The midpoint of the line segment from P, to P₂ is (-8,5). If P, =(-8,1), what is P₂?
The midpoint of the line segment from P to P₂ is (-8,5) and the coordinates of P are (-8,1). The coordinates of point P₂ is determined by using the midpoint formula, as (-8,9).
The coordinates of point P₂ can be determined by using the midpoint formula.
Given that the midpoint of the line segment from P to P₂ is (-8,5) and the coordinates of P are (-8,1), we can find the coordinates of P₂.
The midpoint formula states that the coordinates of the midpoint between two points (x₁, y₁) and (x₂, y₂) can be found by taking the average of the x-coordinates and the average of the y-coordinates.
Let's apply the midpoint formula to find the coordinates of P₂:
Midpoint coordinates: (-8,5)
Coordinates of P: (-8,1)
To find the x-coordinate of P₂, we can average the x-coordinates of the midpoint and P:
(x₁ + x₂)/2 = (-8 + x₂)/2
-8 + x₂ = -16
x₂ = -16 + 8
x₂ = -8
Similarly, to find the y-coordinate of P₂, we average the y-coordinates of the midpoint and P:
(y₁ + y₂)/2 = (1 + y₂)/2
1 + y₂ = 10
y₂ = 10 - 1
y₂ = 9
Therefore, the coordinates of P₂ are (-8,9).
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Add the integers.
-6 + (-4) =( ?
B-2
C 2
D 10
Answer:
-10
Step-by-step explanation:
Helpppppppppppppp pleaseeeeeeeee
First, lets put this into slope intercept form
3x + 2y = -6
2y = -3x - 6
y = -3/2x - 3
The y intercept is (0, -3)
To find the x intercept we set the new equation to zero and solve
0 = -3/2x - 3
+3 +3
(2)3 = -3/2x(2)
6 = -3x
6/-3 = -3x/-3
-2 = x
The x intercept is (-2,0)
Therefore, your intercepts are:
y-int. = (0,-3)
x-int. = (-2,0)
Hope this helps! =D
If f(t)=(t 2
+4t+4)(5t 2
+3) Find f ′
(2). Question 16 If f(x)= x
+6
x
−6
, find: f ′
(x)= f ′
(4)=
The derivative of f(t) is f'(t) = 10t^3 + 38t^2 + 38t + 22. Evaluating f'(2), we find f'(2) = 134.
To find the derivative of f(t), we apply the product rule and chain rule. Let's break down the function f(t) = (t^2 + 4t + 4)(5t^2 + 3).
Using the product rule, we differentiate the first term (t^2 + 4t + 4) while keeping the second term (5t^2 + 3) constant. The derivative of the first term is 2t + 4.
Next, we differentiate the second term (5t^2 + 3) while keeping the first term (t^2 + 4t + 4) constant. The derivative of the second term is 10t.
Now, applying the chain rule, we multiply the derivative of the first term by the second term and the derivative of the second term by the first term. Thus, f'(t) = (2t + 4)(5t^2 + 3) + (t^2 + 4t + 4)(10t).
Expanding and simplifying, we get f'(t) = 10t^3 + 38t^2 + 38t + 22.
To evaluate f'(2), we substitute t = 2 into the derivative function. Therefore, f'(2) = 10(2)^3 + 38(2)^2 + 38(2) + 22 = 134.
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PLEASE HURRY!!!!!
In the regular octagon , if AP = 10 cm. and BC = 15 cm, find its area.
The area of the regular octagon is $\boxed{\frac{225}{2}}$ square centimeters, or $\boxed{112.5}$ square centimeters, rounded to one decimal place.
An octagon is an eight-sided polygon. An octagon with all sides congruent is called a regular octagon. Since AP = 10 cm and BC = 15 cm are given, and the octagon is regular,
we can find the area of the octagon.To find the area of the regular octagon, we can divide the octagon into 8 congruent isosceles triangles, each of which has an angle measure of 135 degrees.
First, let's find the length of the side of the regular octagon. Let "s" be the length of one side of the octagon, and let "r" be the radius of the circumscribed circle.
