Milan bought a table for rs 3600 he sells it to kirtim at a profit of rs 205 kritim sells it at rs 4968 to aayush find the percentage profit of kritim

Answer:

30

Step-by-step explanation:

first, create two equations.

let x = Julio's number and y = answer for Julio's number substrates 17

\(x - 17 = y \\ y ( - 3) = - 39 \\ \)

by using substitution method, you will get

\(x = 30 \\ y = 13\)

so the answer is 30

The probability that both the first and second student studied = p²

To find the probability that both the first and second students studied when two different students are randomly selected, we can use the multiplication rule of probability.

The multiplication rule of probability states that if the probability of event A is p(A), and the probability of event B, given that event A has occurred, is p(B|A), then the probability of the joint occurrence of A and B is given by p(A and B) = p(A) × p(B|A).

So, if we let A be the event that the first student studied, and B be the event that the second student studied, then we need to find the probability of the joint occurrence of A and B.

We can assume that the probability that any student studied is equal to some value p, and the probability that any student didn't study is equal to q = 1 - p. Since there are only two possibilities for each student (studied or not studied), then p + q = 1. So, we can use the complement rule of probability to write:

p(A) = probability that the first student studied = p, and

p(not A) = probability that the first student didn't study = q = 1 - p,

p(B|A) = probability that the second student studied, given that the first student studied = p, and

p(B|not A) = probability that the second student studied, given that the first student didn't study = p.To find the probability that both the first and second student studied, we need to find the probability of the joint occurrence of A and B. Using the multiplication rule, we get:

p(A and B) = p(A) × p(B|A) = p × p = p².

Which is the probability that both the first and second students studied.

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we can solve the equation using the inverse of A:\(\[x = A^{-1}v = \begin{bmatrix} -1 & 2 & -5 \\ 5 & -9 & 20 \\ -1 & 2 & -4 \end{bmatrix} \begin{bmatrix} 1 \\ 1 \\ 1 \end{bmatrix} = \begin{bmatrix} -4 \\ 16 \\ -3 \end{bmatrix}\]Therefore, the four vectors:\[u_1 = \begin{bmatrix} 1 \\ -1 \\ 2 \end{bmatrix} , \; u_2 = \begin{bmatrix} 2 \\ 1 \\ 0 \end{bmatrix} , \; u_3 = \begin{bmatrix} -1 \\ 3 \\ -1 \end{bmatrix} , \; v = \begin{bmatrix} -4 \\ 16 \\ -3 \end{bmatrix}\]\)form a basis of .

To do that, we will solve the equation:\[Ax = v\]where x is a column vector of three unknowns. We want v to be linearly independent from the columns of A, so we need the equation to have a unique solution. We can achieve that by taking v to be any vector that is not in the column space of A. For example, we can take:\\([v = \begin{bmatrix} 1 \\ 1 \\ 1 \end{bmatrix}\]\)Then, we can solve the equation using the inverse of A:\(\[x = A^{-1}v = \begin{bmatrix} -1 & 2 & -5 \\ 5 & -9 & 20 \\ -1 & 2 & -4 \end{bmatrix} \begin{bmatrix} 1 \\ 1 \\ 1 \end{bmatrix} = \begin{bmatrix} -4 \\ 16 \\ -3 \end{bmatrix}\]Therefore, the four vectors:\[u_1 = \begin{bmatrix} 1 \\ -1 \\ 2 \end{bmatrix} , \; u_2 = \begin{bmatrix} 2 \\ 1 \\ 0 \end{bmatrix} , \; u_3 = \begin{bmatrix} -1 \\ 3 \\ -1 \end{bmatrix} , \; v = \begin{bmatrix} -4 \\ 16 \\ -3 \end{bmatrix}\]\)form basis of .

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Answer:

here is the answer I simply don't the answer to

Step-by-step explanation:

a) 2 square.

b)because there is two k's

Answer:

Equal x

Step-by-step explanation:

I just took it

Answer:

105cm & 245cm

Step-by-step explanation:

\(3x+7x=350\\10x=350\\x=35\\\\\\3(35)=105\\7(35)=245\)

Answer:

a vertical shift of 6 units up

Step-by-step explanation:

We have the transformation:

g(x) = f(x) + k

This is what we call a vertical shift, this transformation moves the graph of f(x) k units, and the motion is upwards if k is positive, and downwards if k is negative.

