So Can Someone Help Me Please Asap!!!!!!!!!!!!!!!!!!!!!!!
What are the rules for the game badminton??????????

Answer:

The wave which is created by causing vibrations in particles of matter is a mechanical wave.

Bose-Einstein statistics apply to particles called bosons, which have integer spins, and can occupy the same quantum state. Fermi-Dirac statistics apply to particles called fermions, which have half-integer spins and are subject to the Pauli Exclusion Principle, meaning they cannot occupy the same quantum state.

Classical particles follow the laws of classical mechanics, whereas quantum particles obey the principles of quantum mechanics. In classical mechanics, particles have well-defined positions and velocities, while quantum particles are described by wave functions that determine the probabilities of their positions and momenta.
Bose-Einstein statistics apply to particles called bosons, which have integer spins, and can occupy the same quantum state. Fermi-Dirac statistics apply to particles called fermions, which have half-integer spins and are subject to the Pauli Exclusion Principle, meaning they cannot occupy the same quantum state.
A transition from Fermi-Dirac to Maxwell-Boltzmann statistics occurs when the quantum effects become negligible. This typically happens at high temperatures or low particle densities, where the particles behave more classically. The Boltzmann distribution can be considered a limiting case of the Fermi-Dirac distribution under these conditions.
For a system with only three particle states (e1, e2, e3), the maximum number of fermions is three. This is because, according to the Pauli Exclusion Principle, each fermion must occupy a unique quantum state.
The entropy of an ideal fermion gas can be shown to agree with the Third Law of Thermodynamics, which states that the entropy of a system approaches zero as its temperature approaches absolute zero. In an ideal fermion gas, at absolute zero, all fermions occupy their lowest energy states, and the system's entropy reaches its minimum value, consistent with the Third Law.

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Answer:

d. The times on the clocks for the seismographs are not accurately set

Explanation:

Answer: The gravity on Mars is considerably less than it is on Earth, so while the buggy still has the same physical mass, its relative weigh it considerably less.

it would be on the right end I believe. Forgive me if I am incorrect.

The binding energy per nucleon for 10747Ag is 7.47 MeV, and for 10947Ag, it is 7.39 MeV.

The binding energy per nucleon is the amount of energy required to completely separate the nucleus of an atom into its individual nucleons. It is a measure of the stability of the nucleus, and the higher the binding energy per nucleon, the more stable the nucleus.

To calculate the binding energy per nucleon for each isotope of silver, we need to first calculate the total binding energy of each isotope. The total binding energy is the sum of the binding energies of all the nucleons in the nucleus. The binding energy per nucleon is then calculated by dividing the total binding energy by the number of nucleons.

Using the given atomic masses and isotopic abundances, we can calculate the mass of each isotope and the number of nucleons in each isotope. The number of neutrons in each isotope can be calculated by subtracting the atomic number (47) from the mass number (106 or 108). The binding energy of each isotope can then be calculated using the Einstein's famous equation E=mc², and the binding energy per nucleon can be calculated by dividing the binding energy by the number of nucleons.

After these calculations, we find that the binding energy per nucleon for 10747Ag is 7.47 MeV, and for 10947Ag, it is 7.39 MeV. This indicates that 10747Ag is more stable than 10947Ag, as it has a higher binding energy per nucleon.

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Pressure is the force acting per unit area and increases with increase in the weight of a body.

Pressure is defined as the force acting per unit area of a body.

Pressure depends upon the amount of force on an object and the size of the area the force pushes or pulls on.

The greater the amount of weight pressing on an object, the greater the amount of pressure.

Of the following objects air, ice, plastic, and gold, gold is the most dense.

A dense object will produce more pressure than one that is not dense since it exerts a greater force per unit area.

Solids exert pressure because gravity is pulling downward on the object.

It is not true that the human body has more pressure sensors in the legs than in the fingertips as pressure sensors are more in fingertips.

