plz help plz :( (asap)

Answer:

325 centimeters

Step-by-step explanation:

Answer:

21 square feet

Step-by-step explanation:

A cube has 6 faces, therefore 126/6 = 21 sq/ft the area of 1 face

The area of one face of a cube is 21 feet.

Surface area of cube is the sum of areas of all the faces of cube, that covers it.

The formula for surface area is equal to six times of square of length of the sides of cube.

A cube has a surface area of 126 feet.

The area of one face is given by;

\(\rm Area \ of \ one \ face=\dfrac{Surface \ area}{Total \ number \ of \ faces}\\\\ Area \ of \ one \ face=\dfrac{126}{6}\\\\ Area \ of \ one \ face=21\)

Hence, the area of one face of a cube is 21 feet.

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Answer:

2.59d + 5.19b = 33.71

Step-by-step explanation:

Each candy costs $3 and each pretzel costs $4.25

From the question, we are to determine the price of each candy and the price of each pretzel

Let the price of each candy be x and the price of each pretzel be y

From the given information,

3 candies and 2 pretzels cost $17.50

Then, we can write that

3x + 2y = 17.50          ----------- (1)

Also,

9 candies and 4 pretzels cost $44

Then,

9x + 4y = 44              ------------ (2)

Solve the equations simultaneously

Multiply equation (1) by 2 and subtract it from equation (2)

2 × [3x + 2y = 17.50

6x + 4y = 35

Subtract from equation (2)

9x + 4y = 44

- [6x + 4y = 35

---------------------------------

3x + 0 = 9

3x = 9

Divide both sides by 3

3x/3 = 9/3

x = 3

substitute the value of x into equation (2)

9x + 4y = 44  

9(3) + 4y = 44  

27 + 4y = 44

4y = 44 - 27

4y = 17

y = 17/4

y = 4.25

Hence, the cost of the candy is $3 and the cost of the pretzel is $4.25

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Answer:

6*6=36

Step-by-step explanation:

6*6. 6 with exponent of 2=36

Answer:   WHAT IS THIS SUPPOSE TO BE

Step-by-step explanation:

Answer:

n o

Step-by-step explanation:

n and o put together means no which is the opposite of yes.

Answer:

a. first coin heads: 82/160

b. second coin heads: 115/250

a AND b: a x b = 82/160 x 115/250

Step-by-step explanation:

if not then im confuzzled

Answer: 1.8 L/h

Step-by-step explanation:

To convert the rate of water dripping from a tap from millilitres per second (ml/sec) to litres per hour (L/h), we need to use conversion factors.

Step 1:

First, let's convert the rate from millilitres per second to litres per second.

There are 1000 millilitres in a litre, so we can divide the rate in millilitres per second by 1000 to get the rate in litres per second:

\(\LARGE \boxed{\textsf{0.5 ml/sec $\div$ 1000 = 0.0005 L/sec}}\)

Step 2:

We can convert the rate from litres per second to litres per hour. There are 3600 seconds in an hour, so we can multiply the rate in litres per second by 3600 to get the rate in litres per hour:

\(\LARGE \boxed{\textsf{0.0005 L/sec $\times$ 3600 = 1.8 L/h}}\)

Therefore, the rate of water dripping from the tap is 1.8 L/h.

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The estimates that is led from the data from a poll conducted by Travelocity , then the percentages are "computed from a sample"  .

The Data from the poll conducted by Travelocity was computed from a sample of travelers and was used to estimate the proportion of travelers

The travelers have certain habits or behaviors, such as checking work email (44%) taking a cell phone (32%) , or bringing a laptop computer on vacation (26%) .

The sample estimates are used to make inferences about the population.

Therefore , the given percentages are that they were  "computed from a sample" .

The given question is incomplete , the complete question is

Data from a poll conducted by Travelocity led to the following estimates:

Approximately 44% of travelers check work email while on vacation, about 32% take cell phones on vacation in order to stay connected with work, and about 26% bring a laptop computer on vacation.