Here we can see that the graph of f(x) intersects the y-axis at y = -2

While the graph of g(x) intersects the y-axis at y = 4.

Then the distance between these two points is:

4 - (-2) = 6

This means that the graph of g(x) is 6 units above the graph of f(x)

Then we have that k must be equal to 6, then the transformation is:

g(x) = f(x) + 6

This is a vertical shift of 6 units up.

7x + 3y + 2z

Answer: Can't be simplified

P cannot be bounded below by any multiple of ||·||₂, since ||f||₂ can be

Let's first examine whether p(f) satisfies the definition of a norm.

To be a norm, p(f) must satisfy the following properties for all f ∈ L²[0, 1]:

Non-negativity: p(f) ≥ 0

Definiteness: p(f) = 0 if and only if f = 0 almost everywhere

Homogeneity: p(αf) = |α|p(f) for any scalar α

Triangle inequality: p(f+g) ≤ p(f) + p(g) for any f, g ∈ L²[0, 1]

Non-negativity:

We have - (11/1²) ≤ 0 for all f, and clearly ||f||₂ ≥ 0 as well. Therefore, p(f) is non-negative.

Definiteness:

If p(f) = 0, then we must have f = 0 almost everywhere, since the constant function 1 belongs to L²[0, 1] and has a nonzero integral. Conversely, if f = 0 almost everywhere, then p(f) = 0. Therefore, p(f) satisfies the definiteness property.

Homogeneity:

For any scalar α, we have:

p(αf) = - (11/1²) + ||αf||₂¹ + ∫₀¹ |αf'|² dx

= - (11/1²) + |α|²||f||₂¹ + ∫₀¹ |αf'|² dx

= |α|(- (11/1²) + ||f||₂¹ + ∫₀¹ |f'|² dx)

= |α|p(f),

so p(f) satisfies the homogeneity property.

Triangle inequality:

For any f, g ∈ L²[0, 1], we have:

p(f+g) = - (11/1²) + ||f+g||₂¹ + ∫₀¹ |(f+g)'|² dx

= - (11/1²) + ||f||₂¹ + ||g||₂¹ + 2∫₀¹ |f'g'| dx + ∫₀¹ |g'|² dx + ∫₀¹ |f'|² dx

≤ - (11/1²) + ||f||₂¹ + ||g||₂¹ + 2(||f'||₂ ||g||₂ + ||f||₂ ||g'||₂) + ||f'||₂² + ||g'||₂² + ||f||₂² + ||g||₂²

≤ - (11/1²) + 2(||f||₂¹ + ||g||₂¹) + 2(||f'||₂² + ||g'||₂²)

= (2-11/1²)(||f||₂¹ + ||g||₂¹)

= 3(||f||₂¹ + ||g||₂¹)

= 3(p(f) + p(g)),

where we have used the Cauchy-Schwarz inequality and the fact that ||f+g||₂ ≤ ||f||₂ + ||g||₂. Therefore, p(f) satisfies the triangle inequality.

In summary, we have shown that p(f) satisfies all the necessary properties to be a norm. Now, let's examine whether it is equivalent to the standard L²-norm ||f||₂.

We say that two norms p and q on a vector space V are equivalent if there exist positive constants A and B such that for all v ∈ V, Aq(v) ≤ p(v) ≤ Bq(v).

Let's first consider the upper bound. For any f ∈ L²[0, 1], we have:

p(f) = - (11/1²) + ||f||₂¹ + ∫₀¹ |f'|² dx

≤ 1||f||₂ + ||f'||₂² + 1

≤ (√2 + 1) ||f||₂,

where we have used the Cauchy-Schwarz inequality and the fact that ||f'||₂² ≤ 2||f||₂². Therefore, p is dominated by ||·||₂ with a constant of √2 + 1.

Now let's consider the lower bound. For any ε > 0, we can choose a function f ∈ L²[0, 1] such that:

(11/1²) + ||f||₂¹ + ∫₀¹ |f'|² dx < ||f||₂ + ε

This is possible because ||f'||₂ → 0 as ||f||₂ → 0. Therefore, p cannot be bounded below by any multiple of ||·||₂, since ||f||₂ can be

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a) The probability that the bank is empty is approximately 0.0026.

b) the average time the customer spends waiting to be called is approximately -0.25 c) hours the average number of customers in the bank is -1.5 d) the average number of customers waiting to be served is approximately 9.

