Explanation:
The magnitude of the electric field due to a point charge object at a distance 4.0 m is 9 N/C. From the same
charged object the electric field of magnitude, 16 N/C will be at a distance of
The electric field of magnitude 16 N/C will be at a distance of 6.0 meters from the charged object.
The magnitude of the electric field due to a point charge object follows the inverse square law, which states that the magnitude of the electric field is inversely proportional to the square of the distance from the charged object. Mathematically, this is expressed as:
\(E = k*q/r^2\)
where E is the electric field, k is Coulomb's constant (\(k = 9 x 10^9 N*m^2/C^2\)), q is the charge of the object, and r is the distance from the object.
We can use this formula to find the distance at which the electric field has a magnitude of 16 N/C. Let's call this distance x:
16 = \(k*q/x^2\)
We can rearrange this equation to solve for x:
x = \(\sqrt(k*q/16)\)
To find q, we need another piece of information. We know that the electric field has a magnitude of 9 N/C at a distance of 4.0 m. Using the same formula as before, we can solve for q:
9 = \(k*q/4^2\)
q = \(9*4^2/k\)
Now we can substitute this value for q into the equation for x:
x =\(\sqrt(k*(9*4^2/k)/16)\)
x =\(\sqrt(9*4^2/16)\)
x = \(\sqrt(36)\)
x = 6.0 meters
Therefore, the electric field of magnitude 16 N/C will be at a distance of 6.0 meters from the charged object.
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What ideas do you have about what determines how currents like this move?
1. What is the total distance traveled?
A 3.0m
B 4.0m
C 5.0m
D 6.0m
Answer:
c
Explanation:
25. You lift a book from the floor to a bookshelf 1.0 m above the ground. How much power is used if the
upward force is 15.0 N and you do the work in 2.0 ?
Explanation:
P=E/T
E=15N
T=2s
P=15/2
P=7.5
What color is iodine solid and its gas?
Collisions question plzz help mee
Voltage
Depends on the amount of resistance
Depends on the amount of current
Is the measurement of electrical pressure
All of the above
Voltage depends on the amount of resistance, current according to the Ohm's law, and, by definition, is the measurement of electrical pressure.
According to the Ohm's Law, the current through a conductor between two points is directly proportional to the voltage across the two points.
Mathematically,
V ∝ I
V = IR
where, R is the resistance of the conductor and I is the current flowing in the conductor. So, the voltage depends on the amount of resistance and current.
Also, Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light.
Hence All of the above option in the given question are true.
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A roller coaster car is going over the top of a 15-m-radius circular rise. The passenger in the roller coaster has a true weight of 600 N (therefore a mass of 61.2 kg). At the top of the hill, the passengers "feel light," with an apparent weight of only 360 N. How fast is the coaster moving
Answer:
v = 7.67 m/s
Explanation:
The equation for apparent weight in the situation of weightlessness is given as:
Apparent Weight = m(g - a)
where,
Apparent Weight = 360 N
m = mass passenger = 61.2 kg
a = acceleration of roller coaster
g = acceleration due to gravity = 9.8 m/s²
Therefore,
360 N = (61.2 kg)(9.8 m/s² - a)
9.8 m/s² - a = 360 N/61.2 kg
a = 9.8 m/s² - 5.88 m/s²
a = 3.92 m/s²
Since, this acceleration is due to the change in direction of velocity on a circular path. Therefore, it can b represented by centripetal acceleration and its formula is given as:
a = v²/r
where,
a = centripetal acceleration = 3.92 m/s²
v = speed of roller coaster = ?
r = radius of circular rise = 15 m
Therefore,
3.92 m/s² = v²/15 m
v² = (3.92 m.s²)(15 m)
v = √(58.8 m²/s²)
v = 7.67 m/s
Two blocks are sliding on a horizontal frictionless surface with velocities shown in the sketch. Block A has mass 0.500 kg and block B has mass 0.750 kg. The two blocks have a perfectly inelastic collision and stick together after the collision.
