select below the type of cluster where standby server exists only to take over for another server in the event of its failure.

Based on the information provided by these technicians, both of them are correct.

According to heating, ventilation, and air conditioning (HVAC), heat in an air-conditioning system generally flows from the hotter object to the colder object.

As the refrigerant evaporates in a small radiator-type unit (evaporator), it absorbs heat as it changes phase from liquid to gas. Also, as the heat is being absorbed by the refrigerant, the small radiator-type unit (evaporator) becomes cold.

In conclusion, we can logically deduce that both of them are correct.

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Answer:

Hello There!!

Explanation:

The answer is territorial.

hope this helps,have a great day!!

~Pinky~

\(\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}\)

The county is normally the state's largest political and Territorial unit.

On a 20-degree inclined plane using the polar plot angle definition, a stationary object will have a normal pointing along an elevation angle of 20 degrees.

According to the polar angle definition, the angle of inclination is calculated from the horizontal, with 0 degrees being parallel to the horizontal and 90 degrees being perpendicular to the horizontal. As a result, on a 20-degree inclined plane, the angle of inclination is measured from the horizontal plane, with 20 degrees being the angle of inclination.Therefore, the normal force, which is perpendicular to the plane, will point along an elevation angle of 20 degrees. The normal force, on the other hand, is equivalent in magnitude to the weight of the stationary object on the inclined plane, which is given by the formula:weight of stationary object = mass of object x gravitational accelerationwhere the mass of the object and gravitational acceleration are constant values determined by the properties of the object and the location of the inclined plane.

Finally, it is critical to emphasize that the polar angle definition is only relevant when dealing with two-dimensional systems. When dealing with three-dimensional systems, the angle of inclination is calculated differently and is referred to as the inclination angle, which is the angle between the plane and the horizontal plane.

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Answer:

The entire place was dark and cold as the train whooshed by. This place was nothing like Platform 9 and 3/4. The rain was loud on the roof of the station, but you could still hear the faint noises of a violin. "20 pence for requests" read a sign from a man who's just trying to get by.

Explanation:

hope this helps:)

Note that the option which is true of multibody parts in SolidWorks Simulation are Options A - C.

It is to be noted that SolidWorks Simulation is a computer-aided engineering (CAE) tool that is used to analyze the behavior of mechanical systems and components under different loads and operating conditions.

It allows engineers to virtually test the strength, durability, and performance of designs before they are physically built, which can help to identify and correct potential problems early in the design process. SolidWorks Simulation can be used to analyze a wide range of mechanical systems, including structures, mechanisms, and fluids, and can be applied to various industries such as automotive, aerospace, and manufacturing.

The software provides a range of analysis types, including static, dynamic, fatigue, and thermal analysis, and can be used to optimize designs for weight, cost, and performance.

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The defining feature of the Metaverse is that it is Virtual. This is its a most distinctive feature. See further details below.

The Metaverse does not compete with the internet; rather, it expands upon it.

Users navigate a virtual environment that duplicates features of the actual world utilizing technologies such as virtual reality (VR), augmented reality, artificial intelligence (AI), social media, and digital money in the metaverse.

Metaverse features include digital avatars, remote working, developing decentralization, hardware, encryption, and many more.

Similarly, virtual places like Zoom only allow for a single conversation. Participants at physical events can transition seamlessly from one talk to the next. Some colleges are utilizing metaverse technology to bypass internet and video meeting tool constraints.

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Answer:

the lead of a 1/2 inch diameter drill with a 118 degree included angle is approximately 0.661 inches.

Explanation:

The lead of a drill bit is the distance that the bit advances axially for each complete revolution. The formula for lead is:

lead = (π / tan(θ)) x d

where:

- π is the mathematical constant pi (approximately 3.14159)

- θ is the included angle of the drill bit (in radians)

- d is the diameter of the drill bit

In this case, the diameter of the drill bit is given as 1/2 inch. We need to convert this to inches:

d = 1/2 inch = 0.5 inches

The included angle of the drill bit is given as 118 degrees. We need to convert this to radians:

θ = 118 degrees x (π / 180 degrees) = 2.058 radians

Now we can use the formula to calculate the lead:

lead = (π / tan(θ)) x d

= (π / tan(2.058)) x 0.5

≈ 0.661 inches

Therefore, the lead of a 1/2 inch diameter drill with a 118 degree included angle is approximately 0.661 inches.

