Answer: C. Trial 3
Explanation:
Trial 1 and 2 equal 1.5, Trial 3 equals 1 and Trial 4 equals 3. Trial 3 is the smallest current .
The trial for which the students would measure the smallest current is the circuit is trial 2 and trial 3.
To know the trial which generates the smallest current, we need to determine the current in each trial.
Since current I = V/R where V = voltage and R = resistance.
For trial 1, V = 1.5 V and R = 200 Ω
So, I = 1.5 V/200 Ω
= 0.0075 A
= 7.5 mA
For trial 2, V = 1.5 V and R = 100 Ω
So, I = 1.5 V/100 Ω
= 0.015 A
= 15 mA
For trial 3, V = 3 V and R = 200 Ω
So, I = 3 V/200 Ω
= 0.015 A
= 15 mA
For trial 4, V = 3 V and R = 100 Ω
So, I = 3 V/100 Ω
= 0.03 A
= 3 mA
Trial 2 and trial 3 both produce a the smallest current of 15 mA.
So, the trial for which the students would measure the smallest current is the circuit is trial 2 and trial 3.
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whag are the major ways of keeping the eyes healthy SUB:HEALTH
Answer:
Eat green vegetables
Wash your face with clean water
Eat the food containing vitamin A
Go to the clinic once a week for your eye check up
Thanks for the question dear!
Enjoy your day ☺️
HELP I DON'T PAY ATTENTION ENOUGH
Answer:
I think 1 is d and 2 is A
Explanation:
but I may be wrong and I am so sorry if I am
Answer: Well the first one is D. The second one would be A because if you do the research and eliminate the other ones, these answers would have to be the correct ones following the reading and checking websites
Explanation:
which is the fastest moving component in the electropherogram?
Answer:
Y
Explanation:
I had this question and y was right .
What is the relationship between temperature and kinetic energy?
Answer:
temperature is the average kinetic energy of the particles of matter. the hotter something is the more kinetic energy it has.
Explanation:
Four friends, a, b, c, and d are standing varying distances away from a speaker which is producing sound waves. an illustration of a point labeled speaker with concentric circles spreading out from it. every other circle is 1 more meter away from the source. 1 m is labeled a, 2 m is labeled b, 3 m is labeled c and 4 m is labeled d. which person will most likely hear the loudest sound? a b c d
The answer is a. Because person A is closest to the speaker, so they will hear the loudest sound.
What is the frequency of the sound waves? The frequency of a sound wave is the number of complete wave cycles that occur in one second. It is measured in hertz (Hz), which is equal to one cycle per second. The frequency of sound waves is determined by the number of vibrations per second that the sound wave produces. A higher frequency sound wave has a higher pitch and a lower frequency sound wave has a lower pitch. For example, the frequency of a middle C note on a piano is approximately 262 Hz. This means that the sound wave produces 262 complete cycles per second. Generally, humans can hear sound frequencies between 20 Hz and 20,000 Hz.
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Answer:A
Explanation:
A is correct
At rest, a car's horn has a frequency of
395 Hz. Car A passes car B on the street
in the same direction. If car A is traveling
at 22.0 m/s and car B is traveling
at 19.5 m/s, what frequency does
car B hear when car A honks?
(Speed of sound = 343 m/s)
(Unit = Hz)
The frequency heard by car A is determined as 398.4 Hz.
What is the frequency heard by car A?
The frequency heard by car A is determined by applying the following equation.
f = fs(v - v₀) / (v - vs)
where;
v is the speed of sound = 343 m/sv₀ is the speed car B = 19.2 m/svs is the speed of car A = 22 m/sfs is the frequency of car A = 395 Hzf is the frequency of car B = ?f = 395(343 - 19.2) / (343 - 22)
f = 395(1.0087)
f = 398.4 Hz
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pls help if u can!!! i hate physics ughhh
a model rocket is launched horizontally from the same spot on the top of the 30.0 meter-tall building, but this time with an initial velocity of 22.0 meters per second. Predict if the rocket will hit the other 30.0-meter-tall building that is 40.0 meters away on its upper half or lower half, and perform a calculation to support your claim.
would I use the horizontal velocity equation????? ugh
Answer:
The rocket hit the top half of the building.
