Hence, the area of the rectangle is \(\frac{21}{32}m^2\).
What is the rectangle?
A rectangle is a two-dimensional flat shape. In an \(XY\) plane, we can easily represent a rectangle, where the arms of x-axis and y-axis show the length and width of the rectangle, respectively.
Area of rectangle = Length × Width
Here given that,
\(L=\frac{7}{8}m\)
\(W=\frac{3}{4}m\)
So,
Area of rectangle = \((\frac{7}{8}m)*(\frac{3}{4}m)\\\)
\(=\frac{21}{32}m^2\)
Hence, the area of the rectangle is \(\frac{21}{32}m^2\).
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lower quartile of 5, 8, 6, 11, 5, 4, 7, 3, 5, 9, 6, 8
Answer: 5
Step-by-step explanation:
First order from least to gratest: 3, 4, 5, 5, 5, 6, 6, 7, 8, 8, 9, 11
Then find median (center): 6
Next find the lower quartile also known as the first quartile: 5
Your answer is 5
If you need additional help you can go to khan academy it is a great site with math for pre-k -SAT. Using khan academy I have become an A student.
I hope this helps and may God bless you. Have a nice day, bye!
Express 75 as a product of its prime factors write the prime factors in ascending order and give your answer in index form
Step-by-step explanation:
75 = 3 x 5 x 5 in prime factorization
Answer:
Step-by-step explanation:
3x5x5
-8-2(6-5x) = 5(2x+3) what is the solution
\({ \blue{ \sf{x = - 15}}}\)
Step-by-step explanation:
\({ \red{ \sf{ - 8 - 2(6 - 5x) = 5(2x + 3)}}}\)
\({ \red{ \sf{ - 10(6 - 5x) = 5(2x + 3)}}}\)
\({ \red{ \sf{ - 60 + 5x = 10x + 15}}}\)
\({ \red{ \sf{5x = 10x + 15 + 60}}}\)
\({ \red{ \sf{5x = 10x + 75}}}\)
\({ \red{ \sf{5x - 10x = 75}}}\)
\({ \red{ \sf{ - 5x = 75}}}\)
\({ \red{ \sf{x = - \frac{75}{5}}}} \)
\({ \blue{ \boxed{ \sf{x = - 15}}}}\)
Is Mia correct?
17, 37 and 47 end in 7 and are prime numbers, so 57 and 67 must also be prime number
Answer:
no she is not correct
just because it ends in 7 does not mean that it is prime
Step-by-step explanation:
57 is divisible by 1, 3, 17, and 57
67 is a prime number and is only divisible by 1 and itself
a thanks would be appreciated
During practice, the players on a softball team warm up by running the bases. This graph shows the relationship between the number of hours, x, of practice the players attend and the number of minutes, y, the players spend running the bases.
How many minutes do the players spend running the bases during each hour of practice?
The number of minutes that the players spend running bases during each hour of practice is the constant of proportionality of the proportional relationship.
What is a proportional relationship?A proportional relationship is defined as follows:
y = kx.
In which k is the constant of proportionality.
In the context of this problem, the variables x and y are given as follows:
Variable x: number of hours.Variable y: time spent running the bases.The equation for the constant is given as follows:
k = y/x.
Representing the hourly time spent running times, you can calculate it taking any point (x,y) on the graph of the function.
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A baker makes 60 muffins. He sells 24 of the muffins.
He put the rest of the muffins in boxes. Each box can hold 4 muffins.
Which equation can be used to find b, the number of boxes the baker will need?
OA.
B.
OC.
OD. (60
60+ 24 ÷ 4 = b
60 24 ÷ 4 = b
-
(60+24) ÷ 4 = b
24) = 4 = b
-
Answer:c
Step-by-step explanation:
c
Answer:b
Step-by-step explanation:
Shoe Size
2
4
6
8
10
12
At soccer practice, Mike asked each of his teammates to write down their shoe size.
What is the interquartile range for Mike's teammates' shoe sizes?
Answer:
2
Step-by-step explanation:
To find the interquartile range, subtract the lower quartile from the upper quartile.
The upper quartile is 7.
The lower quartile is 5.
Subtract.7–5=2
The interquartile range for Mike's teammates' shoe sizes is 2 sizes.
The interquartile range for Mike's teammates' shoe sizes is R = 2
What in Interquartile Range ( IQR )?The distance between the upper and lower quartiles is known as the interquartile range. Half of the interquartile range corresponds to the semi-interquartile range. Finding the values of the quartiles in a small data set is straightforward.
