Please help me, I really need help

Answer:√40 to be the square root of 40, and can investigate between which two whole numbers it lies. The number 40 lies between 36 and 49 hence √40 lies between 6 and 7.

Answer:

Between 6 and 7

Step-by-step explanation:

40 lies between 36 and 49

find square root of each (6 and 7)

checkers, also called drafts, board game, one of the oldest games in the world. Checkers are played by two people facing each other on a chessboard with 64 light and dark squares, just like a chessboard.

with n=0 clearly 1 path.

with n=1 clearly 0 ways.

with n=2 clearly 0 ways.

with n=3 clearly 0 ways.

If n=4, then the columns must be 2,2,0 and the rows must be 2,2,0. So the tiles must form the corners of the rectangle, there are 3 ways to select the top and bottom sides of the rectangle and 3 ways to select the left and right sides of the rectangle. So a total of 9.

If n=5, consider how many per row, it can only be 3,2,0. And clearly this means that one column has exactly one chip, so zero paths.

If n=6, consider how many per row, it could be 3,3,0 or 2,2,2. If it is 3,3,0 then there are clearly 3 ways. If it is 2,2,2, there are two possible column arrangements: 3,3,0 or 2,2,2. The first produces 3 arrangements and the second 6 arrangements. 12 ways in total.

If n=7 then it doesn't just work that the two "missing" squares are in the same row/column, there are obviously 6×3=18 ways to pick the two missing tiles, so there are (97) −18=18 correct arrangements .

If n=8 each method clearly works, then 9.

If n=9 each method clearly works, then 1.

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We can express the interval where f(x) is continuous as: (-∞, -5) ∪ (-5, 4) ∪ (4, ∞). We find the values of x for which the denominator is non-zero.

To determine where the function f(x) = (x-9)/((x-4)(x+5)) is continuous algebraically, we need to find the values of x for which the denominator is non-zero.

The function will be continuous for all x except the values that make the denominator zero. We can find these values by setting the denominator equal to zero and solving for x.

The function f(x) is defined as f(x) = (x-9)/((x-4)(x+5)). To determine where f(x) is continuous, we need to find the values of x that make the denominator, (x-4)(x+5), non-zero.

Setting the denominator equal to zero, we have:

(x-4)(x+5) = 0

To find the values of x that satisfy this equation, we set each factor equal to zero and solve for x:

x-4 = 0 => x = 4

x+5 = 0 => x = -5

Therefore, the function f(x) is not continuous at x = 4 and x = -5, because these values make the denominator zero. For all other values of x, the function f(x) is continuous.

In interval notation, we can express the interval where f(x) is continuous as:

(-∞, -5) ∪ (-5, 4) ∪ (4, ∞)

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10^-5 = 1/100,000

10^20 = 100,000,000,000,000,000,000

10^-12 = 1/1,000,000,000,000

10^0 = 1

10^3 = 1,000

10^-85 =  a very tiny number (basically 0)

Answer: 10^-85, 10^-12, 10^-5, 10^0, 10^3, 10^20

You can also see that it goes in order so the higher the power, the larger the number.

Barbara wrote an equation, 1.25x + 1.49, to find the number of bottles (x) she needs to sell in order to earn $100.

The equation 1.25x + 1.49 represents the total earnings Barbara would make by selling x bottles of water at $1.25 per bottle and x bottles of iced tea at $1.49 per bottle. The term 1.25x represents the earnings from selling water, and 1.49 represents the earnings from selling iced tea.

To find the number of bottles (x) Barbara needs to sell to earn $100, we set the equation equal to $100 and solve for x:

1.25x + 1.49 = 100

By rearranging the equation and isolating the variable x, we can solve for x. This equation can be solved using algebraic techniques such as combining like terms, subtracting 1.49 from both sides, and dividing by 1.25.

Once we determine the value of x, we will know the number of bottles Barbara needs to sell in order to earn $100.

