Marcus is responsible for maintaining the swimming pool in his community. He adds chemicals, when needed, to lower the pH of the pool.



-The maximum pH value allowed for the pool is 7. 8.


-The pool currently has a pH value of 6. 9.


-The pH value of the pool increases by 0. 05 per hour.



Write an inequality that can be used to determine x, the number of hours before Marcus will need to add chemicals to maintain the pH for the pool

Answers

Answer 1

An inequality that can be used to determine x, the number of hours before Marcus will need to add chemicals to maintain the pH for the pool would be 6.9 + 0.05x ≤ 7.8

To determine the number of hours (x) before Marcus will need to add chemicals to maintain the pool's pH, we can use an inequality with the given information.

-The maximum pH value allowed for the pool is 7.8.
-The pool currently has a pH value of 6.9.
-The pH value of the pool increases by 0.05 per hour.

The inequality for this scenario would be:

6.9 + 0.05x ≤ 7.8

This inequality states that the current pH value (6.9) plus the increase in pH per hour (0.05x) should be less than or equal to the maximum allowed pH value (7.8). This will help us determine the number of hours (x) before Marcus needs to add chemicals to maintain the pH for the pool.

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Related Questions

-4×(-2)[2×(-6)+3×(2×6-4-4)]

Answers

\(\large{\underline {\underline {\frak {SolutioN:-}}}}\)

➝ -4 × (-2) [2 × (-6)+ 3×(2×6-4-4) ]

➝ -4 × (-2) [2 × (-6) + 3 × (12-4-4) ]

➝ -4 × (-2) [2 × (-6) + 3 × (12-8) ]

➝ -4 × (-2) [2 × (-6) + 3 × (4) ]

➝ -4 × (-2) [2 × (-6) + 12 ]

➝ -4 × (-2) [(-12) + 12 ]

➝ -4 × (-2) [0]

➝ -4 × 0

➝ 0

Answer:

-4*-2

Step-by-step explanation:

the multiple of both side is 4*2*,26+*32*--=6 44

Jackson Stationary sells cards in packs of 10 and envelopes in packs of 12. If Kina wants the same number of each, what is the minimum number of cards that she will have to buy? Put in race

Answers

Answer:

143

Step-by-step explanation:

Answer:

she would have to buy 6 packs of cards and 5 packs of envelopes to have even numbers.

6 packs of cards- 60 cards

5 packs of envelopes- 60 envelopes

an+element+with+mass+310+grams+decays+by+5.7%+per+minute.+how+much+of+the+element+is+remaining+after+9+minutes,+to+the+nearest+10th+of+a+gram?

Answers

Given dataAn element with mass 310 grams decays by 5.7% per minute. We need to find how much of the element is remaining after 9 minutes, to the nearest 10th of a gram.Solution

Let P be the amount of the element remaining after 9 minutes. Then, the amount of the element that decayed in 9 minutes is:Q = 310(1 - 0.057)^9= 310(0.943)^9≈ 174.24 gramsTherefore, the amount of the element remaining after 9 minutes is:P = 310 - Q≈ 135.76 grams.So, the amount of the element remaining after 9 minutes is approximately 135.76 grams, rounded to the nearest 10th of a gram.

Let x be the number of ounces of the 40% alloy Dr. Hamilton used.Then (80 - x) would be the number of ounces of the 60% alloy he used. Therefore, the equation is:0.4x + 0.6(80 - x) = 0.45(80)Simplify this equation to solve for x as follows:0.4x + 48 - 0.6x = 36Add like terms:-0.2x + 48 = 36Subtract 48 from both sides of the equation:-0.2x = -12Solve for x by dividing both sides of the equation by -0.2:x = 60Therefore, Dr. Hamilton used 60 ounces of the 40% alloy.

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Use the quadratic formula to find the solutions to the equation y = 5x² - 9x + 3.
What are the zeros of the equation?