Solution :

Taken moment about point B;

\($\sum M_B = 0$\)

\($\left[(w)(4)(2)-N_A \sin 30^\circ (3)(\sin 30^\circ)-N_A \cos 30^\circ(3 \cos 30^\circ +4) \right] =0$\)

\($N_A = 1.2376w$\)

\($\sum F_x = 0$\)

\($N_A \sin 30^\circ - B_x = 0$\)

\($B_x = 1.2376w \times \sin 30^\circ$\)

\($B_x = 0.6188w$\)

\($\sum F_y = 0$\)

\($B_y+N_A \cos^\circ - (w \times 4) = 0$\)

\($B_y+(1.2376w) \cos 30^\circ - (w \times 4)=0 $\)

\($B_y = 2.9282w$\)

Now calculating the resultant force at B,

\($F_B= \sqrt{B_x^2+B_y^2}$\)

\($F_B= \sqrt{(0.6188w)^2+(2.9282w)^2}$\)

     = 2.9929w

For no failure,

\($N_A<4 \ kN $\)

2.9929 w < 4 kN

\($w < 3.232 \ kN/m$\)

And,

\($F_B < 8 \ kN$\)

2.9929 w < 8 kN

w < 2.673 kN/m

For the safe operation, w = 2.673 kN/m  

The Cartesian and polar notation based on the information is solved below.

Cartesian notation:

P₁ - P₂ = (6cos(445°) - 2cos(460°))i + (6sin(445°) - 2sin(460°))j

≈ 3.43i - 2.91j

P₂ - P₁ = (-3.43)i + (2.91)j

Polar notation:

R1 = sqrt((6^2 + 2^2) - (262cos(460°-445°))))

≈ 3.91"

θ1 = atan2(6sin(445°) - 2sin(460°), 6cos(445°) - 2*cos(460°))

≈ -20.94°

R2 = sqrt((6^2 + 2^2) - (262cos(445°-460°))))

≈ 3.91"

θ2 = atan2(2sin(460°) - 6sin(445°), 2cos(460°) - 6*cos(445°))

≈ 159.06°

b) Cartesian notation:

P₁ - P₂ = (10cos(120°) - 4cos(40°))i + (10sin(120°) - 4sin(40°))j

≈ -5.74i + 8.66j

P₂ - P₁ = (5.74)i - (8.66)j

Polar notation:

R1 = sqrt((10^2 + 4^2) - (2104cos(40°-120°))))

≈ 11.18 cm

θ1 = atan2(10sin(120°) - 4sin(40°), 10cos(120°) - 4*cos(40°))

≈ 123.69°

R2 = sqrt((10^2 + 4^2) - (2104cos(120°-40°))))

≈ 11.18 cm

θ2 = atan2(4sin(40°) - 10sin(120°), 4cos(40°) - 10*cos(120°))

≈ -56.31°

c) Cartesian notation:

P₁ - P₂ = (4cos(4225°) - 3cos(45°))i + (4sin(4225°) - 3sin(45°))j

≈ -2.58i - 0.17j

P₂ - P₁ = (2.58)i + (0.17)j

Polar notation:

R1 = ✓(4^2 + 3^2) - (243cos(45°-4225°))))

≈ 4.14'

θ1 = atan2(4sin(4225°) - 3sin(45°), 4cos(4225°) - 3*cos(45°))

≈ -44

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Answer:

I think 1 31/32

Answer:

The main reason for bridges collapses is: earthquakes (natural disasters) and construction incidents. Whenever a natural disaster occur, it makes the bridge collapse. An example is hurricanes. Hurricanes come with a great wind and that might lead to the bridge collapsing. Construction incidents means the bridge falls during construction. Those who are employed in health, safety and environmental management need to make sure that during the construction, they have examined the material and made sure it is strong. Working with economists, they should seek better understanding of the methods for minimizing the costs during the life of the bridge. In case for natural disasters, like flooding, they should make the bridge in a lever where the water won't reach the bridge. And they should have a limit for weight in the bridges because that is another reason it collapses, because the bridge does not support extra weight.