Explanation:
Here is the formula for displacement
\(x(t)=\frac{at^{2} }{2}vt\)
Because the projectile is being launched at zero degrees, all of its velocity is in the horizontal direction and so there is no initial velocity for the fall, therefore
\(h=\frac{at^{2} }{2}\)
\(2h=at^{2}\)
\(\frac{2h}{a}=t^{2}\)
\(\sqrt{|\frac{2h}{a}| } =t\)
Now that we have the time taken for the object to fall, we can use it to find d by applying the displacement formula again. In this case we will remove the initial term because the acceleration is zero in the horizontal direction. Therefore
\(d=vt\)
\(d=v*\sqrt{|\frac{2h}{a}| }\)
\(d=22*\sqrt{|\frac{2*30}{9.81}| }\)
\(d=54.41\)
If there wasn't a building in the way the displacement in the x direction is 54.41.
\(y=(tan0*40)-[\frac{-9.81}{2(22*cos0)^{2}}]40^{2}\)
\(y=16.21\)
Like you said the building is 30 meters tall. You were looking to find out is it was going to hit the top or bottom half.
\(15 < 16.21\)
So it hit the top half of the other building.
People can snorkel down to a depth of 1.6 meters. This means that the additional pressure on the air in their lungs is roughly a. 19 000 Pa. b. 1 8000 N. c. 19 600 N. d. 800 ATM. e. 15 700 N/m^2
The additional pressure on the air in their lungs when snorkeling down to a depth of 1.6 meters when calculated using the hydrostatic pressure formula is option e) 15,700 N/m².
Using hydrostatic pressure formula:
P = ρgh
Where:
P is the pressure,
ρ is the density of the fluid (in this case, water),
g is the acceleration due to gravity, and h is the depth.
The density of water is approximately 1000 kg/m³, and the acceleration due to gravity is approximately 9.8 m/s².
Plugging in the values:
P = (1000 kg/m³) * (9.8 m/s²) * (1.6 m)
Calculating this, we get:
P = 15,680 Pa
Therefore, the additional pressure on the air in their lungs when snorkeling down to a depth of 1.6 meters is approximately 15,680 Pa. Hence, the correct answer is option e) 15,700 N/m².
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(310-60(A)) Thermal resistivety is the reciprocal of thermal conductivity; it is designated Rho and expressed in units of ______.
Thermal resistivity is the reciprocal of thermal conductivity; it is designated Rho and expressed in units of ohm-meters (Ω⋅m).
Thermal resistivity, also known as thermal resistivity coefficient, is a measure of the resistance of a material to the flow of heat. It is expressed in units of kelvin-meters per watt (K·m/W) and is the reciprocal of thermal conductivity, which is the measure of a material’s ability to transfer heat. Thermal resistivity is a property of a material that can be used to predict its performance in applications where significant temperature gradients exist. On the other hand, the lower the thermal resistivity, the higher the rate of heat transfer.
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a diverging lens has a focal length of magnitude 20.0 cm. (a) locate the images for object distances of (i) 40.0 cm, (ii) 20.0 cm, and (iii) 10.0 cm. for each case, state whether the image is (b) real or virtual and (c) upright or inverted. (d) for each case, find the magnification.
It is only necessary to know the direction of two of the three rays in order to graphically depict the formation of an image in a thin lens with virtual image.
(i) The one that strikes the lens perpendicular to the optical axis of the lens is one of them. When this is refracted in the lens, the image focus will not be affected. Its trajectory won't be altered by this.
(ii) The third and final one is the one that crosses the object focus (or its extension does), which, following refraction, will move in a direction parallel to the optical axis of the lens.
Accordingly, depending on how an object or body is positioned in relation to the lens, one type of image will generally be formed in the lenses. The image will always be virtual, smaller than the body, and to the right in divergent lenses.
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2. A barista uses the expression 4.25v + 2.65g to calculate her profit when she sells v, ven
and g, grande, beverages. What is the barista's profit, in dollars, when she sells 36 venti an
44 grande beverages?
the loudness of a sound is determined by the __________, or height, of the sound wave.
Answer: Aplitude
Explanation: Loudness depends on the amplitude,or height, of sound waves. The greater the amplitude, the louder the sound perceived. Amplitude is measured in decibels.