Use the quadratic formula to find the solutions to the equation y = 5x - 9x + 3.What are the zeros of

Answers

On solving the provided question, we can say that the quadratic equation is  y = 5x² - 9x + 3 this quadratic equation can not factorized further

What is quadratic equation?

A quadratic equation is x ax2+bx+c=0, which is a quadratic polynomial in a single variable. a 0. The Fundamental Theorem of Algebra ensures that it has at least one solution since this polynomial is of second order. Solutions may be simple or complicated. An equation that is quadratic is a quadratic equation. This indicates that it has at least one word that has to be squared. The formula "ax2 + bx + c = 0" is one of the often used solutions for quadratic equations. where are numerical coefficients or constants a, b, and c. where the variable "X" is unidentified.

the quadratic equation is

y = 5x² - 9x + 3

this quadratic equation can not factorized further

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Abowling team consists of 34 members and 18 are male if 4females leaves the team ,what percent off the remaining number are male

Answers

after 4 females leave the team, the percentage of remaining team members who are male is 60%.

Initially, the team has 34 members with 18 males and 34 - 18 = 16 females. If 4 females leave the team, the number of females becomes 16 - 4 = 12. The number of remaining team members is 34 - 4 = 30 (since 4 members left).

To calculate the percentage of remaining team members who are male, we divide the number of males (18) by the total number of remaining team members (30) and multiply by 100:

Percentage of remaining team members who are male = (18 / 30) * 100 = 60%

Therefore, after 4 females leave the team, the percentage of remaining team members who are male is 60%.

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Write an equation of the parabola. Justify your answer.

Write an equation of the parabola. Justify your answer.

Answers

Check the picture below.

so from the picture we can pretty much tell two solutions or zeros and another point where it passes up above, so

\(\begin{cases} x=-1\implies &x+1=0\\\\ x=7\implies &x-7=0 \end{cases}\hspace{8em} \begin{array}{llll} a(x+1)(x-7)=0\\\\ a(x+1)(x-7)=y \end{array} \\\\[-0.35em] ~\dotfill\\\\ \textit{we also know that} \begin{cases} x=5\\ y=3 \end{cases}\implies a(5+1)(5-7)=3 \\\\\\ a(6)(-2)=3\implies -12a=3\implies a=\cfrac{3}{-12}\implies a=-\cfrac{1}{4} \\\\[-0.35em] ~\dotfill\)

\(-\cfrac{1}{4}(x+1)(x-7)=y\implies -\cfrac{1}{4}\stackrel{F~O~I~L}{(x^2-6x-7)}=y \\\\[-0.35em] ~\dotfill\\\\ ~\hfill {\Large \begin{array}{llll} -\cfrac{x^2}{4}+\cfrac{3x}{2}+\cfrac{7}{4}=y \end{array}}~\hfill\)

Write an equation of the parabola. Justify your answer.

Solve the inequality 3(4x+1)<39

Answers

x < 3, hope this helps :)
x < 3 is your answer

During a science experiment,the temperature of a solution in beaker 1 was 5 degrees below zero. The temperature of a solution in Beaker 2 was the opposite of the temperature in beaker 1. What was the temperature in beaker 2?


A. - 5 degrees
B- 0 degrees
C- 5 degrees
D- 10 degrees

Answers

Answer:
5 degrees

Step-by-step explanation:

We are given that during a science experiment
The temperature of a solution in a beaker 15 degrees below zero
The temperature of solution in a beaker 2 was opposite of the temperature in beaker 1
We have to determine the temperature of beaker 2.
It mean temperature of beaker 1 solution=-5 degrees
According to question
Temperature of beaker 2 solution =5 degrees
Hence, the temperature of solution in a beaker 2=5 degrees

The turtle's distance from his starting point is increasing
between
seconds.
The turtle's distance from his starting point is constant
between
seconds.
The turtle's distance from his starting point is
decreasing between
seconds.