The spread of the data, or statistical dispersion, is measured by the interquartile range. The middle 50%, fourth spread, or H-spread are further names for the IQR. It is described as the spread between the data's 75th and 25th percentiles.
Given data ,
Let the interquartile range be represented as R
Now , the equation will be
Let the shoe sizes be represented as set A
A = { 2 , 4 , 6 , 8 , 10 }
Now , the upper range of the quartile is = 7
The lower range of the quartile is = 5
And , the interquartile range R = upper quartile - lower quartile
On simplifying , we get
The interquartile range R = 7 - 5 = 2
Hence , the interquartile range R = 2
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How do I complete this
Answer:
Point A: y = 552
Point B: y = 123
Step-by-step explanation:
y = -13x - 46
A: x = -46
y = -13(-46) - 46 ==> plugin -46 for x in y = -13x - 46
y = 598 - 46
y = 552
A: x = -13
y = -13(-13) - 46 ==> plugin -13 for x in y = -13x - 46
y = 169 - 46
y = 123
I need help pls the answer choices are A) 8cm
B)2.1cm
C)4cm
D)5.46cm
15 points!
Answer:
x = 4
Step-by-step explanation:
5.2cm/1.3cm = 4 so it increased/decreased by 4
16cm/4 = 4cm
Suppose Derrick is an insect enthusiast who measured the body length and weight of three insects in his backyard. His data are shown in the table.
Answer:
Step-by-step explanation:
lim (cosec 2x - xcosec³x)
x approaches 0
The limit lim(x approaches 0) (cosec(2x) - x*cosec³(x)) is undefined.
We have,
To evaluate the limit of the expression as x approaches 0, we can simplify the expression first.
The expression is given as lim(x approaches 0) (cosec(2x) - x cosec³(x)).
Using trigonometric identities, we can rewrite cosec(2x) as 1/sin(2x) and cosec³(x) as 1/(sin(x))³.
Substituting these into the expression,
We get lim(x approaches 0) (1/sin(2x) - x (1/(sin(x))³)).
Now, let's evaluate the limit term by term:
lim(x approaches 0) (1/sin(2x)) = 1/sin(0) = 1/0 (which is undefined).
lim(x approaches 0) (x (1/(sin(x))³))
= 0 (1/(sin(0))³)
= 0 x 1/0 (which is also undefined).
Since both terms of the expression are undefined as x approaches 0, we cannot determine the limit of the expression.
Therefore,
The limit lim(x approaches 0) (cosec(2x) - x*cosec³(x)) is undefined.
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1. Assume that f is an increasing, nonnegative function on [a, b]. What can be concluded about the relationships among LRAMn f, RRAMn f, and the area on [a, b]?
2. Assume that f is a decreasing, nonnegative function on [a, b]. What can always be concluded about the relationships among LRAMn f, RRAMn f, and the area on [a, b]?
3. Prove or disprove the following statement: MRAMn f is the average of LRAMn f and RRAMn f. Give specific examples.
4. Given the function f(x) = 2x over the interval [0, 3], explain how to find a formula for the Riemann sum obtained by dividing the interval into n subintervals and using the right-hand endpoint for each ci. Then take a limit of these sums as n approaches infinity to calculate the area under the curve over the interval.
The area under the curve of function f on [a, b] is the limit of both LRAMn f and RRAMn f as n approaches infinity.
What is a function?
In mathematics, a function is a unique arrangement of the inputs (also referred to as the domain) and their outputs (sometimes referred to as the codomain), where each input has exactly one output and the output can be linked to its input.
The Left Riemann Sum (LRAM) and Right Riemann Sum (RRAM) of a non-negative, increasing function f on the interval [a, b] are defined as follows -
LRAMn f = (b - a)/n × [ f(a) + f(a + (b-a)/n) + f(a + 2(b-a)/n) + ... + f(a + (n-1)(b-a)/n) ]
RRAMn f = (b - a)/n × [ f(a + (b-a)/n) + f(a + 2(b-a)/n) + ... + f(a + n(b-a)/n) ]
As f is an increasing, non-negative function on [a, b], both LRAMn f and RRAMn f will be non-negative, and the area under the curve of f will also be non-negative.
Since f is increasing on [a, b], we have -
f(a) ≤ f(a + (b-a)/n) ≤ f(a + 2(b-a)/n) ≤ ... ≤ f(a + (n-1)(b-a)/n) ≤ f(b)
Therefore, LRAMn f will be less than or equal to the area under the curve of f on [a, b], which is less than or equal to RRAMn f.
