Answers
the maximum bending stress in the lithosphere is 202 MPa
hear
Given that Hite 34 km
12 2 70 9 Pa
N 2 0. 25
ρm- ρw= 2300 kgm 3
3 = 10 ms - 2
Moh depressed about 10km beneath the centre or Islands .
We know, flexural rigidity
Equation
D=E/12 (1 - V 2 )
be neath the center of Isla g
=70 x 109 pa x 103 x ( 10 m ) 312 (1 - 0.0625 )
=70 x 1021- Nm
=12X 019375Fox 10 212
=2 6: 222 x 102 Mm
Again , total maximum bending stress in the
lithosphere 6 = = 90 - ( 8 m - Pm ) 8 u
Where , Applied load of upper Surface of lithosph
We Replaced manthe rock thickness = 34 1
Bending stress = 6. 222 x 10' Alm- 2300 108 x 10->52 x 34 km
=n3 4
= 6. 2327 10 1/m- 230 0 kg x 10 m 2 x 34 x103 x]
=2 6 . 222 x 102/ nim - . 2300 X10 x 34x103 Pa
= 6222x1021 am 2 x 18 Alm
34x 34 x 34x( 103) ,m 3
6:222 X 102 Mm
2
3 4 x 3 4x34 x 109 m 3
2 6 .222 x 1012 na
34 x 34 x 39
6. 222
- x 10 2 pa
39, 304
2 0. 000 ( 5 8 307 10 - Pas
158, 83 X 108 pa .
-'. Bendig stress - 15.83 x108 pa . 782 x 10 Pa
2 15. 53 x108 pa - 7. 8 2x108 pc
Bendig stress=202 M Pa
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Related Questions
what is soil texture?
Answers
Explanation:
soil texture-the relative content in the soil of precipitation rock or anthropogenic formations of particles of various sizes independent of the chemical or mineralogical composition
1. What is the speed of light in a vacuum? (1 point)
Responses
a. c=3⋅108 m/s
b. c=2⋅108 m/s
c. v=2⋅108 m/s
d. v=3⋅108 m/s
2. Why is a polarized filter helpful to a photographer?(1 point)
Responses
a.It transmits all light.
b.It scatters all light.
c.It blocks all light.
d.It blocks some light but not all
3. When a sound wave propagates through air, how do the air molecules move?(1 point)
Responses
a.The air molecules move randomly.
b.The air molecules vibrate forward and back along the wave’s direction of travel.
c.The energy is transferred without physical motion.
d.The air molecules vibrate side to side, perpendicular to the wave’s direction of travel.
Answers
1. The speed of light in vacuum is 3x108 m/s
2. Polarized filter is helpful to a photographer because, it blocks some light but not all.
3. When a sound wave propagates through air, the air molecules vibrate side to side, perpendicular to the wave’s direction of travel.
What is meant by polarization of light ?Polarization of light is defined as the phenomenon by which the vibrations of light gets restricted to a particular direction that is perpendicular to the direction of wave motion.
Here,
1. The speed of light in the vacuum, c = 3x108 m/s
2. Photographers use the polarized filters for photography to improve the landscape photographs. This is because, using polarized filters in the camera can reduce unwanted reflections and glares from the external light. This could help to improve the contrast in landscape photography.
3. When a sound wave is propagated through air, the air molecules also move along with it. This is because, when the wave passes through the air, it pushes the air molecule, leading to the bouncing of air molecules with the surrounding molecules. Thus exerts a high pressure in air and when the the peak of the wave is passed, the pressure gets lower. This causes the movement of air molecules in a direction perpendicular to the direction of propagation of the wave.
Hence,
1. The speed of light in vacuum is 3x108 m/s
2. Polarized filter is helpful to a photographer because, it blocks some light but not all.
3. When a sound wave propagates through air, the air molecules vibrate side to side, perpendicular to the wave’s direction of travel.
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According to Dallas Morning News in June 2021, the 386.243 kilometers high-speed rail would run from Dallas to Houston in 90 minutes, with a stop in the Brazos Valley, between College Station and Huntsville. What would be the average speed of the train in meters per second?
