Malachite green elutes faster from the column than crystal violet so malachite green is the _________ dye.

According to the Aufbau principle, the 4s orbital is filled first instead of the 3d orbital

Each electron shell and its orbitals have a specific energy level.

The farther the shell is from the atomic nucleus, the higher the energy level.

This energy level is expressed in the form of electron configurations.

Writing electron configurations starts from the lowest to the highest sub-shell energy level. There are 4 sub shell in the shell of an atom, namely s, p, d and f.

Charging electrons in the subshell uses the following sequence:

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.

According to Aufbau, electrons occupy orbitals of the lowest energy level  

So the 4s orbital has a lower energy level than the 3d orbital, so the electrons fill the 4s orbital first

Answer: The freezing point (in °C) of a 0.743 m aqueous solution of KCI is \(2.763^{o}C\).

Explanation:

Given: Molality = 0.743 m

\(K_{f}\) for water = \(1.86^{o}C/m\)

The equation for dissociation of KCl when dissolved in water is as follows.

\(KCl \rightarrow K^{+} + Cl^{-}\)

As it is giving 2 ions. Therefore, Van't Hoff factor for it is equal to 2.

Formula used to calculate the freezing point is as follows.

\(\Delta T_{f} = i \times K_{f} \times m\)

where,

i = Van't Hoff factor

\(K_{f}\) = molal depression constant

m = molality

Substitute the values into above formula as follows.

\(\Delta T_{f} = i \times K_{f} \times m\\= 2 \times 1.86^{o}C/m \times 0.743 m\\= 2.763^{o}C\)

Thus, we can conclude that the freezing point (in °C) of a 0.743 m aqueous solution of KCI is \(2.763^{o}C\).

Answer:

The number of these organisms in the soil would decrease.

Explanation:

Answer:

\(M_{acid}=0.0444M\)

Explanation:

Hello,

In this case, for the given reaction:

\(H _2 S O _4 + 2 N a O H \rightarrow 2 _H 2 O + N a _2 S O_ 4\)

We find a 1:2 molar ratio between the acid and the base respectively, for that reason, at the equivalence point we find:

\(2*n_{acid}=n_{base}\)

That in terms of concentrations and volumes we can compute the concentration of the acid solution:

\(2*M_{acid}V_{acid}=M_{base}V_{base}\\\\M_{acid}=\frac{M_{base}V_{base}}{2*V_{acid}}=\frac{0.697M*28.07mL}{2*220.1mL}\\ \\M_{acid}=0.0444M\)

Best regards.

The concentration of the sulfuric acid solution (H₂SO₄) is 0.0444 M

From the question,

We are to determine the concentration of the H₂SO₄ solution

Using the titration formula

\(\frac{C_{A}V_{A} }{C_{B}V_{B}} = \frac{n_{A}}{n_{B}}\)

Where

\(C_{A}\) is the concentration of acid

\(C_{B}\) is the concentration of base

\(V_{A}\) is the volume of acid

\(V_{B}\) is the volume of base

\(n_{A}\) is the mole ratio of acid

and \(n_{B}\) is the mole ratio of base

The given balanced chemical equation for the reaction is

H₂SO₄ + 2NaOH ⟶ 2H₂O + Na₂SO₄

∴ \(n_{A} = 1\)

and \(n_{B} = 2\)

From the given information

\(V_{A} = 220.1 \ mL\)

\(C_{B} = 0.697 \ M\)

\(V_{B} = 28.07 \ mL\)

Putting the parameters into the equation, we get

\(\frac{C_{A} \times 220.1}{0.697 \times 28.07}= \frac{1}{2}\)

∴ \(C_{A} = \frac{1 \times 0.697 \times28.07}{2\times 220.1}\)

\(C_{A} = \frac{19.56479}{440.2}\)

\(C_{A} = 0.0444 \ M\)

Hence, the concentration of the sulfuric acid solution (H₂SO₄) is 0.0444 M

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Answer:

the pressure in The air increase

Answer:

Mitochondria

Explanation:

Mitochondria are organelles whose membranes are specialized for aerobic respiration.

The concentration of the acid is \(0.25 M\).

Titration is a laboratory technique used to determine the concentration of a substance in a solution by reacting it with a standardized solution of known concentration.