Explanation:

hope this helps

The lighting fixtures should be waterproof and properly sealed.

Lighting fixtures installed above an indoor pool need to meet specific criteria to ensure safety and durability. These fixtures should be designed specifically for wet or damp environments and be rated as waterproof.

Water can create a hazardous situation if it comes into contact with electrical components, so the fixtures must have appropriate seals to prevent water ingress. Additionally, it's crucial to choose fixtures that are corrosion-resistant to withstand the humid environment around the pool.

The requirements for lighting fixtures in wet environments to ensure safety and longevity. Waterproofing and proper sealing are crucial to protect against electrical hazards and ensure the fixtures can withstand the pool's surroundings.

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Tensile strength is a measure of the maximum stress that a material can resist under tensile stress.

The strength of a material is a measure of its ability to withstand external forces without breaking or deforming. It is usually expressed as the maximum stress that a material can withstand before it fails. In the case of tensile strength, this refers to the maximum stress that a material can resist under tension, which is when a force is applied to pull it apart.

Tensile strength is an important property to consider when selecting materials for engineering applications. The tensile strength of a material can be determined through a variety of tests, including the tensile test, where a sample of the material is subjected to tension until it breaks.

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Therefore, the pressure of the flow downstream of the compression corner is approximately 26.274 atm.

To calculate the pressure of the flow downstream of the compression corner, we can use the conservation of total pressure across the expansion and compression corners. Assuming ideal gas behavior, the total pressure remains constant throughout the flow.

Given:

Mach number (M) = 3

Pressure (P1) = 3 atm

Expansion corner angle (θ1) = 20°

Compression corner angle (θ2) = 20°

We can use the following equation to calculate the pressure downstream of the compression corner:

P2 = P1 * (1 + [(γ - 1) / 2] * M^2)^(γ / (γ - 1))

where:

P2 is the pressure downstream of the compression corner

γ is the specific heat ratio of the gas

For air, the specific heat ratio (γ) is approximately 1.4.

Let's plug in the values and calculate the pressure:

P2 = 3 * (1 + [(1.4 - 1) / 2] * 3^2)^(1.4 / (1.4 - 1))

Simplifying the equation:

P2 = 3 * (1 + [0.4 / 2] * 9)^1.4

P2 = 3 * (1 + 0.2 * 9)^1.4

P2 = 3 * (1 + 1.8)^1.4

P2 = 3 * (2.8)^1.4

P2 ≈ 3 * 8.758

P2 ≈ 26.274 atm

Roundingto three decimal places:

P2 ≈ 26.274 atm

Therefore, the pressure of the flow downstream of the compression corner is approximately 26.274 atm.

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Answer:

He can take the job at the fast food restaurant to make money in order to pursue his career in robotics it doesnt mean he cant pursue it just he needs to make money for it first.

Answer:

20368.917N

Explanation:

Frictional force (F) is the product of the Coefficient of friction and the normal reaction.

F = μN

Coefficient of friction, μ = 0.2

Normal reaction = MgCosθ

Mass, m = 12 tonnes = 12 * 1000 = 12000 kg

N = 12000 * 9.8 * cos30

N = 101844.58

F = 0.2 * 101844.58

F = 20368.917N

There are 2n potential binary input possibilities for n input variables. There is just one potential output value for each given input combination.

The number of combinations is two to the power of N, and in this case, N is equal to eight, as shown by our general expression for a circuit with N inputs. Therefore, two to the power of eight, or 256, distinct configurations are possible for a circuit having eight inputs. The sequence of the results is irrelevant when calculating the overall outcomes of an event using combinations. In order to calculate combinations, divide the total number of items (n) by the number of items being chosen at a time (r).

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Answer:

This is not a clear indication of the hot zone as the information of the radioactivity of the background is not provided clearly.

Explanation:

According to IAEA as well as NRCP, the hot area is defined on the basis of the radioactivity reading it shows instead of contrast or comparative reading from the background. The value of radiation activity which will be required to declare an area as hot zone is if it is greater than 0.1 mSv/h or \(1.5091\times 10^{29} kg^{-1} s^{-1}\).

