Answer:
z = 55.15432893
x = 59.61543424
y = 22.5166605
Step-by-step explanation:
To find length "z" you will have to use SOHCAHTOA.
Labelling the triangle will show us that the side marked "z" is the hyp and the side marked 39 is the opp.
sin 45 = \(\frac{39}{z}\)
z sin 45 = 39
z = \(\frac{39}{sin45}\)
z = 55.15432893
Using Pythagoras' theorem, you can find that the adj = 39
In the other triangles POV, the adj is actually the opp.
Therefore, use tangent to find y.
tan 60 = \(\frac{39}{adj}\)
y tan 60 = 39
y = \(\frac{39}{tan60}\)
y = 22.5166605
Use Pythagoras's Theorem to find x.
\(23^{2} + 55^{2} = x^{2}\\\sqrt{23^{2} + 55^{2}} = x\\59.61543424=x\)
Which of the following algebraic statements are true?
There is at least one true statement. Mark all true statements.
The only true statement is A/B + A/C = 2A/B+C. The correct answer is option 1.
Let's evaluate each statement one by one.
1. A/B + A/C = 2A/B+C. This statement is true. We can solve this by taking the least common multiple of the two denominators (B and C).
Multiplying both sides by BC, we get AC/B + AB/C = 2A. And if we simplify, it becomes A(C+B)/BC = 2A. Since A is not equal to 0, we can divide both sides by A and get: (C+B)/BC = 2/B+C
2. a^2b-c/a^2 = b-c. This statement is false. Let's try to solve this: If we simplify the left side, we get \((a^2b - c)/a^2\). And if we simplify the right side, we get: (b-c). The two expressions are not equal unless c = 0, which is not stated in the original statement. Therefore, this statement is false.
3. \(x^2y - xz/x^2 = xy-z/x\). This statement is also false. Let's try to simplify the left side: \(x^2y - xz/x^2 = x(y - z/x)\). And let's try to simplify the right side: \(xy - z/x = x(y^2 - z)/xy\). The two expressions are not equal unless y = z/x, which is not stated in the original statement. Therefore, this statement is false.
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at west high school, 2/5 of the students play a sport. of the students who play a sport, 1/4 play football. what fraction of the students at west high school play football?
A) 1/10
B) 1/3
C) 1/5
D) 2/3
Answer:
A, 1/10
Step-by-step explanation:
multiply 2/5 by 1/4 to get 2/20 which simplifies to 1/10
Ray is measuring fabric for the costumes of a school play. He needs 12. 5 meters of fabric. He has 30. 5 centimeters of fabric. How many more centimeters of fabric does he need?
Answer:
1219.5 more centimeters of fabric
Step-by-step explanation:
First, we need to convert 12.5 meters to centimeters, since the given amount of fabric is in centimeters.
12.5 meters = 12.5 x 100 centimeters/meter = 1250 centimeters
Now we can find the difference between what Ray needs and what he has:
1250 centimeters - 30.5 centimeters = 1219.5 centimeters
Therefore, Ray needs 1219.5 more centimeters of fabric.
PLEASE HELP FAST ILL GIVE BRAINLIST! And extra points I promise ANSWER ONLY IF YOU KNOW
Answer:
It would be B
Step-by-step explanation:
24 and 36 greatest common factor is 12 and its least is 72
Mention the difference between fossils fuel and alternative energy source with examples.
Answer:
comparing fossils with other engerys:
Most alternatives energy sources doesn't have as much pollution produce like fossil fuel does,
Fossil comes from underground or persevered by nature, when others can be made by renewable resources, such as Wind(windmills) , sun (solar), and water (those rolly things)
What is the measure of angle X, to the
nearest degree?
Answer:
56 degrees
Step-by-step explanation:
Assuming this is trigonometry, you use the tangent method. Which means in order to find the angle you put the adjacent side of what your finding and the opposite on top of it.
The equation is tan(angle)= 9/6
You multiply both sides by the arch of tangent and get
angle =tan^-1 (9/6)
I inserted it into my geometry calculator and got 56.30993247, I rounded to the nearest degree and got 56 degrees
Answer:
56°
Step-by-step explanation:
the printed area of a rectangular poster is 384 cm2, with margins of 4.00 cm on each side and margins of 6.00 cm at the top and bottom. find the dimensions of the poster with the smallest area.
The dimensions of the poster with the smallest area is 24 x 36.
Let's let "W" be the overall width of poster and "H" be the overall height of the poster.
A = H•W
The area of the printed material is 384.
The width of the printed material is W - 4(2) or W - 8.
The height of the printed material is H - 6(2) = H - 12.
So the area of the printed material is (W - 8)(H - 12) and that equals 384
(W - 8)(H - 12) = 384
WH - 12W - 8H + 96 = 384
W(H - 12) - 8H = 288
W = (288 + 8H)/(H - 12)
the area equation (A = H•W), we get:
A(H) = H(288 + 8H)/(H - 12)
A(H) = (288H + 8H2)/(H - 12)
To find the minimum, take the derivative and set it equal to zero.
To take the derivative, we must use the quotient rule
If f(x) = u/v then f '(x) = (u'v - uv')/v2
In this case u = 288H + 8H2 so u' = 288 + 16H
and v = H - 12 so v' = 1 and v2 = (H - 12)² so
A'(H) = [(288 + 16H)(H - 12) - (288H + 8H2)(1)]/(H - 12)²
A'(H) = (288H - 3456 + 16H2 - 192H - 288H - 8H2)/(H - 12)²
A'(H) = (8H² - 192H - 3456)/(H - 12)²
A'(H) = 8(H² - 24H - 432)/(H - 12)²
Setting it equal to zero:
8(H² - 24H - 432)/(H - 12)² = 0
(H² - 24H - 432)/(H - 12)² = 0 This can only be zero if the numerator is zero so:
H² - 24H - 432 = 0
(H - 36)(H + 12) = 0
H = 36 or H = -12
We can neglect the negative answer since the poster can't be a negative height so H = 36. Since H = 36, and we know that W = (288 + 8H)/(H - 12), we can solve for W:
W = (288 + 8(36))/(36 - 12)
W = 24
H = 36
Therefore, the dimensions of the poster with the smallest area is 24 x 36.
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Compared to the power generated by the student after 2.0 seconds, the power generated by the student after 4.0 seconds is
The power generated by the student after 4 seconds is one-fourth of the power generated by the student after 2 seconds.
Power generated by a student when standing up from a chair depends on the height, mass, and acceleration of the student.
If we assume that all other factors remain constant, the power generated by a student can be calculated using the equation:
Power = Work done / time Taken
The energy required to lift a student of mass m to a height h is given by the equation:
mgh, where g is the acceleration due to gravity.
Therefore, the work done in lifting the student from a chair is given by the equation:
mgh.
The acceleration of the student is given by the equation:
a = (final velocity - initial velocity) / time Taken.
For the student standing up from a chair, the initial velocity is zero.
Therefore, the acceleration is given by the equation:
a = (2h / timeTaken²)
The power generated by the student after 2 seconds is:
P1 = (mgh / 2) × (2h / 2²)
P1 = (mgh² / 4)
The power generated by the student after 4 seconds is:
P2 = (mgh / 2) × (2h / 4²)
P2 = (mgh² / 16)
Comparing P1 and P2, we can see that the power generated by the student after 4 seconds is:
P2 = P1 / 4
Therefore, the power generated by the student after 4 seconds is one-fourth of the power generated by the student after 2 seconds.
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Can someone help me with fill the blanks of this pls? It’s about geometry
Answer:
see below
Step-by-step explanation:
2: letter at the vertex, placing a letter or number inside .... , or by using 3 letters
3:
WXY
WXZ
YXZ
4: X
PLEASE HELP ME ASAP!!!!!
TY :)
Answer:
y < 2
Step-by-step explanation:
The shaded part is all under y = 2
Answer is
y = 2
We're going up since the dashed lines are on the second line of y on the graph. If we were to tell the x axis, then the probability would 4 (right side) and -5 (on the left side).
lmk if im wrong :)
Can someone solve this rational equation and plz don’t link files
r=13/2
After I solved it it was kinda easy
Answer:
r=13/2
Step-by-step explanation:
What else is produced during the replacement reaction of magnesium and hydrochloric acid? Mg + 2HCl H2 + ________ MgCl2 Mg2Cl2 Mg2Cl MgCl
Step-by-step explanation:
Magnesium chloride (MgCl2).
Answer:a
A
Step-by-step explanation:
Edge 2021
Order these numbers least to greatest.
1/2, 3/4, 0.8, 0.25, 1/10, 0.4
1 1. 0.25
12. 1/10
+
3. 0.4
14. 0.8
15. 1/2
1 6. 3/4
Answer:
to be quick divide 3/4 ×100=75 percent
1/10=10
.25×100=25
0.8=80
1/2=50 so now u know which one is the smallest from largest so it is 1/10 , 0.25 ,1/2, 3/4, 0.8
Plz help me to solve this question
Step-by-step explanation:
diagonals of the rhombus bisect each other at right angles .
5a = 90
a = 90/5 = 18
in ∆ OCD:
5a + 2a + b = 180
7a+ b = 180
b = 180 - 7 ( 18)
b = 180 - 126
b = 54 °
plz mark my answer as brainlist plzzzz.
hope this will be helpful to you.☺️
Answer:
a = 18°
\( b= 108\degree \)
Step-by-step explanation:
ABCD is a rhombus.
AC and BD are its diagonals
Diagonals of a rhombus bisects at right angles.
Therefore,
5a = 90°
a = 90°/5
a = 18°
2a = 2*18° = 36°
Diagonals of a rhombus bisects the opposite angles.
Therefore,
\( m\angle ADC = 2(2a)\)
\( m\angle ADC = 2\times 36\degree \)
\( m\angle ADC = 72\degree \)
\( m\angle ADC+m\angle DCB= 180\degree \)
(Adjacent angles of a rhombus are supplementary)
\( 72\degree+b= 180\degree \)
\( b= 180\degree-72\degree \)
\( b= 108\degree \)
6. From the menu, select the correct
approximation.
If the expression
√24 × √10
represents the area of a rectangle, then
the approximate area of the rectangle is
60 square units
15 square units
8 square units
120 square units
The approximate area of the rectangle as per the options will be equal to 15 square units. Hence, option B is correct.
What is area?An object's area is how much space it takes up in two dimensions. It is the measurement of the amount of unit squares which completely encompass the surface of a compact figure.
The squared unit, which is frequently expressed as inches, square feet, etc., is the accepted unit of area.
As per the given information in the question,
Let the length is given as, l = √24 and,
The width is given as, w = √10
Use the formula of area of rectangle,
A = lw
A = √24 × √10
A = 4.89 × 3.16
A = 15.45 ≈ 15 square units.
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Domain and range function graph plz help asap
Answer:
Domain and range: All possible real numbers.
Step-by-step explanation:
Since both end contains arrows, that means that it keeps going on and on.
12. Ogrodnik zebrał 110 kg jabłek,
które ułożył w trzech jednako-
wych skrzynkach. Jedna skrzynka
ważyła brutto 34 kg, a druga
36,3 kg. Trzy puste skrzynki
ważą razem 6 kg. Ile ważyły jabł-
ka w trzeciej skrzynce?
Answer:
EVERYONE REPORT ME PLEASE
Which graph best shows the solution to the following equation?
Answer:
c
Step-by-step explanation:
to disprove the null hypothesis a researcher must develop a number that demonstrates the existence of difference between two variables. this is called the:
To disprove the null hypothesis a researcher must develop a number that demonstrates the existence of a difference between two variables. this is called the alternative hypothesis.
Null hypothesis and Alternative hypothesis are two basic types of hypothesis that express the criteria of a research problem as a relationship between two or more variables.
Null hypothesis refers to the hypothesis which clarifies that there is no relationship between two variables.
An alternative hypothesis is the inverse of the null hypothesis which tells that there is a relationship between two variables.
Hence, demonstrating that there exist a difference between two variables is an alternative hypothesis.
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5196
A large rectangle is made by joining three identical small rectangles as shown.
The perimeter of one small rectangle is 21 cm.
The width of one small rectangle is x cm.
x cm
Work out the perimeter of the large rectangle.
The final line of your answer should be of the form,
Perimeter of large rectangle is ... cm
Answer:
35 cm
Step-by-step explanation:
As shown in the image attached, the A large rectangle is made by joining three identical small rectangles,
The width of one small rectangle is x cm and the length of one small rectangle is 2x cm. Therefore the perimeter of the small rectangle is given as:
2(length + width) = Perimeter
2(2x + x) = 21
2(3x) = 21
6x = 21
x = 21/6 = 3.5 cm
x = 3.5 cm
From the image attached, the width of the large rectangle is 2x (x + x) and the length is 3x (2x + x). Therefore, the perimeter of the large rectangle is:
2(length + width) = Perimeter
2(3x + 2x) = Perimeter
Perimeter = 2(5x)
Perimeter = 10x
Perimeter = 10(3.5)
Perimeter = 35 cm
measurements from a sample are called:
statistics.
inferences.
parameters.
variables.
A population has 75 observations. One class interval has a frequency of 15 observations. The relative frequency in this category is:
0.20.
0.10.
0.15.
0.75.
The relative frequency in the class interval with 15 observations is 0.20 or 20%.
The correct answers are: Measurements from a sample are called: statistics. The relative frequency in the class interval with 15 observations is: 0.20.
Statistics are measurements or data collected from a sample of a larger population. They are used to make inferences about the population.
To find the relative frequency of a class interval, you divide the frequency of that interval by the total number of observations. In this case, the relative frequency is:
relative frequency = frequency of interval / total number of observations
relative frequency = 15 / 75
relative frequency = 0.20
Therefore, the relative frequency in the class interval with 15 observations is 0.20 or 20%.
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Two lines, R and M, are represented by the following equations:
Line R: 2x + 2y = 18
Line M: x + y = 9
Which statement is true about the solution to the set of equations? (4 points)
a
It is (18, 9).
b
It is (9, 18).
c
There are infinitely many solutions.
d
There is no solution.
M is the midpoint of AB, AM=2x+3, and AB= 8x-10. Find MB
PLEASE HELP ASAP ILL MAKE YOU THE BRAINIEST Find the area of the rhombus
Answer:
the answer is 40
Step-by-step explanation:
A = 10 x 8 over 2 which is 40
If \(\frac{a+b}{3}=\frac{b+c}{6}=\frac{c+a}{5}\) then prove that: \(\frac{a+b+c}{a}=7\)
Answer:
\(\dfrac{a+b+c}{a} =7\)Step-by-step explanation:
Given :-
\(\dfrac{a+b}{3} =\dfrac{b+c}{6} =\dfrac{c+a}{5}\)And we need to prove that ,
\(\dfrac{a+b+c}{a} =7\)So let us assume that ,
\(\implies\dfrac{a+b}{3} =\dfrac{b+c}{6} =\dfrac{c+a}{5}=k\)
Where k is a constant . Now equate each of the three terms separately to k . Therefore we have ,
\(\dfrac{a+b}{3}=k\)
\(\implies a + b = 3k \quad \dots (i) \)
Similarly we can say that ,
\(\implies c + b = 6k \quad \dots (ii)\)
\(\implies a + c = 5k\quad \dots (iii) \)
Subtracting (i) and (ii) :-
\(\implies a - c = -3k \quad \dots (iv) \)
Adding (iv) and (iii) :-
\(\implies 2c = 4k \)
\(\implies \boxed{c = 4k }\)
Put this is (ii) :-
\(\implies b +4k = 6k \)
\(\implies \boxed{b= 2k }\)
Similarly we will get ,
\(\implies \boxed{a = k }\)
Proving the given equation :-
\(\implies \dfrac{a+b+c}{a} \\\\\implies \dfrac{k+2k+4k}{k} \\\\\implies \dfrac{7k}{k}=\boxed{\red{ 7}}\)
Hence proved !
Can you get the answer then you win
There were 21 children who were older than 7 years.
What is Histogram?A histogram is a graph that depicts the frequency distribution of a few data points from a single variable. Histograms frequently divide data into "bins" or "range groups" and count the number of data points that belong to each of those bins.
The bar graph graphically represents category data. A histogram is a graph that represents quantitative data. Each pair of consecutive bars is separated by an equal amount of space.
The data from the Histogram can written as
Age group Number of Children
1 - 3 5
3 - 5 3
5 - 7 6
7 - 9 8
9 -11 9
11 - 13 4
So, the number of children who were older than 7 years
= 8 + 9 + 4
= 21 children
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A ball is thrown upward from a height of 15 m with a velocity of 20 m/sec. Acceleration due to gravity is 9.8 m/s2. A. Find the relation between height h and time t after the ball is released. B. How high is the ball after 3 seconds?C. When will the ball hit the ground?2. Repeat problem 1, only answer the questions as if the ball were on the moon. Acceleration due to gravity on the moon is 1.6 m/s2. 3. A ball is kicked upward from a height of 1 m with a velocity of 25 m/sec. Acceleration due to gravity is 9.8 m/s2a. Find the relation between height h and time t after the ball is released.B. How high is the ball after 2 seconds?C. When will the ball hit the ground?D. What is the maximum height of the ball?
Answer:
A. h = h₀ + u·t - 1/2·g·t²
B. 30.9 m
C. 4.73 seconds
2. A. h = h₀ + u·t - 1/2·a·t²
B. 67.8 m
C. Approximately 25.73 seconds
3. A. h = h₀ + u·t - 1/2·g·t²
B. 31.38 m
C. Approximately 5.142 seconds
D. Approximately 32.9 m
Step-by-step explanation:
The given parameters are;
The initial height of the ball, h₀ = 15 m
The upward velocity with which the ball is thrown, u = 20 m/sec.
The acceleration due to gravity, g = 9.8 m/s²
A. The relation between the height, h, and the time, t, after the ball is released is given as follows;
h = h₀ + u·t - 1/2·g·t²
B. The height of the ball after 3 seconds is given by substitution as follows;
At t = 3 seconds, h = 15 + 20 × 3 - 1/2 × 9.8 × 3² = 30.9
The height of the ball, h, after 3 seconds is h = 30.9 m
C. The time the ball takes to hit the ground = 2 × The time it takes to maximum height + The time it takes the ball to fall with an initial velocity of 20 m/sec for 15 m height
The time it takes to maximum height, \(t_{max}\), is given as follows;
v = u - g·\(t_{max}\)
Where;
v = The final velocity = 0 at maximum height
Therefore, we have;
0 = 20 - 9.8 × \(t_{max}\)
∴ \(t_{max}\) = 20/9.8 ≈ 2.0408
The time it takes to maximum height, \(t_{max}\) ≈ 2.0408 seconds
The time it takes the ball to fall with an initial velocity of 20 m/sec for 15 m height, \(t_{15}\) is given as follows;
v₂² = u₂² + 2·g·h₀
v₂² = 20² + 2×9.8×15 = 694
v₂ = √694 ≈ 26.344 m/s
v₂ ≈ 26.344 m/s
From, v₂ = u₂ + g·\(t_{15}\), we have;
26.344 = 20 + 9.8×t
9.8·\(t_{15}\) = 26.344 - 20 = 6.344
∴ \(t_{15}\) = 6.344/9.8 ≈ 0.647
The ball will hit the ground after 2 × \(t_{max}\) + \(t_{15}\) ≈ 2 × 2.0408 + 0.647 ≈ 4.7286
The ball will hit the ground after approximately 4.7286 ≈ 4.73 seconds
2. When the ball is thrown upward from the Moon, we have;
The acceleration due to gravity on the moon, a = 1.6 m/s², therefore, we have;
A. The relation between the height, h, and the time, t, after the ball is released is given as follows;
h = h₀ + u·t - 1/2·a·t²
B. The height of the ball after 3 seconds is given by substitution as follows;
At t = 3 seconds, h = 15 + 20 × 3 - 1/2 × 1.6 × 3² = 67.8
The height of the ball, h, thrown on the Moon, after 3 seconds is h = 67.8 m
C. The time the ball takes to hit the ground = 2 × The time it takes to maximum height + The time it takes the ball to fall with an initial velocity of 20 m/sec for 15 m height
The time it takes to maximum height, \(t_{max}\), is given as follows;
v = u - a·\(t_{max}\)
Where;
v = The final velocity = 0 at maximum height
Therefore, we have;
0 = 20 - 1.6 × \(t_{max}\)
∴ \(t_{max}\) = 20/1.6 = 12.5
The time it takes to maximum height, \(t_{max}\) = 12.5 seconds
The time it takes the ball to fall with an initial velocity of 20 m/sec for 15 m height, \(t_{15}\) is given as follows;
v₂² = u₂² + 2·a·h₀
v₂² = 20² + 2×1.6×15 = 448
v₂ = √448 ≈ 21.166 m/s
v₂ ≈ 21.166 m/s
From, v₂ = u₂ + a·\(t_{15}\), we have;
21.166 = 20 + 9.8×t
1.6·\(t_{15}\) = 21.166 - 20 = 1.166
∴ \(t_{15}\) = 1.166/1.6 ≈ 0.72785
The ball will hit the ground after 2 × \(t_{max}\) + \(t_{15}\) ≈ 2 × 12.5 + 0.72875 = 25.72875 ≈ 27.73
The ball will hit the ground after approximately 25.73 seconds
3. The height from which the ball is kicked, h₀ = 1 m
The initial velocity of the ball, u = 25 m/sec
The acceleration due to gravity, g = 9.8 m/s²
The relationship between the height, h and the time, t after the ball is released, is given as follows;
h = h₀ + u·t - 1/2·g·t²
B. The height of the ball after 2 seconds is given as follows;
At t = 2, h = 1 + 25 × 2 - 1/2 × 9.81 × 2² = 31.38
The height of the ball, after 2 seconds, h = 31.38 m
C. The time it takes the ball to hit the ground is given by the following kinematic equation, as follows;
h = h₀ + u·t - 1/2·g·t²
At the ground level, h = 0, therefore, we have;
0 = 1 + 25·t - 4.9·t²
Therefore, by the quadratic formula, we have;
t = (-25 ± √(25² - 4×(-4.9)×1))/(2 × -4.9)
Therefore, t ≈ 5.142, or t ≈ -0.03969
Given that the time is a natural number, we have, t ≈ 5.142 seconds
D. The maximum height, \(h_{max}\) the ball reaches is given as follows;
From the kinematic equation, v² = u² - 2·g·h,
Where;
v = 0 at maximum height
h = The height the ball reaches above the initial height, we have;
0² = u² - 2·g·h
u² = 2·g·h
h = u²/(2·g) = 25²/(2 × 9.8) ≈ 31.888
\(h_{max}\) = h₀ + h = 1 + 31.888 ≈ 32.9
The maximum height the ball reaches, \(h_{max}\) ≈ 32.9 m
HELP PLEASE I NEED THIS QUICK!!!! SHOW WORK TOO PLS IN ANSWER
2. Solve each given equation and show your work. Tell whether it has one solution, an infinite number of solutions, or no solutions, and identity each equation as an identity, a contradiction, or neither. Hint: Remember to group like terms. (a) 5x + 9 = 2x + 7 + 3x - 15 (b) 7x + 5x - 7 = 21 + 10x (c) 24 - 3x = 8 - 2x + 16- x by the way a b and c are different parts in problem please help i need this tomorrow
Answer:
(a) 5x + 9 = 2x + 7 + 3x - 15
combine like terms
5x + 9 = 5x - 8
subtract 5x and 9 from both sides
0 = -17
This statement is false, so there are no solutions. This is a contradiction equation.
(b) 7x + 5x - 7 = 21 + 10x
combine like terms
12x - 7 = 21 + 10x
subtract 10x from both sides and add 7 to both sides
2x = 28
divide by 2
x = 14
neither - it's a conditional equation
(c) 24 - 3x = 8 - 2x + 16 - x
combine like terms
24 - 3x = 24 - 3x
This equation is true and will always be true no matter what x value is plugged in. There are an infinite number of solutions. This is an identity equation.
What is the 8 times table?
The 8 times table is a mathematical table that lists the products of 8 and the integers from 1 to 10. The table is typically used to help students learn and memorize the multiplication facts for the number 8.
Here is the 8 times table:
8 x 1 = 8
8 x 2 = 16
8 x 3 = 24
8 x 4 = 32
8 x 5 = 40
8 x 6 = 48
8 x 7 = 56
8 x 8 = 64
8 x 9 = 72
8 x 10 = 80
As you can see, the 8 times table is a list of the products of 8 and the integers from 1 to 10. By memorizing this table, students will be able to quickly and easily solve multiplication problems involving the number 8. It is important to practice and memorize the 8 times table, as well as other multiplication tables, as they form the foundation for more advanced mathematical concepts.
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Which is the correct form of the partial fraction decomposition for the expression StartFraction 4 x cubed + 3 x squared Over (x + 1) squared (x squared + 7) squared EndFraction?
StartFraction A Over x + 1 EndFraction + StartFraction B Over (x + 1) squared EndFraction + StartFraction C x + D Over x squared + 7 EndFraction + StartFraction E x + F Over (x squared + 7) squared EndFraction
StartFraction A x + b Over x + 1 EndFraction + StartFraction C x + D Over (x + 1) squared EndFraction + StartFraction E x + F Over x squared + 7 EndFraction + StartFraction G x + H Over (x squared + 7) squared EndFraction
StartFraction A squared Over x + 1 EndFraction + StartFraction B squared Over (x + 1) squared EndFraction + StartFraction C x + D Over x squared + 7 EndFraction + StartFraction (E x + F) squared Over (x squared + 7) squared EndFraction
StartFraction A x + b Over x + 1 EndFraction + StartFraction (C x + D) squared Over (x + 1) squared EndFraction + StartFraction E x + F Over x squared + 7 EndFraction + StartFraction (G x + H) squared Over (x squared + 7) squared EndFraction
The correct form of the partial fraction decomposition for the expression \($\frac{4x^3+3x^2}{(x+1)^2(x^2+7)^2}$\) is:
\(\frac{A}{x+1} + \frac{B}{(x+1)^2} + \frac{Cx+D}{x^2+7} + \frac{Ex+F}{(x^2+7)^2}\) (Option 1).
The given expression can be written in the form \($\frac{4x^3+3x^2}{(x+1)^2(x^2+7)^2}$\). To decompose this into partial fractions, we need to find the values of constants A, B, C, D, E, and F such that the expression can be written in the form of the options given.
Using partial fraction decomposition method, we can write the expression as:
\($\frac{4x^3+3x^2}{(x+1)^2(x^2+7)^2} = \frac{A}{x+1} + \frac{B}{(x+1)^2} + \frac{Cx+D}{x^2+7} + \frac{Ex+F}{(x^2+7)^2}$\)
Then we multiply both sides by the denominator of the expression on the left and simplify to get:
\($4x^3+3x^2 = A(x+1)(x^2+7)^2 + B(x^2+7)^2 + (Cx+D)(x+1)^2(x^2+7) + (Ex+F)(x+1)^2$\)
Next, we can solve for the unknown constants by equating the coefficients of the same powers of x on both sides of the equation. We will end up with a system of linear equations, which can be solved using various methods.
After solving, we get the coefficients as:
\(A = -\frac{1}{2}$, $B = \frac{5}{4}$, $C = 0$, $D = -\frac{1}{4}$, $E = 0$, and $F = \frac{3}{28}$.\)
Therefore, the correct form of the partial fraction decomposition for the given expression is:
\($\frac{4x^3+3x^2}{(x+1)^2(x^2+7)^2} = -\frac{1}{2(x+1)} + \frac{5}{4(x+1)^2} - \frac{1}{4(x^2+7)} + \frac{3}{28(x^2+7)^2}$\)
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Complete Question:
Which is the correct form of the partial fraction decomposition for the expression \($\frac{4x^3+3x^2}{(x+1)^2(x^2+7)^2}$\)?
\($\frac{A}{x+1} + \frac{B}{(x+1)^2} + \frac{Cx+D}{x^2+7} + \frac{Ex+F}{(x^2+7)^2}$\)\($\frac{Ax+b}{x+1} + \frac{Cx+D}{(x+1)^2} + \frac{Ex+F}{x^2+7} + \frac{Gx+H}{(x^2+7)^2}$\)\($\frac{A^2}{x+1} + \frac{B^2}{(x+1)^2} + \frac{Cx+D}{x^2+7} + \frac{(Ex+F)^2}{(x^2+7)^2}$\)\($\frac{Ax+b}{x+1} + \frac{(Cx+D)^2}{(x+1)^2} + \frac{Ex+F}{x^2+7} + \frac{(Gx+H)^2}{(x^2+7)^2}$\)