Answer:
The molecules in the liquid are moving past one another. The hydrogen end of one water molecule is attracted to the oxygen end of another but only for a short time because they are moving. The molecules in ice are further apart than in liquid water. The molecules in ice are in fixed positions but still vibrate.
Explanation:
express 0.0005L as an integer
Answer:
I had this question on a test a long time ago and i believe it is
16- or 32-
Explanation:
Which ONE of the following has the most mass (assume they are all of the same volume)?
A block of styrofoam.
b. A block of copper.
c. A box of feathers.
d. An empty cardboard box.
Answer:
the answer is b
Explanation:
Convert 100.6 Kelvin to degrees C.
°C = K - 273
[?] °C
Answer:
-172.6 °C
Explanation:
You want to know the Celsius equivalent of the temperature 100.6 K.
ConversionThe relation is ...
C = K - 273.15
C = 100.6 -273.15 = -172.55
The temperature is -172.55 °C, about -172.6 °C.
__
Additional comment
We have rounded to tenths, because that is precision of the temperature given. If you use 273 as the conversion constant, you will get -172.4.
2.50 g of As2O3 are titrated with 38.5 mL of KMnO4 to reach the end point.
5As2O3(s)+4MnO−4(aq)+9H2O(l)+12H+(aq)⟶10H3AsO4(aq)+4Mn2+(aq)
Calculate the concentration of the KMnO4 solution.
50 g of As\(_2\)O\(_3\) are titrated with 38.5 mL of KMnO\(_4\) to reach the end point. 0.26M is the concentration of the KMnO\(_4\) solution.
Concentration in chemistry refers to the quantity of a material in a certain area. The ratio of the solute within a solution to the solvent or whole solution is another way to define concentration. In order to express concentration, mass in unit volume is typically used.
The solute concentration can, however, alternatively be stated in moles or volumetric units. Concentration may be expressed as per unit mass rather than volume.
5As\(_2\)O\(_3\)(s)+4MnO\(_4\)⁻(aq)+9H\(_2\)O(l)+12H⁺(aq)⟶10H\(_3\)AsO\(_4\)(aq)+4Mn\(_2\)⁺(aq)
the stoichiometry ratio between As\(_2\)O\(_3\) and MnO\(_4\)⁻ is 5:4
0.0126 moles of As\(_2\)O\(_3\) will react with 4/5×0.0126 moles = 0.01008moles
0.01008moles of MnO\(_4\)⁻ is present in 38mL
concentration of KMnO\(_4\)= moles×volume
= 0.010/38×1000
=0.26M
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According to the kinetic-molecular theory, what happens to a liquid when it is transferred from one container to another?
1. The volume and the shape stay the same.
2. The volume increases to fill the new container, but the shape stays the same.
3. The volume stays the same, but the shape changes to fit the new container.
4. The volume and the shape change to fill the new container.
According to the kinetic-molecular theory, if a liquid is transferred from one container to another, the volume stays the same, but the shape changes to fit the new container.
What is the kinetic-molecular theory?The kinetic theory of gases is a simple, historically significant classical model of the thermodynamic behavior of gases, with which many principal concepts of thermodynamics were established.
The kinetic-molecular theory is based on some assumptions which includes:
Gases are composed of a large number of particles that behave like hard, spherical objects in a state of constant, random motion.These particles move in a straight line until they collide with another particle or the walls of the container.These particles are much smaller than the distance between particles. Most of the volume of a gas is therefore empty space.Learn mote about the kinetic-molecular theory at: https://brainly.com/question/134712
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How many grams of NaCl
You would recover 36.525g of NaCl after evaporating all of the water.
How to find the how many grams of NaCl that would be recover when all water is evaporated off of this solution?To find the grams of NaCl that would be recovered after evaporating all the water, we can use the following formula:
mass = moles * molar mass
Where:
Moles = Molarity * Volume
Molarity = 0.250 M
Volume = 2500.0 mL = 2.5 L
Molar mass of NaCl = 58.44 g/mol
mass = 0.250 M * 2.5 L * 58.44 g/mol
mass = 36.525 g
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what is the energy of a photon that emits a light frequency of 6.42X10(14)HZ? got it... 4.25 X10 (-19)J
Among electromagnetic waves, UV rays are most dangerous because exposure to these radiation cause serious problems in living organism. Therefore, 4.28×10⁻¹⁹J is the energy of a photon that emits a light frequency of 6.67×10⁻³⁴ Hz.