The number of tie-downs can be increased for extra safety. Therefore, it is essential to consult the FMCSA regulations and the manufacturer's guidelines to determine the appropriate number of tie-downs required for a 20-foot load. 150 words

The number of tie-downs required for a 20-foot load will depend on the type of cargo, the weight, the size, and the configuration of the vehicle, among other factors.

The Federal Motor Carrier Safety Administration (FMCSA) regulates the use of tie-downs to secure cargo on commercial motor vehicles. The FMCSA requires that all cargo be adequately secured to prevent shifting during transportation, especially on open trucks, flatbeds, and trailers. Therefore, the number of tie-downs will depend on the weight and type of cargo being transported. It is essential to note that the FMCSA has specific regulations and requirements for different types of cargo. For instance, FMCSA regulations require that a 20-foot load weighing less than 1,100 pounds may require at least one tie-down.

However, the rules can change depending on the length and weight of the load. For a 20-foot load weighing between 1,100 pounds and 2,200 pounds, two tie-downs are required. For loads weighing between 2,200 pounds and 5,000 pounds, the number of tie-downs required will depend on the length of the load and the type of cargo. In general, at least two tie-downs are required for cargo shorter than 5 feet, while longer cargo may require at least four tie-downs to secure the load.

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Answer:

  a) up

  b) down

Explanation:

When the cube is less dense than water, it will tend to float (move upward). When it is more dense, it will sink (move downward).

a) 160.2 kg/m^3 < 1000 kg/m^3. The cube will move up.

__

b) 7849 kg/m^3 > 1000 kg/m^3. The cube will move down.

Answer:

substance B

Explanation:

Answer:

Explanation:

Hi sorry I'm new and need points ty

Explanation:

proof that the flow area of a triangular hydraulic section is half of a rectangular section with the same base and height.

Let's consider a rectangular channel with width "b" and height "h". The flow area of the rectangular channel can be calculated as:

A_rectangular = b * h

Now, let's consider a triangular channel with base "b" and height "h". The flow area of the triangular channel can be calculated as:

A_triangular = 0.5 * b * h

To prove that the flow area of the triangular channel is half of the rectangular channel, we can take the ratio of the two flow areas:

A_triangular / A_rectangular = (0.5 * b * h) / (b * h)

Simplifying this expression, we get:

A_triangular / A_rectangular = 0.5

Therefore, we can conclude that in the case of a rectangular channel with width "b" and height "h", the flow area of a triangular channel with base "b" and height "h" is half of the flow area of the rectangular channel.

However, it's important to note that this result only holds true for this specific case where the rectangular channel and the triangular channel share the same base and height. If the dimensions of the channels differ, the flow area of the triangular channel will not necessarily be half of the flow area of the rectangular channel.

NOTE. (just a concern)

it's important to note that this is only true for a specific case, and it's not a general rule that applies to all triangular and rectangular sections. In general, the flow area of a hydraulic section depends on its geometry and cannot be determined solely based on the shape of the section.

Radio waves are radiated by charged particles when they are accelerated. They are produced artificially by time-varying electric currents, consisting of electrons flowing back and forth in a specially-shaped metal conductor called an antenna. ... Radio waves are received by another antenna attached to a radio receiver.

Answer: Wave Currents??

WIDE OPEN GUESS

Answer:

Click "Simulate"-"Edit Simulation Cmd" in the menu bar to open the "Edit Simulation Command" screen. Select "Transient" and enter "10 m" for Stop time. You should now see ". tran 10m" at the bottom of the screen.

Explanation:

Answer:

wind vane if it can be used to show wind speed and the other is a

Explanation:

please mark 5 star if im right and brainly when ya can

Answer:

1100

Drafting Standard AS 1100

AS1100 is the drawing standard that is used within Australia. It defines every aspect of the drawing. AS1100 provides a standard that (if followed by all companies), allows for a clarity, understanding and uniformity across all drawings generated nation wide.

The Australian standard that endorses drawing symbols and shape codes for RC drawing is; AS1100

Different countries have their different codes and drawing standards that serve as a basis for drawings. For most of Europe, it is Euro Code while for US it is ACI Code and for UK, it is BS Code.

Other codes of countries could be BS 5950 which is steel code for the UK and BS 8110 which is concrete code for the UK. Whereas, for Australia it is called AS1100 Code for drawing symbols and shape codes.

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