Problem 18 if anyone could help that would be amazing!

The change in momentum is 594 m/s.

An object's momentum is a vector quantity equal to the product of its mass and velocity. A body can only gain momentum when another force exerts pressure on it.

When a net force is applied to an object, the force changes the object's momentum while it is being applied. In other words, the short-term force applied to the body controls the pace at which momentum changes.

When an item suffers a significant change in momentum in a short amount of time, a significant net force must have been exerted on it. This serves as the foundation for the idea of a body's momentum changing.

Therefore, The change in momentum is 594 m/s.

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Answer:

Explanation:

Given:

m₁

m₂

R₁

F₁ = 16 units

m₁' = 2·m₁

m₂' = 2·m₂

R₂ = 2·R₁

_________

F₂ - ?

The force of gravity:

F₁ = G·m₁·m₂ / (R₁)²

F₂ = G·m₁'·m₂' / (R₂)² = G·(2·m₁)·(2·m₂) / (2·R₁)² =

= 4·m₁·m₂ / (4·R₁²) = m₁·m₂ / (R₁)² = F₁

F₂ = F₁ = 16 units

Answer: C. 12.6

Explanation: 2*pi*1.8= 11.304

11.304/0.9= 12.56

Answer:

SF4 + 3H2O → H2SO3 + 4HF

Explanation:

I found it

The distance the 2.0 N object will move, given that 35 J of energy is used to move it is 17.5 m

Work done is defined as the product of force and the distance moved in the direction of the force. Mathematically, it is expressed as:

Work done (Wd) = force (F) × distance (d)

Using the above formula, we can detertmine the distance the object will move as illustrated below:

Work done (Wd) = force (F) × distance (d)

35 = 2 × distance moved

Divide both sides by 2

Distance moved = 35 / 2

Distance moved = 17.5 m

Therefore, we can conclude from the calculation made above that the distance moved is 17.5 m

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Complete question:

You use 35 J of energy to move a 2.0 N object. How far did you move it?

Answer

Clinometers measure both inclines and declines using three different units of measure: degrees, percentage points, and topo . Astrolabe is example of an inclinometer that was used for celestial navigation and location of astronomical objects from ancient times to the Renaissance.

Answer:

453,870 J

Explanation:

KE = 1/2mv² = 1/2(1500 kg)(24.6 m/s)² = 453,870 J

This motion of the balloon is an example of buoyancy, which is the upward force exerted by a fluid on an object immersed in it.

When the balloon is neutrally buoyant, it means that the weight of the balloon and the weights attached to it is equal to the weight of the water displaced by the balloon.

If you push the balloon down to a greater depth and then release it, the balloon will rise back up to its original position.

This is because the balloon is still partially inflated and contains air, which is less dense than water. When you push the balloon down, the water pressure compresses the air in the balloon, causing it to become smaller in size.

When you release the balloon, the compressed air expands and pushes the balloon upwards towards the surface of the water.

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Science and technology have had a significant influence on society, with both successes and difficulties.

The achievements can be noted as -

The challenges can be noted as -

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The rock will reach a height of approximately 27.76 meters.

1. Calculate the spring's potential energy (PE) when compressed:
PE = (1/2) * k * x^2
where k = 5400 N/m (force constant), x = 3.3 m - 1.0 m = 2.3 m (compression distance)

PE = (1/2) * 5400 * 2.3^2
PE ≈ 14157 J (joules)

2. At the highest point, all the potential energy is converted to gravitational potential energy (GPE):
GPE = m * g * h
where m = 52 kg (mass of the rock), g = 9.81 m/s^2 (acceleration due to gravity), and h (height) is what we want to find.

3. Equate GPE and PE, then solve for h:
14157 J = 52 kg * 9.81 m/s^2 * h

h ≈ 27.76 m

The rock will reach a height of approximately 27.76 meters.

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The ideal banking angle for a gentle turn of 1.20 km radius on a highway with a 30.0 m/s speed limit is 10.68 degrees.

The banking angle can be defined as the angle at which the road is inclined towards the inside of a curve so that the required centripetal force can be provided by the frictional force on the tyres.