Answers

Answer:

10 seconds, decreasing, standing still

Step-by-step explanation:

solve the equation

pic:

solve the equation pic:

Answers

The solution to the equation \((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2\) is 10.3891

How to solve the equation

From the question, we have the following parameters that can be used in our computation:

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2\)

Using the following trigonometry ratio

sin²(x) + cos²(x) = 1

We have

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = (\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + 1 + e^2\)

The sum to infinity of a geometric series is

S = a/(1 - r)

So, we have

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = \frac{1/2}{1 - 1/2} + \frac{9/10}{1 - 1/10} + 1 + e^2\)

So, we have

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = 1 + 1 + 1 + e^2\)

Evaluate the sum

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = 3 + e^2\)

This gives

\((\sum\limits^{\infty}_{i=1} \frac{1}{2^i}) + (\sum\limits^{\infty}_{i=1} \frac{9}{10^i}) + \sin^2(\theta) + \cos^2(\theta) + e^2 = 10.3891\)

Hence, the solution to the equation is 10.3891

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PART 1. Fred and Ginger are married and file a joint return for 2021. They have one dependent child, Carmen (age 18), who lives with them. Fred and Ginger have the following items of income and expense for 2021:


Income:


Fred’s salary

$110,000

Ginger’s salary

125,000

Interest income on State of Arizona bonds

3,000

Interest income on US Treasury bonds

8,000

Qualified cash dividends

6,000

Regular (nonqualified) cash dividends

9,500

FMV of shares received from stock dividend

8,500

Share of RKO Partnership loss*

(10,000)

Share of Hollywood Corporation (an electing S corporation) income**

30,000

Life insurance proceeds received on the death of Fred’s mother

150,000

Short-term capital gains

5,000

Short-term capital losses

(10,000)

15% Long-term capital gains

30,000

15% Long-term capital losses

(7,000)



Expenses:


Traditional IRA Contributions

12,000

Home mortgage interest ($300,000 principal)

18,000

Home equity loan interest ($75,000 principal)

6,000

Vacation home loan interest ($120,000 principal)

8,400

Car loan interest

3,000

Home property taxes

6,000

Vacation home property taxes

1,800

Car tags (ad valorem part)

950

Arizona income tax withheld

8,000

Federal income taxes withheld

45,000

Arizona sales taxes paid

6,500

Medical insurance premiums (not part of an employer plan)

12,000

Unreimbursed medical bills

10,000

Charitable contributions

12,000


* Fred and Ginger invested $15,000 as limited partners in the RKO Partnership at the beginning of 2021. The loss is not the result of real estate rentals. Neither Fred nor Ginger materially participate.

** Ginger is a 50% owner and President of Hollywood. She materially participates in the corporation.


REQUIRED: Determine Fred and Ginger’s tax liability, using the tax formula. You must label your work, provide supporting schedules for summary computations, and indicate any carryovers. Present your work in a neat, orderly fashion

Answers

Tax Liability = Tax on 10% Bracket + Tax on 12% Bracket + Tax on 22% Bracket + Tax on 24% Bracket

To determine Fred and Ginger's tax liability for 2021, we will use the tax formula and consider the various items of income and expenses provided. Let's go through each category step by step:

Calculate Adjusted Gross Income (AGI):

AGI = (Fred's Salary) + (Ginger's Salary) + (Interest Income on State of Arizona Bonds) + (Interest Income on US Treasury Bonds) + (Qualified Cash Dividends) + (Share of Hollywood Corporation S Corporation Income) + (Short-term Capital Gains) + (15% Long-term Capital Gains) + (Share of RKO Partnership Loss) + (Life Insurance Proceeds)

AGI = $110,000 + $125,000 + $3,000 + $8,000 + $6,000 + $30,000 + $5,000 + $30,000 + (-$10,000) + $150,000

AGI = $547,000

Determine Itemized Deductions:

Itemized Deductions = (Home Mortgage Interest) + (Home Equity Loan Interest) + (Vacation Home Loan Interest) + (Car Loan Interest) + (Home Property Taxes) + (Vacation Home Property Taxes) + (Car Tags) + (Arizona Sales Taxes Paid) + (Medical Insurance Premiums) + (Unreimbursed Medical Bills) + (Charitable Contributions)

Itemized Deductions = $18,000 + $6,000 + $8,400 + $3,000 + $6,000 + $1,800 + $950 + $6,500 + $12,000 + $10,000 + $12,000

Itemized Deductions = $95,650

Calculate Taxable Income:

Taxable Income = AGI - Itemized Deductions

Taxable Income = $547,000 - $95,650

Taxable Income = $451,350

Determine Tax Liability using the Tax Table or Tax Formula:

Based on the provided information, we'll assume Fred and Ginger are filing as Married Filing Jointly for 2021. Using the tax brackets and rates for that filing status, we can calculate their tax liability. Please note that the tax rates and brackets are subject to change, so it's important to refer to the most recent tax regulations.

Tax Liability = (Tax on 10% Bracket) + (Tax on 12% Bracket) + (Tax on 22% Bracket) + (Tax on 24% Bracket)

The taxable income falls into multiple brackets, so we'll calculate the tax liability for each bracket separately:

Tax on 10% Bracket: $0 - $19,900 = $0

Tax on 12% Bracket: $19,901 - $81,050 = ($81,050 - $19,900) * 0.12

Tax on 22% Bracket: $81,051 - $172,750 = ($172,750 - $81,050) * 0.22

Tax on 24% Bracket: $172,751 - $451,350 = ($451,350 - $172,750) * 0.24

Calculate the total tax liability:

Tax Liability = Tax on 10% Bracket + Tax on 12% Bracket + Tax on 22% Bracket + Tax on 24% Bracket

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1) Select the linear function that is perpendicular to the following: y = 4x + 12

Answers

Answer:

Step-by-step explanation:

slope of line y=4x+12 is 4

slope of line perpendicular to y=4x+12 is -1/4

eq. of perpendicular line or perpendicular linear function is y=-1/4x+b  where b is the y-intercept.

15+2 parentheses 2×4 parentheses -4 to the power of two

Answers

Hey there!


Do PEMDAS

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

15 + 2(2 * 4) - 4^2

= 15 + 2(8) - 4^2

= 15 + 16 - 4^2

= 31 - 4^2

= 31 - 4 * 4

= 31 - 16

= 15


Therefore, your answer is: 15


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

Answer:

The answer is 15.

Step-by-step explanation:

\({\tt{\underline{\underline{\pink{SOLUTION:}}}}}\)

To solve the above equation we will follow the BODMAS rule.

\(\blue\star\) BODMAS is an order of mathematic operations.\(\blue\star\) BODMAS rule is to be followed while solving expressions in mathematics.

It stands for :

\(\purple\star\) B = bracket\(\purple\star\) O = order of power\(\purple\star\) D = division\(\purple\star\) M = multiplication\(\purple\star\) A = addition\(\purple\star\) S = subtraction

Solving this question by bodmas rule :

\(\begin{gathered}\qquad{\twoheadrightarrow{\tt{15 + 2(2 \times 4) - {4}^{2}}}} \\ \\ \qquad{\twoheadrightarrow{\tt{15 + 2(8) - {4}^{2}}}} \\ \\ \qquad{\twoheadrightarrow{\tt{15 + 2 \times 8 - {4}^{2}}}} \\ \\ \qquad{\twoheadrightarrow{\tt{15 + 16 - {4}^{2}}}} \\ \\ \qquad{\twoheadrightarrow{\tt{31 - {4}^{2}}}} \\ \\ \qquad{\twoheadrightarrow{\tt{31 - {4} \times 4}}} \\ \\ \qquad{\twoheadrightarrow{\tt{31 - 16}}} \\ \\ \qquad{\twoheadrightarrow{\tt{\underline{\underline{15}}}}} \end{gathered}\)

Hence, the answer is 15.

