WOULD A KIND SOUL PLEASE PLEASE PLEASE HELP ME OUT???????!!!!!!!!!!! NO links as answers

Which of the following statements must be true about parallelogram ABCD? Question 10 options: A) ∠A+∠D = 180° B) || C) ≅ D) ∠B ≅ ∠C

The steps to calculate the fraction of a whole number are:

1) Write the fraction as a decimal

2) Multiply the decimal by the whole number

3) Interpret the result

To calculate a fraction of a whole number, you need to follow these steps:

Write the fraction as a decimal: If the fraction is not already in decimal form, you will need to convert it. To do this, divide the numerator (the top number) by the denominator (the bottom number).

Multiply the decimal by the whole number: Once you have the fraction in decimal form, you can multiply it by the whole number you want to find a fraction of.

Interpret the result: The result of the calculation is the fraction of the whole number you were trying to find.

Therefore, these are the steps to calculate a fraction of a whole number

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The first derivatives for the given functions are:

For \(y = 3x^2 + 5x + 10,\) the first derivative is dy/dx = 6x + 5.

For  \(y = 100200x + 7x,\) the first derivative is dy/dx = 100207.

For \(y = ln(9x^4),\) the first derivative is dy/dx = 4/x.

To find the first derivative for each of the given functions, we'll use the power rule, constant rule, and chain rule as needed.

For the function\(y = 3x^2 + 5x + 10:\)

Taking the derivative term by term:

\(d/dx (3x^2) = 6x\)

d/dx (5x) = 5

d/dx (10) = 0

Therefore, the first derivative is:

dy/dx = 6x + 5

For the function y = 100200x + 7x:

Taking the derivative term by term:

d/dx (100200x) = 100200

d/dx (7x) = 7

Therefore, the first derivative is:

dy/dx = 100200 + 7 = 100207

For the function \(y = ln(9x^4):\)

Using the chain rule, the derivative of ln(u) is du/dx divided by u:

dy/dx = (1/u) \(\times\) du/dx

Let's differentiate the function using the chain rule:

\(u = 9x^4\)

\(du/dx = d/dx (9x^4) = 36x^3\)

Now, substitute the values back into the derivative formula:

\(dy/dx = (1/u) \times du/dx = (1/(9x^4)) \times (36x^3) = 36x^3 / (9x^4) = 4/x\)

Therefore, the first derivative is:

dy/dx = 4/x

To summarize:

For \(y = 3x^2 + 5x + 10,\) the first derivative is dy/dx = 6x + 5.

For y = 100200x + 7x, the first derivative is dy/dx = 100207.

For\(y = ln(9x^4),\) the first derivative is dy/dx = 4/x.

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I earn $12 in interest after 12 years while my friend earns the same amount in 4 years.

Simple interest is an interest charge that borrowers pay lenders for a loan. It is calculated using the principal only and does not include compounding interest. Simple interest relates not just to certain loans. It's also the type of interest that banks pay customers on their savings accounts.

Given here: My principal = $50 and friend's =$50 also friend's account earns 6% annual interest rate

As per question we get

let the time taken to earn $12 interest rate be t then

12=50×2×t /100

t=12 years

while for my friend

12=50×6×t /100

3t=12

t=4 years

Hence, I earn $12 in interest after 12 years while my friend earns the same amount in 4 years.

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Answer:

look at the picture i have sent

The range of the data set is 16 inches.

The range of a data set represents the difference between the highest and lowest values in the set. In this case, the data set consists of the following heights (in inches):

59, 62, 62, 62, 64, 66, 67, 67, 67, 71, 72, 75

To find the range, we need to determine the minimum and maximum values in the set. By sorting the data set in ascending order, we can identify the minimum and maximum values more easily:

59, 62, 62, 62, 64, 66, 67, 67, 67, 71, 72, 75

The smallest value in the set is 59, which is the minimum value, and the largest value is 75, which is the maximum value.

