Answer:
169 I believe
Step-by-step explanation:
Ifsifskfskfzfkxjf
Fill in the missing number/percentage
75% is the missing percentage in x% of 1000000 = 750000.
Define percentage.A fraction of a number in hundredths, or fractions with a denominator of 100 (such as 5/100), can be expressed as a percentage, also known as a %. The Latin phrase per centum, which means "per hundred," or the French word pour cent, which has a similar meaning to the Latin word, may have been the source of the word %. A value or ratio that may be stated as a fraction of 100 is referred to as a percentage in mathematics. If we need to calculate a percentage of a number, we should divide it by its entirety and then multiply it by 100. The proportion therefore refers to a component per hundred. Percent is a unit of measurement.
Given,
Let x be the missing percentage,
x% of 1000000 = 750000
Dividing,
x% = 750000/1000000
x/100 = 0.75
Cross multiplying,
x = 75
75% is the missing percentage in x% of 1000000 = 750000.
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An educational researcher devised a wooden toy assembly project to test learning in 6-year-olds. The time in seconds to assemble the project was noted, and the toy was disassembled out of the child's sight. Then the child was given the task to repeat. The researcher would conclude that learning occurred if the mean of the second assembly times was less than the mean of the first assembly times.
Find the 99% confidence interval for the difference in means.
Child
2
3
4
Trial 1
108 140
154
115
Trial 2
99
118 154
96
5
130
108
107
102
110
0 0.7
0-07<4-4 < 23.5
0-29
O 29
find the exact value of each of the remaining trigonometric functions of 0. rationalize denominators when applicable.
sin 0 = v3/6 given that cos 0 = 0
Given that cos (0) = 0, we can use the Pythagorean identity sin^2(x) + cos^2(x) = 1 to find the value of sin (0).
sin^2(0) + cos^2(0) = 1
sin^2(0) = 1 - cos^2(0)
sin^2(0) = 1 - 0^2
sin^2(0) = 1
So, sin (0) = sqrt(sin^2(0)) = sqrt (1) = 1.
However, the given value is sin (0) = v3/6. This means that sin (0) = sqrt (3)/2, which is the value of sin (60). Therefore, the correct value of sin (0) is sqrt (3)/2, not 1.
trigonometry, the branch of mathematics deal with specific functions of angles and their application to calculations. There is total six functions of an angle commonly used in trigonometry.
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Help me pls I am stuck and this is due in 30min
Solve the given equation for x8-6/5 x = 10
8 - 6/5 x = 10
Solve for x
-6/5 x = 10 - 8
-6/5 x = 2
Water is filling a conical tank at a rate of 3 pi cubic feet per second. However, the water level is only increasing at a rate of 1/2 pi feet per second. There must be a leak in the tankout the rate water is out of the tank when the water level is 5 feet from the bottom of the tank. The tank is 10 feet in height and has a radius at the top of 2 feet.
What’s negative one and one fourths subtract one and three eights
Answer:
negative two and five eights
Step-by-step explanation:
It usually helps to break down the equation like this:
-1 - 1 = -2
1/4 = 2/8
2 - 3 = 5, therefore 2/8 - 3/8 = 5/8.
Put it all together,
-1 1/4 - 1 3/8 = -2 5/8
Denise has taken four math tests this semester and
has received grades of 89, 85, 96 and 87. What is the
minimum score that Denise needs to receive on the
next test in order to get an average math grade of at
least 90?
Answer:
93
Step-by-step explanation:
Setup an equation. Add the 5 tests together, the unknown test will be represented by x, Since there are 5 tests total, you will divide by 5. to find the average.
\(\frac{89 + 85+96+87+x}{5} = 90\)
To solve first multiply both side by 5.
\((5) \frac{89 + 85+96+87+x}{5} = 90 (5)\)
\(89 + 85+96+87+x = 450\)
Add the left side and then solve for x
\(357 + x = 450\)
Subtract 357 from both sides
357 - 357 + x = 450 - 357
x = 93
The last test has to be a score of 93 to get an average of 90.