To answer these questions, we can use the M/M/4 queuing model, where the arrival rate follows a Poisson distribution and the service time follows an exponential distribution. In this case, we have four bank tellers, so the system is an M/M/4 queuing model.

Given information:

Arrival rate (λ) = 12 customers per hour

Service rate (μ) = 1 customer every 15 minutes (or 4 customers per hour)

(a) To calculate the probability that the bank is empty, we need to find the probability of having zero customers in the system. In an M/M/4 queuing model, the probability of having zero customers is given by:

P = (1 - ρ) / (1 + 4ρ + 10ρ² + 20ρ³)

where ρ is the traffic intensity, calculated as ρ = λ / (4 * μ).

ρ = (12 customers/hour) / (4 customers/hour/teller) = 3

Substituting ρ = 3 into the formula, we have:

P = (1 - 3) / (1 + 4 * 3 + 10 * 3² + 20 * 3³) ≈ 0.0026

Therefore, the probability that the bank is empty is approximately 0.0026.

(b) The average time the customer spends waiting to be called is given by Little's Law, which states that the average number of customers in the system (L) is equal to the arrival rate (λ) multiplied by the average time a customer spends in the system (W). In this case, we want to find W.

L = λ * W

W = L / λ

Since the average number of customers in the system (L) is given by L = ρ / (1 - ρ), we can substitute this into the equation to find W:

W = L / λ = (ρ / (1 - ρ)) / λ

W = (3 / (1 - 3)) / 12 ≈ -0.25

Therefore, the average time the customer spends waiting to be called is approximately -0.25 hours, which is not a meaningful result. It seems there might be an error in the given data.

(c) The average number of customers in the bank (L) can be calculated as:

L = ρ / (1 - ρ) = 3 / (1 - 3) = -1.5

Therefore, the average number of customers in the bank is -1.5, which is not a meaningful result. It further suggests an error in the given data.

(d) The average number of customers waiting to be served can be calculated as:

\(L_q\) = (ρ² / (1 - ρ)) * (4 - ρ)

Substituting ρ = 3, we have:

\(L_q\\\) = (3² / (1 - 3)) * (4 - 3) ≈ 9

Therefore, the average number of customers waiting to be served is approximately 9.

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Answer:

it would be six square yards or add all the numbers and your total will be it

Step-by-step explanation:

Answer:18

4x +108=180

Step-by-step explanation:

Answer:

x=18

Step-by-step explanation:

a straight angle is a total of 180 degrees so you subtract 108 from 180 to get 72 and then divide by 4 to get 18

⇛2x + 5 = 3

⇛2x = 5 - 3

⇛2x = 2

⇛x = 2/2

⇛x = 1

Answer:

1

Step-by-step explanation:

Answer:

hope this will help you.

Answer:

2

Step-by-step explanation:

that's because there are two sandwiches and two drinks so one sandwich and drink is one lunch special

hello

the question presented before me seem incomplete due to lack of diagram to give a detailed expression

if 2D and ZE are complimentary, then the sum of both angles must be equal to 90 degrees

divide both sides of the equation by 8

x = 11

Step-by-step explanation:

graph of a line passing through the points negative 2 comma negative 3 and 0 comma negative 2

Answer:

it's c if you are taking pre algerbra 8th on question 5 if ur on flvs

Step-by-step explanation:

line passing through the points (-2,-3) (0,-2)

In reality, 21.19% of the hams weigh 21.19% less than is stated on the label.

u=9.2,\(\sigma= 0.25\)

Requrired proportion =P(X<a)

\(=P(\frac{X-\mu}{\sigma} < \frac{9-9.2}{0.25})\\= P(z < 0.8)=21.19 \%\\=21.19\%\)

when b(i) the mean is increased

Required Probability= P(X<a)

\(=P(\frac{X-\mu}{\sigma} < \frac{9-9.25}{0.25})\\= P(z < -1)=0.1587\\=0.1587\)

when still is decreased

Required Probability = P(X<a)

\(=P(\frac{X-\mu}{\sigma} < \frac{9-9.2}{0.25})\\= P(z < -1.333)=0.0912\\=0.0912\)

Probability is a branch of mathematics that deals with the study of uncertainty and randomness. It involves the analysis of the likelihood of an event occurring, based on the available information and past experiences. Probability can be expressed as a number between 0 and 1, where 0 means an event is impossible and 1 means it is certain to occur.