Answers
The average speed of the train is 71.52 meters per second.
The total distance the object covers in a given amount of time is its average speed. It's a scalar quantity. Average speed has no direction and is represented by the magnitude. The equation of average speed is given below.
\(v_{avg} = \frac{distance}{time}\)
The distance and time is given in the problem and they are 386.243 kilometers and 90 minutes respectively.
The distance in meters = 386.243*1000 = 386243 m
The time in seconds = 90*60 = 5400 s
The average speed = 386243 m/5400 s = 71.52 m/s
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A bird accelerating from rest at a constant rate , experiences a displacement of 28m in 11s .what is the final velocity after 11s?
Answers
Answer:
308m/s
Explanation:
Let the final velocity, displacent, time taken and initial velocity be V, S, T and U respectively.
Given,
U=0( The bird started from rest)
T= 11s
S=28m
then,
V=U+S×T
or, V=0+11×28
or, V= 308m/s
Help me please!!!!!!!!!!
Answers
The velocity of the ball just before it hits the ground is 14.0 m/s
Let's solve the problem using the given equation:
\(v^2 = u^2 + 2as\)
We know that u (initial velocity) is zero, s (distance traveled) is 10 meters, and a (acceleration due to gravity) is 9.81 m/s^2. We want to find the final velocity (v) just before the ball hits the ground.
Plugging in the given values, we get:
v^2 = 0 + 2(9.81)(10)
v^2 = 196.2
Taking the square root of both sides, we get:
v = sqrt(196.2)
v = 14.0 m/s
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--The complete Question is, A ball is dropped from a height of 10 meters. What is its velocity just before it hits the ground, assuming no air resistance? (Assume that the acceleration due to gravity is 9.81 m/s^2)
Hint: You can use the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity (which is zero in this case), a is the acceleration due to gravity, and s is the distance traveled.--
A flat circular mirror of radius 0.170 m is lying on the floor. Centered directly above the mirror, at a height of 0.720 m, is a small light source. Calculate the diameter of the bright circular spot formed on the 2.80 m high ceiling by the light reflected from the mirror.
Answers
Answer:
Explanation:
The light coming from source will be falling on the periphery of the mirror at an angle of θ where
tanθ = .17 / .72
= 17 / 72
angle of reflection will also be θ . The reflected light will fall on the ceiling at a distance d from a point just above the point where the incident light falls .
d / 2.8 = tanθ
d = 2.8 x 17 / 72
= .66 m
radius of the circular spot on the ceiling
= .66 + .17
= .83 m
diameter = 2 x .83
= 1.66 m
The flat circular radius of 0.170m is lying on the floor and is dorecly inthe center of the mirror and has a height of 0.702m and is a small light source.
The light coming from source will be falling on the periphery of the mirror at an angle of θ where tanθ = .17 / .72 = 17 / 72 The angle of reflection will also be θ . The reflected light will fall on the ceiling at a distance d from a point just above the point where the incident light falls . d / 2.8 = tanθ d = 2.8 x 17 / 72 = .66 m.Learn more bout the radius 0.170 m is lying on the floor.
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a double-decker london bus (figure 1) might be in danger of rolling over in a highway accident, but at the low speeds of its urban environment, it's plenty stable. the track width is 2.05 m. with no passengers, the height of the center of gravity is 1.45 m, rising to 1.73 m when the bus is loaded to capacity. What are the critical angles for both the unloaded and loaded bus?
Answers
When the bus is fully loaded, the center of gravity rises to 1.73 m, and the critical angles are 35.3 degrees for the unloaded bus and 30.6 degrees for the loaded bus, respectively.
Center of gravity: What is it?Theoretically, the body's total weight is concentrated at a location called the center of gravity.
What distinguishes the center of mass from the center of gravity?The main distinction between the centers of mass and gravity is that the center of gravity refers to the location where the total weight of the body is balanced, whereas the center of mass refers to the location where the body's complete mass is directed.
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A car and driver weighing 5060N passes a sign stating "Bridge out 27.5 meters ahead." She slams on the brakes and the car decelerates at a constant rate of 14 m/s^2. The acceleration of gravity is 9.8 m/s^2. What is the magnitude of the work done stopping the car if the car just stops in time to avoid diving into the water?
