Predict the product of the following Wittig reaction. Be sure your answer accounts for stereochemistry, where appropriate. If multiple stereoisomers form, be sure to draw all products using appropriate wedges and dashes 1. PPh3 5-iodo-1-phenyl-1-pentanone 2. n-Buli 1st attempt l See Periodic Table See Hint e stereoisomers form, be sure to draw all products using appropriate wedges and dashes.
Answers
If more than one stereoisomer forms, be sure to depict each one with the proper wedges and dashes; the result is cyclopent-1-en-1-ylbenzene.
We have a Wittig reaction in this situation. The "Ylide compound" is created by mixing and n-Buli. The iodide will first be replaced by triphenylphosphine in a Sn2 reaction.
After then, the base n-Buli will eliminate an atom of hydrogen to create a double bond (Ylide compound). The double bond will then undergo delocalization, resulting in a carbanion.
The carbonyl group's carbon will be attacked by this carbanion, creating a negative charge in the oxygen. The phosphorus atom will then be attacked by the negative charge, creating a cyclic structure. In order to create the alkene, the cyclic structure is finally disrupted (cyclopent-1-en-1-ylbenzene).
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Related Questions
Pcl3+H2O=H3PO3+Hcl=?
Answers
Answer:
PCl3 + 3H2O → HPO(OH)2 + 3HCl. Phosphorus(III) chloride react with water to produce phosphorous acid and hydrogen chloride.
Explanation:
Answer:
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Explanation:
i dunno
Sulfur dioxide and nitrogen dioxide react at 298 K via the reaction
SO2(g)+NO2(g)⇌SO3(g)+NO(g)
A system at equilibrium contains 0.369 mol SO2 , 0.369 mol NO2 , 0.654 mol SO3 , and 0.718 mol NO. O2 is added to the container and NO reacts completely with the O2. Calculate the amount of SO3 in the container after the system returns to equilibrium.
Answers
O₂ reacts increasing the NO₂ to 0.718 moles. At the return to equilibrium,
the amount SO₃ in the container approximately 0.931 moles.
How can the equilibrium values indicate the amount of SO₃?The equilibrium constant for the reaction aA + bB ⇌ cC + dD is presented as follows;
\(K_c = \mathbf{\dfrac{[C]^c_{eq} +[D]^d_{eq} }{[A]^a_{eq} +[B]^b_{eq} }}\)
The equilibrium constant for the reaction, whereby the volume is same for the contents is therefore;
\(K = \dfrac{0.654 \times 0.718}{0.369 \times 0.369} \approx 3.45\)
Given that the NO reacts with the O₂ as follows;
2NO + O₂ \(\longrightarrow\) 2NO₂
We have;
The number of moles of NO₂ added = 0.718 moles
The new number of moles are therefore;
\(K = \mathbf{ \dfrac{(0.654 + x) \times (0+ x)}{(0.369-x) \times (0.369 + 0.718-x)}} \approx 3.45\)Which gives;
0 = (0.654 + x) × x - 3.45 × (0.369 × (0.369 + 0.718)
2.45·x² - 5.6772·x + 1.384 = 0
\(x = \dfrac{5.6772 \pm \sqrt{(-5.6772)^2 - 4 \times 2.45 \times (1.3834)} }{2\times 2.45}\)
x ≈ 0.2768 or x ≈ 2.04
The possible number of moles of SO₃ in the container after equilibrium is reestablished is therefore;
n ≈ 0.654 + 0.2768 ≈ 0.931
The number of moles of SO₃ in the container after returning to equilibrium is 0.931 molesLearn more about equilibrium constant here:
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Given the balanced equation below:3Cu + 8HNO3 — 3Cu(NO3)2 + 2NO + 4H2OThe total number of grams of Cu neededto produce 188 grams of Cu(NO3)2 is?