Are the given percentages "population values" or were they "computed from a sample" ?

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The answer for the following question is 0.7

Answer: 0.7

Step-by-step explanation:

It provides character details that indicate Mrs. This function Faxon's interaction with this character serve in the given excerpt. Therefore, the correct option is option A.

An excerpt is indeed a quotation from that other resource that the author introduces with fresh language in a sentence. This phrase is taken from Thomas Jefferson's 1801 inaugural speech: As he warned his audience, "I may often go wrong by defect of judgement," Jefferson admitted the fallibility of human nature. "I shall frequently err through lack of judgement" is the excerpt. It provides character details that indicate Mrs. This function Faxon's interaction with this character serve.

Therefore, the correct option is option A.

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Answer:

c d

Step-by-step explanation:

9514 1404 393

Answer:

  b.  They are at a speed of 30 mph when time begins.

Step-by-step explanation:

The y-axis represents time zero, when time begins. The curve intercepts the y-axis at y=30. Y-values on the graph represent speed in miles per hour (mph), so a y-value of 30 at the point on the y-axis represents ...

  a speed of 30 mph when time begins

An ordered pair is a solution of an equation in two variables if replacing the variables by the coordinates of the ordered pair results in a true statement.

In mathematics, an equation in two variables represents a relationship between two quantities. An ordered pair consists of two values, typically denoted as (x, y), that represent the coordinates of a point in a two-dimensional plane.

When these values are substituted into the equation, if the equation holds true, then the ordered pair is considered a solution or a solution set to the equation. This means that the relationship described by the equation is satisfied by the values of the ordered pair. In other words, the equation is true when evaluated with the values of the ordered pair.

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Answer:

Side-Angle-Side

Explanation:

In the two triangles:

• Side: ,AB is congruent to EF (side length 1.4).

• Angle: ,B is congruent to F (angle 107.9 degrees).

• Side: ,BC is congruent to FG (side length 2.2).

Therefore, triangle ABC is congruent to triangle EFG by the Side-Angle-Side congruence postulate.

Answer: 60 cents

Step-by-step explanation: 1 Dime= 10 cents; 10x6= 60.

Answer: 60 cents.

Step-by-step explanation:

One dime is worth 10 cents. Therefore, if you have six of them it's simple repeated addition

10+10+10+10+10+10

or simple multiplication.

10(6)

Which are both the same exact thing.

So six dimes are 60 cents. Hope that helps!!

The graph of the inequality y ≥ 2 - 2x is attached

An equation is an expression that is used to show how numbers and variables are related using mathematical operators

Inequality shows the non equal comparison of two or more numbers and variables.

Given the inequality:

y ≥ 2 - 2x

The graph of the inequality is attached

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Answer:

m=96

Step-by-step explanation:

Set up the equation:    m/8 = 12

Multiply each side by 8:  (the 8 on the left side cancels out) and you get left with m= 96

The set B∪C is the set of all tax returns showing business loss or filed in 2009.

The set B∪C represents the union of sets B and C, which includes all tax returns that show business loss or were filed in 2009.

This means that the set B∪C may include tax returns that show business loss but were not filed in 2009, and tax returns filed in 2009 that do not show business loss.

For example, a tax return filed in 2009 that shows no business loss would be included in set C but not in set B. On the other hand, a tax return that shows business loss but was filed in a year other than 2009 would be included in set B but not in set C.

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9514 1404 393

Explanation:

General information

All of these questions have to do with various translations of the square root function. The first problem deals with the basic function. Other problems translate the graph in various ways.

The basic square root function has its vertex at (0, 0) and is defined for x-values (domain) that are 0 or positive. The resulting y-values (range) are also zero or positive.

The basic function intercepts the x- and y-axes only at the point (0, 0), so both intercepts are 0. Unless the function is reflected vertically or horizontally, its minimum will be at the left end of any interval, and its maximum will be at the right end.

