Initial common temperature upto three significant figure will be \(27.3830\)
After mixing up water and cooper the final temperature will \(18^0\) C
Let the initial temperature of the water and copper calorimeter is T
Here, ice takes the heat from water and copper calorimeter, and they give heat so they lose the temperature.
So, T>18
\(=(29 \times 0.5 \times 10)+(29 \times 80)+(29 \times 1 \times 18)=145+2320+522=2987 \:Cal\)
Let initial temperature of water and copper calorimeter be T
300 g water and 200 g copper calorimeter when changes temperature T to \(18^0 C\) then heat loss \(=300\times 1 \times(\mathrm{T}-18)+(200 \times 0.0917) \times(T-18) \:cal\)
The specific heat of copper in cgs unit is 0.0917
heat gain = heat loss
\(300 \times 1 \times(\mathrm{T}-18)+(200 \times 0.0917) \times(T-18)=2987\)
\((T-18) \times(300+18.34)=2987\)
Calculating \(T=9.3830+18=27.3830\)
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The lowest-pitch tone to resonate in a pipe of length L that is closed at one end and open at the other end is 200 Hz. Which one of the following frequencies will NOT resonate in the same pipe
a. 1800 Hz
b. 1000 Hz
c. 1400 Hz
d. 600 Hz
e. 400 Hz
Answer:
e. 400 Hz
Explanation:
In closed organ pipe, only odd harmonics of fundamental note is possible .
The fundamental frequency is 200 Hz . Then other overtones will be having following frequencies .
200 x 3 , 200 x 5 , 200 x 7 , 200 x 9 etc
600 Hz , 1000 Hz , 1400 Hz , 1800 Hz .
Frequency not possible is 400 Hz .
16) Find the orbital speed of an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radius of 3.00 x 105 km. (G= 6.67 × 10-11 N·m2/kg2) A) 19.5 km/s B) 27.5 km/s *C) 11.2 km/s D) 20.5 km/. orbital speed?
The orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s. The correct answer is option C
What does Orbital speed depend on ?The speed of an object travelling around a circle depends on two quantities namely;
Its angular velocity wIts distance from the center of the circle.Given that an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radius of 3.00 x 105 km. (G= 6.67 × 10-11 N·m2/kg2)
The given parameters are:
The mass of Saturn = 5.68 x 10^26 kgThe orbital radius = 3.00 x 105 kmG = 6.67 × 10-11 N·m2/kg2Let us first calculate the gravitational field strength on the Saturn.
g = GM/r²
Substitute all the necessary parameters and convert km to m
g = (6.67 × \(10^{-11}\) × 5.68 × \(10^{26}\)) ÷ (300000 × 1000)²
g = 3.79 × \(10^{16}\) ÷ 9 × \(10^{16}\)
g = 0.421 m/s²
The orbital speed will be
V² = gr
V² = 0.4211 × 300000 × 1000
V² = 126333333.3
V = √126333333.3
V = 11239.8 m/s
Convert it to Km/s by dividing the answer by 1000
V = 11239.8/1000
V = 11.2 Km/s
Therefore, the orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s
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1. A 63 kg driver gets into an empty taptap to start the day's work. The springs compress 1.5x10-2 m. What is the effective spring constant of the spring system in the taptap?
2. After driving a portion of the route, the taptap is fully loaded with a total of 24 people including the driver, with an average mass of 68 kg per person. In addition, there are three 15-kg goats, five 3-kg chickens, and a total of 25 kg of bananas on their way to the market. Assume that the springs have somehow not yet compressed to their maximum amount. How much are the springs compressed?
(1) When the driver is at rest, the restoring force exerted by spring is equal in magnitude to the driver's weight, so that
∑ F = s - mg = 0 ==> s = mg = 617.4 N
If the spring is compressed 0.015 m, then the spring constant k is such that
617.4 N = k (0.015 m) ==> k = 41,160 N/m ≈ 41 kN/m
(2) The total mass of the passengers is
24 (68 kg) + 3 (15 kg) + 5 (3 kg) + 25 kg = 1717 kg
so that if everyone is at rest, the spring is compressed a distance x such that
kx = (1717 kg) g ==> x ≈ 0.41 m
Three people are trying to move a box. Which set of forces will result in a net
force on the box of 20 N to the left?