That is -
LRAMn f ≤ Area under curve of f on [a, b] ≤ RRAMn f
So we can conclude that the area under the curve of f on [a, b] is bounded between LRAMn f and RRAMn f.
Therefore, as n increases, both LRAMn f and RRAMn f converge to the area under the curve of f on [a, b].
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The Indas Valley Civilization began in 7000BC and come to an end in 1900BC. How long did it lost?
The group of individuals fitting a description is the _____
A.census
B.sample
C.parameter
D.population
The group of individuals fitting a description is called option D: Population, this is because, in statistics, a population is seen as am entire group of individuals, items, or elements that tends to have or share a common characteristics.
What is population?The term "population" describes the complete group of people or things that you are interested in investigating. It is the group of individuals or thing(s) about which you are attempting to draw conclusions.
There are infinite and finite populations. A population with a set quantity of people or things is said to be finite. An endless population is one that has an infinite amount of people or things.
Therefore, the correct option is D
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See full text below
A group of individuals fitting a description is the _____
Which of the term below fit the description above.
A.census
B.sample
C.parameter
D.population
Find the value of y.
The value of y is 4√3
What are similar triangles?Similar triangles have the same corresponding angle measures and proportional side lengths. The corresponding angles of similar triangles are congruent or equal.
Also , the ratio of corresponding sides of similar triangles are equal.
There are two triangles that are similar
Therefore;
y /16 = 4/y
y² = 48
y = √48
y = √16 × √ 3
y = 4√3
Therefore, the value of y is 4√3
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Jen purchased the items shown in the table.
Item Cost ($)
shirt 11.99
shoes 35.50
belt 6.75
socks 3.00
In the city she lives in, the sales tax rate is 7.15%. In another city, the sales tax rate is 6.35%. How much more is she spending if she purchases the items in the city where she lives? Round to the nearest cent.
She spends the cost of $0.46 if she purchases the items in the city where she lives.
What is the percentage?The percentage is defined as a ratio expressed as a fraction of 100.
The given data below as:
Cost of the shirt = $11.99
Cost of the shoes = $35.50
Cost of the belt = $6.75
Cost of the socks = $3.00
Total cost of the items = 11.99 + 35.50 + 6.75 + 3.00
Total cost of the items = $57.24
In the city she lives in, the sales tax rate is 7.15%.
Total cost of the items with tax of 7.15%
= 57.24 × 7.15/100 + 57.24 = 4.092 + 57.24 = $61.33
In another city, the sales tax rate is 6.35%
Total cost of the items with tax of 6.35%
= 57.24 × 6.35/100 + 57.24 = 3.633+ 57.24 = $60.87
Hence, she spends the cost of $0.46 if she purchases the items in the city where she lives.
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You start at (-1, -2). You move down 3 units. Where do you end?
You will end up at the point (-1, -5).
We have,
Starting at the point (-1,-2), moving down 3 units means moving 3 units in the negative y-direction.
Now,
The endpoint will have the same x-coordinate as the starting point but a y-coordinate that is 3 less than the starting y-coordinate.
This means,
The endpoint is (-1, -5).
Thus,
You will end up at the point (-1, -5).
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The cost of 3 pounds of grapes is 6.57$. What is the cost of 2 pounds of grapes? Please help! I’ll give brainly.
Derivative/Derivada
1) In(2x²-x)
The derivative is f'(x) = (4x - 1) / (2x² - x).
To find the derivative of the function f(x) = ln(2x² - x), we can use the chain rule.
Begin by identifying the function to be differentiated, which is f(x) = ln(2x² - x).
Apply the chain rule, which states that if we have a composition of functions, f(g(x)), the derivative is given by (f'(g(x))) g'(x).
Let's consider the inner function g(x) = 2x² - x.
To differentiate g(x), we need to apply the power rule and the constant rule. The derivative of 2x² is 4x, and the derivative of -x is -1.
Now, we differentiate the outer function f'(g(x)). The derivative of ln(x) is 1/x.
Finally, we multiply the derivatives obtained in steps 3 and 4. Thus, the derivative of f(x) = ln(2x² - x) is:
f'(x) = (1 / (2x² - x)) * (4x - 1)
Simplifying further, we have:
f'(x) = (4x - 1) / (2x² - x)
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SOMEONE PLEASE HELP ME ASAP THIS IS ALMOST DUE ILL MARK BRAINLIEST!!!!
Answer:
153
Step-by-step explanation:
If the table adds up to 20 and opened toe counts for 45% of the total. then 45% of 340 is 153 !
Question 2 (15 points )
Determine the scale factor from circle A to circle B.
O
Scale factor =
B
30
Thus, the scale factor from circle A to circle B is found to be 2.
Explain about the scale factor:The ratio between comparable measurements of just an element and a portrayal of that element is known as a scale factor in mathematics. The copy will be larger if the scaling factor is a whole number. A fractional scaling factor means that the duplicate will be smaller.
You must first choose which direction we are scaling in order to determine the scale factor:
Scale Up = larger measurement / smaller measurement (smaller to larger).Smaller measurement equals greater measurement when scaling down.The radius of circle A = 2 units
The radius of circle B = 4 units.
So, there is a dilation with the scale factor of 2 units as 2*2 = 4 units.
Thus, the scale factor from circle A to circle B is found to be 2.
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Factor x² - 4x + 5.
Prime
O(x + 5)(x - 1)
O(x - 5)(x - 1)
(x+5)(x + 1)
Answer:
(x-5)(x+1)
Step-by-step explanation:
x² - 4x + 5 = (x-5)(x+1)
How does the radian measure of a central angle of circle O with radius 3 cm change when
circle O is dilated by a factor of 2? Explain.
Answer:
Step-by-step explanation:
The radius of the is extended to 2*3 = 6 cm.
The measure of the central angle is unchanged.
Francesca obtains a loan of $18.965.00. The loan has a simple interest rate of 3%. How much interest will Francesca owe at the end of the first year?
Answer:
$568.95
Step-by-step explanation:
Given parameters:
Value of loan = $18965
Interest rate = 3%
Time = 1year
Unknown:
Interest = ?
Solution:
The interest on a particular amount is given as:
I = \(\frac{PRT}{100}\)
I is the interest
P is the principal
R is the rate
T is the time
I = \(\frac{18965 x 3 x 1}{100}\) = $568.95
Paul rolls a fair dice 174 times. How many times would Paul expect to roll a number greater than 2?
Answer:
116 times
Step-by-step explanation:
A fair dice has 6 faces: 1, 2, 3, 4, 5, 6
The probability of rolling a number greater than 2( face of 3, 4, 5, 6 - 4 elements in total) is:
P = number of selected elements/total number of elements
P = 4/6
P = 2/3
=> Paul rolls a fair dice 174 times, Paul will expect the number of times that a number greater than 2 is rolled:
N = 174 x (2/3) = 116
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The function f(x) = -2(4)²+1 +140 represents the number of tokens a child has x hours after arriving at an arcade.
What is the practical domain and range of the function?
Enter your answer by filling in the boxes to correctly complete the statements. If necessary, round to the nearest hundredth.
The practical domain of the situation is ?
The practical range of the situation is ?
a
A solid metal cone of base radius a cm and height 2a cm is melted and solid
spheres of radius are made without wastage. How many such spheres can be
made?
volume of a cone
.
.
.
volume of sphere
.
.
number of spheres that can be made......
.
.
hence a hemisphere can be formed
An amount of Birr 500 is deposited in an account at the end of each six-month period with an interest computed at 6% compounded semi-annually. How many years does it take for the amount to reach Birr 56,398.43?
It would take approximately 17.12 years for the amount to reach Birr 56,398.43 with a deposit of Birr 500 at the end of each six-month period, compounded semi-annually at an interest rate of 6%.
To solve this problem, we can use the formula for compound interest:
A = P(1 + r/n)^(nt)
Where:
A = Final amount
P = Principal amount (initial deposit)
r = Annual interest rate (in decimal form)
n = Number of compounding periods per year
t = Number of years
In this case, the principal amount is Birr 500, the annual interest rate is 6% (or 0.06), and the interest is compounded semi-annually, so there are 2 compounding periods per year.
We need to find the number of years (t) it takes for the amount to reach Birr 56,398.43.
Let's substitute the given values into the formula and solve for t:
56,398.43 = 500(1 + 0.06/2)^(2t)
Divide both sides by 500:
112.79686 = (1 + 0.03)^(2t)
Take the natural logarithm of both sides to eliminate the exponent:
ln(112.79686) = ln(1.03)^(2t)
Using the property of logarithms, we can bring down the exponent:
ln(112.79686) = 2t * ln(1.03)
Now, divide both sides by 2 * ln(1.03):
t = ln(112.79686) / (2 * ln(1.03))
Using a calculator, we find t ≈ 17.12.
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300 + 200 = ????????????????????????
i am gust giving free brainiest i know the answer.
Answer: 500
Step-by-step explanation:
300
+ 200
500
FIND THE DISTANCE BETWEEN EACH PAIR OF POINTS !