Question 1 of 15

All digits shown on the measuring device, plus one estimated digit, are

considered

Answer here

SUBMIT

Scientific theories are the results of many experiments over a long period of time.

Scientific theories are explanations that have been developed through extensive experimentation and observation over a period of time. They are supported by a large body of evidence from multiple sources and have been subjected to rigorous testing and scrutiny by the scientific community. Scientific theories are not based on a single experiment but rather on a vast accumulation of knowledge and data. They provide a framework for understanding the natural world and can help predict future observations and experiments. Scientific theories are also subject to change or revision if new evidence is discovered that contradicts or expands upon the existing theory. The development of scientific theories is a collaborative effort among scientists from different disciplines, and the peer-review process is used to ensure that scientific theories are reliable and accurate representations of reality. Scientific theories have been used to make significant advancements in fields such as medicine, engineering, and physics, and they continue to play a critical role in advancing our understanding of the world.

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Answer:

D.  instrusive igneous ​

Explanation:

Answer: it’s intrusive igneous

Explanation:

I got it right.

Answer: The period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m is 5.73 sec.

Explanation:

Given: Mass = 5 kg

Spring constant = 6 N/m

Formula used to calculate period is as follows.

\(T = 2 \pi \sqrt\frac{m}{k}\)

where,

T = period

m = mass

k = spring constant

Substitute the values into above formula as follows.

\(T = 2 \pi \sqrt\frac{m}{k}\\= 2 \times 3.14 \times \sqrt\frac{5}{6}\\= 5.73 s\)

Thus, we can conclude that the period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m is 5.73 sec.

The right sphere will acquire an equal and opposite net positive charge to balance the negative charge on the left sphere.

Since the left sphere is attracted to the positively charged rod, it means that the left sphere acquires a temporary negative charge due to induction.

The positive charge on the rod repels electrons in the left sphere, causing them to move away from the rod side and accumulate on the opposite side, resulting in a net negative charge on the left sphere.

According to the principle of charge conservation, the net charge on the system must remain zero. Therefore, the right sphere acquires an equal and opposite net positive charge to balance the negative charge on the left sphere.

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Answer:

Explanation:

he modulus of elasticity (E) can be calculated using the formula:Stress = Force / AreaStrain = Change in length / Initial lengthModulus of Elasticity (E) = Stress / StrainWe have the Force = 8000 N, Area = 0.7 m^2, Change in length = 0.002 m and initial length = 5 in = 0.127 mStress = Force / Area = 8000 N / 0.7 m^2 = 11428.57 N/m^2Strain = Change in length / Initial length = 0.002 m / 0.127 m = 0.0157Modulus of elasticity (E) = Stress / Strain = 11428.57 N/m^2 / 0.0157 = 727,279.9 N/m^2So the modulus of elasticity for the material of the bar is 727,279.9 N/m^2This is the ratio of the applied stress to the corresponding strain within the elastic limit, which is a measure of a material's resistance to deformation.

There is decreased pressure on the air molecules as one moves higher and the air is thinner

We know that the air pressure decreases with height. This implies that the air is thinner as you move up to higher altitude. This is the idea behind the use of the phrase; "Thin air".

Now, owing to the fact that there is decreased pressure on the air molecules as one moves higher and the air is thinner, it is much harder to breath until her aunt adjusts to the higher altitude.

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Answer:

The impedance of the inductor is ω L:

This is in parallel wth R giving a resistance of the parallel combination:

1 / Rp = 1 / ω L + 1 / R

Rp = (ω L * R) / (ω L + R)      for the impedance of the parallel combination

Total resistance (impedance) Rt = Rp + R2 = Z

One can use the term impedance to show that the resulting current is not in phase with the resulting voltage    

phase angle φ -    cos φ  = ω L / Rt

V = I Z        shows the relation of voltage and urrent

The resistance of working potential difference of the 6.2 V, 4.5 W lamp is 8.54 ohm. When terminal pd across the battery is 6.2 V, the emf of the battery is 8.01 V.