Answer:
yes the answer is D as the two people if we calculate
Answer:
A
Explanation:
correct on A P E X
a uniform ladder of mass 100kg leans at 60° to the horizontal against a frictionless wall, calculate the reaction on the wall.
Answer:
\(500\text{N} (490\text{N}) (490.5\text{N})\)
Explanation:
The reaction force is the force that is in the perpendicular direction to the wall.
We have an angle and a hypotenuse, we need to find the adjacent angle - so we can just use cos:
\(cos(\theta)=\frac{\text{adj}}{\text{hyp}}\\\text{hyp}*cos(\theta)=\text{adj}\\100*cos(60)=100*0.5=50\text{kg}\)
However, we would like a force and not a mass.
\(W=mg\\W=50g\\W=500\text{N} (490\text{N}) (490.5\text{N})\)
Answer 1 if you use g as 10, answer 2 if you're studying mechanics in maths, answer 3 if you're studying mechanics in physics.
A 10 kg medicine ball is thrown at a velocity of 15 km/hr ( m/s) to a 50 kg skater who is
at rest on the ice. The skater catches the ball and subsequently slides with the ball across the
ice.
Complete Question
A 10 kg medicine ball is thrown at a velocity of 15 km/hr ( m/s) to a 50 kg skater who is at rest on the ice. The skater catches the ball and subsequently slides with the ball across the ice.
Calculate the kinetic energy after collision(in joules).
Answer:
\(K.E=70.23J\)
Explanation:
From the question we are told that:
Mass of ball \(m_b=10kg\)
Speed \(V_{b1}=15 km/hr ( m/s)\)
\(V_{b1} = 4.1667 m/s\)
\(V_{b1} = 4.1667 m/s\)
Mass of Skater \(m_s=50kg\)
Generally the equation for conservation of momentum is mathematically given by
\(m_sV_{s1}+m_bV_{b1}=(m_s+m_b)V\)
\(V=\frac{m_sV_{s1}+m_bV_{b1}}{(m_s+m_b)}\)
\(V=\frac {50+10*4.1667}{(50+10)}\)
\(V=1.53m/s\)
Generally the equation for Kinetic energy is mathematically given by
\(K.E=\frac{1}{2}(m_s+m_b)V^2\)
\(K.E=\frac{1}{2}(50+10)(1.53)^2\)
\(K.E=70.23J\)
Therefore kinetic energy K.E after collision is given as
\(K.E=70.23J\)
If a longitudinal wave passes a specific point seven times per second, and the distance between wave rarefaction points is 2 meters, what is the speed of the wave? 14 m/s 3. 5 m/s 0. 29 m/s 9 m/s.
The speed of the wave from the calculation that we have done is 14 m/s
What is the wave speed and how do we find it?To find the wave speed, we need to know the frequency and wavelength of the wave. These values can be measured experimentally or calculated based on the properties of the medium through which the wave is traveling.
For example, the wavelength of a sound wave can be determined by measuring the distance between two consecutive points of maximum compression or rarefaction, while the frequency can be measured using a frequency meter or calculated based on the properties of the sound source.
We know that;
Frequency = 7 cycles/s
Wavelength = 2 m
Wave speed = λf
= 7 cycles/s * 2 m
= 14 m/s
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1 a Explain the difference between a transverse wave and a longitudinal
wave.
b Give one example of each.
c Draw a diagram of a transverse wave. On your diagram, mark the
wavelength and amplitude of the wave.
The difference between transverse and longitudinal waves is direction of wave motion in relative to direction of the particle motion.
Transverse vs Longitudinal Waves: What's the Difference?The particle motion in a transverse wave is only perpendicular to the wave motion but in longitudinal wave, the particle motion is parallel to the wave motion.
An example of transverse wave is a wave on a guitar string which when plucked, it vibrates back and forth in a direction perpendicular to the direction of the wave traveling along the string.
An example of a longitudinal wave is sound waves which are created when a source like speaker or a musical instrument vibrates back and forth in the same direction as the wave is traveling through the air.