The relationship between banking angle (θ), the radius of the turn (r), and the speed limit (v) can be described as:tan(θ) = v² / (rg)where g is the acceleration due to gravity.The radius is given as r = 1.20 km = 1200 m

The speed limit is given as v = 30.0 m/sNow, substitute the given values in the above equation.tan(θ) = (30.0 m/s)² / [(1200 m) (9.81 m/s²)]tan(θ) = 0.02602θ = tan⁻¹(0.02602)θ = 1.496 degreesTo convert degrees to radians, multiply by π/180.r = 1.496° × π/180 = 0.02614 radians

Therefore, the ideal banking angle for a gentle turn of 1.20 km radius on a highway with a 30.0 m/s speed limit is approximately 0.02614 radians or 10.68 degrees.

Summary:The ideal banking angle for a gentle turn of 1.20 km radius on a highway with a 30.0 m/s speed limit is 10.68 degrees. The formula used to calculate banking angle is tan(θ) = v² / (rg), where θ is the banking angle, v is the speed limit, r is the radius of the turn, and g is the acceleration due to gravity.

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The ideal banking angle for a gentle turn of 1.20 km radius on a highway with a 30.0 m/s speed limit can be determined through the following steps: Step 1: Determine the centripetal force The centripetal force, which is the force required to keep an object moving in a circular path, is given by the formula.

The gravitational force acting on the object can be determined using the formula :Fg = mg where F g is the gravitational force, m is the mass of the object, and g is the acceleration due to gravity .Step 3: Determine the angle of banking The angle of banking, which is the angle at which the road should be inclined to provide the required centripetal force, can be determined using the formula.

v is the velocity of the object, g is the acceleration due to gravity, and r is the radius of the circular path. Substituting the given values, we have (approx) Therefore, the ideal banking angle for a gentle turn of 1.20 km radius on a highway with a 30.0 m/s speed limit is approximately 20.5°.

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The direction of acceleration in uniform circular motion is towards the center of the circle. The acceleration is always perpendicular to the velocity and is constantly changing the direction of motion.

The acceleration in uniform circular motion is constant in magnitude but changes its direction with the change in direction of velocity. It acts towards the center of the circle. The net force responsible for this acceleration is known as the centripetal force. The direction of centripetal force is always towards the center of the circle.

In uniform circular motion, the velocity vector of an object moving along a circular path changes continuously. However, the magnitude of velocity remains constant, i.e., it moves with constant speed. The direction of velocity changes because the direction of the object's motion changes. The acceleration in uniform circular motion is given by the equation:

a = v² / r

Where, v is the velocity of the object and r is the radius of the circular path. This equation implies that the magnitude of acceleration increases as the speed of the object increases or the radius of the circular path decreases. But the direction of acceleration is always towards the center of the circle.

The conclusion is that acceleration in uniform circular motion is towards the center of the circle. It is constant in magnitude but changes its direction with the change in direction of velocity. The net force responsible for this acceleration is known as the centripetal force. The direction of centripetal force is always towards the center of the circle.

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The resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

To calculate the effective stress in the aquifer, we need to subtract the fluid pressure from the total stress.

Given:

Pressure head in the aquifer = 100 ft (or 30.48 m)

The pressure head in the aquifer is directly proportional to the fluid pressure, which can be calculated using the formula:

Fluid pressure (P) = ρ * g * h

Where:

ρ = density of the fluid (water) = approximately 1000 kg/m³

g = acceleration due to gravity = 9.8 m/s²

h = pressure head

Fluid pressure = 1000 kg/m³ * 9.8 m/s² * 30.48 m ≈ 298,440 N/m² (or Pa)

The total stress in the aquifer is the sum of the fluid pressure and the effective stress. Therefore, the effective stress can be calculated by subtracting the fluid pressure from the total stress.

Now, let's consider the changes in the hydraulic head due to pumping:

Change in hydraulic head = -12 ft (or -3.66 m)

The resulting changes in each parameter will be as follows:

1. Pressure head:

The pressure head will be reduced by 12 ft, so the new pressure head will be 100 ft - 12 ft = 88 ft (or 26.82 m).

2. Fluid pressure:

The fluid pressure does not change, as it depends on the density of the fluid and the acceleration due to gravity, which remain constant.

3. Effective stress:

The effective stress can be calculated as the total stress minus the fluid pressure. Since the fluid pressure remains constant, the effective stress will also remain constant unless there are other factors affecting it.

4. Total stress:

The total stress is the sum of the fluid pressure and the effective stress. As mentioned earlier, the fluid pressure remains constant, so the total stress will decrease by the same amount as the effective stress, assuming no other factors affect the total stress.