The opposition that a substance provides to the flow of electric current is referred to as resistance. The uppercase letter R represents it. The ohm is the standard unit of resistance, which is sometimes written as a word and sometimes represented by the uppercase Greek letter omega. Resistance is a measure of an electrical circuit's resistance to current flow. Resistance is measured in ohms, which is represented by the Greek letter omega ().

Here,

r=2.5 ohm

V= 6.2 volts

P=4.5 watt

P=V²/R

R=V²/P

R=6.2*6.2/4.5

R=8.54 ohm that is about 9 ohm.

I=V/R

I=0.726 A

EMF=V+Ir

=6.2+0.726*2.5

=6.20+1.81

=8.01 volts

The resistance of the 6.2 V, 4.5 W lamp at its working potential difference is 8.54 ohm. The emf of the battery when terminal pd across the battery is 6.2 V is 8.01 V.

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Answer:

here

Explanation:

Examples of insulators include plastics, Styrofoam, paper, rubber, glass and dry air.

Examples of conductors include metals, aqueous solutions of salts

Explanation:

Find the time it takes to hit the  bottom....then multiply this time by the horizontal velocity .......

Time to hit bottom :

       d = 1/2 at^2

        9 m  = 1/2 (9.81 m/s^2) (t^2)    shows  t = 1.35 s

Now the horizontal displacement is

      x = rate * time = 24.40 m/s * 1.35 s = 33.1 m

Answer:

To explain it we will use the following figure

Then, if a projectile is launched with the same velocity, the greatest range will be reached when the launch angle is 45° and for angles that sum 90°, the range will be the same. So, the launch angle affect the range of the projectile motion, when it is closer to 45°, the range will be maximum.

While certain types of glass containers may be suitable for short-term storage of vinegar, it is generally recommended to use non-reactive materials, such as plastic or stainless steel, for long-term storage to avoid any potential chemical reactions or corrosion.

Vinegar is an acidic liquid that contains acetic acid. When vinegar comes into contact with certain types of glass, particularly those made of lead or other reactive materials, a chemical reaction can occur. This reaction can lead to the leaching of potentially harmful substances into the vinegar.

Glass containers made from specific types of glass, such as soda-lime glass, are generally safe for storing vinegar.

However, it is important to note that prolonged storage or exposure to vinegar can still cause the glass to corrode over time. This can result in the deterioration of the glass container, potentially leading to breakage or the release of glass fragments.

To avoid any potential issues, it is recommended to use containers made of non-reactive materials, such as food-grade plastic or stainless steel, for long-term storage of vinegar. These materials do not react with the acidic nature of vinegar and do not pose a risk of leaching harmful substances.

Additionally, it is important to store vinegar in a cool, dark place to maintain its quality and prevent spoilage. Exposure to light and heat can degrade the quality of vinegar over time.

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Answe ¡Buenos días! –

#3 ¡Buenas tardes! –

#4 ¡Bienvenid

The two different types of equilibrium discussed in the video are

1. Static equilibrium and dynamic equilibrium

Static equilibrium refers to a state where an object is at rest and the net force acting on it is zero. In other words, the forces acting on the object are balanced, so there is no acceleration. For example, a book lying on a table is in static equilibrium, as the gravitational force pulling it down is balanced by the force of the table pushing it up.

On the other hand, dynamic equilibrium refers to a state where an object is moving with a constant velocity, which means that its acceleration is zero. In this case, the net force acting on the object is also zero, but unlike static equilibrium, the object is in motion. For example, a car driving at a constant speed on a straight road is in dynamic equilibrium.

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The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.

1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).

2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.

3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.

4. However, the given equation does not explicitly mention resistance.

5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).

6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.

7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).

8. Therefore, V = VR + VL.

9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.

10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.

The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.

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The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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Answer:

The answer is 2.5 m/s^2.

Explanation:

Average acceleration is (final velocity - Initial velocity) ÷ time.