The transformation of a function g(x) to f(x) = g(x -a) +b causes it to be translated 'a' units to the right and 'b' units up. For the functions here, that means the vertex is translated from (0, 0) to (a, b). For the functions here, the vertex values are the limits of the domain and range, so those will be altered accordingly.

Problems

1.

a) The graph is shown in the attachment as f1 (orange).

b) vertex: (0, 0); domain: [0, ∞); range: [0, ∞)

c) x-intercept: 0; y-intercept: 0

d) On the interval [1, 4], the minimum is √1 = 1, and the maximum is √4 = 2.

__

2.

a) The graph is shown in the attachment as f2 (green). The basic function is translated left 1 and down 2.

b) vertex: (-1, -2); domain: [-1, ∞); range: [-2, ∞)

c) x-intercept: 3; y-intercept: -1 (read from the graph)

d) On the interval, [0.5, 5], the minimum is √1.5 -2 ≈ -0.78; the maximum is √6 -2 ≈ 0.45. Min and max values are shown in the table in the second attachment.

__

3.

a) The graph is shown in the attachment as f3 (purple). The basic function is translated up 3.

b) vertex: (0, 3); domain: [0, ∞); range: [3, ∞)

c) x-intercept: (none); y-intercept: 3 (the vertex)

d) On the interval, [2, 4], the minimum is √2 +3 ≈ 4.41; the maximum is √4 +3 ≈ 5. Min and max values are shown in the table in the third attachment.

__

4.

a) The graph is shown in the attachment as f4 (red). The leading multiplier of -2 causes the graph to be reflected over the x-axis and vertically expanded by a factor of 2 before being translated right 2 and up 3.

b) vertex: (2, 3); domain: [2, ∞); range: (-∞, 3]. Note the range is all y-values less than or equal to 3 because of the vertical reflection.

c) x-intercept: 4.25; y-intercept: (none). The x-intercept is found by solving ...

  0 = -2√(x -2) +3

  (-3/-2)² = x-2

  2 +2.25 = x = 4.25

d) On the interval, [4, 7], the minimum is -2√(7 -2)+3 = 3-2√5 ≈ -1.47; the maximum is -2√(4-2)+3 = 3-2√2 ≈ 0.17. Min and max values are shown in the table in the second attachment.

Answer:

  ₹168 per hour

Step-by-step explanation:

The hourly rate at which Tamara is paid can be found by dividing her ₹1050 pay by the 6:15 hours that she worked.

We know there are 60 minutes in an hour, so the fraction of an hour represented by 15 minutes is ...

  (15 min)/(60 min/h) = (15/60) h = 1/4 h = 0.25 h

Added to the 6 whole hours Tamara worked, her pay is for 6.25 hours.

The pay per hour is found by dividing pay by hours.

  ₹1050/(6.25 h) = ₹168/h

Tamara's hourly rate of pay is ₹168 per hour.

The answer is "false". The interval [1, 2] contains all the real numbers between 1 and 2 including the endpoints.

An interval notation is used for representing the continuous set of real values. This is the shortest way of writing inequalities.

Intervals are represented within the brackets such as square brackets or open brackets(parenthesis).

The given interval is [1, 2]

The given statement is - 'the interval [1, 2] contains exactly two numbers - the numbers 1 and 2'

The given statement is 'false'.

This is beacuse, an interval consists set of all the real values in between the two values given.

So, according to the definition, there are not only the end values but also many real values in between them.

Thus, the answer is "false". The interval [1, 2] consists of all the real values between 1 and 2 including 1 and 2.

