Scientific theories are always?

Answer:

Hydrogen

Explanation:

These are what hydrogen isotopes look like

Taking into account the reaction stoichiometry, 112.5 grams of water are formed when 12.5 g of hydrogen reacts with oxygen.

In first place, the balanced reaction is:

2 H₂ + O₂ → 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 4 grams of H₂ form 36 grams of H₂O, 12.5 grams of H₂ form how much mass of H₂O?

mass of H₂O= (12.5 grams of H₂×36 grams of H₂O)÷4 grams of H₂

mass of H₂O= 112.5 grams

Finally, 112.5 grams of H₂O are formed.

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The NBS (N-bromosuccinimide) bromination of cyclohexa-1,4-diene can result in the formation of two different products due to the presence of two different reactive positions (double bonds) in the starting material. The reaction can occur at either one or both of these positions.

Here are the possible products:

1. 1-Bromo-1,4-cyclohexadiene:

   H   H Br

   |    |    |

H-C=C-C=C-C-H

   |   |     |

  H  Br  H

2. 1-Bromo-1,2-cyclohexadiene:

   H  Br H

    |   |    |

H-C=C-C=C-C-H

    |    |   |

    H  H  Br

In the first product, bromination occurs at the 1,4-positions of the cyclohexadiene, while in the second product, bromination takes place at the 1,2-positions. Remember that the double bonds are depicted as lines, and the superscripts indicate the bromine atom attached to the respective carbon atoms.

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The half-reactions for a galvanic cell with Zn and Ni electrodes are,

Zn(s) → Zn2+(aq) + 2e- (oxidation half-reaction) and Ni2+(aq) + 2e- → Ni(s) (reduction half-reaction)

The correct option is option D. Zn(s) → Zn2+(aq) + 2e and Ni2+(aq) + 2e → Ni(s).

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newton's first law of motion states than an object motion will not change unless subjected to an external force.

Answer:

The absorbed energy will change the electron's position. We can never know both the momentum and position of an electron in an atom.

Explanation:

Based on the results obtained, the sample with the shortest time taken for the color change to occur contains the largest number of carbon to carbon double bonds.

What is Saturated Fat?

Saturated fat is a type of fat in which all the carbon atoms in the fatty acid chains are bonded to hydrogen atoms, leaving no double bonds between the carbon atoms. This results in a straight and rigid molecular structure that allows the fat molecules to pack tightly together, leading to a solid or semi-solid consistency at room temperature. Saturated fats are commonly found in animal products, such as meat and dairy, as well as in some plant-based sources like coconut and palm oil. A diet high in saturated fats has been linked to an increased risk of heart disease and other health problems.

The sample with the largest number of carbon to carbon double bonds will react the fastest with the bromine water, resulting in the quickest color change from orange to colorless. Therefore, the sample with the shortest time taken for the color change to occur will contain the largest number of carbon to carbon double bonds.

Therefore, the sample that contains the most carbon to carbon double bonds can be determined by comparing the times taken for the color change to occur in each sample.

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Answer:

c = 0.898 J/g.°C

Explanation:

1) Given data:

Mass of water = 23.0 g

Initial temperature = 25.4°C

Final temperature = 42.8° C

Heat absorbed = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Specific heat capacity of water is 4.18 J/g°C

ΔT = 42.8°C - 25.4°C

ΔT = 17.4°C

Q = 23.0 g ×  × 4.18 J/g°C × 17.4°C

Q = 1672.84 j

2) Given data:

Mass of metal = 120.7 g

Initial temperature = 90.5°C

Final temperature = 25.7 ° C

Heat released = 7020 J

Specific heat capacity of metal = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 25.7°C - 90.5°C

ΔT = -64.8°C

7020 J = 120.7 g ×  c ×  -64.8°C

7020 J = -7821.36 g.°C ×  c

c = 7020 J / -7821.36 g.°C

c = 0.898 J/g.°C

Negative sign shows heat is released.

Answer:

from what it is reduced

The mass of anhydrous magnesium sulfate that will remain is 11.7 g.

When a hydrated salt such as MgSO₄⋅7H₂O is heated thoroughly so it becomes anhydrous, all the moles of water of crystallization are driven off.

The mass of anhydrous magnesium sulfate will remain if 24.0 g of MgSO₄⋅7H₂O is thoroughly heated is calculated as follows:

Molar mass of MgSO₄⋅7H₂O = 24 + 32 + 16 * 4 + 7 * 18

Molar mass of MgSO₄⋅7H₂O = 246 g/mol

Percentage mass of anhydrous magnesium sulfate will be:

mass of MgSO₄ = 24 + 32 + 16 * 4

mass of MgSO₄ = 120 g

Percentage mass of anhydrous magnesium sulfate = 120/246 * 100%

Mass of anhydrous magnesium sulfate that will remain = 120/246 * 100 * 24

Mass of anhydrous magnesium sulfate that will remain = 11.7 g

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Answer:

Single Replacement.

Explanation:

\(hopefully \: \: that \: \: helps\)

1618.974g is the mass of 9.45 moles Ba(OH)\(_2\).  In current physics, mass has several meanings that are theoretically distinct but physically equal.

A body's mass is an inherent attribute. Until the discovery of both the atom as well as particle physics, it was thought to be tied to the amount of matter inside a physical body.

It was discovered that although having the same quantity of stuff, various atoms and fundamental particles had varying masses. In current physics, mass has several meanings that are theoretically distinct but physically equal.

mole of Ba(OH)\(_2\)=mass of Ba(OH)\(_2\)/Molar mass of Ba(OH)\(_2\)

mass of Ba(OH)\(_2\)= number of mole× Molar mass

Molar mass of Ba(OH)\(_2\)=171.32g/mol

mole of Ba(OH)\(_2\)= 9.45 mol

mass of Ba(OH)\(_2\) = 171.32x9.45= 1618.974g

Therefore, 1618.974g is the mass of 9.45 moles Ba(OH)\(_2\).

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The answers to the given problem are monthly energy use of household in m3 of natural gas equivalent = 787.5 m³, Monthly energy use of household in kg of oil equivalent = 0.29484627 ktoe, CO2 footprint of household in kg = 1500 kgCO2 (1.5 metric tonnes of CO2).

1) Calculation of monthly energy use in m3 of natural gas equivalent:For every 1 kWh of electricity produced, the gas turbines consume 0.21 m³ of natural gas equivalent.

The consumption of natural gas equivalent can be calculated by multiplying the monthly average electric energy consumption by the quantity of natural gas equivalent that is consumed by gas turbines for every 1 kWh of electricity produced.

So, the monthly consumption of natural gas equivalent will be,

3750 kWh * 0.21 m³/kWh = 787.5 m³ of natural gas equivalent

Calculation of monthly energy use in kg of oil equivalent:

Assuming that natural gas has a calorific value of 55.5 MJ/m³, and that the conversion efficiency of natural gas turbine is 33%, the equivalent energy that will be produced from 1 m³ of natural gas is 55.5 x 0.33 = 18.315 MJ/m³.

In order to calculate the equivalent energy that will be produced from 787.5 m³ of natural gas, we can use the formula:

Equivalent energy = calorific value of natural gas x volume of natural gas x conversion efficiency

So, the equivalent energy that will be produced from 787.5 m³ of natural gas is,

Equivalent energy = 55.5 x 787.5 x 0.33

= 12337.3125 MJ

= 12.337 GJ

So, the monthly consumption of oil equivalent will be:

12.337 GJ / 41.868 = 0.29484627 ktoe (kilo tonnes of oil equivalent)

2) Calculation of CO2 footprint in kg:

Assuming the average CO2 emissions coefficient for gas fired power plants is 400 g/kWh.

The CO2 footprint in kg can be calculated by multiplying the monthly average electric energy consumption by the CO2 emissions coefficient of gas-fired power plants.

So, the CO2 footprint in kg will be:

3750 kWh x 0.4 kg/kWh = 1500 kgCO2 (i.e., 1.5 metric tonnes of CO2).

