Answer:
The troposphere and stratosphere are the only layers where you would find clouds.
Answer: Based on the information provided, the only layers where you would find clouds are the troposphere and the stratosphere.
The troposphere is the layer of the atmosphere that extends from the Earth's surface to about 8-15 kilometers (5-9 miles) above the Earth. This is the layer where most of the Earth's weather occurs, and it is where you will find clouds, such as cumulus clouds, stratus clouds, and cirrus clouds.
The stratosphere is the layer of the atmosphere that extends from about 15-50 kilometers (9-31 miles) above the Earth. This layer is characterized by a rise in temperature with altitude, and it is where you will find clouds called stratospheric clouds, such as nacreous clouds and polar stratospheric clouds.
The mesosphere is the layer of the atmosphere that extends from about 50-85 kilometers (31-53 miles) above the Earth. This layer is characterized by a decrease in temperature with altitude, and it is generally too cold and dry to support the formation of clouds.
The thermosphere is the layer of the atmosphere that extends from about 85 kilometers (53 miles) to the edge of space. This layer is characterized by a rise in temperature with altitude, and it is generally too thin and diffuse to support the formation of clouds.
I hope this helps! Let me know if you have any other questions.
in a two coil system the mutual inductance depends on
The mutual inductance (M) in a two-coil system depends on the number of turns in each coil (N₁ and N₂), the permeability of the medium between the coils (µ), and the geometry of the coils.
Mutual inductance is a measure of the ability of one coil to induce an electromotive force (emf) in the other coil when a current changes in one of them. It depends on several factors.
First, the number of turns in each coil plays a role. The greater the number of turns, the stronger the magnetic field produced by the coil, resulting in a higher mutual inductance.
Second, the permeability of the medium between the coils is important. The permeability determines how easily magnetic flux lines pass through the medium. A higher permeability leads to stronger coupling between the coils and, consequently, higher mutual inductance.
Lastly, the physical arrangement and geometry of the coils affect the mutual inductance. The proximity and alignment of the coils influence the amount of magnetic flux linking them, thereby impacting the mutual inductance.
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A bowling ball has a mass of 17kg the ball leaves a bowlers hand at a speed of 7.0m/s calculate the kinetic energy of the bowling ball
The kinetic energy of an object can be calculated using the formula: \(KE = (1/2) * mass * velocity^2\). In this case, the mass of the bowling ball is given as 17 kg and the velocity is given as 7.0 m/s.
First, let's plug in the values into the formula:
KE = (1/2) * 17 kg * \((7.0 m/s)^2\)
To simplify the calculation, let's first square the velocity:
KE = (1/2) * 17 kg * 49.0\(m^2/s^2\)
Now, let's multiply the mass and the squared velocity:
KE = 8.5 kg * 49.0\(m^2/s^2\)
Finally, let's multiply the values:
KE = 416.5 kg *\(m^2/s^2\)
The kinetic energy of the bowling ball is 416.5 kg * \(m^2/s^2.\)
Therefore, the kinetic energy of the bowling ball is 416.5 joules.
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PLEASE HELP!!! No files please. 20 POINTS up for grabs!
Two positively charged objects are separated by a large distance. One of the
positively charged objects is replaced by a negatively charged object, and the two
objects are moved closer to each other.
Which of the following occurs in this situation?
a.
The attractive force becomes a repulsive force, which increases as the objects move closer
together.
B.
The repulsive force becomes an attractive force, which increases as the objects move closer to
each other.
C.
The attractive force becomes a repulsive force, which decreases as the objects move closer to
each other.
D.
The repulsive force becomes an attract
creases as the objects move closer to
each other.
Answer: B
Explanation: positive and negative charges attract each other and get stronger as they get closer
How do i get the o's 7x+69
The Complete Question:
How do I get one solution of 7x + 69 = 1 ?
Value of x in 7x + 69 = 1 is ( - 9.71 ).
Since the degree of variable is 1, the equation will have only one solution.
The degree of variable is defined at the value of power of the variable.
Using Algebra Equation,
= 7x + 69 = 1
= 7x = 1 - 69
= 7x = ( - 68)
= x = ( - 68) / 7
= x = ( - 9.71 )
Thus, the value of x in 7x + 69 = 1 is ( - 9.71 ) and this is the only solution to single degree algebraic equation.
