In machines with low efficiency, most of the lost energy is turned into?

a. Light
b. Sound
c. Power
d. Heat

Answer:

1) If a cell or battery is used, the key in the circuit should be left open so as not to drain the battery or cell.

2) Also, leaving the key closed causes current to flow through the circuit, which also causes the temperature of the circuit to increase. Since the resistance of most metals increases with an increase in temperature, the resistance of the circuit will increase, which will then affect the integrity of the whole experiment.

Answer:

4.16×103 m/s

Explanation:

Answer:

no

Explanation:

because it cannot be represented by a sine or cosine curve.

This question is incomplete, the complete question is;

In a simple model of a potassium iodide (KI) molecule, we assume the K and I atoms bond ionically by the transfer of one electron from K to I.

(a) The ionization energy of K is 4.34 eV, and the electron affinity of I is 3.06 eV. What energy is needed to transfer an electron from K to I, to form K+ and I- ions from neutral atoms? This quantity is sometimes called the activation energy Ea.eV

(b) A model potential energy function for the KI molecule is the Lennard - jones potential:

U(r) = 4∈[ (α/r)¹² - (α/r)⁶ ] + Ea

where r is the internuclear separation distance and α and ∈ are adjustable parameters (constants) . The Ea term is added to ensure the correct asymptotic behavior at large r and is activation energy calculated in a. At the equilibrium separation distance, r=r₀=0.305 nm, U(r) is a minimum, and dU/dr=0. In addition, U(r₀)=-3.37 eV.

Us the experimental values for the equilibrium sepeartion and dissociation energy of KI to determine/find 'α' and '∈'.

(c) calculate the force needed to break the KI molecule in nN

Answer:

a) energy is needed to transfer an electron from K to I, to form K+ and I- ions from neutral atoms is 1.28 eV

b) α = 0.272, ∈ = 4.65 eV

c) the force needed to break the KI molecule in nN 65.6 nN

Explanation:

a) The ionization energy of K is 4.34 ev ( energy needed to remove the outer most electrons)

And the electron affinity of I is 3.06 ev ( which is energy released when electron is added)

Now the energy that is need to transfer an electron from K to I,

i.e the ionization energy of K(4.34 ev) and the electron affinity of I (3.06 ev)

RE = 4.34 - 3.06 = 1.28 eV

b)

from the question we have

U(r) = 4∈[ (α/r)¹² - (α/r)⁶ ] + Ea

now taking d/drU(r₀)=0  (at r = r₀)

= 4∈d/dr [ (α/r)¹² - (α/r)⁶ ] = 0

= ( -12(α¹²/r¹³)) - (-6 (α⁶/r⁷)) = 0

12(α¹²/r¹³) = 6 (α⁶/r⁷)

α⁶ = r⁶/2

α = r/(2)^1/6

at equilibrium r = r₀ = 0.305 nm

α = 0.305 nm / (2)^1/6

C = 0.0305/1.1246

α = 0.272

Now substituting the values of U(r₀), α, Eₐ in the initial expression

U(r) = 4∈[ (α/r)¹² - (α/r)⁶ ] + Ea

we have

- 3.37eV = 4∈ [ (0.272 nm / 0.305 nm)¹² - (0.272 nm / 0.305 nm )⁶ ] + 1.28

- 1.65 eV = ∈(0.25 - 0.5)

∈ = 4.65 eV

c)

Now to break the molecule then the potential energy should be zero(0)

and we know r = 0.272 nm

therefore force needed to break the molecule is

F = -dU/dR_r-α

F = -4∈ (-12/α  + 6/α)

F = -4(4.65eV) ( -12/0.272nm + 6/0.272nm)

F = 65.6 nN

Answer:

83.33% of the roof area will be occupied by the PV cells

Explanation:

Given the data in the question;

time-averaged lighting requirement \(P_{lighting\) = 10 W/m²

the annual average solar irradiance \(q_{solar\) = 150 W/m²

the PV efficiency η\(_{pv\) = 10% = 0.1

battery charging/discharging efficiency η\(_{battery\) = 80% = 0.8

we know that; Annual average power to the light = \(P_{lighting\) × A\(_{roof\)

Now, the electrical power delivered by the solar cell battery system will be;

⇒  \(q_{solar\) × A\(_{pv\) × η\(_{pv\) × η\(_{battery\)

\(P_{lighting\)A\(_{roof\) = \(q_{solar\) × A\(_{pv\) × η\(_{pv\) × η\(_{battery\)

Such that;

A\(_{pv\) = \(P_{lighting\)A\(_{roof\) / \(q_{solar\) × A\(_{pv\) × η\(_{pv\) × η\(_{battery\)

A\(_{pv\) / A\(_{roof\) = \(P_{lighting\) /  \(q_{solar\) × η\(_{pv\) × η\(_{battery\)

so we substitute

A\(_{pv\) / A\(_{roof\) = 10 W/m² / [ 150 W/m² × 0.1 × 0.8 ]

A\(_{pv\) / A\(_{roof\) = 10 W/m² / 12 W/m²

A\(_{pv\) / A\(_{roof\) = 0.8333

A\(_{pv\) / A\(_{roof\) = (0.8333 × 100)%

A\(_{pv\) / A\(_{roof\) = 83.33%

Therefore, 83.33% of the roof area will be occupied by the PV cells.

Answer:

See below

Explanation:

The units of the specific heat hint at how to solve these types of problems

.88 J/(g-C)   * 10 g  *  (100- 50 C) = 440 J  

                                  ( see how the g and the C 'cancel out' ?)

Answer:

16

Explanation:

6+10=16

the box will go forward but it will be a little harder.

Answer:B

Explanation:

Answer:B

Explanation:

took the test

Answer: c

Explanation:

Answer:

answer c

Explanation:

Answer:

Correct Answer: B. Beaker A will be 72 °C and beaker B will be 28 °C.

This one is actually right!

Answer:

The hot coffee has a higher temperature, but not a greater internal energy. Although the iceberg has less internal energy per mass, its enormously greater mass gives it a greater total energy than that in the small cup of coffee.

Explanation:

Answer:

The hot coffee has a higher temperature, but not a greater internal energy. Although the iceberg has less internal energy per mass, its enormously greater mass gives it a greater total energy than that in the small cup of coffee.

Answer:

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Explanation:

The torque applied will be the average of the 3 torque calculated.

Torque = 12.01 Nm

Torque of a couple is the product of a force and its perpendicular distance to the direction of the force. Torque is synonymous to moment.

From the question, the given radius is 0.53m. The perpendicular distance for each torque will be 2 x 0.53 = 1.06 m

We will calculate for each torque

T1 = F1d

T1 = 8 x 1.06 = 8.48 Nm

T2 = F2d

T2 = 15 x 1.06 = 15.9 Nm

T3 = F3d

T3 = 11 x 1.06 = 11.66 Nm

The torque applied will be the average of the 3 torque calculated. That is,

Torque = (8.48 + 15.9 + 11.66)/3

Torque = 36.04 /3

Torque = 12.01 Nm

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Given :

Solenoid 2 has twice the radius and six times the number of turns per unit length as solenoid 1.

To Find :

The ratio of the magnetic field in the interior of 2 to that in the interior of 1.

Solution :

We know, magnetic field in the interior of a solenoid is given by :

\(B = \dfrac{\mu ni}{L}\)

Let, length of solenoid 2 is L.

Therefore, length of solenoid 1 is 6L.

\(B_a=\dfrac{\mu (6n)i}{L}\\\\B_b = \dfrac{\mu n i}{L}\)

Dividing \(B_a\) by \(B_b\) :

\(\dfrac{B_a}{B_b}=\dfrac{\dfrac{\mu (6n)i}{L}}{\dfrac{\mu n i}{L}}\\\\\dfrac{B_a}{B_b}=6\)

Therefore, the correct answer is C. 6.