Answer:
Amplitude
Explanation:
The loudness of a sound is determined by the amplitude of the wave. In terms of the pattern of a transverse wave, amplitude refers to how "high" and "low" the waves go from the center line.
PF
according to the most recent data from satellites making precise measurements of the properties of the cosmic background radiation (cbr) the dark energy makes?
According to the most recent data from satellites making precise measurements of the properties of the cosmic background radiation (CBR), it has been determined that dark energy makes up approximately 68% of the total energy density of the universe.
This means that dark energy is the dominant force driving the acceleration of the expansion of the universe.
The CBR is the afterglow of the Big Bang, and by analyzing its properties, scientists can learn more about the structure and evolution of the universe. The Planck satellite, launched in 2009, has been instrumental in providing high-precision measurements of the CBR and contributing to our understanding of dark energy.
Despite being the dominant force in the universe, dark energy remains a mystery. Its nature and properties are still largely unknown, but it is thought to be a property of space itself rather than a type of matter or energy. Ongoing research and observations will continue to shed light on this elusive phenomenon and deepen our understanding of the universe as a whole.
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Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging (a) from A to B and (b) from A to C?
Answer:
Explanation:
(a) It is given that Joseph jogs on a straight road of 300m in a time interval of 2 minutes and 30 seconds, which is equal to 150seconds. Therefore, when Joseph jogs from point A to point B, he covers a distance of 300m in time of 150seconds. Hence, his average speed is 300m/150s=2ms^−1. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m.
Hence, his average velocity is 300m/150s=2ms^−1
(b) Then it is given that he turns back and points B and jogs on the same road but in the opposite direction for a time interval for 1 minute and covers a distance of 100m.If we consider the whole motion of Joseph, i.e. from point A to point C, then he covers a total distance of 300m+100m=400m. And he covers this total distance in a time interval of 2.5min+1min=3.5min=210s.
Therefore, his average speed for this journey is 400m210s=1.9ms−1.
For the same journey is displacement is equal to the distance between the points A and C,i.e. 300m−100m=200m.
Hence, his average velocity for this case is 200m/210s=0.95ms^−1
A weightless beam supports a weight of 266N down. Find FA up at 3.00 m from this weight and FB up on the other side of this weight at 5.00m from it. Draw the situation.
The given problem can be exemplified using the following diagram:
To determine the value of the unknown force we will add the torques that act upon the point where the force F2 is acting. We will take torques that are clockwise to be negative and counterclockwise to be positive. Adding the torques we get:
\(-(F_1)(3m+5m)+(266N)(5m)=0\)We set the sum equal to zero because we are assuming that the beam is in equilibrium.
Now, we solve the operations:
\(-F_1(8m)+1330Nm=0\)Now, we solve for the force, first by subtracting 1330 Nm from both sides:-
\(-F_1(8m)=-1330Nm\)Now, we divide both sides by -8m:
\(F_1=\frac{-1330Nm}{-8m}\)Solving the operations:
\(F_1=166.25N\)Therefore, the force that is 3 meters away from the weight is 166.25 Newtons. -
Now, to determine the force F2 we will add the forces in the vertical direction taking the forces downwards as negative and upwards as positive:
\(F_1-266N+F_2=0\)Now, we plug in the value of F2:
\(166.25N-266N+F_2=0\)Solving the operations:
\(-99.75N+F_2=0\)Now, we solve for F2 by adding 99.75N to both sides:
\(F_2=99.75N\)Therefore, the force that is 5 meters away must be 99.75 Newtons.
You place a sheet of paper on a 3 beam balance, it has a mass of
3.15g, you then take the paper off the scale and rip it precisely in half.
Into two smaller sheets. You then put both pieces back on the scale,
what should the new mass be? ANswer:
The mass will remain same of 3.15g.
Mass is used in physics to express inertia, a fundamental function of all be counted.
Essentially, it's far a mass of depend's resistance to converting its direction or velocity in reaction to the application of a pressure. The exchange that an implemented pressure produces is smaller the extra mass a body has.
The kilogram, the unit of mass within the international gadget of units, corresponds to 6.62607015 1034 joule seconds the usage of Planck's constant (SI). One joule is produced with the aid of multiplying one kilogram via one square meter in keeping with second.
