 mL
of HNO3
.

Answers

Answer:

ok, here is your answer

Explanation:

i am going to solve this problem by using the ICE table method which is an easy method to determine the pH of a weak base with the given data of the problem.Given:Initial volume of NH3 solution (Vi) = 75.0 mLInitial concentration of NH3 solution (Ci) = 0.200 MInitial moles of NH3 solution (Ni) = Ci x Vi = 0.200 M x 75.0 mL = 0.0150 molesKb = 1.8 x 10^-5Moles of HNO3 added (n) = 0.500 M x 17.0 mL = 0.00850 molesVolume of NH3 solution after the addition of HNO3 (Vf) = 75.0 mL + 17.0 mL = 92.0 mLConcentration of NH3 solution after the addition of HNO3 (Cf) = Ni / Vf = 0.0150 moles / 92.0 mL = 0.163 MTo find the pH after the addition of 17.0 mL of HNO3, we need to use the ICE table method.ICE table method:Initial: NH3 + H2O ⇌ NH4+ + OH-Change: -x 0 +x +xEquilibrium: 0.0150 - x 0 x xKb = [NH4+][OH-] / [NH3]1.8 x 10^-5 = x^2 / 0.163Solving for x, x = 0.00171 M[OH-] = 0.00171 M[OH-] = Kw / [H3O+] = 1.0 x 10^-14 / [H3O+][H3O+] = 5.85 x 10^-12pH = -log[H3O+]pH = -log(5.85 x 10^-12)pH = 11.23Therefore, the pH after the addition of 17.0 mL of HNO3 is approximately 11.23.

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what mass of water is produced from 2.5g of glucose?

Answers

From the calculation, there are 1.5 g of water produced in the reaction.

What is an equation?

An equation shows the chemical transformation that takes place in a reaction vessel. In this case, the equation is; C6H12O6 + 6 O2 --> 6 CO2 + 6 H2O.

Now;

Number of moles of glucose = 2.5g/180 g/mol = 0.014 moles

Since 1 mole of glucose produces 6 moles of water

0.014 moles of glucose produces 0.014 moles * 6 moles/ 1 mole

= 0.084 moles

Mass of water produced = 0.084 moles * 18 g/mol = 1.5 g of water

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why does the ratio of chloride ions to calcium ions is 2:1 when calcium chloride forms

Answers

This is the formula because Calcium has a charge of +2 and Chloride ion has a charge of -1 so when they combine to be neutral you need two chloride ions to even out the +2 charge of the Calcium.

A pharmacist quizzes a pharmacy intern on the aliquot method in the preparation of 12 capsules each to contain 80 mg of morphine sulfate and 3.2 mg of naltrexone hydrochloride. Lactose is to be used as a diluent, a prescription balance with a sensitivity of 6 mg is proposed, and a 4% error is acceptable. Provide the relevant calculations.

Answers

To prepare 12 capsules each containing 80 mg of morphine sulfate and 3.2 mg of naltrexone hydrochloride, the following calculations can be used:

Calculate the total weight of the morphine sulfate and naltrexone hydrochloride: 80 mg + 3.2 mg = 83.2 mg

Calculate the weight of the diluent required: 12 capsules * 83.2 mg/capsule = 999.6 mg

Calculate the volume of the diluent required based on its density (assume a density of 0.9 g/mL for lactose): 999.6 mg / (0.9 g/mL) = 1.11 mL

Calculate the weight of the diluent required based on its volume: 1.11 mL * 0.9 g/mL = 1 g

Calculate the amount of the diluent required based on the sensitivity of the prescription balance: 1 g / (6 mg/g) = 166.7 mg

The amount of the diluent required according to this calculation is 166.7 mg. This amount should be rounded up to the nearest whole number (167 mg) to account for the 4% error tolerance. The final aliquot would therefore contain 167 mg of lactose, 80 mg of morphine sulfate, and 3.2 mg of naltrexone hydrochloride.

In one to two sentences, explain how this reaction demonstrates that matter is neither created nor destroyed in a chemical reaction.