Then, we have:$$s^2 + s^2 = r^2$$$$2s^2 = r^2$$$$r = s\sqrt{2}$$Since the diameter of the circumscribed circle is BC = 15 cm,
we have:$$2r = 15$$$$s\sqrt{2} = \frac{15}{2}$$$$s = \frac{15}{2\sqrt{2}}$$
Now, let's find the area of one isosceles triangle. We can use the formula:$$\frac{1}{2}ab\sin C$$where a = b = s, and C = 135 degrees.
Then, we have:$$\frac{1}{2}(s)(s)\sin 135 = \frac{1}{2}s^2\frac{1}{\sqrt{2}} = \frac{s^2}{2\sqrt{2}}$$
Finally, the area of the regular octagon is given by:$$8\cdot \frac{s^2}{2\sqrt{2}} = \frac{4s^2\sqrt{2}}{2\sqrt{2}} = \boxed{2s^2}$$
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Which of the following sets of numbers could represent the three sides of a triangle? {6,8,14} {13,20,34} {11,14,22} {13,20,35}
The set of numbers {6, 8, 14} and the set {11, 14, 22} could represent the three sides of a triangle.
To determine whether a set of numbers could represent the sides of a triangle, we need to check if it satisfies the triangle inequality theorem. According to the theorem, the sum of any two sides of a triangle must be greater than the length of the third side.
Let's evaluate each set of numbers:
1. {6, 8, 14}
The sum of the two smaller sides is 6 + 8 = 14, which is greater than the third side 14. Therefore, this set could represent the sides of a triangle.
2. {13, 20, 34}
The sum of the two smaller sides is 13 + 20 = 33, which is less than the third side 34. Hence, this set cannot represent the sides of a triangle.
3. {11, 14, 22}
The sum of the two smaller sides is 11 + 14 = 25, which is greater than the third side 22. Therefore, this set could represent the sides of a triangle.
4. {13, 20, 35}
The sum of the two smaller sides is 13 + 20 = 33, which is less than the third side 35. Hence, this set cannot represent the sides of a triangle.
In summary, the sets {6, 8, 14} and {11, 14, 22} could represent the three sides of a triangle.
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A cylindrical canister contains three tennis balls. assume the tennis balls touch the sides of the canister and the top and bottom with no gaps. if each ball is 2.7 inches in diameter, how much wasted space is in the canister? round to the nearest hundredth.
To calculate the wasted space in the canister, we need to determine the volume of the canister and subtract the combined volume of the three tennis balls. Given that each tennis ball has a diameter of 2.7 inches, By subtracting the total ball volume from the canister volume, we can determine the amount of wasted space.
The volume of a sphere can be calculated using the formula:
Volume = (4/3) * π * (radius)^3
Since each tennis ball has a diameter of 2.7 inches, the radius is half of that, which is 1.35 inches. Thus, we can calculate the volume of each ball as follows:
Volume of one ball = (4/3) * π * (1.35)^3
To find the total volume of the balls, we multiply the volume of one ball by three:
Total ball volume = 3 * (4/3) * π * (1.35)^3
The canister is cylindrical, so its volume can be calculated as the product of the cross-sectional area (π * radius^2) and the height of the canister.
To calculate the wasted space, we subtract the total ball volume from the volume of the canister. By rounding the result to the nearest hundredth, we obtain the amount of wasted space in the canister.
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I need some help with this please
Answer:
Step-by-step explanation:
An angle bisector line divides or makes two congruent angles for any given angle.
so measurement of angle 1 = 25 degrees
and measurement of angle FEG = 50 degrees
and done!
Graph this inequality on the number line. 2>3.2. TIHL -4 -3 -2 -1 0 1 2 3 4 1 > 0-> 1 3 4 N
Answer:
See belowStep-by-step explanation:
Given inequality:
x > 3.2Mark the point 3.2 with open dot and shade zone right to that point.
See attached
Linda had 90 fliers to post around town. Last week, she posted 1/5 of them. This week, she posted 1/3 of the remaining fliers. How many fliers has she still not posted?
The number of fliers that she has still not broadcasted will be 48 fliers.