(a) What is the speed of the combined blocks after the collision?
(b) What angle does the velocity of the combined blocks make with the +x-axis after the collision?
(c) What is the magnitude of the decrease in kinetic energy of the system of two blocks due to the collision?
(a) The conservation of momentum applies to this inelastic collision. The total momentum of the system before the collision is the sum of the momentum of block A and the momentum of block B:
p_i = m_A * v_A + m_B * v_B
= (0.500 kg)(4.00 m/s) + (0.750 kg)(-2.50 m/s)
= 0.500 kg * 4.00 m/s - 0.750 kg * 2.50 m/s
= 0.500 kg * 4.00 m/s + (-0.750 kg) * (-2.50 m/s) (note: v_B is negative)
= 1.250 kg m/s
The total momentum of the system after the collision is the momentum of the combined blocks:
p_f = (m_A + m_B) * v_f
where v_f is the velocity of the combined blocks after the collision. Since the blocks stick together after the collision, they move with the same velocity. Therefore, we can write:
v_f = p_f / (m_A + m_B)
= 1.250 kg m/s / (0.500 kg + 0.750 kg)
= 1.00 m/s
Therefore, the speed of the combined blocks after the collision is 1.00 m/s.
(b) The angle that the velocity of the combined blocks makes with the +x-axis after the collision can be found by using the conservation of momentum in the x and y directions separately. Since there is no external force acting on the system in either the x or y direction, the total momentum in each direction is conserved.
In the x direction, the momentum before the collision is:
p_i,x = m_A * v_A,x + m_B * v_B,x
= (0.500 kg)(4.00 m/s) + (0.750 kg)(-2.50 m/s)
= 0.500 kg * 4.00 m/s - 0.750 kg * 2.50 m/s
= 0.500 kg * 4.00 m/s + (-0.750 kg) * (-2.50 m/s) (note: v_B,x is negative)
= 1.250 kg m/s
After the collision, the x-component of the velocity of the combined blocks is:
v_f,x = p_f,x / (m_A + m_B)
Since there is no external force in the x direction, the x-component of the momentum is conserved, i.e., p_i,x = p_f,x. Therefore, we can write:
p_f,x = m_A * v_f,x + m_B * v_f,x
= (m_A + m_B) * v_f,x
= 1.250 kg m/s
Substituting the values, we get:
v_f,x = 1.250 kg m/s / (0.500 kg + 0.750 kg)
= 1.00 m/s
In the y direction, the momentum before the collision is:
p_i,y = m_A * v_A,y + m_B * v_B,y
= 0 + 0
= 0
After the collision, the y-component of the velocity of the combined blocks is:
v_f,y = p_f,y / (m_A + m_B)
Since there is no external force in the y direction, the y-component of the momentum is conserved, i.e., p_i,y = p_f,y. Therefore, we can write:
p_f,y = m_A * v_f,y + m_B * v_f,y
= (m_A + m_B) * v_f,y
Since the blocks stick together after the collision, their y-velocities must cancel out, i.e., v_f,y = 0. Therefore, we can write:
0 = (m_A + m_B) * v_f,y
Substituting the values, we get:
v_f,y = 0
Therefore, the velocity of the combined blocks after the collision is purely in the x-direction, and makes an angle of 0 degrees (i.e., is parallel to) with the +x-axis.
(c) The kinetic energy of the system before the collision is:
KE_i =\((1/2) * m_A * v_A^2 + (1/2) * m_B * v_B^2\)
=\((1/2) * (0.500 kg) * (4.00 m/s)^2 + (1/2) * (0.750 kg) * (-2.50 m/s)^2\)
= \(2.000 J + 2.344 J\)
= 4.344 J
The kinetic energy of the system after the collision is:
KE_f = (1/2) * (m_A +m_B) * v_f^2
= (1/2) * (0.500 kg + 0.750 kg) * (1.00 m/s)^2
= 0.937 J
Therefore, the decrease in kinetic energy of the system due to the collision is:
ΔKE = KE_i - KE_f = 4.344 J - 0.937 J = 3.407 J
The decrease in kinetic energy is dissipated as heat and sound during the collision.