A student was given two data sets, Set A and Set B. Which of the following
statements is true?
Set A
3
50
75
100
125
150
Set B
-1
2
3
0.60
15
75
375
O A. Set A is a linear function and the values increase at a faster rate
than Set B.
OB. Set B is an exponential function and the values increase at a faster
rate than Set A.
OC. Set A is a linear function and the values increase at the same rate
as Set B.
OD. Set B is an exponential function and the values increase at the
same rate as Set A.
Answer:
I don't know were the statement are but here are the specs of each set
Step-by-step explanation:
Set A
mean; 83.83333
median; 87.5
mode; it has no mode
range; 147
Set B
mean; 67.08571
median; 3
mode; no mode
range; 376
hope this helps sorry for late answer :)
The person at (0, 1) needs a bottled water. He moved to the right on a slope of -4. Where can you find him to give him the water he ordered?
Answer:
cjsbg sorry
Step-by-step explanation:
not haha
A friend recently planned a camping trip. He had two flashlights, one that required a single 6-V battery and another that used two size-D batteries. He had previously packed two 6-V and four size-D batteries in his camper. Suppose the probability that any particular battery works is p and that batteries work or fail independently of one another. Our friend wants to take just one flashlight. For what values of p should he take the 6-V flashlight
Answer:
The values of p = 0 < p ≤ 2/3
Step-by-step explanation:
First we write the probability of 6V flashlight working representing it as a binomial mass function of a binomial random variable
P ( 6v flashlight working ) = P ( at least one 6V battery works )
= P ( 1 6v battery work ) + P ( 2 6v battery work )
= b( 2; 2, p ) + b( 1; 2, p )
write out a formula of b( 2; 2, p ) + b( 1; 2, p )
P ( 6v flashlight working ) = p^2 + 2p( 1 - p )
Next we write the probability of D flashlight working representing it as a binomial mass function of a binomial random variable
P ( D flashlight works ) = p ( at least two D batteries works )
= b( 4; 4, p ) + b(3;4, p ) + b(2; 4, p )
write out a formula of b( 4; 4, p ) + b(3;4, p ) + b(2; 4, p )
P ( D flashlight works ) = \(P^4 + 4p^3 ( 1- p ) + 6p^2 ( 1- p)^2\)
attached below is the remaining solution
As the CAPS document outlines, the Content Specification and Content Clarification for Patterns, Functions, and Algebra shows sequenced mathematics content topics and a content area spread. In the Intermediate Phase, select one topic and report on the topic sequence and content area spread. Your report should demonstrate mathematics concepts and procedures’ hierarchical and logical progression.
Answer:
Step-by-step explanation:
In the Intermediate Phase of mathematics education, one topic that demonstrates a hierarchical and logical progression in patterns, functions, and algebra is the concept of "Linear Equations."
The topic of Linear Equations in the Intermediate Phase builds upon the foundation laid in earlier grades and serves as a stepping stone towards more advanced algebraic concepts. Here is an overview of the topic sequence and content area spread for Linear Equations:
Introduction to Variables and Expressions:
Students are introduced to the concept of variables and expressions, learning to represent unknown quantities using letters or symbols. They understand the difference between constants and variables and learn to evaluate expressions.
Solving One-Step Equations:
Students learn how to solve simple one-step equations involving addition, subtraction, multiplication, and division. They develop the skills to isolate the variable and find its value.
Solving Two-Step Equations:
Building upon the previous knowledge, students progress to solving two-step equations. They learn to perform multiple operations to isolate the variable and find its value.
Writing and Graphing Linear Equations:
Students explore the relationship between variables and learn to write linear equations in slope-intercept form (y = mx + b). They understand the meaning of slope and y-intercept and how they relate to the graph of a line.
Systems of Linear Equations:
Students are introduced to the concept of systems of linear equations, where multiple equations are solved simultaneously. They learn various methods such as substitution, elimination, and graphing to find the solution to the system.
