how many 4 digit numbers have at least 1 even digit
Answer: I hope this is helpful
Step-by-step explanation:
A 4-digit number contains at least one even digit. To find:How many such numbers are there?Solution:Digits are 0,1,2,3,4,5,6,7,8,9.Number of odd digits = 5Number of even digits = 54-digit numbers are from 1000 to 9999.Total number of 4-digit numbers = 9000Possible ways to get odd digits on all the 4 places isIt means 625 numbers are their in which all 4 digits are odd.To find total 4-digit number that contains at least one even digit, subtract the numbers which contains only odd numbers from the total 4-digit numbers.Therefore, total 4-digit number that contains at least one even digit is 8375.
QUESTION 4 Consider the formulas of the graphs of f(x)=(1/x+2)-3 and g(x) = 4x - 3. 4.1 Draw the graphs of f(x) and g(x) on the same Cartesian plane. Show all intercepts with the axes. 4.2 Write down the equations of the asymptotes of f. 4.3 Determine the equation of the symmetry axis of f, representing the line with the positive gradient. 4.4 Write down the domain and range of f. 4.5 The graph of h(x) is obtained by reflecting f(x) in the x-axis followed by a translation 3 units upwards. Write down the equation of h(x). (6) (2) (2) (2) (3)
The graphs of f(x) and g(x) are drawn on the same Cartesian plane. The intercepts with the axes are shown, and the equations of the asymptotes and symmetry axis of f are determined. The domain and range of f are identified. Additionally, the equation of h(x), obtained by reflecting f(x) in the x-axis and translating it upwards by 3 units, is provided.
4.1 The graphs of f(x) and g(x) are plotted on the same Cartesian plane. To find the intercepts with the axes, we set x or y to zero and solve for the other variable. For f(x), when x = 0, we have f(0) = (1/0 + 2) - 3, which is undefined. Therefore, there is no x-intercept for f(x). For the y-intercept, when x = 0, we have f(0) = (1/0 + 2) - 3, which is also undefined. Thus, there is no y-intercept for f(x). For g(x), the x-intercept is found by setting g(x) = 0 and solving for x: 4x - 3 = 0, x = 3/4. So, the x-intercept for g(x) is (3/4, 0). The y-intercept is g(0) = 4(0) - 3 = -3. Thus, the y-intercept for g(x) is (0, -3).
4.2 The equation of the asymptote for f(x) can be found by analyzing the behavior of the function as x approaches positive or negative infinity. As x approaches positive infinity, 1/x approaches 0, so f(x) approaches (0 + 2) - 3 = -1. Therefore, the horizontal asymptote for f(x) is y = -1. As x approaches negative infinity, 1/x approaches 0, and f(x) approaches (0 + 2) - 3 = -1 as well. Hence, the same horizontal asymptote y = -1 applies.
4.3 The equation of the symmetry axis of f(x) can be determined by finding the line with a positive gradient that bisects the graph symmetrically. The gradient of f(x) can be found by taking the derivative of f(x) with respect to x. Differentiating f(x) gives f'(x) = -1/(x^2). Since the gradient is always negative, there is no line with a positive gradient that can serve as the symmetry axis for f(x).
4.4 The domain of f(x) is the set of all real numbers except x = 0, as 1/x is undefined at x = 0. Hence, the domain of f is (-∞, 0) ∪ (0, ∞). The range of f(x) is all real numbers except y = -1, as f(x) cannot equal -1 due to the horizontal asymptote. Therefore, the range of f is (-∞, -1) ∪ (-1, ∞).
4.5 To obtain the equation of h(x), which is obtained by reflecting f(x) in the x-axis and translating it upwards by 3 units, we first reflect f(x) by multiplying it by -1. This gives us -f(x) = -[(1/x + 2) - 3] = 3 - (1/x + 2). Next, we translate -f(x) upwards by 3 units, resulting in h(x) = -f(x) + 3 = 3 - (1/x + 2) + 3 = 6 - (1/x). Therefore, the equation of h(x) is h(x) = 6 - (1/x).
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If the simple interest on $2000 for 10 years is $,1000 then what is the interest rate?
\( \bf \underline{Given :}\)
\( \sf{• \: Principal \: (P) = \$ \: 2000}
\)
\( \sf{• \: Simple \: Interest \: (I) = \$ \: 1000}
\)
\( \sf{• \: Time \: (T) = 10 \: years}\)
\( \sf{• \: Interest \: Rate \: (R) = \: ?}\)
\( \bf \underline{Solution:-}\)
\( \sf {We \: know \: that, }\)
\(\bf \red{\bigstar{ \: I = PRT}}\)
\( \sf{⟹1000 = 2000 \times \frac{R}{100} \times 10 }\)
\( \sf{⟹1000 = \frac{R}{100} \times 20000}\)
\( \sf{⟹ \frac{R}{100} = \frac{1000}{20000} }\)
\( \sf{⟹R = \frac{1}{20} \times 100 }\)
\( \sf⟹ R = 5\)
\( \pink{\bf{Hence, \: the \: interest \: rate \: is \: 5 \: \%. }}\)
Solve the heat equation modeling the heat conduction on a metal circular ring of radius 1 , if the initial temperature equals 2δ(θ− 4
π
). What is the temperature after a "very long time"?
The temperature after a "very long time" in the heat conduction model on a metal circular ring of radius 1, with an initial temperature of 2δ(θ - 4π), approaches a constant value of zero.
The heat equation describes the behavior of temperature distribution over time in a conducting medium. In this case, we have a metal circular ring with a radius of 1, and the initial temperature is given by 2δ(θ - 4π), where δ represents the Dirac delta function and θ is the angular coordinate.
To solve the heat equation for this scenario, we need to consider the boundary conditions, which include the initial temperature distribution and the properties of the ring. The initial temperature distribution indicates a temperature spike at θ = 4π and zero temperature elsewhere.
As time progresses, the heat conduction in the metal ring will cause the temperature to equalize throughout the ring. Since the heat is continuously dissipating to the surroundings, the temperature will tend towards a steady-state condition. In the case of a "very long time," the temperature will approach a constant value of zero.
This result can be understood by considering the heat diffusion process. As time increases, the heat will flow from regions of higher temperature to regions of lower temperature until equilibrium is reached. In this case, since the initial temperature is concentrated at a single point and dissipates continuously, the temperature will eventually reach a state where it is uniformly distributed and approaches zero.
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Please I need help on this problem
Answer:
148
Step-by-step explanation:
180 is the whole thing and if the inner of one is 16 then the other one is also 16 so u add this and subtract 180-32=148
(16+16=32)
Answer:
C. x=42
Step-by-step explanation:
First find the measurement of missing angles. 126+16=142
180-142=38
Now, 16, 3x and 38 should add up to 180 because it is a line.
16+38+3x=180
54+3x=180
Solve for x.
3x=126
3 = 3
x=42. Hope this helps.
he BLS employer cost survey uses a sample to establish the average wage of receptionists. Based on a large number of observations, the distribution of receptionist wages is normally distributed with a mean $10.38/hour and a standard deviation of $2.05. What is the probability that the wages for a sample of 20 receptionists exceeds $11/hour
If the BLS employer cost survey uses a sample to establish the average wage of receptionists and the distribution of receptionist wages is normally distributed with a mean of $10.38/hour and a standard deviation of $2.05, then the probability that the wages for a sample of 20 receptionists exceed $11/hour is 38.16%
To find the probability, follow these steps:
So, the probability is approximately 0.3816 or 38.16%.
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12. Lucy has a bag of Skittles with 3 cherry, 5 lime, 4 grape, and 8 orange
Skittles remaining. She chooses a Skittle, eats it, and then chooses
another. What is the probability she get cherry and then lime?
10x + 8 = 3(x - 2)
10x + 8 = 3x
Answer:
1) -2
2) 8/7
Step-by-step explanation:
1) 10x+8=3(x-2)
10x+8=3x-6
10x-3x=-6-8
7x=-14
x=-2
2) 10x+8=3x
10x-3x=8
7x=8
x=8/7
Hope it helps
If the point P(-1,0) is a point on the terminal side of angle 0, an angle in standard position, what is the value of csc 0 ?
We know that the value of CSC 0 is undefined if the point P(-1,0) is a point on the terminal side of angle 0, an angle in standard position.
If the point P(-1,0) is a point on the terminal side of angle 0, an angle in standard position, then we can use the Pythagorean theorem to find the value of the hypotenuse. The hypotenuse (r) is the distance from the origin to point P, and can be found using the formula r = sqrt(x^2 + y^2), where x = -1 and y = 0.
r = sqrt((-1)^2 + 0^2) = 1
Since csc 0 is the reciprocal of sin 0, and sin 0 = 0/1 = 0, we have:
CSC 0 = 1/sin 0 = 1/0 = undefined.
Therefore, the value of CSC 0 is undefined if the point P(-1,0) is a point on the terminal side of angle 0, an angle in standard position.
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The ___________ the r2 and the __________ the s (standard error), the stronger the relationship between the dependent variable and the independent variable.
The larger the \(r^{2}\) and the smaller the s ( standard error).
The correlation coefficient ranges from 0 and 1. A coefficient of determination that is close to 1 indicates that the dependent and independent variables have a solid linear relationship.The following equation relates the standard error of the estimate to the coefficient of determination:\(s = \sqrt{\frac{1-r^{2} }{n-2} }\)
Where, \((1-r^{2} )\) is the non determination factor, and (n−2) represents the degrees of freedom.
According to the aforementioned calculation, a smaller standard error and a stronger association between the dependent and independent variables result from a smaller coefficient of determination (or a bigger coefficient of determination).Learn more about standard error here: https://brainly.com/question/23947134
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A rental car company charges $74.90 per day to rent a car and $0.13 for every mile driven. Tyee wants to rent a car, knowing that:
He plans to drive 175 miles.
He has at most $210 to spend.
Write and solve an inequality which can be used to determine
x
x, the number of days Tyee can afford to rent while staying within his budget.
The inequality which can be used to determine the number of days he can afford as required is; 74.90x + 22.75 ≤ 210.
The solution of the inequality is; x = 2 days.
Which inequality represents the situation?As evident in the task content; the company charges $74.90 per day to rent a car and $0.13 for every mile driven, hence, since he drives 175 miles.
The total mileage cost = 175 × 0.13 = $22.75.
since, x = number of days he can afford to rent the car.
74.90x + 22.75 ≤ 210.
74.90x ≤ 210 - 22.75
74.90x ≤ 187.25
x ≤ 2.5 days.
Ultimately, the number of days Tes can afford the car within his budget is; 2 days.
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the confidence interval for the mean amount of money spent per household on internet service
each month is $47.45 to $72.45. what is the estimated mean?
internet each
The estimated mean amount of money spent per household on internet service each month is $59.95 with confidence interval.
To calculate the estimated mean amount of money spent per household on internet service each month, we first need to find the lower and upper bounds of the confidence interval. The lower bound is $47.45 and the upper bound is $72.45. We then take the average of these two numbers to get the estimated mean. The average of $47.45 and $72.45 is
($47.45 + $72.45) / 2
= $59.95.
Therefore, the estimated mean amount of money spent per household on internet service each month is $59.95.
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If one zero of 14² − 42² − 9 is the negative of the other, find the value of k �
Given
One of the zeros of 14² − 42² − 9 is the negative of the other.
To find the value of k.
Explanation:
It is given that,
One of the zeros of 14² − 42² − 9 is the negative of the other.
That implies,
Let α, -α be the zeros of the polynomial f(x) = 14² − 42² − 9.
Then,
\(\begin{gathered} f(\alpha)=0 \\ \Rightarrow14\alpha^2-42k^2\alpha-9=0\text{ \_\_\_\_\_\_\lparen1\rparen} \end{gathered}\)Also,
\(\begin{gathered} f(-\alpha)=0 \\ \Rightarrow14\alpha^2+42k^2\alpha-9=0\text{ \_\_\_\_\_\_\lparen2\rparen} \end{gathered}\)Subtracting (1) and (2) implies,
\(\begin{gathered} (2)-(1)\Rightarrow(14\alpha^2+42k^2\alpha-9)-(14\alpha^2-42k^2\alpha-9)=0 \\ \Rightarrow84k^2\alpha=0 \\ \Rightarrow k^2\alpha=0 \\ \because\alpha\ne0\Rightarrow k^2=0 \\ \Rightarrow k=0 \end{gathered}\)Hence, the value of k is 0.
HELPPPPPP PLS I DONT UNDERSTAND
Answer:
7.59 m^2
Step-by-step explanation:
here's your solution
=> Radius of circle = 2.2 m
=> we need to find out area of semicircle
=> area = 1/2πr^2
=>. area = 1/2*3.14*2.2*2.2
=> area = 7.59 m^2
Which point would be a solution to the system of linear inequalities shown below?
y>-4x+6 Y>1/3x -7
(9,-7)
(-12,-2)
(12, 1)
(-12,-7)
The point (9, -7) is the only solution to the system of linear inequalities given.
To determine which point would be a solution to the system of linear inequalities, let's substitute the given points into the inequalities and see which point satisfies both inequalities.
The system of linear inequalities is:
y > -4x + 6
y > (1/3)x - 7
Let's test each given point:
For the point (9, -7):
Substituting the values into the inequalities:
-7 > -4(9) + 6
-7 > -36 + 6
-7 > -30 (True)
-7 > (1/3)(9) - 7
-7 > 3 - 7
-7 > -4 (True)
Since both inequalities are true for the point (9, -7), it is a solution to the system of linear inequalities.
For the point (-12, -2):
Substituting the values into the inequalities:
-2 > -4(-12) + 6
-2 > 48 + 6
-2 > 54 (False)
-2 > (1/3)(-12) - 7
-2 > -4 - 7
-2 > -11 (False)
Since both inequalities are false for the point (-12, -2), it is not a solution to the system of linear inequalities.
For the point (12, 1):
Substituting the values into the inequalities:
1 > -4(12) + 6
1 > -48 + 6
1 > -42 (True)
1 > (1/3)(12) - 7
1 > 4 - 7
1 > -3 (True)
Since both inequalities are true for the point (12, 1), it is a solution to the system of linear inequalities.
For the point (-12, -7):
Substituting the values into the inequalities:
-7 > -4(-12) + 6
-7 > 48 + 6
-7 > 54 (False)
-7 > (1/3)(-12) - 7
-7 > -4 - 7
-7 > -11 (True)
Since one inequality is true and the other is false for the point (-12, -7), it is not a solution to the system of linear inequalities.
In conclusion, the point (9, -7) is the only solution to the system of linear inequalities given.
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What does the word “change “ tell you to do in “keep change flip” for dividing fractions? A) change the sing to multiplication b) change the sing to addition c) change the first fraction d) change the second fraction
Answer:
A
Step-by-step explanation:
Multiply by the reciprocal, also sometimes referred to as "Keep, Change, Flip." Here is how it works. You rewrite the division question as a multiplication question by flipping the second fraction over. Next, keep the first number, change the division to multiplication and then flip the second fraction over.
Answer:
d change the second fraction
Step-by-step explanation:
i dont know how to explain it but yeah
"
if
a particle has a mass of 0.00000000572 g, how would you convert
this value to ng?
"
To convert a mass value from grams to nanograms, we need to multiply the given value by a conversion factor. In this case, we can convert 0.00000000572 grams to nanograms by multiplying it by 1,000,000,000.
To convert grams to nanograms, we use the conversion factor that 1 gram is equal to 1,000,000,000 nanograms. Therefore, to convert the mass of 0.00000000572 grams to nanograms, we multiply it by the conversion factor:
0.00000000572 g × 1,000,000,000 ng/g = 5.72 ng
Hence, the mass of 0.00000000572 grams is equivalent to 5.72 nanograms.
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To convert a mass of 0.00000000572 g to ng (nanograms), we can multiply the given mass by a conversion factor.
The prefix "nano-" represents a factor of 10^-9. Therefore, to convert grams to nanograms, we need to multiply the given mass by 10^9.
0.00000000572 g × 10^9 ng/g = 5.72 ng
By multiplying the mass in grams by the conversion factor, we find that the mass of 0.00000000572 g is equivalent to 5.72 ng.
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Jane and her neighbor Amil are jealous of each other’s gardens. Amil’s garden is twice the size of Jane’s garden. Janes garden has 22 watermelons and Amil’s garden has 28. Whose garden has the greatest density of watermelons Support your answer with math?
Answer:
Jane has the greatest desity of watermelons.
Step-by-step explanation:
25ft2/22= 1.13 100ft2/28= 3.57
For example, if Jane’s garden is 25 square feet then that means there would be about 1 watermelon per square foot. If Amil’s garden is twice the size of Jane’s at 100 square feet, then you could fit about 3 watermelons per square foot. This means that Jane has the greatest density of watermelons because Amil can fit more watermelons per square foot.
Which ratio would you use to find AC? Sine B) Cosine C) Tangent?
Answer:
Step-by-step explanation: Sine
Choose the system of equations which matches the following graph.
A. 3x-6y=12
9x-18y=36
B. 3x+6y=12
9x+18y=36
The system of equations that matches the given graph is:
A. 3x - 6y = 12
9x - 18y = 36
To determine which system of equations matches a given graph, we need to analyze the slope and intercepts of the lines in the graph.
Looking at the options provided:
A. 3x - 6y = 12
9x - 18y = 36
B. 3x + 6y = 12
9x + 18y = 36
Let's analyze the equations in each option:
For option A:
The first equation, 3x - 6y = 12, can be rearranged to slope-intercept form: y = (1/2)x - 2.
The second equation, 9x - 18y = 36, can be simplified to 3x - 6y = 12, which is the same as the first equation.
In option A, both equations represent the same line, as they are equivalent. Therefore, option A does not match the given graph.
For option B:
The first equation, 3x + 6y = 12, can be rearranged to slope-intercept form: y = (-1/2)x + 2.
The second equation, 9x + 18y = 36, can be simplified to 3x + 6y = 12, which is the same as the first equation.
In option B, both equations also represent the same line, as they are equivalent. Therefore, option B does not match the given graph.
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y = -4x + 3
8x + 2y = 8
Solve by using elimination.
Answer:
The equations are not compatible
Step-by-step explanation:
y = -4x + 3
8x + 2y = 8
substitute for y:
8x + 2(-4x + 3) = 8
simplify:
8x - 8x + 6 = 8
6 ≠ 8
For f(x)=-7x -15, find f(x) when x=2.
91
b. -29
a.
-22
d. -1
Step-by-step explanation:
for f(x) = -7x - 15
f(2) = -7(2) - 15
f(2) = -14 - 15
f(2) = -29
Ayuda porfa doy corona
Answer:
goto chrome and search spankbang
Step-by-step explanation:
thet the answer
.....................
Answer:
6/5 or 1 1/5
Step-by-step explanation:
2/3 * 9/5
~Multiply both numerators and denominators together
18/15
~Simplify
6/5
Best of Luck!
Answer:
D. 1 1/5
Step-by-step explanation:
\(\frac{2}{3} *\frac{9}{5}\)Multiply the numerators:
\(2*9=18\)
Multiply the denominators:
\(3*5=15\)
\(\frac{18}{15}\)
Simplify:
Use the greatest common factor, in this case 3.
\(\frac{18}{15}\)÷\(\frac{3}{3}\)
\(\frac{6}{5}\)
\(\frac{6}{5} = 1\frac{1}{5}\)
The product of \(\frac{2}{3}*\frac{9}{5}=1 \frac{1}{5}\)
·Has to be a number
Answer:
x=-4
Step-by-step explanation:
How many term of the A. P. 16,14,12,. Are needed to give the um 60? explain why do we get two anwer
The sum of first five or twelve term in the A.P given the value 60.
The term AP refers a sequence of numbers in order, in which the difference between any two consecutive numbers is a constant value.
Here we have given that A. P. 16,14,12,.
And we need to find the number of term to get the value of 60.
While we looking into the given question we have identified that the common difference d of the A.P. is − 2
Here we also know that the terms of the A.P. are in descending order.
Now, we have to take n = 5 then then first 5 terms are 16,14,12,10,8.
Here we have identified that the sum is 60.
Similarly, here by taking n = 12 , then the last 7 terms ( 12 − 5 ) (12-5) are 6 , 4 , 2 , 0 , − 2 , − 4 , − 5 6,4,2,0,-2,-4,-5
Here we have identified that the sum of these seven terms is 0.
Therefore, sum of first 12 terms is also 60.
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an equation of a circle is given by (x+3)^2+(y_9)^2=5^2 apply the distributive property to the square binomials and rearrange the equation so that one side is 0.
The equation of the circle is \(x^2 + y^2 + 6x - 18y + 65 = 0\).
Given:
Equation of the circle is \((x+3)^2+(y-9)^2=5^2\)
Expand the equation
\((x+3)^2 = (x+3)(x+3) = x^2 + 3x + 3x + 9 = x^2 + 6x + 9\)
\((y-9)^2 = (y-9)(y-9) = y^2 - 9y - 9y + 81 = y^2 - 18y + 81\)
\(5^2 = 25\)
Then, substitute the expanded expressions into the equation
\((x+3)^2+(y-9)^2=5^2\\(x^2 + 6x + 9) + (y^2 - 18y + 81) = 25\\\)
Simplify and combine like terms
\((x^2 + 6x + 9) + (y^2 - 18y + 81) = 25\\x^2 + y^2 + 6x - 18y + 90 = 25\)
Rearrange the equation so that one side is 0
\(x^2 + y^2 + 6x - 18y + 90 = 25\\x^2 + y^2 + 6x - 18y + 90 - 25 = 0\\x^2 + y^2 + 6x - 18y + 65 = 0\)
Thus, the equation of a circle \((x+3)^2+(y-9)^2=5^2\) can be rearranged using the distributive property to form \(x^2 + y^2 + 6x - 18y + 65 = 0\), with one side equaling 0.
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What is the HCF of 21,28,42
Answer:
Greatest common factor of 21 28 and 42
We found the factors and prime factorization of 28 and 42. The biggest common factor number is the GCF number. So the greatest common factor 28 and 42 is 14.
Tell me if I'm wrong.
Finiteness of spinfoam vertex amplitude with timelike polyhedra and the regularization of full amplitude
The finiteness of the spinfoam vertex amplitude with timelike polyhedra is achieved through a regularization process in the calculation of the full amplitude.
The spinfoam vertex amplitude represents the transition amplitude between different quantum states in loop quantum gravity. When timelike polyhedra are involved, the vertex amplitude can diverge due to the presence of singularities.
To address this issue, a regularization technique is employed, which introduces a cutoff or smoothes out the problematic regions.
This regularization ensures that the calculations remain finite and well-defined, allowing for meaningful physical predictions within the framework of loop quantum gravity.
By employing a regularization technique, the finiteness of the spinfoam vertex amplitude with timelike polyhedra is ensured. This regularization process is crucial in maintaining the mathematical consistency of loop quantum gravity and enables the study of quantum gravitational phenomena in a well-defined manner.
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The height of a tennis ball tossed into the air is modeled by h(x) = 40x â€" 16x 2, where x is elapsed time in seconds. During what time interval will the tennis ball be at least 15 feet above the ground? x > 0. 5 seconds and x > 2. 04 seconds x > 0. 5 seconds and x ≤ 2. 04 seconds x ≥ 0. 5 seconds and x > 2. 04 seconds x ≥ 0. 5 seconds and x ≤ 2. 04 seconds.
The time interval x >0.5 and x > 2.04 will the tennis ball be at least 15 feet above the ground.
Given that,
The height of a tennis ball tossed into the air is modeled by,
\(\rm h(x) = 40x - 16x^2\)
Where x is elapsed time in seconds.
We have to determine,
During what time interval will the tennis ball be at least 15 feet above the ground?
According to the question,
The height of a tennis ball tossed into the air is modeled by,
\(\rm h(x) = 40x - 16x^2\)
Where x is elapsed time in seconds.
Then,
When the tennis ball be at least 15 feet above the ground,
\(h(x) = 15\)
Substitute the value of h(x) in the equation,
\(\rm h(x) = 40x - 16x^2\\\\ 15 = 40x - 16x^2\\\\ 16x^2-40x+15=0\)
Factorize the equation for finding the time interval will the tennis ball be at least 15 feet above the ground is,
\(\rm 16x^2-40x+15= 0\\\\x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\x = \dfrac{-(-40)\pm \sqrt{(-40)^2-4 \times 16 \times 15}}{2 \times 16}\\\\x = \dfrac{-(-40)\pm \sqrt{1600- 960}}{32}\\\\x = \dfrac{40\pm \sqrt{640}}{32}\\\\x = \dfrac{40 + 25.29}{32} \\\\x = \dfrac{40 + 25.29}{32} \ and \ x = \dfrac{40 - 25.29}{32}\\\\x = \dfrac{65.29}{32} \ and \ x = \dfrac{14.71}{32}\\\\x = 2.04 \ and \ x = 0.45\)
Hence, The time interval x >0.5 and x > 2.04 will the tennis ball be at least 15 feet above the ground.
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