QUESTION 5
Insomnia is a sleep disorder most characterized by
a. chronic problems in getting adequate sleep.
b. frequent, reflexive gasping for air.
C. potentially troublesome dream enactments.
d. sudden and irresistible onsets of sleep during normal waking periods.
N

Answer:

0.484 m/s²

Explanation:

To solve this question, we would apply the formula for calculating gravitational acceleration at any distance.

g = GM/r², where

g = acceleration due to gravity

G = gravitational constant

r = radius of the meteoroid

Radius of the earth is given as 6371 km

The meteoroid is located at a distance 3.5 times the radius of the earth, so

r = R + 3.5R = 4.5R

r = 28670 km

Mass of the earth is, 5.97*10^24 kg

Now, we proceed to substitute our values into the earlier equation

g = GM/r²

g = (6.67*10^-11 * 5.97*10^24) / 28670²

g = 398.2*10^12 / 822*10^12

g = 0.484 m/s²

Thus, it's acceleration due to earth's gravitation is 0.484 m/s²

By supplying the fundamental knowledge required to create new instruments and techniques for medical use, physics enhances our quality of life

From can openers, light bulbs, and mobile phones to muscles, lungs, and brains; from paintings, piccolos, and pirouettes to cameras, vehicles, and cathedrals; from earthquakes, tsunamis, and storms to quarks, DNA, and black holes, physics aids us in understanding the workings of the world around us.

The science of physics is the most fundamental and has many applications in contemporary technology. Because it makes it possible for smartphones, computers, televisions, watches, and many other modern technologies to function automatically, physics is crucial to modern technology.

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Answer:

A. smaller arteries

Explanation:

A. because it makes no sence.

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Answer:

P = VI

Explanation:

the power is equal to the current × voltage

Answer:

P = V • I

Explanation:

Power = Voltage • Current

Answer:

19.5 m/s

87.8 m

Explanation:

The acceleration of block one is:

∑F = ma

-m₁gμ = m₁a

a = -gμ

a = -(9.8 m/s²) (0.22)

a = -2.16 m/s²

The velocity of block one just before the collision is:

v² = v₀² + 2aΔx

v² = (8.25 m/s)² + 2 (-2.16 m/s²) (2.3 m)

v = 7.63 m/s

Momentum is conserved, so the velocity of block two just after the collision is:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

m₁u₁ = m₂v₂

(18.5 kg) (7.63 m/s) = (7.25 kg) v

v = 19.5 m/s

The acceleration of block two is also -2.16 m/s², so the distance is:

v² = v₀² + 2aΔx

(0 m/s)² = (19.5 m/s)² + 2 (-2.16 m/s²) Δx

Δx = 87.8 m

The velocity of block 2 and the distance traveled by it prior to being at rest post-collision are 19.5 m/s and 87.8 m. Check the calculations below:

Given that,

\(m_{1}\) = 18.5 kg

d = 2.3m

To find,

Acceleration of block 1:

∑\(F = ma\)

⇒ -m₁gμ = m₁a

⇒ a = -gμ

⇒ a \(= -(9.8 m/s^2) (0.22)\)

∵ a \(= -2.16 m/s^2\)

Now,

To determine the velocity of block one prior to the collision:

We know,

The initial velocity of block 1 = 8.25 m/s

⇒ \(v^2 = v_{o}^2 + 2\)aΔx

⇒ \(v^2 = (8.25 m/s)^2 + 2 (-2.16 m/s^2) (2.3 m)\)

∵ \(v = 7.63 m/s\)

We also know,

\(m_{2}\) = 7.25 kg

Now,

The velocity of block 2 post collision:

⇒ \(m_{1} u_{1} + m_{1} u_{1} = m_{1} v_{1} + m_{2} v_{2}\)post-collision

Through this,

⇒ \((18.5 kg) (7.63 m/s) = (7.25 kg) v\)

∵\(v = 19.5 m/s\)

The distance can be found through:

⇒ \(v^2 = v_{o} ^{2} + 2\)\(a\)Δ\(x\)

⇒ \((0 m/s)^2 = (19.5 m/s)^2 + 2 (-2.16 m/s^2)\)Δ\(x\)

∵ Δ\(x = 87.8 m\)

Thus, 19.5 m/s and 87.8 m are the correct answers.