Please note that without the complete equation or additional information, we cannot provide the specific solution for x or the exact number of bottles Barbara needs to sell to earn $100.

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Answer:

x > 3   or   3 < x < infinity

Step-by-step explanation:

Since the circle over 3 is "open" (not filled in), this means that the symbol we use for the inequality is simply "greater than" rather than "greater than/equal to".

Additionally, there is no point on the right side; it is an infinite arrow. This means that x is equivalent to anything above 3.

Therefore, x is greater than 3 is the correct inequality. Depending on the answer your teacher is looking for, however, it could also be 3 < x < infinity. this is because there is no visible end to the arrow.

*As I don't know what you're focusing on, I cannot tell you which answer your teacher is looking for. Base your answer off the form of the answers of the lesson you are focusing on.

Then subtract the time of the 60 minute class from both sides of the equation, divide both sides of the equation by 45, and the answer is 5.

1. Start by writing an equation that equation by 45, and the answer is 5.adds the total time of the 60 minute class to the time of all of the weekday classes multiplied by x, the number of weekday classes.

60 + 45x = 285

2. Subtract the time of the 60 minute class from both sides of the equation to solve for x.

45x = 225

3. Divide both sides of the equation by 45 to solve for x.

x = 5

4. The number of weekday classes is 5.

There were 5 weekday classes that lasted a total of 285 minutes. This can be determined by writing an equation that adds the 60 minute class to the time of all the weekday classes multiplied by x, the number of weekday classes. Then subtract the time of the 60 minute class from both sides of the equation, divide both sides of the equation by 45, and the answer is 5.

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Answer:

$12.72 or $25.44

Step-by-step explanation:

if he buys 2 tickets that are $12 each. half of 12 is 6 so you will have to pay 12 plus tax(6%). to find tax you would multiply 12 x .06 which would be $12.72. if it say the tickets are half off from $24 being $12 each then the answer would be $25.44. the question  dosent specify that.

hope i helped

Answer:

Following are the solution to this question:

Step-by-step explanation:

Using formula:

\(\text{Simple Interest} = \frac{P \times R \times T}{100} \\\\\text{ Total amount} = \text{principle}+ \text{Simple Interest}\)

In question (1):

\(Principle= \$ 600\\Rate = \ 8 \%\\Time= \ 5\)

In point a:

\(\to \frac{P \times R \times T}{100} \\\\\to \frac{(600 \times 8 \times 5)}{100}\\\\ \to 240\)

In point b:

\(\to amount = principle \ +\ simple \ interest\)

                 \(= 600 + 240 \\\\= 840\)

In question (2):

\(Principle= \$ 12,450\\Rate = \ 7.25 \%\\Time= \ 6\)

In point a:

\(\to \frac{P \times R \times T}{100} \\\\\to \frac{(12,450 \times 7.25 \times 6)}{100}\\\\ \to 5,415.75\)

In point b:

\(\to amount = principle \ +\ simple \ interest\)

                 \(= 12,450 + 5,415.75 \\\\= 17,865.75\)

The 3 question is incomplete, that's why it can't be solved.

Answer: There were 99 more skateboarders than skaters at the park on Saturday.

Step-by-step explanation:

Let there were 8x skaters and 3x skateboarders on Friday.

There were 168 skaters on Friday.

So, \(8x=168\)

\(\Rightarrow\ x=\dfrac{168}{8}=21\)

3x = 3 (21)=63

Total skaters and skateboarders on Friday = 168+63 =  231

Also, the  ratio of the number of skaters to the number of skateboarders was 2:5

Let there were 2x skaters and 5x skateboarders on Saturday.

Then,

\(2x+5x= 231\\\\\Rightarrow\ 7x = 231\\\\\Rightarrow\ x=\dfrac{231}{7}\)

\(\Rightarrow\ x=33\)

Number of skaters = 2(33) = 66

Number of skateboarders = 5(33) = 165

Difference = 165-66= 99

Hence, there were 99 more skateboarders than skaters at the park on Saturday.

the two angles that satisfy sinθ = -√2/2 are 5π/4 and 7π/4.

Why it is?

sinθ = -√2/2 is equivalent to saying that the sine of angle θ is negative and equal to √2/2.

We know that the sine function is positive in the first and second quadrants, and negative in the third and fourth quadrants. Therefore, we can limit our search for angles θ to the third and fourth quadrants where the sine function is negative.

In the third quadrant, the reference angle that satisfies sinθ = √2/2 is π/4, since the sine function is negative in this quadrant. Therefore, the angle θ in the third quadrant that satisfies sinθ = -√2/2 is:

θ = π + π/4 = 5π/4

In the fourth quadrant, the reference angle that satisfies sinθ = √2/2 is also π/4, since the sine function is negative in this quadrant. Therefore, the angle θ in the fourth quadrant that satisfies sinθ = -√2/2 is:

θ = 2π - π/4 = 7π/4

So the two angles that satisfy sinθ = -√2/2 are 5π/4 and 7π/4.

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Answer:

the answer is 5x^2+9x-18y

Step-by-step explanation:

since 5x^2 does not have like terms, it is left alone. next, combine all of the x variables which are 7x and 2x to get 9x. that leaves you with the y values which are -8y and -10y to get -18y. when combining terms, always look for similar variables. remember, just because some value has the same variable doesn't mean it is necessarily the same. for example, you cannot combine x^2 and x because one has a power and the other does not. i hoped this helped.

i. weekly receipts at a clothing boutique

ii. monthly demand for an automotive part

Time series data refers to information collected and recorded at regular intervals over a specific period. In the case of i. weekly receipts at a clothing boutique and ii. monthly demand for an automotive part, both data sets are examples of time series data.

Time series data consists of observations recorded over regular intervals, allowing for the analysis of patterns and trends over time. In i. weekly receipts at a clothing boutique, the data is collected on a weekly basis, providing insights into the boutique's revenue fluctuations over different weeks. Similarly, ii. monthly demand for an automotive part captures the demand for the part on a monthly basis, enabling analysis of monthly variations and seasonal patterns.

On the other hand, iii. quarterly sales of automobiles do not fall under time series data. While it represents sales data, the intervals between measurements are not consistent enough to qualify as time series. Quarterly intervals are less frequent and may not capture shorter-term trends or variations as effectively as weekly or monthly intervals.

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Answer:

we have the equation y = (1/2)*x + 4.

now, any equation that passes through the point (4, 6) will intersect this line, so if we have an equation f(x), we must see if:

f(4) = 6.

if f(4) = 6, then f(x) intersects the equation y = (1/2)*x + 4 in the point (4, 6).

If we want to construct f(x), an easy example can be:

f(x) = y = k*x.

such that:

6 = k*4

k = 6/4 = 3/2.

then the function

f(x) = y= (3/2)*x intersects the equation  y = (1/2)*x + 4 in the point (4, 6)

Answer:

A. y=6

Step-by-step explanation:

For anyone who doesn't wanna read a boring giant paragraph.

Answer: 10 seconds, decreasing, standing still,

Step-by-step explanation:

The probability, to the nearest thousandth, of getting exactly 5 tails is 0.031

The likelihood of getting tails on a single flip of a reasonable coin is 0.5. To discover the likelihood of getting precisely 5 tails in 5 flips, we utilize the binomial likelihood equation:

P(X = k) = (n select k) * \(p^k * (1-p)^(n-k)\)

where:

n = 5 (number of trials)

k = 5 (number of victories)

p = 0.5 (likelihood of tails on a single flip)

Stopping within the values, we get:

P(X = 5) = (5 select 5) * \(0.5^5 * (1-0.5)^(5-5)\)

= 1 * 0.03125 * 1

= 0.03125

So the likelihood of getting precisely 5 tails in 5 flips is around 0.031 (adjusted to the closest thousandth). 

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Answer:

120 f

Step-by-step explanation:

The expression cos⁡(−x)+tan⁡(−x)sin⁡(−x) simplifies to cos⁡(x)+tan⁡(x)sin⁡(x).

To find the minterms using Karnaugh maps (K-maps), we need to create the K-maps for each Boolean expression and identify the cells corresponding to the minterms.

a) For the expression wyz + w'x' + wxz':

We have three variables: w, x, and yz. We create a 2x4 K-map with w and x as the inputs for the rows and yz as the input for the columns:

\begin{array}{|c|c|c|c|c|}

\hline

\text{w\textbackslash x,yz} & 00 & 01 & 11 & 10 \\

\hline

0 & & & & \\

\hline

1 & & & & \\

\hline

\end{array}

Next, we analyze the given expression wyz + w'x' + wxz' and identify the minterms:

- For wyz, we have the minterm 111.

- For w'x', we have the minterm 010.

- For wxz', we have the minterm 110.

Placing these minterms in the corresponding cells of the K-map, we get:

\begin{array}{|c|c|c|c|c|}

\hline

\text{w\textbackslash x,yz} & 00 & 01 & 11 & 10 \\

\hline

0 & & & & \\

\hline

1 & & \textbf{1} & & \textbf{1} \\

\hline

\end{array}

Therefore, the minterms for the expression wyz + w'x' + wxz' are 111, 010, and 110.

b) For the expression A'B + A'CD + B'CD + BC'D':

We have four variables: A, B, C, and D. We create a 4x4 K-map with AB as the inputs for the rows and CD as the inputs for the columns:

\begin{array}{|c|c|c|c|c|}

\hline

\text{A\textbackslash B,CD} & 00 & 01 & 11 & 10 \\

\hline

0 & & & & \\

\hline

1 & & & & \\

\hline

\end{array}

Next, we analyze the given expression A'B + A'CD + B'CD + BC'D' and identify the minterms:

- For A'B, we have the minterm 10xx.

- For A'CD, we have the minterm 1x1x.

- For B'CD, we have the minterm x11x.

- For BC'D', we have the minterm x1x0.

Placing these minterms in the corresponding cells of the K-map, we get:

\begin{array}{|c|c|c|c|c|}

\hline

\text{A\textbackslash B,CD} & 00 & 01 & 11 & 10 \\

\hline

0 & & & & \textbf{1} \\

\hline

1 & \textbf{1} & \textbf{1} & \textbf{1} & \\

\hline

\end{array}

Therefore, the minterms for the expression A'B + A'CD + B'CD + BC'D' are 1000, 1011, 1111, and 0110.

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We are given a problem regarding trigonometric identities and asked to resolve for theta.

Recall that:

Therefore, we have:

In radians, we have:

x-int  (-40,0)

y-int (0,15)

(x,y)

its just asking for the point when the line crosses or intercpets the x axis (horizontal, left to right) and y axis (vertical, up and down).

also its going by 5's if that helps

Answer:

5x + 8

Step-by-step explanation:

2x+3+3x+5

2x+8+3x

And, thus 5x + 8 is the answer.

sorry if i get it wrong.......

The solution for x^2 - 3x - 28 ≥ 0 isD) (–7, -4] ∪ [4, ∞).

To find the solution for x^2 - 3x - 28 ≥ 0, we can use the method of factoring and determining the sign of the quadratic expression.

Factorize the quadratic expression: x^2 - 3x - 28 = (x - 7)(x + 4).

Set each factor equal to zero and solve for x:

x - 7 = 0 => x = 7

x + 4 = 0 => x = -4

Draw a number line and mark the critical points -7, -4, and 4.

Test intervals to determine the sign of the expression. We can choose any value within each interval and evaluate the expression.

For x < -7, let's choose x = -8:

(-8 - 7)(-8 + 4) = (-15)(-4) = 60, which is positive.

For -7 < x < -4, let's choose x = -5:

(-5 - 7)(-5 + 4) = (-12)(-1) = 12, which is positive.

For -4 < x < 4, let's choose x = 0:

(0 - 7)(0 + 4) = (-7)(4) = -28, which is negative.

For x > 4, let's choose x = 5:

(5 - 7)(5 + 4) = (-2)(9) = -18, which is negative.

Analyze the signs of the expression in each interval to determine the solution.

The solution is D) (–7, -4] ∪ [4, ∞), meaning all x-values between -7 and -4 (inclusive) and all x-values greater than 4 satisfy the inequality x^2 - 3x - 28 ≥ 0.

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Answer:

1/4 and 1/2

Step-by-step explanation:

Answer:

0.75

Step-by-step explanation:

The answer is 0.75 you can calculate yourself it's easy.

The probability she makes at least 65 is 0.0139.

What is probability?

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a proposition is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.

\(\begin{aligned}P(x \geq 65) & =1-P(x < 65) \\& =1-P\left(\frac{x-\mu}{n} < \frac{65-56}{4.0988}\right) \\& =1-P(z < 2.1958) \\& =1-0.9861 \\& =0.0139\end{aligned}\)

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The value of the given expression is approximately 71.31.

\($$75 - 12(20 ÷ 2.5) ÷ 26$$\)

The Order of Operations states that the sequence of steps in which we carry out the operations of a given problem.

So, we follow the Order of Operations to solve this expression.

Firstly, we will evaluate the parentheses:

\($$20 ÷ 2.5 = 8$$\)

Now, the given expression becomes:

\($$75 - 12 × 8 ÷ 26$$\)

Then, we will evaluate multiplication and division in order from left to right.

12 × 8 = 96

So, the given expression becomes:

\($$75 - 96 ÷ 26$$\)

Evaluating division, we get:

\($$75 - 3.6923$$\)

Now, we will add and subtract from left to right.

\(75 − 3.6923 ≈ 71.31\)

Therefore, the value of the given expression is approximately 71.31.

So, the required  is approximately 71.31.

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Answer:

-3.68 = n

Step-by-step explanation:

1. Simplify

-2.04-12= n- 3+2n

2. Isolate n

-2.04-12+3=n+2n

3. Simplify

-11.04=3n

4. Divide both sides by 3

-3.68 = n

Answer:

The answer is 11, I think, hope this helps!

Step-by-step explanation:

=================================================

Solve.

\( \tt4 + 2(5) + ( - 3) \\ = \tt4 + 10 + ( - 3) \\ = \tt14 + ( - 3) \\ = \underline{ \boxed{\tt 11}}\)

Therefore, the answer is 11.

=================================================

\( \underline{{\sf \: \: \#CarryOnLearning! \: \:}} \)

Average is determined by the sum of test scores divided by total number of tests. This can be represented in this equation:

95 + X / 2 = 92 ⇒ Multiply both sides by 2 to get of the divided by 2

95 + X /2 (2) = 92 (2)

95 + X = 184 ⇒ Subtract 95 from both sides to isolate x

95 -95 + X = 184 -95

X = 89

Therefore, they must get at least 89% to maintain an A.

Answer:

b. interaction effect

Step-by-step explanation:

In a regression model, the interaction effect is present when a predictor variable changes the effect of another predictor variable on the outcome.

In a regression model, the interaction effect exists when one predictor variable impacts the outcome of another predictor variable differently than when examined individually. It refers to the interaction between two or more predictor variables and their influencers on an outcome or response variable. For example, in a regression model, studying and having a quiet place may individually contribute to a better score on a test, but perhaps studying in a quiet place provides a significantly better effect than the sum of those two effects separately. This would be considered an interaction effect.

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