Therefore, the answers to the given problem are:

Monthly energy use of household in m3 of natural gas equivalent = 787.5 m³

Monthly energy use of household in kg of oil equivalent = 0.29484627 ktoe

CO2 footprint of household in kg = 1500 kgCO2 (1.5 metric tonnes of CO2).

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A solution is defined as a mixture of two or more substances, usually, a solute and a solvent, and the difference between these two are in quantity, solute represents the smallest amount and solvent will represent the highest amount, and while you can have more than one solute, you can only have one solvent for a solution. Therefore the statement is true

Answer:

in sixth period out of 32 elements, 14 elements have been placed separately in horizontal row below periodic table.

The molar solubility of lead II iodide is 1.21 × 10^-3 M.

The term solubility product refers to the equilibrium constant that shows the extent to which a substance is dissolved in water. For the dissolution of lead II iodide we can write;

PbI2(s) ⇄ Pb^2+(aq) + 2I^-(aq)

Hence;

Ksp = [x] [2x]^2 = 4x^3

x = ∛Ksp/4

x  = ∛7 × 10^-9/4

x = 1.21 × 10^-3 M

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The molecular formula of eugenol is C10H12O2.  

To determine the molecular formula, we need to know the molar mass of eugenol. The molar mass of eugenol can be calculated using the given mass of eugenol (157.0 mg) and the volume of the solution (9.562 mm).
First, convert the mass of eugenol to grams by dividing by 1000:
157.0 mg = 0.157 g
Next, calculate the molarity of the solution using the volume and mass:
Molarity (M) = moles of solute / volume of solution (L)
Convert the volume from milliliters to liters by dividing by 1000:
9.562 mm = 0.009562 L
Now we can calculate the molarity:
Molarity = 0.157 g / 0.009562 L = 16.387 M

Since the molarity is given in moles per liter, we can divide the molar mass by the molarity to find the number of moles of eugenol:
Number of moles = molar mass / molarity
Number of moles = 0.157 g / 16.387 M = 0.00957 moles
From the molecular formula of eugenol, we know that it has 10 carbon atoms, 12 hydrogen atoms, and 2 oxygen atoms. The molar mass of eugenol is 164.2 g/mol. By dividing the molar mass by the number of moles, we can find the molecular formula:
164.2 g/mol / 0.00957 moles = 17162

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Answer: kerosene, coal

Explanation:

These are renewable resources obtained from petroleum, kerosene was used in olden times to light the lamps and are still used today for lighting purposes. Coal was used in trains to produce steam( steam powered trains).

Answer:

Fuel Oil and Kerosene Oil are used as fuel. They are an important part of our life. Kerosene Oil is primarily used in the laboratory. Fuel Oil is used in power stations.

Answer: H2SO4 + 2NaOH = Na2SO4 2H2O

Explanation: The ChemicalAid website is very helpful if you need to balance chemical equations.

If you are unsure which layer is which in an extraction procedure, there are a few steps you can take to try and identify them.

One approach is to carefully observe the physical properties of each layer, such as color, viscosity, and density. For example, the aqueous layer is typically clear or pale yellow in color, while the organic layer may be darker and more viscous.
You can also perform a simple test to determine which layer is which. One common method is to add a small amount of water to the mixture and observe which layer the water separates into. Since water is more polar than many organic solution, it will typically dissolve in the aqueous layer and not in the organic layer.
If you are still unsure which layer is which, you may need to consult a reference or an expert in the field to help you identify them. In any case, it is important to take care when working with extraction procedures, as improper identification of layers can result in loss of product or inaccurate analysis.

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The Molar Concentration Of A =0.099 .