Answer in units of J.
Answers
Answer:
198785.714286 Joules
Explanation:
\(W=f*d\)
\(F=ma\\F=516.326530612*-14\\F=-7228.57142857 N\\\)
To find work:
Now that the force and the distance are known, plug and chug:
\(W=f*d\\W=-7228.57142857*27.5\\W=-198785.714286J\)
Note that the question is asking for the magnitude of work, so the negative can be discarded as it is a directional component.
So, your answer is
198785.714286 Joules
The following are four electrical components.
A. A component which obeys ohm's law
B. Another component which obeys ohm's law
but which has higher resistance than A
A filament lamp
C.
D. A component, other than a filament lamp,
which does not obey ohm's law.
a. For each of these components, sketch current-
voltage characteristics, plotting current on the
vertical axis, and showing both positive and
negative values. Use one set of axes for A and
B, and separate sets of axes for C and for D.
label your graphs clearly.
b.
Explain the shape of the characteristic for C
c. Name the component you have chosen for D.
Answers
For the following are four electrical components:
a. For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.
b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it.
c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction.
For the following are four electrical components:
a. Sketches of current-voltage characteristics:
For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.
Current (I)
^
| B
| /
| /
| /
| /
| /
| /
| /
| /
| /
|/
+------------------> Voltage (V)
Current (I)
^
| A
| /
| /
| /
| /
| /
| /
| /
| /
| /
|/
+------------------> Voltage (V)
For component C, a filament lamp, the current-voltage characteristic would be a curve that is not linear. It would exhibit a non-linear increase in current with increasing voltage. At lower voltages, the lamp would have low resistance, but as the voltage increases, the resistance of the filament also increases due to the phenomenon of thermal self-regulation. This leads to a slower increase in current at higher voltages.
For component D, a component that does not obey Ohm's law, the current-voltage characteristic could be any non-linear curve depending on the specific component chosen. Examples of components that do not obey Ohm's law include diodes and transistors.
b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it. As the voltage across the filament increases, the temperature of the filament increases as well, causing its resistance to increase. This increase in resistance results in a slower increase in current with increasing voltage, leading to the characteristic non-linear curve observed.
c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction. It exhibits a non-linear current-voltage characteristic where it conducts current only when the voltage is above a certain threshold, known as the forward voltage. Below this threshold, the diode has a high resistance and blocks current flow in the reverse direction. The characteristic curve of a diode would show negligible current flow until the forward voltage is reached, after which it exhibits a rapid increase in current with a relatively constant voltage.
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is a fuel cell a primary or secondary cell
Answers
Answer:
Enrol in our 50 studyscore masterclass. Click here! Fuel cells are a type of primary cell in that they are not recharged, However, they are unique because they never run out, if the reactants are constantly supplied.
How can a body have centripetal acceleration even if the speed is constant?
Please help me understand this it’ll be greatly appreciated!
Answers
Answer:
motion of an object—even if the object is maintaining a constant speed—still count as acceleration
Explanation:
A 750 kg race car accelerates to the right. The engine applies a force of
+7000 N to the car. The total friction on the car in the opposite
direction is -200 N.
Find the net force on the car then use 'Fnet = m a' to find the
acceleration.
O a
b
Oc
Od
12.4 m/s2
10.5 m/s2
8.0 m/s2
9.1 m/s2
Answers
Answer: Option D, 9.1 m/s^2
cart is sliding across a horizontal floor. It has a mass of 25 kg and a force of 250 N. Using Newton's second law, a = F ÷ m, what is the acceleration of the cart?
0.1 m/s2
5 m/s2
10 m/s2
25 m/s2
Answers
Answer:
10m/s2
Explanation:
250/25=10
On the same object as in the previous question, you have to pus
with 15 N to move it 10 meters. How much work do you do?
Answers
Answer:
150 J
Explanation:
To find the work done by pushing the object with a force of 15 N over a distance of 10 meters, we can use the equation:
Work = Force × Distance × cos(θ)
Where:
Force is the applied force (15 N)
Distance is the distance over which the force is applied (10 m)
θ is the angle between the force vector and the direction of motion. In this case, we assume that the force is applied in the same direction as the motion, so θ = 0 degrees, and cos(θ) = 1.