What is Algebra?Algebra is the study of ideational characters, while logic is the manipulation of all those opinions.
Linda had 90 fliers to post around town. Last week, she posted 1/5 of them. Then the number of fliers staying is given as,
⇒ (1 - 1/5) x 90
⇒ (4/5) x 90
⇒ 72 fliers
This week, she posted 1/3 of the remaining fliers. Then the number of fliers that she has still not broadcasted is given as,
⇒ (1 - 1/3) x 72
⇒ (2/3) x 72
⇒ 48 fliers
The number of fliers that she has still not broadcasted will be 48 fliers.
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To increase morale among employees, a company began a program in which one employee is randomly selected each week to receive a gift card. Each of the company’s 200 employees is equally likely to be selected each week, and the same employee could be selected more than once. Each week’s selection is independent from every other week. (a) Consider the probability that a particular employee receives at least one gift card in a 52-week year. (i) Define the random variable of interest and state how the random variable is distributed. (ii) Determine the probability that a particular employee receives at least one gift card in a 52-week year. Show your work. (b) Calculate and interpret the expected value for the number of gift cards a particular employee will receive in a 52-week year. Show your work. (c) Suppose that Agatha, an employee at the company, never receives a gift card for an entire 52-week year. Based on her experience, does Agatha have a strong argument that the selection process was not truly random? Explain your answer.
a) i) The variable of interest is a binomial variable with p = 0.005 and n = 52.
ii) The probability that a particular employee receives at least one gift card in a 52-week year is of 0.2295 = 22.95%.
b) The expected number of gifts that each employee should receive during a year is of: 0.26.
c) Considering the above expected value, Agatha does not have a strong argument that the selection process was not truly random.
How to define the variable?For each employee, there are only two possible outcomes, either they get a gift, or they do not, hence the binomial distribution is used to describe the variable.
Each of the company’s 200 employees is equally likely to be selected each week, hence the parameter p is given as follows:
p = 1/200 = 0.005.
The year has 52 weeks, hence the parameter n is given as follows:
n = 52.
The probability of winning no cards is of:
P(X = 0) = (1 - 0.005)^52 = 0.7705.
Hence the probability of at least one gift is of:
P(X > 0) = 1 - P(X = 0) = 1 - 0.7705 = 0.2295.
The expected value is calculated as follows:
E(X) = np = 52 x 0.005 = 0.26.
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40x3.03 In standard form
Answer:
1.212 x 10^2
Step-by-step explanation:
Step 1 we get true decimal form answer = 121.2
Step 2 we count numbers for power in front of decimal before conversion and -1 = 3-1 = 2 power.
Step 3 We rewrite 121.2 in standard form 1.212 and x10 and use 2 power we proved.
-v + 5 + 6v = 1 + 5v + 3
Answer:
v does not exist
Step-by-step explanation:
5v+5=4+5v
there is no v
Ms. Storch is organizing a dance competition. She is charging a flat fee of 1 $18 for each group to enter the competition and an additional $2.75 per person in the group. If your dance group owes $70.25 for the competition, how many dancers participated?
What is the End Behavior of the following Graph?
Answer:
The answer is B
Step-by-step explanation:
The asymptote of this graph is -4. If you look at the bottom of the graph, the line is going flat to -4, that means it's the asymptote. B has the only option where -4 occurs. Therefore, it's B.
Hope this helps.
A new ice cream shop in town plans to use a half circle atop a triangle as their logo.
The shop plans to paint the logo on one wall. The triangle will be 8 ft tall, and the entire logo will be 12 ft tall. How much of the wall will be covered by the logo? Show your work and/or explain your reasoning.
The total area will be covered by the logo is 57.13 square ft if a new ice cream shop in town plans to use a half circle atop a triangle as their logo.
What is a circle?It is described as a set of points, where each point is at the same distance from a fixed point (called the center of a circle).
As we know,
The area of the semicircle = πr²/2 = π(12-8)²/2
The area of the semicircle = 25.13 square ft
The area of the triangle = (1/2)8(8) = 32 square ft
Total area = 25.13 + 32 = 57.13 square ft
Thus, the total area that will be covered by the logo is 57.13 square ft if a new ice cream shop in town plans to use a half circle atop a triangle as their logo.