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Answer:

20

Step-by-step explanation:

x^2 -y +1

Let x =5 and y = 6

5^2 -6+1

25-6+1

19+1

20

Answer:

Step-by-step explanation:

-0.25

-1/3

1/4

0.3

Answer:

D

Step-by-step explanation:

Answer:

8 and -1.4

Step-by-step explanation:

2(4x)=8x

-.7x2=1.4

The determinants you're looking for are:
det(AB) = -45
det(3A) = -135
det(A^T) = -5
det(B^-1) = 1/9
det(B^4) = 6561

If A and B are 3 X 3 matrices, det (A) = -5, det (B) = 9, then:

- det (AB) = det(A) * det(B) = (-5) * (9) = -45
- det (3A) = 3^3 * det(A) = 27 * (-5) = -135
- det (A^T) = det(A) = -5 (since transpose does not affect determinant)
- det (B^-1) = 1/det(B) = 1/9 (since inverse is reciprocal of determinant)
- det (B^4) = (det(B))^4 = 9^4 = 6561


Given that A and B are both 3x3 matrices with det(A) = -5 and det(B) = 9, we can find the determinants of the different matrix expressions as follows:

1. det(AB): According to the determinant product property, det(AB) = det(A) * det(B) = -5 * 9 = -45.

2. det(3A): For a scalar multiple, det(kA) = k^n * det(A), where n is the matrix size. In this case, det(3A) = 3^3 * (-5) = 27 * (-5) = -135.

3. det(A^T): The determinant of a transpose is equal to the determinant of the original matrix, so det(A^T) = det(A) = -5.

4. det(B^-1): For an inverse matrix, det(B^-1) = 1/det(B). Therefore, det(B^-1) = 1/9.

5. det(B^4): The determinant of a matrix raised to a power is the determinant of the original matrix raised to that power, so det(B^4) = (det(B))^4 = 9^4 = 6561.

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The coordinates of the vertices of the image of the trapezoid are A'(x, y) = (- 4, 1), B'(x, y) = (- 2, 1), C'(x, y) = (- 5 / 2, 5 / 2) and D'(x, y) = (- 7 / 2, 5 / 2).

In this question we have a representation of a trapezoid, whose image has to be generated by a kind of rigid transformation known as dilation, whose equation is described below:

P'(x, y) = O(x, y) + k · [P(x, y) - O(x, y)]

Where:

If we know that k = 1 / 2, A(x, y) = (- 5, - 2), B(x, y) = (- 1, - 2), C(x, y) = (- 2, 1), D(x, y) = (- 4, 1), O(x, y) = (- 3, 4), then the coordinates of the vertices of the image are:

Point A'

A'(x, y) = O(x, y) + k · [A(x, y) - O(x, y)]

A'(x, y) = (- 3, 4) + (1 / 2) · [(- 5, - 2) - (- 3, 4)]

A'(x, y) = (- 3, 4) + (1 / 2) · (- 2, - 6)

A'(x, y) = (- 3, 4) + (- 1, - 3)

A'(x, y) = (- 4, 1)

Point B'

B'(x, y) = O(x, y) + k · [B(x, y) - O(x, y)]

B'(x, y) = (- 3, 4) + (1 / 2) · [(- 1, - 2) - (- 3, 4)]

B'(x, y) = (- 3, 4) + (1 / 2) · (2, - 6)

B'(x, y) = (- 3, 4) + (1, - 3)

B'(x, y) = (- 2, 1)

Point C'

C'(x, y) = O(x, y) + k · [C(x, y) - O(x, y)]

C'(x, y) = (- 3, 4) + (1 / 2) · [(- 2, 1) - (- 3, 4)]

C'(x, y) = (- 3, 4) + (1 / 2) · (1, - 3)

C'(x, y) = (- 3, 4) + (1 / 2, - 3 / 2)

C'(x, y) = (- 5 / 2, 5 / 2)

Point D'

D'(x, y) = O(x, y) + k · [D(x, y) - O(x, y)]

D'(x, y) = (- 3, 4) + (1 / 2) · [(- 4, 1) - (- 3, 4)]

D'(x, y) = (- 3, 4) + (1 / 2) · (- 1, - 3)

D'(x, y) = (- 3, 4) + (- 1 / 2, - 3 / 2)

D'(x, y) = (- 7 / 2, 5 / 2)

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