(C)

Explanation:

The circle has a radius r = 0.5 m, which means that its circumference C is

\(C = 2\pi r = 2\pi(0.5\:\text{m}) = 3.14\:\text{m}\)

One revolution means that the stopper travels a distance equal to the circumference of the circle so the velocity of the stopper is

\(v = \dfrac{C}{t} =\dfrac{3.14\:\text{m}}{0.2\:\text{s}} = 15.7\:\text{m/s} \approx 16\:\text{m/s}\)

Answer:

The answer is below

Explanation:

a) The location ӯ of the center of mass G of the pendulum is given as:

\(y=\frac{0+(\pi*(0.3\ m) ^2*12kg/m^2*1.8\ m-\pi*(0.1\ m) ^2*12kg/m^2*1.8\ m)+0.75\ m*1.5\ m *3\ kg/m}{(\pi*(0.3\ m) ^2*12kg/m^2-\pi*(0.1\ m) ^2*12kg/m^2)+3\ kg/m^2*0.8\ m+3\ kg/m^2*1.5\ m} \\\\y=0.88\ m\)

b)  the mass moment of inertia about z axis passing the rotation center O is:

\(I_G=\frac{1}{12}*3(0.8)(0.8)^2+ 3(0.8)(0.888)^2-\frac{1}{2}*(12)(\pi)(0.1)^2(0.1)^2 -(12)(\pi)(0.1)^2(1.8-\\0.888)^2+\frac{1}{2}*(12)(\pi)(0.3)^2(0.3)^2 +(12)(\pi)(0.3)^2(1.8-0.888)^2+\frac{1}{12}*3(1.5)(1.5)^2+\\3(1.5)(0.888-0.75)^2\\\\I_G=13.4\ kgm^2\)

c) The mass moment of inertia about z axis passing the rotation center O is:

\(I_o=\frac{1}{12}*3(0.8)(0.8)^2+ \frac{1}{3}* 3(1.5)(1.5)^2+\frac{1}{2}*(12)(\pi)(0.3)^2(0.3)^2 +(12)(\pi)(0.3)^2(1.8)^2-\\\frac{1}{2}*(12)(\pi)(0.1)^2(0.1)^2 -(12)(\pi)(0.1)^2(1.8)^2\\\\I_o=13.4\ kgm^2\)

Answer:

B

Explanation:

The more mass an object has, the more gravity it has.

The statement which correctly explains the weight you would experience on each planet is: B. You would weigh less on planet A because it has less mass than  planet B.

Weight can be defined as the force acting on a body or an object as a result of gravity.

Mathematically, the weight of an object is given by the formula;

\(Weight = mg\)

Where;

Hence, we can deduce that the weight and gravity acting on an object is highly dependent on the mass of an object.

Therefore, the higher the mass in a planet, the higher the gravity existing there.

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Answer:

We can use the equations of rotational motion to solve this problem:

Final angular velocity:

ω = ω0 + αt

where

ω0 = initial angular velocity = 2 rev/s

α = angular acceleration = 0.5 rev/s^2

t = time = 10 s

Plugging in the values, we get:

ω = 2 rev/s + (0.5 rev/s^2)(10 s) = 7 rev/s

Therefore, the final angular velocity is 7 rev/s.

Average angular velocity:

The average angular velocity is given by:

ωavg = (ω0 + ω) / 2

Plugging in the values, we get:

ωavg = (2 rev/s + 7 rev/s) / 2 = 4.5 rev/s

Therefore, the average angular velocity is 4.5 rev/s.

Angular displacement:

θ = θ0 + ω0t + (1/2)αt^2

where

θ0 = initial angular displacement = 0 (since the problem does not specify an initial angular displacement)

Plugging in the values, we get:

θ = (1/2)(0.5 rev/s^2)(10 s)^2 = 25 rev

Therefore, the angular displacement is 25 rev.

The experiment to show the random motion of the particles is the movement of particles in a solution is the simplest representation of motion of particles.

Pick up two glass beakers. Fill one beaker with hot water and the second one with cold water. Add KMnO4 crystals in very small quantities to both. We thus see that KMnO4 particles move faster in hot water than in cold water.

Pick up some iron and  a piece of chalk. We learn that it's quite difficult to work with iron. This leads us to believe that the Forces can affect matter particles. among them. The pressure kept between  particles and the power of the attraction in materials is at its strongest between particles the least in gases.