\(\rule{300}{2.5}\)

classify the quadrilateral by its most specific name. then find the missing angle measure(s)

classify the quadrilateral by its most specific name. then find the missing angle measure(s)

Answers

The specific name of the quadrilateral is trapezoid

The measure of the missing angle is 55 degrees

How to determine the value

To determine the measure of the angle, we need to know the following;

The properties of a trapezoid are listed as;

The bases are parallel to each other.Opposite sides of a trapezoid (isosceles) are of the same length.Angles next to each other sum up to 180 degreesThe median is parallel to both the bases.Median's length is the average of both the bases

From the information given, we have that;

125 + x = 180

collect the like terms, we have;

x = 180 - 125

subtract the values, we get;

x = 55 degrees

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Find the average quarterly loads for the rest of the years.

Find the quarterly seasonal indices by dividing the actual quarterly loads by the average quarterly loads for a year. For​ example, for Quarter​ 1, Year​ 1, the seasonal index is

Answers

To find the average quarterly loads for the rest of the years, you can use the formula below:

Average Quarterly Load = Total Annual Load  4 For example, let's say the total annual load for Year 1 is 800.

To find the average quarterly loads for Year 1, we would divide 800 by 4 to get an average quarterly load of 200. Then, you can use this average quarterly load to find the seasonal indices for each quarter of each year.To find the seasonal index for a given quarter and year, you would divide the actual quarterly load by the average quarterly load for that year.

For example, let's say the actual load for Quarter 1, Year 1 is 240. To find the seasonal index for this quarter and year, we would divide 240 by 200 to get a seasonal index of 1.2. You would repeat this process for each quarter and year to find the seasonal indices for all quarters and years.

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Mary spent $8 of the $40 that
she had. What is this as a
fraction?

Answers

Answer:

8/40 is the correct answer

Please only answer : The horizontal scale should be X-scale and The vertical scale should be Y-scale

Please only answer : The horizontal scale should be X-scale and The vertical scale should be Y-scale

Answers

Regarding the scales to plot the points on the table, we have that:

The horizontal goes from X-min = -7 to X-max = 6.The horizontal scale should be X-scale = 1.The vertical goes from Y-min = -1500 to Y-max = 1200.The vertical scale should be Y-scale = 200.

What are the ideal scales for the graphs?

To find the ideal scales, we have to verify which are the extrema values of each variable, that is, the minimum and maximum value of each x and y.

From the table, the minimum and maximum values of X are given as follows:

X-min = -7.X-max = 6.

This is a small range of values, hence the horizontal scale should be of 1.

From the same table, second column, the minimum and maximum values of Y are given as follows:

Y-min: -1500.Y-max: 1200.

This is a large range of values, hence an ideal vertical scale is of 200, as then the number of traces would be almost the same as the number of traces of x.

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solve the equation
9 = b ÷ (-1)​

Answers

Answer:

b=-9

Step-by-step explanation:

b/-1=9

times both sides by -1

b=-9

B=(-9)
-9 divided by -1=9

a shoe store has a sale in which all shoes are priced at $33.00. the original price was $44. what is the percent of discount. ​

Answers

Answer:

44 - 33 = 11

11/44 X 100 = 25%

Step-by-step explanation:

find the difference between the original price and new price (change)

change/original price X 100 = percentage change

Tutoria
A line has a slope of -7 and includes the points (-9, 7) and (-8,k).
What is the value of k?
k =

Answers

Answer:

k= 0

Step-by-step explanation:

\(\boxed{ slope = \frac{y _{1} - y_2 }{x_1 - x_2} }\)

where (x₁, y₁) is the first coordinate and (x₂, y₂) is the second coordinate

\( - 7 = \frac{k - 7}{ - 8 - ( - 9)} \)