To calculate the range, we subtract the minimum value from the maximum value:

Range = Maximum value - Minimum value

Range = 75 - 59

Range = 16 inches

Therefore, the range of the given data set is 16 inches. This means that the difference between the tallest and shortest student in the class is 16 inches.

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Answer:

t=1

Step-by-step explanation:

2t+t−3=0

2t+t+−3=0

(2t+t)+(−3)=0(Combine Like Terms)

3t+−3=0

3t−3=0

Step 2: Add 3 to both sides.

3t−3+3=0+3

3t=3

Step 3: Divide both sides by 3.

3t

3

=

3

3

t=1

Answer:

Step-by-step explanation:

F(x)=0

Answer: C

It is right lol

Answer:

the answer is 7,184.47

Step-by-step explanation:

Answer:

Given - A triangle

- Sides are 5cm 8cm and X cm

To find - Measure of X cm

Solution -

This is a right angled triangle

Using Pythagoras theorem , which is Sum of square of altitude and base is equal to hypotenuse

(5)² + (X )² = (8)²

25+ X^2 = 64

X^2 = 64 - 25

X^2 = 39

X= root 39

Answer:

6400

Step-by-step explanation:

We have 1 + 3 + 5 + ... + 155 + 157 + 159.

We can use Gauss's strategy.

Since we are adding 80 numbers, there are 40 pairs. Each pair adds up to 1 + 159 = 160. (Notice that 3 + 157, 5 + 155 = 160)

Thus, because there are 40 pairs and each pair adds up to 160, we have 160 * 40 = 6400.

I hope this helps!

The area of the region cut from the first quadrant by the cardioid is 3π/8 +1

A cardioid is a two-dimensional plane figure that has a heart-shaped curve. The equation of cardioid is r = a(1 ± sinθ) .

The area of the polar function can be calculated if the boundary condition that form the reason is given or can be found from the given information now we use the formula using the polar formula of the area as:

\(A = \int\limits^b_a {\frac{r^{2}}{2}} d\theta\)

The Area of the region cut from the first quadrant by cardioid,

\(A = \int\limits^\frac{\pi}{2}_0 {\frac{r^{2}}{2}} d\theta\)

Substituting r = 1 + sin ∅

\(A = \int\limits^\frac{\pi}{2}_0 {\frac{(1+ sin\theta)^{2}}{2}} d\theta\)

Opening square ,

\(A = \frac{1}{2}\int\limits^\frac{\pi}{2}_0 {1 +2sin\theta + sin^{2}\theta d\theta\)

=> \(A = [ \frac{1}{2} (\theta - 2cos\theta + \frac{1}{2} (\theta - \frac{1}{2}sin2\theta))]^\frac{1}{2}_{0}\)

=> 3π / 8 - (-1)

=> 3π/8 +1

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Answer:

48 and 32

Step-by-step explanation:

both numbers get rounded by 8 going up and down rounding it to 40

Answer:

what you need help on

Step-by-step explanation:

what problem you struggling on the most I tried to help you

The intercepts are the points where the graph crosses the x or y-axis

The functions are given as:

\(f(x) = x^2\)

\(g(x) = x^2 - 3\)

Function f(x)

\(f(x) = x^2\)

The x-intercept is calculated as follows:

Set f(x) to 0

\(x^2 = 0\)

Solve for x

\(x = 0\)

The y-intercept is calculated as follows:

Set x to 0

\(f(0) = 0^2\)

\(f(0) = 0\)

Hence, the intercepts are 0

Function g(x)

\(g(x) = x^2 - 3\)

The x-intercept is calculated as follows:

Set g(x) to 0

\(x^2 - 3 = 0\)

Solve for x

\(x^2 = 3\)

\(x = \±\sqrt 3\)

The y-intercept is calculated as follows:

Set x to 0

\(g(x) = x^2 - 3\)

\(g(0) = 0^2 - 3\)

\(g(0) = - 3\)

The x-intercepts are \(\±\sqrt 3\), while the y-intercept is -3

By comparing the intercepts of f(x) and g(x),

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Answer:

the

Step-by-step explanation:

the comen factor are 10-15+20-30

and Factor the entire expression completely.

are n and 2

Answer:

let x = total cost

x = 5(18.5 + 3.25)

x = 5(21.75)

x = $108.75

108.75 = 5(18.5) + 5(3.25)

108.75 = 92.5 + 16.25

108.75 = 108.75

Therefore, the total cost will be $108.75.