Therefore, pressure is the force acting per unit area and increases with increase in the weight of a body.

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A charged balloon illustrates that something can have a great amount of electric charge.

When a balloon is rubbed against certain materials like hair or wool, electrons are transferred between the balloon and the material, resulting in a buildup of electric charge on the balloon's surface. The excess electrons give the balloon a negative charge.

The concept of electric charge is fundamental to understanding the behavior of electricity and magnetism. It is a property of particles, such as electrons and protons, and determines their interaction with electric and magnetic fields. The amount of electric charge an object possesses is measured in coulombs.

The charged balloon demonstrates that objects can accumulate a significant amount of electric charge, resulting in attractive or repulsive forces between charged objects, the ability to discharge and create sparks, and the potential to interact with other electrically charged entities.

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Answer:

3000 m/s

Explanation:

Acceleration is changes in velocity over change in time which can be expressed mathematically as:

\(\displaystyle{\vec a = \dfrac{\Delta \vec v}{\Delta t}}\)

In basic physic, we express the equation as:

\(\displaystyle{\vec a =\dfrac{\vec v - \vec u}{t}}\)

Sometimes the equation is expressed without vector arrows. Each terms represent each meanings:

We know that initial velocity is 0 m/s because it’s already given in the problem, acceleration is 50 m/s² and time is 60 seconds.

Substitute in the formula:

\(\displaystyle{50 \ \, m/s^2= \dfrac{\vec v-0 \ \, \text{m/s}}{60 s}}\\\\\displaystyle{50 \ \, m/s^2= \dfrac{\vec v}{60 s}}\\\\\displaystyle{3000 \ \, m/s=\vec v}\)

Therefore, speed is 3000 m/s

Answer:

As = 7.33 [m/s]

Explanation:

To solve this problem we must use the definition of the average speed, which is equal to the relationship between the distance over time.

As = x/t

where:

As = average speed [m/s]

x = distance = 132 [m]

t = time = 18 [s]

As = 132/18

As = 7.33 [m/s]

Answer:

Accuracy is how far off a measurement is from its true value. A measured value that's far from a true value is inaccurate, while a measure that is close to a true value is accurate.

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The momentum of a 2kg mass moving at 25 m/s is 50kgm/s.

Momentum in physics refers to the tendency of a body to maintain its inertial motion.

It is the product of its mass and velocity, or the vector sum of the products of its masses and velocities i.e.

p = mass × velocity

According to this question, a 2kg mass is moving at 25 m/s. The momentum of the body can be calculated as follows:

Momentum = 2kg × 25m/s

Momentum = 50kgm/s

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To calculate the average power of the elevator motor, we need to find the work done by the motor and divide it by the time interval. The work done can be calculated using the formula: Work = Force × Distance.

Initially, the elevator is at rest, so the net force acting on it is the force required to overcome its own weight. The weight is given by the formula: Weight = mass × acceleration due to gravity = 500 kg × 9.8 m/s^2 = 4900 N.

To accelerate the elevator, an additional force is required. This force can be calculated using Newton's second law: Force = mass × acceleration. The acceleration is given as 1.75 m/s^2, and the mass is 500 kg, so the force is 500 kg × 1.75 m/s^2 = 875 N.

The distance traveled during acceleration can be found using the formula: Distance = (1/2) × acceleration × time^2. Plugging in the values, we get Distance = (1/2) × 1.75 m/s^2 × (3.00 s)^2 = 7.875 m.

Now we can calculate the work done by the motor: Work = (Force × Distance) + (Weight × Distance) = (875 N + 4900 N) × 7.875 m = 40,987.5 J.

The average power can be calculated by dividing the work done by the time interval: Average Power = Work / Time = 40,987.5 J / 3.00 s = 13,662.5 W.

To convert the power from watts to horsepower, we divide by 746: Pave = 13,662.5 W / 746 = 18.33 hp.

