Answer:
its d, forming a hypothesis is always one of the first things you do, and d is the best answer from these 4
Answer:
D. A scientist should form a hypothesis, then conduct an experiment
Draw the electron dot structure for the convalebt bond of F and I
Answer:
this is your answer hope it will help you
2. If you put 156. 32g barium hydroxide into this reaction, how much aluminium hydroxide can be
produced?
When 156.32 g of barium hydroxide is reacted, approximately 142.34 g of aluminum hydroxide can be produced, based on the balanced chemical equation and stoichiometry.
To determine the amount of aluminum hydroxide that can be produced when 156.32 g of barium hydroxide is reacted, we need to consider the balanced chemical equation for the reaction and use stoichiometry.
The balanced chemical equation for the reaction is:
Ba(OH)2 + 2AlCl3 → 2Al(OH)3 + 3BaCl2
From the balanced equation, we can see that for every 1 mole of Ba(OH)2, 2 moles of Al(OH)3 are produced.
First, we need to calculate the number of moles of barium hydroxide (Ba(OH)2) in 156.32 g:
Molar mass of Ba(OH)2 = (137.33 g/mol + 2(16.00 g/mol + 1.01 g/mol)) = 171.34 g/mol
Moles of Ba(OH)2 = mass / molar mass = 156.32 g / 171.34 g/mol = 0.911 mol
Now, using the stoichiometry of the balanced equation, we can determine the moles of aluminum hydroxide (Al(OH)3) produced:
Moles of Al(OH)3 = 2 × Moles of Ba(OH)2 = 2 × 0.911 mol = 1.822 mol
Finally, to convert the moles of aluminum hydroxide to grams, we need to multiply by the molar mass of Al(OH)3:
Molar mass of Al(OH)3 = (26.98 g/mol + 3(16.00 g/mol + 1.01 g/mol)) = 78.00 g/mol
Mass of Al(OH)3 = Moles of Al(OH)3 × molar mass = 1.822 mol × 78.00 g/mol = 142.34 g
Therefore, when 156.32 g of barium hydroxide is reacted, approximately 142.34 g of aluminum hydroxide can be produced.
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When a scientist uses reasoning to explain or interpret the things they observe
Answer:
Inferring is when a scientist uses reasoning to explain or interpret the things they observe
According to kinetic-molecular theory, in which of the following gases will the root-mean-square speed of the molecules be the highest at 200°C? О H2O SF6 None. The molecules of all gases have the same root-mean-square speed at any given temperature
The root-mean-square speed of the molecules will be the highest in SF6 at 200°C. According to the kinetic-molecular theory, the root-mean-square speed of gas molecules is directly proportional to the square root of their absolute temperature and inversely proportional to the square root of their molar mass.
The formula for calculating the root-mean-square speed is:
vrms = √(3RT/M)
where:
vrms = root-mean-square speed
R = ideal gas constant
T = absolute temperature
M = molar mass of the gas
At a given temperature, gases with lower molar masses will have higher root-mean-square speeds. In this case, we are comparing gases at 200°C. Among the given options (O2, H2O, and SF6), SF6 has the highest molar mass. Therefore, according to the kinetic-molecular theory, the root-mean-square speed of SF6 molecules will be the highest at 200°C.
The root-mean-square speed of molecules is not the same for all gases at a given temperature. It depends on the molar mass of the gas. In this case, SF6 has the highest molar mass among the given options, so its molecules will have the highest root-mean-square speed at 200°C.
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URGENT! Please help! Hi, I have to do a titration lab report using the Royal Society of Chemistry online titration lab. Please help me answer the following questions using the observation table I think?
Answer:
I'm sorry, but I cannot see the observations or the data table you mentioned in your question. However, I can still provide you with some general guidance on how to approach the calculations and answer the questions based on the given information.
4. To calculate the concentration of the NaOH solution, you need to know the mass of NaOH used and the volume of the solution. The formula to calculate concentration is:
Concentration (in mol/L) = (Mass of NaOH (in grams) / molar mass of NaOH) / Volume of solution (in L)
Make sure to convert the mass of NaOH to moles by dividing it by the molar mass of NaOH. The molar mass of NaOH is the sum of the atomic masses of sodium (Na), oxygen (O), and hydrogen (H).
5. The balanced equation for the neutralization reaction between NaOH and HCl is:
NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
(aq) represents an aqueous solution, and (l) represents a liquid.
6a. To calculate the average concentration of HCl in the sample from site B, you need to know the volumes and concentrations of the NaOH and HCl solutions used in the titration. Use the formula:
Concentration of HCl (in mol/L) = (Volume of NaOH solution (in L) * Concentration of NaOH (in mol/L)) / Volume of HCl solution (in L)
Multiply the volume of NaOH solution used by its concentration to find the amount of NaOH used. Then, divide this amount by the volume of HCl solution used to find the concentration of HCl.