Answers
Answer
Mass of Cu = 63.7 g
Explanation
Given:
A balanced chemical equation: 3Cu + 8HNO3 — 3Cu(NO3)2 + 2NO + 4H2O
Required: The total number of grams of Cu
Solution
\(\begin{gathered} 188\text{ g Cu\lparen NO}_3)_2\text{ x }\frac{1\text{ mole Cu\lparen NO}_3)_2}{187,56\text{ g Cu\lparen NO}_3)_2}\text{ x }\frac{3\text{ mole Cu}}{3\text{ mole Cu\lparen NO}_3)_2}\text{ x }\frac{63,546\text{ g Cu}}{1\text{ mole Cu}} \\ \\ =\text{ 63.7 g Cu} \end{gathered}\)A sample of the compound has 9 grams of cobalt. How many grams of fluorine does the sample have?
Answers
The mass (in grams) of fluorine the sample have is 2.91 g
How do I determine the mass of fluorine?First, we shall determine the mole of 9 grams of cobalt. Details below:
Mass of cobalt = 9 grams Molar mass of cobalt = 58.93 g/mol Mole of cobalt =?Mole = mass / molar mass
Mole of cobalt = 9 / 58.93
Mole of cobalt = 0.153 mole
Finally, we shall determine the mass of fluorine the present in the compound. Details below:
Molar mass of fluorine = 19 g/mol Mole of cobalt = 0.153 moleMole of fluorine = Mole of cobalt = 0.153 moleMass of fluorine = ?Mole = mass / molar mass
0.153 = Mass of fluorine / 19
Cross multiply
Mass of fluorine = 0.153 × 19
Mass of fluorine = 2.91 g
Thus, the mass of fluorine is 2.91 g
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match the following
1. the electrode within an electrochemical cell where oxidation occurs
2. the electrode within an electrochemical cell where reduction occurs
3. the voltage associated with the electron trances within an electrochemical cell
anode
oxidation potential
cathode
Answers
Answer:
1= anode, 2=cathode and 3=oxidation potential
Explanation:
Anode is the electrode within an electrochemical cell where oxidation occurs.
Cathode is the electrode within an electrochemical cell where reduction occurs.
Oxidation is the voltage associated with the electron trances within an electrochemical cell.
Calculate the standard biological Gibbs free energy for the reaction: pyruvate- + NADH + H+(aq) ---> Lactate- + NAD+ at 309 K given that the standard Gibbs free energy = -65.0 kJ/mol at this temperature. This reaction occurs under conditions of low oxygen supply, such as in muscle cells during strenuous exercise. Note: See Box 7.1 on page 164. The biological standard state has hydrogen ions at 1x10-7 molar instead of 1 M.
Answers
Answer:
\(-23592.19\ \text{J/mol}\)
Explanation:
T = Temperature = 309 K
\(\Delta G^{\circ}\) = Standard Gibbs free energy = -65.0 kJ/mol
R = Gas constant = 8.314 J/mol K
\([H^+]\) = Biological standard state has hydrogen ions = \(10^{-7}\ \text{molar}\)
Reaction quotient is given by
\(Q=\dfrac{1}{[H^+]}\\\Rightarrow Q=\dfrac{1}{10^{-7}}\\\Rightarrow Q=10^7\)
Standard biological Gibbs free energy is given by
\(\Delta G=\Delta G^{\circ}+RT\ln Q\\\Rightarrow \Delta G=-65000+8.314\times 309\times \ln10^7\\\Rightarrow \Delta G=-23592.19\ \text{J/mol}\)
The standard biological Gibbs free energy of the reaction is \(-23592.19\ \text{J/mol}\)
In an experiment, 3.25 g of C3H8 react with 3.50 g of O2.How many grams of H2O are formed?
Answers
Answer:
1.57 g of H2O.
Explanation:
What is given?
Mass of C3H8 = 3.25 g,
Mass of O2 = 3.50 g,
Molar mass of C3H8 = 44 g/mol,
Molar mass of O2 = 32 g/mol,
Molar mass of H2O = 18 g/mol.