Word Problems and Applications:
Students apply their understanding of linear equations to solve real-life word problems and situations. They learn to translate verbal descriptions into algebraic equations and solve them to find the unknown quantities.
The content area spread for Linear Equations includes concepts such as variables, expressions, equations, operations, graphing, slope, y-intercept, systems, and real-world applications. The progression from simple one-step equations to more complex systems of equations reflects a logical sequence that builds upon prior knowledge and skills.
By following this hierarchical progression, students develop a solid foundation in algebraic thinking and problem-solving skills. They learn to apply mathematical concepts and procedures in a systematic and logical manner, paving the way for further exploration of patterns, functions, and advanced algebraic topics in later phases of mathematics education.
When 893893 male workers were asked how many hours they worked in the previous week, the mean was 45.645.6 with a standard deviation of 14.614.6. Does this suggest that the population mean work week for men exceeds 4040 hours? Answer by completing parts (a) through (d).
Answer:
a) A. The relevant variable is the population mean work week (in hours) for workers aged 18-25.
b) Null hypothesis:\(\mu \leq 40\)
Alternative hypothesis:\(\mu > 40\)
c) \(t=\frac{45.6-40}{\frac{14.6}{\sqrt{893}}}=11.46\)
The p value for this case would be:
\( p_v = P(t_{110} >11.46) \approx =0\)
d) Since the p value is a very low value we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case exceeds 40 hours.
Step-by-step explanation:
Information provided
\(\bar X=45.6\) represent the sample mean
\(s=14.6\) represent the sample standard deviation
\(n=893\) sample size
\(\mu_o =40\) represent the value to verify
t would represent the statistic
\(p_v\) represent the p value
a. Identify the relevant and parameter variable. Choose the correct relevant variable below.
A. The relevant variable is the population mean work week (in hours) for workers aged 18-25.
b. State the null and alternative hypotheses. State the null hypothesis.
We want to verify if the population mean is higher than 40, the system of hypothesis would be:
Null hypothesis:\(\mu \leq 40\)
Alternative hypothesis:\(\mu > 40\)
c. Calculate the statistic
\(t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}\) (1)
Replacing the info given we got:
\(t=\frac{45.6-40}{\frac{14.6}{\sqrt{893}}}=11.46\)
The p value for this case would be:
\( p_v = P(t_{110} >11.46) \approx =0\)
d. Conclusion
Since the p value is a very low value we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case exceeds 40 hours.
Let A and B be n-by-n matrices in R^n, and let c be a real number. Which of the following statements about trace is not necessarily true? a. tr(A+B) = tr(A) + tr(B) b. tr(AB) = tr(BA) c. tr(AB) = tr(A)tr(B) d. tr(CA) = ctr(A)
Answer:
c. tr(AB) = tr(A)tr(B)
Step-by-step explanation:
The trace of a matrix is only valid for a square matrix, that is a n by n matrix. The trace of a matrix is the sum of all its diagonal elements. The following properties of trace holds for a matrix A and B with size n by n and a real number c.
i) The trace sum of two matrix is equal to the sum of their individual traces. That is:
tr(A + B) = tr(A) + tr(B)
ii) The trace of the product of a scalar and a matrix is the same as the product of the scalar and the trace of the product, that is:
tr(cA) = ctr(A)
iii) The trace of a transpose of a matrix is equal to the trace of the matrix, that is:
\(tr(A^T)=tr(A)\)
iv) The trace of a product of matrix is given as:
tr(AB) = tr(BA)
Answer:
c. tr(AB) = tr(A)tr(B)
You decide you need a new computer. The cost of the computer is $864. However, the store also offers a rent to own option which will cost $41 per week for 24 weeksHow much more will the rent to own option cost after you have made all of the payments? $
The rent option will cost 120 more dollars than the outright cost of the computer .
How to find how much more the rent to own option cost?The outright cost of the computer is $864.
The store also offers a rent to own option which will cost $41 per week for 24 weeks.
