Please help me solve this problem

Graph (C) which has points (0, 400) and (16, 0) represent the solution to the given situation of Rashawn.

In mathematics, a graph is a visual representation or diagram that shows facts or values in an ordered way.

The relationships between two or more items are frequently represented by the points on a graph.

Graphs and charts are useful visual aids because they make information accessible and quick to understand.

Therefore, it is not unexpected that print and electronic media frequently use graphs.

When data is displayed as a graph rather than a table, it can often be easier to understand because the graph might show a pattern or comparison.

So, Rashawn consumed 25 pages of his book daily till it was finished. There were 400 pages in his book.

400 / 25 = 16 days is the estimated number of days he needs to finish the book.

He will have 400 pages finished in 0 days and 0 pages in 16 days.

As a result, the situation is represented by a graph with a line segment in the first quadrant.

Days are shown on the x-axis, and Pages left are listed on the y-axis.

The line segment's ends are (0, 400) and (16, 0).

Therefore, graph (C) which has points (0, 400) and (16, 0) represent the solution of the given situation of Rashawn.

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Complete question:
Rashawn read 25 pages of his book each day until he finished the book. His book was 400 pages long.

Which sketch represents this situation?

a) A graph in the first quadrant containing a line segment. The x axis is labeled Days and the y axis is labeled Pages remaining. The endpoints of the line segment are begin ordered pair 0 comma 400 end ordered pair and begin ordered pair 25 comma 0 end ordered pair.

b) A graph in the first quadrant containing a line segment. The x axis is labeled Days and the y axis is labeled Pages remaining. The endpoints of the line segment are begin ordered pair 0 comma 16 end ordered pair and begin ordered pair 400 comma 0 end ordered pair.

c) A graph in the first quadrant containing a line segment. The x axis is labeled Days and the y axis is labeled Pages remaining. The endpoints of the line segment are begin ordered pair 0 commas 400 end ordered pair and begin ordered pair 16 commas 0 ends ordered pair.

d) A graph in the first quadrant containing a line segment. The x axis is labeled Days and the y-axis is labeled Pages remaining. The endpoints of the line segment are begin ordered pair 0 commas 25 ends ordered pair and begin ordered pair 400 commas 0 ends ordered pair.

Answer:

246.76$

Step-by-step explanation:

199 x .24 =

47.76

199 + 47.76 =

246.76

Answer:

x=2

Step-by-step explanation:

Because you Subtract 1 from both sides of the equation

and simplify which will give you 2x=x+2 then subtract Subtract x from both sides of the equation then simplify and you will get your answer x=2

Answer:

178.48

Step-by-step explanation:

We are asked what is 46 percent out of 388.

To solve this, we need to follow the formula when finding the percentage of a number.

P being the percentage

X being the number

Y being the answer, the forumla is

Y = P * X

Substitute :

Y = 46% * 388

Convert the percentage into a decimal,

46%/100

0.46

Y = 0.46 * 388

Multiply :

178.48 = 0.46 * 388

178.48

your welcome btw

Answer:

$5.86

Step-by-step explanation:

The total was $36.31

We were given the price of 1, which was $1.15

$36.31-$1.15 = $35.16 remaining

Since the other 6 friends ordered the same meal, they would have paid the same price, so we would divide by 6

$35.16/6 = $5.86

Answer:

BOYS = 30.

GIRLS = 12.

Step-by-step explanation:

Boys: B

Girls: G

B = (2/5)G

B + G = 42.

(2/5)G + G = 42

2G + 5G = 210

7G = 210

G = 210/7

G = 30.

B = (2/5)G

B = (2/5)(30)

B = 60/5

B = 12.

Answer:

\(\Huge \boxed{\bold{\text{12 Boys}}}\)

\(\Huge \boxed{\bold{\text{30 Girls}}}\)

Step-by-step explanation:

Let the number of girls be \(g\) and the number of boys be \(b\).

According to the problem: \(b = \frac{2}{5} \times g\)

We also know that the total number of students is 42, so \(b + g = 42\).

Now, we have two equations with two variables:

We can solve these equations to find the values of \(b\) and \(g\).

Step 1: Solve for \(\bold{b}\) in terms of \(\bold{g}\)

From the first equation, we have\(b = \frac{2}{5} \times g\)

Step 2: Substitute the expression for \(\bold{b}\) into the second equation

Replace \(b\) in the second equation with the expression we found in step 1.

\(\frac{2}{5} \times g + g = 42\)

Step 3: Solve for \(\bold{g}\)

Now, we have an equation with only one variable, \(g\):

\(\frac{2}{5} \times g + g = 42\)

To solve for \(g\), first find a common denominator for the fractions:

\(\frac{2}{5} \times g + \frac{5}{5} \times g = 42\)

Combine the fractions:

\(\frac{7}{5} \times g = 42\)

Now, multiply both sides of the equation by \(\frac{5}{7}\) to isolate \(g\):

Step 4: Find the value of \(\bold{b}\)

Now that we have the value of \(g\), we can find the value of \(b\) using the first equation:

So, there are 12 boys and 30 girls in the class.

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The area of the smaller rectangle (KLMN) is 16.

Since rectangles ABCD and KLMN are similar, their corresponding sides are proportional.

Let's assume the length of side AB in rectangle ABCD is x, and the length of side KL in rectangle KLMN is y.

We can set up the proportion:

(x/y) = (20/16)

To find the area of the smaller rectangle, we need to determine the ratio of their areas.

Since the area of a rectangle is given by the product of its length and width, the ratio of the areas will be equal to the square of the ratio of their sides:

(Area of ABCD)/(Area of KLMN) = (x²)/(y²)

We are given that the area of ABCD is 25, so we have:

25/(Area of KLMN) = (x²)/(y²)

To find the area of KLMN, we need to substitute the values of x and y from the proportion:

25/(Area of KLMN) = (20/16)²

Simplifying the right side:

25/(Area of KLMN) = (5/4)²

25/(Area of KLMN) = 25/16

Cross-multiplying:

25 × 16 = 25 × (Area of KLMN)

400 = 25 × (Area of KLMN)

Dividing both sides by 25:

16 = Area of KLMN

Therefore, the area of the smaller rectangle (KLMN) is 16.

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The coordinates of V' include the following: V' (-5, -10).

In Geometry, a dilation is a type of transformation which typically changes the side lengths of a geometric object, but not its shape.

This ultimately implies that, the dimension (size) or side lengths of the dilated geometric object would increase or decrease depending on the scale factor applied.

In this scenario an exercise, we would dilate the coordinates of V at (-2, -4) by applying a scale factor of 2.5 that is centered at the origin as follows:

V (-2, -4) → V' (-2 × 2.5, -4 × 2.5) = V' (-5, -10).

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Explanation:

The two digit numbers can be broken up into a stem representing the tens digit, and the leaf is the units digit. A stem of 8 would have multiple leaves because there are a lot of values in the 80s. Something like 36 only has one stem and leaf since there aren't any other values in the 30s listed.

Note how 36 is the smallest number (min) so the smallest stem is 3. The largest number (max) is 99, so the largest stem is 9. The stems range from 3 to 9.

The value of the f(1) should be -1 when the  equation of the piecewise defined function f(x).

here first we are required to determine which expression to use for f(1). The first function does not involve 1, because it is <, and not ≤

And,

The second functions involved 1, because it has a ≤ that  meaning greater than or equal to, so this is the function we must use.

So, it can be like

f(1) = -1

= -(x^2)

= -(1)

= -1

hence,

The value of the f(1) should be -1 when the  equation of the piecewise defined function f(x).

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By trigonometric functions, the length of the hypotenuse is approximately equal to 131.571.

In this problem we find the measure of an angle and its opposite side from a right triangle, whose representation is shown in the image attached below.

Trigonometric functions are transcendent expression that relates an angle of the right triangle with two sides of the same. We can find the measure of the hypotenuse by the definition of the sine function:

sin θ = h / r

Where:

If we know that h = 45 and θ = 20°, then the length of the hypotenuse is:

r = h / sin θ

r = 45 / sin 20°

r ≈ 131.571

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Answer:

16

Step-by-step explanation:

Step-by-step explanation:

1/2+ 1/4 +2/5

we find the lcm

the lcm of 2,4 and 5 is 20

the answer is 23/20

To mixed fraction in its simplest form it is 1 3/20

Answer:

\(a) ?=23\frac{1}{24}\)

\(b)?=106\frac{34}{87}\)

Step-by-step explanation:

\(?+59\frac{5}{8} =82\frac{2}{3}\)

\(?+59\frac{5}{8}-59\frac{5}{8} =82\frac{2}{3}-59\frac{5}{8}\)

\(?=23\frac{1}{24}\)

87 × ? = 9526

87 ÷ 87 × ? = 9256 ÷ 87

\(?=106\frac{34}{87}\)

a-

the equation is 5x=30, so we need to find the real-life problem that can be represented by x=30/5

let's analyze one by one

- total books, 5 books for student, 30 students, so x=5*30 this isn't

- donations (20+10=$30) and 5 times (20+10) so x=30+30*5 this one isn't

- (4+1)people and they spent $30, so each one pay x=30/5 this one IS

b-

Solve the equation,

x=30/5=6

x=6

c-

The value of x represents each one pays $6

The number of students who play chess, but not tennis is 3.

Given that there are 25 students on the Geoville Math Team and that 11 students play chess and 15 play tennis. Also, it's given that 3 students play neither chess nor tennis. Let's solve the problem using a Venn diagram as shown below:In the diagram, let's label the unknown part, i.e. the number of students who play chess but not tennis, as "x".Now, let's fill in the diagram with the given values.

The number of students who play chess is 11, so we write "11" in the chess circle. The number of students who play tennis is 15, so we write "15" in the tennis circle. And the number of students who play neither chess nor tennis is 3, so we write "3" outside of both circles.

To find the number of students who play chess but not tennis, we need to subtract the number of students who play both chess and tennis from the total number of students who play chess. From the diagram, we can see that 8 students play both chess and tennis (since 11 - 3 = 8). Therefore, the number of students who play chess but not tennis is:11 - 8 = 3 students.

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Part (a)

\(\overline{x}=\frac{\sum x}{n} \\ \\ \boxed{\sum x=n\overline{x}}\)

Part (b)

\(\sum x^2-2\overline{x}(n\overline{x})+n\overline{x}^2 \\ \\ =\sum x^2 -2n\overline{x}^2+n\overline{x}^2 \\ \\ =\boxed{\sum x^2-n\overline{x}^2}\)

Answer:

the probability is 5 ÷ 51

Step-by-step explanation:

The computation of the probability is shown below:

 = green jelly beans ÷ total jelly beans × remaining jelly beans ÷ remaining total jelly beans

=  6 ÷ 18 × 5 ÷ 17

= 30 ÷ 306

= 5 ÷ 51

Hence, the probability is 5 ÷ 51

Answer:

Step-by-step explanation:

sp = 504

gain = 12%

in this case

sp =100%+12%=504

112%=504

1%=504/112 =4.5

100%=450

so cost =$450

Hope im correct, if i am im glad to be of service.

Answer:

-86.07

Step-by-step explanation:

Theres a negative 86 and a 7 over 100.

Answer:

-86.07

Step-by-step explanation:

A percentage is a way to describe a part of a whole. The investment that was put in the account is 6805, while the amount that is invested in the stock is 5505.

A percentage is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25 which is equal to 25%.

To convert a fraction to a percentage, convert the fraction to decimal form and then multiply by 100 with the '%' symbol.

Le the amount that is put into the account is x, while the amount that is invested in the stock market is y. Given the investor puts $1300 more in the first account than in the stock fund, therefore, the equation can be written as,

x - y =1300

x = 1300 + y

Also,  at the end of the year the total interest from the two investments was $1270. Therefore, we can write,

0.13x + 0.07y = 1270

Substitute the value of x from the above,

0.13(1300 + y) + 0.07y = 1270

169 + 0.13y + 0.07y = 1270

0.20y = 1101

y = 5505

substitute the value of y in the first equation,

x - y = 1300

x = 6805

Hence, the investment that was put in the account is 6805, while the amount that is invested in the stock is 5505.

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The statement which is not true about the circle M is ∆ABM is isosceles.

The correct answer choice is option 2.

Based on the circle M;

diameter AC,

chords AB and BC,

radius MB

Isosceles triangle: This is a type of triangle which has two equal sides and angles.

Equilateral triangle is a triangle which has three equal sides and angles.

Hence, ∆ABM is equilateral triangle.

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On solving the provided question we can say that As a result, set D denotes a linear function.

The slope of a line indicates how steep it is. The gradient's mathematical equation is known as "gradient overflow" (the change in y divided by the change in x). The slope is defined as the ratio of the vertical change (rise) between two places to the horizontal change (run). The slope-intercept form of an equation is used to express a straight line's equation, which is written as y = mx + b. The y-intercept is found where the slope of the line is m, b is b, and (0, b). For example, consider the slope and y-intercept of the equation y = 3x - 7.The slope of the line is m. b is b at the y-intercept, and (0, b).

The set of ordered pairs expressing a linear function must meet the requirement that any two locations in the set have a constant rate of change (slope).

We can determine the rate of change between the two supplied positions using set D:

slope = (y2 - y1) / (x2 - x1)

slope = (1 - 2) / (2 - (-1))

slope = -1/3

We may use the slope-intercept form of a linear equation to see if the remaining points in set D fulfil the same rate of change: y = mx + b, where m is the slope and b is the y-intercept.

We can solve for b using the first point in D, (-1,2):

2 = (-1/3)(-1) + b

b = 7/3

So the linear equation for set D is: y = (-1/3)x + 7/3

Now we can check if the remaining points in set D satisfy this equation:

(2, 1): 1 = (-1/3)(2) + 7/3 (satisfies the equation)

As a result, set D denotes a linear function.

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Answer:

this is the solution