Answer:

From far away, Saturn looks like it has seven large rings. Each large ring is named for a letter of the alphabet. The rings were named in the order they were discovered.

Answer: It should be (C.) Rachel has a greater power output than Madison

Explanation: The reason of my Answer is because Rachel completed her job of bringing her box to the fourth floor faster than Madison

Answer:

c

Explanation:

because Rachel is faster

Answer:

neither A nor B

Explanation:

There are a lot of reasons, quite handful of them. About why scientists repeat experiments.

They do so sometimes to persistently verify the results they have gotten. Another reason is so as to be able to study and improve them in other ways.

This is just 2 of the very many reasons why scientists repeat experiments. Remember the popular saying, that practice makes perfect? yeah, that's just it

I hope you understand. Thanks

Answer:

Centripetal acceleration = 83.77m/s²

Explanation:

Given the following data;

Radius, r = 0.13m

Velocity, v = 3.3m/s

To find centripetal acceleration;

Centripetal acceleration is given by the formula;

\( Acceleration, a = \frac {v^{2}}{r}\)

Substituting into the equation, we have;

\( Centripetal \; acceleration, a = \frac {3.3^{2}}{0.13}\)

\( Centripetal \; acceleration, a = \frac {10.89}{0.13}\)

Centripetal acceleration = 83.77m/s²

Therefore, the centripetal acceleration of the edge of the disc is 83.77 m/s².

Answer:

the answer is 84

Explanation:

Answer:

wind energy is safe

Explanation:

because it just is

Answer:

Wind energy isn't perfect, but better than the alternatives. There is a risk of falling off a turbine in maitenence and there are instances where birds fly into the blades, however there are far more casualties as a result of coal and other fossil fuel extraction.

Explanation:

The IDEAL mechanical advantage of this ramp is (25m / 5m) = 5 .

But it's only giving you a real MA of (4500N/1000N) = 4.5 .

The friction between the crate and the surface of the ramp is robbing some of the work you do as you slide the crate up the ramp, which degrades the mechanical advantage.

The velocity of the stuntman, once he has left the cannon is 5 m/s.

The right option is O A. 5 m/s

The Kinetic energy of the stuntman is equal to the elastic potential energy of the spring.

This is the ratio of displacement to time. The S.I unit of Velocity is m/s.  The velocity of the stuntman can be calculated using the formula below.

⇒ Formula:

⇒ Where:

⇒ Make v the subject of the equation

From the question,

⇒ Given:

⇒ Substitute these values into equation 2

Hence, The velocity of the stuntman, once he has left the cannon is 5 m/s.

The right option is O A. 5 m/s

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Answer:

the particle is at coordinates (18,15/2)

Explanation:

To find the acceleration of the particle, we can use the formula for velocity: v = v0 + at, where v0 is the initial velocity, a is the acceleration, and t is the time. Since we know the initial and final velocities, as well as the time interval, we can solve for the acceleration:

a = (v - v0)/t = [(9i + 7j) - (3i - 2j)]/3 = (6i + 9j)/3 = 2i + 3j

So the acceleration of the particle is a = 2i + 3j m/s².

To find the coordinates of the particle at t=3s, we can use the formula for position: r = r0 + v0t + 1/2at², where r0 is the initial position. Since the particle starts at the origin, r0 = 0. Plugging in the values we have:

r = 0 + (3i - 2j)(3) + 1/2(2i + 3j)(3)² = 9i - 6j + 9i + 27/2 j = 18i + 15/2 j

We can use the kinematic equations of motion to solve this problem.

Let the acceleration of the particle be a = axî + ayj.

(a) Using the equation of motion v = u + at, where u is the initial velocity:

f = v = u + at

Substituting the given values, we get:

(91+7j) = (3î-2j) + a(3î + 3j)

Equating the real and imaginary parts, we get:

91 = 3a + 3a (coefficients of î are equated)

7 = -2a + 3a (coefficients of j are equated)

Solving these equations simultaneously, we get:

a = î(23/6) + j(1/2)

So the acceleration of the particle is a = (23/6)î + (1/2)j.

(b) Using the equation of motion s = ut + (1/2)at^2, where s is the displacement and u is the initial velocity:

At t = 3s, the displacement of the particle is:

s = ut + (1/2)at^2

Substituting the given values, we get:

s = (3î-2j)(3) + (1/2)(23/6)î(3)^2 + (1/2)(1/2)j(3)^2

Simplifying, we get:

s = 9î + (17/2)j

So the coordinates of the particle at t=3s are (9, 17/2).

An insulating vessel contains 80 g of a block of ice at -12 °C. If 450 g of water at 60 °C is added to the ice in the vessel, Energy required for complete melting = \(80 g X (3.33 X 10^3 J/kg)\).

To determine whether the ice will soften absolutely and calculate the final temperature of the system, we need to do not forget the strength transferred among the ice and water at some stage in the procedure.

(i) To decide if the ice will melt completely, we need to examine the energy won by using the ice to the electricity required for complete melting.

Energy received by way of the ice = mass of ice × particular heat capacity of ice × alternate in temperature

Energy won by using the ice = eighty g × 2100 J/(kg·°C) × (final temperature - (-12°C))

Energy required for complete melting = mass of ice × latent warmth of fusion of ice

Energy required for whole melting = 80 g × (3.33 × 10^3 J/kg)

If the strength received via the ice is extra than or same to the electricity required for entire melting, the ice will soften completely.

(ii) To calculate the very last temperature of the gadget, we want to keep in mind the power transferred between the ice and water.

Energy won by the water = mass of water × unique heat ability of water × trade in temperature

Energy received by using the water = 450 g × 4200 J/(kg·°C) × (final temperature - 60°C)

Since electricity is conserved inside the machine, the power gained by means of the ice and water need to be identical:

Energy gained through the ice = Energy won by the water

Using the equations above, we will installation the following equation:

80 g × 2100 J/(kg·°C) × (very last temperature - (-12°C)) = 450 g × 4200 J/(kg·°C) × (very last temperature - 60°C)

Thus, this the final temperature of the system.

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1.) To protect buildings, structures and people from lightning strikes ; 2.)  Using materials that are good conductors of electricity ;3.)Provides low-resistance path for any static electricity ; 4.)Dryer sheets, damp towel or washcloth to dryer, metal dryer ball or other anti-static device; 5.)Anti-static mats, humidifiers, anti-static wrist straps and cleaning carpets.

1. Function of lightning rod is to protect buildings, structures, and people from lightning strikes. It works by providing a low-resistance path for lightning current to follow, directing it safely into ground.

2. Charge build-up on airplanes is reduced by using materials that are good conductors of electricity, such as aluminum, to help distribute any charge that builds up across the surface of the airplane.

3. Ground strap is a necessary safety feature when transferring fuel because it provides low-resistance path for any static electricity that may build up during transfer process.

4. Three methods for reducing charge build-up in clothes dryers are as :

Using dryer sheets or fabric softeners, which can help to dissipate any static charge that may build up on clothes during drying process.

Adding damp towel or washcloth to dryer, which can help to increase humidity inside the dryer and reduce the likelihood of static build-up.

Using metal dryer ball or other anti-static device, which can help to neutralize any charge that may build up on clothes.

5. The four methods for reducing charge build-up in computer room with carpet are as follows:

Using anti-static mats or flooring, which can help to dissipate any static charge that may build up on carpet.

Installing humidifiers, which can help to increase the humidity in room and reduce the likelihood of static build-up.

Using anti-static wrist straps or other grounding devices when handling sensitive electronic equipment, to help discharge any static electricity that may have built up on body.

