Question 4 (1 point)
Having the ability to play or stay active longer without getting tired explains which
Health-Related Fitness Component?

Answer: \(0.00680\ m^3\)

Explanation:

Given

The weight of the object, when submerged in the water is \(980\ N\)

When it is submerged in the bromine liquid, it weighs \(840\ N\)

Suppose,

\(\rho=\text{Density of object}\\\rho_w=\text{Density of water}\\\rho_b=\text{Density of bromine}\\V=\text{Volume of the object}\)

for water,

\(\Rightarrow V(\rho -\rho_w)g=980\quad \ldots(i)\)

For bromine

\(\Rightarrow V(\rho-\rho_b)g=840\quad \ldots(ii)\)

Divide (i) and (ii)

\(\Rightarrow \dfrac{\rho-1000}{\rho-3100}=\dfrac{980}{840}\\\\\Rightarrow 840\rho -840\times 1000=980\rho-980\times 3100\\\\\Rightarrow 140\rho=(3038-840)\cdot 1000\\\\\Rightarrow \rho=15,700\ kg/m^3\)

Put the density value in equation (i)

\(\Rightarrow V(15,700-1000)\cdot 9.8=980\\\\\Rightarrow V=\dfrac{100}{14,700}\\\\\Rightarrow V=0.00680\ m^3\)

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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Answer:

Number 19

10 x 7.2

72N

Explanation:

20.

1.66 x 7.2

11.9

Which is approximately

12N

If you follow the arc of the big dipper handle to the next bright star in the sky, you will find Arcturus.

Arcturus is a giant, orange star located in the constellation Bootes and is the brightest star in the northern celestial hemisphere. If you follow the arc of the Big Dipper handle, you will eventually find Arcturus, which is considered one of the most prominent stars in the night sky. It is approximately 36.7 light-years away from Earth and has a luminosity that is approximately 110 times greater than our sun.

Arcturus is a type of star known as a K-type giant, which means it has exhausted the hydrogen fuel in its core and expanded to its current size. This star is also known for its high proper motion, which means it appears to move rapidly across the sky relative to other stars. Arcturus is considered a key star for navigation, as its position in the sky remains relatively constant and can be used as a reference point for astronomers and stargazers alike.

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Your question seems to be missing, but I suppose the question was:

"If you follow the arc of the big dipper handle to the next bright star in the sky, you will find _____."

Answer:

When the cold weather fills hard surfaces with water, it causes it to freeze and expand, causing cracks in the surface.

On one cookie containing 50 calories, you could potentially go approximately 298 meters

Given that one food calorie is equivalent to 4184 joules, we can calculate the total energy in joules contained in the 50 calorie cookie:

50 food calories * 4184 J/calorie = 209,200 joules

Assuming an average efficiency of around 25% (meaning 25% of the energy is effectively used for movement), and a body weight of 70 kilograms, we can use a rough estimation that it takes about 1 joule of energy to move 0.4 meters (based on the energy cost of walking).

Distance = (Energy obtained from the cookie * Efficiency) / (Energy cost per meter * Body weight)

Distance = (209,200 J * 0.25) / (1 J/m * 0.4 m/kg * 70 kg)

Distance ≈ 298 meters

Therefore, on one cookie containing 50 calories, you could potentially go approximately 298 meters

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The time it takes the stone to fall from a height of 7.11 m is 1.2 seconds.

Time can be defined as an ongoing and continuous sequence of events that occur in succession, from past through the present, and to the future.

To calculate the time it takes the stone to drop from an height of 7.11 m, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1 and solve for t.

Hence, the time it takes the stone to fall is 1.2 seconds.

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3500 N is the same amount of force in cord BC as it is in cord AB. The equation of equilibrium Fy=Fabsin(theta)=Fbccos(theta), where theta is the angle between the two cords, may be used to compute the distance y.

The idea of force equilibrium can be used. To balance the weight of the crate (200 kg * 9.8 m/s2 = 1960 N), the force in cord BC (F bc) must be equal to the force in cord AB (3500 N). The idea of mechanical advantage may also be used to determine the distance y, which in this example equals the weight-to-force ratio of the BC cord. As a result, y = (200 kg * 9.8 m/s2) / 3500 N = 0.564 m if we assume that y is the distance from the point of suspension to the container. As a result, the distance y is 0.564 m and the force in cord BC is 3500 N.

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Hooke's Law can be given as follows sometimes:

The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:

F = -kx

Where, F = Restoring force of a spring (Newtons, N)

k = Spring constant (N/m)

x = Displacement of the spring (m)

The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.

Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.

The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.

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A free body diagram is a visual representation of all the forces acting on an object.

A free body diagram is a visual representation of all the forces acting on an object. It is a tool commonly used in physics to help analyze the motion of an object.

In the case of an air cart, the forces acting on the cart might include the force of gravity pulling the cart downward, the normal force of the surface supporting the cart pushing upward, and the force of air resistance acting against the cart as it moves through the air. There may also be other forces at play, depending on the specific situation, such as an applied force from a fan or a motor driving the cart forward.

If there is an extra force causing a discrepancy between your numbers, you would also include this force on the free body diagram, with an arrow representing the magnitude and direction of the force

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The bicyclist is applying more force on the pedals at Time 2. Option C

If we look at the image that have been shown, we can be able to see that the force that is acting have been shows by the arrows that have been used to label the movement of the cyclist in the image that is shown here.

We can see that the forward arrow at the time 2 is seen to be larger than the forward arrow that is shown for time 1. The implication of this is that the cyclist is cycling harder and applying more force at time 2 than at time 1.

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The slope of a line perpendicular to y = 1/8x + 2 is -8.

The equation of a line in point-slope form is y - y1 = m (x - x1), where m is the slope and (x1, y1) is a point on the line.

The point-slope form of a line is given by y - y1 = m (x - x1), where (x1, y1) is a point on the line and m is the slope of the line.

In this equation, y1 and x1 are the coordinates of a point on the line, and m is the slope of the line.

So, given a point on the line, and the slope, you can use this form to write the equation of the line.

So, the equation of the line through point (1, -5) and perpendicular to y = 1/8x + 2 is y + 5 = -8(x - 1) => y = -8x + 13.

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Explanation:

wavelength=3.42m

velocity=330m/s

T=?

v=f×wavelength

f=330÷3.42

f=96.5Hz

T=1/f

=1/96.5

T=0.01s

Explanation:

here, force applied (N) = 345 N

or, mass of scooter (m) = 70 kg

now, acceleration (a) = ?

we know, force = mass × acceleration

or, 345 = 70 × acceleration

or, acceleration = 345/70

therefore, acceleration = 4.9 m/s2 (meter/second square)

A 7 kg mass moving across the table at an acceleration of 25 m\(/s^2\)requires a force of 175 N.

To determine the force required to cause the acceleration of a 7 kg mass moving across the table at 25\(m/s^2\), we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration.

Given:

Mass (m) = 7 kg

Acceleration (a) = 25 \(m/s^2\)

We can substitute these values into the equation:

Force (F) = mass (m) * acceleration (a)

F = 7 kg * 25 \(m/s^2\)

F = 175 kg·\(m/s^2\)

Therefore, the force required to cause the acceleration of the 7 kg mass is 175 kg·\(m/s^2\).

To understand the calculation, we need to know that force is a measure of how much an object accelerates when a certain amount of mass is acted upon by that force. In this case, the mass of the object is 7 kg, and it is experiencing an acceleration of 25\(m/s^2\).

By multiplying the mass and acceleration together, we find that the force required is 175 kg·\(m/s^2\). This unit, also known as a Newton (N), represents the force required to accelerate a 1 kg mass at a rate of 1 \(m/s^2\)

In summary, the force required to cause the acceleration of the 7 kg mass across the table at 25 \(m/s^2\) is determined to be 175 kg·\(m/s^2\). This calculation follows Newton's second law of motion and shows the relationship between mass, acceleration, and force.