Step-by-step solution:
First, let's see the chemical equation:
\(C_3H_8+5O_2\rightarrow3CO_2+4H_2O.\)Let's convert the mass of each reactant to moles using their respective molar mass:
\(\begin{gathered} 3.25\text{ g C}_3H_8\cdot\frac{1\text{ mol C}_3H_8}{44\text{ g C}_3H_8}=0.0739\text{ moles C}_3H_8, \\ \\ 3.50\text{ g O}_2\cdot\frac{1\text{ mol O}_2}{32\text{ g O}_2}=0.109\text{ moles O}_2. \end{gathered}\)Now let's see how many moles of H2O can be produced by each reactant. In the chemical equation 1 mol of C3H8 and 5 moles of O2 react to produce 4 moles of H2O:
\(\begin{gathered} 0.0739\text{ moles C}_3H_8\cdot\frac{4\text{ moles H}_2O}{1\text{ mol C}_3H_8}=0.296\text{ moles H}_2O, \\ \\ 0.109\text{ moles O}_2\cdot\frac{4\text{ moles H}_2O}{5\text{ moles O}_2}=0.0872\text{ moles H}_2O. \end{gathered}\)You can note that the limiting reactant is O2. This is because O2 is being consumed first and this reactant imposes the limit to produce H2O.
The final step is to convert 0.0872 moles of H2O to grams using the molar mass of H2O, as follows:
\(0.0872\text{ moles H}_2O\cdot\frac{1\text{8 g H}_2O}{1\text{ mol H}_2O}=1.57\text{ g H}_2O.\)The answer would be that 1.57 g of H2O are formed.
Give an example of an electrolyte
Answers
Answer: sodium chloride water solution
Explanation: Eelctrolyte contains cations and anions which can
Transfer charge
Answer:
some energy drinks like powerade or Gatorade, and some juice drinks to.
Where are each located? How does each contribute to the formation of the atom (think balance)?
Answers
Answer:
Where are what located no picks no pdf so what?
The following Lewis diagram represents the valence electron configuration of a main-group element.
This element is in group
.
According to the octet rule, this element would be expected to form an ion with a charge of
.
If is in period 5, the ion formed has the same electron configuration as the noble gas
.
The symbol for the ion is
.
Answers
This element is in group 1.
According to the octet rule, this element would be expected to form an ion with a charge of +1.
If X is in period 5, the ion formed has the same electron configuration as the noble gas Krypton
The symbol for the ion is Rb⁺
What is electronic configuration?Electronic configuration refers to the arrangement of electrons in the orbitals of an atom or molecule, indicating the energy level of the electrons, the number of electrons in each energy level, and the number of electrons in each orbital.
Considering the given element:
It has one valence electron, hence it is in group 1. Group 1 elements form ions with a charge of +1.
Losing one electron will give the ion the same electron configuration as Kyrton since it is the noble gas in Period 4.
The element is rubidium and the ion is Rb⁺.
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If Earth is in between the sun and the Moon in both Image 1 and Image 2, why do you think a lunar eclipse is only happening in Image 2?
Answers
Answer: do you want to become the best of friends well if you do all you have to do is say yes in the comments and ill give you the answer to your little problem here so all i want you to do is join this link tomorrow and come at 8:00 and zoom bomb my class this is the zoom link
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Which of the following has kinetic energy? Wind blowing at 3 km/h A fully stretched elastic band A boulder sitting on top of a hill An unused battery
Answers
There is a law called conservation of energy which states that energy can neither be created nor be destroyed. It can be only transferred from one form to another form. Therefore, the correct option is option A.
What is energy transfer in thermodynamics?Energy transfer is a phenomenon in which energy transfer from one matter to another matter. Energy can be transferred in two forms that are by doing work or by transferring heat.
To move any object energy is required so work has to be done by the gas to the piston. Heat can be transferred by three ways conduction, convention and radiation. In conduction, when two object are in direct contact, transfer of molecules takes place. Wind blowing at 3 km/h has kinetic energy. Anything that move possess kinetic energy.
Therefore, the correct option is option A.
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Photoelectric effect will occur only if frequency of light striking an electron in a metal is above a certain threshold frequenci
Answers
The statement is correct. The photoelectric effect refers to the phenomenon where electrons are ejected from the surface of a material when it is exposed to light. The frequency of light striking an electron in a metal must be above the threshold frequency in order for the photoelectric effect to occur.
The statement is correct. The photoelectric effect refers to the phenomenon where electrons are ejected from the surface of a material when it is exposed to light. However, for the photoelectric effect to occur, the frequency of the incident light must be above a certain threshold frequency.
