PLEASE help
evaluate the expression to find the missing values in the table ​

The cost price of the article, which is sold for Rs. 150 at a gain but if sold for Rs. 135 would have resulted in a loss equal to 50% of the original gain, is Rs. 127.50.

The cost price is the difference between the selling price and the profit or gain.

The difference is determined by subtraction.

Selling price of the article = Rs. 150

Loss if sold at Rs. 135 = 50% of the original gain

Original gain = Rs. 15 (Rs. 150 - Rs. 135)

50% of the original gain = Rs. 7.50 (Rs. 15 x 50%)

Cost price of the article = Rs. 127.50 (Rs. 135 - Rs. 7.50)

Thus, the cost price is Rs. 127.50.

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Answer:

40

112

2n^2 + 2n       C

Step-by-step explanation:

a)The correct formula is 2n^2 + 2n

So for n =4, the answer is

2*4^2 + 2*4

2*16 + 8

32 + 8

40

b) For the seventh answer you get

2 * 7^2 + 2*7

2*49 + 14

98 + 14

112

c) The correct formula to use is

2n^2 + 2n  See diagrams for the number of matchsticks to be used.

n                    2n^2 + 2n

1                    2*1^2 + 2*1

1                    2 + 2

1                    4

2                    2*2^2 + 2*2

2                    2* 4 + 4

2                    8 + 4

2                    12

3                    2*3^2 + 2*3

3                    18 + 6

3                    24

What an extremely interesting sequence. I'll bet not one person in 100 could get this without the match stick diagrams.  I'm sorry I didn't read the question more carefully.

The Answer:

Width = 6

Step-by-step explanation:

Let width be w

(3w + 8) x w = 156

3 \(w^{2}\) x 8n - 156 = 0

(w + 8 x 6) (w-6) = 0

w = 6

the expected value for the given data set will be 0.423

Probability is a number that expresses the likelihood or chance that a specific event will take place. Both proportions ranging from 0 to 1 and percentages ranging from 0% to 100% can be used to describe probabilities.

Given, a data set gives prizes and probabilities of winning (on a single $1 ticket) for the Multi-State Powerball lottery.

We have to determine the expected value of winnings when buying one ticket. This can be computed using the expected value formula.

Recall the formula for the expected value E for events A and B whose probabilities of occurring are P(A) and P(B), respectively:

E  = (P(A)×value for A)+(P(B)×value for B)

​Using the formula above and extending it to 99 events yields:

E(x) = (1/ 292, 201,338 * 30,000,000) + (1 / 11,688,053 * 1,000,000) + (1/913,129 * 50,000) + (1/ 36,525 * 100) + (1/14,494 * 100) + (1/ 580 *7) + (1 /701 * 7) + (1/92 * 4) + (1/ 38 * 4)

E = 0.423

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Answer:

$15 an hour

Step-by-step explanation:

To find this, we divide 120 by 8.

120 ÷ 8 = 15

So Jane gets $15 an hour

I hope this helped, please mark Brainliest, thank you!

Now we know PR∥QX , according to construction with transversal line TX.

∠PTS=∠QXS (Alternate angle)

In △PTS and △QSX

∠PTS=∠QXS (Alternate angle)

∠PST=∠QSX(vertically opposite angles)

PS=SQ(S is mid point of PQ)

△PTS≅△QSX(AAS rule)

So, TP=QX(CPCT)

As we know, TP=TR (T is midpoint)

Hence, TR=QX

Now, in quadrilateral TSQR

TS∥QR

Hence proved.

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A function that represents a reflection of \(f(x) = \frac{3}{8} (4)^x\) across the y-axis include the following: D. \(g(x) = \frac{3}{8} (4)^{-x}\).

In Mathematics and Geometry, a reflection over or across the y-axis or line x = 0 is represented and modeled by this transformation rule (x, y) → (-x, y).