Substituting the given values:
Work = 15 N × 10 m × cos(0) = 150 J
.
which of the numbers below correctly describes 1,250 volts?a.0.00125 mvb.0.125 mvc.1.25 mvd.1,250 mv
Answers
1.25 MV is the numbers below correctly describes.
We know, 1000 volts = 1MV
Given, 1250 volts
We have to convert 1250 volts in MV.
1 volt = \(\frac{1}{1000}\) MV
1250 volts = 1.25 MV
Hence, the correct answer is 1.25 MV.
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If an object is between a concave mirror and its focal point, the image will be(A) real and smaller than the object.(B) real and larger than the object.(C) virtual and smaller than the object.(D) virtual and larger than the object.
Answers
(D) virtual and larger than the object.
Explanation
Concave mirror is spherical mirror which has its reflecting surface bulging inwards
. The focal length of a mirror is the distance between the pole of the mirror and a point where all the reflected rays merge,The focal point and the centre of curvature of the concave mirror lie in front of the mirror
so,if an object is located between the focal point and a concave mirror we can use the ray diagram to check this,
.
, the image produced will be virtual , and longer than the object
so, the answer is
(D) virtual and larger than the object.
I hope this helps you
A string has its 4th harmonic at 31.5 Hz. What is the fundamental frequency?
Answers
Given data
*The given 4th harmonic frequency is 31.5 Hz
The fundamental frequency is calculated as
\(\begin{gathered} f_n=\frac{31.5}{4} \\ =7.875\text{ Hz} \end{gathered}\)Hence, the fundamental frequency is 7.875 Hz
At a temperature of 300 K, the pressure of the gas in a deodorant can is 3 atm.
Calculate the pressure of the gas when it is heated to 900 K.
Answers
The pressure of the gas in the deodorant can when it is heated to 900 K is 9 atm.
What is the pressure of the gas when it is heated to 900 Kelvin?Gay-Lussac's law states that the pressure exerted by a given quantity of gas varies directly with the absolute temperature of the gas.
It is expressed as;
P₁/T₁ = P₂/T₂
From the data:
Initial pressure P₁ = 3 atmInitial temperature T₁ = 300 KFinal pressure P₂ = ?Initial temperature T₂ = 900 KWe substitute our values into the expression above and solve for final pressure.
P₁/T₁ = P₂/T₂
P₁T₂ = P₂T₁
P₂ = P₁T₂ / T₁
P₂ = ( 3 atm × 900 K ) / 300 K
P₂ = 9.0 atm
Therefore, the final pressure is 9.0 atm.
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Can you please do this for me I’ll do 50 points
Answers
Answer:
1. Chemical → (A) Energy stored in a substance that can be released through a chemical change. (When the substance reacts)
2. Light → (B) Caused by the vibrations of electrically charged particles, also called electromagnetic or light energy, can travel through spaces that are absent matter.
3. Sound → (G)Caused by an objects vibrations. Causes air particles to vibrate allowing energy to travel from particle to particle.
4. Mechanical → (F) The Sum of the kinetic energy and potential object in a system
5. Kinetic → (A) Energy of motion
6.Potential → (D)The energy an object has because of its position or shape
7.Energy → (I) The ability to do work
8. Thermal → (C) Total energy of the particles that make up an object. Higher temperature, particles move faster
9. Nuclear → (L) Energy that can be caused by changes in the nucleus of an atom, joining or splitting
10.Electrical → (H) Energy of moving electrons. Usually transformed into other forms of energy to help us do work
PLEASE HELP
the graph shows a plot of an objects velocity versus time for 15 seconds. is the acceleration of the object constant or changing? how do you know? what does this tell you about the net force on the object?
Answers
Answer:
It cannot be constant because if it does not change and each time it increases its strength and speed.
Explanation:
There are 25 elements found in living things. How many of these elements are found in some organisms but not all?
