Repeating an entire experiment more than once is

Replication

Trial

Research

Experiment

2.56 moles of HCl are required to react with 0.64 moles of KMnO4.

The balanced chemical equation is given as;2KMnO4 + 8HCl → 3Cl2 + 2MnO2 + 4H2O + 2KCl.This equation is balanced in such a way that 2 moles of KMnO4 reacts with 8 moles of HCl to produce 3 moles of Cl2, 2 moles of MnO2, 4 moles of H2O and 2 moles of KCl.We are given the number of moles of KMnO4 as 0.64 moles.Now, we can use stoichiometry to find the number of moles of HCl required to react with 0.64 moles of KMnO4.The balanced chemical equation shows that 8 moles of HCl reacts with 2 moles of KMnO4.

So, one mole of KMnO4 would react with 8/2 = 4 moles of HCl.Now, the number of moles of HCl required to react with 0.64 moles of KMnO4 would be;Moles of HCl = Moles of KMnO4 x (Moles of HCl / Moles of KMnO4) Moles of HCl = 0.64 x 4 = 2.56 moles of HCl.

for such more questions on moles

https://brainly.com/question/15356425

#SPJ8

Answer:

Iron (Fe)

Explanation:

# of protons is the atomic number of the element

the element with the atomic number 26 is Iron

with 26 electrons this means it is Iron with no charge

with 30 neutrons this means the atomic weight will be

26 (protons) + 30 (neutrons) = 56

the real atomic weight of iron listed on the periodic table is 55.845, this rounded up is 56.

Answer:

Thomson's results showed that atoms contain smaller particles, so Dalton's theory had to be modified. Rutherford's results showed that most of an atom is empty space and that the mass is concentrated in the center of the atom.

Explanation:

( like and follow if it helps >W< )

The reaction between zinc and iodine is a single replacement or redox reaction. The Correct answer is option: d.

In this reaction, zinc (Zn) reacts with iodine (I2) to produce zinc iodide (ZnI2), and the oxidation state of zinc changes from 0 to +2, while the oxidation state of iodine changes from 0 to -1. A single replacement reaction is a type of redox reaction in which an element replaces another element in a compound. In this case, zinc replaces the iodine in the zinc iodide compound. The other reaction types listed, such as synthesis, acid-base, double displacement, combustion, precipitation, and halogen replacement reactions, do not accurately describe the reaction between zinc and iodine. Correct option is : d .

To know more about single replacement, here

brainly.com/question/392491

#SPJ4

Answer:

Explanation:I hope it help:)

Instead of being utilized horizontally, the Liebig condenser is frequently tilted because this promotes greater cooling and circulation of the cooling fluid.

A popular condenser used in chemistry to cool and condense heated vapor or gas into liquid form is the Liebig condenser.

It is constructed with an inner tube that allows hot vapor or gas to pass through and an outer jacket that allows cooling fluid, such water, to flow through in order to condense the vapor or gas.

Slanted condensers allow cooling liquid to pass through the outer jacket more freely, improving heat transfer and increasing cooling effectiveness.

Therefore, it provides for better cooling and circulation of the cooling fluid, the Liebig condenser is often utilized in a tilted position as opposed to a horizontal one.

Learn more about condenser, here:

https://brainly.com/question/5793750

#SPJ2

Answer:

no.

Explanation:

Answer:

Sb

Explanation:

Sb (antimony) is an metalloid

Answer:

creo q es electrico

Explanation:

Treating an amide with excess LiAlH4, followed by water, will produce an amine.

Let's understand this in detail:

1. LiAlH4 is a reducing agent used in organic chemistry. It reduces functional groups like carboxylic acids, esters, and ketones to their respective alcohols.

2. Amides are molecules that include nitrogen and are derived from carboxylic acids. When carboxylic acids react with ammonia, the amide's nitrogen-containing functional group (-CONH2) is formed. It is one of the most common functional groups in organic chemistry. It includes a carbonyl group with an amine or ammonia. They can be synthesized from the reaction of carboxylic acids with ammonia or amines.