The threshold frequency is the minimum frequency of light required to dislodge electrons from the material. Below this threshold frequency, regardless of the intensity or duration of the light, no electrons will be emitted.
This behavior can be explained by the particle-like nature of light, where light is composed of discrete packets of energy called photons. The energy of a photon is directly proportional to its frequency. Only photons with energy greater than or equal to the binding energy of the electrons in the material can dislodge them.
Therefore, the frequency of light striking an electron in a metal must be above the threshold frequency in order for the photoelectric effect to occur.
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Place the following gases in order of increasing average velocity at 300 K: Ar, CH4, N2, and N2O.
a. Ar = CH4 = N2 = N2O
b. N2O < Ar < N2 < CH4
c. N20 < N2 < CH4 < Ar
d. Ar < N2 < N2O < CH4
e. CH4 < N2 < N2O < Ar
Answers
At 300 K, The gases in order of increasing average velocity will be N2O < Ar < N2 < CH4
The molecular mass of of a gas is directly proportional to its Molecular Velocity. That is to say that Gases made up lighter molecules will have greater high-speed particles and relatively higher velocities while . Gases made up of heavier molecules have greater low-speed particles, and relatively lower velocities.
Therefore considering the gases
N20 with 44.013 g/mol , Ar with 39.948g/mol N2 with 28.0134 g/mol CH4 with 16.04 g/molThe order of increasing average velocity at 300K will be N2O < Ar < N2 < CH4
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since, as the temperature of a gas sample increases, the velocity distribution of the molecules shifts toward a blank velocity and becomes blank sharply peaked, temperature blank is greater.
Answers
As the temperature of a gas sample increases, the velocity distribution of the molecules shifts towards higher velocities and becomes less peaked.
This is due to the fact that the average kinetic energy of the molecules increases with increasing temperature. Since the molecules have more energy, their velocities become more spread out, and the peak of the velocity distribution shifts to the right.
This means that the fastest molecules are moving faster than before. At the same time, the spread of the distribution becomes tighter, resulting in a sharper peak. This is because the molecules are more likely to move at the same speed, so the fraction of them moving at any given speed is much higher.
This effect is most pronounced at higher temperatures, as the molecules have more energy to spread out in a larger range of velocities.
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2.
Which mixture could be a useful buffer in a solution?
acetic acid (CH3CO2H) and hydrochloric acid (HCl)
sodium hydroxide (NaOH) and elemental sodium (Na)
ammonia (NH3) and ammonium chloride (NH4Cl)
acetic acid (CH3CO2H) and ammonia (NH3)
Pls answer quickly
Answers
Ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)) mixture could be a useful buffer in a solution. Option C
A buffer is a solution that can resist changes in pH when small amounts of acid or base are added. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer system works by the principle of Le Chatelier's principle, where the equilibrium is shifted to counteract the changes caused by the addition of an acid or a base.
In option A, acetic acid (\(CH_3CO_2H\)) is a weak acid, but hydrochloric acid (HCl) is a strong acid. This combination does not form a buffer because HCl is completely dissociated in water and cannot provide a significant concentration of its conjugate base.
Option B consists of sodium hydroxide (NaOH), which is a strong base, and elemental sodium (Na), which is a metal. This combination does not form a buffer as there is no weak acid-base pair involved.
Option D contains acetic acid (\(CH_3CO_2H\)), a weak acid, and ammonia (\(NH_3\)), a weak base. Although they are weak acid and base, they do not form a buffer system together as they are both weak acids or bases and lack the required conjugate acid-base pair.
Option C, ammonia (\(NH_3\)), is a weak base, and ammonium chloride (\(NH_4Cl\)) is its conjugate acid. This combination can form a buffer system. When ammonia reacts with water, it forms ammonium ions (NH4+) and hydroxide ions (OH-).
The ammonium ions act as the weak acid, while the ammonia acts as the weak base. The addition of a small amount of acid will be counteracted by the ammonium ions, and the addition of a small amount of base will be counteracted by the ammonia, thus maintaining the pH of the solution relatively stable.
Therefore, option C, consisting of ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)), is the suitable mixture that could be a useful buffer in a solution.