1
6
19
25
Answers
Answer: 6
Explanation:
Of those 25 elements found in living things, 6 of them can be found in all of them. These 6 are very integral to life as when they combine, they make up cells, tissues and other body components.
These elements are: Carbon, Oxygen, Nitrogen, Hydrogen, Phosphorus and Sulfur. Their combinations can either create organic or inorganic compounds.
Answer:
19
Explanation:
i got 19... not sure if 6 is correct
Two blocks, 1 and 2, are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105
. The figure illustrates the configuration.
A system of two blocks connected by a rope passing over a pulley. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle. Box M subscript 1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M sub 1 and the surface is mu subscript 1. Box M subscript 2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle. The coefficient of friction between box M sub 2 and the surface is mu subscript 2.
Answers
The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.
The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.
The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.
The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.
The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).
The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).
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the waves that heat a cup of water in the microwwave are an example of electromagnetic waves. True or False
Answers
An object is placed 250 cm in front of a concave circular mirror, and the image of the object also appears at 250 cm in front of the mirror. What is the radius of curvature of the mirror?
500 cm
125 cm
25.0 cm
250 cm
Answers
Answer:
Radius of curvature of the mirror = 250 cm
Explanation:
Given:
Object distance from mirror = 250 cm (u=-250)
Object distance appears in mirror = 250 cm (v=-250)
Find:
Radius of curvature of the mirror
Computation:
Using mirror formula
1/f = 1/v + 1/u
1/f = 1/(-250) + 1/(-250)
f = (-250/2)
f = -125 cm or 125 cm
Radius of curvature of the mirror = 2(f)
Radius of curvature of the mirror = 2(125)
Radius of curvature of the mirror = 250 cm
Equation of path of projectile is y=x(1-x)
Answers
The equation of the path of a projectile is y = x(1 - x). Projectile motion is the movement of an object in a parabolic trajectory as a result of being propelled or released under the influence of gravity. A projectile, in simple terms, is any object that is launched into the air, such as a bullet, a baseball, or a rock. It's important to note that the parabolic trajectory is due to the force of gravity acting on the object.
To better understand projectile motion, we must first examine the horizontal and vertical components of motion. The horizontal component of motion is constant, indicating that there is no acceleration in that direction. The vertical component, on the other hand, has acceleration because of gravity. The parabolic trajectory is the result of these two components of motion.As the projectile is launched, it travels a certain distance horizontally before beginning to descend as a result of gravity's influence, resulting in a parabolic path.The general formula for the trajectory of a projectile in two dimensions is given by:y = xtanθ - (gx²) / 2(v₀cosθ)²Where:y is the vertical distance covered by the projectilex is the horizontal distance covered by the projectileθ is the angle of projectiong is the acceleration due to gravityv₀ is the initial velocity of the projectile In the case of the given equation, y = x(1 - x), the path of the projectile will be a parabolic trajectory with a vertex at x = 0.5 and y = 0.25. The equation represents the projectile's vertical distance, y, as a function of its horizontal distance, x. It is crucial to note that the projectile's initial velocity and angle of projection are not considered in this equation.For such more question on acceleration
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An airplane with a speed of 92.3 m/s is climbing upward at an angle of 51.1 ° with respect to the horizontal. When the plane's altitude is 532 m, the pilot releases a package.
(a) Calculate the distance along the ground, measured from a point directly beneath the point of release, to where the package hits the earth.