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1. Find the equation of a line passing through the points (1,-2) and (-3,10).
Answer:
Step-by-step explanation:
(1 , -2) x₁ =1 & y₁ = -2
(-3,10) x₂= -3 & y₂ = 10
First we need to find the slope.
\(\boxed{Slope = $\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$}\)\(\boxed{Slope=\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}}\)
\(=\dfrac{10-[-2]}{-3-1}\\\\\\=\dfrac{10+2}{-4}\\\\\\=\dfrac{12}{-4}\\\\\\= - 3\)
m = -3
Equation of the line: y = mx + b
y = -3x + b
To find the value of b, take one of the point and substitue in the above equaiton.
(1 , -2)
-2 = -3*1 + b
-2 = -3 + b
-2 + 3 = b
b = 1
Equation of the line:
y = -3x + 1
In ΔSTU, u = 340 inches, t = 620 inches and ∠T=110°. Find all possible values of ∠U, to the nearest degree.
One possible value of ∠U is 80° (to the nearest degree).
What is a triangle?A triangle is a three-sided polygon with three vertices. The triangle's internal angle, which is 180 degrees, is constructed.
To find the possible values of ∠U, we can use the Law of Cosines:
c² = a² + b² - 2ab cos(C)
Where c is the side opposite the angle we want to find (∠U), a and b are the other two sides, and C is the angle opposite side c.
In this case, we want to find ∠U, so we'll use side u as c and sides t and s (which we don't know yet) as a and b, respectively:
u² = t² + s² - 2ts cos(U)
Substituting the given values, we get:
340² = 620² + s² - 2(620)(s)cos(U)
Simplifying:
115600 = 384400 + s² - 1240s cos(U)
Subtracting 384400 and rearranging:
s² - 1240s cos(U) + 268800 = 0
Now we can use the quadratic formula to solve for s:
s = [1240 cos(U) ± √(1240² cos²(U) - 4(1)(268800))]/(2)
Simplifying under the square root:
s = [1240 cos(U) ± √(1537600 cos²(U) - 1075200)]/(2)
s = [1240 cos(U) ± √(409600 cos²(U) + 1742400)]/(2)
s = [620 cos(U) ± √(102400 cos²(U) + 435600)]
Since s must be positive, we can discard the negative solution, and we have:
s = 620 cos(U) + √(102400 cos²(U) + 435600)
Now we can use the fact that the sum of angles in a triangle is 180° to find ∠U:
∠U = 180° - ∠T - ∠S
Since we know ∠T = 110°, we just need to find ∠S. We can use the Law of Sines to do this:
sin(S)/s = sin(T)/t
sin(S) = (s/t)sin(T)
Substituting the values we know:
sin(S) = (620 cos(U) + √(102400 cos²(U) + 435600))/620 * sin(110°)
sin(S) ≈ (1.481 cos(U) + 2.225)/6.959
Now we can use a calculator to find the arcsin of both sides to get ∠S:
∠S ≈ arcsin((1.481 cos(U) + 2.225)/6.959)
Finally, we can substitute the values we found for ∠S and ∠T into the equation we found earlier for ∠U:
∠U = 180° - 110° - arcsin((1.481 cos(U) + 2.225)/6.959)
Simplifying:
∠U = 70° - arcsin((1.481 cos(U) + 2.225)/6.959)
Now we can use trial and error or a graphing calculator to find the values of ∠U that satisfy this equation. One possible solution is:
∠U ≈ 80°
Therefore, one possible value of ∠U is 80° (to the nearest degree).
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Handy is making floor plan for a treehouse using a scale of 1 inch to 2 foot he wants to make the floor of the treehouse have a length of 8 foot how many inches should he show
Answer: \(4\ in.\)
Step-by-step explanation:
Given
Handy uses a scale of 1 inch to 2 foot i.e. 1 inch of drawing represents 2 foot
For 8 foot length of tree house he draw x inch(say)
\(\therefore \ \dfrac{1\ \text{inch}}{2\ \text{foot}}=\dfrac{x}{8}\\\\\Rightarrow x=8\times \dfrac{1}{2}\\\Rightarrow x=4\ in.\)
So, handy draw 4 inches.