As part of astronaut training, a prospective astronaut is spun around in a human centrifuge such that the candidate experiences a centripetal acceleration that is 2.8 times the acceleration due to gravity on the surface of the earth. If the candidate is 11.05 m from the center, determine the candidate's speed in meters per second.
The candidate's speed (m/s), given that the candidate experiences a centripetal acceleration that is 2.8 times the acceleration due to gravity is 17.4 m/s
How do I determine the candidate's speed?We understood that the centripetal acceleration is related to speed and radius according to the following formula:
a = v² / r
Cross multiply
v² = ar
Take the square root of both sides
v = √ar
Where
v is the speeda is the centripetal accelerationr is the radiusWithe the above formula, we can determin the speed of the candidate. Details below:
Acceleration due to gravity (g) = 9.8 m/s²Centripetal acceleration = 2.8 × g = 2.8 × 9.8 = 27.44 m/s²Radius (r) = 11.05 mSpeed of candidate (v) =?v = √ar
v = √(27.44 × 11.05)
v = 17.4 m/s
Thus, the speed of the candidate is 17.4 m/s
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vertical columns in the periodic table represent a group or family of elements that have the same number of valence electrons by having similar electron configurations elements in the same group have similar properties list elements that have similar properties
The examples of elements with similar properties in the same group are fluorine, chlorine, bromine and iodine.
What is group of elements in a periodic table?
The groups in periodic table is the same as vertical columns in the periodic table
These groups represent a group or family of elements that have the same number of valence electrons by having similar electron configurations elements in the same group have similar properties.
Examples of elements found in the same group with similar chemical properties include;
group 7 elements.
FluorineChlorineBromineIodineThe valence electron of elements found in the group 7 of periodic table is negative 1 (-1).
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A baseball is hit almost straight up into the air with a speed of 22 m/s. Estimate (a) how high it goes, and (b) how long it is in the air. (c) What factors make this an estimate ?
(a) The ball goes up to the height of 31.89 m. (b) The ball stays for 5.1 s in the air. (c) The acceleration due to gravity and wind resistance can affect the estimation.
What is Acceleration due to gravity?Acceleration owing to gravity is the term used to describe the rate at which a body's velocity changes as a result of the earth's gravitational pull. In general, it is assumed that the acceleration caused by gravity is in the downward direction.
The acceleration caused by gravity has been calculated as, however as it changes from location to location, it may have an impact on the estimation.
You may have thought that the wind has no impact, but it can actually generate drag and even cause the ball to shift course.
Therefore, (a) The ball goes up to the height of 31.89 m. (b) The ball stays for 5.1 s in the air. (c) The acceleration due to gravity and wind resistance can affect the estimation.
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Weight is best defined as _____. A the amount of space an object takes up B the speed of an object C the force of gravity on an object D the amount of energy in an object
Weight is best defined as C) the force of gravity on an object.
what is the mass of 5m³of cement of density 3000kg/m³?
Answer:
The mass of the cement is 15,000 kg.
Explanation:
To evaluate the mass we can use this equation
\(\sf m=dv\)
Where
\(\sf m\) is the mass
\(\sf d\) is the density
\(\sf v\) is the volume
Numerical Evaluation
In this example we are given
\(\sf d=3000\)
\(\sf v=5\)
Substituting our given values into the equation yields
\(\sf m=3000 \cdot 5\)
\(\sf m=15000\) kg
The thermal energy that causes the ice to melt is transferred from the lemonade as it cools. The loss of this thermal energy causes the temperature of the 300 g of the lemonade to fall by 19 °C. Calculate the specific heat capacity of the lemonade.