(b) Relative to the ground, determine the angle of the velocity vector of the package just before impact. (a) Number Units (b) Number Units
Answers
Answer:
a
\(D = 1162.7 \ m \)
b
\(\beta =- 65.55^o\)
Explanation:
From the question we are told that
The speed of the airplane is \(u = 92.3 \ m/s\)
The angle is \(\theta = 51.1^o\)
The altitude of the plane is \(d = 532 \ m\)
Generally the y-component of the airplanes velocity is
\(u_y = v * sin (\theta )\)
=> \(u_y = 92.3 * sin ( 51.1 )\)
=> \(u_y = 71.83 \ m/s\)
Generally the displacement traveled by the package in the vertical direction is
\(d = (u_y)t + \frac{1}{2}(-g)t^2\)
=> \( -532 = 71.83 t + \frac{1}{2}(-9.8)t^2\)
Here the negative sign for the distance show that the direction is along the negative y-axis
=> \(4.9t^2 - 71.83t - 532 = 0\)
Solving this using quadratic formula we obtain that
\(t = 20.06 \ s\)
Generally the x-component of the velocity is
\(u_x = u * cos (\theta)\)
=> \(u_x = 92.3 * cos (51.1)\)
=> \(u_x = 57.96 \ m/s\)
Generally the distance travel in the horizontal direction is
\(D = u_x * t\)
=> \(D = 57.96 * 20.06 \)
=> \(D = 1162.7 \ m \)
Generally the angle of the velocity vector relative to the ground is mathematically represented as
\(\beta = tan ^{-1}[\frac{v_y}{v_x } ]\)
Here \(v_y\) is the final velocity of the package along the vertical axis and this is mathematically represented as
\(v_y = u_y - gt\)
=> \(v_y = 71.83 - 9.8 * 20.06\)
=> \(v_y = -130.05 \ m/s \)
and v_x is the final velocity of the package which is equivalent to the initial velocity \(u_x\)
So
\(\beta = tan ^{-1}[-130.05}{57.96 } ]\)
\(\beta =- 65.55^o\)
The negative direction show that it is moving towards the south east direction
A 5.760 kg
block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is s=0.455
and the coefficient of kinetic friction is k=0.205.
At time =0,
a force =15.8 N
is applied horizontally to the block. State the force of friction applied to the block by the table at times =0
and >0.
Answers
A block of wood resting on a steel desk experiences a force of friction that opposes the applied force. The force of friction depends on the coefficients of friction and the normal force acting on the block.
At time t=0, the force applied on the block is 15.8 N. Since the block is at rest, the frictional force must be equal and opposite to the applied force to maintain static equilibrium. Therefore, the force of friction acting on the block at t=0 is:
Ffriction = Fapplied = 15.8 N
Now, when the applied force is greater than the maximum static frictional force (i.e., Fs > μsN), the block will start to move, and the frictional force acting on the block will be the kinetic frictional force. The kinetic frictional force is given by:
Ffriction = μkN
where μk is the coefficient of kinetic friction and N is the normal force acting on the block.
The normal force N acting on the block can be calculated using Newton's second law, which states that the net force acting on an object is equal to its mass times its acceleration:
ΣF = ma
Since the block is moving horizontally, its acceleration in the vertical direction is zero, and the normal force N is equal to the weight of the block:
N = mg
where m is the mass of the block and g is the acceleration due to gravity.
Substituting the given values, we get:
N = 5.760 kg × 9.81 m/s^2 = 56.47 N
The maximum static frictional force Fs can be calculated using:
Fs = μsN
Substituting the given values, we get:
Fs = 0.455 × 56.47 N = 25.68 N
Since the applied force is greater than the maximum static frictional force, the block will start to move, and the frictional force acting on the block will be the kinetic frictional force. The kinetic frictional force can be calculated using:
Ffriction = μkN
Substituting the given values, we get:
Ffriction = 0.205 × 56.47 N = 11.56 N
Therefore, the force of friction acting on the block at t=0 is 15.8 N, and the force of friction acting on the block when it starts to move is 11.56 N.
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A 6.30-N force is applied to a 4.5-kg object to accelerate it rightwards. Neglecting any frictional forces, what is the acceleration of the object?
Answers
Answer:
1.4 m/s2
Explanation:
i took the test
Two identical cars A and B are at rest on a loading dock with brakes released. Car C, of a slightly different style but of the same weight, has been pushed by dock workers and hits car B with a velocity of 3.25 m/s. Knowing that the coefficient of restitution is 0.8 between B and C and 0.5 between A and B, determine the velocity of each car after all collisions have taken place.
Answers
Answer:
V(c)' = 0.325 m/s
V(a)' = 2.19375 m/s
V(b)'' = 0.73125
Explanation:
See attachment for explanation.
Answer these questions pls ASAP
Answers
Answer:
Balloon , vaccum,and thats about it at least all i can think of