The kilogram is decided by using exact measurements of Planck's regular given that the second and the meter have formerly been defined in phrases of different physical constants.
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A pinball bangs against a bumper of a pinball machine with a speed of 0.9 m/s. If the ball has a mass of 0.056 kg, what is the ball's kinetic energy?
Saturn’s moon titan has a mass of 1.35 × 10^23 kg. if titan is 1.19 × 10^6 km from saturn, and saturn’s mass is 5.86 × 1026 kg, what is the gravitational force between saturn and its moon?
Answer:The gravitational force equation is Fg=(G*M*m)/r² where, G is the gravitational constant, G=6.67*10^-11 m³/kg*s², M is the mass of Saturn, M=5.86*10^26, m is the mass of Titan, m=1.35*10^23 and r is the distance, r=1.19*10^6 km=1.19*10^9 m. Now we simply input the numbers into the equation:
Fg=(6.67*10^-11)*(5.86*10^26)*(1.35*10^23)/(1.19*10^6)²
Fg=(5.277*10^39)/(1.41*10^18)=3.743*10^21 N
The correct answer is the third one.
Explanation:
9. AM 630 is a station where you can listen to sports. The frequency is 630 khz (or
630,000 hz). What is the wavelength?
Help
Answer:
475861.044 is the wavelength
Explanation:
wavelength= speed/frequency
speed of light equals 299,792,458
and the frqeuncy equals 630
so 299,792,458/630=475861.044 equals the wavelength
The wavelength of the waves is equal to 476.2 m
What are frequency and wavelength?The frequency of a wave can be described as the number of oscillations in one second. The frequency has S.I. units represented as per second or hertz.
Wavelength is the distance between the two adjacent points in phase with each other. Two adjacent crests or troughs are separated by a distance of a single wavelength.
The relationship between frequency, speed of the wave, and wavelength are:
c = νλ
Given, the frequency of the wave, ν = 630 kHz = 630 ×10³ s⁻¹
Then the speed of all electromagnetic waves including radio waves is equal to the speed of light, c = 3 ×10¹⁰ m/sc
The wavelength of the waves can be determined from the relationship:
λ = c/ν = 3× 10⁸/ 630 ×10³
λ = 476.2 m
Therefore, the wavelength of the wave is 476.2 m.
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you want the maximum compression of the spring to be 0.31 m . what must be the force constant of the spring?
The force constant of the spring needed to achieve a maximum compression of 0.31 m is 31.71 N/m.
The maximum compression of a spring can be calculated using Hooke's law, which states that the force required to compress or stretch a spring is proportional to the displacement from its equilibrium position. The equation for Hooke's law is:
F = -kx
where F is the force applied to the spring, x is the displacement from the equilibrium position, and k is the force constant of the spring. The negative sign indicates that the force is in the opposite direction to the displacement.
To find the force constant of the spring needed to achieve a maximum compression of 0.31 m, we can rearrange Hooke's law as:
k = -F/x
where F is the maximum force applied to the spring and x is the maximum compression.
Substituting the values given, we get:
k = -F/0.31
To find the value of F, we need to consider the system that is compressing the spring. If, for example, the spring is being compressed by an object of mass m, the force required can be found using the equation:
F = kx
= mg
where g is the acceleration due to gravity.
Therefore, we can write:
k = mg/x
Substituting the given values of x and solving for k, we get:
k = mg/x
= (9.81 m/s^2)(m)/(0.31 m)
= 31.71 N/m
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What is the ideal banking angle (in degrees) for a gentle turn of 2.00 km radius on a highway with a 125 km/h speed limit (about 78 mi/h), assuming everyone travels at the limit
An "ideal" banking angle assumes no friction is required to keep a car on the road as it turns. Let θ denote the banking angle, and consult the attached free-body diagram for a car making the turn. There are only 2 relevant forces acting on the car,
• the normal force with magnitude n
• the car's weight with magnitude w
and the net force points toward the center of the circle made by the turn, with centripetal acceleration
a = (125 km/h)² / (2.00 km) = 7812.5 km/h² ≈ 0.603 m/s²
Split up the forces into components acting perpendicular (⟂) and parallel (//) to the banked curve, so that by Newton's second law,
∑ F (⟂) = N + W (⟂) = m a (⟂)
and
∑ F (//) = W (//) = m a (//)
Let the direction of N be the positive perpendicular axis, and down the incline and toward the center of the circle the positive parallel axis. The net force vector and acceleration both make an angle θ with the banked curve, and W makes the same angle with the negative perpendicular axis, so that the equations above reduce to
N - m g cos(θ) = m a sin(θ)
and
m g sin(θ) = m a cos(θ)
The second equation is all we need at this point to find the ideal θ. The mass m cancels out, and we can solve for θ to get
tan(θ) = a/g ≈ (0.603 m/s²) / (9.80 m/s²) ≈ 0.0615
→ θ ≈ 3.52°
Determine how the electric field is different from that of the positive charge. Describe the differences in the electric field due to a negative charge as compared to a positive charge
The difference between the electric field and positive chargeAn electric field refers to a region where an electric charge experiences an electric force due to the presence of other charges.
