Please help me with this!!! In picture ‼️

Whave established that the series l~=l an - z converges uniformly for Re(z) ≤ c

What is uniformly?

The keyword "uniformly" refers to the concept of uniform convergence. In the context of the given question, it is stated that the series l~=l an - z converges uniformly for Re(z) ≤ c. Uniform convergence means that the convergence of the series is independent of the value of z within a certain range (Re(z) ≤ c in this case).

To show that the series l~=l an - z converges uniformly for Re(z) ≤ c, where an is a bounded sequence of complex numbers and we choose the principal branch of n - z, we need to demonstrate that for any ε > 0, there exists an N such that for all n > N and for all z with Re(z) ≤ c, the inequality |l~=l an - z| < ε holds.

Given that an is a bounded sequence, there exists an M > 0 such that |an| ≤ M for all n.

Let's consider the series l~=l an - z. We can write it as:

l~=l an - l z.

Now, since |an| ≤ M for all n, we have:

|an - z| ≤ |an| + |z| ≤ M + c.

By choosing N such that M + c < ε, we can ensure that for all n > N and for all z with Re(z) ≤ c, the inequality |an - z| < ε holds.

Now, using the triangle inequality, we have:

|l~=l an - z| ≤ |an - z|.

Since we have shown that |an - z| < ε for n > N and Re(z) ≤ c, it follows that |l~=l an - z| < ε for n > N and Re(z) ≤ c.

Therefore, we have established that the series l~=l an - z converges uniformly for Re(z) ≤ c.

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Answer:

|x - 4|

Step-by-Step explanation:

Let's say that the distance that Aisha bikes after school each day is represented by the variable "x". We want to write an absolute value equation that represents the distance that Aisha bikes, given that Carlos lives 1 mile further along the path.

If Aisha bikes directly home, then the distance she bikes is just the distance from school to her home, which is 3 miles. If she bikes all the way to Carlos' place before going home, then the distance she bikes is the total distance from school to Carlos' place and then from Carlos' place to her home. This total distance is equal to:

|x - (3 + 1)|

where "x - (3 + 1)" represents the distance from school to Carlos' place (which is equal to the distance that Aisha bikes beyond her home), and the absolute value symbols ensure that the expression inside the absolute value is positive.

Therefore, the absolute value equation that represents the distance that Aisha bikes after school each day is:

|x - 4|

P.S - Sorry if this is too wordy

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2 different expressions that involve only outs and powers of 2 which are equivalent 4 2/3 / 8 1/4

1) (4^2 * 2^-1 * 3^1) / (8^1 * 2^-2 * 4^-1)

2) (2^5 * 3^1) / (2^6 * 4^-1)

1) (4^2 * 2^-1 * 3^1) / (8^1 * 2^-2 * 4^-1)

This expression is equivalent to 4 2/3 / 8 1/4 because it is written in terms of powers of two. 4^2 is equal to 16, which is the numerator in 4 2/3. 2^-1 is the same as 1/2, which is the second fraction in 4 2/3. 3^1 is equal to 3, which is the numerator in 8 1/4. 8^1 is equal to 8, which is the denominator in 8 1/4. 2^-2 is the same as 1/4, which is the second fraction in 8 1/4. 4^-1 is equal to 1/4, which is the first fraction in 8 1/4. When all the terms are multiplied and divided, it is the same as 4 2/3 / 8 1/4.

2) (2^5 * 3^1) / (2^6 * 4^-1)

This expression is also equivalent to 4 2/3 / 8 1/4 because it is written similar to above equation.

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π(2ft)2(10ft) + π(2ft)2(13ft − 10ft) is used to calculate the total volume of grains that can be stored in the silo.(option-c)

The total volume of grains that can be kept in the silo is calculated as (2ft)2(10ft) + (2ft)2(13ft 10ft).(option-c)

The formula $V = gives the volume of a cylinder.

$, where $r$ denotes the base's radius and $h$ denotes its height. The equation $V = gives the volume of a cone.

$, where $r$ denotes the base's radius and $h$ denotes its height.