Combine like terms to create an equivalent expression. -\dfrac{1}{2}\left(-3y+10\right)−
2
1
(−3y+10)
Answer:
3/2y-5
Step-by-step explanation:
The expression – 1/2 (–3y + 10) is equivalent to the expression (3/2)y – 5.
What is an equivalent expression?The equivalent is the expressions that are in different forms but are equal to the same value.
The expression is given below.
⇒ – 1/2 (–3y + 10)
Simplify the equation, we have
⇒ (3/2)y – 5
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the function call ____ passes a copy of the complete emp structure to calcnet().
The function call "calcNet(emp)" passes a copy of the complete emp structure to calcNet(). This is because "emp" refers to the variable name of the structure, and passing it without the "&" operator or the "*" operator means that a copy of the structure is passed instead of a reference or a pointer.
In this case, calcNet() would receive a complete copy of the emp structure and be able to perform calculations on it. However, any changes made to the structure within calcNet() would not be reflected in the original emp structure.
It is important to understand the difference between passing by value (copying the data) and passing by reference or pointer (passing a reference to the data). Passing by reference or pointer allows for changes made to the data within a function to be reflected in the original variable outside of the function.
In summary, the correct answer to the question is b) calcNet(emp), which passes a copy of the complete emp structure to calcNet().
The complete question is:-
the function call ____ passes a copy of the complete emp structure to calcnet().
a) calcNet(struct emp);
b) calcNet(emp);
c) calcNet(&emp);
d) calcNet(*emp)
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what is the diffrence between 1/2 and 1 1/2
Answer:
1/2 is a fraction and 1 1/2 is a whole number
PLEASE HELP!! DUE REALLY SOON (LINK)
Answer:
youngest=115
middle=150
elder=230
Step-by-step explanation:
let the youngest be x
the middle will be x+35
the oldest will be 2x
x+x+35+2x=495
4x+35=495
4x=495-35
4x=460
x=115
since the youngest is x,the money he will receive is $115.
the middle will be x+35 which is equal to 115+35=$150.
lastly the oldest will be 2x which is equal to 2×115=$230.
Answer:
Defined variables:
Y - amount the youngest son gets
M - amount the middle son gets
O - amount the oldest son gets
Y got $115
M got $150
O got $230
Step by Step explaination:
If Y is the youngest, then the middle son, M = Y + $35 since the middle child gets $35 more than the youngest gets. The oldest son, O = 2Y since it’s twice the amount the youngest gets.
If you add each of those up, the equation you get is 2Y + (Y+$35) + Y = $495. Now you can solve for Y, the youngest son.
2Y + (Y+$35) + Y = $495
4Y + $35 = $495
4Y = $460
Y = $115
If Y gets $115 and M gets $35 more, M gets $150.
If Y gets $115 and O gets twice that amount, O gets $230.
To double check my work add 230 + 115 + 150. This equals $495. Hope this helps!
a line ray or segment that divides a segment into two congruent parts at a 90° angle
A line, line segment, or ray that divides an angle into two congruent angles is called an angle bisector.
What are supplementary angles example?
Supplementary angles are those angles that sum up to 180 degrees. For example, angle 130° and angle 50° are supplementary angles because sum of 130° and 50° is equal to 180°. Similarly, complementary angles add up to 90 degrees.
What do you mean by angle bisector?
If the angle is divided by the line and the angle is divided such that the angles are equal to each other then the line is called the angle bisector.
The word congruent means equal of the things. In this, the angles are congruent to each other which means the angles are equal to each other.
Thus, the black space is to be filled by the angle bisector.
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help please thanks.
Answer:
Answer below
Step-by-step explanation:
a. g(w)=$30+$15w
b. h(w)=$65+$20w
c. g(3)=125 represents that Darnell's account has $125 after 3 weeks
d. w=3.5
what is m
A.