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Answer:

1.0 volts

Explanation:

Given that:

The potential difference between the plate V = 10 V

C = 0.160 pF = 0.160 × 10⁻¹² F

The charge on the capacitor

Q = CV

Q = 0.160 × 10⁻¹² × 10

Q = 1.6 × 10⁻¹² C

It implies that the positive plate of capacitor has +1.6 × 10⁻¹² C charge while the negative plate has -1.6 × 10⁻¹² C

The number of excess electrons on the negative plate is:

\(n = \dfrac{q}{e}\)

\(n = \dfrac{-1.6\times 10^{-12}}{-1.6\times 10^{-19}}\)

\(n = 1.0 \times 10^7\)

Thus, electron deficiency on the positive plate is \(1.0 \times 10^7\)

The net negative charge that moves towards the positive plate is :

q = number of electrons moved × e

\(q = 1\times 10^6 \times (-1.6 \times 10^{-19})\)

\(q = -1.6 \times 10^{-13} \ C\)

Now, the net charge on the positive plate is:

\(q_{net} = q +q' \\ \\ q_{net} = (1.6 \times 10^{-12}) + (-1.6 \times 10^{-13})\)

\(q_{net} =1.44 \times 10^{-12} \ C\)

The potential difference between the plate;

\(V_{new} = \dfrac{q_{net} }{c}\)

\(V_{new} = \dfrac{1.44 \times 10^{-12} }{0.16 \times 10^{-12}}\)

\(V_{new} = 9.0 V\)

The reduction in potential difference

\(\Delta V = V - V_{new}\)

\(\Delta V = 10 - 9.0\)

\(\mathbf{\Delta V = 1.0 \ volts}\)

Answer:

Tension

Explanation:

(a) The work done by the donkey on the cart is 59,721.9 J.

(b) The work done by the force of gravity on the cart is -48,434.87 J.

(c) The work done on the cart by friction during this time is 11,315.12 J.

(a) The work done by the donkey on the cart is calculated as follows;

Wd = Fd cosθ

where;

Wd = 375 N x 163 m x cos(12.3)

Wd = 59,721.9 J

(b) The work done by the force of gravity on the cart is calculated as;

Wg =  Fg x d x cosθ

Where;

θ = 90⁰ + 4.03⁰ = 94.03⁰

Wg = (431 kg x 9.81 m/s²) x 163 m x cos (94.03)

Wg = -48,434.87 J

(c) The work done on the cart by friction during this time is calculated as;

Wf = Ff x d x cosθ

where;

Ff = μmg cosθ

Ff = 0.0165 x 431 kg x 9.81 x cos (4.03)

Ff = 69.59 N

Wf = 69.59 x 163 x cos (4.03)

Wf = 11,315.12 J

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Answer:

\(Va-Vb=168KV\)

Explanation:

From the question we are told that

Two points charge of 4\mu C and 2\mu C

Generally we find the  Va and Vb individually to find there difference

Given a rectangle with two equal sides each,Assume lengths for bot sides

Length L=0.3

Breath B=0.4

Diagonal D=\(\sqrt{0.3^2+0.4^2} =0.5\)

at  opposite sides

Mathematically Va can represented as

\(Va =k(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )\)

\(Va =9*10^9(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )\)

\(Va =9*10^9(0.00001333333-0.000004} )\)

\(Va =84000V\)

\(Va =84KV\)

Mathematically Vb is  represented as

\(Va =k(\frac{-4*10^_-_6}{0.3} +\frac{2*10^_-_6}{0.5} )\)

\(Va =9*10^9(\frac{-4*10^_-_6}{0.3} +\frac{+2*10^_-_6}{0.5} )\)

\(Va =9*10^9(-0.00001333333+0.000004} )\)

\(Va =-84000V\)

\(Va =-84KV\)

Therefore

\(Va-Vb=84-(-84)\\Va-Vb=84+84\\Va-Vb=168KV\)

Answer:

\(\huge\underline\color{green}{Answer \: ☘}\)

In the case of a water wave in the ocean, the medium through which the wave travels is the ocean water. In the case of a sound wave moving from the church choir to the pews, the medium through which the sound wave travels is the air in the room.

hope helpful~

\({\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\\)

\(\:\:\:\:\bullet\:\:\:\sf{Focal\:length=10\:cm}\)

\(\:\:\:\:\bullet\:\:\:\sf{Object \ distance = -15\:cm}\)

\(\\\)

\({\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}} \\ \\\)

\(\:\:\:\:\bullet\:\:\:\sf{Nature \: of \:the\:image}\)

\(\\\)