6b. To determine the pH of the water at site B, you need to know the concentration of HCl from the previous calculation. The pH can be calculated using the formula:
pH = -log10[H+]
Since HCl is a strong acid, it dissociates completely into H+ ions. Therefore, the concentration of H+ ions is equal to the concentration of HCl. Take the negative logarithm (base 10) of the H+ concentration to find the pH.
To check if the water is safe, compare the calculated pH value to the range provided (pH 4.5-7.5). If the pH falls within this range, the water is considered safe for plant and animal reproduction in an aquatic environment.
6c. Use a similar calculation as in 6a to determine the average concentration of HCl in the sample from site C.
6d. Use the concentration of HCl from 6c to calculate the pH using the formula in 6b. Follow the same procedure to check if the water is safe based on the pH range.
7. To find the most current pH value for the Grand River, you can search for the latest data from reliable sources such as environmental agencies, research institutions, or government websites. Compare this pH value to the pH values obtained in the experiment to assess the difference between them.
Remember, without the specific data and observations, the calculations and comparisons provided here are only general guidelines. It's important to use the actual data from your experiment to obtain accurate results and conclusions.
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What is the temperature?
Answer:
17.25 degrees
Explanation:
....but I cannot tell you if that is °C or °F <===== that is left out of the question.
What element is the only metal in group VB?
Vanadium
Atleast i think so
What is the elements don’t bond with other elements because their outer shell is filled?
Answer:
Inert gases or noble gases
Explanation:
These gases have 8 outer shells meaning their full so they won't allow chemical reactions therefore providing an inert environment hence the name inert gas.
What will happen to a salt water fish if placed in freshwater?
Answer:
they will die because they need to be in salt water
What is the molecular weight of a peptide chain with 40 residues? 0.36 Da 60 Da O 4.4 kDa 5.5 kDa
The molecular weight of a peptide chain with 40 residues is approximately 4.4 kDa.
To determine the molecular weight of a peptide chain with 40 residues, you'll need to know the average molecular weight of an amino acid residue and then perform a simple calculation. A peptide chain is a linear chain of amino acids that are linked together through peptide bonds.
Peptide chains are the building blocks of proteins and are formed by a process called protein biosynthesis, which involves the translation of genetic information from DNA into a specific sequence of amino acids.
Here's a step-by-step explanation on how to calculate molecular weight :
1. The average molecular weight of an amino acid residue is approximately 110 Da (Daltons).
2. Multiply the number of residues (40) by the average molecular weight of a residue (110 Da):
40 residues * 110 Da/residue = 4400 Da
3. Convert the molecular weight to kilodaltons (kDa) by dividing by 1000:
4400 Da / 1000 = 4.4 kDa
So, the molecular weight of a peptide chain with 40 residues is approximately 4.4 kDa.
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What do you think are other important application of these
reference lines that we have just discussed? Write your
answer on a separate sheet of paper. Be sure to be guided by
the rubrics for scoring. Please po pero wag lang yung link
Reference lines are crucial in creating technical drawings. They are used as guidelines in drawing objects.
Other important applications of these reference lines are in the fields of architecture, engineering, and construction. In architecture, reference lines are used to create accurate drawings of buildings, homes, and other structures. These reference lines help architects to accurately depict the structure of buildings and ensure that they are structurally sound.
In engineering, reference lines are used to create technical drawings of machines, engines, and other mechanical structures. These drawings are used in the manufacturing process to ensure that the machines and engines are built according to the design specifications. The reference lines help engineers to create accurate drawings that can be used to build the machines and engines.In construction, reference lines are used to create plans for buildings, roads, and other infrastructure. These plans are used to ensure that the construction project is completed according to the design specifications. The reference lines help construction workers to accurately lay out the building or road and ensure that it is constructed properly. In addition to architecture, engineering, and construction, reference lines also have other important applications. In the field of product design, reference lines are used to create technical drawings of products.
These drawings are used in the manufacturing process to ensure that the products are built according to the design specifications. The reference lines help product designers to create accurate drawings that can be used to build the products.In the field of automotive design, reference lines are used to create technical drawings of automobiles. These drawings are used in the manufacturing process to ensure that the automobiles are built according to the design specifications. The reference lines help automotive designers to create accurate drawings that can be used to build the automobiles. Reference lines are also used in the field of graphic design. In graphic design, reference lines are used to create logos, icons, and other graphic elements. The reference lines help graphic designers to create accurate drawings that can be used in a variety of applications. In conclusion, reference lines are important in creating accurate technical drawings in various fields. These reference lines help architects, engineers, construction workers, product designers, automotive designers, and graphic designers to create accurate drawings that can be used in the manufacturing process. The use of reference lines ensures that the final product is built according to the design specifications and is structurally sound.