Probability has a wide range of applications in various fields such as statistics, economics, physics, engineering, and finance. It is used to model complex systems, make predictions, and solve problems involving uncertain events. For example, in gambling, probability is used to calculate the odds of winning or losing, while in finance, it is used to evaluate investment risks and returns.

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Complete Question:-

The weights of canned hams processed at Henline Ham Company follow the normal distribution, with a mean of 9.20 pounds and a standard deviation of 0.25 pound. The label weight is given as 9.00 pounds. a. What proportion of the hams actually weigh less than the amount claimed on the label? (Round your answer to 2 decimal places.)

Answer:

-5/4

Step-by-step explanation:

use the formula rise/run

Answer:

12.35 should be the 10th term sorry if im wrong tho

Step-by-step explanation:

Change the sample size from n  will increase the power of a statistical test. The correct answer is C.

Increasing the sample size is one of the most effective ways to increase the power of a statistical test. With a larger sample size, there is a greater chance of detecting a true effect or rejecting a false null hypothesis.

This is because a larger sample provides more information and reduces sampling variability, leading to more precise estimates and increased statistical power.

The other options listed, such as changing the variability of the scores or changing the significance level, may have an impact on the statistical test but may not directly increase the power. Changing the variability of the scores may affect the precision of the estimates, but it may or may not increase the power of the test.

Similarly, changing the significance level affects the trade-off between Type I and Type II errors, but it does not directly increase the power. The correct answer is C.

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Answer:

41.67πunits³

Step-by-step explanation:

Since we are not asked what to find, we can as well  look for the volume of the cone.

Find the diagram of the cone attached

Volume of the cone = 1/3πr²h

h is the height of the cone

r is the radius of the cone

Volume of the cone = 1/3π(5)²(5)

Volume of the cone= 1/3π(125)

Volume of the cone = 125π/3

Volume of the cone = 41.67πunits³

For the given question, we will find the equation of the parabola of each box

then, we will select the correct equation from the tiles

The first box: focus (2, -2) and directrix y = -8

So, the parabola will open up and the equation will be:

simplify the equation

The second box: Focus (-3, 6) and Directrix (x = -11)

So, the parabola will open right

The values of (a) and the vertex (h,k) will be:

The equation of the parabola will be:

Simplifying the equation:

The third box: Focus (2, -2); Directrix (x = 8)

So, the parabola will open left

The values of (a) and the vertex (h,k) will be:

The equation of the parabola will be:

Simplifying the equation:

The fourth box: Focus (-7, 1) and Directrix (y = 11)

The parabola will open down

The values of (a) and the vertex (h,k) will be:

The equation of the parabola will be:

Simplifying the equation:

The drag of the tiles to the boxes according to the following figure:

Answer:

880 mm

Step-by-step explanation:

Perimeter of circle = 2πr

= 2(22/7)(140)

=880 mm

The perimeter of circle is 880 mm.

It is given that radius(r) = 140mm

The perimeter of a circle is also known as circumference of circle.

Circumference (c) = 2\(\pi \\\)r

It is also given that we have to use the value of pie as 22/7

Now,

c = 2 × 140 ×22/7

c = 6160/7

c = 880 mm

The perimeter of circle is 880mm.

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The hash of the given message is 135.

In computing, a message digest is a fixed-sized string of bytes that represents the original data's cryptographic hash. This hash is used to authenticate a message, guaranteeing the integrity of the data in the message.

Here, it is given the message m = 23  

The formula to calculate hash is him) - (m*7;2 MOD 7793.

So, let's calculate the hash : him) - (m*7;2 MOD 7793(him) - (23*7;2 MOD 7793

⇒ (8*23) - (49 MOD 7793)

⇒ 184 - 49= 135.

So, the hash of the given message is 135.

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Answer:

1.445 × 10³ hope it helped goodluck!

Answer:

$36

Step-by-step explanation:

$540÷15 = $36