The titration formula can be given by,

(Volume of the Base) \(\times\) (Normality of the Base) = (Volume of the Acid) \(\times\) (Normality of the Acid)

\(\Rightarrow V_1N_1=V_2N_2\)

Given, the volume of the base (\(NaOH\)), \(V_1 =25 ml\).

The concentration of the base (\(NaOH\)), \(M_1=0.5 M\).

The equivalence of the base (\(NaOH\)) is \(1\).

Hence, the normality of the base (\(NaOH\)), \(N_1=\frac{0.5}{1}N=0.5N\).

Given, the volume of the acid (\(HCl\)), \(V_2 =50 ml\).

Let us assume that the normality of the acid (\(HCl\)) \(N_2\).

Substitute the values in the given formula of titration.

\((25\times0.5)=(50 \times N_2)\\\Rightarrow 12.5=50N_2\\\Rightarrow N_2=\frac{12.5}{50} N\\\Rightarrow N_2=0.25 N\)

Hence, the normality of the acid (\(HCl\)), \(N_2=0.25 N\).

The equivalence of the acid (\(HCl\)) is \(1\).

Therefore, the concentration of the acid, \(M_1=\frac{0.25}{1}=0.25 M\).

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Answer:

The wall that was retaken in attack on titan after a great battle.

See image for refrence

Explanation:

Answer:

it's B for sure because it's flat areas formed by solar winds

The compound would have a molecular formula of C5H10O2.

The empirical formulas is the simplest formula of a compound.

We know that;

Mass  of the carbon = 14.03 * 12/44 = 3.82 g

Moles of C = 3.82 g/12 g/mol = 0.32 moles

Mass of water = 3.83 * 2/18 = 0.43 g

Moles of H =  0.43 g/1 g/mol =  0.43  moles

Mass of oxygen = 8.5 - (3.82 + 0.43)

= 4.25 g

Moles of oxygen = 4.25 g/16 g/mol = 0.27 moles

We can now divide through by the lowest ratio;

C - 0.32    H - 0.43    O - 0.27

C - 1   H - 2  O - 1

The empirical formula is CH2O

The molecular formula is;

[12 + 2+ 16]n = 160

n = 160/30

n = 5

The molecular formula is;

C5H10O2

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Answer:

Ionic Bond

Explanation:

The atom with the higher electronegativity wants to fill its valence electron shell (meaning it wants 8 electrons in this shell). The atom with lower electronegativity will want to empty or donate an electron so that it can have an empty valence shell.

Answer:

2.91M is the concentration of the household ammonia solution

Explanation:

18.2mL of a 0.800M HCl solution to neutralize 5.00mL

The reaction of HCl with NH3 is:

HCl + NH3 → NH4Cl

Thus, the moles of HCl needed to neutralize the household are equal to moles of NH3. That is:

18.2mL = 0.0182L * (0.800mol / L) = 0.01456 moles HCl = Moles NH3.

In 5.00mL = 0.005L:

0.01456 moles NH3 / 0.005L =

Answer:

proton :

a particale or atom containing a postive charge

nuutron

a particale or atom that contains a negative charge

electron :

a particale or atom with a negative chrage.

Explanation:

proton:

a stable subatomic particle occurring in all atomic nuclei, with a positive electric charge equal in magnitude to that of an electron, but of opposite sign.

nuetron:

a subatomic particle of about the same mass as a proton but without an electric charge, present in all atomic nuclei except those of ordinary hydrogen.

elcetron:

a stable subatomic particle with a charge of negative electricity, found in all atoms and acting as the primary carrier of electricity in solids.

Answer:

They are compounds.

Explanation:

..........

Answer:

compounds!!

Explanation:

...........

Answer:

4.50 L

Explanation:

First we calculate how many moles are there in 3.84 L of a 8.50 mol/L solution:

Now, keeping in mind that

we can calculate the volume of a 7.25 mol/L solution that would contain 32.64 moles:

So we could take 4.50 L of the 7.25 mol/L solution and evaporate the solvent until only 3.84 L remain.

Answer:

Yeasts reproduce asexually by a process called budding (see Figure 8.2. 1 and Figure 8.2. 6). A bud is formed on the outer surface of the parent cell as the nucleus divides.

Explanation:

On CK-12 all of these answers are correct

1.9

1.888

1.89

1.88

The molality of a 10.0 % by mass solution of sodium chloride (NaCl) is 1.7M.

Molarity of any solution will be calculated as number of moles of solutes present in per litre of the solution.