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Answer:

Force = Mass × Acceleration

\({ \tt{force = 2250 \times 4.3}} \\ = { \tt{9675 \: newtons}}\)

Explanation:

Yes, there are differences in the shapes of position-time graphs for uniform acceleration and uniform deceleration in different directions. Let's consider each case separately:\(\hrulefill\)

(1) - Uniform acceleration towards the positive direction:

In this case, the object is moving in the positive direction with a constant acceleration. The displacement-time graph will typically be a curve that starts from an initial position and shows a steady increase in displacement over time. The shape of the graph will depend on the specific acceleration value.

(2) - Uniform acceleration towards the negative direction:

In this case, the object is moving in the negative direction with a constant acceleration. The displacement-time graph will also be a curve, but it will show a steady decrease in displacement over time.

(3) - Uniform deceleration towards the positive direction:

In this case, the object is initially moving in the positive direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a positive slope and gradually levels off.

(4) - Uniform deceleration towards the negative direction:

In this case, the object is initially moving in the negative direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a negative slope and gradually levels off.

Answer:

The answer is "\(15.38\%\)"

Explanation:

Background\(= 13 \ mv\\\\\)

corrected signal\(= 91 \ mv-13\ mv= 78\ mv\\\\\)

with attenuator\(=25\ mv-13\ mv= 12\ mv\\\\\)

\(\to \frac{p_t}{p_i}=\frac{12}{78}\times 100= 15.38\%\)

Answer:

c

Explanation:

In the parallel combination, the current through R3 is 3 A. In the series combination, the current through R3 is 0.75 A.

To determine the current through resistor R3 in both the parallel and series combinations, we need to apply Ohm's Law and the appropriate formulas for calculating total resistance and current in each configuration.

First, let's consider the parallel combination:

In a parallel combination, the voltage across each resistor is the same. Therefore, the voltage across R3 is also 90 V.

Using Ohm's Law (V = I × R), we can calculate the current flowing through R3 in the parallel combination:

I_parallel = V / R3

= 90 V / 30 Ω

= 3 A

So, in the parallel combination, the current through R3 is 3 A.

Now, let's consider the series combination:

In a series combination, the total resistance is the sum of the individual resistances:

R_total = R1 + R2 + R3

= 60 Ω + 30 Ω + 30 Ω

= 120 Ω

To find the current through the series combination, we can use Ohm's Law:

I_series = V / R_total

= 90 V / 120 Ω

= 0.75 A

Therefore, in the series combination, the current through R3 is 0.75 A.

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Note the complete questions is User

90 V R₁=60 R2=  30, R3 = 30

Based on the circuit above, what would be the current through the R3 resistor in parallel and in series combinantion.

Explanation:

Speed - The rate at which something moves

Velocity - The speed of something in a specific direction

Velocity is kind of a specific type of speed.

Answer: b the energy of light...

Explanation:

Answer:

Magdeburg hemispheres are two half-spheres of equal size. Placing them together traps air between them. This air is merely trapped, and not compressed, so the pressure inside is the same as the pressure of the atmosphere outside the spheres. The spheres thus pull apart with nearly no resistance.

The Magdeburg hemispheres are a pair of large copper hemispheres, with mating rims. They were used to demonstrate the power of atmospheric pressure. When the rims were sealed with grease and the air was pumped out, the sphere contained a vacuum and could not be pulled apart by teams of horses.

Changing the amount of a substance changes its mass or volume but won't change its density.

This is used to describe how compact a material is and it is also the mass per unit volume of a material substance with its S.I unit being  grams per cubic centimetre.

We should note that hanging the amount of a substance changes its mass or volume .However ,if the amount of matter is increased without changing the volume, then the density increases which is therefore the reason why it was chosen as the correct choice.

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The given problem can be exemplified in the following diagram:

To determine the extension force we will use the definition of pressure:

Where "F" is the force, and "A" is the area. To determine the area we will use the following equation:

Where "D" is the diameter. The force acts over the area of the 10 inches diameter alone, therefore we don't need to have into account the area of the rod. Replacing the value of the diameter we get:

Solving the operation:

Replacing in the formula for the pressure we get:

Since we are required to determine the force, we will multiply both sides by the area:

Replacing the given value of the pressure we get:

Solving the operations we get:

Therefore, the extension force is 107756.62 lbf.

Answer: No.

Explanation: Light exists in 3+1 dimensional space (3 space, 1 time).

A normal force is a force applied perpendicular to a surface on an object in contact with it. The weight is the gravitational force imposed on an object, and it is equal to the mass multiplied by the acceleration due to gravity.

When an object is put on a scale at rest on a level surface, the normal force equals the weight. In this instance, the normal force acting upwards from the scale on the object is equal to the weight acting downwards.