What is electromagnetic wave?Electromagnetic wave is a wave which contain two component one is electric component and other is magnetic component. The electric and magnetic component are perpendicular to each other. There are so many wave that comes under electromagnetic wave like infrared wave , radio wave.
There is a relation between energy of wave. frequency of wave, and wavelength of wave
Mathematically,
E=h×ν
where,
E = energy of electromagnetic wave =?
h is planks constant having value 6.67×10⁻³⁴js
ν= frequency of photon=6.42X10¹⁴ Hz
Substituting all the given values in the above equation, we get
E= 6.67×10⁻³⁴×6.42X10¹⁴
E=4.28×10⁻¹⁹J
Therefore, 4.28×10⁻¹⁹J is the energy of a photon that emits a light frequency of 6.67×10⁻³⁴ Hz.
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Carbon-11 is a radioactive isotope of carbon. Its half-life is 20 minutes. What amount of the initial mass of 70.0g of C-11 atoms in a sample will be left after 80 minutes?
a)5.68 g
b)4.38 g
c)4.20 g
d)3.96 g
e)50.00 g
Answer:
Option B. 4.38 g
Explanation:
The following data were obtained from the question:
Half life (t½) = 20 mins
Original amount (N₀) = 70 g
Time (t) = 80 mins
Amount remaining (N) =.?
Next, we shall determine the decay constant. This can be obtained as illustrated below:
Half life (t½) = 20 mins
Decay constant (K) =.?
Decay constant (K) = 0.693/ half life (t½)
K = 0.693/20
K = 0.03465 min¯¹
Finally, we shall determine the amount remaining after 80 mins as follow:
Original amount (N₀) = 70 g
Time (t) = 80 mins
Decay constant (K) = 0.03465 min¯¹
Amount remaining (N) =.?
Log (N₀/N) = kt/2.303
Log (70/N) = (0.03465 × 80)/2.303
Log (70/N) = 2.772/2.303
Log (70/N) = 1.2036
Take the anti log of 1.2036
70/N = antilog (1.2036)
70/N = 15.98
Cross multiply
70 = N × 15.98
Divide both side by 15.98
N = 70/15.98
N = 4.38 g
Therefore, the amount of the isotope remaining after 80 mins is 4.38 g
Why were the results of the meta-analysis of 12 randomized controlled trials more significant than the results from the observational studies
of the Britons and Seventh-Day Adventists in North America?
Answer: Why were the results of the meta-study of 12 randomized reserved troubles more meaningful than the results from the practical studies of the Britons and Seventh-Day Adventists in North America? The meta-study is more meaningful cause matters were carelessly picked and pressure misfortune was calculated.
HQ5.40
Homework Answered Due Today, 11:59 PM
The reaction 3H₂(g) + N₂(g) → 2NH3(g) has an enthalpy of reaction of -92.6 kJ/mol. If 1 g of hydrogen and 2 g of nitrogen are
reacted, how much heat is produced (kJ)?
The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ
How do i determine the heat energy produced?First, we shall obtain the limiting reactant. Details below:
3H₂ + N₂ -> 2NH₃
Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 g Molar mass of H₂ = 2 g/molMass of H₂ from the balanced equation = 3 × 2 = 6 gFrom the balanced equation above,
28 g of N₂ reacted with 6 g of H₂
Therefore,
2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂
We can see that only 0.43 g of H₂ is needed in the reaction.
Thus, the limiting reactant is N₂
Finally, we the amount of heat energy produced. Details below:
3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ
Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 gFrom the balanced equation above,
When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.
Therefore,
When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ
Thus the heat energy produced from the reaction is -6.61 KJ
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Calculate the [H+] and pH of a 0.000185 M acetic acid solution. Keep in mind that the Ka of acetic acid is 1.76×10−5. This is a problem that will require you to use the quadratic. Start by setting up the quadratic equation before using the quadratic formula and find the coefficients. Then, solve the quadratic. Quadratic formula: ax2+bx+c=0; enter the values of a, b, and c
Answer:
[H⁺] = 0.000048936M
pH = 4.31
Explanation:
Acetic acid, CH₃COOH, dissociates in water as follows:
CH₃COOH(aq) ⇄ H⁺(aq) + CH₃COO⁻(aq)
And Ka is defined as:
Ka = 1.76x10⁻⁵ = [H⁺] [CH₃COO⁻] / [CH₃COOH]
Where [] are equilibrium concentrations of the species.
The 0.000185M of acetic acid will decreases X, and X of [H⁺] and [CH₃COO⁻] will be produced. That means Ka is:
1.76x10⁻⁵ = [X] [X] / [0.000185 - X]
3.256x10⁻⁹ - 1.76x10⁻⁵X = X²
3.256x10⁻⁹ - 1.76x10⁻⁵X - X² = 0
Solving for X:
X = -0.000066M → False solution. There is no negative concentrations.
X = 0.000048936
As [H⁺] = X,
[H⁺] = 0.000048936M
And pH = -log [H⁺]
pH = 4.31The density of an object is 5g/cm^3 and the volume of the object is 10 cm^3. What is the mass of the object
The mass of the object of density 5g/cm³ and volume 10 cm³ is 50kg.
What does physics mean when it refers to density?Defining density How tightly a material is packed together is determined by its density. Its definition is "mass per unit volume". D or, the symbol for density
Density Formula: = m/V,
where is the density, m is the object's mass, and V is its volume.
The units used change depending on the calculation's use of mass and volume units. Density would be expressed in kg/cm³ if the mass is expressed in kg and the volume in cm³.
Density = mass / volume
Mass = density × volume
Mass = 5×10
Mass = 50 kg.
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What mass of NaCl is needed to produce a 26.4 mol/L with a 1.7 L volume?
we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.
To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.
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What is the ratio of ions in 2Na3PO4?
The ratio of ions in the given ionic compound, 2 Na₃PO₄ is 6 : 2.
What are ions?Ions are substances formed when atoms of elements gain or lose or lose electrons.
In some instances, the group of atoms may come together and react as one unit and these are called radicals.
Ionic compounds are formed when two oppositely charged ions are held together by electrostatic forces of attraction.
The ions in the given ionic compound, 2 moles of Na₃PO₄, are as follows;
2 * 3 moles of Na⁺ = 6 moles
2 * 1 mole of PO₄ = 2 moles
The ratio of ions = 6 : 2
The ratio of ions = 3 : 1
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Which subatomic particle has the least mass?
URGENT
Subject/SCIENCE
A. electron
B. proton
C. neutron
D. the atom
Answer:
I thinnk neutron bcoz its is a charge less particle and it's contains less atom so it has less mass
..................
are called energy giving nutrients
Answer:
macronutrients (carbohydrates, lipids, and proteins)
Check the box under each molecule in the table below that is an isomer of this molecule:
The branched alkanes in boxes two and three all have molecular formula C6H14 and are isomers of the compound shown.
Isomers are compounds that has the same molecular formula but different structural formulas. Hence, isomers of compounds can be represented by the same molecular formula since they contain the same number of each atom.
The molecule shown has molecular formula C6H14. The branched alkanes in boxes two and three all have molecular formula C6H14 and are isomers of the compound shown.
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Which structure is the Lewis structure for ammonia (NH3)?
A.
A bond line structure of a compound has N H H H. The nitrogen has two dots at its bottom represents a lone pair of electrons.
B.
A bond line structure of a compound has H N H in the linear plane and hydrogen is branching upward, and the compound is H N (H) H.
C.
A bond line structure of a compound has H N H in linear plane and a hydrogen is branching upward, and the compound is H N (H) H. The nitrogen has two dots at its bottom represents a lone pair of electrons.
D.
A bond line structure of a compound has H N H H. The nitrogen has two dots on its top represents a lone pair of electrons.
Answer: **
H-N-H
|
H
Explanation:
Look at a periodic table to determine how many electrons you need to account for. Hydrogen (H) only has 1 electron, while Nitrogen (N) has 5. We have three Hydrogen atoms and one Nitrogen atom, so the total number of electrons will be 3 * 1 + 5 = 8 e-.
Now, place the center atom, which will be Nitrogen and place the three Hydrogens on three sides of it as above in the answer. You should use single bonds for this. Each single bond is a pair of electrons, so since we have three single bonds so far, we have accounted for 2 * 3 = 6 electrons. However, we need 2 more electrons for the total of 8. We put these electrons in as a lone pair above Nitrogen.
We check to see if everything follows the octet rule: Nitrogen has three single bonds, so that's 6 e-, as well as one lone pair, so that's another 2 e- for a total of 8 e-. Check. Now look at Hydrogen: H is the only element whose full orbital is 2 e-. Each H has a single bond with Nitrogen, so each does have 2 e-.
Thus, we know this is the correct diagram, and we are done.
Explanation:
A bond line structure of a compound has H N H in linear plane and a hydrogen is branching upward, and the compound is H N (H) H. The nitrogen has two dots at its bottom represents a lone pair of electrons. So ,the correct answer is option C.
The correct Lewis structure for ammonia (\(NH_3\)) is option C. It shows a bond line structure with three hydrogen atoms (H) bonded to a central nitrogen atom (N) in a linear plane.
One hydrogen atom branches upward from the plane. Additionally, the nitrogen atom in this structure has two dots at its bottom, indicating a lone pair of electrons. This arrangement follows the octet rule, as nitrogen has formed three covalent bonds with hydrogen, completing its valence shell. The lone pair on nitrogen gives ammonia its characteristic properties.
Thus, option C accurately represents the Lewis structure of ammonia, showing the bonding and lone pair arrangement of its atoms.
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when molecules colide is the explosion instant or is there a delay if so why is there a delay
When molecules collide, there is generally a delay before an explosion occurs, if an explosion occurs at all. This is because an explosion requires a chemical reaction to take place, which involves the breaking of chemical bonds and the formation of new bonds. These reactions require a certain amount of energy, which is called the activation energy.
The collision of molecules can provide energy to the system, but it is not always enough to overcome the activation energy needed for a chemical reaction to occur. If the energy of the collision is less than the activation energy, no reaction will occur and there will be no explosion. If the energy of the collision is equal to or greater than the activation energy, a chemical reaction may occur and an explosion may result.
The time delay between the collision of molecules and an explosion occurring depends on the nature of the molecules and the conditions under which the collision occurs. Some chemical reactions are very fast and can occur almost instantly, while others may take longer to reach the activation energy and proceed to completion.
It's worth noting that not all collisions between molecules result in an explosion. In many cases, the collision may simply transfer energy from one molecule to another without leading to a chemical reaction.
what is the linkage that binds one monosaccharide to another?
Answer:
hope this helps
Explanation:
glycosidic bond
A covalent bond formed between a carbohydrate molecule and another molecule (in this case, between two monosaccharides) is known as a glycosidic bond (Figure 4). Glycosidic bonds (also called glycosidic linkages) can be of the alpha or the beta type.
Answer:
glycosidic bond
Explanation:
A covalent bond formed between a carbohydrate molecule and another molecule (in this case, between two monosaccharides) is known as a glycosidic bond
_____ resources are resources that cannot be replenished within a lifetime.
Question 1 options:
Nonrenewable
Renewable
Living
Endangered
Nonrenewable natural resources are resources that cannot be replenished within a lifetime.
out of ammonia (molecular mass 17 g ) and helium (mass 4 g ) which one diffuses faster?
Answer:
ammonia diffuses faster.
hope this helps.
It is difficult to break the ionic bonds in a compound because of the
An OH group attached to a hydrocarbon is called a _________ group whereas ______________ is a polyatomic ion with a charge of _______.
An OH group attached to a hydrocarbon is called an alkyl group whereas hydroxide is a polyatomic ion with a charge of -1.
What is OH group?OH group is also called hydroxyl group. Alcohol is a type of organic compound that is characterized by one or more hydroxyl (―OH) groups attached to a carbon atom of an hydrocarbon chain so we can conclude that an OH group attached to a hydrocarbon is called an alkyl group whereas hydroxide is a polyatomic ion with a charge of -1.
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What is the density of a piece of granite whose volume is 20 mL and mass is 53
grams?
3.05 g/mL
2.75 g/mL
4.0 g/mL
2.65 g/mL
2.65g/ml is the density of a piece of granite whose volume is 20 mL and mass is 53grams. Density is the mass of a specific material per unit volume.
What is density?Density is the mass of a specific material per unit volume. Density is defined as d = M/V, in which d represents density, M is weight, as well as V is volume. Density is generally expressed in grams every cubic centimetre. Water, for example, has a density of 1 gram per square centimeter, but Earth has a density of 5.51 kilograms per cubic centimetre.
Density is sometimes measured in kilos per cubic centimeter (in metre-kilogram-second or SI units). The density of air, for example, is 1.2 kilos per cubic metre.
density = mass / volume
=53/ 20
=2.65g/ml
Therefore, 2.65g/ml is the density of a piece of granite whose volume is 20 mL and mass is 53grams.
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Which of the following is true for the theoretical yield of a reaction? (1 point)
It is always calculated as a ratio.