Moles of the substance will be calculated as:

n = W/M, where

W = given mass

M = molar mass

Given that percent mass of NaCl = 10% i.e. 10g of NaCl is present in 100 g of solution.

We know that 1 g = 0.001 L

100 g = 0.1 L

Moles of NaCl = 10g / 58.44g/mol = 0.17 mol

Molarity of NaCl = 0.17 / 0.1 = 1.7M

Hence required molarity is 1.7 M.

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Answer: K=8, C=1, O=12

Explanation:

The empirical formula of the compound with 14.3% Nitrogen, 4.1% Hydrogen, and 81.6% Bromine would be \(NH_4Br\).

The compound contains 3 atoms of different elements according to the following percentage:

Let's find the mole equivalent of each percentage:

Divide by the smallest mole:

Thus, the empirical formula of the compound is \(NH_4Br\).

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Answer:

D. As a particle and a wave

The mass of the cereal that you would need to consume can be obtained as 84.8 g

The number of moles, denoted by the symbol "n," is a fundamental unit of measurement in chemistry that represents the amount of a substance. It is used to quantify the quantity of atoms, molecules, or ions in a sample.

Number of moles of sucrose in the cereal = 11g/342 g/mol

= 0.03 moles

Now;

0.03 moles of sucrose is contained in 60 g of cereal

0.0424 moles of sucrose would contain 0.0424 moles * 60 g/0.03 moles

= 84.8 g

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Answer:

Well, there is no photo...

Explanation:

The activation energy of this reaction is approximately -13.770 J/mol.

1. To graphically determine the activation energy, we need to plot two points. The given data points are:

  Point 1: (1, -1.275)

  Point 2: (2, 0.379725)

2. The rise is the change in the y-coordinate between the two points:

  Rise = y2 - y1 = 0.379725 - (-1.275) = 1.654725

3. The run is the change in the x-coordinate between the two points:

  Run = x2 - x1 = 2 - 1 = 1

4. The slope of the line formed by these two points can be calculated using the formula:

  Slope = rise / run = 1.654725 / 1 = 1.654725

5. The activation energy (Ea) can be determined using the equation:

  Ea = -R * slope

 Here, R is the ideal gas constant, which is approximately 8.314 J/(mol·K).

6. Plugging in the values:

  Ea = -8.314 * 1.654725 = -13.770 J/mol

Note that the activation energy is negative because it represents the energy difference between the reactants and the transition state (higher energy) in an exothermic reaction.

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For each molecule, the hydrolyzable (scissile bond) is located between the α and β phosphates (the first two phosphate groups connected to the ribose sugar).

Hydrolysis of this bond releases energy stored in the molecule.

To draw the requested molecules, follow the steps below:
(i) ATP (Adenosine Triphosphate)
1. Draw an adenine base with a double-ring structure (a purine).
2. Connect the adenine to a ribose sugar (a 5-carbon pentose sugar) at the N9 position of the adenine and the C1' position of the ribose.
3. Add a chain of three phosphate groups \(PO_4\) to the C5' position of the ribose.
(ii) GTP (Guanosine Triphosphate)
1. Draw a guanine base with a double-ring structure (another purine).
2. Connect the guanine to a ribose sugar at the N9 position of the guanine and the C1' position of the ribose.
3. Add a chain of three phosphate groups to the C5' position of the ribose.
(iii) GMP-PCP (Guanosine 5'-[(α,β)-Methylene]triphosphate)
1. Draw a guanine base and connect it to a ribose sugar, as in GTP.
2. Add two phosphate groups to the C5' position of the ribose.
3. Add a methylene group \(CH_2\)  between the second and third phosphate groups, replacing the oxygen that normally connects them.
The difference between ATP and GTP is the base: ATP has adenine while GTP has guanine.

GMP-PCP differs from GTP in that it has a methylene group connecting the second and third phosphate groups instead of an oxygen atom.

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Answer:

6060 moles

Explanation:

3.65x10^27 atoms *( 1 mol/6.02*10^23 atoms)= 6063 moles ≈ 6060 moles

Answer:

d) Copper(I) sulfate

Explanation:

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The reaction order and specific reaction rate constant can be determined by performing the kinetics experiment on irreversible polymerization A. Kinetic experiments can be used to investigate the rate and mechanism of chemical reactions. Chemical kinetics is the study of chemical reactions' speed and pathway.

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