Step-by-step explanation:

The one-time administration fee is (d) $60

From the question, we have the following parameters that can be used in our computation:

12 months costs $660.

15 months costs $810.

This means that

(x, y) = (12, 660) and (15, 810)

For the one-time administration fee, we have

(x, y) = (0, y)

So, we calculate the slope using

slope = (y₂ - y₁)/(x₂ - x₁)

So, we have

(y - 660)/(0 - 12) = (810 - 660)/(15 - 12)

This gives

(660 - y)/12 = 50

So, we have

660 - y=600

This gives

y = 60

Hence, the administration fee is $60

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Answer:

f=1 1/4

Step-by-step explanation:

Answer:

f(5) = 4

Step-by-step explanation:

Given f(x) = 4

Irrespective of the value of x , f(x) = 4 , then

f(5) = 4

The optimal pair for the problem min 2tx(t)-3t³u(t)dt is u*(t) = -t³/b³, x*(t) = -t⁴/b³.

To find the optimal pair for the problem min 2tx(t)-3t³u(t)dt, we need to use the calculus of variations.

We start by considering the functional \(J(u) = \int_{a}^{b} (2tx(t)-3t^3u(t))dt\), where u is the control function that we want to optimize.

We can find the optimal pair (x*, u*) by solving the Euler-Lagrange equation:
d/dt (∂L/∂u') - ∂L/∂u = 0,
where L(t, x(t), u(t), u'(t)) = 2tx(t)-3t³u(t) and u' = du/dt.

After some calculations, we obtain:
-3t² = u''/u',

which is a separable first-order differential equation that we can solve using integration.

We get:
u(t) = c1*t³ + c2,

where c1 and c2 are constants of integration that we can determine using the boundary conditions.

Since we want to minimize J(u), we need to choose the constants that minimize J(u). Using the boundary condition u(a) = u(b) = 0, we get:
c1 = -c2/b³, c2 = 0,

so that:
u(t) = -t³/b³.

Finally, we can compute the corresponding optimal x* using the formula:
\(x^*(t) = \int_{a}^{t} (\partial L/ \partial u)du + K\),
where K is a constant of integration that we can determine using the boundary condition x(a) = x(b) = 0.

We obtain:
x*(t) = -t⁴/b³.

Therefore, the optimal pair is given by:
u*(t) = -t³/b³, x*(t) = -t⁴/b³.

Note that we also need to check that this is indeed a minimum by verifying that the second variation of J(u) is positive.

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The time between buses is 10 minutes and the bus waits at the station for 3 minutes, so the time between the departure of one bus and the departure of the next bus is 10 + 3 = 13 minutes.

Since you arrive at a random time, the time you have to wait for the next bus can be any number from 0 to 13 minutes, with each value between 0 and 13 being equally likely.

The probability that you will have to wait more than 6 minutes to board a bus is the probability that you arrive at the station between 0 and 7 minutes after a bus has left.

This is because if you arrive at the station more than 7 minutes after a bus has left, you will have to wait less than 6 minutes for the next bus to arrival time.

The probability that you arrive at the station between 0 and 7 minutes after a bus has left is 7/13, or approximately 0.538.

Therefore, the probability that you will have to wait more than 6 minutes to board a bus is approximately 0.462 (1 - 0.538).

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The value x-coordinates which is required is found out to be as Q = -19.41 and +19.41.