It is the yield from the excess reactant.
It is the yield from the limiting reactant.
It is always twice the value of the actual yield.
Answer:
It is always twice the value of the actual yield.
Explanation:
PLEASE HELP IT IS DUE IN 2HOURS THE ASSIGNMENT ON THE PICTURE
Note that convection currents in the mantle drive plate tectonics, causing the event. These currents push and pull on plates, creating divergent, convergent, and transform boundaries. This event is caused by plate interaction at divergent or convergent boundaries.
Divergent and convergent boundaries can be found along plate tectonic boundaries such as mid-oceanic ridges and subduction zones.
What are convection currents in this context?Convection currents are the movement of material in a fluid or solid due to differences in temperature and density. In the context of plate tectonics, convection currents in the Earth's mantle drive the movement of the tectonic plates. These currents are thought to be driven by heat from the Earth's interior and the cooling and sinking of dense materials at the surface.
Note that in the attached image, the lines in red mark the divergent and convergent boundaries and where they can be found.
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A slice of Swiss cheese contains 41 mg of sodium.
Required:
a. What is this mass in grams?
b. What is this mass in ounces?
c. What is this mass in pounds?
Answer:
a. 41 mg equals 0.041 grams.
b. 41 mg equals 0.0014462 ounces
c. 41 mg equals 9.039*10⁻⁵ pounds
Explanation:
You know that a slice of Swiss cheese contains 41 mg of sodium.
a. What is this mass in grams?
Knowing that 1 mg = 10⁻³ g, you can apply the following rule of three: if 1 mg equals 10⁻³ g or 0.001 grams, 41 mg will be equivalent to how much mass in g?
\(mass=\frac{41 mg*0.001 g}{1 mg}\)
mass= 0.041 grams
41 mg equals 0.041 grams.
b. What is this mass in ounces?
Knowing that 1 mg = 3.5274 * 10⁻⁵ ounces, you can apply the following rule of three: if 1 mg equals 3.5274 * 10⁻⁵ ounces, 41 mg will be equivalent to how much mass in ounces?
\(mass=\frac{41 mg*3.5274*10^{-5}ounces }{1 mg}\)
mass= 1.4462*10 ⁻³ ounces= 0.0014462 ounces
41 mg equals 0.0014462 ounces
c. What is this mass in pounds?
Knowing that 1 mg = 2.20462 * 10⁻⁶ pounds, you can apply the following rule of three: if 1 mg equals 2.20462 * 10⁻⁶ pounds, 41 mg will be equivalent to how much mass in pounds?
\(mass=\frac{41 mg*2.20462*10^{-6}pounds }{1 mg}\)
mass= 9.039*10⁻⁵ pounds
41 mg equals 9.039*10⁻⁵ pounds
Match the atom to the number of electrons it is likely to gain/lose.Calcium (Ca)Phosphorus (P)Potassium (K)Sulfur (S)Fluorine (F)Boron (B)?lose 1?lose 2?lose 3?gain 3
To answer this question, we have to look for the oxidation numbers of each of the elements.
Oxidation number of calcium is +2, which means that it is likely to lose 2 electrons.
Oxidation number of potassium is +1, which means that it is likely to lose 1 electron.
Oxidation number of Boron in +3, which means that it is likely to lose 3 electrons.
Oxidation number of Fluorine is -1, which means that is is likely to gain 1 electron.
Oxidation number of Phosphorus is -3, which means that it is most likely to gain 3 electrons.
Oxidation number of Sulfur is -2, which means that it is most like to gain 2 electrons.
It means that the final answer is:
Potassium - Lose 1
Calcium - Lose 2
Boron - Lose 3
Fluorine - Gain 1
Sulfur - Gain 2
Phosphorus - Gain 3
Find energy is the wavelength is 5.2x10^-7m (Show work)
Answer:
E = 3.825×10⁻¹⁹ J
Explanation:
Wavelength of photon = 5.2 ×10⁻⁷m
Energy of photon = ?
Solution:
Formula:
E = hc/λ
h = plancks constant = 6.63×10⁻³⁴ Js
c = speed of wave = 3×10⁸ m/s
by putting values,
E = 6.63×10⁻³⁴ Js ×3×10⁸ m/s / 5.2 ×10⁻⁷m
E = 19.89×10⁻²⁶ J.m / 5.2 ×10⁻⁷m
E = 3.825×10⁻¹⁹ J