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The microwaves produced inside a microwave have a wavelength of 12.0m and a frequency of 25Hz. At what speed do the microwaves travel in units of m/s ?
Answer: 300 m/s
Explanation:
The equation for finding wave speed is the wavelength times the frequency which would be
12.0mx 25hz=300m/s
Did the energy you used to lift the notebook get stored in the book as potential energy? Explain your answer with reasons.
Answer:
Because when you move a object the energy stored in moving objects. As the object moves faster, more energy is stored. Motion energy is the sum of potential and kinetic energy in an object that is used to do work.
Explanation:
answer it please
What is the Central Idea of "Shelter Dog Protects Owner with Epilepsy“
What is the author’s viewpoint?
Do you agree or disagree with that viewpoint?
Why? Explain your answer.
parpgraph 1-2
Answer:
Yes, the energy used to lift the book was stored in the book as potential energy. The book moved when it was let go.
Explanation:
This is what edmentum sample answer says so I hope this helps out!
Describe and explain motion due to uniform velocity in one direction and uniform acceleration in a perpendicular direction
Answer: you have to divide and multiple fam
Explanation:
Can you use an adjustable gas lift leg (Similar to office chair) on the moon?
a plane wall is 250mm thick and it's wall area is 4.5m^2. if the thermal conductivity is 9.35w/m°c and surface temperature are steady at 150°c and 40°c. calculate the heat flow across the plane wall and the temperature gradient in the flow direction
The temperature gradient in the flow of direction is 294525 W.
What is Temperature gradient?A temperature gradient is the gradual variance in temperature with distance. The slope of the gradient is consistent within a material. A gradient is established anytime two materials at different temperatures are in physical contact with each other.
Q= T/( L/ KA)
Q= ( 1500 − 450) / 0.15 / 9.35v * 4.35)
= 294525 W
Units of measure of temperature gradients are degrees per unit distance, such as °F per inch or °C per meter.
Many temperature gradients exist naturally, while others are created. The largest temperature gradient on Earth is the Earth itself. Q= T/Ka.
Therefore, The temperature gradient in the flow of direction is 294525 W.
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WILL GIVE BRAINLIEST PLS HELPPP !!!
A 2,713 kg van runs into the back of a 843 kg compact car at rest. They move off together at 6.9 m/s. Assuming the friction with the road is negligible, calculate the initial speed of the van.
The initial speed of the van of mass 2713 kg is 9.04 m/s.
What is speed?Speed is the ratio of distance to time.
To calculate the initial speed of the van, we use the formula below.
Formula:
u = V(m+M)/m................. Equation 1Where:
u = Initial speed of the vanm = Mass of the vanM = Mass of the carV = Common speed of the van and the carFrom the question,
Given:
V = 6.9 m/sm = 2713 kgM = 843 kgSubstitute these values into equation 1
V = 6.9(2713+843)/(2713)V = 6.9×3556/2713V = 9.04 m/sHence, the initial speed of the van is 9.04 m/s.
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A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.32 cm. A compressive force of F = 5000 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
The length of the stack shortens by 4.88 x 10-6 m.
What is Young's brass modification?Brass and steel have Young's modules of 1.0 and 2 respectively, 1010N/m2. Under the same force, a brass wire of the same length and a steel wire with radii of RB and RS, respectively, are both expanded by 1 mm.
The change in length of each cylinder due to the compressive force can be found using the formula:
ΔL = (F * L) / (A * E)
First, let's find the cross-sectional area of each cylinder:
A = π * r² = π * (0.32 cm)² = 0.3217 cm²
L = Lcopper + Lbrass
L = 2 * Lcopper
Ftotal = Fbrass + (-Fcopper) = Fbrass - Fbrass = 0
Since the total force on the stack is zero, the amount by which the length of the stack decreases is the same as the amount by which the length of the brass cylinder decreases:
ΔL = (Fbrass * Lbrass) / (Abrass * Ebrass)
ΔL = (5000 N * Lbrass) / (0.3217 cm²* 9.0 x 10¹⁰ N/m²)
ΔL = (1.554 x 10⁻⁴ m/N) * Lbrass
V = π * r² * Lbrass
Lbrass = V / (π * r²)
Lbrass = 1 cm / (π * (0.32 cm)^2)
Lbrass = 3.14 cm
Finally, we can substitute this value into the equation for ΔL:
ΔL = (1.554 x 10⁻⁴ m/N) * 3.14 cm
ΔL = 4.88 x 10⁻⁶ m
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1. Single Choice
The higher the frequency of a wave, ( )
A:The smaller its speed
B:The shorter its wavelength
C:The greater its amplitude
D:The larger its period
isotope A: 95
ending measure weight 5.9
half life 6 days
what day was isotope measured
If the half-life of an isotope is found to be 6 days, then the isotope whose initial weight is 95 and the final weight is 5.9. It would take approximately 24 days.
What is an Isotope?Isotope may be defined as the type of atom in which the number of neutrons differs and the number of protons is the same. They are atoms of the same element, having the same atomic number but different mass numbers.
According to the context of this question,
The initial weight of an isotope = 95
The final weight of an isotope = 5.9
The half-life = 6 days
After 6 days, the weight of 95 reduced to 47.5.
After 6 days, the weight of 47.5 was reduced to 23.75.
After 6 days, the weight of 23.75 reduced to 11.87
After 6 days, the weight of 11.87 was reduced to 5.93.
Therefore, if the half-life of an isotope is found to be 6 days, then the isotope whose initial weight is 95 and the final weight is 5.9. It would take approximately 24 days.
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Your question is incomplete, but most probably your full question is as follows:
An isotope A has an initial weight of 95g, but after some time its weight was reduced to 5.9g being a half-life of 6 days. On what day it was measured?
For which type of pathogens do immunizations/vaccinations help prevent?
To reduce the risk of atherosclerosis, it is important to cut down on?
The pathogen that immunization helps to prevent is virus.
To reduce the risk of atherosclerosis cut down on saturated fatty foods.
What is immunization?Immunization is defined as the prevention of pathogenic viral organisms from harming a living human host through the exposure of the host to an attenuated form of the virus to develop immunity prior to a future exposure.
Atherosclerosis is the deposition of fatty substances on the arterial wall leading to blocking of the blood vessels.
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A 10 kg rock falls 5 meters and hits the ground. Did the rock have any energy just
before it hit the ground? If so, how much? What force did it require, to get the rock to start
moving?
Answer:
495.5 Joules
Explanation:
Given data
Mass= 10kg
Height= 5meters
g= 9.81m/s^2
Yes the rock will possess potential energy before it hits the ground
The potential energy is expressed as
PE=mgh
substitute
PE= 10*9.91*5
PE= 495.5 Joules
What statement is not an example of Newton’s first law of motion
Answer:
c
Explanation:
im smart....................... i think
This law is about inertia, and the law displayed in A is Newton's third law of equal and opposite reactions, so option A is correct.
What is Newton’s first law of motion?The basis of classical mechanics is laid out in three assertions known as Newton's laws of motion, which were first articulated by English physicist and mathematician Isaac Newton. These laws describe the relationships between forces acting on a body and its motion.
Unless a force acts on a body that is at rest or moving in a straight line at a constant speed, Newton's first law asserts that it will continue to be at rest or move in that direction.
This law is about inertia (an object wanting to stay in its state of motion) and the law displayed in A is Newton's third law of equal and opposite reactions, therefore, it is not an example of Newton’s first law of motion.
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A train station bell gives off a fundamental tone of 500 Hz as the train approaches the station at a speed of 20 m/s. If the speed of sound in air is 334 m/s, what will be the apparent frequency of the bell to an observer riding the train
Answer: 529.9 Hz
Explanation:
Here we need to use the Doppler equation, so we have:
f' = f*(v + v0)/(v - vs)
Here, f is the frequency = 500Hz
v is the velocity of the wave, = 334m/s
v0 is the velocity of the observer = 20m/s
vs is the velocity of the source = 0m/s
Then we have:
f' = 500Hz*(334m/s + 20m/s)/(334m/s) = 529.9 Hz
Problem
THE FLIGHT OF A BALL A ball is launched at 5.5 m/s at 76° above
the horizontal. It starts and lands at the same distance from the
ground. What are the maximum height above its launch level and the
flight time of the ball?
1. The maximum height above its launch level is 1.45 m
2. The time of flight of the ball is 1.1 s
1. How do I determine the maximum height?
From the question given above, the following data were obtained:
Initial velocity (u) = 5.5 m/sAngle of projection (θ) = 76 °Acceleration due to gravity (g) = 9.8 m/s²Maximum height (H) =?The maximum height can be obatianed as follow:
H = u²Sine²θ / 2g
H = [5.5² × (Sine 76)²] / (2 × 9.8)
Maximum height = 1.45 m
How do I determine the time of flight?
The time of flight of the ball can be obtained as follow:
Initial velocity (u) = 5.5 m/sAngle of projection (θ) = 76 °Acceleration due to gravity (g) = 9.8 m/s²Time of flight (T) = ?T = 2uSineθ / g
T = [2 × 5.5 × Sine 76] / 9.8
Time of flight = 1.1 s
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If the fundamental frequency of this harmonic is 7 Hz, at which frequency is this created? (Just type the number, not the units) pic attached below
If the fundamental frequency of the harmonic is 7 Hz, the frequency at which it is created depends on the harmonic being referred to.
How do we explain?Frequency of harmonics
If the fundamental frequency of a harmonic is 7 Hz, then the frequency at which the harmonic is created depends on the harmonic series being used.
The frequency of the nth harmonic in a harmonic series is equal to n times the fundamental frequency. Therefore, the first five harmonics of a harmonic series with a fundamental frequency of 7 Hz would be:
First harmonic (fundamental): 7 Hz
Second harmonic: 2 x 7 Hz = 14 Hz
Third harmonic: 3 x 7 Hz = 21 Hz
Fourth harmonic: 4 x 7 Hz = 28 Hz
Fifth harmonic: 5 x 7 Hz = 35 Hz
So, the frequency at which the harmonic with a fundamental frequency of 7 Hz is created depends on which harmonic is being referred to.
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Give me the real answer
Answer: 12,339
Explanation:
The weight of a 0.5 kg object on the surface of Planet X is 20 N. If the radius of the planet is 4 X 106 m, what is its mass?
Answer:
The mass of the Planet X is 9.595 x 10²⁴ kg.
Explanation:
mass of the object, m = 0.5 kg
radius of the Planet X, r = 4 x 10⁶ m
weight of the object, W = F = 20 N
let the mass of the Planet X = mₓ
Apply Newton's gravitational law;
\(F = \frac{Gmm_x}{r^2} \\\\m_x = \frac{Fr^2}{Gm} \\\\m_x = \frac{(20)(4\times 10^6)^2}{6.67 \times 10^{-11} \ \times \ 0.5} \\\\m_x = 9.595 \times 10^{24} \ kg\)
Therefore, the mass of the Planet X is 9.595 x 10²⁴ kg.
Um corpo de massa m= 2,0Kg é lançado horizontalmente, de uma altura h= 125m, com velocidade de módulo Vo =10m/s, como mostra a figura. Desprezando a resistência do ar e adotando g= 10m/s2 , determine: a) A energia mecânica total do corpo; b) A energia cinética do corpo a meia altura em relação ao solo; c) O tempo gasto até que o corpo atinja o solo; d) O alcance do movimento.
Answer:
A) E = 2550 J
B) K = 1325 J
C) t = 5,05 s
Explanation:
A) The total mechanical energy is given by the sum of the gravitational potential energy and the kinetic energy of the body:
\(E=U+K=mgh+\frac{1}{2}mv^2\) (1)
m: mass of the body = 2,0 kg
g: gravitational acceleration = 9,8 m/s^2
h: height = 125 m
v: initial velocity of the body = 10 m/s
You replace the values of all variables h, m, g and v in the equation (1):
\(E=(2,0kg)(9,8m/s^2)(125m)+\frac{1}{2}(2,0kg)(10m/s)^2=2550\ J\)
the total mechanical energy is 2550 J
B) The kinetic energy of the corp, when it is at a height of h/2 is given by:
\(K=\frac{1}{2}mv^2\)
where
\(v=\sqrt{(v_x)^2+(v_y)^2}\)
The x component of the velocity is constant in the complete trajectory, which is the initial velocity, that is, vo = vx
The y component is given by:
\(v_y^2=v_{oy}^2+2gy\)
voy: vertical initial velocity = 0m/s
y: height = h/2 = 125/2 = 62.5 m
\(v_y=\sqrt{2g\frac{h}{2}}=\sqrt{2(9.8m/s^2)(62.5m)}=35m/s\)
Then, you can calculate the velocity of the body and next, you can calculate the kinetic energy:
\(v=\sqrt{(10m/s)^2+(35m/s)^2}=36,40\frac{m}{s}\\\\K=\frac{1}{2}(2,0kg)(36,40m/s)^2=1325\ J\)
C) The time that body takes in all its trajectory is:
\(t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(125m)}{9,8m/s^2}}=5,05s\)
Which statement about kinetic and static friction is accurate?
Static friction is greater than kinetic friction, and they both act in conjunction with the applied force.
Kinetic friction is greater than static friction, and they both act in conjunction with the applied force.
Kinetic friction is greater than static friction, but they both act opposite the applied force.
Static friction is greater than kinetic friction, but they both act opposite the applied forcr
Answer:
Static friction is greater than kinetic friction, but they both act opposite the applied force.
Explanation:
Newton's 3rd law states that every action has and equal but opposite reaction.
If an object has static friction, that means it stays in one spot, and it takes a great amount of force to get it moving.
Once the object is moving it has kinetic friction, but it's easier to keep it moving unless you are trying to stop it.
The equal but opposite reaction to something moving it is stopping it, and the equal but opposite reaction to stopping something is moving it.
The same amount of force used to move/stop something is used to stop/move it.
Static friction is greater than kinetic friction, but they both act opposite the applied force.
Friction is the force that opposes motion. Frictional force always acts in opposition to the direction of motion.
There are two kinds of friction;
Static frictionDynamic frictionSince more forces tend to act on a body at rest and prevent it from getting into motion than the forces that tend to stop an already moving body, it follows that static friction is greater than kinetic friction. Both act in opposite direction to the applied force.
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In scientific terms, anything that represents something else is called a
O theory
O model
O hypotnesis
O chemical bond
the photo shows a skateboarder applying a force against one edge of a skateboard as she rides down a hill. how does this action cause the skateboarders motion to change?
A.it applies an unbalanced sideways force that causes a change in direction.
B.it increases the net force pointing down the hill so she speeds up.
C. it applies a balanced sideways force that causes a change in direction.
D. it increases the force of friction so she slows down.
Option D. This action cause the skateboarders motion to change because it increases the force of friction so she slows down.
What is frictional force?
This is the force that opposes motion or cause a moving object to stop or slow down.
Ff = μmg
where;
Ff is frictional force
μ is coefficient of frcitionm is mass of the objectg is acceleration due to gravityThe frictional force between the skateboard and the hill increases with increase in weight of the skateboard.
As the skateboarder applies the force on one edge of the skateboard, the applied to the skateboard increases which in turn increases the frictional force between the skateboard and the hill, reducing the speed of the skateboarder.
Thus, this action cause the skateboarders motion to change because it increases the force of friction so she slows down.
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The forces exerted on an object are shown. (3 points)
A box has an arrow pointing up labeled F and an arrow pointing down labeled 3 N.
If the net force on the object along the vertical plane is zero, which statement is correct?
F equals 3 N and the object moves up.
F equals 3 N and the object remains stationary.
F equals 0 N and the object moves down.
F equals 0 N and the object remains stationary.
Answer:
F equals 3 N and the object remains stationary. (second option in the list)
Explanation:
For sure to cancel acting forces, F must be 3N pointing up. But with regards to the object stationary or not, the question is tricky. We could have a ZERO net force applied, and the object moving at constant speed, which could still verify Newton's Laws. But considering the first answer option that refers to vertical motion upward where the object could be gaining potential energy, the most accurate response is that the force F has to be 3 N pointing up to make the object in equilibrium, and no motion in the vertical axis.
Answer: F equals 3 N and the object remains stationary.
Explanation: