Sarah weighs 392 N. She pushes a 56 kg rock with a force of 65 N. What force does the rock exert on Sarah?

According to Ohm's law: V = IR

The rate of flow of charges will depend on the voltage supplied and the resistance in the wire.

ELECTRIC CHARGE

Current can be defined as the rate of flow of charges. Where charge is the product of current and time. This means that electric charge is proportional to electric current. The current in a conducting wire depends on;

The two factors that can affect the flow of electric charge in the given options are voltage and resistance

Because according to Ohm's law: V = IR

The rate of flow of charges will depend on the voltage supplied and the resistance in the wire.

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Answer:

A. and D.

Explanation: Identifying Factors That Affect Current

Which factors affect the flow of electric charge? Select two options.

[voltage]

ampere X

ohmX

[resistance]

volt X

Answer:

first one is - conduction

second one is - convection

I think conduction moves more easily

Fspring = mv, where Fspring is the force of the spring, m is the mass, and v is the velocity. The correct option is C.

The momentum of the mass when the spring passes its equilibrium position can be calculated by using Newton's second law of motion, Fnet = mv. The force of the spring Fspring is equal to mv, and so the momentum is equal to mv.

The momentum of the mass when the spring passes its equilibrium position is given by xVmk. Momentum is a vector quantity that is given by the product of the mass and velocity of an object.

It is represented by p. It is denoted as p = mv, where m is the mass of the object and v is the velocity of the object. Momentum is always conserved in an isolated system.

So, the momentum of the mass is given as xVmk.

Where x is the distance the spring was compressed from its original position, m is the mass attached to the spring and k is the force constant of the spring.

The correct formula for the momentum of the mass is p = m*v which is also known as the principle of conservation of momentum. Thus, the correct answer is option C.

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Answer:

Calculations involving forces

The resultant force is the single force that has the same effect as two or more forces acting together.

Two forces in the same direction

Two forces that act in the same direction produce a resultant force that is larger than either individual force.

You can easily calculate the resultant force of two forces that act in a straight line in the same direction by adding their sizes together.

Example

Two forces, 3 N and 2 N, act to the right. Calculate the resultant force.

Two arrows, one above the other, both pointing to the right, one labelled 2 N and one labelled 3 N. Then an equals sign and then another arrow to the right labelled 5 N.

Two forces acting in the same direction

Resultant force F = 3 N + 2 N = 5 N to the right.

The resultant force is 5 N to the right.

Two forces in opposite directions

Two forces that act in opposite directions produce a resultant force that is smaller than either individual force.

To find the resultant force subtract the magnitude of the smaller force from the magnitude of the larger force.

The direction of the resultant force is in the same direction as the larger force.

Example

A force of 5 N acts to the right, and a force of 3 N act to the left.

Calculate the resultant force.

Two arrows, one above the other, one pointing to the left, labelled 2 N, the other pointing to the right labelled 3 N. Then an equals sign, with an arrow to the right labelled 1 N.

Two forces acting in opposite directions

Resultant force F

Resultant force F = 5 N - 3 N = 2 N to the right.

The resultant force is 2 N to the right.

Explanation:

Thanks me later

Field strength refers to the magnitude of the gravitational field strength or acceleration due to gravity. It is measured in newtons per kilogram (N/kg) and can be denoted by the symbol ‘g.' Field strength plays a vital role in calculating the weight of an object.

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The field strength experienced by the object is 290.91 m/s².

The field strength an object experiences is determined by the gravitational force acting on it. The weight of an object is given by the equation w = mg, where w is the weight, m is the mass of the object, and g is the acceleration due to gravity.

Given that the weight of the object is 0.96 N, and the mass of the object is 3.3 g (or 0.0033 kg), we can use the equation w = mg to find the field strength (g). Rearranging the equation, we have g = w/m = 0.96 N / 0.0033 kg = 290.91 m/s².

So, the field strength experienced by the object is 290.91 m/s².

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Answer:

B. lower, greater

...............

The earth receives energy from the sun in one day than all the energy consumed by humans in one year.

The sun provides around 174 petawatts of energy to Earth, of which 89 petawatts is absorbed by the planet.

The Global energy consumption is roughly 15 terawatts annually.

Thus, we can conclude that, the earth receives energy from the sun in one day than all the energy consumed by humans in one year.

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Once a parachutist jumps from an airplane, they will start to accelerate due to the force of gravity pulling them towards the ground. However, as the parachutist falls faster, the air resistance or drag force that opposes their motion increases.

Eventually, the drag force becomes equal to the force of gravity, and the parachutist will stop accelerating and reach a constant speed, which is called the terminal speed or the maximum velocity.

