pls help i need asap

The given statement When inserting a value into a partially-filled array in descending order, the insertion position is indeed the index of the first value smaller than the value being inserted is true.

What is partially filled array?

A partially filled array, also known as a sparse array, is an array data structure where not all elements are populated with values. In other words, it is an array that contains empty or uninitialized elements.

When inserting a new value into this sorted array, we start from the beginning and compare the value with each existing element until we find the first element that is smaller. The insertion position for the new value is the index of this first smaller element.

For example, if we have a partially-filled array [10, 8, 5, 3] and we want to insert the value 6 into the array in descending order, we compare 6 with each element from left to right. The first element smaller than 6 is 5, and its index is 2. Therefore, the insertion position for the value 6 would be index 2, resulting in the updated array [10, 8, 6, 5, 3].

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The problem involves finding all relative extrema of a function and using the second derivative test when applicable.

The given function is f(x) = x^4 - 4x^3 + 7, and we need to find the relative maximum and minimum points, if they exist. To find the extrema, we need to take the first and second derivatives of the function and set them equal to zero to find the critical points. Then, we can use the second derivative test to determine the nature of the critical points. If the second derivative is positive at a critical point, then it is a relative minimum, and if it is negative, then it is a relative maximum. If the second derivative is zero, then the test is inconclusive and another method must be used. Extrema analysis is an important concept in calculus and is used extensively in optimization problems in many fields, including physics, economics, and engineering.

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Answer:43.5

Step-by-step explanation:You have to Add to get your answer.I'll show you how I got 43.5:

1.8+32=33.8

33.8+5=38.8

38.8=4.7=43.5

Your answer is: 43.5

hope this was helpful:)

The area of a rectangle with a width of 8.6 cm and a height of 4.7 is 40.42 \(cm^{2}\). The total area of 40.42 \(cm^{2}\) has 4 significant figures.

By knowing the width and height of a rectangle we will be able to determine the area of the shape by multiplying them. Or the area of a rectangle can be found by multiplying the two sides.

Given,

Then the area of the rectangle:

Area = Width x height

Area = 8.6 cm x 4.7 cm

Area = 40.42 \(cm^{2}\)

So, the area of the rectangle above is 40.42 \(cm^{2}\) and it has 4 significant figures provided that zeros located between non-zero numbers are significant figures.

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Answer:

-9/4

Step-by-step explanation:

-8-1 = -9

2-(-2) = 4

Answer

x=-4

y=9

Step-by-step explanation:

The frequency of A allele after a single generation of mutation can be found as follows: Frequency of A allele after a single generationp(A) = p(A) x (1 - m) + q(a) x m

where,
m = mutation rate = 10^-6p(A) = frequency of A allele in initial generation = 0.75q(a) = frequency of a allele in initial generation = 0.25Thus,p(A) = 0.75 x (1 - 10^-6) + 0.25 x 10^-6 = 0.74999925

And the frequency of a allele will beq(a) = 1 - p(A) = 1 - 0.74999925 = 0.25000075

Therefore, the frequency of the A and a alleles in the next generation will beA: 0.74999925 and a: 0.25000075.

This is option D.

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The limit of Cordelia's money, denoted as Cn, as the number of steps approaches infinity is $125.

In the given scenario, Regan, Cordelia, and Goneril start with initial amounts of $180, $10, and $170, respectively. At each step, they give away all their money and divide it equally between the other two. Let's analyze the steps to understand the pattern.

After the first step, Cordelia gives away $5 to each of the other two, resulting in Regan having $185 and Goneril having $175. Now Cordelia has $0.

In the next step, Regan gives away $92.5 to Cordelia and $92.5 to Goneril, while Goneril gives away $87.5 to Cordelia and $87.5 to Regan. This leaves Cordelia with $92.5 and increases her amount by $92.5 in each subsequent step.

From the pattern, we can observe that Cordelia's money doubles with each step. So, after n steps, Cordelia will have $10 + $5n. As n approaches infinity, the limit of Cn will be $125.

In summary, as the number of steps approaches infinity, Cordelia's money approaches $125.

