PART A) The acceleration of gravity is 9.8 m/s^2 What is the magnitude of the net force on a(n) 82 kg driver operating a dragster as it accelerates horizontally along a straight line from rest to 67 m/s in 8.4 s? Answer in units of kN
PART B) The tension in a string from which a 7 kg
object is suspended in an elevator is equal to 74 N. What is magnitude of the acceleration a of the elevator? The acceleration of gravity is 9.8 m/s^2 Answer in units of m/s^2

Answer:

The magnetic flux density is 3 x 10⁵ Wb/m²

Explanation:

Given;

magnetic flux of each line of force, Ф = 30 Wb

area of the bar magnet, A = 1 cm² = 1 x 10⁻⁴ m²

The flux density of the magnet is the measure of the concentration of the magnetic flux per unit area. The unit is Wb/m² or Tesla.

B = Ф / A

B = 30 / (1 x 10⁻⁴ )

B = 3 x 10⁵ Wb/m²

Therefore, the magnetic flux density is 3 x 10⁵ Wb/m²

Answer:

a = 1.04m/s²

Explanation:

a =f/m

a =77N/74kg

a = 1.04,m/s²

Explanation:

Work done= MGH

180=m×10×3

180/30=m

m=6kg

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Answer:

A

Explanation:

The upper part of a Younger mountain top look like a flattened pancake.

In a process known as plate tectonics, sections of the Earth's crust, known as plates, collide with one another and buckle up like a car's hood in a head-on collision to build the world's largest mountain ranges.

One such enormous catastrophe, which began roughly 55 million years ago, eventually gave rise to the Himalaya in Asia. The Himalaya contains thirty of the tallest mountains in the world. With a height of 29,035 feet (8,850 meters), Mount Everest's peak is the highest point on the planet.

Mauna Kea, an inactive volcano on the island of Hawaii in the Pacific Ocean, is the highest peak in the world when measured from top to bottom.

Therefore, The upper part of a Younger mountain top look like a flattened pancake.

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a. The minimum force required to start moving the block is 9.8 N

b.  The force required to continue moving the block at a constant velocity is 5.88 N.

c. If a force greater than 9.8 N is applied, the block will start moving and continue to move until the applied force is less than 5.88 N.

a. Force = μs * N

N = m * g = 2.0 kg * 9.8 m/s^2 = 19.6 N

Force = μs * N = 0.50 * 19.6 N = 9.8 N

b. Force = μk * N = 0.30 * 19.6= 5.88 N N

c. In conclusion, If a force greater than 5.88 N is applied, the block will accelerate. If a force less than 5.88 N is applied, the block will decelerate and eventually stop if the force becomes less than the force of static friction (9.8 N).

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Answer:

a) The frequency of the waves are = 2 Hz (since you are making two pulses every second)

b)The period of the waves is 0.19 m (as the consecutive crests are separated by 0.19 m)

c) V = L x f

v = 0.19 m x 2 S-1 (Hz is actually per second)

v = 0.38 ms-1

pe nis

Answer:

The statement that the time of ascent of a projectile is equal to the time of descent is not generally true. In most cases, the time of ascent and descent will not be equal.

When a projectile is launched into the air, it follows a curved path known as a parabola. The motion of the projectile can be divided into two phases: the upward motion and the downward motion.

During the upward motion, the projectile is subject to the force of gravity, which acts in the opposite direction to the initial velocity. As a result, the projectile slows down and eventually comes to a stop at the highest point of its trajectory. At this point, the velocity of the projectile is zero.

During the downward motion, the projectile continues to be influenced by gravity, but now the force of gravity acts in the same direction as the initial velocity. This causes the projectile to accelerate as it falls back to the ground.

The key point here is that the time of ascent and descent will only be equal if the projectile reaches the same height on its way up and on its way down. This requires specific conditions, such as launching the projectile from and returning it to the same height, with no air resistance, and with a specific initial velocity and launch angle.

In practical scenarios, the time of ascent and descent will generally be different. Factors such as air resistance, the launch angle, and the initial velocity will all affect the time it takes for the projectile to reach its peak and return to the ground. Additionally, the projectile's final velocity before striking the ground will not necessarily be the negative of its initial velocity.

Therefore, it is incorrect to assume that the time of ascent and descent of a projectile are always equal.

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Answer:

Yes, the time of ascent of a projectile is indeed equal to the time of descent. This is because the only force acting on the projectile is gravity, which is a constant acceleration. This means that the projectile's velocity changes at the same rate in both directions, up and down.

Explanation:

In order to prove this mathematically, we can use the following equations:

\(\boxed{\bold{v = u + at}}\)

\(\boxed{\bold{s = ut + \frac{1}{2} at^2}}\)

where:

For the ascent, we know that the initial velocity is u and the final velocity is 0. We can solve for the time using the equation:

\(\boxed{\bold{t = \frac{(v-u)}{a}}}\)

which gives us:

\(\bold{t =\frac{ (0 - u) }{ -9.8 m/s^2}}\)

\(\bold{t =\frac{ (u) }{ -9.8 m/s^2}}\)

For the descent, we know that the initial velocity is 0 and the final velocity is u. We can solve for the time using the same equation:

\(\bold{t =\frac{ (v- u) }{ -9.8 m/s^2}}\)

which gives us:

\(\bold{t =\frac{ (u - 0) }{ -9.8 m/s^2}}\)

\(\bold{t =\frac{ (u) }{ -9.8 m/s^2}}\)

As you can see, the time for the ascent is equal to the time for the descent. This is because the only force acting on the projectile is gravity, which is a constant acceleration. This means that the projectile's velocity changes at the same rate in both directions, up and down.

As for your point about the body falling and accelerating from rest, this is true.

However, the acceleration is still the same, regardless of whether the body is moving up or down. This is because the acceleration due to gravity is constant.

Given the following data:

First of all, we would calculate the electric field due to B₁ to B₃ and the electric field due to B₂ to B₃ respectively.

The electric field due to B₁ to B₃ is given by:

E₁ = kq₁/r₁²

E₁ = (9 × 10⁹ × 17 × 10⁻⁶)/(0.05² + 0.1²)

E₁ = 153 × 10³/0.0125

Electric field, E₁ = 12.24 × 10⁶ N/C.

The electric field due to B₂ to B₃ is given by:

E₂ = kq₂/r₂²

E₂ = (9 × 10⁹ × 5 × 10⁻⁶)/(0.1²)

E₂ = 45 × 10³/0.01

Electric field, E₂ = 4.5 × 10⁶ N/C.

Also, the magnitude of the angle formed is given by tan trigonometry:

Tanθ = 5/10

Tanθ = 0.5

θ = tan⁻¹(0.5)

θ = 26.56°.

Next, we would calculate the x-component of the electric field at the observation location (Bee number 3) due to B₁:

E₁x = E₁cosθ - E₂

E₁x = 12.24 × 10⁶ × cos(26.56) - 4.5 × 10⁶

E₁x = 10.95 × 10⁶ - 4.5 × 10⁶

E₁x = 6.5 × 10⁶ N/C.

Similarly, we would calculate the y-component of the electric field at the observation location (Bee number 3) due to B₁:

E₁y = -E₁sinθ

E₁y = -12.24 × 10⁶ × sin(26.56)

E₁y = -12.24 × 10⁶ × 0.4471

E₁y = -5.5 × 10⁶ N/C.

Also, the magnitude of the electric field is given by:

Exy = √(E₁x² + E₁y²)

Exy = √(6.5 × 10⁶)² + (-5.5 × 10⁶)²)

Exy = √4.225 × 10¹³ + 3.025 × 10¹³)

Exy = √(7.25 × 10¹³)

Exy = 8.5 × 10⁶ N/C.

We would calculate the x-component of the electric field at the observation location (Bee number 3) due to B₂:

E₂x = -E₂sinθ

E₂x = -4.5 × 10⁶ × sin(90)

E₂x = -4.5 × 10⁶ N/C.

Similarly, we would calculate the y-component of the electric field at the observation location (Bee number 3) due to B₁:

E₂y = E₂cosθ

E₂y = -4.5 × 10⁶ × cos(90)

E₂y = 0 N/C.

The magnitude of the net electric field at B₃ is given by:

Eₙ = √(E₁x + E₂x)² + E₁y²)

Eₙ = √(6.5 × 10⁶ + (-4.5 × 10⁶))² + (-5.5 × 10⁶)²)

Eₙ = √(2.5 × 10⁶)² + (3.025 × 10¹³)

Eₙ = √(6.25 × 10¹²) + (3.025 × 10¹³)

Eₙ = √(3.65 × 10¹³)

Eₙ = 6.04 × 10⁶ N/C.

For the direction, we have:

Tanθ = x/y

Tanθ = 6.5/-5.5

Tanθ = -1.1818

θ = tan⁻¹(-1.1818)

θ = 49.76°.

The magnitude of the force on B₃ due to this net electric field is given by:

F = B₃ × Eₙ

F = 26 × 10⁻⁶ × 6.04 × 10⁶

F = 157.04 Newton.

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The term "internal energy" describes the combined potential and kinetic energy of a system or substance. It is the potential energy held inside the bonds between those particles as well as the energy that results from the motion and interactions of the molecules and atoms within a substance.

The chaotic, random motion of molecules is known as a system's internal energy; a system's total (internal) energy is made up of both potential and kinetic energy.

The sum of the random internal kinetic energies of the atoms and the total internal potential is known as a system's internal energy.energies due to the bonds between atoms. Internal energy is not a new concept or form of energy. On the other hand, heat is a new concept that is central to thermodynamics.

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y= 6.26 lb.

Check attached image 1.

Using the trigonometric functions, we need to find a function that relates the angle, opposite side and adjacent side of the drawn triangle. The function that does this is the tangent.

Let theta (θ) be the angle given by the problem.

Let "y" be the missing y component.

Tangent (θ) = Opposite side (y) / Adjacent side (x)

\(Tan(tetha)=\frac{y}{x}\)

\(Tan(tetha)*x=y\)

\(Tan(51.8)*(4.93)=y\\ \\y=6.26\)

5. Express the result.

y= 6.26 lb.

The work can be seen as a transfer of energy, and can be calculated with the formula below:

Where W is the work in Joules, F is the force in Newtons and d is the distance in meters.

When we have a positive work, that means the body or system is using its own energy and force to move a certain distance, for example.

A negative work means the system is receiving energy from an external source.

Therefore the statement is TRUE.

Your resultant velocity will be along the + y - direction or north direction and has magnitude of 2 m/s.

The quantities that have both magnitude and direction are called vector quantities. Example - velocity, acceleration, force etc.

Given in the question is a plane flying at a rate of 8m/s north and the  wind is blowing 6m/s south.

In order to find the resultant, refer to the diagram attached. The north direction is represented by +y axis and south direction is represented by -y axis.

The velocity vector representing you will be [v1] = 8 j

The velocity vector representing the wind will be [v2]  = - 6 j

Resultant vector [v] = v1 - v2 [Opposite and unequal vectors]

v = 8 j - 6 j

v = 2 j

Therefore, you resultant velocity will be along the + y - direction or north direction and has magnitude of 2 m/s.

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Answer:

Measurement is the comparison of any physical quantity of an object to a standard unit which is pre-determined. The standard units such as length, time, mass etc are known as the Fundamental units of Measurement.

Explanation:

Any object that can be measured is known as a physical quantity. So, to measure the physical quantity, we require some standard units. A measurement consists of two parts - the numerical measurement and the standard unit which is pre-determined. For example, the length of a given table is 10cm, which implies that 10 is the numerical value and the standard unit of measurement is centimeter (cm).

Measurements can be both Fundamental and Derived. Examples of Fundamental quantities are Length, Time etc, while example of Derived quantity is speed which is derived from Length and Time.

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Answer:

Explanation:

We can use the kinematic equation for vertical motion to find the value of the initial vertical velocity, v0y:

v0y = v0 * sin(θ)

Next, we can use the equation for vertical motion with constant acceleration (g = 9.8 m/s^2 is the acceleration due to gravity) to find the time it takes for the ball to reach the target:

v0y * t - 0.5 * g * t^2 = h

Solving for t:

t = sqrt(2 * h / g)

Finally, we can use the kinematic equation for horizontal motion (no acceleration in the horizontal direction) to find the horizontal velocity:

v0x = v0 * cos(θ)

So,

v0x = 10.84 * cos(θ) = 10.84 * cos(θ)

v0x = 10.84 * cos(θ) = 10.84 * cos(θ)

We do not have the value of θ, so we cannot determine the exact value of v0x.

Answer:

45.8

Explanation:

becuse 9.8+36=45.8 simple

The answer is that the time the diver was in the air is 1.13 seconds.

To determine the time the diver was in the air, we can use the kinematic equation:

Δy = viΔt + 1/2at²,

where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0

m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²

Simplifying, we get:

4.9t² + 5.5t - 3.0 = 0

We can solve for t using the quadratic formula:

t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s

Since time cannot be negative, the time the diver was in the air is 1.13 seconds.

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The object requires the MOST power to lift  a 2 kg box 2 m in 1 s. Hence, option (B) is correct.

The quantity of energy moved or converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power.

Power required for lifting a 2 kg box 1 m in 1 s = (2×9.8×1)/1 watt = 19.6 watt.

Power required for lifting a 2 kg box 2 m in 1 s = (2×9.8×2)/1 watt = 39.2 watt.

Power required for lifting a 2 kg box 1 m in 2 s = (2×9.8×1)/2watt =9.8 watt.

Power required for lifting a 2 kg box 2 m in 2 s = (2×9.8×2)/2watt =19.6 watt.

So, The most power required in  lifting a 2 kg box 2 m in 1 s.

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The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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The magnitude of the electric filed strength is -1.44 * 10^-3 N/C away from the electron.

The electric field strength refers to the level of impact that a charge has on another charge in its vicinity. Now you have to know that the electric filed intensity depends on the magnitude of the charge and the force that is exerts on another charge.

Thus;

E = Kq/r^2

K = electric constant

q = magnitude of the charge

r = distance

E = 9.0 * 10^9 * -1.6 * 10^-19/1 * 10^-6

E = -1.44 * 10^-3 N/C

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Answer:

The average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s is 24 \(\frac{m}{s}\).

Explanation:

Velocity ​​is a physical quantity that expresses the relationship between the space traveled by an object and the time used for it. Then, the average velocity relates the change in position to the time taken to effect that change.

\(velocity=\frac{displacement}{time}\)

Velocity considers the direction in which an object moves, so it is considered a vector magnitude.

In this case, the displacement is 192 m and the time period is 8 s. Replacing:

\(velocity=\frac{192 m}{8 s}\)

Solving:

velocity= 24 \(\frac{m}{s}\)

The average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s is 24 \(\frac{m}{s}\).

Explanation:

A concave lens is also known as a diverging lens because it is shaped round inwards at the centre and bulges outwards through the edges, making the light diverge. They are used to treat myopia as they make faraway objects look smaller than they are.

Answer:

time is 32 s and speed is 304.3 m/s

Explanation:

Height, h = 146 m

speed, u = 14 m/s

Angle, A = 43 degree

Let it hits the ground after time t.

Use second equation of motion

\(h = u t +0.5 at^2\\\\- 146 =14 sin 43 t - 4.9 t^2\\\\4.9 t^2 - 9.5 t - 146 =0 \\\\t =\frac{9.5\pm\sqrt {90.25 + 2861.6}}{9.8}\\\\t=\frac{9.5\pm 54.3}{9.8}\\\\t = 32.05 s, - 22.4 s\)

Time cannot be negative so the time is t = 32 s .

The vertical velocity at the time of strike is  

v' =  u sin A - g t

v' = 14 sin 43 - 9.8 x 32 = 9.5 - 313.6 = - 304.1 m/s

horizontal velocity

v'' = 14 cos 43 =10.3 m/s

The resultant velocity at the time of strike is

\(v=\sqrt{v'^2 + v''^2}\\\\v = \sqrt{304.1^2 +10.3^2 }\\\\v = 304.3 m/s\)  

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what is the name of the scientist that discovered gravity?

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The scientist named Isaac Newton discovered the gravity. But before that Aristotle was discovered the gravity first but the calculations were poor and not enough for knowing what it is.

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Reference point

Explanation:

I am not sure

The kinetic energy of an object increases as the mass and speed increases. Here, the truck weighs twice that of car and has a twice speed then it has a kinetic energy 8 times greater than the car.

Kinetic energy is form of energy generated by virtue of the motion of the object. It is related to the mass and velocity of the object by the expression below:

Ke = 1/2 mv²

Let the mass and velocity of the car be m and v. Then its kinetic energy is 1/2 mv²

The mass and velocity of the truck are being 2m and 2v.

Then, kinetic energy of the truck = 1/2 2m (2v)²

Ke = 1/2 8 m v²

Therefore, the  truck has 8 times the kinetic energy of the car. Hence, option  d is correct.

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Your question is incomplete. But your complete question probably was:

A truck weighs twice as much as a car, and is moving at twice the speed of the car. Which statement is true about the truck's kinetic energy compared to that of the car?

a. All that can be said is that the truck has more kinetic energy.

b. The truck has twice the kinetic energy of the car.

c. The truck has 4 times the kinetic energy of the car.

d. The truck has 8 times the kinetic energy of the car.

Answer:

m = 0.5

Explanation:

Given that,

The length of the blade of scissors = 5 cm

The length of the handle = 2.5 cm

Here, effort arm is 2.5 cm and load arm is 5 cm. The mechanical advantage is the ratio of effort arm to the load arm as follows :

\(m=\dfrac{2.5}{5}\\\\m=0.5\)

So, the ideal mechanical advantage of a pair of scissors is 0.5.

The time needed for the block to travel from -A/2 to A/2 is mathematically given as

t=0.5sec

Generally, when the start point is the mean intial position and it goes from  A/2  down through the right goes through and fro back to the mean position, and this is after it must have gone through -A/2. Hence it has finished one cycle (0.1 sec.)

In conclusion, for an -A/2 to A/2 oscillation, then it will finish half-cycle given time period to be

t=1/2

t=0.5sec

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