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asymmetrical alkyne + Hâ‚‚ (1 mol equivalent) + lindlar catalyst
The combination of an asymmetrical alkyne and hydrogen gas (H₂) in the presence of a Lindlar catalyst typically results in the partial reduction of the alkyne to yield a cis-alkene.
The Lindlar catalyst, also known as Lindlar's palladium catalyst, consists of palladium deposited on calcium carbonate or barium sulfate and then poisoned with lead acetate or quinoline.
This modified palladium catalyst is selective for the partial hydrogenation of alkynes to cis-alkenes, without further reduction to the corresponding alkane.
The mechanism of the Lindlar catalyst involves the adsorption of the alkyne onto the surface of the catalyst, followed by the reduction of the alkyne to a cis-alkene via the formation of a metal-carbon intermediate.
The lead acetate or quinoline acts as a poison to prevent the over-reduction of the alkyne to the corresponding alkane.
Overall, the reaction of an asymmetrical alkyne with hydrogen gas and Lindlar catalyst produces a cis-alkene with stereochemistry that is determined by the starting alkyne.
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What does the word omniphobic mean?
Answer:
Special type of surface that repels liquid
Explanation:
How many moles are there in 1.27 x 10^24 atoms of potassium
Answer:
Explanation:
We know that, 1 mole of any substance contain 6.022 X 10^23 atoms/molecules.
Thus, 6.022 X 10^23 atoms = 1 mole
Therefore, 1.29x10^24 =
= 2.14
Thus, 2.14 moles are present in 1.29x10^24 hydrogen atoms in HF.
Is the law of conservation of matter followed in the reaction below?
Answer:
28g
Explanation:
issued this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your etext. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon.
The atomic ratio of carbon to oxygen in carbon monoxide (CO) is 1:1, and the atomic ratio of carbon to oxygen in carbon dioxide (CO₂) is 2:1.
Firstly, we can analyze the decomposition of carbon monoxide (CO) and carbon dioxide (CO₂) to determine the atomic ratios involved.
Let's denote the atomic ratio of carbon to oxygen in carbon monoxide as x, and the atomic ratio of carbon to oxygen in carbon dioxide as y.
According to the given data;
Decomposition of carbon monoxide (CO);
Oxygen produced = 3.36 g
Carbon produced = 2.52 g
We know that the atomic mass of carbon is 12 g/mol, and the atomic mass of oxygen is 16 g/mol. Using these values, we can calculate the number of moles for each element;
Number of moles of oxygen = mass / atomic mass = 3.36 g / 16 g/mol = 0.21 mol
Number of moles of carbon = mass / atomic mass = 2.52 g / 12 g/mol = 0.21 mol
Since the atomic ratio of carbon to oxygen in carbon monoxide is x, we can write the following equation;
0.21 mol C / (0.21 mol O) = x
Simplifying the equation, we have;
x = 1
Therefore, the atomic ratio of carbon to oxygen in carbon monoxide is 1:1.
Decomposition of carbon dioxide (CO₂);
Oxygen produced = 9.92 g
Carbon produced = 3.72 g
Following the same calculations as before;
Number of moles of oxygen = mass / atomic mass = 9.92 g / 16 g/mol = 0.62 mol
Number of moles of carbon = mass / atomic mass = 3.72 g / 12 g/mol = 0.31 mol
Since the atomic ratio of carbon to oxygen in carbon dioxide is y, we can write the following equation;
0.31 mol C / (0.62 mol O) = y
Simplifying the equation, we have;
y = 0.5
Therefore, the atomic ratio of carbon to oxygen in carbon dioxide is 1:0.5, which can be simplified to 2:1.
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--The given question is incomplete, the complete question is
"Missed this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your text. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon. Calculate the atomic ratio of carbon to oxygen in carbon monoxide, and carbon dioxide."--
Which statement is true about heat transfer? *
5 points
a. Heat can only transfer when touching another object.
b. Heat always travels up.
c. Heat transfers from cooler to warmer objects.
d. Heat transfers from hotter to cooler objects.
Answer: A
Explanation:
heat always passes from a warmer object to a cooler object until all objects are the same temperature. Conduction is how heat travels between objects that are touching. Conduction travels fastest through solids, but liquids and gases can also conduct heat.