At this point, the net force acting on the parachutist is zero, and the acceleration is also zero. The terminal speed depends on various factors such as the size and shape of the parachute, the weight of the parachutist, and the density and viscosity of the air.

Once the parachutist has reached terminal speed, they can control their descent by manipulating the shape and size of the parachute. By increasing the surface area of the parachute, they can increase the air resistance, slowing their descent.

Alternatively, by decreasing the surface area of the parachute, they can decrease the air resistance and increase their descent rate.

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Given 16 kg of a radioactive sample with a certain half-life of 15 years:

To determine how much of the 16 kg radioactive sample is left after 60 years with a half-life of 15 years, we will use the following steps:

1. Calculate the number of half-lives that have passed: 60 years / 15 years per half-life = 4 half-lives
2. Calculate the remaining sample amount using the formula: remaining amount = initial amount * (1/2)^number of half-lives
3. Apply the formula: remaining amount = 16 kg * (1/2)^4 = 16 kg * 1/16 = 1 kg

After 60 years, 1 kg of the radioactive sample is left. The correct answer is D. 1kg.

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The centripetal force that must be exerted against the wings to keep the plane moving in a circle is 3.71 × 10⁴ N.

Given that,

Time = 30 min = 30 × 60 sec = 1.8 × 10³ s

Radius = 50 km = 50× 10³ m = 5× 10⁴ m

We know the expression for velocity as,

v = 2πr/(T) = (2π×5× 10⁴) /(1.8 × 10³) = (π×10⁵)/(1.8 × 10³) = (100× 3.14)/1.8 = 174.44 m/s ≈ 175 m/s

Mathematically, centripetal force can be written as,

F = mv²/r = (60,500× 175²)/(5× 10⁴) = 3.71 × 10⁴ N

Thus, required centripetal force is 3.71 × 10⁴ N.

The question is incomplete. The complete question is ' Captain Chip, the pilot of a 60,500-kg jet plane, is told that he must remain in a holding pattern over the airport until it is his turn to land. If Captain Chip flies his plane in a circle whose radius is 50.0 km once every 30.0 min, what centripetal force must the air exert against the wings to keep the plane moving in a circle?'

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The amount of work done by the car of mass 2-kg that travels 7 m is 70 J.

Work is said to be done when a force moves an object through a certain distance.

To calculate the amount of work done by the car, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the amount of work done by the car is 70 J.

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A. spreadsheet or computer script, we can calculate the value, which is 9.80651834 m/s^2. B. the value gives g(90°, 10,000) ≈ 9.81937375 m/s^2. C. the value gives g(45°, 0) ≈ 9.80666553 m/s^2. D. the value gives: g(-66.5°, 3,048) ≈ 9.83065116 m/s^2. E. the cosine function is an even function (cos(-θ) = cos(θ)), the value of g will be different for φ and -φ, except when φ = 0 (equator) where cos(0) = cos(0) = 1.

To compute the acceleration of gravity at the given locations, we'll substitute the values of latitude (φ) and height above mean sea level (Z) into the formula for g(φ, Z).

(a) Baseline Road (latitude 40° North), at an elevation of one mile above mean sea level:

Latitude (φ) = 40°

Height (Z) = 1 mile = 1,609.34 meters

Substituting these values into the formula, we have:

g(40°, 1609.34) = 980.6160(1 - 0.0026373cos^2(40°) + 5.9×10^(-6)cos^2(2 * 40°)) - (3.085462×10^(-4) + 2.27×10^(-7)cos^2(40°)) * 1609.34 + (7.254×10^(-11) + 1.0×10^(-18)cos^2(40°)) * (1609.34)^2 - (1.517×10^(-17) + 6×10^(-20)cos^2(40°)) * (1609.34)^3

Using a spreadsheet or computer script, we can calculate the value, which is approximately: g(40°, 1609.34) ≈ 9.80651834 m/s^2.

(b) 10 km above the North Pole:

Latitude (φ) = 90° (North Pole)

Height (Z) = 10,000 meters

Substituting these values into the formula, we have:

g(90°, 10,000) = 980.6160(1 - 0.0026373cos^2(90°) + 5.9×10^(-6)cos^2(2 * 90°)) - (3.085462×10^(-4) + 2.27×10^(-7)cos^2(90°)) * 10,000 + (7.254×10^(-11) + 1.0×10^(-18)cos^2(90°)) * (10,000)^2 - (1.517×10^(-17) + 6×10^(-20)cos^2(90°)) * (10,000)^3

Calculating the value gives: g(90°, 10,000) ≈ 9.81937375 m/s^2.