\({\mathfrak{\underline{\purple{\:\:\: Solution:-\:\:\:}}}} \\ \\\)

\(\\\)

\(\dashrightarrow\:\: {\boxed{\sf{\dfrac{1}{u} + \dfrac{1}{v} = \dfrac{1}{f}}}}\)

\(\\\)

\(\dashrightarrow\:\: \sf{\dfrac{1}{v}-\dfrac{1}{-15}=\dfrac{1}{10}}\)

\(\\\)

\(\dashrightarrow\:\: \sf{\dfrac{1}{v}+\dfrac{1}{15}=\dfrac{1}{10}}\)

\(\\\)

\(\dashrightarrow\:\: \sf{\dfrac{1}{v} = \dfrac{1}{10} - \dfrac{1}{15}}\)

\(\\\)

\(\dashrightarrow\:\: \sf{\dfrac{1}{v} = \dfrac{1}{30}}\)

\(\\\)

\(\dashrightarrow\:\: \sf{ v = 30 \ cm}\)

\(\\\)

\(\\\)

\(\dashrightarrow\:\: \sf{ m = \dfrac{-30}{-15}}\)

\(\\\)

\(\dashrightarrow\:\: \sf{m = -2}\)

\(\\\)

\(\:\:\:\:\star\:\:\:\sf{Image \ distance = 30 \ cm}\)

\(\:\:\:\:\star\:\:\:\sf{Nature = Real \ \& \ inverted}\)

Option A) 3.9 km is the correct answer. the magnitude of Rhea's displacement vector is approximately 3.92 km.

In order to find out the magnitude of Rhea's displacement vector, we have to add up all of the displacement vectors.

Then we can use the Pythagorean theorem to calculate the magnitude of the resultant vector.

Since Rhea is first driving north for 2.4 km and then west for 3.1 km, we can represent her displacement vectors as follows: Δx = 0 km and Δy = 2.4 km for the first vector, and Δx = -3.1 km and Δy = 0 km for the second vector.

We can then add these vectors together by adding their components: Δx = 0 km + (-3.1 km) = -3.1 km and Δy = 2.4 km + 0 km = 2.4 km.

This gives us a resultant vector of -3.1 km east and 2.4 km north.

Using the Pythagorean theorem, we can find the magnitude of this vector: \(\sqrt{(\(-3.1 km)^{2} + (2.4 km)^{2} ) } = \sqrt{(9.61 + 5.76) km^{2} } = \sqrt{15.37 km^{2} } \approx 3.92 km.\)

Therefore, the magnitude of Rhea's displacement vector is approximately 3.92 km.

Therefore, option A) 3.9 km is the correct answer.

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Answer:

d. such that it never crosses the axis.

Explanation:

A convex lens is type of converging lens. When parallel rays of light pass through a convex lens, the rays which are refracted converge at the principal focus. Focal length is the distance between the principal focus and the centre of the lens.

A light ray, traveling parallel to the axis of a convex thin lens, strikes the lens near its midpoint. After traveling through the lens, this ray emerges traveling obliquely to the axis of the lens such that it never crosses the axis.

Answer:

12

Explanation:

the numbers are swapped so by conclusionn it is 12

The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.

1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).

2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.

3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.

4. However, the given equation does not explicitly mention resistance.

5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).

6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.

7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).

8. Therefore, V = VR + VL.

9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.

10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.

The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.

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Answer:

zeros between nonzero numbers

nonzero numbers

zeros to the right of both the decimal point and a nonzero number

Explanation: edge 2020

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Answer:

Mb²/2

Explanation:

Pls see attached file

The period of oscillation of the system nearest to three decimal places

= 1.092 seconds

The period of an oscillation occurring in a system is the time taken to complete one cycle.

The formula that is used to calculate the period of oscillation (T) is

                = 2π√\(\frac{l}{g}\)

But,

π = 3.14159 (constant)

g= 10m/s² (acceleration due to gravity)

l = 0.302 m

Therefore T = 2 × 3.14159 × √\(\frac{0.302}{10}\)

                    = 6.28318 x √0.0302

                    = 6.28318 x 0.17378

                    = 1.09189s

                    = 1.092 seconds ( to the nearest three decimal places)

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