In one to two sentences, explain how this reaction demonstrates that matter is neither created nor destroyed

Answers

Since the number of atoms which are reacting are equal to the number of to the number of atoms in the product, this reaction demonstrates that matter is neither created nor destroyed in a chemical reaction.

What is the principle of matter conservation?

Any system that is closed to all exchanges of matter and energy is subject to the law of conservation of matter, which is a general law of physics and chemistry. This law states that regardless of how the components rearrange themselves, the mass of an object or group of things remains constant over time.

A chemical reaction is what?

A chemical reaction is a procedure that causes one group of chemical components to change chemically into another. Chemical reactions, which can frequently be described by a chemical equation, traditionally include changes that solely affect the locations of electrons in the formation and dissolution of chemical bonds between atoms, with no change to the nuclei.

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Draw the structure of the tripeptide Gly-Gly-His. It has a role as a metabolite. Then determine the total charge of the tripeptide.

Answers

The molecular formula for tripeptide Gly-Gly-His is C10H15N5O4. The structure is attached below in the picture. It has a role as a metabolite.

A tripeptide is created by combining three amino acids, and it is then joined by two or even three peptide bonds. The order of the individual amino acids that make up a peptide dictates how it functions, just like with proteins. The simplest tripeptide is glycine. The most significant tripeptide, according to scientific studies, is glutathione (-L-Glutamyl-L-cysteinylglycine), which has a number of functions in a wide range of life forms.

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Draw the structure of the tripeptide Gly-Gly-His. It has a role as a metabolite. Then determine the total

Question
The weak base pyridine, C5H5N, is added to water to make up a solution of 0.248 M pyridine in water. The Kb of pyridine
is 1.7 x 109. What is the pH of the solution?
• Round your answer to two decimal places.

Sorry, that's incorrect. Try again?
11.56

Answers

The pH of the solution is approximately 4.84.

To find the pH of the solution, we need to calculate the concentration of hydroxide ions (OH-) and then convert it to the pH scale.

First, let's determine the concentration of hydroxide ions (OH-) using the Kb value and the concentration of pyridine (C5H5N).

Kb = [OH-][C5H5N] / [pyridinium ion]

Since pyridine is a weak base, we can assume that the concentration of pyridinium ion is negligible compared to the concentration of pyridine. Therefore, we can simplify the equation to:

Kb = [OH-][C5H5N]

Now, we can rearrange the equation to solve for [OH-]:

[OH-] = Kb / [C5H5N]

Substituting the given values, we have:

[OH-] = (1.7 x 10^9) / (0.248)

[OH-] ≈ 6.85 x 10^9

Now that we have the concentration of hydroxide ions, we can calculate the pOH:

pOH = -log10([OH-])

pOH = -log10(6.85 x 10^9)

pOH ≈ 9.16

Finally, we can calculate the pH using the relationship between pH and pOH:

pH = 14 - pOH

pH ≈ 14 - 9.16

pH ≈ 4.84

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what is a similarity between the first quarter moon and the third quatre moon

Answers

The similarity between first quarter moon and third quarter moon, is the moon is located perpendicular to Earth and the sun.

What is first quarter moon?

The first quarter moon is a primary moon phase when half of the moon's face is lit up.

The first quarter moon rises around midday and is visible in the day sky.

What is third quarter moon?

Third quarter moon is when the opposite half of the moon is illuminated compared to the first quarter moon. It is the last quarter moon of a lunar month.

Similarity between first quarter moon and third quarter moon?

The similarity between first quarter moon and third quarter moon, is the moon is located perpendicular to Earth and the sun.

Thus, the similarity between first quarter moon and third quarter moon, is the moon is located perpendicular to Earth and the sun.

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What is the final temperature after 840 Joules is absorbed by 10.0g of water at 25.0
C?