The given values are,

radius , r = 35 feet

speed of ball = 11 ft./sec

location of the cup =  (0, 0)

starting location the ball = (-40. -50)

In order to find the possible x-coordinates of Q,

The coordinates of the rightmost edge of the golf course = (35, 0)

slope = m = ( y2 - y1)/ ( x2 - x1)

now , the equation for a circle is known as , (x - h)² + (y - k)² = r²

and the center of the course is given as ,  (h, k) = (0, 0)

Therefore the equation becomes (x - 0)² + (y - 0)² = x² + y² = 35²

equation of tangent , y = -3x/2

putting this value in the tangent = x² + ( -3x/2 )²  = 35²

13x² /4 = 35²

x = √ ( 35²  x 4 )/ 4 = 35²

x = 70/13√ 13 = 19.41

Therefore, the  coordinates of Q are found out to be as  -19.41 and +19.41

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Answer:

4c + 3f + 2s + 20

Step-by-step explanation:

\(c + f + 2f + 3c + s + s + 20\)

\(4c + 3f + 2s + 20\)

A slope of b = 0.007 indicates a weak positive relationship between the two variables, where a small increase in the independent variable corresponds to a small increase in the dependent variable.

The slope of a linear relationship represents the rate of change between two variables. In this case, a slope of b = 0.007 suggests a weak positive relationship between the variables. The positive sign indicates that as the independent variable increases, the dependent variable also tends to increase. However, the small value of 0.007 indicates that the increase in the dependent variable is relatively small for each unit increase in the independent variable.

To illustrate, let's consider an example where the independent variable represents time and the dependent variable represents the number of customers in a store. With a slope of 0.007, it means that for every unit increase in time (e.g., one hour), we can expect a small increase of 0.007 customers on average. This indicates a weak positive relationship, as the increase in customers is relatively modest for each unit increase in time.

In summary, a slope of b = 0.007 indicates a weak positive relationship between the two variables, where a small increase in the independent variable corresponds to a small increase in the dependent variable.

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Answer:

He was traveling for 8 hours

Step-by-step explanation:

If 2 hours he traveled with 4 miles in each hour, then there must be 8 miles in total. 18 miles left to go. Since he was traveling 3 miles per hour, there must be 6 hours. 2+6=8

Step-by-step explanation:

the difference of eleven and four times five

The net profit margin for this shirt is 55%.

What is net profit?

Net profit is the amount of money your business earns after deducting all operating, interest and tax expenses over a period of time. To arrive at this value, you need to know the company's gross profit. If the value of net profit is negative, it is called net loss.

Net profit is another important parameter that determines the financial health of your business. It shows whether the company can earn more than it spends. Net profit helps you decide when and how to expand your business and when to cut costs.

It is important for a business owner to know the difference between profit and profitability. Profit is an absolute number equal to revenues minus expenses. Profitability, on the other hand, is a relative number (percentage) that equals the ratio of profit to revenue.

Profitability is a measure of efficiency and is useful in determining the success or failure of a business.

Given,

Revenue = $12

Cost of goods sold = $3

Operating expenses = 20% of revenue = 20/100 x $12 = $2.4

We know,

Net Profit = Revenue - Cost of goods sold - Operating expenses

\(Net \: Profit = 12 - 3 - 2.4\)

Hence, Net Profit = $6.6

Again,

Net Profit Margin = (Net Profit / Revenue) x 100%

Net Profit Margin \(= ( \frac{6.6}{ 12}) \times 100\%\)

SO, Net Profit Margin = 55%

Therefore, the net profit margin for this shirt is 55%.

So, it is clear that choice A is correct.

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The values of the dummy variable X2 used to indicate the two levels of the qualitative variable are:
Level 1: X2 = 0
Level 2: X2 = 1

To indicate the two levels of the categorical independent variable, let's assign the dummy variable X2 with values of 0 and 1.

Level 1: For level 1 of the categorical variable, we assign X2 = 0.
Level 2: For level 2 of the categorical variable, we assign X2 = 1.

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Answer:

I think the first one.

Step-by-step explanation:

Sorry if I am wrong.