(c) Halfway between the equator and the North Pole at mean sea level:

Latitude (φ) = 45°

Height (Z) = 0 meters

Substituting these values into the formula, we have:

g(45°, 0) = 980.6160(1 - 0.0026373cos^2(45°) + 5.9×10^(-6)cos^2(2 * 45°)) - (3.085462×10^(-4) + 2.27×10^(-7)cos^2(45°)) * 0 + (7.254×10^(-11) + 1.0×10^(-18)cos^2(45°)) * (0)^2 - (1.517×10^(-17) + 6×10^(-20)cos^2(45°)) * (0)^3

Calculating the value gives: g(45°, 0) ≈ 9.80666553 m/s^2.

(d) 10,000 feet above mean sea level at the Antarctic Circle (≈66.5 degrees South latitude):

Latitude (φ) = -66.5°

Height (Z) = 10,000 feet = 3,048 meters

Substituting these values into the formula, we have:

g(-66.5°, 3,048) = 980.6160(1 - 0.0026373cos^2(-66.5°) + 5.9×10^(-6)cos^2(2 * -66.5°)) - (3.085462×10^(-4) + 2.27×10^(-7)cos^2(-66.5°)) * 3,048 + (7.254×10^(-11) + 1.0×10^(-18)cos^2(-66.5°)) * (3,048)^2 - (1.517×10^(-17) + 6×10^(-20)cos^2(-66.5°)) * (3,048)^3

Calculating the value gives: g(-66.5°, 3,048) ≈ 9.83065116 m/s^2.

(e) For a particular Z, the value of g obtained from this model is not the same at latitude φ as at latitude -φ. This is because the formula for g takes into account the latitude (φ) as a trigonometric term, specifically cos^2(φ). Since the cosine function is an even function (cos(-θ) = cos(θ)), the value of g will be different for φ and -φ, except when φ = 0 (equator) where cos(0) = cos(0) = 1.

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Answer:

1kg = 1000g

67kg therefore would be equal to

67 x 1000 = 67,000g = 6.7 x 10⁴g.

Answer: 20 N

Explanation: Net force is the sum of all forces acting on an object. For example, in a tag of war, when one team is pulling the tag with a force of 100 N and the other with 80 N, the net force would be 20 N at the direction of the first team (100 N - 80 N = 20 N).

(a) This is because the lowest three standing wave vibration frequencies for a closed-open pipe correspond to odd harmonics (1st, 3rd, and 5th).

As for the length of the pipe, we can use the formula L = (n/4) * wavelength, where n is the harmonic number and wavelength is the distance between two adjacent nodes. For the first harmonic (n=1) with a frequency of 120 Hz, the wavelength is four times the length of the pipe. Thus, L = (1/4) * wavelength = (1/4) * (4L) = L. Solving for L, we get L = wavelength/4 = (speed of sound)/(4 * frequency) = 0.71 meters (assuming the speed of sound in air is 343 m/s).

(b), the frequencies of the first two harmonic vibrations on a pipe of the same length but of the other type (open-closed) can be found using the formula f = (n * v)/(2L), where v is the speed of sound in air and n is the harmonic number. For the first harmonic (n=1), we have f = v/(2L) = (343 m/s)/(2 * 0.71 m) = 242 Hz. For the second harmonic (n=2), we have f = 2v/(2L) = (2 * 343 m/s)/(2 * 0.71 m) = 485 Hz.

Therefore, the frequencies of the first two harmonic vibrations on an open-closed pipe of the same length are 242 Hz and 485 Hz, respectively.

Hence, The formula for the frequency of a standing wave in a pipe depends on the speed of sound, the length of the pipe, and the harmonic number.

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C. The magnitude of the acceleration of a planet in an orbit around the sun is proportional to the reciprocal of the distance between the planet and the sun.

The reciprocal of the distance between the planet and the sun ,This is known as Kepler's third law. The farther a planet is from the sun, the weaker the gravitational force between them and the slower the planet's acceleration.
The magnitude of the acceleration of a planet in an orbit around the sun is proportional to: C. The reciprocal of the distance between the planet and the sun.

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Answer:

Mass:  Choices 1, 2, 4, 6

Weight: Choices 3, 5, 7, 8

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That  when two trains emit 424 hz whistles and  one a train is stationary, the conductor on the stationary train hears a 3.0  frequency when the other train approaches. However  to fully understand area  This  a phenomenon are  is known as the Doppler effect.

which is a change in frequency or wavelength of a wave in relation to an observer who is moving relative to the wave source. In this case, the frequency of the sound waves emitted by the moving train is higher when it approaches the stationary train and lower when it moves away.

the observed frequency (427 Hz), f_source is the source frequency (424 Hz), v_sound is the speed of sound in air (approx. 343 m/s), v_observer is the speed of the stationary train (0 m/s), and v_source is the speed of the approaching trai the Doppler effect formula by plugging in known values: 427 = 424 * (343 + 0) / (343 + v_source  Solve for v_source: (427 / 424) * (343 + 0) = 343 + v_source Calculate the speed of the approaching train: v_source = (427 / 424) * 343 - 343 ≈ 2.34 m/s the speed of the approaching train is approximately 2.34 m/s.