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After 3 years, Joe will have $579.14 in their savings account if they do not withdraw any money.

To solve the given problem, we need to use the formula for the amount of money in a savings account with compounded interest, which is given by:

A = P(1 + r/n)^(nt), where A is the final amount of money,P is the principal (the initial amount of money deposited),r is the annual interest rate,n is the number of times the interest is compounded per year, and t is the time in years.

Using the given values, we can substitute them into the formula and solve for the final amount of money that Joe will have after 3 years:A = $\(500(1 + 0.045/1)^(^1 ^× 3)A = $500(1.045)^3A\)= $579.14.

Therefore, after 3 years, Joe will have $579.14 in their savings account if they do not withdraw any money.

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Answer:

final answer is 21

Step-by-step explanation:

since x+y=7 and xy=10

2+5=7 and 2(5)=10

so,

(5)3=15  

(2)3=6

15+6= 21

Answer:

Possible dimensions are 10, 4, and 216.

Step-by-step explanation:

All we have to do is find three numbers, that when multiplied, equal 8,640.

I found the numbers 10, 4, and 216.

Answer:

The rate that the distance between the police car and car is changing = 3 m/s

Step-by-step explanation:

The given speed of the police car = 35 mph

The speed of the speeding car = 30 mph

The position of the police car = 0.75 miles north

The position of the speeding car = 1 miles east

The distance of the police car from the speeding car, d = √(0.75² + 1²) = 1.25

d² = x² + y²

2d·dd/dt = 2x·dx/dt + 2·y·dy/dt

Where;

dx/dt = 30 mph

dy/dt = -35 mph

x = 1

y = 0.75

Substituting gives;

2×1.25 ×dd/dt = 2×1×30 - 2×0.75×35

2×1.25 ×dd/dt = 7.5

dd/dt = 7.5/2.5 = 3

dd/dt = 3 m/s

The rate that the distance between the police car and car is changing = dd/dt = 3 m/s

Answer:

The answer is increasing by 3 mph

Step-by-step explanation:

Answer:

63⁰

Step-by-step explanation:

As in cyclic quadrilateral sum of opposite angles us equal to 180⁰

Six Sigma provides a continuous improvement framework and it has two methodologies.

DMAIC - Define, Measure, Analyze, Improve and Control.

DMADV - Define, Measure, Analyze, Design and verify

What is Six Sigma ?

According to the Six Sigma philosophies, every work can be broken down into discrete processes that may be measured, evaluated, improved, and managed.

                     Processes result in outputs after requiring inputs (x) (y). You can manage the outputs if you manage the inputs. This is typically written as y = f. (x).

What is a fundamental principle of Six Sigma?

The management practice known as "six sigma" aims to reduce errors. It is based on the idea that reducing defects is essential for improving margins, that costs can be cut, and that increasing customer loyalty can help because it is expensive to harbor defects.

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Answer:

$17.00

Step-by-step explanation:

10 x 1.70 = $17.00

Answer:

The retail price is $17.00

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

60÷100=0.6 0.6x20=12

Therefore the sports shop has 12 part-time employees

By complex and real number properties, the resulting electric resistance is equal to R' = 47 / 270 + i 4 / 45 ohms.

Complex numbers are numbers of the form z = a + i b, where a, b are real numbers. The first component is the real component and the second one is the complex one. In this problem we find the case of a combination of two electric resistances described by two complex numbers. This expression must be simplified by means of real number and complex number properties:

R' = 1 / R₁ + 1 / R₂

If we know that R₁ = 4 + i 6 and R₂ = 2 - i 4, then the resulting electric resistance is:

1 / (4 + i 6) + 1 / (2 - i 4)

(4 - i 6) / [(4 + i 6) · (4 - i 6)] + (2 + i 4) / [(2 - i 4) · (2 + i 4)]

(4 - i 6) / (16 - i² 36) + (2 + i 4) / (4 - i² 16)

(4 - i 6) / (16 + 36) + (2 + i 4) / (4 + 16)

(4 - i 6) / 52 + (2 + i 4) / 20

(2 - i 3) / 27 + (1 + i 2) / 10

47 / 270 + i 4 / 45

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This means that on a random day, there is a 16.78% chance that the number of shoppers at the grocery store will fall between 200 and 400.