Regularly cleaning carpet with a vacuum cleaner that is equipped with anti-static brush or hose, which can help to remove any static charge that may have built up on carpet fibers.

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Explanation:

We can use the Lorentz transformation to calculate the distance to the star system as measured by an observer in the rocket ship.

The Lorentz transformation for length is:

L = L0 / sqrt(1 - v^2/c^2)

where L0 is the proper length (the distance as measured by an observer at rest with respect to the distance), v is the velocity of the rocket ship, c is the speed of light, and L is the length as measured by the observer in the rocket ship.

In this case, L0 = 38 trillion km, v = 0.68c, and c = 299,792.458 km/s.

Plugging these values into the equation, we get:

L = 38 trillion km / sqrt(1 - (0.68c)^2/c^2)

= 38 trillion km / sqrt(1 - 0.68^2)

= 38 trillion km / 0.748331

= 50.8 trillion km

Therefore, the distance to the star system as measured by an observer in the rocket ship is approximately 50.8 trillion km.

When a mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth), the period of revolution of the given satellite is approximately 8207 seconds or 2.28 hours.

The period of revolution of a satellite with mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth) can be determined by using Kepler's third law which relates the period of revolution of a satellite to the average radius of its orbit.

Kepler's third law states that the square of the period of revolution of a satellite is proportional to the cube of the average radius of its orbit.

Mathematically, the law can be expressed as: T² = (4π² / GM) × R³Where T is the period of revolution, G is the gravitational constant, M is the mass of the earth, and R is the average radius of the orbit of the satellite.

To find the period of revolution of the given satellite, we can substitute the given values in the equation: R = 7480 km + 6370 km = 13850 kmM = 5.97 × 10²⁴ kgG = 6.67 × 10⁻¹¹ Nm²/kg²T² = (4π² / GM) × R³T² = (4π² / (6.67 × 10⁻¹¹ × 5.97 × 10²⁴)) × (13850 × 10³)³T² = 6.7182 × 10¹⁴ seconds²

Taking the square root of both sides, we get:T = 8.2079 × 10³ seconds

Therefore, the period of revolution of the given satellite is approximately 8207 seconds or 2.28 hours.

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n unit vector notation, -22j is the torque about the origin on a particle located at coordinate (o, -4.0m, 3.0m)


Torque is defined as the force that can cause an object to rotate along an axis is measured as torque. Estimate the angle between the vector connecting the force's application point and the pivot point and the direction of the applied force. You may calculate the torque by multiplying r by F and sin.

T=R (distance) x F (Force)

R=-4j+3k

F=2J

Hence, t=  R x F vector product

=(-4j+3k)x2j

=-4x2x(y x J)

=+3x2y(k x r)

=-8x(-k)+6j

=(6j+8k) nm

b) F^2=2J+4K

Hence, t=r x f^2

=(-4j+3k)x(2j+4k)

=0-16( J x k)+6(K x J)+0

=-16j-6j

=-22j  

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Answer:

here is answer!

Explanation:

Question 1:

Light bends when it transitions from air to glass due to differences in refractive indices. It follows an incident path in air, refracts at the air-glass boundary, and continues through the glass as a transmitted ray. Total internal reflection may occur if the angle of incidence is large enough.

Question 2:

Brightness in the wave model of light is determined by the amplitude and intensity of the light waves. Higher amplitudes and intensities correspond to brighter light. When multiple light waves overlap, their amplitudes add up, resulting in increased brightness

Explanation:

step 1. since the magnification is negative this means the object is real and is farther away from the lens than the focal point

step 2. 1/f = 1/o + 1/i where f is the focal length, o is the object distance from the lens and i is the image distance from the lens

step 3. 1/12 = 1/o + 1/i, -i/o = -2.5 (these are our 2 equations or system

step 4. 1/12 = 1/o + 1/2.5o

step 5. o = 12 + 12/2.5 = 16.8cm

step 6. i = 2.5o = 2 5(16) = 42cm

N₂O: Nitrous oxide

oxygen