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Answer:

The wavelength is 2 meters

Explanation:

The relationship between the frequency, the speed and the wavelength is given by the relation;

v = f × λ

The given parameters are;

The distance of the duck from the edge of the pond = 12 m

The number of ripples produced per second = Frequency, f = 2 Hz

The time it takes the ripple to reach the edge of the pond after travelling past the duck = 3 seconds

Therefore, speed of the wave, v = Distance/time = 12 m/(3 s) = 4 m/s

The wavelength, λ, is therefore;

λ = v/f = (4 m/s)/(2 Hz) = 2 meters.

Given data

*The given distance is s = 128 m

*The initial speed of the motorcycle is u = 0 m/s

*The final speed of the motorcycle is v = 32.6 m/s

The expression for the acceleration of the bike is given by the kinematic equation of motion as

Substitute the known values in the above expression as

Hence, the acceleration of the bike undergoes is a = 4.15 m/s^2

That depends on the values of the resistors.

If the same two resistors are used in both cases, then the total resistance is more in series and less in parallel.

Here's a catchy little factoid for ya:

-- In series, the total resistance is more than the biggest single one.

-- In parallel, the total resistance is less than the smallest single one.

Answer:

running a mile in six minutes

Explanation:

Answer:

Not example is B: Running a mile in six minutes

Answer:

Object D

Explanation:

Use Newton's Second Law to determine the acceleration that each object has.

The force applied in both cases is 50 N, but the mass for object C and object D is different.

Let's start with object C first:

The acceleration object C undergoes is 5 m/s².  

Now let's calculate object D next:

The acceleration object D undergoes is 25 m/s².

Object D has greater acceleration because it has a smaller mass. The object with a smaller mass will accelerate more in order to satisfy Newton's 2nd Law.

To calculate the entropy change of the two reservoirs, we need to use the formula:

ΔS = Q/T, where ΔS is the entropy change, Q is the amount of heat transferred, and T is the temperature of the reservoir.

First, let's calculate the entropy change of the hot reservoir. We know that Q = 100 kJ, and T = 950 K. Therefore:

ΔS(hot) = Q/T = 100 kJ / 950 K = 0.1053 kJ/K

Next, let's calculate the entropy change of the cold reservoir. We know that Q = -100 kJ (because heat is being removed from the hot reservoir and transferred to the cold reservoir), and T = 600 K. Therefore:

ΔS(cold) = Q/T = -100 kJ / 600 K = -0.1667 kJ/K

Note that the entropy change of the cold reservoir is negative because the heat transfer is from hot to cold, which goes against the natural flow of energy. This means that the cold reservoir becomes more ordered (less entropy) as it receives heat.

So, the detailed answer to the question is that the entropy change of the hot reservoir is 0.1053 kJ/K, and the entropy change of the cold reservoir is -0.1667 kJ/K.

We can use the following steps:

Step 1: Calculate the entropy change for the hot reservoir (ΔS_H)
ΔS_H = -Q/T_H
Since Q = 100 kJ = 100,000 J, and T_H = 950 K, the equation becomes:
ΔS_H = -100,000 J / 950 K

Step 2: Calculate the entropy change for the cold reservoir (ΔS_C)
ΔS_C = Q/T_C
With Q = 100,000 J, and T_C = 600 K, the equation becomes:
ΔS_C = 100,000 J / 600 K

Step 3: Calculate the total entropy change (ΔS_total)
ΔS_total = ΔS_H + ΔS_C

After calculating the entropy changes for both reservoirs, you will find the total entropy change of the two reservoirs.

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Answer:

Gravitational Energy

Answer:

taste buds

Explanation:

very sensitive microscopic hairs called microvilli. The tiny hairs send messages to the brain about how something tastes, so you know if it's sweet, sour, bitter, or salty

Answer:

i don't know but have a good day

The ball travelled approximately 18.7 meters.

We can use the following kinematic equation to calculate the distance the ball travelled:

v² = u² + 2as

Where

Substituting the given values, we get:

15² = 1² + 2(6)s

225 = 1 + 12s

224 = 12s

s = 224/12

s ≈ 18.7

Therefore, the ball travelled approximately 18.7 meters.

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