3. The reduction of amides to amines is also possible with LiAlH4, but the reduction is usually carried out in two steps. Firstly, the amide is converted to an intermediate carbamate with LiAlH(O-t-Bu)3; then, it is further reduced to the amine with excess LiAlH4. This procedure has been developed for the selective reduction of secondary amides to their respective amines.

LiAlH4 is used to reduce the carbonyl group of an amide to an amine. This reaction requires a two-step process. In the first step, the carbonyl group is reduced to an intermediate carbamate, which can then be converted to an amine in the second step by reacting it with excess LiAlH4. After reduction, the amide is transformed into an amine.

#SPJ11

Learn more about reducing agents: Identify the reducing agent https://brainly.com/question/19033088

BaSO₄ is safe to ingest because of its low solubility in water and limited release of Ba²⁺ ions. The sparing solubility of BaSO₄ ensures that only a minimal amount of Ba²⁺ ions are present, reducing the risk of toxicity. This property makes BaSO₄ an effective and safe contrast agent for obtaining X-ray images of the gastrointestinal tract.

BaSO₄ (barium sulfate) is safe to ingest because it has very low solubility in water, meaning it does not readily dissolve into Ba²⁺ ions in the gastrointestinal tract. This property is crucial for its use in medicine to obtain X-ray images of the gastrointestinal tract.

When BaSO₄ is ingested, it remains mostly undissolved as a solid in the gastrointestinal tract. Only a small fraction of BaSO₄ will dissolve, leading to the release of a negligible amount of Ba²⁺ ions into the surrounding solution. The concentration of Ba²⁺ ions in the gastrointestinal tract remains extremely low due to the limited solubility of BaSO₄.

The toxicity of barium arises primarily from the presence of Ba²⁺ ions in the body, which can interfere with various physiological processes. However, since BaSO₄ does not readily dissociate into Ba²⁺ ions, the amount of toxic Ba²⁺ ions released into the body from ingested BaSO₄ is extremely minimal. As a result, the risk of toxicity or harm from ingesting BaSO₄ is negligible.

The principle that governs the limited solubility of BaSO₄ is the common ion effect. The common ion effect states that the solubility of a sparingly soluble salt is decreased in the presence of a common ion, which in this case is the Ba²⁺ ion. When BaSO₄ is ingested, the presence of Ba²⁺ ions already in the body (such as from dissolved barium salts) further decreases the solubility of BaSO₄, making it even less likely to dissolve and release toxic Ba²⁺ ions.

To learn more about gastrointestinal tract refer here:

https://brainly.com/question/1593655#

#SPJ11

The electronic configuration in order of increasing orbital energy as  

The Br , bromine  : [Ar] 3d¹⁰ 4s² 4p⁵

The I, iodine  : [Kr] 4d¹⁰ 5s² 5p⁵

The  electronic configuration is given as :

a) Bromine , denoted as Br atomic number is 35.

electronic configuration  :  [A r] 3d¹⁰ 4s² 4p⁵

b) The I, iodine atomic number is 53.

electronic configuration : [Kr] 4d¹⁰ 5s² 5p⁵

Thus, The electronic configuration are : Br , bromine with atomic number with  35 : [Ar] 3d¹⁰ 4s² 4p⁵ I, iodine with atomic number is 53 : [Kr] 4d¹⁰ 5s² 5p⁵

To learn more about electronic configuration here

https://brainly.com/question/13497372

#SPJ4

Answer: The value of acid ionization constant \(K_a\) for acetic acid is \(1.87\times 10^{-5}\)

Explanation:

\(CH_3COOH\rightarrow H^+CH_3COO^-\)

 cM              0             0

\(c-c\alpha\)        \(c\alpha\)          \(c\alpha\)  

So dissociation constant will be:

\(K_a=\frac{(c\alpha)^{2}}{c-c\alpha}\)

Give c= 0.85 M and \(pH\) = 2.4

\(pH=-log[H^+]\)

\([H^=}=c\times \alpha=10^{-2.4}=3.98\times 10^{-3}\)

\(K_a=?\)

Putting in the values we get:

\(K_a=\frac{(3.98\times 10^{-3})^2}{(0.85-3.98\times 10^{-3})}=1.87\times 10^{-5}\)