A positive charge in an electric field is repelled from positively charged objects and attracted to negatively charged objects. Its direction is the opposite of the electric field because it is positively charged. An electric field is also the force exerted on a unit charge, while a positive charge is an object that has excess protons in its nucleus. The difference in the electric field due to a negative charge compared to a positive charge
A negative charge is an object that has excess electrons in its nucleus, which creates an attractive force between it and positively charged objects. Negatively charged objects are attracted to positively charged objects in an electric field. The direction of the electric field is the same as the direction of the electric force that acts on a negative charge.
A negative charge in an electric field will always be attracted to positively charged objects and repelled from negatively charged objects, which is the opposite of a positive charge. Hence, the difference in the electric field due to a negative charge compared to a positive charge is that a negative charge is attracted to positive charges, while a positive charge is repelled by other positive charges and attracted to negative charges.
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suppose you lift a stone that has a mass of 5.9 kilograms off the floor onto a shelf that is 0.5 meters high. how much work have you done?
Work done to lift the stone of mass 5.9 kg is 28.91 J.
The work done through pressure is made of the displacement and the component of the carried-out force of the object inside the direction of displacement. whilst we push a block with a few pressure ' F ' the body movements with a few accelerations, paintings are carried out. paintings executed is written as W = F.
The paintings executed by using pressure are defined to be manufactured from the aspect of the force in the path of the displacement and the significance of this displacement. formula. work can be calculated by multiplying pressure and Distance within the course of force as follows. W = F × d.
Work is achieved whenever a pressure actions something over a distance. you can calculate the strength transferred, or work carried out, by multiplying the pressure via the space moved in the route of the pressure.
Calculation:-
mass = 5.9
g = 9.8 m/s
f = 0.5 m
work done = mgh
= 5.9 × 9.8 × 0.5 J
= 28.91 J
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An ion rocket engine produces 1 newton of thrust. What acceleration can it give to a space probe with a mass of 1000kg?.
According to the thrust force, the acceleration is 0.001 m/s².
We need to know about force to solve this problem. According to second Newton's Law, the force applied to an object will be proportional to mass and acceleration. Hence, it can be written as
F = m . a
where F is force, m is mass and a is acceleration
From the question above, we know that
F = 1 N
m = 1000 kg
By substituting the given parameters, we can calculate the acceleration
F = m . a
1 = 1000 . a
a = 1/1000 m/s²
a = 0.001 m/s²
Hence, the acceleration is 0.001 m/s².
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calculate the magnitude of the angular momentum of the earth in a circular orbit around the sun.
The magnitude of the angular momentum of the Earth in a circular orbit around the sun is 1.91 x 10^40 kg m^2/s.
To calculate the magnitude of the angular momentum of the Earth in a circular orbit around the sun, angular momentum, L = I * w where L is the angular momentum, I is the moment of inertia, and w is the angular velocity.
For a circular orbit, the angular velocity is given by, w = v / r, where v is the speed of the Earth in its orbit and r is the radius of the orbit.
The moment of inertia of a rotating object is given by,
I = 2/5 * m * r^2
where m is the mass of the Earth and r is the radius of the orbit.
We can find the speed of the Earth in its orbit using the formula,
v = 2 * pi * r / T
where T is the period of the Earth's orbit around the sun.