\( - 7 = \frac{k - 7}{ - 8 + 9} \)

\( - 7 = \frac{k - 7}{1} \)

k -7= -7

+7 on both sides:

k= -7 +7

k= 0

1) Pansy Meadows Primary Care Clinic provides routine diagnostic and treatment services for common illnesses. Assume they see 1000 patients per month for office visits. (We have not looked at data in this way in class. Think about what it is telling you and try to logic your way through it.) A) What is Pansy Meadow Primary Care Clinic's total revenue per month? B) Assume that PMPCC's fixed costs are \$25000 per month and their variable costs are S10 per office visit. What is their monthly profit (loss)? C) What would happen to your profitability of the commercial insurance company changed their reimbursement rate to $65? D) What if the Commercially Insured Patients were all covered by a capitated contract. Instead of being reimbursed per service, (this is not changing the total number of office visits PMPCC treats), they are paid by the commercial insurance company \$2 PMPM to be available to provide services. i. What are PMPCC's monthly revenue ii. What is PMPCC's monthly profit/loss?

Answers

A) Pansy Meadows Primary Care Clinic's total revenue per month is $10,000. B) The clinic's monthly profit is a loss of $15,000. C)  if the commercial insurance company changes the reimbursement rate to $65, the monthly profit would be $30,000. D) if all commercially insured patients are covered by a capitated contract, the monthly profit would be a loss of $33,000.

To calculate the clinic's total revenue, monthly profit/loss, and the impact of changes in reimbursement rates, we'll use the given information and perform the necessary calculations.

Given:

Number of office visits per month = 1000

Fixed costs = $25,000 per month

Variable costs per office visit = $10

A) Total revenue per month:

Revenue per office visit = $10 (variable cost per visit)

Total revenue per month = Revenue per office visit * Number of office visits per month

Total revenue per month = $10 * 1000

Total revenue per month = $10,000

Therefore, Pansy Meadows Primary Care Clinic's total revenue per month is $10,000.

B) Monthly profit (loss):

Profit (loss) = Total revenue per month - Fixed costs - (Variable costs per office visit * Number of office visits per month)

Profit (loss) = $10,000 - $25,000 - ($10 * 1000)

Profit (loss) = -$15,000

Therefore, the clinic's monthly profit is a loss of $15,000.

C) Impact of changing the commercial insurance reimbursement rate to $65:

To determine the impact on profitability, we need to recalculate the monthly profit using the new reimbursement rate.

New total revenue per month = $65 * 1000 = $65,000

Profit (loss) = New total revenue per month - Fixed costs - (Variable costs per office visit * Number of office visits per month)

Profit (loss) = $65,000 - $25,000 - ($10 * 1000)

Profit (loss) = $30,000

Therefore, if the commercial insurance company changes the reimbursement rate to $65, the monthly profit would be $30,000.

D) Impact of all commercially insured patients being covered by a capitated contract:

i. Monthly revenue:

Revenue per patient per month = $2 (capitated payment per patient)

Monthly revenue = Revenue per patient per month * Number of office visits per month

Monthly revenue = $2 * 1000

Monthly revenue = $2,000

ii. Monthly profit/loss:

Profit (loss) = Monthly revenue - Fixed costs - (Variable costs per office visit * Number of office visits per month)

Profit (loss) = $2,000 - $25,000 - ($10 * 1000)

Profit (loss) = -$33,000

Therefore, if all commercially insured patients are covered by a capitated contract, the monthly profit would be a loss of $33,000.

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Complete the proof!!!

Complete the proof!!!