According to the give value of the mass of lemonade and change in the temperature, the specific heat capacity of the lemonade is 3.81 J/kg/k.
The formula for the specific heat capacity (C) = Q/ m × ΔT
Q is energy added and the value, which is 334J
m is the mass of the lemonade, which is 300g = 0.3 kg
Δ T is the change in temperature, which is 19°C =(273+19)= 292 K
So, C = 334/ 0.3 × 292
= 3.81 J/kg/k
So the specific heat capacity of the lemonade is 3.81 J/kg/k.
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6. The work done in pushing a 40 kg chair from the kitchen table to 10 meters down the
hall would be about_
,neglecting friction.
A. 40J
B. 4000J
C. OJ
D. 0.25J
Answer:
B
Explanation:
W = f * d
= mg * d
= 40(9.81)(10) =~4000 J
On top labeled A 2 waves 1 above the other, with crests and troughs that line up. On bottom labeled B 2 waves, 1 above the other, so that the crests of the top wave line up with the troughs of the bottom wave.
Will there be noise cancellation in example A or example B?
Answer:
b
Explanation:
Answer:
B B*
Explanation:
B BBBBB
BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB
In a given crt, electrons are accelerated horizontally by 7.0kv . they then pass through a uniform electric field e for a distance of 2.4cm , which deflects them upward so they travel 24cm to the top of the screen, 10cm above the center.Estimate the value of E. Neglect the upward distance that electron moves while in the electric field.
Given that,
Potential energy = 7.0 kV
Distance = 2.4 cm
Initial horizontal velocity covered 24cm down and new velocity covered 10 cm up.
The final velocity is
\(v_{f}=\dfrac{10}{24}v_{i}\)
The kinetic energy of electron is
Using conservation of energy
\(mgh=\dfrac{1}{2}mv_{i}^2\)
\(E=\dfrac{1}{2}mv_{i}^2\)
\(7000=\dfrac{1}{2}mv_{i}^2\)
\(\dfrac{1}{2}mv_{i}^2= 7000\ V\)
When an electron passing through field E experience force F produces change in momentum.
Initial vertical momentum is zero.
We need to calculate the value of E
Using formula of momentum
\(P_{f}=m\cdot v_{f}\)
\(F\cdot t= m\cdot v_{f}\)
Where,F = change in potential energy
\(F =\dfrac{dU}{dx} = E\)
\(E\times \dfrac{d}{v_{i}}=m\cdot v_{f}\)
\(E=\dfrac{10}{24}\times\dfrac{mv_{i}^2}{d}\)
Put the value into the formula
\(E=\dfrac{10}{24}\times\dfrac{2\times7000}{2.4\times10^{-2}}\)
\(E=243055.5\ V/m\)
\(E=2.4\times10^{5}\ V/m\)
Hence, the value of E is \(2.4\times10^{5}\ V/m\)
convert 2 days into second
Gravity is a
A.pushing force
B. not a force at all
C. pulling force
Answer:
C
Explanation:
gravity is a pulling force according to Newton
If the volume of the balloon is 500 m3m3 and the surrounding air is at 15.0 ∘C∘C, what must the temperature of the air in the balloon be for it to lift a total load of 290 kgkg (in addition to the mass of the hot air)? The density of air at 15.0 ∘C∘C and atmospheric pressure is 1.23 kg/m3
Answer:
Temperature of the air in the balloon = 272°C
Explanation:
Given:
Volume of balloon = 500 m³
Air temperature = 15° C = 273 + 15 = 288 K
Total weight = 290 kg
Density of air = 1.23 kg/m³
Find:
Temperature of the air in the balloon
Computation:
Density of hot air = Density of air - [Total weight / Volume of balloon]
Density of hot air = 1.23 - [290 - 500]
Density of hot air = 0.65 kg/m³
[Density of hot air][Temperature of the air in the balloon] = [Density of air][Air temperature ]
Temperature of the air in the balloon = [(1.23)(288)]/(0.65)
Temperature of the air in the balloon = 544.98
Temperature of the air in the balloon = 545 K
Temperature of the air in the balloon = 545 - 273 = 272°C
Temperature of the air in the balloon to lift a total load of 290 kg is 272°C.