This ultimately implies that, a reflection over or across the y-axis or line x = 0 would maintain the same y-coordinate while the sign of the x-coordinate changes from positive to negative or negative to positive.

By applying a reflection over the y-axis to the parent exponential function, we would have the following transformed exponential function:

(x, y)                                              →                 (-x, y).

\(f(x) = \frac{3}{8} (4)^x\)                               →              \(g(x) = \frac{3}{8} (4)^{-x}\)

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If a parallelogram is (x + 5) cm long and (x-8) cm wide. The perimeter is: 4x - 6 cm.

The length of all four sides of a square constitutes its perimeter whereas the circumference of a circle which is also known as the perimeter is the distance around it.

One pair of opposite sides lengths are determined by (x + 5) cm and the other pair's length is determined by (x - 8) cm.

Let x represent the  perimeter P of the parallelogram:

P = 2(x + 5) + 2(x - 8)

Simplify

P = 2x + 10 + 2x - 16

P = 4x - 6

Therefore  we can conclude  that the perimeter  of x is 4x - 6 cm.

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The complete question is:

A parallelogram is (x+5)cm long and (x-8)cm wide. Find the perimeter of the parallelogram.

Answer:

\(n = 12h\)

Step-by-step explanation:

Given

\(r = 12/hr\) --- rate

\(h \to hours\)

\(n \to amount\)

Required

Determine which solution is correct or incorrect

The solutions are not given. So, I will provide a general explanation

The amount (n) is calculated as:

\(n = r * h\)

So, we have:

\(n = 12 * h\)

\(n = 12h\)

The above is the general equation to solve for the amount, given h hours

When h = 2.5, we have:

\(n = 12*2.5\)

\(n = 30\)

Answer:

going to add a picture

Step-by-step explanation:

:)

Answer: 5 inspections in 4 hours, because if its 8 hours it would be 10 inspections

Step-by-step explanation:

Answer:

1.25

Step-by-step explanation:

10 ÷ 8 = 1.25

Step-by-step explanation:

since you provided 1st and the last terms

the equation can be nth term

n/2 × ( a + l) = nth sum

n/2 × ( 1 + 121) = 671

n/2 × 122 = 671

61 n = 671

n = 11

a) so there are 11 terms

then,

so as 11th term is 121

let's find common diff

a + ( n-1) d = nth term

1 +( 11-1) d= 121

10d = 121 -1

10d = 120

common difference = 12

━━━━━━━☆☆━━━━━━━

▹ Answer

About 10.247

▹ Step-by-Step Explanation

√105 ≈ 10.247

Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

━━━━━━━☆☆━━━━━━━

Answer:

1. 10$

2. 24,59$

To graph the function g(x) = 7x + 10, we shift the graph of f(x) = 7x vertically by adding a constant term of +10. This means every y-coordinate on the graph increases by 10 units. The slope of the line remains the same at 7. The resulting graph is a straight line passing through (0, 10) with a slope of 7.

To graph the function g(x) = 7x + 10, you need to make the following change to the graph of f(x) = 7x:
1. Translation: The graph of f(x) = 7x can be shifted vertically by adding a constant term to the equation. In this case, the constant term is +10.
Here's how you can do it step by step:
1. Start with the graph of f(x) = 7x, which is a straight line passing through the origin (0,0) with a slope of 7.
2. To shift the graph vertically, add the constant term +10 to the equation. Now, the equation becomes g(x) = 7x + 10.
3. The constant term of +10 means that every y-coordinate of the points on the graph will increase by 10 units. For example, the point (0,0) on the original graph will shift to (0,10) on the new graph.
4. Similarly, if you take any other point on the original graph, such as (1,7), the corresponding point on the new graph will be (1,17) since you add 10 to the y-coordinate.
5. Keep in mind that the slope of the line remains the same, as only the y-values are affected. So, the new graph will still have a slope of 7.
By making this change, you will have successfully graphed the function g(x) = 7x + 10.

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The sum of the sequence based on the function Sn = ( -1 )n + 1 will be -6.

The formula for finding the nth term in an arithmetic sequence given as:

= a + (n - 1)d

Here, Sn is given as ( -1 )n + 1. This is used to illustrate the sum in the sequence. Based on the function given, let's assume that n = 5. Therefore, the 5th term will be:

= (-1)n + 1

= (-1)5 + 1

= (-1)6

= -6

Here is the complete question:

Find the 5th term of a sequence given the function Sn = ( -1 )n + 1.

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Step-by-step explanation:

∫ dt / (cos²(t) ⁹√(1 + tan(t)))

If u = 1 + tan(t), then du = sec²(t) dt.

∫ du / ⁹√u

∫ u^(-1/9) du

9/8 u^(8/9) + C

9/8 (1 + tan(t))^(8/9) + C

Answer:

100

Step-by-step explanation:

8 x 1 = 8

8 x 10 = 80

8 x 100 = 800

Is this what you need? Sorry if its not.

Young adults might value credit in case of an emergency for several reasons. Firstly, credit provides financial flexibility, allowing them to access funds quickly when unexpected expenses arise.

This can be essential for covering costs related to medical emergencies, car repairs, or other unforeseen events that may strain their limited savings. Secondly, young adults often have less established financial safety nets than older individuals. They may not have significant savings, insurance policies, or support from family members to fall back on during emergencies. Credit, in this case, acts as a temporary financial cushion, enabling them to manage immediate needs without resorting to high-interest loans or further jeopardizing their financial stability.

Thirdly, responsible use of credit can help young adults build a positive credit history. Demonstrating responsible borrowing and repayment habits will make it easier for them to access more favorable credit terms in the future, such as lower interest rates or higher credit limits. This can prove valuable when making significant purchases, like buying a home or financing higher education.

Lastly, having access to credit can also provide young adults with a sense of financial independence and empowerment. Knowing they have the means to handle emergencies without relying on others can boost their confidence in managing personal finances and help them make more informed financial decisions as they navigate adulthood.

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The solution of the system is then given by:

x = t[1 -1 1 0.5 0.5 0.33] + s[0 -2 1 1 -2 1]

This is the general solution of the system in the form of a sum of scalar multiples of fixed column vectors.

The system of linear equations can be written in matrix form as:

[1 0 1 2 1 3 | 1]

[2 1 2 4 0 10| 5]

[3 1 3 6 6 15| 8]

where the augmented matrix is [A | B].

To solve the system using the method of specifying appropriate free variables, we first convert the coefficient matrix into reduced row echelon form using Gaussian elimination.

In reduced row echelon form, the first non-zero element of each row (known as the leading entry) is 1, and the leading entries of lower rows are to the right of the leading entries of higher rows.

Applying Gaussian elimination to the coefficient matrix, we get:

[1 0 1 2 1 3 | 1]

[0 1 0 2 -2 7| 0]

[0 0 0 0 0 0| 0]

We can see that there are two non-zero rows, indicating that the system has two independent equations.

We can choose two of the variables to be free variables, and express the other variables in terms of the free ones.

Let's choose x1 and x3 as the free variables.

We can find x2 as follows:

x2 = -x1 - 2x3 + 7

And we can find x4, x5 and x6 as follows:

x4 = (1 - x1 - x3)/2

x5 = 1 - x1 - 2x3 + 2x4

x6 = (1 - x1 - x3 - 2x4)/3

So the general solution of the system can be expressed as a sum of scalar multiples of fixed column vectors:

x1 = t

x2 = -t - 2s + 7

x3 = s

x4 = (1 - t - s)/2

x5 = 1 - t - 2s + (1 - t - s)/2

x6 = (1 - t - s)/3

where t and s are scalars.

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Answer:

4 seconds

Step-by-step explanation:

6000/1500=4

Hi there!

~

\(1500 \div 6000 = 4\)

Hope this helped you!

Answer:

I think its C

Step-by-step explanation:

Answer:

a 84

Step-by-step explanation:

add them all together then subtract by 360

Answer:

d

Step-by-step explanation:

d

Answer:

The solutions for 1 + 3 + 5 +...+ (2n - 1), for the first 10 natural numbers are given in the explanation section below.

Step-by-step explanation:

To calculate 1 + 3 + 5 +...+ (2n - 1) for several natural numbers n, we will use several natural numbers to represent n.

For n= 1,

2n - 1 = 2(1) - 1 = 2 - 1 = 1

Hence, 1 = 1

For n = 2,

2n - 1 = 2(2) - 1 = 4 - 1 = 3

Hence, 1 + 3 = 4

For n = 3,

2n - 1 = 2(3) - 1 = 6 - 1 = 5

Hence, 1 + 3 + 5 = 9

For n = 4,

2n - 1 = 2(4) - 1 = 8 - 1 = 7

Hence, 1 + 3 + 5 + 7 = 16

For n = 5,

2n - 1 = 2(5) - 1 = 10 - 1 = 9

Hence, 1 + 3 + 5 + 7 + 9 = 25

For n = 6,

2n - 1 = 2(6) - 1 = 12 - 1 = 11

Hence, 1 + 3 + 5 + 7 + 9 + 11 = 36

For n = 7,

2n - 1 = 2(7) - 1 = 14 - 1 = 13

Hence, 1 + 3 + 5 + 7 + 9 + 11 + 13 = 49

For n = 8,  

2n - 1 = 2(8) - 1 = 16 - 1 = 15

Hence, 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 = 64

For n = 9,

2n - 1 = 2(9) - 1 = 18 - 1 = 17

Hence, 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 = 81

For n = 10,

2n - 1 = 2(10) - 1 = 20 - 1 = 19

Hence, 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 = 100

The various answers to the question are:

a)

A number of extension lines needed to accommodate $90 in calls immediately:

Use the calculation for busy k servers.

\($$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$$\)

The probability that 2 servers are busy:

The likelihood that 2 servers will be busy may be calculated using the formula below.

\(P_{2}=\frac{\frac{\left(\frac{20}{12}\right)^{2}}{2 !}}{\sum_{i=0}^{2} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$\)

Hence, two lines are insufficient.

The probability that 3 servers are busy:

Assuming 3 lines, the likelihood that 3 servers are busy may be calculated using the formula below.

\(P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{2} \frac{\left(\frac{\lambda}{\mu}\right)^{i}}{i !}}$ \\\\$P_{3}=\frac{\frac{\left(\frac{20}{12}\right)^{3}}{3 !}}{\sum_{i=0}^{3} \frac{\left(\frac{20}{12}\right)^{1}}{i !}}$$\approx 0.1598$\)

Thus, three lines are insufficient.

The probability that 4 servers are busy:

Assuming 4 lines, the likelihood that 4 of 4 servers are busy may be calculated using the formula below.

\(P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$ \\\\$P_{4}=\frac{\frac{\left(\frac{20}{12}\right)^{4}}{4 !}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{7}}{i !}}$\)

Generally, the equation for is  mathematically given as

To answer 90% of calls instantly, the organization needs four extension lines.

b)

The probability that a call will receive a busy signal if four extensions lines are used is,

\(P_{4}=\frac{\left(\frac{20}{12}\right)^{4}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{1}}{i !}} $\approx 0.0624$\)

Therefore, the average number of extension lines that will be busy is Four

c)

In conclusion, the Percentage of busy calls for a phone system with two extensions:

The likelihood that 2 servers will be busy may be calculated using the formula below.

\(P_{j}=\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}$$\\\\$P_{2}=\frac{\left(\frac{20}{12}\right)^{2}}{\sum_{i=0}^{2 !} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$\)

For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

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