Answers

Answer:

The correct options are;

1. Definition of supplementary angles

2. m∠1 + m∠2 = m∠1 + m∠3

3. m∠2 = m∠3

4. Definition of congruent angles

Step-by-step explanation:

The two column proof is presented as follows;

Statement    \({}\)                                      Reason

1. ∠1 and ∠2 are supplementary \({}\)       Given

∠1 and ∠3 are supplementary \({}\)      

2. m∠1 + m∠2 = 180°     \({}\)                      (1) Definition of supplementary angles

m∠1 + m∠3 = 180°

3. (2) m∠1 + m∠2 = m∠1 + m∠3      \({}\)     Transitive Property

4. (3) m∠2 = m∠3     \({}\)                            Subtraction property of equality

5. ∠2 ≅ ∠3     \({}\)                                       (4) Definition of congruent angles

Given that angles ∠1 and ∠2 are supplementary, we have, ∠1 + ∠2 = 180°

Given that angles ∠1 and ∠3 are also supplementary, we also have, ∠1 + ∠3 = 180°

∴ ∠1 + ∠2 = 180° = ∠1 + ∠3

∠1 + ∠2 = ∠1 + ∠3

∠1 + ∠2 - ∠1 = ∠1 + ∠3 - ∠1

∴ ∠2 = ∠3

∴ ∠2 ≅ ∠3, by definition of congruent angles.

An automobile manufacturer claims that their van has a 53.8 miles/gallon (MPG) rating. An independent testing firm has been contracted to test the MPG for this van. After testing 16 vans they found a mean MPG of 53.4 with a standard deviation of 1 MPG. Is there sufficient evidence at the 0.1 level that the vans have an incorrect manufacturer's MPG rating

Answers

The value of 0.0062 is less that our significance level of 0.1, we reject the null hypothesis at the 0.1 level of significance and conclude with sufficient evidence that the manufacturer's MPG rating is incorrect.

To answer the question, we will conduct a hypothesis test to at the 0.1 level to ascertain whether or not the manufacturer's MPG rating is incorrect.

We start by stating the null and alternative hypotheses:

\($H_0$\): The mean miles/gallon for the vans is 53.8

\($H_A$\): The mean miles/gallon for the vans is not 53.8

We choose a significance level $\alpha = 0.1$ and calculate the following test statistic:

\($z = \frac{\bar{x}-\mu}{\sigma/\sqrt{n}} = \frac{53.4-53.8}{1/\sqrt{16}} = -2.5$\)

With a standard normal table, we look for the area to the left of -2.5, which is 0.0062. Because this value of 0.0062 is less that our significance level of 0.1, we reject the null hypothesis at the 0.1 level of significance and conclude with sufficient evidence that the manufacturer's MPG rating is incorrect.

Therefore, the value of 0.0062 is less that our significance level of 0.1, we reject the null hypothesis at the 0.1 level of significance and conclude with sufficient evidence that the manufacturer's MPG rating is incorrect.

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B^3 = 1,000 what is B

Answers

B is 10. If you do 10x10x10, you get the answer of 1,000

Answer:

B = 10

I hope this helps!

PQ=RQ
b
140°
P
R
b = [? ]°
pls help me besties

PQ=RQb140PRb = [? ]pls help me besties

Answers

Answer:

b=40 I just took this quiz

Answer:b=40 a=100

Step-by-step explanato a line is 180 degrees, the outside of the triangle is 140 degrees so the inside must be 40 to make 180 and a is also 40 because the triangles sides are the same

 

to find a we now know that both angles on the bottom 40+40 will add up to 80 and to make a complete triangle we need 180 so the measure of a is 100 degrees

a=100

b=40

This topic is all about inequalities!
The question is in this image.

This topic is all about inequalities! The question is in this image.

Answers

Considering the perimeter of the trapezoid, the set-builder representation of the possible values for the length of the sides labeled m is:

{m | m > 6}.

What is the perimeter of a polygon?

The perimeter of a polygon is calculated by the sum of the lengths of all the outer edges of the figure.

In the context of this problem, these measures of the outer edges are given as follows:

6.10.m.m.

Hence the perimeter of the trapezoid is given as follows:

P = 6 + 10 + m + m = 16 + 2m.

The perimeter is greater than 28, hence the inequality is:

P > 28.