The Relative Molar Mass Of A = 35.0129 gm

Given,

Mass of HX = 3.5 g

Moles of solution B (\(Na_{2} CO_{3}\)) = 0.05 moles

Volume of HX = 26.10 mL

Volume of Solution B = 25 mL

Molecular weight of solution B = 2(atomic weight of Na )+ atomic weight of C + 3(atomic weight of O)

                 = 2(23) + 12 + 3(16)

                 =106 gm

Equivalent weight of  \(Na_{2} CO_{3}\) = molecular weight / 2 = 106 /2  =53 g

Mole = mass / molecular weight

∴0.05 = mass / 106

∴ mass = 5.3 gm \(Na_{2} CO_{3}\)

Normality = mass ÷ (equivalent weight × volume of the solution in liter)

                = 5.3 ÷( 53 × 0.025)

                =4 N

So, by using formula ,

\(N_{1} V_{1} =N_{2} V_{2}\)

\(N_{1}\) = normality of solution B = 4 N

\(V_{1}\) = volume of solution B = 25 mL

\(N_{2}\) = normality of solution A = ? N

\(V_{2}\) =Volume of solution A = 26.1 mL

∴ 4×25 = \(N_{2}\) × 26.1

∴\(N_{2}\) = 3.83 N

∴ normality of solution A = 3.83 N

from Formula of the normality we can find the equivalent weight of the A

Normality = mass of HX ÷ (equivalent weight × volume of the solution in liter)

3.83 = 3.5 ÷( equivalent weight × 0.0261)

∴equivalent weight = 35.0129 g

In case of HX the electron transfer is 1 ,so equivalent weight = molecular weight ; which is also termed as relative molar mass in given case.

∴The Relative Molar Mass Of A = 35.0129 g

Molar concentration = mass / molar mass

                               = 3.5 / 35.0129

                               = 0.099 mole

∴ The Molar Concentration of A  is 0.099 .

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The correct statement is as follows: No, it is not because the freezing point is not related to electrostatic forces (option C).

Electrostatic forces are attractive or repulsive forces between particles that are caused by their electric charges.

Melting point refers to the temperature at which the solid and liquid phases of a substance are in equilibrium.

According to this question, a student wants to determine the melting point of water as part of an investigation into the strength of electrostatic forces.

However, the student considers determining the freezing point of water instead. This is not valid because freezing point is not related to electrostatic force.

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Answer:

Any kind, as long as there is an action.

Answer:

Energy can be transferred from one form to another like kinetic energy to potential energy, light energy to heat energy, kinetic energy to electrical energy, light energy to chemical energy .etc ...

Explanation:

brainest please

The strength of metallic bonds is dependent on the protons, delocalized electrons and ions.

The strength of a metallic bond is dependent on:

The strength of metallic bonds is dependent on the protons, delocalized electrons and ions.

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Answer:

C or B(most likley C)

Explanation:

The retention times of the compounds change if the solvent composition was changed from 55 vol% acetone and 45 vol% water to 85 vol% acetone and 15 vol% water is decreases..

The acetone and the water mixture is polar . this makes the example of reversed phase reaction. Acetone is the polar molecule and the water is also o polar molecule and there mixture is polar mixture.

For the polar solutes which are separated by the hydrophilic interaction chromatography. the the solvent composition changed from the 55 vol% of the acetone and the 45 vol% of the water to the 85 vol% of the acetone and the 15 vol% of the water , the retention times decreases.

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Answer:

The substances more alkaline than water are;

1) Spit, 2) Blood, 3) Hand Soap, and 4) Drain Cleaner

Explanation:

The diagram in the simulation displays a list of liquid substances, arranged from bottom to top in the order of increasing alkalinity.

The ph of water is 7.0

The ph of spit (saliva) is between 6.2 and 7.6

The ph of blood is about 7.4

The ph of hand soap is between 9 and 10

The ph of drain cleaner is between 12 and 14.

Hope this helps!

The increased variation in thorn size could lead to some individuals having thorns that are too large for Ostrilopes to handle, reducing the availability of food resources.

The impact of changing the thorn palm's average thorn size and increasing thorn size variation on the Ostrilopes population would depend on various factors such as the number of thorn palms in the area, the availability of other food sources, and the Ostrilope's ability to adapt to the changes.

Additionally, the relationship between thorn palms and Ostrilopes is complex, and changes in one can have cascading effects on the other and the entire ecosystem. Therefore, more research is needed to understand the specific effects of the thorn palm modifications on the Ostrilope population.

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