What is temperature?Temperature is the degree of hotness or coldness of the object.
Given is Volume of balloon = 500 m³, Air temperature = 15° C = 273 + 15 = 288 K
Total weight = 290 kg and Density of air = 1.23 kg/m³
Density of hot air = Density of air - [Total weight / Volume of balloon]
Density of hot air = 1.23 - [290 - 500]
Density of hot air = 0.65 kg/m³
Density is inversely proportional to the temperature.
[ρ hot air] x [T air in the balloon] = [ρ air] x [T air ]
Putting the values, we get temperature of the air in the balloon is
T air = [(1.23)(288)]/(0.65)
T air in Kelvin is 545 K
T air in Celcius is 545 - 273 = 272°C.
Thus, the temperature of the air in balloon is 272°C.
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Cass is walking her dog (Oreo) around the neighborhood. Upon arriving at Calina's house (a friend of Oreo's), Oreo turns part mule and refuses to continue on the walk. Cass yanks on the chain with a 67 N force at an angle of 30° above the horizontal. Determine the horizontal and vertical components of the tension force.
Answer:
Horizontal component: \(F_x = 58\ N\)
Vertical component: \(F_y = 33.5\ N\)
Explanation:
To find the horizontal and vertical components of the force, we just need to multiply the magnitude of the force by the cosine and sine of the angle with the horizontal, respectively.
Therefore, for the horizontal component, we have:
\(F_x = F * cos(angle)\)
\(F_x = 67 * cos(30)\)
\(F_x = 58\ N\)
For the vertical component, we have:
\(F_y = F * sin(angle)\)
\(F_y = 67 * sin(30)\)
\(F_y = 33.5\ N\)
So the horizontal component of the tension force is 58 N and the vertical component is 33.5 N.
4. The angle of projection at which a projectile attains the minimum range is A. 45⁰ B. 60⁰ C. 76⁰ D. 90⁰ E. None
Explanation:
Free Solutions to GR BATHLA & SONS BIOLOGY (HINGLISH) Class 12 book Chapters, Questions, Answers and Solutions 2022
A remote control boat with a mass of 4.5 kg starts at rest. A propeller performs 300 joules of work on the boat. What is the boats final velocity ?
The boat's final velocity can be determined using the work-energy principle. Since the boat starts at rest, the work done on it will be equal to its change in kinetic energy.
Using the equation:
Work = Change in Kinetic Energy
300 J = (1/2) * m * v^2
where m is the mass of the boat and v is the final velocity, we can solve for v.
Plugging in the values:
300 J = (1/2) * 4.5 kg * v^2
Simplifying the equation:
v^2 = (2 * 300 J) / 4.5 kg
v^2 = 200 J / 4.5 kg
v^2 = 44.44 m^2/s^2
Taking the square root of both sides:
v = √(44.44 m^2/s^2)
v ≈ 6.66 m/s
Therefore, the boat's final velocity is approximately 6.66 m/s.
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A toy rocket is shot straight up into the air with an initial speed of 45m/s. The acceleration of gravity is -9.8m/s^2. a) How long does it take for the rocket to reach its highest point?
The rocket to reach its highest point at Δt = 4.59s.
Equation :Given data,
a = -9.8m/s²
v = 45m/s
t = ?
So using formula,
a = Δv/Δt
Where,
a is acceleration
v is velocity or speed
t is time
Now putting values,
-9.8m/s² = 45m/s / Δt
Δt = Δv/a
Δt = 45m/s / 9.8m/s²
Δt = 4.59s
What is acceleration ?Any process where the velocity changes is referred to as acceleration. There are only two ways to accelerate because velocity is a function of both speed and direction: changing your speed, changing your direction, or changing both.