Using the normal distribution formula, we can calculate the z-scores for 200 and 400 shoppers:

z(200) = (200 - 505) / 115 = -2.65
z(400) = (400 - 505) / 115 = -0.91

Next, we can use a standard normal distribution table or calculator to find the area between these two z-scores. The probability is:

P(-2.65 < z < -0.91) = 0.1678

Therefore, the probability that there are between 200 and 400 shoppers at the grocery store is 0.1678.


To calculate the probability that there are between 200 and 400 shoppers at the grocery store, we first need to determine the z-scores for those values. We can then use a standard normal distribution table or calculator to find the area between those two z-scores. The result is the probability of interest. In this case, the probability that there are between 200 and 400 shoppers at the grocery store is 0.1678.


The probability that there are between 200 and 400 shoppers at the grocery store is 0.1678. This means that on a random day, there is a 16.78% chance that the number of shoppers at the grocery store will fall between 200 and 400.

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Answer:

See below

Step-by-step explanation:

Find the value of X In 10 X + 2Y = 12 Y + 20

Find the value of 3 ^ 4

Find the value of - ( 10 J + 2 Y )

Find the value of ( 6 X - 3Y ) ( -2 )

Find the value of 4 P ( 8 P - 9 Q)

Find the value of X In 12 X + 3Y + 16 X + 9 Y = 40

Find the value ½ ( 10 x + 20 y )

Find the value 24 abc /12 ab

Answer:

A 500 grain arrow moving at 260 fps has a kinetic energy of 75.04 ft-lbs and a momentum of . 577 slugs*. A 700 grain arrow moving at 175 fps has a kinetic energy of 47.59 ft-lbs and a momentum of . 544 slugs*.

Answer:

(a)

\(\begin{array}{ccc}{} & {W} & {w} & {w} & {Ww } & {ww } & {w} & { Ww} & {ww } \ \end{array}\)

(b)

\(White = 50\%\)

\(Yellow = 50\%\)

Step-by-step explanation:

See attachment for initial punnet square

Solving (a): Complete the square

Initially, we have:

\(\begin{array}{ccc}{} & {W} & {w} & {w} & { } & { } & {w} & { } & { } \ \end{array}\)

To complete the square, we simply write the letter at the column and the letter at the row in each cell;

So, we have:

\(\begin{array}{ccc}{} & {W} & {w} & {w} & {Ww } & {ww } & {w} & { Ww} & {ww } \ \end{array}\)

Solving (b): Percentage of each

From the question, we understand that W are dominant to w.

So:

\(Ww = White\)

\(ww = Yellow\)

From (a) above

\(Ww = 2\)

\(ww = 2\)

\(Total = 4\)

So, the percentage of each is:

\(White = \frac{Ww}{Total} * 100\%\)

\(White = \frac{2}{4} * 100\%\)

\(White = 0.5 * 100\%\)

\(White = 50\%\)

\(Yellow = 100\% - White\) --- Complement rule

\(Yellow = 100\% - 50\%\)

\(Yellow = 50\%\)

Ultimately, the specific goal for Atlas will depend on its unique circumstances, financial position, and growth objectives.

Setting a realistic goal for Atlas to reduce outstanding amounts each month depends on various factors, including the company's financial situation, industry norms, and specific objectives. However, a common approach is to aim for a consistent reduction in outstanding amounts over time while considering practical limitations and sustainability.

One possible goal could be to target a percentage reduction in outstanding amounts each month. This could be based on factors such as historical data, industry benchmarks, and the company's financial capabilities. For example, Atlas could set a goal of reducing outstanding amounts by 5% each month.

Alternatively, Atlas could establish a specific dollar amount as a target for reduction. This could be based on the company's financial goals, cash flow projections, and outstanding debt levels. For instance, Atlas could aim to reduce outstanding amounts by $10,000 each month.

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There are 5,040 permutations of the sequence 's' with the first number being 4 and the eighth number being 5.


Since the first and eighth numbers are fixed (4 and 5), we need to determine the permutations for the remaining 6 numbers. There are 6! (6 factorial) ways to arrange these numbers, as each position can be filled by any of the remaining numbers. The formula for the number of permutations is:

Permutations = 6! = 6 × 5 × 4 × 3 × 2 × 1 = 720

However, we must also account for the repetition of the numbers 4 and 5 in the sequence. Since there are two instances of each number (one at the beginning and one at the end), we must multiply the number of permutations by 2! for both 4 and 5:

Adjusted Permutations = 720 × 2! × 2! = 720 × 2 × 2 = 2,880


Taking into account the fixed positions of the numbers 4 and 5 and their repetition in the sequence, there are a total of 2,880 permutations of the sequence 's' with the first number being 4 and the eighth number being 5.

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Answer:

t=0.57h

Step-by-step explanation:

Answer:

\(given \: x = - \frac{1}{7} \)

\(x {}^{2} + \frac{1}{x {}^{2} } \)

\(( - \frac{1}{7} ) {}^{2} + \frac{1}{ ( - \frac{1}{7} ) {}^{2} } \)

\( \frac{1}{49} + \frac{1}{ \frac{1}{49} } \)

\( \frac{1}{49} + \frac{1 \times 49}{1} \)

\( \frac{1}{49} + 49\)

\( \frac{2402}{49} \: or \: 49.02\)

Answer:

The answer is 112.5

Step-by-step explanation:

the volume in the first octant bounded by\(y^2=4−x\) and y=2z is pi/36 sqrt(3).

(1) To find the volume in the first octant bounded by the surfaces \(y^2 = 4 - x\) and y = 2z, we can set up a triple integral in cylindrical coordinates.

First, we need to determine the bounds for our variables. Since we are working in the first octant, we know that 0 <= z, 0 <= theta <= pi/2, and 0 <= r.

Next, we need to find the equation for the upper and lower bounds of z in terms of r and theta. We can start with the equation \(y^2 = 4 - x\) and substitute y = 2z to get:

\((2z)^2 = 4 - x\)

\(4z^2 = 4 - x\)

\(x = 4 - 4z^2\)

We can then use this equation along with the equation z = y/2 to get the bounds for z:

\(0 < = z < = (4 - x)^(1/2)/2 = (4 - 4z^2)^(1/2)/2\)

Squaring both sides, we get:

\(0 < = z^2 < = (1 - z^2)/2\)

\(0 < = 2z^2 < = 1 - z^2\)

\(z^2 < = 1/3\)

So the bounds for z are:

\(0 < = z < = (1/3)^(1/2)\)

Finally, we can set up the triple integral in cylindrical coordinates:

V = ∫∫∫ r dz dtheta dr

with bounds:

0 <= r

0 <= theta <= pi/2

\(0 < = z < = (1/3)^(1/2)\)

and integrand:

r

So the volume in the first octant bounded by y^2=4−x and y=2z is:

V = ∫∫∫ r dz dtheta dr

= ∫ from 0 to\((1/3)^(1/2) ∫ from 0 to pi/2 ∫ from 0 to r r dz dtheta dr\)

= ∫ from 0 to\((1/3)^(1/2) ∫ from 0 to pi/2 r^2/2 dtheta dr\)

= ∫ from 0 to\((1/3)^(1/2) r^2 pi/4 dr\)

\(= pi/12 (1/3)^(3/2)\)

= pi/36 sqrt(3)

Therefore, the volume in the first octant bounded by\(y^2=4−x\) and y=2z is pi/36 sqrt(3).

(2) To find the volume bounded by z = x^2 + y^2 and z = 4, we can use a triple integral in cylindrical coordinates.

First, we need to determine the bounds for our variables. Since we are working in the region where z is bounded by \(z = x^2 + y^2\) and z = 4, we know that 0 <= z <= 4.