When the elevator reaches its cruising speed, it is moving at a constant velocity, which means there is no net force acting on it. Therefore, the motor power required to maintain the cruising speed is zero. Thus, Pcruising = 0 hp.

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Answer:

The correct option is;

D. There is not enough information to answer this question

Explanation:

The universal gravitational constant = 6.67408 × 10⁻¹¹ 3³/(kg·s²)

For an in between distance of 1 m and equal masses of 60 kg, we have;

\(F = G \times \dfrac{m_{1} \times m_{2}}{r^{2}} = 6.67408 \times 10^{-11} \times \dfrac{60 \times 60}{1^{2}} \approx 2.403 \times 10^{-7} N\)

The gravitational attraction ≈ 2.403 × 10⁻⁷ N, which does not correspond with the answers, therefore, the best option is that there is not enough information to answer this question.

The free body diagram of the crate can be shown as,

Here, N is the normal force acting on crate, mg is the weight of crate, f is the frictional force and theta is the angle of inclination of plane.

Answer:

A) The explanation for this claim is that the fan and vent system in a convection oven helps to distribute heat evenly throughout the oven, reducing hot and cold spots. The circulating air speeds up cooking time by increasing the overall temperature of the oven and exposing food to hot air on all sides. This results in a more even cooking process, as the food is cooked consistently from all angles.

B) To test this claim, you could conduct a controlled experiment by preparing identical dishes in both a conventional and a convection oven. You would need to control several variables to ensure the validity of your results, including:

By controlling these variables, you can determine if the claims about the effectiveness of convection ovens are supported by the data.

Explanation:

The values and the description of the motion of the objects under gravity are as follows;

1. The same

2. A smaller

3. A greater

4. 40 m/s

a. 5 m/s directed down

b. 45 m/s

5. a. Upwards

b. B

c. B

d. 10 m/s²

e. 10 m/s²

f. C

Gravitational acceleration is the acceleration due to the force of the Earth's attraction or pull on an object.

1. Compared with X, Y has the same acceleration as they fall

2. Compared with X, Y hits the ground with a smaller speed

3. Compared with X, Y has a greater time of descent

4. Assume g = 10 m/s², and that there is no air resistance. A stone is dropped from rest. What is its speed after 4 seconds.

The speed is given by the equation;

v = u + g•t

The velocity of the stone is therefore;

v = 0 + 10 × 4 = 40

The speed of the stone = 40 m/s

a. The initial speed of the stone u = 25 m/s

Therefore;

v = 25 - 10 × 3 = -5

The speed of the stone after 3 seconds is 5 m/s directed down

b. The initial speed of the stone = 15 m/s

Direction of the stone = Downwards

The speed after 3 seconds is therefore;

v = 15 + 10 × 3 = 45

The speed after 3 seconds is 45 m/s

5. a. The speed of the ball at point A is -30 m/s which is upwards, given that the speed is measured in the downward direction

b. The ball is stationary when the speed is 0, which is at point B.

c. The motion is a projectile motion, of an object moving upwards under gravity. The ball reaches its maximum height when its speed is 0, which is at point B.

d. The acceleration of the ball is due to gravity and it is constant. The acceleration at point C is therefore, 10 m/s²

e. The acceleration at point A is 10 m/s²

f. The point where the ball has the same speed as it did at point A is given by the point that is equidistant as point A from the point B where the speed is 0, which is point C.

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The mass of the second box car from the calculation is  22317 Kg.

We have to note that we can be able to obtain the momentum as the product of the mass and the velocity of the object that is to be studied. In the case of the cars that we have here;

The momentum before Collison = Momentum after collision

We would then have from the question;

(10300 * 19) + (M * 0) = (10300 + M) * 6

Let the mass of the second box car be M

Then;

195700 = 61800 + 6M

M = 22317 Kg

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Answer:

neutron.

Explanation:

subatomic particles include,

neutron.

proton.

electron.

hope it helps. :)

The normalized deflection is given as yEl/ wLvs.x/L = (1/24 EI) [x3 - 3L2x2 + 2L3x].

The deflection of the beam can be determined using the following formula:

y(x) = (W0 L3 sin phi/24 EI) [x3 - 3L2x2 + 2L3x], where

- EI is the flexural rigidity of the beam.

The normalized deflection is given as yEl/ wLvs.x/L. Therefore, substituting the given values of the load distribution and using the above formula,

the deflection of the beam is:y(x) = (W0 L3 sin phi/24 EI) [x3 - 3L2x2 + 2L3x]

Normalized deflection, yEl/ wLvs.x/L = (W0 L2 sin phi/24 EI) [x3 - 3L2x2 + 2L3x] / W0 L2/Lvs.x/LyEl/ wLvs.x/L = (1/24 EI) [x3 - 3L2x2 + 2L3x]

Therefore, the deflection of the beam is given as y(x) = (W0 L3 sin phi/24 EI) [x3 - 3L2x2 + 2L3x] and the normalized deflection is given as yEl/ wLvs.x/L = (1/24 EI) [x3 - 3L2x2 + 2L3x].

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The linear acceleration of the bucket as it falls is \(13.5 m/s^2\)

To find the linear acceleration of the bucket as it falls, we need to use the free-body diagram and the equations of motion.

The forces acting on the system are the weight of the bucket, the tension in the cord, and the weight of the pulley. Since the pulley is frictionless, we can assume that the tension in the cord is the same on both sides of the pulley.

The weight of the bucket can be calculated as:

F_b = m_b * g

where m_b is the mass of the bucket and g is the acceleration due to gravity.

The weight of the pulley can be calculated as:

F_p = m_p * g

where m_p is the mass of the pulley.

The tension in the cord can be calculated from the torque equation:

τ = F * r

where τ is the torque, F is the tension in the cord, and r is the radius of the pulley.

The torque on the pulley can be calculated as:

τ = I * α

where I is the moment of inertia of the pulley and α is the angular acceleration of the pulley.

Since the pulley is rolling without slipping, the linear acceleration of the pulley is related to its angular acceleration as:

a = r * α

where a is the linear acceleration of the pulley.

To find the linear acceleration of the bucket, we can use the equations of motion for the system:

F_t - F_b - F_p = m_total * a

where F_t is the tension in the cord, F_b is the weight of the bucket, F_p is the weight of the pulley, m_total is the total mass of the system, and a is the linear acceleration of the bucket.

Substituting the torque equation and the linear acceleration of the pulley, we get:

F_t - F_b - F_p = m_total * (F_t / (m_b + m_p + I/r²))

Substituting the given values, we get:

F_t - 15 N - 39.2 N = (1.5 kg + 4.0 kg + (1/2)(4.0 kg)(0.33 m)²/(0.33 m)²) * (F_t / (1.5 kg + 4.0 kg + (1/2)(4.0 kg)(0.33 m)²/(0.33 m)²))

Simplifying, we get:

F_t - 54.2 N = (5.0 kg) * (F_t / 6.5 kg)

Solving for F_t, we get:

F_t = 35.2 N

The linear acceleration of the bucket can now be calculated from the equation:

F_t - F_b = m_b * a

Substituting the given values, we get:

35.2 N - 15 N = 1.5 kg * a

Solving for a, we get:

a = 13.5 \(m/s^2\)

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Answer: 40 mins

Explanation:

If the capacitor is discharged in 1.0 ms, the amount of charge passes through the body tissues is is 5 x 10^-9 C.

The amount of charge passing through the body tissues can be calculated using the formula:
Q = C x V
where Q is the charge, C is the capacitance, and V is the voltage.Since the capacitor is discharged in 1.0 ms, the time taken is:
t = 1.0 x 10^-3 s
The capacitance is:
C = 100 pF = 100 x 10^-12 F
The voltage is:
V = 50 V
Therefore, the charge passing through the body tissues is:
Q = C x V = (100 x 10^-12 F) x (50 V) = 5 x 10^-9 C. Hence, the amount of charge passing through the body tissues is 5 x 10^-9 C.

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The hypothetical planet discovered orbiting the star has an orbital period of 4.44 Earth years.

When a hypothetical planet is discovered orbiting a star, its orbital distance is measured to be 300 million kilometers. The orbital period of the planet is determined by its distance from the star and the mass of the star.

The time taken by an object to complete a single orbit around another object is known as the orbital period. It is calculated based on the distance between the two objects and the mass of the central object. The formula for calculating the orbital period of a planet is:

Orbital period = 2π √(r³/GM)

Where r is the distance between the planet and the star, G is the gravitational constant, and M is the mass of the star.π is the mathematical constant pi whose value is 3.14.So, in the case of the hypothetical planet, the orbital period can be calculated as:

Orbital period\(= 2π √(r³/GM) = 2 x 3.14 √[(300,000,000)^3/ (6.67 x 10^-11 x M)]\)

Where the value of the gravitational constant is\(6.67 x 10^-11 Nm^2/kg^2\).

Assuming the mass of the star is one solar mass or \(1.989 x 10^30\)kg,

the orbital period can be calculated as:

Orbital period = \(2 x 3.14 √[(300,000,000)^3/ (6.67 x 10^-11 x 1.989 x 10^30)] = 4.44\) Earth years

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The final speed of the train after 42 minutes is 90 km/h

We are provided with acceleration, initial speed and time after which final speed is to be found

Let us consider the motion of the train to be in one dimension

Then, formulas of one dimension can be applied to find the final speed.

Let the initial speed of the train be 'u'

Let the final speed of the train be 'v'

Let the acceleration due to gravity be 'a'

Let the time take to reach the speed 'v' be t

Now, as per the data given,

u=55km/h

acceleration due to gravity= 50km/h^2

Time taken, t= 42 minutes

Now as we can see that all units are in km/h, time must also be in hour

As we know that 1 hour= 60 minutes

therefore, 42 minutes= 42/60=7/10= 0.7 hour

Now using the formula v = u +at

v =  u +at

v = 55 + 50 x 0.7

v = 55 +35 = 90 km/hr

Hence, the final speed of the train after 42 minutes is 90 km/h

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The maximum value of the magnetic field in the electromagnetic wave is approximately 1.86 x 10⁻⁶ T.

Given information,

The energy flow per unit time per unit area = 601 mW/m²

The energy flow per unit time per unit area is given: S = (1/2) x  ε₀ x  c x  E₀²

Where ε₀ is the vacuum permittivity, c is the speed of light in a vacuum, and E₀ is the maximum electric field strength.

The magnetic field strength (B) and electric field strength (E) in an electromagnetic wave are related by the equation: B = E / c

S = (1/2) x  ε₀ x  c x  (B x c)²

S = (1/2) x  ε₀ x  c³ x  B²

B² = (2 x  S) / (ε₀ x  c³)

Taking the square root of both sides:

B = sqrt((2 x  S) / (ε₀ x  c³))

ε₀ = 8.854 x 10⁻¹² F/m (vacuum permittivity)

c = 3 x 10⁸ m/s (speed of light in a vacuum)

B = sqrt((2 x  0.601) / (8.854 x 10⁻¹² x  (3 x 10⁸)³))

B ≈ 1.86 x 10⁻⁶ T (Tesla)

Therefore, the maximum value of the magnetic field in the electromagnetic wave is approximately 1.86 x 10⁻⁶ T.

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Answer:

mass = GPE divided by gxh

Explanation:

Answer:

69.9 kg

Explanation:

w = mg

m = w/g

m = 685/9.8

m = 69.9 kg