The radius of the Earth's orbit is approximately 1.496 x 10^11 meters, and the period of the Earth's orbit is approximately 365.25 days or 31,557,600 seconds.
Using these values, we can calculate the speed of the Earth in its orbit.
v = 2 * pi * 1.496 x 10^11 / 31,557,600 = 29,783 meters per second
We can also calculate the moment of inertia of the Earth.
I = 2/5 * 5.972 x 10^24 kg * (1.496 x 10^11 meters)^2 = 9.70 x 10^37 kg m^2
L = I * w = (9.70 x 10^37 kg m^2) * (29,783 meters per second / 1.496 x 10^11 meters) = 1.91 x 10^40 kg m^2/s
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derive mean in science
Explanation:
derive its name from a Native American word meaning wild onion
An object is thrown upward with an initial velocity of 32.1 m/s. When the object reaches it maximum height, it is true of the acceleration, a, and the velocity, v, that:
both its acceleration and velocity are zero
both its acceleration and velocity change sign
velocity is equal to zero, but acceleration is not
acceleration is equal to zero, but velocity is not
None of the above.
When the object reaches its maximum height, it is true that: velocity is equal to zero, but acceleration is not.
At the maximum height, the object's upward velocity has been reduced to zero due to the acceleration caused by gravity (approximately -9.8 m/s²) acting against it. However, the acceleration due to gravity still exists, continuing to affect the object as it starts to fall back down.
We know that,
the initial velocity of the object thrown up (u) = 32.1 m/s
When the object reaches its maximum height,
its final velocity (v) = 0
acceleration against gravity (a) = -9.81 m/s²
Therefore, the statement "velocity is equal to zero, but acceleration is not" is true.
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If a tennis ball has a velocity of 18 m/s and a momentum of 1.06 kg. m/s, what is the mass of the tennis ball in grams?
Round the answer to two significant figures.
Blank grams
Answer:
59g
Explanation:
The tennis ball with a velocity of 18 m/s and momentum of 1.06 kg m/s then the mass of the tennis ball in grams will be 59 grams (approx) two significant figures.
What is Momentum?Regardless of the frame of reference, momentum is a conserved quantity in any inertial frame, which means that if an enclosed system is not subject to outside influences, its total linear momentum remains constant.
Additionally, momentum is preserved in general relativity, electrodynamics, quantum mechanics, quantum field theory, and special relativity (using a modified formula). It is a manifestation of translational symmetry, one of the basic symmetries of space and time.
According to the question, the given values are :
Velocity, v = 18 m/s
Momentum, p = 1.06 kg m/s
p = m × v
1.06 kg m/s = m × 18 m/s
m = 1.06 / 18
m = 0.0589 kg or
m = 58.9 grams or 59 grams approx in two significant figures.
So, the mass will be 59 grams.
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The quantity "pressure" expressed in terms of the fundamental quantities (mass, length, time) is equivalent to
a. MLT^-1
b. M²L^-1T^-3
c. ML^-T^-2
d. a dimensionless quantity.
The quantity "pressure" expressed in terms of the fundamental quantities (mass, length, time) is equivalent to option c. ML^-T^-2.
This is because pressure is defined as force per unit area, where force is mass times acceleration (MLT^-2) and area is length squared (L^2).
Therefore, pressure can be expressed as (MLT^-2)/(L^2), which simplifies to ML^-T^-2. Option a (MLT^-1) represents the dimension of force, not pressure.
Option b (M²L^-1T^-3) is not a valid unit for pressure, and option d (a dimensionless quantity) is incorrect because pressure does have dimensions.
Therefore, the correct answer is option c. ML^-T^-2.
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a 28 kg box rests on the back of a truck. the coefficient of static friction between the box and the truck bed is 0.334. the acceleration of gravity is 9.81 m/s2 . what maximum acceleration can the truck have before the box slides backward?
The maximum acceleration will be 3.27 meter per second square.
We have given that mass of the box m = 28 kg
Coefficient of static friction u = 0.334
Acceleration due to gravity g = 9.8m/s^2
For maximum acceleration
umg = ma
Cancelling m from both sides we get
ug = a
thus on substituting the values which we have mentioned above we get;
So acceleration will be 9.81 X 0.334 m/s^2
So maximum acceleration will be 3.27 m/s^2
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