Next, we can rewrite the equation \(z = x^2 + y^2\) in cylindrical coordinates as \(z = r^2.\)

So the bounds for r and theta are:

0 <= r <= 2

0 <= theta <= 2pi

And the bounds for z are:

\(r^2 < = z < = 4\)

Finally, we can set up the triple integral in cylindrical coordinates:

V = ∫∫∫ r dz dtheta dr

with bounds:

0 <= r <= 2

0 <= theta <= 2pi

\(r^2 < = z < = 4\)

and integrand: 1

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A: The range of the function f(x) is (-3,∞).

B: The horizontal asymptote for y=2^(x+1)−3 is y=-3, the vertical and horizontal asymptote for y=10/x is x=0 and y=0 respectively.

C: The end behaviour of y=2^(x+1)−3 is [x→∞,x→-∞] = [f(x)→∞,f(x)→-3] and the end behaviour of y=10/x is [x→∞,x→-∞] = [f(x)→0,f(x)→0].

What is a function?

In mathematics, a function is a unique arrangement of the inputs (also referred to as the domain) and their outputs (sometimes referred to as the codomain), where each input has exactly one output and the output can be linked to its input.

The set of values of the dependent variable for which a function is defined is known as the range of the function.

The range of an exponential function of the form c·n^(ax+b) + k is f(x) > k.

So, the range of function {2^(x+1)}-3 is f(x)>-3.

The range of function 10/x is (-∞,+∞).

So, the range for system of function becomes (-3,+∞).

The line x=L is a vertical asymptote of the function y=2^(x+1)−3, if the limit of the function (one-sided) at this point is infinite.

In other words, it means that possible points are points where the denominator equals 0 or doesn't exist.

So, find the points where the denominator equals 0 and check them.

As it can be seen, there are no such points, so this function doesn't have vertical asymptotes.

Line y=L is a horizontal asymptote of the function y=f(x), if either limx→∞f(x)=L or limx→−∞f(x)=L, and L is finite.

Calculate the limits -

limx→∞(2x+1−3)=∞

limx→−∞(2x+1−3)=−3

Thus, the horizontal asymptote is y=−3.

The line x=L is a vertical asymptote of the function y=10x, if the limit of the function (one-sided) at this point is infinite.

In other words, it means that possible points are points where the denominator equals 0 or doesn't exist.

So, find the points where the denominator equals 0 and check them.

x=0, check:

limx→0+(10x)=∞

Since the limit is infinite, then x=0 is a vertical asymptote.

Line y=L is a horizontal asymptote of the function y=f(x), if either limx→∞f(x)=L or limx→−∞f(x)=L, and L is finite.

Calculate the limits:

limx→∞(10x)=0

limx→−∞(10x)=0

Thus, the horizontal asymptote is y=0.

The end behaviour of a function f(x) describes the behaviour of the function as x approaches +∞ and x approaches -∞.

The end behaviour of y=2^(x+1)−3 is as x approaches +∞, f(x) approaches +∞ and x approaches -∞, f(x) approaches -3.

The end behaviour of y=10/x is as x approaches +∞, f(x) approaches 0 and x approaches -∞, f(x) approaches 0.

Therefore, the range, asymptotes and end behaviour is found.

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Answer:

It's quite easy

Step-by-step explanation:

people less than 30 years = frequency of people 0 to 15 + 15 to 30 = 8+15 =23

Therefore there are 23 people less than 30 years old.

pls mark me as brainliest pls.

After 21 years, the amount in the account would be approximately $2160 to the nearest dollar.

To find out how much money would be in the account after 21 years, we can use the concept of compound interest.

Given that the money in the account doubles every 9 years, we can calculate the number of doubling periods within 21 years:

Number of doubling periods = 21 years / 9 years = 2.333 (approximately)

Since we can't have a fraction of a doubling period, we need to consider that there are 2 doubling periods within 21 years.

Now, let's calculate the final amount in the account using the formula for compound interest:

Final amount = Initial amount * (1 + interest rate)^(number of doubling periods)

In this case, the initial amount is $540 and the interest rate is 100% because the money doubles. The number of doubling periods is 2.

Final amount = $540 * (1 + 1)^(2)

Final amount = $540 * (2)^2

Final amount = $540 * 4

Final amount = $2160

Therefore, after 21 years, the amount in the account would be approximately $2160 to the nearest dollar.

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