Therefore, the resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

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Answer:

C.

Explanation:

the earth has a high greavitational pull

Answer: C the person and earth

Explanation: I just answered it on a p e x

correct answer is option (B)

As a general rule of thumb, you should wait to exercise until three to four hours after eating a meal, and one to two hours after eating a snack.

How Soon Can You Workout After Eating?

Experts generally advise waiting 3 to 4 hours after a meal and 30 to 90 minutes after a snack. Your meals should be basic and simple to digest as you come closer to your workout. This is from the general rule of thumb.

A quick, readily digested snack should be planned for about an hour before to an intense workout, but if you are undertaking a workout that takes less energy and haven't eaten in four hours, you may be able to forgo the snack. Remember that every body is different, so what you require might not be the same as what your workout partner needs. That is the fundamental idea of IIN's bio-individuality in action.

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Answer:

D. 60-90 minutes

Explanation:

Just did it and koukladina stop deleting my answers

Answer:

B

b

b

b

b

b

b

b

b

b

b

b

b

b

b

bb

b

b

b

b

b

b

b

b

b

b

b

b

b

b

Answer:

B is the answer

Explanation:

i marked b on my test and got 100%

Answer:

(b) 2

Explanation:

Answer:

21.4 mph

Explanation:

Circumference of tire in FEET   = pi * d =  pi * 1 ft = pi  feet

pi feet  x  600 rot/min  *  60 min /hr  *  1 mile / 5280 feet = 21.4 mph

Answer:

given that

V = 12.0 m/s

U = 0 m/s

s = 28 m

Explanation:

using the equation of motion

V^2 = U^2 + 2as

12^2 = 0 + 2(28)a

144 = 56a

a = 5.5 m/s^2

v = u +at

12 = 0 + 5.5t

12 = 5.5t

t = 2.2s

By ideal gas approximation, the final pressure is 75.76 atm.

We need to know about the ideal gas theory to solve this problem. The ideal gas is assumed that there is no interaction between particles in a gas. It can be determined by the equation

P . V = n . R . T

where P is pressure, V is volume, n is the number of moles gas, R is the ideal gas constant (8.31 J/mol.K) and T is temperature.

From the question above, we know that

P1 = 50 atm

T1 = 330 K

T2 = 500 K

When the initial and final volume is the same, we can use the ratio of pressure and temperature as

P1 / P2 = T1 / T2

50 / P2 = 330 / 500

P2 = 50 x 500 / 330

P2 = 75.76 atm

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Answer:

12mph in 2hrs and 3mph in 0.5hrs the total distance would be 12*2 and 3*0.5 which would be 24 and 1.5 so we add those 24+1.5= 25.5. The answer would be 25.5

Answer:

About 250 Hz

Explanation:

People of All ages without a hearing impairment should be able to hear the 8000hz. People under 50 should be able to hear the 12,000hz and people under 40, the 15,000hz. Under 30s should hear the 16,000hz, and the 17,000hz is receivable for those under 24.

The term alkaline reserve is used to describe the bicarbonate buffer system. Thus, the correct option is C.

The bicarbonate buffer system or alkaline reserve is an acid-base homeostatic mechanism which involves the balance of carbonic acid, bicarbonate ion, and carbon dioxide molecules in order to maintain the pH in the blood and duodenum optimum, among other body tissues, to support proper metabolic functions of the body.

Because of the high concentration of bicarbonate ions in the extracellular fluid (ECF), bicarbonate ions act as the dominant buffer of the ECF. Importantly, the body can independently modulate the concentrations of both the weak acid and weak base in the bicarbonate buffer.

Therefore, the correct option is C.

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Your question is incomplete, most probably the complete question is:

The term alkaline reserve is used to describe the ________ buffer system.

A) phosphate

B) hemoglobin

C) bicarbonate

D) protein

Answer:

11

Explanation:

There are 2.2lbs in a kilo

times the KG by 2.2 and u get the amount in lbs (pounds)

Answer: 1) It keeps us on the earth so that we can live on the earth and not flying someone else in the atmosphere and space. 2) It maintains the motion of motion of all the planets around the sun and moon around the earth. 3) It pulls all the object towards the earth. 4) The flowing of water in the rivers and seas.

Explanation: