(1-cosx)/(tanx) + (sinx)/(1+cosx) trig identity’s

Answer:

The choice B.

\(f(x) ^{ - 1} = 7 - 21x\)

I hope I helped you^_^

Answer:

a= -2     b =4

Step-by-step explanation:

I put it in a calculator and found the answer

Answer:

it's -5/2

A-P-E-X

Answer:

The constraints are:

Plot the graphs of the constraints

From the graph (see attachment), the only optimal point is (3,4)

Substitute 3 for x and 4 for y in the objective function.

So, we have:

Hence, the maximum value of C is 17

Step-by-step explanation: Hope this helps!!!

Answer:

The statement "The value of f(–10) = 82" is not true. To find the value of f(–10), we substitute –10 for x in the equation:

Step-by-step explanation:

The statement "The value of f(–10) = 82" is not true. To find the value of f(–10), we substitute –10 for x in the equation:

f(–10) = (–10)^2 – 5(–10) + 12 = 100 – (–50) + 12 = 162

The statement "The graph of the function is a parabola" is true. Because the equation of the function is of the form f(x) = ax^2 + bx + c, where a, b, and c are constants and a is not equal to 0, the graph of the function is a parabola.

The statement "The graph of the function opens down." is true. The coefficient of x^2 is a positive value, which means the parabola opens down.

So, the true statements are

The graph of the function is a parabola.

The graph of the function opens down.

The graph does not contain the point (20, –8)

The optimal profit is $38.

What is the optimal profit?

The optimum profit is the highest level of profit that an individual can achieve. An individual is at the optimum profit level when the marginal revenue from the sale of a commodity equals the marginal cost of production.

Here,

We have to determine the optimal prices for the dessert that the restaurant should charge during the evening hours and during the day, the associated quantities sold, and the total daily profit.

Since dessert is the signature mousse of the restaurant implies the restaurant is a monopolist in this case.

So, profit-maximizing condition would be

μ(R) = μ(C)

Now, for daytime μ(R)d = μ(C)t never hold. So it is profitable to produce until

μ(R)d > μ(C)t.

Since, μ(R)d < μ(C) for Q(d) = 2 implies that:

The optimal price in the daytime is $10 when the output is 1.

Now, for evening μ(R)e = μ(C)t hold when Q(e) = 6

So, the optimal price in the evening is $14 when the output is 6.

Optimal profit = P(e) × Q(e) + P(d) × Q(d) - (μ(C₁) + μ(C₂))(Q(e)+Q(d))

= 14×6+ 10×1 - (3+5)(6+1)

= 38

Hence, the optimal profit is $38.

Question: A restaurant faces very high demand for its signature mousse desserts in the evening but is less busy during the day. Its manager estimates that the inverse) demand curves are pe = 20 - Q. in the evening and pa = 11 - Q. during the day, where e and d denote evening and daytime. The marginal cost of producing its dessert, MC1, is $3. Any morning, the restaurant can bring in additional tables and convert its storage space to seating to increase capacity for that day. Creating enough extra capacity to provide one more dessert in the evening or the day costs $5, which is the restaurant's marginal capacity cost MC. Pe 20 Qe Pa 11 Qd MC 3 MC2 5 MR. 20 MR. 11 = = 2 Qe.

Determine the optimal prices for the dessert that the restaurant should charge during the evening hours and during the day, the associated quar ties sold, and the total daily profit. The optimal price in the daytime is when the output is in the evening is when the output is The optimal price The optimal profit is

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The equation of the tangent line to the curve `y = 2ex cos(x)` at the point (0,2) is given by `y = 2ex + 2`.

To find an equation of the tangent line to the curve at the given point (0,2) whose equation is given by `y = 2ex cos(x)`, we need to determine the derivative `y'` of `y = 2ex cos(x)` first. Using the product rule, we have;

`y = 2ex cos(x)`...let `u = 2ex` and `v = cos(x)`, then `u' = 2ex` and `v' = -sin(x)`.`y' = u'v + uv'` `= 2ex cos(x) - 2ex sin(x)` `= 2ex(cos(x) - sin(x))`

Therefore, the derivative of `y = 2ex cos(x)` is `y' = 2ex(cos(x) - sin(x))`.

The equation of the tangent line to the curve at the point (0,2) is obtained by using the point-slope formula, which is given by: `y - y1 = m(x - x1)`where `(x1,y1)` is the point of tangency, `m` is the slope of the tangent line.

Substituting the values of `m`, `x1` and `y1`, we obtain: `m = y' |(0,2)` `= 2e(1 - 0)` `= 2e`Using the point-slope formula with `(x1,y1) = (0,2)` and `m = 2e`, we have: `y - 2 = 2e(x - 0)` `y - 2 = 2ex` `y = 2ex + 2`

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Answer:

The answer is 12ac^14/b^3

Answer

12ac^14/b^3

Step-by-step explanation:

The probability that the individual likes both vehicle #1 and vehicle #2 is 0.40.

The probability that the individual liked at least one of the other two vehicles, given that he/she did not like vehicle #1, is approximately 1.044.

a. To find the probability that the individual likes both vehicle #1 and vehicle #2, we need to calculate the intersection of events a1 and a2, denoted as a1 ∩ a2.

p(a1 ∩ a2) = p(a1) + p(a2) - p(a1 ∪ a2)

= 0.55 + 0.65 - 0.80

= 0.40

b. The probability of the union of events a2 and a3, denoted as a2 ∪ a3, can be calculated as:

p(a2 ∪ a3) = p(a2) + p(a3) - p(a2 ∩ a3)

= 0.65 + 0.70 - 0.88

= 0.47

The interpretation of p(a2 ∪ a3) is the probability that the individual likes either vehicle #2 or vehicle #3 (or both).

c. Two events, a2 and a3, are independent if the occurrence of one event does not affect the probability of the other event. We can determine independence in two ways:

Check if p(a2 ∩ a3) = p(a2) * p(a3)

If p(a2 ∩ a3) = 0.40 and p(a2) * p(a3) = 0.65 * 0.70 = 0.455, since these values are not equal, events a2 and a3 are not independent.

Check if p(a2 | a3) = p(a2)

If the probability of event a2 given that event a3 has occurred is equal to the probability of event a2, then the events are independent. However, this information is not provided in the given data, so we cannot determine independence based on this criterion.

Therefore, events a2 and a3 are not independent.

d. If we know that the individual did not like vehicle #1, we are interested in finding the probability that he/she liked at least one of the other two vehicles. This can be represented by the event a2 ∪ a3.

To calculate this probability, we can use the formula:

p(a2 ∪ a3 | not a1) = p(a2 ∪ a3) / (1 - p(a1))

= 0.47 / (1 - 0.55)

= 0.47 / 0.45

≈ 1.044

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Answer:

672 had dark hair, 592 had blond hair, and 48 had red hair

Step-by-step explanation:

To solve this problem, we need to first find the total number of people for each hair color based on the given ratio.

Let's start by finding the common factor that we can use to scale the ratio up to the total number of people, which is 1,312:

42 + 37 + 3 = 82

We can then divide 1,312 by 82 to get the scaling factor:

1,312 ÷ 82 = 16

This means that for every 16 people, there are 42 with dark hair, 37 with blond hair, and 3 with red hair.

To find the actual number of people with each hair color in the town meeting, we can multiply the scaling factor by the number of people for each hair color in the ratio:

Dark-haired people: 42 × 16 = 672

Blond-haired people: 37 × 16 = 592

Red-haired people: 3 × 16 = 48

Therefore, there are 672 people with dark hair, 592 people with blond hair, and 48 people with red hair at the town meeting.

Answer:

8 maybe

Step-by-step explanation:

Answer:

$105 per hour

Step-by-step explanation:

$648.50 - $71 = $577.50

$577.50 / 5.5 = $105 per hour

105 x 5.5 = 575.50

+ 71.00

648.50

The per hour charge of the technician is given as $15.

A ratio is the relation between two numbers as a / b. A proportion is the equality of two ratios as a / b = c / d.

Ratio and proportion can be applied to solve Mathematical problems dealing with unit values of the quantities.

The given problem can be solved by ratio method as follows,

The remaining cost charged by the technician is $648.50 - $71 = $577.50

Now, the per hour charge is remaining cost divided by total number of hours as given below,

577.50/5.5

= 57750/550

= 15

Hence, the cost of labor per hour is given as $15.

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the maximum number of possible non-zero values in an adjacency matrix of a simple graph with n vertices is (n-1) × n / 2.

In an adjacency matrix of a simple graph with n vertices, the maximum number of possible non-zero values can be found by considering that each vertex can be connected to every other vertex except itself (as self-loops are not allowed in a simple graph).

For each vertex, there are (n-1) possible connections to other vertices. However, since the adjacency matrix is symmetric for an undirected graph (as each edge is represented twice), we only need to consider the upper or lower triangular portion of the matrix.

The number of non-zero values in the upper triangular portion (or lower triangular portion) of the adjacency matrix can be calculated using the formula

Number of non-zero values = (n-1) + (n-2) + (n-3) + ... + 1 = (n-1) × n / 2

Therefore, the maximum number of possible non-zero values in an adjacency matrix of a simple graph with n vertices is (n-1) × n / 2.

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Answer:

Xjxhxbxbxbxbxjxjs sjsnsndbxnxj

Answer:

x=$20/$2.55.

Step-by-step explanation:

if each package is $2.55 then and it cost $20 then you will have to divide the numbers wich will give u x

Answer:

20 - 2.55x

Step-by-step explanation:

20 is the dollar bill Sophie bought the packages with,  x represents the number of packages bought and 2.55 is the price for each, so by subtracting 20 by the cost of the total packages results in the amount of change the cashier should give back to Sophie.

For example, if Sophie bought 3 packages of graph paper with a $20 bill the cashier should give back to Sophie $12.35.

20 - 2.55 (3)

20 - 7.65  

12.35

hope this helps!

The sum of the square of the constants is 3/4

Given the equation \(\frac{1}{a+1} +\frac{1}{b+1} +\frac{1}{c+1} =2\)

The partial form of the equation is given as:

Solve for the constant "a"

\(\frac{1}{a +1} = 2\\a+1 = \frac{1}{2} \\a = \frac{1}{2} - 1\\a =-\frac{1}{2}\)

Hence \(a=b=c=-\frac{1}{2} \\\)

Taking the square of the constant, we will have:

\(a^2 + b^2 + c^2 =(-1/2)^2 +(-1/2)^2+(-1/2)^2\\a^2 + b^2 + c^2 =1/4 + 1/4 + 1/4\\a^2 + b^2 + c^2 =3/4\)

Hence the sum of the square of the constants is 3/4

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Answer -the sum of the square of the consonants is 3/4

Answer:

C

Step-by-step explanation:

it was correct for me on edge

In analyzing the performance of implementing the given methods over Singly Linked List and Doubly Linked List data structures, we consider the Big-O notation, which provides insight into the time complexity of these operations as the size of the list increases.

Add to Start of List:

Singly Linked List: O(1)

Doubly Linked List: O(1)

Both Singly Linked List and Doubly Linked List offer constant time complexity, O(1), for adding an element to the start of the list.

This is because the operation only involves updating the head pointer (for the Singly Linked List) or the head and previous pointers (for the Doubly Linked List). It does not require traversing the entire list, regardless of its size.

Add to End of List:

Singly Linked List: O(n)

Doubly Linked List: O(1)

Adding an element to the end of a Singly Linked List has a time complexity of O(n), where n is the number of elements in the list. This is because we need to traverse the entire list to reach the end before adding the new element.

In contrast, a Doubly Linked List offers a constant time complexity of O(1) for adding an element to the end.

This is possible because the list maintains a reference to both the tail and the previous node, allowing efficient insertion.

Add at Given Index:

Singly Linked List: O(n)

Doubly Linked List: O(n)

Adding an element at a given index in both Singly Linked List and Doubly Linked List has a time complexity of O(n), where n is the number of elements in the list.

This is because, in both cases, we need to traverse the list to the desired index, which takes linear time.

Additionally, for a Doubly Linked List, we need to update the previous and next pointers of the surrounding nodes to accommodate the new element.

In summary, Singly Linked List has a constant time complexity of O(1) for adding to the start and a linear time complexity of O(n) for adding to the end or at a given index.

On the other hand, Doubly Linked List offers constant time complexity of O(1) for adding to both the start and the end, but still requires linear time complexity of O(n) for adding at a given index due to the need for traversal.

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Using the circumference of the circle, it is found that:

About 7.1 feet of railing needs to be replaced.

The circumference of a circle of radius r is given by:

\(C = 2\pi r\)

It is equivalent to 360º.

In this problem, the diameter is of 30 feet, hence the radius is 15 feet, so:

\(C = 2\pi (15) = 30\pi\)

Then, considering that the circumference is equivalent to 360º, the length to be replaced is given by:

\(L = \frac{27}{360} \times 30\pi = 7.1\)

About 7.1 feet of railing needs to be replaced.

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Answer: 7.1

Step-by-step explanation: ANSWER ON EDMENTUM/PLUTO

Answer: 122

Step-by-step explanation:

Answer:

122

Step-by-step explanation:

Answer:

Coordinates of E is (-2,7)

Step-by-step explanation:

Midpoint = ((x1+x2)/2,(y1+y2)/2)

xK = (xW + xE)/2 => xE = 2xK - xW = 2(0) - 2 = -2

yK = (yW + yE)/2 => yE = 2yK - yW = 2(3) - (-1) = 7

Answer:

Step-by-step explanation:

You want two unit vectors that make an angle of 60° with v(6, 8).

After we normalize v to a unit vector, we can find the two desired vectors by adding or subtracting 60° from its angle. The normalized vector v is ...

  v = (6, 8)/√(6² +8²) = (3/5, 4/5)

This can be rotated 60° CCW by the transformation ...

  (x, y) ⇒ (x·cos(60°)-y·sin(60°), x·sin(60°)+y·cos(60°)) = (x-y√3, x√3+y)/2

  (3/5, 4/5) ⇒ ((3-4√3)/10, (3√3+4)/10) . . . . 60° CCW from v

It can be rotated 60° CW by the transformation ...

  (x, y) ⇒ (x·cos(60°)+y·sin(60°), -x·sin(60°)+y·cos(60°)) = ((x+y√3, -x√3+y)/2

  (3/5, 4/5) ⇒ ((3+4√3)/10, (4-3√3)/10)

__

Additional comment

When the vector is written as a complex number, it can be rotated by multiplying by 1∠±60° = (cos(60°)±i·sin(60°). That is what the calculator did.

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Answer:

arc IAR

Step-by-step explanation:

major arc mean longer arc of circle connecting two end points

Answer:

Divide both sides by 22.

\frac{3y}{2}=x

2

3y

=x

2 Switch sides.

x=\frac{3y}{2}

x=

2

3y

Therefore, the statistics summary for the daily production is as follows:

a. Mean ≈ 211.67, b. Median ≈ 207.5, c. Standard Deviation ≈ 14.26

d. Margin of Error ≈ 7.03   CI high ≈ 218.70    CI low ≈ 204.64

Step 1: Arrange the data in ascending order:

198, 203, 203, 207, 208, 214, 225, 226, 243

Step 2: Calculate the mean (average):

Mean = (198 + 203 + 203 + 207 + 208 + 214 + 225 + 226 + 243) / 9 = 211.67

Step 3: Calculate the median (middle value):

Median = (207 + 208) / 2 = 207.5

Step 4: Calculate the standard deviation:

a. Calculate the squared deviations from the mean:

(198 - 211.67)² = 190.89

(203 - 211.67)² = 74.76

(203 - 211.67)² = 74.76

(207 - 211.67)² = 21.61

(208 - 211.67)² = 13.36

(214 - 211.67)² = 5.29

(225 - 211.67)² = 177.36

(226 - 211.67)² = 206.76

(243 - 211.67)²= 985.29

b. Calculate the average of the squared deviations:

Average = (190.89 + 74.76 + 74.76 + 21.61 + 13.36 + 5.29 + 177.36 + 206.76 + 985.29) / 9 = 203.59

c. Calculate the square root of the average squared deviation to get the standard deviation:

Standard Deviation = √(203.59) ≈ 14.26

Step 5: Calculate the margin of error and the confidence interval (CI) for a 90% confidence level:

a. Calculate the margin of error (ME):

ME = (Z ×Standard Deviation) / √(n)

Here, Z is the z-score corresponding to the desired confidence level. For a 90% confidence level, Z ≈ 1.645.

n is the number of data points, which is 9 in this case.

ME = (1.645×14.26) / √(9) ≈ 7.03

b. Calculate the CI high and CI low:

CI high = Mean + ME

CI high = 211.67 + 7.03 ≈ 218.70

CI low = Mean - ME

CI low = 211.67 - 7.03 ≈ 204.64

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Answer: \(-\frac{31}{12}\)

Step-by-step explanation:

The volume of the parallelepiped defined by the vectors(1) (1) (1)0 1 20 1 30 1 4 is 3 cubic units.

The volume of a parallelepiped in three-dimensional space is given by the scalar triple product of its defining vectors.

In this case, the three vectors defining the parallelepiped are:

a = (1, 1, 1)

b = (0, 1, 2)

c = (0, 1, 3)

The scalar triple product of these vectors is:

a · (b × c)

where × denotes the cross product.

We can calculate the cross product of b and c as follows:

b × c = (1)(2) - (1)(3), -(0)(3) - (1)(0), (0)(1) - (2)(1) = (-1, 0, -2)

So the scalar triple product is:

a · (b × c) = (1)(-1) + (1)(0) + (1)(-2) = -3

Hence the volume of parallelepiped is 3 units.

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