Thus the value of acid ionization constant \(K_a\) for acetic acid is \(1.87\times 10^{-5}\)

Answer:

The cell membrane is, The thin membrane that forms the outer surface of the protoplasm of a cell

Answer:

The volume of stock solution needed to make the solution is 1875 ml

Explanation:

The parameters given are;

The volume of 75 M solution of H₂SO₄ = 400 ml

The concentration of stock solution = 16.0 M

Number moles per liter of stock solution = 16 moles

Number of moles in required 400 ml solution = 0.4×75 = 30 M

Volume of stock solution that contains 30 M = 30/16×1 = 1.875 l

The volume of stock solution that is required = 1875 ml

Answer:

ITS FALSE electricity doesn't travel through wood same with cement!

Answer:

sugar i believe

Explanation:

Answer:

Metamorphic rocks can also be formed in ocean floors.

Explanation:

The ocean floor is made up predominantly of basalts and are derived by the cooling an solidification of magma in this environment.

Answer: a is incorct

Explanation:

Total pressure = 4.9 atm

Partial pressure of neon =  3.4 atm

Partial pressure of oxygen = 1.5 atm

We know that the partial pressure could be obtained as the product of the mole fraction and the total pressure thus we have to obtain the total pressure by the use of the partial pressures.

For the number of moles of helium;

P = 101.3 kPa or 0.99 atm

T =  25ºC or 298 K

V =  27 L

n = PV/RT = 0.99 atm * 27 L/0.082 *  298 K = 26.73/24.44 = 1.1 moles

Number of moles of oxygen

P = 101.3 kPa or 0.99 atm

T =  25ºC or 298 K

V =  12 L

n = PV/RT = 0.99 atm * 12 L/0.082 *  298 K =11.88 /24.44 = 0.5 moles

Total number of moles = 1.1 moles + 0.5 moles = 1.6 moles

Total pressure is obtained from;

nRT/V

= 1.6 moles * 0.082 * 298/8

= 4.9 atm

Partial pressure of neon = 1.1 moles/1.6 moles * 4.9 atm = 3.4 atm

Partial pressure of oxygen = 0.5 moles/1.6 moles * 4.9 atm = 1.5 atm

Learn more about partial pressure:https://brainly.com/question/13199169

#SPJ1

The substrates that will react are CH₃CH₂CH₂Br and CH₃CH₂CH₂CH₂Br  and (CH₃)₃CNH₂ and CH₃CH₂OH will not react with naome in an sn2 reaction to form an appreciable amount of product.

Based on the Sn2 reaction mechanism, substrates with good leaving groups and low steric hindrance are more likely to react with nucleophiles like NaOMe.

Therefore, the substrates CH₃CH₂Br, (CH₃)₂CHBr, CH₃CH₂I, and (CH₃)₃CBr are expected to react with NaOMe to form appreciable amounts of product. On the other hand, substrates with poor leaving groups or high steric hindrance are less likely to undergo Sn2 reactions.

Therefore, the substrates (CH₃)₃CNH₂ and CH₃CH₂OH are not expected to react with NaOMe to form appreciable amounts of product. Finally, CH₃CH₂CH₂Br and CH₃CH₂CH₂CH₂Br may react with NaOMe, but to a lesser extent due to their higher steric hindrance.

To know more about the Sn2 reaction mechanism refer here :

https://brainly.com/question/31472916#

#SPJ11

Complete question :

Determine which of the substrates will and will not react with NaOMe in an Sy2 reaction to form an appreciable amount of product. Substrate will react Substrate will NOT react Answer Bank CH,CH.CH,BE (CH),CBE (CH), CHRE CH, CH,CH,NH, (CH),CCH,BE CH,CH.CH, OH

Percent composition indicates the relative amounts of each element in a compound. For each element, the mass percent formula is: % mass = (mass of element in 1 mole of the compound) / (molar mass of the compound) x 100% or. mass percent = (mass of solute / mass of solution) x 100%.

The formulas for the of the t-statistic and f-ratio concern and involve group of standard deviation.