Here are two instances of normal forces that are not equal to weight:

When a person stands on an inclined plane or ramp, the normal force applied by the plane is less than the person's weight, because some of the weight is resolved parallel to the plane, causing the person to slide down if enough friction exists.

The normal force exerted by the air or other medium on a person in free fall is zero, while their weight due to gravity stays constant.

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Answer:

Yes

Explanation:

Accerelation is measured by change in velocity. So naturally, if an object is slowing down, its velocity is decreasing so acceleration is negative. If it is speeding up velocity is increasing so positive acceleration.

(Velocity final - Velocity initial)/t

Note that this does not apply only to gravity, but to all linear accelerations

(a)

To find the current flowing through each resistor, we can use Ohm's Law, which states that the current (I) through a resistor is equal to the voltage (V) across the resistor divided by the resistance (R) of the resistor:

I = V / R

As there is only one path for the current to go in the series circuit, the current flowing through both resistors is the same.

We can determine the current flowing through the circuit using the values provided in the problem by doing the following:

Total resistance (Rt) = 47 Ώ + 28 Ώ = 75 Ώ

Total current (It) = V / Rt = 12 V / 75 Ώ = 0.16 A

Therefore, the current flowing through each resistor is 0.16 A.

(b)

We may apply Ohm's Law once more to determine the voltage difference between each resistor, but this time we will solve for the voltage:  

V = I x R              

The voltage difference across each resistor can be determined using the values provided in the problem as follows:

Voltage across 47 Ώ resistor = 0.16 A x 47 Ώ = 7.52 V

Voltage across 28 Ώ resistor = 0.16 A x 28 Ώ = 4.48 V

Therefore, the voltage difference across the 47 Ώ resistor is 7.52 V, and the voltage difference across the 28 Ώ resistor is 4.48 V.

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Answer:

Pure substance are made of only one kind of particles and fixed constant.

Explanation:

Pure substance are combined in fixed ratio into separate by chemical methods into a physical and chemical methods.

Answer:

A compound is a pure substance composed of two or more different atoms chemically bonded to one another. A compound can be destroyed by chemical means. It might be broken down into simpler compounds, into its elements or a combination of the two

Explanation:

Answer:

Answer B is correct: The wave's energy decreases.

Explanation:

When some of the wave's energy is absorbed by the new medium, the wave's energy decreases. Hence, option (B) is correct.

A wave is an energetic disturbance in a medium that doesn't include any net particle motion. Elastic deformation, a change in pressure, an electric or magnetic intensity, an electric potential, or a change in temperature are a few examples.

When light wave transmits from one medium to another medium, some amount of energy of the light wave  is absorbed by the new medium. Then the transmitted light wave travels with remaining energy. So, the energy of the wave decreases in this case. Hence, option(B) is correct.

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Answer: 317.52

Explanation:

I'm just better

Some of the Sun's energy is absorbed, scattered, or reflected as it travels through the atmosphere to the surface of the Earth by a variety of atmospheric constituents, including gases, aerosols, clouds, and the Earth's surface.

50% of the heat energy from the Sun can reach Earth's surface thanks to the atmosphere. The Sun's energy is reflected back into space at a rate of 30%. The atmosphere greenhouse gases, such as carbon dioxide, water vapour, and methane, absorb 20% of the remaining solar energy.

Ozone (O3) in the upper atmosphere absorbs a substantial amount of the Sun's ultraviolet (high-energy, shortwave) light (the stratosphere). The Earth system does not become hotter as a result of solar radiation that Earth's surface or atmosphere reflect back into space. Heat is produced as a result of absorbed radiation.

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In mathematics, an algebraic expression is an expression built up from integer constants, variables, and the algebraic operations. For example, 3x² − 2xy + c is an algebraic expression.

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Protons, neutrons, and electrons are the three main subatomic particles that make up atoms.

An oxygen atom has 8 protons, 8 electrons, and its number of neutrons may vary depending on the isotope of oxygen. The more frequently encountered isotope of oxygen is oxygen-16, with 8 neutrons.

The element with 13 protons is aluminum (Al). To find the mass number, we add the number of protons and neutrons in the nucleus. Therefore, the mass number of this aluminum isotope would be 13 + 14 = 27.

If an atom has 7 electrons, it must be nitrogen (N), which has an atomic number of 7.

Number of neutrons = Mass number - Atomic number

Thus, we obtain the number of neutrons by the equation: 14 - 7 = 7

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