B.
C.
D.
Answer: .B.
Step-by-step explanation
A. nominal. B. ordinal. C. interval. D. ratio. 49. Identify the data set's level of measurement for Ages of students in a statistic class A. nominal. B. ordinal. C. interval. D. ratio. 50. A bank has stated that it will take on an average 35 minutes to clear a check with a lower specification limit of 30 minutes and an upper specification limit of 40 minutes. You collected the following data from the process: 34,42,40,38, and 36 . The σ shorterm
is given as 3.450, determine the Cp. A. 0.211. B. 0.527. C. 0.193. D. 0.483. SECTION B (ANSWER ANY FOUR QUESTIONS IN THIS SECTION) 10 MARKS EACH Q51. You are the Quality Manager of your company. Your secretary types 350 reports written by you and made up of 350 words each month \begin{tabular}{ll} Misspelled words: & 22 \\ Typographical error: & 120 \\ \hline Total number of defects: & 142 \end{tabular} Total number of defects: 142
Calculate:
(1) Defects per Unit (DPU)
(2) Defects per unit opportunity (DPO) (3) Defect per million opportunity (DPMO) (4) Part per million defect rate (PPM). Q52a. A process has a Cp equal to 3.5. Determine the standard deviation of the process if the design specifications are 16.08 inches plus or minus 0.42 inches. b. A bottling machine fills soft drink bottles with an average of 12.000 ounces with a standard deviation of 0.002 ounces. Determine the process capability index, Cp, if the design specification for the fill weight of the bottles is 12.000 ounces plus or minus 0.015 ounces. c. The upper and lower one-sided process capability indexes for a process are 0.90 and 2.80, respectively. The Cpk for this process is d. A black belt is developing a failure mode and effects analysis (FMEA) for the hamburger preparation station in a fast-food restaurant. The following ratings were developed for the low-heat temperature failure mode. Severity =9 Occurrence =8 Detection =7 and the std dev=15. What is the risk priority number (RPN) for this FNEA? Q53. Your company is incorporating a Six Sigma program with a lower specification limit 55, and an upper specification limit of 60 . After a discussion with your boss, you have been asked to calculate the process capability of the following six samples you collected: 52,61,54,53,58. The σ short term
is given as 3.869, determine the following: (i) C p
(ii) C w
(iii) P p
, (iv) P p
(v) How will you proceed with the Improve phase?
Q49: 1.The level of measurement for ages of students in a statistics class is C. interval.
Q50. the answer is D. 0.483
Q51:
(1) DPU = 142 / 350 = 0.406
(2) DPO = 142 / (350 × 350) = 0.00114
(3) DPMO = 0.00114 × 1,000,000 = 1,140
(4) PPM = 1,140
Q52:
a) σ = 0.84 / 21 ≈ 0.04 inches
b) σ = 0.002 ounces
c) Cpk = min(2.80, 0.90) = 0.90
d) RPN = Severity × Occurrence × Detection = 9 × 8 × 7 = 504
Q53:
1. σ = 3.869
2.Cw = (USL - LSL) / (6 * σw)
2.To calculate Cp, we use the formula:
Cp = (USL - LSL) / (6 * σ)
where Cp is the process capability index, USL is the upper specification limit, LSL is the lower specification limit, and σ is the short-term standard deviation.
Given:
USL = 40 minutes
LSL = 30 minutes
σ = 3.450
Cp = (40 - 30) / (6 * 3.450)
Cp = 10 / 20.7
Cp ≈ 0.483
Therefore, the answer is D. 0.483.
Q51:
(1) Defects per Unit (DPU) = Total number of defects / Total number of units
DPU = 142 / 350 = 0.406
(2) Defects per unit opportunity (DPO) = Total number of defects / (Total number of units × Number of opportunities)
DPO = 142 / (350 × 350) = 0.00114
(3) Defect per million opportunity (DPMO) = DPO × 1,000,000
DPMO = 0.00114 × 1,000,000 = 1,140
(4) Part per million defect rate (PPM) = DPMO
PPM = 1,140
Q52a. Cp = (USL - LSL) / (6 * σ)
Given:
Cp = 3.5
USL = 16.08 + 0.42 = 16.5 inches
LSL = 16.08 - 0.42 = 15.66 inches
3.5 = (16.5 - 15.66) / (6 * σ)
21 = 0.84 / σ
σ = 0.84 / 21 ≈ 0.04 inches
b. Cp = (USL - LSL) / (6 * σ)
Given:
Cp = ?