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The compound iron oxide can exist with either iron(II) ions or iron(III) ions. Conduct Internet research to learn about the differences between iron(II) oxide and iron(III) oxide. Give the chemical formula for each compound. Describe their appearance and uses. Based on your findings, are these two forms of the same compound, or are they two completely different compounds?
(What goes in the 6 empty spaces?)
Answers
Based on our finding these two compounds are not same they are completely different from each other as Formula of both compounds are different, their appearance is also different from each other.
What is Iron (II) Oxide ?The formula of the Iron II oxide is FeO. Common name of Iron (II) Oxide is Ferrous Oxide. Iron (II) Oxide is a black colored powder. The mineral form of Iron (II) oxide is known as Wustite. Iron (II) Oxide is used as a pigment. It is also used to make dyes.
What is Iron (III) Oxide ?The formula of the Iron (III) Oxide is Fe₂O₃. Common name of Iron (III) Oxide is Ferric oxide. Iron (III) Oxide appears as Red-Brown solid. It is also known as Hematite. Iron (III) oxide is used as pigments. It is used in dental composites , cosmetics. It is also used to apply the final polish on metallic jewellery.
Thus from the above conclusion we can say that Based on our finding these two compounds are not same they are completely different from each other as Formula of both compounds are different, their appearance is also different from each other.
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What is the systematic name of the following compound?
Li2S
Answers
Answer:
the systematic name is called Lithium sulfide.
An inorganic substance composed of the elements lithium (Li) and sulfur (S) is known as lithium sulfide \((Li_2S)\).
It is a substance that solidifies in the shape of a crystal. Lithium ions in lithium sulfide have a positive charge, while sulfide ions have a negative charge. The chemical lithium sulfide is important in many industries. It is often employed in the synthesis of various lithium compounds, the manufacture of lithium batteries, and the manufacture of ceramics. Due to their high energy density, lithium batteries are often employed in portable electronics and electric vehicles.
Lithium sulfide is an ionic compound that has a high melting point in terms of physical characteristics. Although it is insoluble in water, many organic solvents can help dissolve it.
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Atoms are neutral because the number of
Answers
Answer:
electrons and protons
Explanation:
Literally search it up
To what volume ( in mL ) would you need to dilute 25.0 mL of a 1.45 M solution of KCl to make a 0.0800 M solution of KCI?
Answers
Answer:
V₂ = 453.125 mL
Explanation:
Given data:
Initial volume = 25.0 mL
Initial molarity = 1.45 M
Final molarity = 0.0800 M
Final volume = ?
Solution:
Formula:
M₁V₁ = M₂V₂
Now we will put the values in formula.
1.45 M × 25.0 mL = 0.0800 M × V₂
V₂ = 1.45 M × 25.0 mL / 0.0800 M
V₂ = 36.25 M.mL / 0.0800 M
V₂ = 453.125 mL
What specialized plant structures increase the probability of successful reproduction?
Answers
Answer:
The pistil and the stamen.
Explanation:
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The pistil and the stamen are the specialized structures increase the probability of successful plant reproduction
what is reproduction in plants ?Reproduction in Flowering Plants occur both asexually and sexually, flowering plants or angiosperms, use the sexual mode of reproduction.
Reproduction in Flowering Plants occurs in the flower as both male and the female gametes are present in it, various parts of flower involve in the process of reproduction.
There are four important steps in the reproduction of flowering plants. such as Pollination, Gametogenesis, Fertilization
The flower is a specialized structure where reproductive part of the plant, containing the male and female reproductive organs which facilitate fertilization.
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It is an assignment question, so please check it properly to answer it and do use graph to explain it better!
Answers
The instantaneous rate of reaction at 17 minutes is approximately -0.178 mol dm⁻³
To find the instantaneous rate of reaction at 17 minutes, we can use the concept of differential calculus and estimate the slope of the tangent line at t=17 on the graph of rate versus time.
To do this, we can use the formula for the slope of a line
slope = (change in y) / (change in x)
In this case, the "y" values are the rates of reaction and the "x" values are the times. We want to find the slope at t=17, so we can choose two points that are very close to t=17, such as t=15 and t=20. Then, we can use these values to estimate the slope at t=17
slope = (rate at 20 min - rate at 15 min) / (20 min - 15 min)
slope = (0.135 - 0.223) / (20 - 15)
slope = -0.178
This slope represents the instantaneous rate of reaction at t=17. However, since it has a negative value, it means that the rate of reaction is decreasing at t=17.