4) The principle of ________ states that the physical, chemical, and biological processes at work shaping the Earth today have also operated in the geologic past.
A) catastrophism
B) plate tectonics
C) plutonism
D) Uniformitarianism
The principle of option D. Uniformitarianism states that the physical, chemical, and biological processes at work shaping the Earth today have also operated in the
Option D. Uniformitarianism is the principle stating that the physical, chemical, and biological processes at work shaping the Earth today have also operated in the geologic past. It is based on the idea that the present is the key to the past. In other words, the same natural laws that operate in the universe today have been operating since the beginning of time.
James Hutton was the first to propose this principle in the late 18th century. He suggested that the Earth was shaped by slow-acting geological forces such as erosion, sedimentation, and uplift over long periods of time. He believed that the same processes were still happening today and that they had operated in the past.
This principle is an important concept in geology because it allows scientists to interpret the Earth's history based on the processes that they observe today. By understanding how these processes work and how they have changed over time, scientists can reconstruct the history of the Earth and its environments.
Uniformitarianism has been tested and proven through many observations and experiments. For example, the study of sedimentary rocks has shown that they were formed in the past through the same processes that are observed today, such as deposition of sediment by water, wind, or ice.
Similarly, the study of volcanoes has shown that they are formed by the same processes as today, such as the movement of magma from deep within the Earth.
In conclusion, Uniformitarianism is the principle that allows us to interpret the Earth's history by observing the processes that shape it today. It is a fundamental concept in geology and has been tested and proven through many observations and experiments.
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Experimental
is a factor that can arise from incorrect use
of measuring tools or malfunctioning equipment..
Answer:
Error.
Explanation:
An experiment can be defined as an investigation which typically involves the process of manipulating an independent variable (the cause) in order to be able to determine or measure the dependent variable (the effect).
This ultimately implies that, an experiment can be used by scientists to show or demonstrate how a condition causes or gives rise to another i.e cause and effect, influence, behavior, etc in a sample.
Cause and effect can be defined as the relationship between two things or events in which an occurrence one (cause) leads to the occurrence of another (effect).
Experimental error is a factor that can arise from incorrect use of measuring tools or malfunctioning equipment such as thermometer, barometer, multimeter, voltmeter, ammeter, vernier caliper, etc. This error usually causes test results to be inaccurate, incorrect and as such leading to wrong experimental conclusions.
Also, one common example of an experimental error is the error due to parallax.
How many mole ratios can be written for a chemical reaction involving four substances?
Answer:
12 and 20 moles ratios, respectively.
Explanation:
Note that the number of mole ratios you can write for a chemical reaction involving a total of n substances is (n)(n–1). Thus, for reactions involving four and five substances, you can write 12 and 20 moles ratios, respectively.
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Which action results from the combination of gravity and inertia working on the moon?
the moon’s orbit around Earth
Earth’s downward pull on the moon
the moon’s push against other planets
Earth’s gravitational pull toward the moon
Answer: The correct option is A. The moon's orbit around Earth
Explanation: Newtons first law of motion says that an object in motion will always remain in motion and an object in erst will always stay at rest untill an external force acts upon it. This law is also called law of inertia which is the property of a body to resist any change in its state of rest or motion. Since moon is also revolving around the earth so it is in motion always and it continues its motion.
Answer:
the moon’s orbit around Earth
Explanation:
pls help with chemistry asap
Answer:
1.63mole
Explanation:
The novice nurse administers RBCs to a client. Which actions by the novice nurse are deemed safe by the nurse preceptor? (Select all that apply.)
Priming the intravenous tubing with 0.9% sodium chloride.
Obtaining and documenting a full set of baseline vital signs.
NOT setting the infusion rate to deliver blood within 6 hours - it should be 4 hours.
Also require large gauge catheters 20-24 gauge.
Should stay with client for first 15 minutes
According to the nurse preceptor, the new nurse adheres to a number of safe practices while administering red blood cells (RBCs) to a patient.
Based on the given options, the actions that are deemed safe by the nurse preceptor are:
Priming the intravenous tubing with 0.9% sodium chloride.Obtaining and documenting a full set of baseline vital signs.Setting the infusion rate to deliver blood within 4 hours instead of 6 hours.Using large gauge catheters (20-24 gauge). When giving red blood cells (RBCs) to a patient, the novice nurse follows a number of safe procedures, according to the nurse preceptor. To ensure appropriate flushing and lower the chance of an air embolism, the inexperienced nurse correctly primes the intravenous tube with 0.9% sodium chloride in the first step. The second step is for the inexperienced nurse to collect and record a complete set of baseline vital signs. This creates a baseline for monitoring the client's status both before and after the transfusion. Third, in accordance with the advised duration for safe administration, the nurse modifies the infusion rate to administer the RBCs in 4 hours as opposed to 6 hours. Fourth, the inexperienced nurse employs big gauge catheters (20-24 gauge) to promote quick and smooth blood product flow and reduce problems.