USL = 12.000 + 0.015 = 12.015 ounces
LSL = 12.000 - 0.015 = 11.985 ounces
σ = 0.002 ounces
Cp = (12.015 - 11.985) / (6 * 0.002)
Cp = 0.03 / 0.012
Cp ≈ 2.5
c. Cpk = min(Cpu, Cpl) = min(USL - μ / (3 * σ), μ - LSL / (3 * σ))
Given:
Cpk = ?
Cpu = 2.80
Cpl = 0.90
Cpk = min(2.80, 0.90) = 0.90
d. The Risk Priority Number (RPN) is calculated as Severity × Occurrence × Detection.
Given:
Severity = 9
Occurrence = 8
Detection = 7
std dev = 15
RPN = Severity × Occurrence × Detection = 9 × 8 × 7 = 504
Q53:
(i) Cp = (USL - LSL) / (6 * σ)
Given:
USL = 60
LSL = 55
σ = 3.869
Cp = (60 - 55) / (6 * 3.869)
Cp ≈ 0.217
(ii) Cw = (USL - LSL) / (6 * σw)
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Suppose the sample mean CO2CO2 level is 418 ppm.418 ppm. Is there any evidence to suggest that the population mean CO2CO2 level has increased
The probability that sample is greater than 418 will be is 6.533.
What is a probability?Probability is the occurence of likely events. It is the area of mathematics that deals with numerical estimates of the likelihood that an event will occur or that a statement is true.
Here we have
\(\mu=397.64,n=40,\sigma=20\)
According to central limit theorem, the sampling distribution of mean will be normal with mean
\(\mu_{\bar{x}}=\mu=397.64\)
and standard deviation
\(\sigma_{\bar{x}}=\frac{\sigma}{\sqrt{n}}=\frac{20}{\sqrt{40}}=3.1623\)
The z-score for\(\bar{x}=418\) is
\(z=\frac{\bar{x}-\mu_{\bar{x}}}{\sigma_{\bar{x}}}=\frac{418-397.34}{3.1623}=6.533\)
Therefore, the probability that sample is greater than 418 will be
\(P(\bar{x} > 418)=P(z > 6.533)\)
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Incomplete Question
Carbon dioxide (CO2) is one of the primary gases contributing to the greenhouse effect and global warming. The mean amount of CO2 in the atmosphere for March 2013 was 397.34 parts per million (ppm). Suppose 40 atmospheric samples are selected at random in May 2013 and the standard deviation for CO2 in the atmosphere is σ = 20 ppm. (1 pt.)
c) Suppose the sample mean CO2 level is 400. Is there any evidence to suggest that the population mean CO2 level has increased?
a measure of variability of the sample means xbar in repeated samples of n observations randomly selected from a given population is
The correct answer is B i.e. Standard Error of the Mean (SE) = σ / √(n)
The measure of the variability of the sample means, also known as the standard error of the mean, can be calculated using the formula:
Standard Error of the Mean (SE) = σ / √(n)
sigma is the population standard deviation,
n is the sample size.
The standard error of the mean represents the variability or dispersion of the sample means obtained from repeated samples of size n from a population. It indicates how much the sample means are likely to differ from the true population mean.
The smaller the standard error of the mean, the less variability is expected among the sample means, indicating a more precise estimate of the population mean.
Therefore, the correct answer is B i.e. Standard Error of the Mean (SE) = σ / √(n)
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Given question is incomplete, the complete question is below
A measure of variability of the sample means xbar in repeated samples of n observations randomly selected from a given population is
a. s
b. σ/√(n)
c. s/√(n)
d. σ
How do I figure out if it is tru or false
Answer:
Step-by-step explanation:
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