16 + 2m > 28. (replacing the equation for P into the inequality).

2m > 12

m > 12/2

m > 6.

The set-builder notation of this interval is:

{m | m > 6}.

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If a decimal point is only in the ________, you can move it up into the quotient.

Answers

Answer:

divident

Step-by-step explanation:

If the distance from A to B is 7 units, which of the following could be used to calculate the coordinates for point B? 07. Vix + 4y + +(y + 5)2 07. Vix + 5)2 + (y + 45° 07. V(x - 4) +(y – 5) 07. Vix - 5) + (y - 4)

Answers

The coordinates for point B are 7 = √(x - 5)² + (y - 4)².

What is the distance formula?

The distance formula is used to calculate the length of the line which joins the two points in an x−y plane. The distance between two points is the length of the line joining the two points. If the two points lie on the same horizontal or same vertical line.

Here, we have

Given: Segment AB Has point A located At (5, 4). If The Distance from A To B Is 7 units.

To find the distance between any two the following formula is used.

D = √(x₂ - x₁)² + (y₂ - y₁)²

7 = √(x - 5)² + (y - 4)²

Hence, the coordinates for point B are 7 = √(x - 5)² + (y - 4)².

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Find all real numbers a such that
a2=a−2.
Explain why this does not violate the exponential function property which states
ax=ay
if and only if
x=y.

Answers

To find all real numbers a that satisfy the equation \(a^2\) = a - 2, we can rewrite the equation as\(a^2\) - a + 2 = 0 and solve for a using quadratic equation methods.

The quadratic equation is given by ax^2 + bx + c = 0, where in our case a = 1, b = -1, and c = 2. Substituting these values into the quadratic equation formula (-b ± √(b^2 - 4ac)) / (2a), we get:

a = (-(-1) ± √(\((-1)^2\) - 4(1)(2))) / (2(1))

  = (1 ± √(1 - 8)) / 2

  = (1 ± √(-7)) / 2

Since the square root of a negative number is not a real number, there are no real solutions for a that satisfy the equation \(a^2\) = a - 2. In other words, there are no real numbers that make the equation true.

This does not violate the exponential function property because the equation\(a^2\) = a - 2 does not involve raising a to a power. The property ax = ay if and only if x = y holds for exponential functions, but it does not apply to the equation in question. In this case, we are solving a quadratic equation, not dealing with exponentiation.

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3) Each sequence below is geometric. Identify the values of a and r Write the formula for the general term, an State whether or not the sequence is convergent or divergent and how you know. Hint: Some

Answers

To identify the values of a and r and determine if the sequence is convergent or divergent, we need to analyze each given geometric sequence.

1) Sequence: 3, 6, 12, 24, ...

  The common ratio (r) can be found by dividing any term by its preceding term. Here, r = 6/3 = 2. The first term (a) is 3. The general term (an) can be written as an = a * r^(n-1) = 3 * 2^(n-1). Since the common ratio (r) is greater than 1, the sequence is divergent, as it will continue to increase indefinitely as n approaches infinity.

2) Sequence: -2, 1, -1/2, 1/4, ...

  The common ratio (r) can be found by dividing any term by its preceding term. Here, r = 1/(-2) = -1/2. The first term (a) is -2. The general term (an) can be written as an = a * r^(n-1) = -2 * (-1/2)^(n-1) = (-1)^n.  Since the common ratio (r) has an absolute value less than 1, the sequence is oscillating between -1 and 1 and is divergent.

3) Sequence: 5, -15, 45, -135, ...

  The common ratio (r) can be found by dividing any term by its preceding term. Here, r = -15/5 = -3. The first term (a) is 5. The general term (an) can be written as an = a * r^(n-1) = 5 * (-3)^(n-1). Since the common ratio (r) has an absolute value greater than 1, the sequence is divergent. In summary, the first sequence is divergent, the second sequence is divergent and oscillating, and the third sequence is also divergent.

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