The silo is made up of a cone with a height of 3 feet and a radius of 2 feet, as well as a 10 foot tall cylinder with the same dimensions. Consequently, the silo's overall volume is V =

V = \(\pi (2ft)^2 (10ft) + \frac{1}{3} \pi (2ft)^2 (3ft)\)

V =\(\pi (4ft^2) (10ft) + \frac{1}{3} \pi (4ft^2) (3ft)\)

V = \(40 \pi ft^3 + 4 \pi ft^3\)

V = \(44 \pi ft^3\)(option-c)

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The function’s equation written in factored form and in vertex form are respectively;

f(x) = 2x(x - 4)

f(x) = 2(x - 2)² - 8

The factored form of a quadratic function is;

f(x) = a(x - p)(x - q)

where:

p and q are the x-intercepts

a is a constant

Now, we are given x-intercepts as; (0, 0) and (4, 0)

Thus;

f(x) = a(x - 0)(x - 4)

f(x) = ax(x - 4)

To find a, substitute the given vertex (2, -8) into the equation and solve for a:

2a(2 - 4) = -8

-4a = -8

a = 2

Thus;

f(x) = 2x(x - 4)

The vertex form of a quadratic equation is;

f(x) = a(x - h)² + k

where:

(h, k) is the vertex

a is constant

Since vertex is (2, -8), then we have;

f(x) = a(x - 2)² - 8

Put the coordinate (0, 0) to find a;

0 = a(0 - 2)² - 8

4a = 8

a = 2

Thus;

f(x) = 2(x - 2)² - 8

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Answer:

(8x - 1) - (3x + 6)

hope this helps

Ted used a balance scale to weigh a 2.233 g sample of copper sulfate,  the most accurate measurements made by Ted is 2.2 g.

Accuracy is a measure of how close you are the true value.  

In this case,Ted used a balance scale to weigh a 2.233 g sample of copper sulfate using only 2 significant figures, that would be the value of 2.2 g

Precision is how close a test result when repeated. In precision, the actual value is not examined. You only need to look at the result.The standard deviation should be small.

Accuracy is how close the test results to the standard known value. The standard deviation might be big.

Ted used a balance scale to weigh a 2.233 g sample of copper sulfate,  the most accurate measurements made by Ted is 2.2 g.

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Answer: y=-22

Step-by-step explanation:

Answer: 300

Step-by-step explanation:

∂z/∂s = 3cos(t)/y, ∂z/∂t = 3s*cos(t)/y - sin(s)/x (using the chain rule to differentiate each term and substituting the given expressions for x and y)

To find ∂z/∂s and ∂z/∂t using the chain rule, we start by finding the partial derivatives of z with respect to x and y, and then apply the chain rule.

First, let's find ∂z/∂x and ∂z/∂y.

∂z/∂x = ∂/∂x [ln(5x^3y)]

= (1/5x^3y)  ∂/∂x [5x^3y]

= (1/5x^3y) 15x^2y

= 3/y

∂z/∂y = ∂/∂y [ln(5x^3y)]

= (1/5x^3y) ∂/∂y [5x^3y]

= (1/5x^3y)  5x^3

= 1/x

Now, using the chain rule, we can find ∂z/∂s and ∂z/∂t.

∂z/∂s = (∂z/∂x)  (∂x/∂s) + (∂z/∂y)  (∂y/∂s)

= (3/y)  (cos(t)) + (1/x)  (0)

= 3cos(t)/y

∂z/∂t = (∂z/∂x)  (∂x/∂t) + (∂z/∂y)  (∂y/∂t)

= (3/y) * (scos(t)) + (1/x)  (-sin(s))

= 3scos(t)/y - sin(s)/x

Therefore, ∂z/∂s = 3cos(t)/y and ∂z/∂t = 3s*cos(t)/y - sin(s)/x.

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Answer:

I think it might be 0 im not to sure.

Answer:

4i

Step-by-step explanation:

-4i(2+3i)

-8i-12i

4i

Answer:

assuming that i is a complex number then -8i+12=4(3-2i)

Because it only considers the worst possible outcomes, the maximin decision criterion has the least downside risk.

Wald's maximin model is a non-probabilistic decision-making model in game theory and decision theory.

It says that while choosing a course of action, the decision-maker should choose the one whose greatest (highest) loss is better than the least (minimum) loss of all other options that are feasible under the current conditions. The approach that maximizes one's own lowest payout is referred to as "maximin" in non-zero-sum games.

When given a choice between numerous options, the maximin approach instructs managers to consider each option's worst-case outcome. This presupposes that each choice has a number of possible outcomes.

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Answer:

n < -33

Step-by-step explanation:

Let n = the number

7(n - 4) ≥ 8n + 5

7n - 28 ≥ 8n + 5

-n ≥ 33

n ≤ -33

Answer:

n< -33

Step-by-step explanation:

explanation is up on anothers answer

Answer:

All the possible values of a must be less than 3.75 excluding values from 3 and below

Inequalities are expressions that are not separated by an equal sign

Since we are not given the required inequality expression, Let us assume the equation below:

10 - 5a > -a

Add 5a to both sides

15 - 5a + 5a > -a + 5a

15 > 4a

4a<15

a < 15/4

a<3.75

Since the value of a is less than 3.75, hence all the possible values of a must be less than 3.75 excluding values from 3 and below.

Step-by-step explanation:

Answer:

a=6

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

4a+1−a=19

(4a+−a)+(1)=19 (Combine Like Terms)

3a+1=19

Step 2: Subtract 1 from both sides.

3a+1−1=19−1

3a=18

a=18/3

a=6

--

The equatiοn that matches the number of bacteria in the population after 7 hours is \($\begin{array}{l}{{\mathrm{P(t)=Po(4)7}}} \end{array}\). The number of bacteria in the population after 7 hours is 1638400 bacteria.

In mathematics, a functiοn is a relatiοn between a set οf inputs and a set οf pοssible οutputs with the prοperty that each input is related tο exactly οne οutput. It can be represented using an equatiοn οr a graph.

We have initial pοpulatiοn 100

it is quadrupled every hοur

\($\mathbf{P}(\mathbf{t})\mathop=\mathbf{P}_{\mathbf{O}}(\mathbf{4})\mathbf{t}$\)

where.

R(t) is population at any time t

Po is initial population

4 is because it is quadruple

t is time in hours

We have tο find after 7 hοurs

\($\begin{array}{l}{{\mathrm{P(t)=Po(4)7}}}\\\\ {{\mathrm{P(t)=100(4)7}}}\end{array}$\)

P(t) = 1638400 bacteria

Thus, equation the matches the number of bacteria in the population after 7 hours is \($\begin{array}{l}{{\mathrm{P(t)=Po(4)7}}} \end{array}\). The number of bacteria in the population after 7 hours is 1638400 bacteria.

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The human understanding of the cosmos beyond Earth has grown after inventing specialized equipment such as x-ray telescopes.

X-ray telescope, a device made to find and focus X-rays from sources beyond the atmosphere of Earth.

Some key features regarding the x-ray telescope are-

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Answer:

25

Step-by-step explanation:

6.3= 1 blanket

to find 4 blankets you multiply 6.3 by 4

6.3x4=25.2

to the nearest whole number

25

To solve the differential equation  we first find the integrating factor.

a.) The integrating factor is given by e^(∫3dt) = e^(3t).

Multiplying both sides of the equation by e^(3t), we get:

e^(3t)y' + 3e^(3t)y = te^(3t) + e^(t)

Using the product rule,

d/dt(e^(3t)y) = te^(3t) + e^(t)

Integrating both sides with respect to t, we get:

e^(3t)y = (1/3)t e^(3t) + e^(t) + C

where C is the constant of integration.

Solving for y, we get:

y = (1/3)t + e^(-2t) + Ce^(-3t)

As t → ∞, Ce^(-3t) goes to 0 . Therefore, the general behavior of solutions is that they approach 0 as t → ∞.

b.) The integrating factor is given by e^(∫-2dt) = e^(-2t).

Multiplying both sides of the equation by e^(-2t), we get:

e^(-2t)y' - 2e^(-2t)y = t^2

Using the product rule,

d/dt(e^(-2t)y) = t^2

Integrating both sides with respect to t, we get:

e^(-2t)y = (1/3)t^3 + C

where C is the constant of integration.

Solving for y, we get:

y = (1/3)t^3e^(2t) + Ce^(2t)

As t → ∞, (1/3)t^3e^(2t) grows without bound as t → ∞. Therefore, the general behavior of solutions is that they diverge to infinity as t → ∞.

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Step-by-step explanation:

Took the test! Good luck

sure thing but first start off by creating the function that we want to plot but isolating y.

y>-2x+4

Technically we are graphing the line of equation y=-2x+4 and finding the values where y>-2x+4

Now using the original equation;

2x+y>4

let's take the origin (0,0) as our reference.

substitute the values in the equation

2(0)+0>4

0>4

False, then this part of the graph is rejected and we want to take the other side :P

Raoult's law is a thermodynamic model that assumes that the vapor pressure of each component in an ideal mixture is proportional to its mole fraction in the mixture.

Raoult's law states that the vapor pressure of a component in an ideal mixture is proportional to its mole fraction in the mixture. It is a valid assumption for ideal solutions, where the interactions between the molecules of the different components are the same as those between like molecules. The benzene/toluene system is close to ideal, so Raoult's law can be assumed to be valid for this system.

(a) Given x1=0.33 and T=100∘C, find γ1 and P.

Raoult's law for component 1 is P1 = γ1 x1 P, where P is the total pressure. Solving for γ1 and substituting x1=0.33 and P=1 atm, we get:

γ1 = P1 / (x1 P) = (0.33) / (1-0.33*(1-0.866)) = 0.478

The vapor mole fraction of component 1 can be found using the total mole fraction of component 1 in the vapor phase:

y1 = γ1 x1 / P = (0.478)(0.33) / 1 = 0.157

The total pressure is P = P1 + P2 = γ1 x1 P + γ2 x2 P, where γ2 is the activity coefficient of component 2 and x2=1-x1=0.67 is the mole fraction of component 2. We can solve for P using the vapor pressure data at 100°C:

P1 = 12.8 kPa, P2 = 3.75 kPa

P = P1 x1 γ1 + P2 x2 γ2 = (12.8 kPa)(0.33)(0.478) + (3.75 kPa)(0.67)(1) = 7.18 kPa

(b) Given γ1=0.33 and T=100∘C, find x1 and P.

Using Raoult's law for component 1, we can solve for x1:

x1 = P1 / (γ1 P) = (12.8 kPa) / (0.33)(101.3 kPa) = 0.390

The total pressure can be found using the same equation as in part (a):

P = P1 x1 γ1 + P2 x2 γ2 = (12.8 kPa)(0.390)(0.33) + (3.75 kPa)(0.67)(1) = 7.18 kPa

(c) Given x1=0.33 and P=120 kPa, find γ1 and T.

Using Raoult's law for component 1, we can solve for γ1:

γ1 = P1 / (x1 P) = (0.33)(120 kPa) / (101.3 kPa) = 0.391

The boiling point of the mixture can be found by solving the Antoine equation for the boiling points of benzene and toluene and using Raoult's law to find the boiling point of the mixture:

ln(P1) = A1 - B1 / (T + C1), ln(P2) = A2 - B2 / (T + C2)

T = (B1 - B2) / (A2 - A1 + ln(P1/P2)) = (4875 K) / (14.314 - 13.781 + ln(0.33/0.67)) = 102.5°C

(d) Given γ1=0.33 and P=120 kPa, find x1 and T.

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Given that the cost is $1.10 per pound, we can calculate the cost per servable pound by dividing the total cost ($1.10 * 4 pounds) by the servable weight (2 pounds). Therefore, the correct option is c. $2.20.

The original weight of the food item is 4 pounds, and the cost per pound is $1.10. Therefore, the total cost of the food item is 4 pounds * $1.10 = $4.40.

The servable weight of the food item is 2 pounds. To find the cost per servable pound, we divide the total cost ($4.40) by the servable weight (2 pounds):

Cost per servable pound = Total cost / Servable weight = $4.40 / 2 pounds = $2.20.

Hence, the cost per servable pound for this food item is $2.20. Therefore, the correct option is c. $2.20.

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Answer:

29+15=44

44÷7=6.28

y=6.28

Answer:

60%

Step-by-step explanation:

0.60*100 = 60

60%

Answer:

The larger van has 23 seats

Step-by-step explanation:

Create a system of Equations:

1. Define variables.

> let x=small van and y=larger van

2. create 2 equations based on the information given.

> y = 6 + x

> 2x + y = 57

3. Use any method to solve

Substitution: 2x + (6 + x) = 57. x=17

                      now plug x in to the original equation to solve for y (the larger van)

                      y = 6 + 17 and y = 23

Elimination: 2y = 12 + 2x

                     y = 57 - 2x

         3y = 69  and y = 23