Therefore, the total cost for the rent option is as follows:
cost of the computer for rent option = 41 × 24
cost of the computer for rent option = 984 dollars
Therefore,
difference in cost = 984 - 864
difference in cost = 120 dollars
Therefore, the rent option will cost 120 more dollars than the outright cost of the computer.
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A news article estimated that only 4% of those age 65 and older who prefer to watch the news, rather than to read or listen, watch the news online. This estimate was based on a survey of a large sample of adult Americans. Consider the population consisting of all adult Americans age 65 and older who prefer to watch the news, and suppose that for this population the actual proportion who prefer to watch online is 0.04. (a) A random sample of n = 100 people will be selected from this population and p, the proportion of people who prefer to watch online, will be calculated. What are the mean and standard deviation of the sampling distribution of p? (Round your standard deviation to four decimal places.) mean 0.04 standard deviation 0.0196 (b) Is the sampling distribution of p approximately normal for random samples of size n = 100? Explain. The sampling distribution of p is approximately normal because np is less than 10. O The sampling distribution of p is approximately normal because np is at least 10. The sampling distribution of p is not approximately normal because np is less than 10. The sampling distribution of p is not approximately normal because np is at least 10. The sampling distribution of is not approximately normal because n(1-P) is less than 10. (c) Suppose that the sample size is n = 400 rather than n = 100. What are the values for the mean and standard deviation when n = 400? (Round your standard deviation to four decimal places.) mean 0.03 standard deviation 0.0085 Does the change in sample size affect the mean and standard deviation of the sampling distribution of ? If not, explain why not. (Select all that apply.) 2 When the sample size increases, the mean increases. When the sample size increases, the mean decreases. When the sample size increases, the mean stays the same. The sampling distribution is always centered at the population mean, regardless of sample size. When the sample size increases, the standard deviation increases. When the sample size increases, the standard deviation decreases When the sample size increase the standard deviation stays the same. The standard deviation of the sampling distribution is always the same as the standard deviation of the population distribution regardless of sample size. Suppose that the sample size is n = 400 rather than n = 100. What are the values for the mean and standard deviation when n = 400? (Round your standard deviation to four decimal places.) mean 0.03 standard deviation 0.0085 Does the change in sample size affect the mean and standard deviation of the sampling distribution of p? If not, explain why not. (Select all that apply.) When the sample size increases, the mean increases. When the sample size increases, the mean decreases. When the sample size increases, the mean stays the same. The sampling distribution is always centered at the population mean, regardless of sample size. When the sample size increases, the standard deviation increases. When the sample size increases, the standard deviation decreases. When the sample size increases, the standard deviation stays the same. The standard deviation of the sampling distribution is always the same as the standard deviation of the population distribution, regardless of sample size. (d) is the sampling distribution of p approximately normal for random samples of size n = 400? Explain. The sampling distribution of p is approximately normal because np and n(1 - p) are both at least 10. The sampling distribution of p is approximately normal because np and n(1 - 0) are both less than 10. The sampling distribution of p is not approximately normal because np and n(i - p) are both at least 10. • The sampling distribution of p is not approximately normal because np and n(1-P) are both less than 10. The sampling distribution of p is not approximately normal because only np is at least 10.