It is frequently noted that the t-statistic and the F-statistic may be calculated from the same data when ANOVA is applied to only two groups, and that the two statistics can therefore be connected using the straightforward formula t2 = F.

The fact that these tests use the F-values to test the hypotheses is the basis for the term "F-test." The ratio of two variances is known as an F-statistic, and it bears Sir Ronald Fisher's name. Variances quantify how evenly distributed the data points are around the mean. When the individual data points tend to deviate further from the mean, there are more variances.

Learn more about group of standard deviation here-

https://brainly.com/question/28098834

#SPJ4

Answer:

9.2% is the answer

Explanation:

In this question asking for the percent error of the students calculated density. The formula that will be given;

density = 9.78g/cm^3

d = 9.78g/cm^3

accepted is on the RT table S = 8.96g/cm^3

%error = (measured - accepted)/accepted * 100%

%error = (9.78 - 8.96/8.96) * 100%

%error = 9.15% or approximately 9.2%

Robinson annulation

To determine the starting materials that could produce the following product from a Robinson annulation procedure with a CO2Et group, follow these steps:

1. Identify the product: The product contains a CO2Et group, which is an ester (CO2R) with an ethyl group (Et) attached.

2. Analyze the Robinson annulation: Robinson annulation is a reaction that combines a ketone and an α,β-unsaturated carbonyl compound (typically an enone) to form a cyclohexenone ring.

3. Determine the starting materials: Based on the product, we need a ketone and an enone as our starting materials. The ketone should have an ethyl ester (CO2Et) attached to the carbonyl carbon.

So, the starting materials for the Robinson annulation procedure that would produce a product with a CO2Et group are:
- A ketone with an ethyl ester (CO2Et) attached to the carbonyl carbon.
- An α,β-unsaturated carbonyl compound (enone).

Please note that without the specific structure of the product, it is not possible to provide the exact structures of the starting materials.

Learn more about the Robinson annulation :

https://brainly.com/question/28564494

#SPJ11

Answer:

The solvent is deionised water

The solute is AgNO3

The solution is [Ag(aq) + NO3(aq)-]

Explanation:

Answer:

2.9 * 10^23 atoms Au

Explanation:

(95 g Au) * (1 mol Au/196.96657) * (6.02 * 10^23 atoms Au / 1 Mol Au)

2.9 * 10^23 atoms Au

Answer:

The products will have one S and four O atoms.

Answer:

Cell division is central to organism growth, reproduction and tissue repair.

Explanation:

Hope this helps!

Answer:

multiply, survive grow

Under the assumption that there is no degradation in solution, a weak acid or weak base could be used to create a buffer solution. As a buffer solution, it preserves a certain reaction's or process's stable (rm pH) range.

When a little bit of acid or base is added to the buffer solution, it can neutralize the solution. A buffer solution should satisfy these two requirements: Strong base or weak acid - A weak base or acid should be the main ingredients in a buffer.

A weak acid and its conjugate base, or vice versa, are combined to form an aqueous solution known as a buffer solution (more specifically, pH buffer or hydrogen ion buffer). A little bit of a weak acid or base applied to it barely affects its pH.

Learn more about  buffer solution here

https://brainly.com/question/24262133

#SPJ4

Answer:

1. Potential

2. The relative potential energy of the reaction is positive.

3. the kinetic energy of the reactant molecules

4. catalyst

5. covalent

Explanation:

For everyone

Heat is added to a chemical system then Potential, The relative potential energy of the reaction is positive and the kinetic energy of the reactant molecules.

The exquisite intricacy and complexity of the biochemical machinery in cells give away the fact that they are the end result of a protracted evolutionary process.

The creation of membranes or the accumulation of information/catalytic machinery are two examples of distinct, well-defined challenges that have long been the focus of research on the origin of life.

This method is gradually being supplanted by a more "systemic" method that prioritizes complicated chemical system processes above particular separate functional apparatuses.

Therefore, Heat is added to a chemical system then Potential, The relative potential energy of the reaction is positive and the kinetic energy of the reactant molecules.

To learn more about chemical system, refer to the link:

https://brainly.com/question/28294176

#SPJ2