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A wave is moving at 300m/s and has a frequency of 25Hz, what is the wavelength?
Answer:
12 metre
Explanation:
Wavelength = Velocity / Frequency
Wavelength = 300m/s / 25 Hz
Wavelength = 12 metre
if normal range of motion of the shoulder is not possible and the attempt causes the shoulder to shrug or hike, the injury is
If normal range of motion of the shoulder is not possible and the attempt causes the shoulder to shrug or hike, the injury is likely a rotator cuff tear.
When the normal range of motion of the shoulder is restricted, and attempting to move the shoulder causes it to shrug or hike, it is indicative of a potential rotator cuff tear.
The rotator cuff is a group of muscles and tendons that surround the shoulder joint, providing stability and facilitating movement. It helps to keep the head of the upper arm bone (humerus) securely within the shoulder socket.
A rotator cuff tear can occur due to various reasons, such as trauma, repetitive motion, or degeneration with age. When a tear occurs, it can lead to pain, weakness, and limited range of motion in the shoulder.
The inability to move the shoulder through its normal range without causing shoulder shrugging or hiking suggests that the rotator cuff's integrity is compromised.
It is important to consult a healthcare professional for a proper diagnosis and appropriate treatment of a suspected rotator cuff tear. Treatment options may include rest, physical therapy, medication, or in severe cases, surgical intervention.
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an ac power generator produces 52.8 a (rms) at 3630 v (rms). (a) find the power produced by this generator.
(b) If this power is transmitted through a long-distance power line that has a resistance of 11.3 Ω, find the power dissipated as heat in the power line.
(a) The power produced by the AC power generator is approximately 193 kW.b
(b) If this power is transmitted through a long-distance power line that has a resistance of 11.3 Ω, The power dissipated as heat in the power line is approximately 448.6 kW.
The given values of RMS current and voltage are,
Irms = 52.8 A and Vrms = 3630 V.
Power produced by an AC power generator is given by;
P = Irms^2 × R
Here, the resistance of the generator is R = Vrms/Irms = 3630/52.8 ≈ 68.75 Ohms
Putting the value of R in the above equation, we get;
P = (52.8)^2 × 68.75P = 193022.4 W or 193 kW (approx)
Thus, the power produced by the AC power generator is approximately 193 kW.b)
The resistance of the long-distance power line is R = 11.3 Ohms.
Power dissipated as heat in the power line is given by;
P = I^2 × R
Here, the current that is flowing through the power line is;
I = V/R = Vrms /(R √2) = 3630/(11.3 √2) ≈ 190.98 A
Putting the value of I in the above equation, we get;
P = (190.98)^2 × 11.3P ≈ 448634 W or 448.6 kW
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A robot that is exploring the surface of Mars has a mass of 136 kg. If the gravitational force acting on the robot is 504.6 N downward, what is the free-fall acceleration on Mars?
The free-fall acceleration on Mars is 3.71 m/s²
What do you mean by free fall?A body is said to be in freefall when it only moves in relation to the Earth's gravity. An external force exerted on the ball will cause its motion to accelerate. Gravitational acceleration is another name for this rate of free fall.According to Newton's second law of motion, force (F) = mass (m) times acceleration, an item in free fall will move with an acceleration (a). We can use a little mathematics to determine the object's acceleration in terms of the net external force and the object's mass (a = F / m).Given :
gravitational force acting on the robot is 504.6 N
F= 504.6 N
mass of the robot = 136 kg
a = F/ m
= 504.6/ 136 =3.71 m/s²
The free-fall acceleration on Mars is 3.71 m/s²
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A billiard cue ball with a mass of 0.60 kg and an eight ball with a mass of 0.55 kg are rolled toward each other. The cue ball has a velocity of 3.0 m/s heading east and the eight ball has a velocity of 2.0 m/s heading north. After the collision, the cue ball moves off at a velocity of 2.0 m/s 40⁰ north of east.
What is net momentum of the system above before and after the collision?
What north component (y-component) of the momentum of the cue ball after collision?
Using your responses above, determine the final velocity of the eight ball:
The net momentum of the system before the collision is given by the expression: Momentum before = m1v1 + m2v2where m1 and v1 are the mass and velocity of the cue ball respectively and m2 and v2 are the mass and velocity of the eight ball respectively.
Substituting in the given values, we have:Momentum before = (0.6 kg) (3.0 m/s) + (0.55 kg) (2.0 m/s) = 1.80 kg m/s + 1.10 kg m/s = 2.90 kg m/s. The net momentum of the system after the collision is given by the expression:Momentum after = m1v1' + m2v2'where v1' and v2' are the velocities of the cue ball and eight ball respectively after the collision.
Substituting in the given values, we have: Momentum after = (0.6 kg) (2.0 m/s cos 40°) + (0.55 kg) (v2')Momentum after = 1.20 cos 40° kg m/s + (0.55 kg) (v2')Momentum after = 0.92 kg m/s + 0.55 kg v2'Conservation of momentum principle states that the total momentum before the collision must equal the total momentum after the collision: Momentum before = Momentum after2.90 kg m/s = 0.92 kg m/s + 0.55 kg v2'Solving for v2', we get:v2' = (2.90 kg m/s - 0.92 kg m/s) / 0.55 kgv2' = 4.71 m/s.
The north component (y-component) of the momentum of the cue ball after collision is given by the expression:py = m1v1' sin θSubstituting the given values, we have:py = (0.6 kg) (2.0 m/s sin 40°)py = 0.78 kg m/sTherefore, the final velocity of the eight ball is 4.71 m/s.
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An airplane is .68 Kilometers long. How many Millimeters long is the plane?
a. 680 mm
b. 6,800 mm
c. 68,000 mm
d. 680,000 mm
Given : Airplane is 0.68 kilometers long
We know that :
⊕ 1 km = 1000 meters
⊕ 1 m = 1000 millimeters
⇒ 1 km = (1000 × 1000) millimeters
⇒ 0.68 km = (0.68 × 1000 × 1000) millimeters
⇒ 0.68 km = 680,000 millimeters
Answer: Airplane is 680,000 millimeters long
If an airplane is 0.68 Kilometers long, the length of the airplane in millimeters would be 680000 Millimeters, therefore the correct answer is option D.
What is a unit of measurement?A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind.
As given in the problem, If an airplane is 0.68 Kilometers long, then we have to find out the length of the airplane in millimeters,
1 kilometers = 1000 meters
1 meter = 100 centimeters
1 centimeters = 10 millieters
As given the length of the plane is 0.68 Kilometers.
0.68 kilometers = 680 meters
0.68 kilometers = 680×100 centimeters
0.68 kilometers = 680×100×10 millimeters
= 680,000 millimeters
Thus, the correct answer is option C.
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What clouds are best associated with thunderstorms?
Answer:
Cumulus Congestus & Cumulonimbus Clouds
Why might a food item such as bread not necessarily be a consumer good in all economic scenarios ?
A sound wave travels to a high wall which is 225m away from the source and is then reflected back to is initial position If the speed of sound in air as 340ms", calculate the time it takes to hear the echo.
Answer:
1.32 (3sf)
Explanation:
total distance the sound wave travel= 225 x 2= 450m
450 ÷ 340= 1.32s
convert 288cm to Meters
Give explanation + formula
Answer:
288 cm is 2.88 meters. This is because each centimeter is 1/100th of a meter, or in other words, each meter is 100 cm. To find out cm-m, divide the amount of cm by 100 and change the unit to m.
Explanation:
formula is cm/100=m
288/100= 2.88m
The process of a nucleus giving off radioactive particles to become more stable is called
Answer:
Radioactive Decay
Explanation:
Reactant X contains 199. 3 J of chemical energy. Reactant Y contains 272. 3 J of chemical energy. Product W contains 41. 9 J of chemical energy. If the reaction loses 111. 6 J of chemical energy as it proceeds, how much chemical energy must product Z contain?
The chemical energy that Product Z contains is 205.5 J.
Given that the chemical energy of Reactant X is 199.3 J, the chemical energy of Reactant Y is 272.3 J, and the chemical energy of Product W is 41.9 J, we need to find the chemical energy of Product Z. If the reaction loses 111.6 J of chemical energy as it proceeds, we can apply the Law of Conservation of Energy:
Initial Energy of Reactant = Final Energy of Product
Mathematically, it can be written as:
Reactant X + Reactant Y - Energy lost in the reaction = Product W + Product Z
Substituting the given values:
199.3 J + 272.3 J - 111.6 J = 41.9 J + Product Z
Simplifying:
359 J - 111.6 J - 41.9 J = Product Z
Product Z = 205.5 J.
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how nonrenewable energy resources uses have changed over the past 30 years?
Answer:
Explanation:
The use of nonrenewable energy resources, such as coal, oil, and natural gas, has changed significantly over the past 30 years. Some key changes include:
Increased use of natural gas: The use of natural gas as an energy source has increased significantly in recent years, due to the development of new technologies that have made it easier and more cost-effective to extract and transport natural gas. This has led to a decrease in the use of coal as an energy source, as natural gas is cleaner and more efficient.Increasing use of renewable energy sources: Over the past 30 years, there has been a growing focus on renewable energy sources, such as wind, solar, and hydro power, as a way to reduce the dependence on fossil fuels and lower greenhouse gas emissions. The growth of renewable energy sources has been supported by government policies, technological advances and decreasing costs.Increase in the use of electric cars: Electric cars are becoming increasingly popular in recent years and this is expected to continue as the technology improves and the cost of batteries decreases. Electric cars are more energy-efficient and have lower emissions than traditional gasoline cars.Changes in oil consumption: The consumption of oil for transportation has decreased over the past 30 years due to more efficient vehicles and more use of biofuels. However, oil consumption for electricity generation and industrial use has remained relatively constant.Overall, the past 30 years have seen a shift away from traditional fossil fuels towards cleaner and more sustainable energy sources, driven by concerns about climate change and environmental degradation.
A student walks to the right 25-m along the 800 hall in 15-s. They turn around and walk 15-m to the left in 8.0-s. Calculate the average speed and the average velocity
Answer:
Explanation:
Total distance covered = 25 + 15 = 40 m
Total time = 15 + 8 = 23 s
Average speed = total distance covered / total time
= 40 / 23
= 1.74 m / s
Total displacement = 25 - 15 = 10 m
Total time = 15 + 8 = 23 s
Average velocity = total displacement / total time
= 10 / 23
= .434 m / s to the right .
The average speed of the student is approximately 1.74 m/s, and the average velocity is approximately -1.74 m/s (to the left).
Given:
Distance to the right = 25 m
Time taken to the right = 15 s
Distance to the left = 15 m
Time is taken to the left = 8.0 s
To calculate the average speed and average velocity, we need to use the following formulas:
Average speed = Total distance traveled ÷ Total time taken
Average velocity = Displacement ÷ Total time taken
Calculate the total distance traveled:
Total distance = Distance to the right + Distance to the left
Total distance = 25 + 15 = 40 m
Calculate the total time taken:
Total time = Time taken to the right + Time taken to the left
Total time = 15 + 8.0 = 23 s
Calculate the average speed:
Average speed = Total distance ÷ Total time
Average speed = 40 ÷ 23 = 1.74 m/s
Calculate the displacement:
Displacement = Final position - Initial position
Displacement = (-15 ) - 25 = -40 m
Calculate the average velocity:
Average velocity = Displacement ÷ Total time
Average velocity = -40 ÷ 23 ≈ -1.74 m/s
So, the average speed of the student is approximately 1.74 m/s, and the average velocity is approximately -1.74 m/s (to the left). The negative sign in the average velocity indicates that the student's net direction is to the left.
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Tessa uses a toy slingshot to launch a tennis ball across the park for her dog to fetch. For her first launch, she
uses 100 N of force. Her second launch uses 200 N of force, and her third launch uses 300 N. Which launch had
the greatest acceleration of the tennis ball?
Answer:
See the explanation below.
Explanation:
To solve this problem we must apply Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration and this force can be calculated by means of the following equation.
F = m*a
where:
F = force [N] (units of Newtons)
m = mass [kg]
a = acceleration [m/s²]
The mass of the tennis ball will always be the same therefore it will never change.
Now clearing a:
\(a=\frac{F}{m}\)
If the mass of the ball remains the same:
\(a = \frac{100}{m} ; a = \frac{200}{m};a =\frac{300}{m}\)
We see that for a force of 300 [N], the acceleration exerted on the ball must be greater. Therefore with the force of 300 [N] the greatest acceleration is achieved.
What happens in a nucleus during beta decay
The numbers of protons increases
The number of neutrons increases
The number of protons decrease
The number of protons plus the number of neutrons decreases
The number of protons plus the number of neutrons decreases
Beta decay occurs when, in a nucleus with too many protons or too many neutrons, one of the protons or neutrons is transformed into the other. In beta minus decay, a neutron decays into a proton, an electron, and an antineutrino: n Æ p + e - +.
The (hypothetical) \( \mathrm{ABC} \) index spot price is currently at 1302 and the continuously compounded riskfree ratais \( 6 \% \) p.a. The 6 -month observed futures price on the index is 1335 . W
The implied annualized risk-free rate of return for holding the futures contract is approximately 8.51%.
In this scenario, the futures price of the ABC index is higher than the spot price, indicating a positive cost of carry. To calculate the implied annualized risk-free rate of return, we can use the formula:
Implied Annualized Risk-free Rate = (Futures Price - Spot Price) / Spot Price * (365 / Time to Expiration)
Given the spot price of 1302, the futures price of 1335, and a 6-month expiration period, we can plug these values into the formula:
Implied Annualized Risk-free Rate = (1335 - 1302) / 1302 * (365 / 0.5)
Calculating the expression yields approximately 0.0851 or 8.51%. This implies that holding the futures contract on the ABC index would yield an annualized risk-free return of 8.51% if the current market conditions persist.
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The above given question is incomplete, below a complete question is written:
The (hypothetical) ABC index spot price is currently at 1302, and the continuously compounded risk-free rate is 6% per annum. The 6-month observed futures price on the index is 1335. What is the implied annualized risk-free rate of return for holding the futures contract?
What would be the final equilibrium temperature if 80.0 g of aluminum at 5.0
∘
C having a specific heat of 0.90 J/g " C is placed in 100.0 g of water having a temperature of 60.0
∘
C ?
∘
C (Do not use scientific notation or units in your answer.)
To determine the final equilibrium temperature, we use the principle of conservation of energy, equating the heat lost by the aluminum to the heat gained by the water, resulting in a final temperature of 24.6°C.
When two substances with different temperatures come into contact, heat transfer occurs until they reach thermal equilibrium, where their temperatures are equal. To determine the final equilibrium temperature, we can use the principle of conservation of energy, which states that the heat lost by one substance is equal to the heat gained by the other.
First, we calculate the heat lost by the aluminum using the formula:
Q = m * c * ΔT
Where:
Q is the heat lost
m is the mass of aluminum
c is the specific heat of aluminum
ΔT is the change in temperature
Substituting the given values:
Q_aluminum = 80.0 g * 0.90 J/g°C * (5.0°C - final temperature)
Next, we calculate the heat gained by the water using the same formula:
Q = m * c * ΔT
Where:
Q is the heat gained
m is the mass of water
c is the specific heat of water
ΔT is the change in temperature
Substituting the given values:
Q_water = 100.0 g * 4.18 J/g°C * (final temperature - 60.0°C)
Since the total heat lost by the aluminum is equal to the total heat gained by the water, we can set up an equation:
Q_aluminum = Q_water
80.0 g * 0.90 J/g°C * (5.0°C - final temperature) = 100.0 g * 4.18 J/g°C * (final temperature - 60.0°C)
Simplifying and solving the equation gives us the final equilibrium temperature of 24.6°C.
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now, consider the collision between two happy balls described in part a. how much of the balls' kinetic energy is dissipated?
The final answer are considering the collision between two happy balls described in part a, the amount of kinetic energy dissipated is -0.15 J.
we need to calculate the kinetic energy dissipated between the happy balls in a collision as described in part a. The question is asking us to use the following terms in our answer: "now, consider the collision between two happy balls described in part
a. how much of the balls' kinetic energy is dissipated? "So, using the given formula of kinetic energy :K = (1/2)mv²Where,K = Kinetic energy of an object m = Mass of an object v = Velocity of an object
Now, we'll begin solving the problem. According to the problem, two balls with a mass of 0.35 kg each, having a velocity of 2.5 m/s and 1.2 m/s, collide in an inelastic collision with each other. From the formula of Kinetic energy, the initial kinetic energy can be calculated as,K1 = (1/2)mv² = (1/2) (0.35 kg) (2.5 m/s)² = 1.09 J
Similarly, for the second ball, the initial kinetic energy can be calculated as,K2 = (1/2)mv² = (1/2) (0.35 kg) (1.2 m/s)² = 0.23 J Now , adding up the initial kinetic energies of both balls, we get the total initial kinetic energy of the system.
That is,K1 + K2 = 1.09 J + 0.23 J = 1.32 J
Therefore, the total initial kinetic energy of the system is 1.32 J. Now, let's calculate the final kinetic energy of the system. During the inelastic collision, some kinetic energy is dissipated and converted to heat, sound, and other forms of energy, which means the kinetic energy will decrease.
Thus, we can use the conservation of momentum to calculate the final velocity of the balls, then calculate the final kinetic energy with the same formula. Now, applying the conservation of momentum (as in Part a), we get,0.35 kg × 2.5 m/s + 0.35 kg × 1.2 m/s = (0.35 kg + 0.35 kg) × v_ v = 1.85 m/s
Now, we can calculate the final kinetic energy of the system as, K_final = (1/2)mv² = (1/2) (0.7 kg) (1.85 m/s)² = 1.47 J Therefore, the final kinetic energy of the system is 1.47 J. Now, the amount of kinetic energy dissipated during the collision can be calculated by subtracting the final kinetic energy from the initial kinetic energy of the system.
K_dissipated = K_initial - K_final= 1.32 J - 1.47 J= -0.15 J
Thus, the amount of kinetic energy dissipated during the collision is -0.15 J (negative sign indicates that the kinetic energy is converted to other forms of energy).
Now, considering the collision between two happy balls described in part a, the amount of kinetic energy dissipated is -0.15 J.
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You are pushing a cart of groceries with a force of 368 N. The mass of the cart is 24 kg. What is the cart’s acceleration?
A. 0 m/s2
B. 15.3 m/s2
C. 8.9 x 103 m/s2
D. 0.7 m/s2
Answer:
B
Explanation:
The distance between two slits in a double-slit experiment is 0.0016 mm. what is the angle between the central maximum and the second dark fringe in the interference pattern produced with light having a wavelength of 520 nm?
The angle between centre maximum and also the second black fringes in the diffraction grating created by light with a wavelength = 520 nm is, in accordance with the stated statement, 26°.
In physics, how do you determine wavelength?The following equation may be used to compute wavelength: spectral = wave velocity/frequency. In most cases, frequency is measured in metres. Greek letter lambda is used to represent wavelength, thus = v/f.
Briefing:The distance between slits (d) = 0.0016mm = 1. * 10⁻⁶m
Wavelength = 520 nm
Order of dark fringe = 2
Using the formula for the distance of n'th dark fringe from the central maxima = (2n-1) λD/2d
D here stands for the screen's separation from the slits.
Plug n = 2
Y2 = 3λD/2d
Y2/D = 0.48
So tan∅2 = Y2/D = 0
tan∅2 = 0.48
∅2 = 26°
Consequently, there is a 26° angle between the centre maximum and the second dark border.
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I need help with this question and please show the whole work
and do it asap
If a star displays \( 0.0190 \) arcseconds of parallax, then long would it take to travel to that star if traveling at half the speed of light?
The first step is to convert the parallax angle of the star to distance. We can use the formula: parallax angle in arc seconds = (distance to star in parsecs)^-1 We can rearrange this equation to isolate distance: d = (parallax angle)^-1 Therefore, the distance to the star in parsecs is:
d = (0.0190 arcseconds)^-1 = 52.6 parsecs Next, we need to find the actual distance in meters. One parsec is equivalent to 3.09 × 10^16 meters. Therefore, the distance to the star in meters is: distance = (52.6 parsecs)(3.09 × 10^16 meters/parsec) = 1.63 × 10^18 meters Now, we can use the formula for time: d = vt Solving for time: t = d/v We are told to travel at half the speed of light, which is v = 0.5c, where c is the speed of light.
Therefore, the time to travel to the star is: t = (1.63 × 10^18 meters)/(0.5c) Using the speed of light, c = 3.00 × 10^8 m/s, we get: t = (1.63 × 10^18 meters)/(0.5 × 3.00 × 10^8 m/s)t ≈ 10.9 years Therefore, it would take about 10.9 years to travel to the star if traveling at half the speed of light.
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How do you find the image size in a concave mirror?
The concave mirror is represented by a vertical line MMl. The principal axis is represented by a horizontal line drawn on the PC. 1 mm. 12 mm (focal length: 12 cm); I Image position.
Here, u = 25 cm for the object distance (To the left of the mirror)
Also, the focal length is f = 20 cm (It is a concave mirror)
What is the size of the image in a concave mirror?
The size of image formed by a concave mirror is same as the size of object.
Use the magnification of a mirror formula to obtain the size of the object. Accordingly depict its nature using the sign of the image height. Where v is the image distance u is the object distance and f is the focal length.
However, if we increase the distance between the object and the mirror then the size of the image reduces and a real and inverted image is formed. The image formed by the concave mirror can be small or large and can be real or virtual.
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The concave mirror is represented by a vertical line MMl. The principal axis is represented by a horizontal line drawn on the PC. 1 mm. 12 mm (focal length: 12 cm); I Image position.
Here, u = 25 cm for the object distance (To the left of the mirror)
Also, the focal length is f = 20 cm (It is a concave mirror)
What is the size of the image in a concave mirror?
The size of image formed by a concave mirror is same as the size of object.
Use the magnification of a mirror formula to obtain the size of the object. Accordingly depict its nature using the sign of the image height. Where v is the image distance u is the object distance and f is the focal length.
However, if we increase the distance between the object and the mirror then the size of the image reduces and a real and inverted image is formed. The image formed by the concave mirror can be small or large and can be real or virtual.
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A scooter acquires a speed of 36km/ h in 5s just after the start. Calculate the acceleration of the scooter
Answer:
We need to convert seconds to hours:
5s= (5/60)min= 0.08min=(0.08/60)h=0.001h
a=v/t=36/0.001=36.000km/h^2
Which statement correctly describes the classification of chemical reactions into different categories?(1 point) Not all reactions fit into a category, and a reaction can fit into only one category. Not all reactions fit into a category, and a reaction can fit into only one category. Not all reactions fit into a category, and some reactions can fit into more than one category. Not all reactions fit into a category, and some reactions can fit into more than one category. All reactions fit into a category, and a reaction can fit into only one category. All reactions fit into a category, and a reaction can fit into only one category. All reactions fit into a category, and some reactions can fit into more than one category. All reactions fit into a category, and some reactions can fit into more than one category.
The statement that correctly describes the classification of chemical reactions into different categories is "All reactions fit into a category, and some reactions can fit into more than one category."
A chemical reaction is said to have occurred when the substances combine and form new substances. The substances that combined together are called reactant while the substance produced by such combination is called a product.
All reactions can be fitted into one category of the other depending on the kind of change that occur in the reaction.
However, some reactions fit more than one category. Let me give you an example. Look at the reaction; C(s) + O2 (g) ------> CO2(g).
This reaction can be viewed as a redox reaction since the oxidation numbers of the species involved in the reaction changed from left to right. On the other, we can also look at the reaction as a combustion reaction since it involves burning carbon in oxygen.
From this little example, we have seen that some reactions can fit into more than one category of reaction, hence the answer .
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a car start to move from the rest with an acceleration of 0.25 metre per second square find the final velocity after 3 min
Using 1st equation of kinematics
\(\\ \bull\sf\longmapsto v=u+at\)
\(\\ \bull\sf\longmapsto v=0+0.25(180)\)
\(\\ \bull\sf\longmapsto v=45m/s\)
⇛Initial velocity (u) = 0 m/s
⇛Acceleration (a) = 0.25 m/s²
⇛Time (t) = 3 minutes
⇛Final velocity (v) = v
Converting 3 minutes into seconds
1 minute = 60 second3 minutes = 60 × 33 minutes = 180 Seconds☛ Using 1st equation of motion\( \Large\begin{gathered} {\underline{\boxed{ \rm {\red{v \: = \: u \: + \: at}}}}}\end{gathered}\)
☛ Substuting the values\( \bf \large \longrightarrow \: \: v \: = \: 0 \: + \: 0.25 \: \: (180)\)
\(\bf \large \longrightarrow \: \: v \: = \:45 \: m/s\)