Answer:
(a) The mean is 0.04
The standard deviation is approximately 0.0196
(b) The sampling distribution of p is not approximately normal because n·p is less than 10
(c) Given that n = 400, we have;
i) The mean is 0.04
The standard deviation is approximately 0.0098
ii) The sampling distribution is always centered at the population mean, regardless of the sample size
iii) When the sample size increases, the standard deviation decreases
(d) The sampling distribution of p is approximately normal because n·p and n·(1 - p) are both at least 10
Step-by-step explanation:
(a) From the question, we have that the actual proportion of all adult Americans who watch online = 0.04
Given that the sample size, 'n' is 100 which is larger than 30, we can assume that the distribution of the sample mean is normal
Therefore, the mean (proportion) of the sample, P = The mean (proportion) of the population = 0.04
The mean, P = 0.04
The standard deviation, σ = √((p·(1 - p))/n)
∴ σ = √((0.04·(1 - 0.04))/100) ≈ 0.0196
(b) The sampling of p is approximately normal, given that the sample size, 'n' = 100 which is randomly selected from the population, we have;
The sampling distribution = n·p = 100 × 0.04 = 4 <10
Therefore, the sample is not approximately normal because the sampling distribution, n·p = 4 which is less than 10
c) Given that n = 400, we have;
p = 0.04 = The [population mean
The standard deviation, σ √((0.04·(1 - 0.04))/400) ≈ 0.0098
According to the central limit theorem when the sample size increases, the mean approaches the population mean, therefore, the sampling distribution is always centered at the population mean, regardless of the sample size
When the sample size increases, the standard deviation decreases
(d) Given that when the sample size, n = 400, we have;
n·p = 400 × 0.04 = 16 > 10
Similarly, we have;
n·(1 - p) = 400 × (1 - 0.04) = 384 > 10
The sample is approximately normal
Therefore, the sampling distribution of p is approximately normal because np and n(1 - p) are both at least 10
1/3 (16a-8) expandesch expression
Answer: To expand the expression 1/3(16a-8), we can distribute the 1/3 to each term inside the parentheses:
1/3(16a-8) = 1/3(16a) - 1/3(8)
Simplifying each term:
1/3(16a) = (1/3)16a = (16/3)*a
1/3(8) = (1/3)*8 = 8/3
So the fully expanded expression is:
1/3(16a-8) = (16/3)*a - 8/3
Step-by-step explanation:
the quotient of a number x and two tenths
The quotient of a number x and two tenths is 5x
What is quotient?Quotient is defined as the quantity derived from the division of two numbers.
From the information given, we are to find the the quotient of;
a number x two tenths represented as 2/ 10 = 0. 2The quotient is written thus;
= x/ 2/ 10
Take the inverse of the denominator and multiply
= x × 10/ 2
= 10x/ 2
find common divisor
= 5x
Thus, the quotient of a number x and two tenths is 5x
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i need help plz plz plz plz
9514 1404 393
Answer:
(a) 34 ft²
Step-by-step explanation:
The "top" and "back" together have a height of 2 ft + 1 1/2 ft = 3 1/2 ft. The bottom and front will have the same height, so the central vertical rectangle in the net will have a height of 2×(3 1/2 ft) = 7 ft. It is shown as having a width of 4 ft, so its area is ...
A = WH = (4 ft)(7 ft) = 28 ft²
__
The two areas labeled "left" and "right" are shown as having a height of 1 1/2 ft. Their width is the same as the width of the bottom (or top), so is 2 ft. The total area of the left and right sides is then ...
left + right = 2WH = 2(2 ft)(1 1/2 ft) = 6 ft²
That makes the area of the entire net be ...
total surface area = 28 ft² +6 ft² = 34 ft²
The surface area of the box is 34 square feet.
A whale starts at -9 m and changes 11 m
When the whale starts at -9 m and changes 11 m, the new position will be 2m.
How to illustrate the expression?It should be noted that an expression simply refers to the mathematical statements which have at least two terms which are related by an operator and contain either numbers, variables, or both. Addition, subtraction, multiplication, and division are all possible mathematical operations.
In this case, the whale starts at -9 m and changes 11 m. The new position will be:
= - 9 + 11
= 2 meters.
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Complete question
A whale starts at -9 m and changes 11 m. What is the new position?
A car is traveling at a rate of 108 kilometers per hour. What is the cars rate in meters per second? How many meters will the car travel in 20 seconds?
Answer:
\(\frac{30meters}{second}\)
600meters
Step-by-step explanation:
Use conversion factors that represent 1. You can cross cancel wods just like numbers.
\(\frac{108km}{1hour}\) · \(\frac{1hour}{60 minutes}\) · \(\frac{1minute}{60seconds}\) ·\(\frac{1000meters}{1 km}\)
\(\frac{108000meters}{3600seconds}\)
\(\frac{30meters}{second}\)
\(\frac{30meters}{second}\) ·\(\frac{20seconds}{1}\)
600 meters
Helping in the name of Jesus.
A can contains 24 fluid ounces of fruit juice. How many pints of fruit juice does the can contain? HELP ASAP FREE BRAINLEST IF ANSWER CORRECTLY.I will be ur gf for a day if u answer this correctly
Answer:1.5 pints
Step-by-step explanation: I only want Brainliest and 5 star. Thank u
A tanker truck is used to deliver gasoline to gas stations. The graph shows the amount of gasoline V in gallons contained in the truck t hours after a set of time.
What are complex numbers? What are some real life applications of complex numbers? Please submit your responses in complete sentences. Also your responses should be no more than two paragraphs.
Answer:
A Complex Number is a combination of a
Real Number and an Imaginary Number
and
Imaginary numbers, also called complex numbers, are used in real-life applications, such as electricity, as well as quadratic equations. In quadratic planes, imaginary numbers show up in equations that don’t touch the x axis. Imaginary numbers become particularly useful in advanced calculus.
Monitors manufactured by TSI Electronics have life spans that have a normal distribution with a standard deviation of 1300 hours and a mean life span of 15,000 hours. If a monitor is selected at random, find the probability that the life span of the monitor will be more than 17,340 hours.
Answer:
0.03593
Step-by-step explanation:
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score = 17,340
μ is the population mean = 15,000
σ is the population standard deviation = 1300
z score:
z = 17340 - 15000/1300
z =1.8
Probability value from Z-Table:
P(x<17340) = 0.96407
P(x >17340) = 1 - P(x<17340)
= 1 - 0.96407
= 0.03593
The probability that the life span of the monitor will be more than 17,340 hours is 0.03593
Which expression is equivalent to 2 (x -2 ) -5 (2x -3)
A: 2x - 4 - 10x - 15
B: 2x - 4 - 10x + 15
C: 2x - 2 - 10x - 3
D: 2x - 2 - 10x +15
The expression equivalent to the given expression 2(x -2)-5(2x -3) is
(2x-4-10x+15)
What is an expression?An expression in maths, a sentence with a minimum of two numbers or variables and at least one maths operation.
Given is an expression, 2(x -2)-5(2x -3)
Using distributive property,
a(b+c) = ab+bc
2(x -2)-5(2x -3) = 2x-4-10x+15
Hence, The expression equivalent to the given expression 2(x -2)-5(2x -3) is (2x-4-10x+15)
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In a big tub of jellybeans. The
probability of picking each different
colour of jellybean is shown below,
complete the table to show the
probability that the jellybean will be
purple.
9v=27 what the answer and solve
Answer:
V=3
Step-by-step explanation:
9v=27
You have to get v on its own so you have to do the inverse operation which in this case would be division, 9/9, what you do to one side you have to do to the other so 27/9
That’s would separate v from the other numbers and so V=3
9v=27
9v/9=27/9
V=3
Answer: v=3
Step-by-step explanation:
Simplifying
9v + -27 = 0
Reorder the terms:
-27 + 9v = 0
Solving
-27 + 9v = 0
Solving for variable 'v'.
Move all terms containing v to the left, all other terms to the right.
Add '27' to each side of the equation.
-27 + 27 + 9v = 0 + 27
Combine like terms: -27 + 27 = 0
0 + 9v = 0 + 27
9v = 0 + 27
Combine like terms: 0 + 27 = 27
9v = 27
Divide each side by '9'.
v = 3
Simplifying
v = 3
HELP ME ASAP! Will give BRAINLIEST! Please read the question THEN answer correctly! No guessing.
Answer:
D. Vertx: (3,-16); Intercepts: x = -1, 7
Step-by-step explanation:
I graphed the equation on the graph below.
Math 1- Simplify 25/100 completely. What is the answer?
Answer:
1/4
Step-by-step explanation:
Divide 25 and 100 by 25. You get 1/4.
Answer:
1/4
Step-by-step explanation:
Convert this fraction.
25/100 is 1/4 reduced to the lowest extent.
1/4 is your answer, hope this helps!