Answers

The final temperature of the water is: T_final = 45.0°C

We can use the formula for the specific heat capacity of the water to solve this problem:

q = mcΔT

First, we can calculate the initial energy of the water:

q = mcΔT

q = (10.0 g) (4.184 J/g°C) (25.0°C)

q = 1,046 J

Next, we can calculate the final temperature after absorbing 840 J:

q = mcΔT

840 J = (10.0 g) (4.184 J/g°C) (ΔT)

ΔT = 20.0°C

Therefore, the final temperature of the water is:

T_final = T_initial + ΔT

T_final = 25.0°C + 20.0°C

T_final = 45.0°C

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Consider the equilibrium of methanol vapor and the liquid.
CH₂OH(1) CH₂OH(g)
What is the vapor pressure of the methanol at -30 °C?
What is the vapor pressure of the methanol at 40 °C?
Thermodynamic Table at 25 °C
Substance AH; (kJ/mol) S (J/mol-K) AG; (kJ/mol)
CH₂OH(1)
126.8
CH₂OH(g)
239.9
Pvap 5
Pap
=
=
-239.2
-201.0
-166.6
-162.3
atm
atm

Answers

The vapor pressure of methanol at 40°C is 0.234 atm.

What distinguishes ethanol from methanol?

Only two types of alcohol are methanol and ethanol. Ethanol, sometimes referred to as ethyl alcohol, has a chemical composition of two carbon atoms. Methanol, sometimes referred to as methyl alcohol, is made up of just one carbon atom.

ln(P2/P1) = (ΔHvap/R) x (1/T1 - 1/T2)

ΔGvap = -RTln(Pvap/P) = ΔHvap - TΔSvap

ΔGvap = -RTln(Pvap/P) = -166.6 kJ/mol

ΔSvap = S(g) - S(l) = 239.9 J/mol-K - 126.8 J/mol-K = 113.1 J/mol-K

ΔHvap = ΔGvap + TΔSvap = -166.6 kJ/mol + (298.15 K)(113.1 J/mol-K) = -134.6 kJ/mol

Now we can use the Clausius-Clapeyron equation to find the vapor pressure of methanol at -30°C and 40°C.

At -30°C, we have:

T1 = 25°C + 273.15 = 298.15 K

T2 = -30°C + 273.15 = 243.15 K

ΔHvap = -134.6 kJ/mol

R = 8.314 J/mol-K

ln(P2/5 atm) = (-134.6 kJ/mol / 8.314 J/mol-K) x (1/298.15 K - 1/243.15 K)

P2 = 0.0038 atm

Therefore, the vapor pressure of methanol at -30°C is 0.0038 atm.

At 40°C, we have:

T1 = 25°C + 273.15 = 298.15 K

T2 = 40°C + 273.15 = 313.15 K

ΔHvap = -134.6 kJ/mol

R = 8.314 J/mol-K

ln(P2/5 atm) = (-134.6 kJ/mol / 8.314 J/mol-K) x (1/298.15 K - 1/313.15 K)

P2 = 0.234 atm

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What volume in milliliters of 0.0130 M Ca(OH)₂ is required to neutralize 75.0 mL of 0.0300 M HCl?

Answers

The volume in milliliters of calcium hydroxide solution required to neutralize 75.0 mL of 0.0300 M HCl is 173.1mL

HOW TO CALCULATE MOLARITY:

The molarity of calcium chloride solution can be calculated by using the following formula:

C1V1 = C2V2

Where;

C1 = concentration of calcium hydroxideV1 = volume of calcium hydroxideC2 = concentration of hydrogen chlorideV2 = volume of hydrogen chloride

According to this question,

C1 = 0.0130MC2 = 0.0300 MV1 = ?V2 = 75.0 mL

0.0130 × V1 = 0.0300 × 75

0.0130V1 = 2.25

V1 = 2.25 ÷ 0.0130

V1 = 173.1mL

Therefore, the volume in milliliters of calcium hydroxide solution required to neutralize 75.0 mL of 0.0300 M HCl is 173.1mL.

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(01.04 LC)
What phase of matter has particles that are held together but can flow past each
other and takes the shape of a container, filling it from the bottom up? (3 points)
1) Gas
2) Liquid
3) Plasma
4) Solid

Answers

the answer is liquid ! hope this helped :)
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