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Answer:

5. An object of mass m = 2 kg, moving with velocity Vi1 = 12 m/s, collides head-on with a stationary object whose mass is m2 = 6 kg. The velocities of the objects after the collision are vj1 -6 m/s and Vr2 = 6 m/s.

Explanation:

We can use the conservation of momentum and kinetic energy to solve for the final velocities of the two objects.

Conservation of momentum:

m1v1i + m2v2i = m1v1f + m2v2f

where m1 and v1 are the mass and velocity of object 1 before the collision, and m2 and v2 are the mass and velocity of object 2 before the collision.

Plugging in the values:

(2 kg)(12 m/s) + (6 kg)(0 m/s) = (2 kg)(v1f) + (6 kg)(v2f)

Simplifying:

24 kg m/s = 2 kg v1f + 6 kg v2f

Conservation of kinetic energy:

(1/2)m1v1i^2 + (1/2)m2v2i^2 = (1/2)m1v1f^2 + (1/2)m2v2f^2

Plugging in the values:

(1/2)(2 kg)(12 m/s)^2 + (1/2)(6 kg)(0 m/s)^2 = (1/2)(2 kg)(v1f)^2 + (1/2)(6 kg)(v2f)^2

Simplifying:

144 J = 1 kg v1f^2 + 3 kg v2f^2

Now we have two equations with two unknowns (v1f and v2f). Solving for v1f in terms of v2f in the first equation:

v1f = (24 kg m/s - 6 kg v2f)/2 kg = 12 m/s - 3v2f

Plugging this into the second equation:

144 J = 1 kg (12 m/s - 3v2f)^2 + 3 kg v2f^2

Simplifying and solving for v2f:

144 J = 1 kg (144 m^2/s^2 - 72 v2f + 9 v2f^2) + 3 kg v2f^2

144 J = 144 J - 72 kg m/s v2f + 9 kg m^2/s^2 v2f^2 + 3 kg v2f^2

6 kg v2f^2 - 72 kg m/s v2f + 144 J = 0

Dividing by 6 kg:

v2f^2 - 12 kg m/s v2f + 24 J/kg = 0

Using the quadratic formula:

v2f = [12 kg m/s ± sqrt((12 kg m/s)^2 - 4(1)(24 J/kg))]/(2)

v2f = [12 kg m/s ± sqrt(96) m/s]/2

v2f = 6 kg m/s ± 2sqrt(6) m/s

v2f ≈ 9.90 m/s or v2f ≈ 2.10 m/s

Plugging these values into the equation we found for v1f:

v1f = 12 m/s - 3v2f

v1f ≈ -16.70 m/s or v1f ≈ 38.70 m/s

Since the negative velocity doesn't make physical sense, the final velocities of the two objects are:

v1f ≈ 38.70 m/s and v2f ≈ 2.10 m/s

Answer:

S = Vy t + 1/2 g t^2 = 1/2 g t^2    vertical speed with zero initial speed

t = (2 S / g)^1/2      with g = 32 ft/sec^2

t = (900 / 32)^1/2 = 5.30 sec    time to reach ground

V = a t = 32 ft/s^2 * 5.30 s = 170 ft/sec

170 ft/sec / (88 ft/sec / 60 mph) = 116 mph           since 88 ft/sec = 60 mph

Answer:

I think it is B

Explanation: the rest don't really make since

The examples of balanced forces include;

Balanced forces are those that are opposite in direction and equal in size. Balanced forces are considered to be in a state of equilibrium.

A tow truck tries and fails to pull a car out of a ditch. Neither the car nor the tow truck move. (forces are balanced that's why they don't move).

Jada and Mya run into each other in bumper cars. They bounce off each other and go in new directions. (forces are  balanced that's why they bounce off in opposite direction).

Zeke rests at the top of Stone Mountain and enjoys the view. (forces are balanced that's why he is at rest).

Haleigh throws a baseball from first base to second. (forces are not balanced that's why the baseball is in motion).

Ryan is playing ice hockey and glides across the ice in a straight line at a constant speed. (forces are not balanced that's why he is in motion).

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It is not recommended to fire a gun straight up into the air.

When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.

Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.

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The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.

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