Therefore, the instantaneous rate of reaction at 17 minutes is approximately -0.178 mol dm⁻³
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How much heat is released when 245 g of steam cools from 106.0°C to -4.5°C
Answers
ANSWER
The amount of heat released is -54, 957.175J
EXPLANATION
Given that;
\(\begin{gathered} \text{ The mass of the steam is 245g} \\ \text{ The final temperature of the steam is -4.5}\degree C \\ \text{ The initial temperature of the steam is 106.0}\degree C \end{gathered}\)To find the amount of energy released, then apply the below formula
\(\text{ q = mc \lparen}\theta2\text{ - }\theta1)\)Recall, that the specific heat capacity of steam (c) is 2.03 J/g degrees Celcius
\(\begin{gathered} \text{ q = 245 }\times\text{ 2.03 \lparen-4.5 - 106\rparen} \\ \text{ q = 245 }\times\text{ 2.03 \lparen -110.5\rparen} \\ \text{ q = -54,957.175J} \end{gathered}\)Therefore, the amount of heat released is -54, 957.175J
Which of these is not used to make models of interstellar medium?
Material from meteorites.
Minerals.
Synthetic materials.
Burnt wood ash.
Answers
Material from meteorites are not the elements used to make models of interstellar medium. The correct option is A.
What is interstellar medium?The matter and radiation that prevail in the space between star systems in a galaxy are referred to as the interstellar medium in astronomy. This matter consists of gas including ionic, atomic, and molecular, dust, and cosmic rays.
Meteorite material is not used to create models of the interstellar medium.
Thus, the correct option is A.
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What is the percent yield for a reaction if we predicted the formation
of 42.0 grams of cyclohexene and actually recovered only 7.6
grams?
Answers
Answer: 18.1%
Explanation:
The percent yield for a reaction whose theoretical yield is 42.0 g and actual yield is 7.6 g is 18.09 g.
What is percentage yield?Percentage yield can be calculated by dividing the actual yield by the theoretical yield multiplied by 100.
The theoretical yield is 42.0 g
The actual yield is 7.6 g
\(\dfrac{actual\;yield}{theoretical \;yield} \times 100\\\\\\\dfrac{7.6}{42.0} \times 100 = 18.09\)
Thus, the percentage yield is 18.09 g.
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If one iron nail weighs 2.0 grams, what would be the mass of 6.022 x 10^23 nails?
Answers
Answer:
\(1.2x10^{24}g\)
Explanation:
Hello!
In this case, it is possible to treat this problem by using a proportional factor which indicates one iron nail equals 2.0 grams:
\(\frac{2.00g}{1nail}\)
Now, for an amount of 6.022x10²³ nails, the corresponding mass will be:
\(6.022x10^{23}nail*\frac{2.00g}{1nail} \\\\1.2x10^{24}g\)
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which of the following statement is true about the molecule shown below
Answers
Please help me with this chem question
Answers
Answer:
D
Explanation:
A and C are physical changes, while B is a solution, only D is a chemical reaction.
which non metals have similar chemical properties
Answers
Answer:
Chemical Properties of Nonmetals :
Nonmetals are poor conductors of heat and electricity. ... Unlike metals, nonmetals aren't malleable and ductile. Nonmetals react more with metals than with nonmetals. Usually, nonmetals react with other nonmetals in high temperature. Most nonmetals do not react with air in room temperature.A small amount of solid calcium hydroxide is shaken vigorously in a test tube almost full of water until no further change occurs and most of the solid settles out. The resulting solution is:______.
Answers
Answer:
Lime water, \(Ca(OH)_{2}_({aq} )\) is formed.
Explanation:
Lime-water is a clear and colourless dilute solution of aqueous calcium hydroxide salt.
Small amounts of calcium hydroxide salt, \(Ca(OH)_{2}_(s)\) is sparsely soluble at room temperature when dispersed vigorously. if in excess, a white suspension called 'milk of lime'is formed.
I hope this explanation is helpful.