The first of the three types of acceleration is
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A comet is known to be traveling toward the earth at a speed of 255 km per second. It is observed to give light with a frequency of 642 x 1014 Hz. What frequency of light would the come be emitting if it were motionless? Express your answer to the nearest hundred trillion Hz.
Given:
The speed of the comet, u=255 km/s=255×10³ m/s
The observed frequency, f_o=642×10¹⁴ Hz
To find:
The frequency emitted by the comet.
Explanation:
The observed frequency is given by,
\(f_o=\sqrt{\frac{c+u}{c-u}}f\)Where c is the speed of light and f is the frequency emitted by the comet.
On substituting the known values,
\(\begin{gathered} 642\times10^{14}=\sqrt{\frac{3\times10^8+255\times10^3}{3\times10^8-255\times10^3}}\times f \\ \implies f=\frac{642\times10^{14}}{\sqrt{\frac{3\cdot10^{8}+255\cdot10^{3}}{3\cdot10^{8}-255\cdot10^{3}}}} \\ =641\times10^{14}\text{ Hz} \end{gathered}\)Final answer:
The frequency emitted by the comet is 641×10¹⁴ Hz
In 1986, a 35 × 10' kg watch was demonstrated in Canada. Suppose this
watch is placed on a huge trailer that rests on a lightweight platform, and
that oscillations equal to 0.71 Hz are induced. Find the trailer's mass if the
platform acts like a spring scale with a spring constant equal to 1.0 x 10° N/m
The mass of the trailer would be 0.10 kg
What is the period of a mass spring system?The period of a mass spring system is said to be directly proportional to the square root of the mass and inversely proportional to the square root of the spring constant.
It is represented thus;
T = 2π × √ m ÷ k
But note that period (T) is the reciprocal of frequency (f)
So, T = 1 ÷ f
Then, T = 2π × √ m ÷ k = 1 ÷ f
Make the mass 'm' the subject of the formula
m = k ÷ 2π^2 × f^2
Where
m = mass
k = spring constant
f = frequency
π = 3. 14
Mass, m = 1. 0 × 10^ 0 ÷ 2× 3.14 × 3.14 × 0.71 × 0. 71
= 1.0 × 1 ÷ 9. 94
= 0. 10 kg
Therefore, the mass of the trailer would be 0. 10kg.
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Planet X has a mass m and a radius r. Planet Y has a mass ½ m and a radius ¼ r. An identical tennis ball of mass mt sits on both planets’ surfaces. How does the magnitude of the gravitational force on planet X compare to the magnitude of the gravitational force on planet Y?
The gravitational force on planet X is one-eight (¹/₈) of the magnitude of gravitational force on planet Y.
What is the gravitational force on both planets?
The gravitational force on each planet is directly proportional to the product of mass of the planet and the tennis ball and inversely proportional to the square of the radius of the planets.
F = GmM/r²
where;
G is universal gravitation constantm is the mass of the tennis ballM is the mass of the planetsr is the radius of the planetThe gravitational force on planet X is written as;
F_X = Gm(mt) / r²
where;
m is the mass of planet Xmt is the mass of the tennis ballr is the radius of the planet xThe gravitational force on planet Y is written as;
F_y = G(½m)(mt) / (¼r)²
F_y = ½(Gm(mt) / (¹/₁₆ r²)
F_y = (16 Gm mt)/(2r²)
F_y = 8(G m(mt) ) / r²
F_y = 8(F_X)
F_X = ¹/₈(F_Y)
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The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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Define invariant transformations
Answer:
For a given system, there can be particular transformations for which the explicit equations of motion are the same for both the old and new variables. Transformations for which the equations of motion are invariant, are called invariant transformations. It will be shown that if the Lagrangian does not explicitly contain a particular coordinate of displacement qi, then the corresponding conjugate momentum, pi, is conserved. This relation is called Noether’s theorem which states “For each symmetry of the Lagrangian, there is a conserved quantity".