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A block pf wood is 5 long, 4cm wide and 10cm high it weighs 100 grams calculate the density
Volume = 5x3x10 = 150 cm cubed
Mass = 150x100 = 15000 grams
Density = 15000/150 = 100g/cm cubed
Please somone help me with a chemistry question brainliest to whoever answers correctly and 20 points
Answer:
3132 is the answer
Explanation:
3BaCl2 + Al2S3 → 3BaS + 2AlCl3
Answer:
Explanation:
Hope this helps u !!
What is the major attractive force that exists among different I2 molecules in the solid? Select one: A. covalent-ionic interactions. B. Dispersion forces. C.
The claim that sense neurons' cell bodies are located in the grey commissure, an expanded region of the dorsal root.
Dorsal nerve roots provide sensory neural signals to the central nervous system from the peripheral nervous system. Anatomically, a dorsal root ganglion develops from the dorsal root of the spinal nerves. For the central nervous system to react, they transmit sensory data from multiple peripheral receptors. It is generally recognised that DRG has a role in chronic pain. The first description of anaesthesia infiltration of the DRG was made in 1949. It has been possible to target the DRG using the dorsal root entry zone (DREZ), a nearby related neural target, dorsal rhizotomy or gangliectomy, conventional radiofrequency denervation, pulsed radiofrequency, and steroid injection.
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How was Bohr’s atomic model different from Rutherford’s atomic model?
Answer:
Bohr thought that electrons orbited the nucleus in circular paths; whereas in the modern view atomic electron structure is more like 3D standing waves. ... He believed that electrons moved around the nucleus in circular orbits with quantised potential and kinetic energies.
Answer:
The answer is A electrons exist in specified energy levels surrounding the nucleus. for people in edguinity
Explanation:
estimate the mass of water that must evaporate from the skin to cool the body by 0.5 degrees celsius. assume a body mass of 95 kg ans assume that the specific heat capacity of the body is 4.0 j/g x degrees celsius
The mass of water that must evaporate from the skin to cool the body by 0.5 degrees Celsius is 90.079 g.
A body's mass is an inherent quality. Prior to the discovery of the atom and particle physics, it was widely considered to be tied to the amount of matter in a physical body. It was discovered that, despite having the same quantity of matter in theory, various atoms and elementary particles had varied masses.
There are several conceptions of mass in contemporary physics that are theoretically different but practically equivalent. The resistance of the body to acceleration (change of velocity) in the presence of a net force may be measured experimentally as mass. The gravitational pull an item has on other bodies is also influenced by its mass.
Change in temperature = ∆T = 0.5°C
Specific heat capacity of the body = s = 4 J/goC = 4000 J/kgoC
Mass of body = m = 95 kg
Now, heat lost by the body will be:
Q1 = - ms∆T ……….(i)
By putting values in equation (i)
Q1 = - (95)(4000)(0.5)
Q1 = - 220000 J = - 220 KJ
Heat absorbed by the water will be:
Q2 = - (Q1) = 220 KJ
Evaporation is an endothermic process and standard enthalpy per mole evaporation of water is 44.01 KJ so,
Mass of evaporated water = (220 KJ)(1 mol/44.01 KJ) (18.02g/1 mol)
Mass of evaporated water = 90.079 g.
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how many electrons does phosphorus need to gain to have a stable outer electron shell
1
2
3
4
Answer:
3
Explanation:
Phosphorous valence is 5. so to get stable electronic configuration it has to gain 3 more electrons to its outer shell
Answer:
3
Explanation:
luckily, every phosphorus atom is looking to gain 3 electrons. It's a perfect match. But something to notice though, look how they have a bond with six electrons. That is called triple bond.
ch 11. which one of these substances is a liquid at room temperature?
a. CH3OH
b. CF4
c.SiH4
d.CO2
CH\(_3\)OH is a liquid at room temperature. Therefore, the correct option is option A.
A liquid comprises an almost incompressible fluid with an almost constant volume regardless of pressure that adapts to the form of its container. It constitutes one among the four basic forms of matter and the only one that has a known volume but no set shape. A liquid typically has a density that is higher than a gas and comparable to a solid. Condensed matter so refers to both liquid and solid. On the opposite hand, since both liquids and gases may flow, therefore are both referred to as fluids. CH\(_3\)OH is a liquid at room temperature.
Therefore, the correct option is option A.
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